Re: Swift: How to determine if a Character represents whitespace?
ok here’s my try, assuming NSLinguisticTagger knows what it’s doing. And yes it’s a bit stupid to use a linguistic tagger to do something like that but .. whatever var str = "Some String WIth Whitespace " var lt = NSLinguisticTagger( tagSchemes: [NSLinguisticTagSchemeTokenType], options: 0 ) lt.string = str var endsWithWhitespace = ( lt.tagAtIndex( (str as NSString).length-1, scheme: NSLinguisticTagSchemeTokenType, tokenRange: nil, sentenceRange: nil ) == NSLinguisticTagOtherWhitespace ) ___ Cocoa-dev mailing list (Cocoa-dev@lists.apple.com) Please do not post admin requests or moderator comments to the list. Contact the moderators at cocoa-dev-admins(at)lists.apple.com Help/Unsubscribe/Update your Subscription: https://lists.apple.com/mailman/options/cocoa-dev/archive%40mail-archive.com This email sent to arch...@mail-archive.com
Re: Converting colorspace of a CGColor
> On 4 Apr 2015, at 1:13 pm, Roland King wrote: > > That’s most definitely not what Graham is looking for. He’s looking for a way > to convert colours programatically, and cross-platform iOS and OSX (no > colorsync on iOS). That's right. In short, a CG equivalent to -[NSColor colorUsingColorspace:] is what I need - I just need to ensure that colours that could originate as grays for example, end up as RGBA colours, since I'm doing work directly on the four components. Converting gray is easy enough actually, if I have to do that myself, but it would be nice if there were a funciton that would work across all possible colorspaces. I thought Id' seen a CG function for this in the past, but I can't remember where I saw it and I may be mistaken. --Graham ___ Cocoa-dev mailing list (Cocoa-dev@lists.apple.com) Please do not post admin requests or moderator comments to the list. Contact the moderators at cocoa-dev-admins(at)lists.apple.com Help/Unsubscribe/Update your Subscription: https://lists.apple.com/mailman/options/cocoa-dev/archive%40mail-archive.com This email sent to arch...@mail-archive.com
Re: Converting colorspace of a CGColor
> On 4 Apr 2015, at 9:38 am, edward m taffel wrote: > > use ColorSync. > That’s most definitely not what Graham is looking for. He’s looking for a way to convert colours programatically, and cross-platform iOS and OSX (no colorsync on iOS). I just looked in my library of bits and pieces and found some code which write into a bitmap and reads it out again. I don’t even know when I wrote that, and it’s not used in any of my projects, but I believe that was me converting colours at low-level. Surely there’s a better way (but then again I said ‘surely there is a better way’ when I saw the discussion on whitespace in swift and there hasn’t been one yet). > Sent from my iPhone > >> On Apr 3, 2015, at 8:35 PM, Graham Cox wrote: >> >> Is there a way to convert a CGColor to a different colorspace? It's trivial >> with NSColor, but I want to do the same at the lower CG level to keep the >> code as portable as possible between iOS and Mac. I'm sure I've done this in >> the past but I'm just not seeing the right function! >> >> --Graham ___ Cocoa-dev mailing list (Cocoa-dev@lists.apple.com) Please do not post admin requests or moderator comments to the list. Contact the moderators at cocoa-dev-admins(at)lists.apple.com Help/Unsubscribe/Update your Subscription: https://lists.apple.com/mailman/options/cocoa-dev/archive%40mail-archive.com This email sent to arch...@mail-archive.com
Re: Converting colorspace of a CGColor
use ColorSync. Sent from my iPhone > On Apr 3, 2015, at 8:35 PM, Graham Cox wrote: > > Is there a way to convert a CGColor to a different colorspace? It's trivial > with NSColor, but I want to do the same at the lower CG level to keep the > code as portable as possible between iOS and Mac. I'm sure I've done this in > the past but I'm just not seeing the right function! > > --Graham > > > > ___ > > Cocoa-dev mailing list (Cocoa-dev@lists.apple.com) > > Please do not post admin requests or moderator comments to the list. > Contact the moderators at cocoa-dev-admins(at)lists.apple.com > > Help/Unsubscribe/Update your Subscription: > https://lists.apple.com/mailman/options/cocoa-dev/etaffel%40me.com > > This email sent to etaf...@me.com ___ Cocoa-dev mailing list (Cocoa-dev@lists.apple.com) Please do not post admin requests or moderator comments to the list. Contact the moderators at cocoa-dev-admins(at)lists.apple.com Help/Unsubscribe/Update your Subscription: https://lists.apple.com/mailman/options/cocoa-dev/archive%40mail-archive.com This email sent to arch...@mail-archive.com
Converting colorspace of a CGColor
Is there a way to convert a CGColor to a different colorspace? It's trivial with NSColor, but I want to do the same at the lower CG level to keep the code as portable as possible between iOS and Mac. I'm sure I've done this in the past but I'm just not seeing the right function! --Graham ___ Cocoa-dev mailing list (Cocoa-dev@lists.apple.com) Please do not post admin requests or moderator comments to the list. Contact the moderators at cocoa-dev-admins(at)lists.apple.com Help/Unsubscribe/Update your Subscription: https://lists.apple.com/mailman/options/cocoa-dev/archive%40mail-archive.com This email sent to arch...@mail-archive.com
Re: Swift: How to determine if a Character represents whitespace?
On Apr 3, 2015, at 13:18 , Charles Jenkins wrote:
>
> is there a way in the playground for use to test addresses to make sure
> attrStr.string as NSString doesn’t perform a copy?
I doubt it. This is the best I could come up with in a couple of minutes:
> import Cocoa
>
> let notWhitespace =
> NSCharacterSet.whitespaceAndNewlineCharacterSet().invertedSet
> let count = 50
>
> let aString: String = String (count: count, repeatedValue: Character ("A"))
> let aNSString: NSString = ("" as NSString).stringByPaddingToLength (count,
> withString: "A", startingAtIndex: 0)
>
> let date1 = NSDate ()
> let bString: String = aNSString as String
> let date2 = NSDate ()
> let time2 = date2.timeIntervalSinceDate(date1)
>
> let date3 = NSDate ()
> let bNSString: NSString = aString as NSString
> let date4 = NSDate ()
> let time4 = date4.timeIntervalSinceDate(date3)
>
> let attrStr = NSAttributedString (string: aNSString)
>
> let date5 = NSDate ()
> let range5 = attrStr.string.rangeOfCharacterFromSet(notWhitespace, options:
> NSStringCompareOptions.allZeros)
> let date6 = NSDate ()
> let time6 = date6.timeIntervalSinceDate(date5)
>
> let date7 = NSDate ()
> let range7 = (attrStr.string as
> NSString).rangeOfCharacterFromSet(notWhitespace, options:
> NSStringCompareOptions.allZeros)
> let date8 = NSDate ()
> let time8 = date8.timeIntervalSinceDate(date7)
Playground results:
time2: 0.3328
time4: 0.1817
time6: 0.0022
time8: 0.0017
Since the “rangeOfCharacter” scans terminate at the first character, this
suggests that there’s no real conversion in the last case, which is the one
you’re interested in. (Also, time6 and time8 don’t vary with the value of
‘count’.) However, generalizing from this seems treacherous. And I may have
just Done It Wrong™.
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Re: Swift: How to determine if a Character represents whitespace?
So my Character.isMemberOfSet() is a poor general-purpose method, and I need to
ditch it.
I like your code. I had to modify it a bit so it wouldn’t fall on strings
composed entirely of whitespace:
let testString = " \n\n \t\t"
let attrStr = NSAttributedString( string:testString )
let str = attrStr.string as NSString
let notWhitespace =
NSCharacterSet.whitespaceAndNewlineCharacterSet().invertedSet
var resultRange:NSRange
let startRange = str.rangeOfCharacterFromSet( notWhitespace,
options:NSStringCompareOptions.allZeros )
if startRange.length > 0 {
let endRange = str.rangeOfCharacterFromSet( notWhitespace,
options:NSStringCompareOptions.BackwardsSearch )
let startIndex = startRange.location
let endIndex = endRange.location + endRange.length
resultRange = NSRange( location:startIndex, length:endIndex - startIndex )
} else {
// String is empty or all whitespace
resultRange = NSRange( location:0, length:0 )
}
let resultStr = attrStr.attributedSubstringFromRange( resultRange )
So, even though attrStr.string returns an NSString, you have use the “as” to
explicitly keep the type and be able to do math on range indexes. Lacking that
cast is what made rangeOfCharacterFromSet() useless to me yesterday.
Your code seems way better. but is there a way in the playground for use to
test addresses to make sure attrStr.string as NSString doesn’t perform a copy?
—
Charles
On April 3, 2015 at 2:04:01 PM, Quincey Morris
(quinceymor...@rivergatesoftware.com) wrote:
On Apr 3, 2015, at 04:00 , Charles Jenkins wrote:
for char in String( self ).utf16 {
if set.characterIsMember( char ) {
return true
}
Now we’re back to the place we started. This code is wrong. It fails for any
code point that isn’t representable a single UTF-16 code value, and it fails
for any grapheme that isn’t representable as a single code point.
This is what I would do (playground version):
import Cocoa
let notWhitespace =
NSCharacterSet.whitespaceAndNewlineCharacterSet().invertedSet
let attrStr = NSAttributedString( string:" Fourscore and seven years ago...
\n\n \t\t" )
let str = attrStr.string as NSString
let startRange = str.rangeOfCharacterFromSet(notWhitespace, options:
NSStringCompareOptions.allZeros)
let endRange = str.rangeOfCharacterFromSet(notWhitespace, options:
NSStringCompareOptions.BackwardsSearch)
let startIndex = startRange.length != 0 ? startRange.location : 0
let endIndex = endRange.length != 0 ? endRange.location + 1 : str.length
let resultRange = NSRange (location: startIndex, length: endIndex - startIndex)
let resultStr = attrStr.attributedSubstringFromRange (resultRange)
It’s the Obj-C code, just written in Swift. The ‘as NSString’ in the 3rd line
makes it work.
The practical difficulty in your original approach is that (e.g.)
String.rangeOfCharacterFromSet returns a Range, but AFAICT that
isn’t convertible back to a NSRange, or even just integer indexes. At the same
time, AFAICT it isn’t useful with a String because it doesn’t contain Character
indexes, just unichar indexes, which have no meaning for a String in general.
Actually, my testing is with Swift 1.1, since I’m not in a position to move to
Xcode 6.3 yet. It’s possible that the results are different in Swift 1.2.
However, in the section of the release notes that talks about bridging between
String and NSString, it says:
Note that these Cocoa types in Objective-C headers are still automatically
bridged to their corresponding Swift type
so I suspect the results would be the same in 1.2. It seems to me there is an
actual bug here:
“String methods corresponding to NSString methods that return NSRange values
actually return Range values, but these are not valid ranges,
either for String objects (they represent UTF-16 code value positions, not
Character positions) or for NSString objects (they’re not convertible back to
NSRange). The String methods ought to return NSRange values just like their
NSString counterparts.”
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Re: Swift: How to determine if a Character represents whitespace?
On Apr 3, 2015, at 11:19 , Marco S Hyman wrote: > > The original code will return true only if all code points map to white space. The “failure” I was talking about is something a bit different. It has two problems: 1. For Unicode code points that are represented by 2 code values, it tests the code values, not the code points. That’s wrong. 2. For graphemes that are represented by 2 or more code points, it still tests the code values, of which there could be 4 or more per grapheme. That’s also wrong. With the ‘for char in String (self)’ code, if you tested whether a decomposed acuteA was in the (7-bit) ASCII character set, you’d get the answer “YES". You could mitigate #1 by using UTF-32 code values instead of UTF-16, but that wouldn’t help with #2. ___ Cocoa-dev mailing list (Cocoa-dev@lists.apple.com) Please do not post admin requests or moderator comments to the list. Contact the moderators at cocoa-dev-admins(at)lists.apple.com Help/Unsubscribe/Update your Subscription: https://lists.apple.com/mailman/options/cocoa-dev/archive%40mail-archive.com This email sent to arch...@mail-archive.com
Re: Swift: How to determine if a Character represents whitespace?
> On Apr 3, 2015, at 11:04 AM, Quincey Morris
> wrote:
>
> On Apr 3, 2015, at 04:00 , Charles Jenkins wrote:
>>
>>for char in String( self ).utf16 {
>> if set.characterIsMember( char ) {
>>return true
>> }
>
> Now we’re back to the place we started. This code is wrong. It fails for any
> code point that isn’t representable a single UTF-16 code value, and it fails
> for any grapheme that isn’t representable as a single code point.
No it doesn't. Give it a test.
let acuteA: Character = "\u{e1}" // An "a" with an accent
let acuteAComposed: Character = "\u{61}\u{301}"// Also an "a" with an accent
func howManyChars( c: Character) -> Int {
var count = 0
for char in String( c ).utf16 {
count += 1
}
return count
}
howManyChars(acuteA)// returns 1
howManyChars(acuteAComposed)// returns 2
The original code will return true only if all code points map to white space.
Marc
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Re: Swift: How to determine if a Character represents whitespace?
On Apr 3, 2015, at 04:00 , Charles Jenkins wrote:
>
> for char in String( self ).utf16 {
> if set.characterIsMember( char ) {
> return true
> }
Now we’re back to the place we started. This code is wrong. It fails for any
code point that isn’t representable a single UTF-16 code value, and it fails
for any grapheme that isn’t representable as a single code point.
This is what I would do (playground version):
> import Cocoa
>
> let notWhitespace =
> NSCharacterSet.whitespaceAndNewlineCharacterSet().invertedSet
> let attrStr = NSAttributedString( string:"Fourscore and seven years
> ago... \n\n \t\t" )
> let str = attrStr.string as NSString
>
> let startRange = str.rangeOfCharacterFromSet(notWhitespace, options:
> NSStringCompareOptions.allZeros)
> let endRange = str.rangeOfCharacterFromSet(notWhitespace, options:
> NSStringCompareOptions.BackwardsSearch)
>
> let startIndex = startRange.length != 0 ? startRange.location : 0
> let endIndex = endRange.length != 0 ? endRange.location + 1 : str.length
>
> let resultRange = NSRange (location: startIndex, length: endIndex -
> startIndex)
> let resultStr = attrStr.attributedSubstringFromRange (resultRange)
It’s the Obj-C code, just written in Swift. The ‘as NSString’ in the 3rd line
makes it work.
The practical difficulty in your original approach is that (e.g.)
String.rangeOfCharacterFromSet returns a Range, but AFAICT that
isn’t convertible back to a NSRange, or even just integer indexes. At the same
time, AFAICT it isn’t useful with a String because it doesn’t contain Character
indexes, just unichar indexes, which have no meaning for a String in general.
Actually, my testing is with Swift 1.1, since I’m not in a position to move to
Xcode 6.3 yet. It’s possible that the results are different in Swift 1.2.
However, in the section of the release notes that talks about bridging between
String and NSString, it says:
> Note that these Cocoa types in Objective-C headers are still automatically
> bridged to their corresponding Swift type
so I suspect the results would be the same in 1.2. It seems to me there is an
actual bug here:
“String methods corresponding to NSString methods that return NSRange values
actually return Range values, but these are not valid ranges,
either for String objects (they represent UTF-16 code value positions, not
Character positions) or for NSString objects (they’re not convertible back to
NSRange). The String methods ought to return NSRange values just like their
NSString counterparts.”
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Re: Swift: How to determine if a Character represents whitespace?
> extension Character {
>
> func isMemberOfSet( set:NSCharacterSet )
> -> Bool
> {
> // The for loop only executes once;
> // its purpose is to convert Character to a type
> // you can actually do something with
> for char in String( self ).utf16 {
> if set.characterIsMember( char ) {
> return true
> }
> }
> return false
> }
>
> }
I believe your comment that the loop executes once is incorrect. It may
execute more than once when the Character is a composed character that
maps to multiple utf16 characters.
Example (stolen from this link):
http://stackoverflow.com/questions/27697508/nscharacterset-characterismember-with-swifts-character-type
let acuteA: Character = "\u{e1}" // An "a" with an accent
let acuteAComposed: Character = "\u{61}\u{301}"// Also an "a" with an accent
Both are a single Character. The latter will cause the loop to iterate twice.
Marc
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Re: Swift: How to determine if a Character represents whitespace?
I imagine you’re right, that they’re NString indexes packaged up into a
frustrating return type. After sleeping on it, though, I imagined that even if
complex grapheme clusters WERE to make count( attrStr.string ) return a
different result than attrStr.length, it would probably never be due to
whitespace. So if I go back to Charles Strstka’s original suggestion, where you
pull off one character at a time, convert it to a 1-Character string, and then
test for whitespace membership, I should be able to count leading and trailing
whitespace characters and then do math based on attrStr.length to create the
range.
Here’s my current playground:
import Cocoa
extension Character {
func isMemberOfSet( set:NSCharacterSet )
-> Bool
{
// The for loop only executes once;
// its purpose is to convert Character to a type
// you can actually do something with
for char in String( self ).utf16 {
if set.characterIsMember( char ) {
return true
}
}
return false
}
}
var result:NSRange
let whitespace = NSCharacterSet.whitespaceAndNewlineCharacterSet()
let attrStr = NSAttributedString( string:" Fourscore and seven years ago...
\n\n \t\t" )
let str = attrStr.string
var headCount = 0
var tailCount = 0
var startIx = str.startIndex
var endIx = str.endIndex
while endIx > startIx && str[ endIx.predecessor() ].isMemberOfSet( whitespace )
{
++tailCount
endIx = endIx.predecessor()
}
if endIx > startIx {
while str[ startIx ].isMemberOfSet( whitespace ) {
++headCount
startIx = startIx.successor()
}
let length = attrStr.length - ( headCount + tailCount )
result = NSRange( location:headCount, length:length )
} else {
// String was empty or all whitespace
result = NSRange( location:0, length:0 )
}
let resultString = attrStr.attributedSubstringFromRange( result )
—
Charles
On April 2, 2015 at 11:16:52 PM, Quincey Morris
(quinceymor...@rivergatesoftware.com) wrote:
On Apr 2, 2015, at 19:28 , Charles Jenkins wrote:
I can indeed call attrStr.string.rangeOfCharacterFromSet(). But in typical
Swift string fashion, the return type is as unfriendly as possible:
Range? — as if the NSString were a Swift string.
I finally read the whole of what you said here, and I had to run to a
playground to check:
import Cocoa
var strA = "Hello?, String”
var strB = "Hello?, String" as NSString
var strC = "Hello\u{1f650}, String”
var strD = "Hello\u{1f650}, NSString" as NSString
var rangeA =
strA.rangeOfCharacterFromSet(NSCharacterSet.whitespaceCharacterSet()) // {Some
“7..<8”}
var rangeB =
strB.rangeOfCharacterFromSet(NSCharacterSet.whitespaceCharacterSet()) // (7,1)
var rangeC =
strC.rangeOfCharacterFromSet(NSCharacterSet.whitespaceCharacterSet()) // {Some
“8..<9”}
var rangeD =
strD.rangeOfCharacterFromSet(NSCharacterSet.whitespaceCharacterSet()) // (8,1)
So, yes, these are NSString indexes all the way, even if the result is packaged
as a Range.
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Re: Do NSStackView's actually work in a NSTableView?
Obviously I am not sure whether you are introducing the NSStackView in to the table view in in IB or in code. Have you made sure that the NSStackView is fully constrained within the NSTableCellView? IB by default does not add constraints to NSView child items added to NSTableCellView instances. > On 3 Apr 2015, at 04:52, Sebastien Boisvert > wrote: > > I only ask because I’m using a stackview that while it behaves as I > configured it in a plain view in a window, it behaves completely different > when put in a tableview. For example, views which I’ve set to detach will > never, ever detach, regardless of the settings I’ve set. > > Anyone have experience with using stackviews in tableviews? > ___ > > Cocoa-dev mailing list (Cocoa-dev@lists.apple.com) > > Please do not post admin requests or moderator comments to the list. > Contact the moderators at cocoa-dev-admins(at)lists.apple.com > > Help/Unsubscribe/Update your Subscription: > https://lists.apple.com/mailman/options/cocoa-dev/jonathan%40mugginsoft.com > > This email sent to jonat...@mugginsoft.com ___ Cocoa-dev mailing list (Cocoa-dev@lists.apple.com) Please do not post admin requests or moderator comments to the list. Contact the moderators at cocoa-dev-admins(at)lists.apple.com Help/Unsubscribe/Update your Subscription: https://lists.apple.com/mailman/options/cocoa-dev/archive%40mail-archive.com This email sent to arch...@mail-archive.com
