forcing tabs in regex
Regex validates years bisexto and not bisextos in format:
const std::regex
pattern(R"(^(?:(?:(0?[1-9]|1\d|2[0-8])([-/.])(0?[1-9]|1[0-2]|[Jj](?:an|u[nl])|[Mm]a[ry]|[Aa](?:pr|ug)|[Ss]ep|[Oo]ct|[Nn]ov|[Dd]ec|[Ff]eb)|(29|30)([-/.])(0?[13-9]|1[0-2]|[Jj](?:an|u[nl])|[Mm]a[ry]|[Aa](?:pr|ug)|[Ss]ep|[Oo]ct|[Nn]ov|[Dd]ec)|(31)([-/.])(0?[13578]|1[02]|[Jj]an|[Mm]a[ry]|[Jj]ul|[Aa]ug|[Oo]ct|[Dd]ec))(?:\2|\5|\8)(0{2,3}[1-9]|0{1,2}[1-9]\d|0?[1-9]\d{2}|[1-9]\d{3})|(29)([-/.])(0?2|[Ff]eb)\12(\d{1,2}(?:0[48]|[2468][048]|[13579][26])|(?:0?[48]|[13579][26]|[2468][048])00))$)");
this regex above validates the formats through backreferences.
dd-mm- ou dd-str- ou dd-Str-
dd/mm/ ou dd/str/ ou dd/Str/
dd.mm. ou dd.str. ou dd.Str.
Regex validates years bisexto and not bisextos in format:
const std::regex
pattern(R"(^(?:\d{4}([-/.])(?:(?:(?:(?:0?[13578]|1[02]|[Jj](?:an|ul)|[Mm]a[ry]|[Aa]ug|[Oo]ct|[Dd]ec)([-/.])(?:0?[1-9]|[1-2][0-9]|3[01]))|(?:(?:0?[469]|11|[Aa]pr|[Jj]un|[Ss]ep|[Nn]ov)([-/.])(?:0?[1-9]|[1-2][0-9]|30))|(?:(0?2|[Ff]eb)([-/.])(?:0?[1-9]|1[0-9]|2[0-8]|(?:(?:\d{2}(?:0[48]|[2468][048]|[13579][26]))|(?:(?:[02468][048])|[13579][26])00)([-/.])(0?2|[Ff]eb)([-/.])29)$)");
this regex above had to validate the formats through
backreferences.
but it is validating in the following formats
-mm/dd ou -str/dd ou -Str/dd
/mm.dd ou /str.dd ou /Str.dd
.mm-dd ou .str-dd ou .Str-dd
when it had to validate only in the following formats
-mm-dd ou -str-dd ou -Str-dd
/mm/dd ou /str/dd ou /Str/dd
.mm.dd ou .str.dd ou .Str.dd
how do I do it validate only with some of the tabs?
Digital mars QT interface?
I would like to know if there is any repository that uses QT to create QT creator-style programs with buttons and combobox cute?
Re: overload
On Friday, 15 December 2017 at 08:57:23 UTC, Biotronic wrote: On Thursday, 14 December 2017 at 22:47:15 UTC, dark777 wrote: I know that this community is not from c ++, but for some time I studied how to do overload of ostream operators in c ++ and I even managed to get to this result, I got to this result in another post done here but I did not understand the that it returns this error below: bin2.cxx:44:43: error: expected ‘,’ or ‘...’ before ‘(’ token std::ostream& operator<<(std::ios_base& (__cdecl *_Pfn)(std::ios_base&)) ^ bin2.cxx: In member function ‘std::ostream& BinStream::operator<<(std::ios_base&)’: bin2.cxx:46:16: error: ‘_Pfn’ was not declared in this scope return os <<_Pfn; I expect it's confused by __cdecl. I just copied the function declaration from VS' iostreams, so it might be tainted by how VS does things. Removing __cdecl might work, or just add #define __cdecl __attribute__((__cdecl__)) A third option is to replace `std::ios_base& (__cdecl *Pfn)(std::ios_base&)` with `decltype(std::hex)& Pfn`. All of this said, I'd suggest finding a C++ forum to get answers to these questions. While I'm happy to help, it's not really the place for these discussions. -- Biotronic I do not use windows I thought it was the standard of iostream ansi c++
overload
I know that this community is not from c ++, but for some time I
studied how to do overload of ostream operators in c ++ and I
even managed to get to this result, I got to this result in
another post done here but I did not understand the that it
returns this error below:
bin2.cxx:44:43: error: expected ‘,’ or ‘...’ before ‘(’ token
std::ostream& operator<<(std::ios_base& (__cdecl
*_Pfn)(std::ios_base&))
^
bin2.cxx: In member function ‘std::ostream&
BinStream::operator<<(std::ios_base&)’:
bin2.cxx:46:16: error: ‘_Pfn’ was not declared in this scope
return os <<_Pfn;
so that the output is the same as below:
127 em binario: 000111
127 em octal: 177
127 em binario: 000111
127 em hexadecimal: 7f
127 em decimal: 127
127 em binario: 000111
and not this:
127 em binario: 000111
127 em octal: 000111
127 em binario: 000111
127 em hexadecimal: 000111
127 em decimal: 000111
127 em binario: 000111
#include //ios_base
#include
#include// CHAR_BIT
#include
#include // reverse
struct BinStream
{
std::ostream& os;
BinStream(std::ostream& os) : os(os) {}
std::string binario(unsigned int n)
{
//converte numero para string de bits
std::stringstream bitsInReverse;
//int nBits = sizeof(n) * CHAR_BIT;
unsigned int nBits = sizeof(n)*2.5;
while (nBits-- > 0)
{
bitsInReverse << (n & 1);
n >>= 1;
}
std::string bits(bitsInReverse.str());
std::reverse(bits.begin(), bits.end());
return bits;
}
template
BinStream& operator<<(T&& value)
{
os << value;
return *this;
}
BinStream& operator<<(int value)
{
os << binario(value);
return *this;
}
std::ostream& operator<<(std::ios_base& (__cdecl
*_Pfn)(std::ios_base&))
{
return os << _Pfn;
}
};
struct Bin
{
friend BinStream operator<<(std::ostream& os, const Bin&
f);
} bin;
BinStream operator<<(std::ostream& os, const Bin& f)
{
return BinStream(os);
}
int main()
{
std::cout << "\n\t127 em binario: " << binario(127)
<< "\n\t127 em binario: " << bin << 127
<< "\n\t127 em octal: " << std::oct << 127
<< "\n\t127 em binario: " << bin << 127
<< "\n\t127 em hexadecimal: " << std::hex << 127
<< "\n\t127 em binario: " << bin << 127
<< "\n\t127 em decimal: " << std::dec << 127
<< "\n\t127 em binario: " << bin << 127 << "\n\n";
}
Re: operator overload
On Tuesday, 12 December 2017 at 17:13:55 UTC, Biotronic wrote:
On Tuesday, 12 December 2017 at 16:54:17 UTC, Biotronic wrote:
There is no way in C++ to set the format the way you want it.
If you want binary output, you need to call a function like
your binario function.
Of course this is not entirely true - there is a way, but it's
ugly and probably not what you want:
struct BinStream
{
std::ostream& os;
BinStream(std::ostream& os) : os(os) {}
template
BinStream& operator<<(T&& value)
{
os << value;
return *this;
}
BinStream& operator<<(int value)
{
os << binario(value);
return *this;
}
std::ostream& operator<<(std::ios_base& (__cdecl
*_Pfn)(std::ios_base&))
{
return os << _Pfn;
}
};
struct Bin
{
friend BinStream operator<<(std::ostream& os, const
Bin& f);
} bin;
BinStream operator<<(std::ostream& os, const Bin& f)
{
return BinStream(os);
}
int main()
{
std::cout << "\n\t127 em binario: " << binario(127)
<< "\n\t127 em binario: " << bin << 127
<< "\n\t127 em octal: " << std::oct << 127
<< "\n\t127 em binario: " << bin << 127
<< "\n\t127 em hexadecimal: " << std::hex << 127
<< "\n\t127 em binario: " << bin << 127
<< "\n\t127 em decimal: " << std::dec << 127
<< "\n\t127 em binario: " << bin << 127 << "\n\n";
}
What is this black magic? Instead of overriding how
std::ostream does formatting, Bin::Operator<< now returns a
wrapper around a std::ostream, which special cases ints. If it
gets any other format specifiers, it returns the ostream again,
and the binary formatting is gone.
All in all, I think the conclusion is: Stay with D.
--
Biotronic
I tried to execute with this part of the code
std::ostream& operator<<(std::ios_base& (__cdecl
*_Pfn)(std::ios_base&))
{
return os <<_Pfn;
}
and it returns me this error below what is the include?
bin2.cxx:44:43: error: expected ‘,’ or ‘...’ before ‘(’ token
std::ostream& operator<<(std::ios_base& (__cdecl
*_Pfn)(std::ios_base&))
^
bin2.cxx: In member function ‘std::ostream&
BinStream::operator<<(std::ios_base&)’:
bin2.cxx:46:16: error: ‘_Pfn’ was not declared in this scope
return os <<_Pfn;
Re: operator overload
On Tuesday, 12 December 2017 at 17:13:55 UTC, Biotronic wrote:
On Tuesday, 12 December 2017 at 16:54:17 UTC, Biotronic wrote:
There is no way in C++ to set the format the way you want it.
If you want binary output, you need to call a function like
your binario function.
Of course this is not entirely true - there is a way, but it's
ugly and probably not what you want:
struct BinStream
{
std::ostream& os;
BinStream(std::ostream& os) : os(os) {}
template
BinStream& operator<<(T&& value)
{
os << value;
return *this;
}
BinStream& operator<<(int value)
{
os << binario(value);
return *this;
}
std::ostream& operator<<(std::ios_base& (__cdecl
*_Pfn)(std::ios_base&))
{
return os << _Pfn;
}
};
struct Bin
{
friend BinStream operator<<(std::ostream& os, const
Bin& f);
} bin;
BinStream operator<<(std::ostream& os, const Bin& f)
{
return BinStream(os);
}
int main()
{
std::cout << "\n\t127 em binario: " << binario(127)
<< "\n\t127 em binario: " << bin << 127
<< "\n\t127 em octal: " << std::oct << 127
<< "\n\t127 em binario: " << bin << 127
<< "\n\t127 em hexadecimal: " << std::hex << 127
<< "\n\t127 em binario: " << bin << 127
<< "\n\t127 em decimal: " << std::dec << 127
<< "\n\t127 em binario: " << bin << 127 << "\n\n";
}
What is this black magic? Instead of overriding how
std::ostream does formatting, Bin::Operator<< now returns a
wrapper around a std::ostream, which special cases ints. If it
gets any other format specifiers, it returns the ostream again,
and the binary formatting is gone.
All in all, I think the conclusion is: Stay with D.
--
Biotronic
I understand is basically this now I will see the necessity of
this basically the example I wanted to do is to understand how it
would be done in the most correct way, now I will study to do
other cases if nescessarios but primarily is to convert only
integers but you did exactly the that I wanted
I did some studies in the D language and it already has a way to
convert to binary without any work just using% b as in printf you
use% X or% x to convert to exa ... and that was the reason that
made me interested in understand this was looking at some older
glibc and the way printf understands these very interesting
conversion operators
operator overload
I know that this community is not of c ++, but some time I have been studying how to do overload of ostream operators in c ++ and I even managed to get to this result but the same is not converting to binary only presents zeros as output to any number already tried to pass parameter of variable and yet he is not getting the number for conversion how to solve it so that it works correctly? PS: if I use the same conversion algorithm in a function it converts normally it is not only converting to the output of the operator .. https://pastebin.com/BXGXiiRk
Re: no print function output do while
On Thursday, 28 September 2017 at 21:34:46 UTC, arturg wrote:
On Thursday, 28 September 2017 at 20:17:24 UTC, Ali Çehreli
wrote:
On 09/28/2017 12:18 PM, dark777 wrote:
On Thursday, 28 September 2017 at 18:46:56 UTC, Ali Çehreli
wrote:
On 09/28/2017 08:13 AM, dark777 wrote:
no print function output do while
in my program after entering the data and select the
function that will print on the screen the same is not
printing ..
and if I choose 'q' or 'Q' does the program not close what
is happening?
should not it work just like in C ++?
https://pastebin.com/iiMVPk4x
You made a simple logic error. Change the following || to &&:
}while(choice != 'q' || choice != 'Q');
Ali
I think it should not give this error
good but until now I do not understand why after I enter with
data in the function add_human
the same is not printed when I choose the 'p' or 'P' option
in the case
void print_list(Human[] human_list)
{
foreach(human; human_list)
{
writefln("\nNome: %s",human.name);
writefln("Peso: %0.2f",human.peso);
writefln("Idade: %d\n",human.age);
}
}
It's because add_human is appending to its own array. Change
it to by-ref:
void add_human(ref Human[] human_list)
Ali
while(choice != 'q' || choice != 'Q');
doesn't seem to exit the loop, while this works:
while(choice != 'q');
or
while(!(choice == 'q' || choice == 'Q'));
wouldn't it be better to use a labeled statement instead?
endless : while(true)
{
...
switch(choice)
{
...
case 'Q':
case 'q': break endless;
...
}
}
It's good that it worked out here.
Re: no print function output do while
On Thursday, 28 September 2017 at 18:46:56 UTC, Ali Çehreli wrote:
On 09/28/2017 08:13 AM, dark777 wrote:
no print function output do while
in my program after entering the data and select the function
that will print on the screen the same is not printing ..
and if I choose 'q' or 'Q' does the program not close what is
happening?
should not it work just like in C ++?
https://pastebin.com/iiMVPk4x
You made a simple logic error. Change the following || to &&:
}while(choice != 'q' || choice != 'Q');
Ali
I think it should not give this error
good but until now I do not understand why after I enter with
data in the function add_human
the same is not printed when I choose the 'p' or 'P' option in
the case
void print_list(Human[] human_list)
{
foreach(human; human_list)
{
writefln("\nNome: %s",human.name);
writefln("Peso: %0.2f",human.peso);
writefln("Idade: %d\n",human.age);
}
}
no print function output do while
no print function output do while in my program after entering the data and select the function that will print on the screen the same is not printing .. and if I choose 'q' or 'Q' does the program not close what is happening? should not it work just like in C ++? https://pastebin.com/iiMVPk4x
Re: Struct List Human
On Sunday, 24 September 2017 at 18:00:32 UTC, Adam D. Ruppe wrote:
I think readf("%s") reads everything available. readf(" %s\n")
might help but personally, I say avoid readf.
Just use readln and to!int instead
auto line = readln();
if(line.length == 0)
writeln("please enter a number");
age = to!int(line);
to is from import std.conv
I added \n and it worked.
I created a float variable and wanted to know how to read or
print the same?
reading?
write ("Weight:");
readf (" %ld\n", &peso);
and
writefln ("Weight:% ld", human.peso);
but he returned me errors
Re: Struct List Human
On Sunday, 24 September 2017 at 17:05:11 UTC, Neia Neutuladh wrote: On Sunday, 24 September 2017 at 16:13:30 UTC, dark777 wrote: when you execute and call Name: I type my name: Name: dark777 + [enter] and he does not jump to the next line to get the age This is what I want to know how to solve. Add a `writeln();` after reading input, maybe? I changed the write by writeln and it still did not work, I added it after receiving the first entry and it did not work ...
Re: Struct List Human
On Sunday, 24 September 2017 at 15:51:01 UTC, dark777 wrote: On Sunday, 24 September 2017 at 15:22:30 UTC, Suliman wrote: On Sunday, 24 September 2017 at 14:32:14 UTC, dark777 wrote: I have the following code: https://pastebin.com/PWuaXJNp but typing my name does not go to the next line as soon as I press enter how to solve this? use writeln instead write nothing to see hand when you execute and call Name: I type my name: Name: dark777 + [enter] and he does not jump to the next line to get the age This is what I want to know how to solve. nothing to see hand when you execute and call Name: I type my name: Name: dark777 + [enter] and he does not jump to the next line to get the age This is what I want to know how to solve.
Re: Struct List Human
On Sunday, 24 September 2017 at 15:22:30 UTC, Suliman wrote: On Sunday, 24 September 2017 at 14:32:14 UTC, dark777 wrote: I have the following code: https://pastebin.com/PWuaXJNp but typing my name does not go to the next line as soon as I press enter how to solve this? use writeln instead write nothing to see hand when you execute and call Name: I type my name: Name: dark777 + [enter] and he does not jump to the next line to get the age This is what I want to know how to solve.
Struct List Human
I have the following code: https://pastebin.com/PWuaXJNp but typing my name does not go to the next line as soon as I press enter how to solve this?
Re: erros em printf[AJUDA]
On Friday, 8 September 2017 at 23:04:07 UTC, kinke wrote:
On Friday, 8 September 2017 at 22:30:16 UTC, dark777 wrote:
ex3.d(19): Error: cannot pass dynamic arrays to extern(C)
vararg functions
printf("Writef Hello %.*s!\n", name.length, name.ptr);
puts por que é mais chato o printf aqui na linguagem D do que no
C?
erros em printf[AJUDA]
estava rodando este programa porem acrescentei o printf mas como
resolver o erro?
bash-4.4$ rdmd ex3
ex3.d(19): Error: cannot pass dynamic arrays to extern(C) vararg
functions
Failed: ["dmd", "-v", "-o-", "ex3.d", "-I."]
import std.stdio;
import std.string; //strip
import core.stdc.stdio;
//more informations: http://ddili.org/ders/d.en/strings.html
void main()
{
//char[] name;
write("What is your name? ");
//readln(name); //acept vector de char on input readln
//name = strip(name); //Hello String!← no new-line
character
string name = readln().strip(); // read string and no new
line strip
write("Write Hello ", name, "!\n");
printf("Writef Hello %s!\n", name);
writef("Writef Hello %s!\n", name);
writeln("Writeln Hello ", name, "!");
writefln("Writefln Hello %s!", name);
}
Re: D is Multiplatform[DUVIDA]
On Friday, 8 September 2017 at 03:56:25 UTC, rikki cattermole wrote: On 08/09/2017 3:08 AM, dark777 wrote: On Friday, 8 September 2017 at 00:09:08 UTC, solidstate1991 wrote: On Thursday, 7 September 2017 at 23:58:05 UTC, dark777 wrote: Good night, did you want to know this? Is the DE language cross-platform or cross-compile like C ++? GDC and LDC has multi-platform support, I'm currently working on an ARM backend for DMD. so does it mean that if I develop a program using the D language in BSD creating generic resources for example and compiling on windows, linux and darwin it would work fine? Each platform has its own unique behavior and related code. Gotta try it to know for certain. But that is unrelated to D in the most part :) but in any case then the D language can be considered multiplatform?
Re: D is Multiplatform[DUVIDA]
On Friday, 8 September 2017 at 00:09:08 UTC, solidstate1991 wrote: On Thursday, 7 September 2017 at 23:58:05 UTC, dark777 wrote: Good night, did you want to know this? Is the DE language cross-platform or cross-compile like C ++? GDC and LDC has multi-platform support, I'm currently working on an ARM backend for DMD. so does it mean that if I develop a program using the D language in BSD creating generic resources for example and compiling on windows, linux and darwin it would work fine?
D is Multiplatform[DUVIDA]
Good night, did you want to know this? Is the DE language cross-platform or cross-compile like C ++?
Re: Adding deprecated to an enum member
On Tuesday, 1 August 2017 at 01:12:28 UTC, Jeremy DeHaan wrote:
I got an error today because I added deprecated to an enum
member.
Is there a way to achieve this, or am I out of luck? If it
isn't doable, should it be?
Here's what I want:
enum PrimitiveType
{
Points,
Lines,
LineStrip,
Triangles,
TriangleStrip,
TriangleFan,
Quads,
deprecated("Use LineStrip instead.")
LinesStrip = LineStrip,
deprecated("Use TriangleStrip instead.")
TrianglesStrip = TriangleStrip,
deprecated("Use TriangleFan instead.")
TrianglesFan = TriangleFan
}
PrimitiveType ptype = LinesStrip; //error, Use LineStrip
instead.
I did as follows using deprecated may help you to elucidate in
relation to this
https://pastebin.com/NEHtWiGx
Csharp para Digital Mars D[AJUDA]
Eu tenho um projeto em windows form C# feito no virual studio um amigo meu e eu criamos para a semana academica ele faz cadastros e marca a presença das visitas na semana por um id de quem ja pagou pelas palestras queria portar ele para D. Que biblioteca para forms vcs me recomendam para desenvolver o mesmo? o que eu teria que dar mais atenção em Csharp para portar para a linguagem D? PS: ele é desktop mas faz redirecionamento para um banco de dados mysql para salvar os dados direto no servidor...
Re: criando modulos em D para classe pessoa[AJUDA]
On Monday, 24 July 2017 at 20:33:42 UTC, dark777 wrote:
On Monday, 24 July 2017 at 20:06:37 UTC, ag0aep6g wrote:
On 07/24/2017 09:45 PM, dark777 wrote:
principal.d(18): Error: octal literals 01023040 are no longer
supported, use std.conv.octal!1023040 instead
Failed: ["dmd", "-v", "-o-", "principal.d", "-I."]
[...]
https://pastebin.com/CYinHWyQ
From there:
e = new Endereco();
e.setCidade("São Paulo");
e.setCEP(01023040);
Google's translator says (from Portuguese):
Endereco = address,
Cidade = City,
CEP = ZIP code.
Don't store ZIP codes as numbers. Store them as strings.
Leading zeroes have meaning in ZIP codes. You don't do math on
ZIP codes.
deu certo aqui agora valeu ai..
Eu tenho um projeto em windows form C# feito no virual studio um
amigo meu e eu criamos para a semana academica ele faz cadastros
e marca a presença das visitas na semana por um id de quem ja
pagou pelas palestras queria portar ele para D. que biblioteca
para forms vcs me recomendam para desenvolver o mesmo? PS: ele é
desktop mas faz redirecionamento para um banco de dados mysql
para salvar os dados direto no servidor...
Re: criando modulos em D para classe pessoa[AJUDA]
On Monday, 24 July 2017 at 20:06:37 UTC, ag0aep6g wrote:
On 07/24/2017 09:45 PM, dark777 wrote:
principal.d(18): Error: octal literals 01023040 are no longer
supported, use std.conv.octal!1023040 instead
Failed: ["dmd", "-v", "-o-", "principal.d", "-I."]
[...]
https://pastebin.com/CYinHWyQ
From there:
e = new Endereco();
e.setCidade("São Paulo");
e.setCEP(01023040);
Google's translator says (from Portuguese):
Endereco = address,
Cidade = City,
CEP = ZIP code.
Don't store ZIP codes as numbers. Store them as strings.
Leading zeroes have meaning in ZIP codes. You don't do math on
ZIP codes.
deu certo aqui agora valeu ai..
criando modulos em D para classe pessoa[AJUDA]
pessoal eu tenho umas classes java e estava portando para D e para usar as importaçoes criei os modules nescessarios todos estao dentro da mesma pasta porem ao fazer: $rdmd principal ele retorna o seguinte erro: principal.d(18): Error: octal literals 01023040 are no longer supported, use std.conv.octal!1023040 instead Failed: ["dmd", "-v", "-o-", "principal.d", "-I."] Os codigos sao os que estao abaixo no pastebin https://pastebin.com/CYinHWyQ
Re: char e string em linguagem D
On Thursday, 13 July 2017 at 22:30:29 UTC, crimaniak wrote:
On Thursday, 13 July 2017 at 21:49:40 UTC, dark777 wrote:
Pessoal eu fiz o seguinte programa em C++.
https://pastebin.com/CvVv6Spn
porem tentei fazer o equivalente em D mas nao entendi muito
bem...
https://pastebin.com/2xw9geRR
alguem poderia me ajudar?
Se acepta utilizar intervalos en lugar de punteros desnudos.
(Hola, soy traductor de google)
import std.stdio, std.string;
//https://www.vivaolinux.com.br/script/GNU-que-bacana
class GnuQueBacana
{
this(){}
char[] stalman()
{
return cast(char[])`
((__-^^-,-^^-__))
*---***---*
*--|o o|--*
\ /
): :(
(o_o)
-
https://www.gnu.org
`;
}
char[] torvald()
{
return cast(char[])`
#
###
##O#O##
###
##\#/##
#lll##
#l##
#l###
#####
OOO#ll#OOO
OO#ll#OO
OOO#ll#OOO
OOO##OOO
https://www.kernel.org
`;
}
string stallman()
{
return `
((__-^^-,-^^-__))
*---***---*
*--|o o|--*
\ /
): :(
(o_o)
-
https://www.gnu.org
`;
}
string torvalds()
{
return `
#
###
##O#O##
###
##\#/##
#lll##
#l##
#l###
#####
OOO#ll#OOO
OO#ll#OO
OOO#ll#OOO
OOO##OOO
https://www.kernel.org
`;
}
};
void main()
{
GnuQueBacana gnu = new GnuQueBacana();
writeln(gnu.stalman(), gnu.torvald(), gnu.stallman(),
gnu.torvalds());
}
muito massa nao achei que era tao simples assim..
char e string em linguagem D
Pessoal eu fiz o seguinte programa em C++. https://pastebin.com/CvVv6Spn porem tentei fazer o equivalente em D mas nao entendi muito bem... https://pastebin.com/2xw9geRR alguem poderia me ajudar?
