DT::Duration overloads
I understand that division can be expressed as multiplication, but is there any particular reason why division (/) is not overloaded but multiplication is for durations? Then you could say: $midpoint = ($dt2 - $dt1)/2; rather than $midpoint = ($dt2 - $dt1) * 0.5; Small thing. Just curious. Thanks, Matt
Re: DT::Duration overloads
On Wed, 9 Jun 2004, Matt Sisk wrote: I understand that division can be expressed as multiplication, but is there any particular reason why division (/) is not overloaded but multiplication is for durations? Then you could say: $midpoint = ($dt2 - $dt1)/2; rather than $midpoint = ($dt2 - $dt1) * 0.5; Small thing. Just curious. Well, division doesn't really work, whether you do it as multiplication or not ;) What is half a minute? How long is half a month? -dave /*=== House Absolute Consulting www.houseabsolute.com ===*/
Re: DT::Duration overloads
On 10 Jun 2004, at 9:25 AM, Dave Rolsky wrote: What is half a minute? How long is half a month? $dtd = DateTime::Duration-new( months = 1, minutes = 1, ); $half_dtd = $dtd / 2; print $half_dtd-months . \n; # 0.5 print $half_dtd-seconds . \n; # 0.5 print strfduration( normalise = 'ISO', pattern = '%Y years, %m months, %e days, %H hours, %M minutes, %S seconds', duration = $half_dtd ); # 0 years, 0 months, 15 days, 0 hours, 0 minutes, 30 seconds Senior Developer PrintSupply - Print Procurement Supply Management 18 Greenaway Street VIC 3105 Tel: (03) 9850 3255 Fx: (03) 9850 3277 http://www.printsupply.com.au/
Re: DT::Duration overloads
On Thu, 10 Jun 2004, Rick Measham wrote: On 10 Jun 2004, at 9:25 AM, Dave Rolsky wrote: What is half a minute? How long is half a month? $dtd = DateTime::Duration-new( months = 1, minutes = 1, ); $half_dtd = $dtd / 2; print $half_dtd-months . \n; # 0.5 print $half_dtd-seconds . \n; # 0.5 print strfduration( normalise = 'ISO', pattern = '%Y years, %m months, %e days, %H hours, %M minutes, %S seconds', duration = $half_dtd ); # 0 years, 0 months, 15 days, 0 hours, 0 minutes, 30 seconds Great, now what should DateTime.pm do in the add_duration method? -dave /*=== House Absolute Consulting www.houseabsolute.com ===*/
Re: DT::Duration overloads
On Wed, 9 Jun 2004, Matt Sisk wrote: I understand that division can be expressed as multiplication, but is there any particular reason why division (/) is not overloaded but multiplication is for durations? Then you could say: $midpoint = ($dt2 - $dt1)/2; rather than $midpoint = ($dt2 - $dt1) * 0.5; Small thing. Just curious. Thinking about this more, I'm considering maybe just requiring that multiplication be passed an integer, because if you do this: my $dur = DateTime::Duration-new( months = 1, days = 1, minutes = 1 ); $dur-multiple(.5); print DateTime-now-add_duration($dur)-datetime; The results are kind of weird, and certainly not what anyone would expect. -dave /*=== House Absolute Consulting www.houseabsolute.com ===*/
Re: DT::Duration overloads
Dave Rolsky wrote: Thinking about this more, I'm considering maybe just requiring that multiplication be passed an integer, because if you do this: What I'd like to do is simply find the midpoint, more or less, between two arbitrary datetimes. Off the cuff, knowing nothing about the internals (which I do, but I'm pretending not to) I'd think this: $mid = $dt1 + ($dt2 - $dt1)/2 to dwim. However, as you say, things aren't really well defined the way durations are defined internally at the moment. So the question becomes -- if the above is not the datetime idiom for finding a midpoint between two datetimes, then what is? Thanks, Matt
