Template type reduction
Suppose I have a templated type like
struct S(T) { int x; static if (T is Y) int y; }
I would like to be able to create a reference to S(T) for any T,
struct Q
{
S!* s; // Can hold any type of S.
}
and be able to access s.x, since it is common to all S.
Can D do anything like this? It is sort of like runtime
inheritance, but at the compile time level.
I do not want to have to cast to S!T every time just to access x,
e.g.,
struct Q
{
Object s;
}
which is too general as s can be things that are not of type S!*.
Is this possible?
Re: Template type reduction
On 8/15/16 3:31 PM, Engine Machine wrote:
Suppose I have a templated type like
struct S(T) { int x; static if (T is Y) int y; }
I would like to be able to create a reference to S(T) for any T,
struct Q
{
S!* s; // Can hold any type of S.
}
and be able to access s.x, since it is common to all S.
Can D do anything like this? It is sort of like runtime inheritance, but
at the compile time level.
I don't think so. You'd have to cast, as the compiler doesn't have any
understanding that all S instantiations will have an x member.
I do not want to have to cast to S!T every time just to access x, e.g.,
struct Q
{
Object s;
}
which is too general as s can be things that are not of type S!*.
This seems odd. You will lose the type information for s if you were to
succeed. Might as well just store an int.
Seems like what you want is a variant or some other kind of tagged union.
-Steve
Re: Template type reduction
On Monday, 15 August 2016 at 19:40:37 UTC, Steven Schveighoffer
wrote:
On 8/15/16 3:31 PM, Engine Machine wrote:
Suppose I have a templated type like
struct S(T) { int x; static if (T is Y) int y; }
I would like to be able to create a reference to S(T) for any
T,
struct Q
{
S!* s; // Can hold any type of S.
}
and be able to access s.x, since it is common to all S.
Can D do anything like this? It is sort of like runtime
inheritance, but
at the compile time level.
I don't think so. You'd have to cast, as the compiler doesn't
have any understanding that all S instantiations will have an x
member.
This is a problem. How can I cast to something I don't know?
I do not want to have to cast to S!T every time just to access
x, e.g.,
struct Q
{
Object s;
}
which is too general as s can be things that are not of type
S!*.
This seems odd. You will lose the type information for s if you
were to succeed. Might as well just store an int.
Seems like what you want is a variant or some other kind of
tagged union.
No, what I want is a type that is the intersection of all the
types it can be.
The problem is I cannot cast because the type is complex and I
don't know the exact signature, but I do know that it has a basic
type embedded in it.
enum Types
{
Int, Word, Complex
}
struct MyType(string name, Types type, Args...)
{
string Name = name;
Types Type = type;
static if (type == Int) int val;
static if (type == word) ushort val;
static if (type == Complex) { ... };
}
So, how can I get val? I know if it is an int or a word, val
exists. But I can't specify the name or type at runtime to get at
the innards of the type.
Object o = MyType!("test", Types.Int);
Useless! I can never retrieve anything from o. I can't cast it
back. Yet I know that o has a name and a type and possibly a val
if I know the type... and I know all this at compile time. Yet D
doesn't seem to allow me to use this information.
I know one will say use either oop or constructors, but neither
of these are appropriate(although constructors are close). What I
need is a type constructor, which bridges the gap. This is how I
am using the data above, to construct the object, but D treats it
as part of the type, which I don't what.
I guess I will have to use string mixins to construct the types
properly ;/ What a pain in the ass ;/
Re: Template type reduction
On 8/16/16 12:33 AM, Engine Machine wrote:
On Monday, 15 August 2016 at 19:40:37 UTC, Steven Schveighoffer wrote:
On 8/15/16 3:31 PM, Engine Machine wrote:
Suppose I have a templated type like
struct S(T) { int x; static if (T is Y) int y; }
I would like to be able to create a reference to S(T) for any T,
struct Q
{
S!* s; // Can hold any type of S.
}
and be able to access s.x, since it is common to all S.
Can D do anything like this? It is sort of like runtime inheritance, but
at the compile time level.
I don't think so. You'd have to cast, as the compiler doesn't have any
understanding that all S instantiations will have an x member.
This is a problem. How can I cast to something I don't know?
First, you have to store it somehow. I don't really know the way you can
do this without a union or a Variant.
Then you can cast it to any concrete version of S, they all have an x
member.
I do not want to have to cast to S!T every time just to access x, e.g.,
struct Q
{
Object s;
}
which is too general as s can be things that are not of type S!*.
This seems odd. You will lose the type information for s if you were
to succeed. Might as well just store an int.
Seems like what you want is a variant or some other kind of tagged union.
No, what I want is a type that is the intersection of all the types it
can be.
Then you want std.variant.Variant. That's the only type that can change
types at runtime.
The problem is I cannot cast because the type is complex and I don't
know the exact signature, but I do know that it has a basic type
embedded in it.
enum Types
{
Int, Word, Complex
}
struct MyType(string name, Types type, Args...)
{
string Name = name;
Types Type = type;
static if (type == Int) int val;
static if (type == word) ushort val;
static if (type == Complex) { ... };
}
So, how can I get val? I know if it is an int or a word, val exists. But
I can't specify the name or type at runtime to get at the innards of the
type.
You need to know the type. Otherwise, how will the compiler be able to
reserve enough space for it? Variant works by having enough space to
store most things, and then boxes if it gets bigger.
With Variant, you can type stored at runtime.
Object o = MyType!("test", Types.Int);
Note that structs are not Objects. There is no base type for structs.
Useless! I can never retrieve anything from o. I can't cast it back. Yet
I know that o has a name and a type and possibly a val if I know the
type... and I know all this at compile time. Yet D doesn't seem to allow
me to use this information.
I know one will say use either oop or constructors, but neither of these
are appropriate(although constructors are close). What I need is a type
constructor, which bridges the gap. This is how I am using the data
above, to construct the object, but D treats it as part of the type,
which I don't what.
In D, structs are not inheritable. You really do need polymorphism for
this. I don't know you reason for rejecting classes, but I would
recommend that. Or use Variant.
-Steve
Re: Template type reduction
On Monday, 15 August 2016 at 19:31:14 UTC, Engine Machine wrote:
Suppose I have a templated type like
struct S(T) { int x; static if (T is Y) int y; }
I would like to be able to create a reference to S(T) for any T,
struct Q
{
S!* s; // Can hold any type of S.
}
and be able to access s.x, since it is common to all S.
Can D do anything like this? It is sort of like runtime
inheritance, but at the compile time level.
I do not want to have to cast to S!T every time just to access
x, e.g.,
struct Q
{
Object s;
}
which is too general as s can be things that are not of type
S!*.
Is this possible?
I don't know if this is exactly what you want:
=
import std.traits: hasMember;
struct Q(T)
if (hasMember!(T, "x"))
{
T s;
@property auto x() { return s.x; }
}
auto makeQ(T)(auto ref T val)
{
return Q!T(val);
}
auto s = myTypeWithFieldX();
auto q = makeQ(s);
assert(q.x == s.x);
=
`Q` can store any type with an `x` field and gives access to it.
The auxiliary function `makeQ` acts as a constructor for `Q` with
template parameter deduction.
Re: Template type reduction
On Tuesday, 16 August 2016 at 17:39:14 UTC, Lodovico Giaretta
wrote:
On Monday, 15 August 2016 at 19:31:14 UTC, Engine Machine wrote:
Suppose I have a templated type like
struct S(T) { int x; static if (T is Y) int y; }
I would like to be able to create a reference to S(T) for any
T,
struct Q
{
S!* s; // Can hold any type of S.
}
and be able to access s.x, since it is common to all S.
Can D do anything like this? It is sort of like runtime
inheritance, but at the compile time level.
I do not want to have to cast to S!T every time just to access
x, e.g.,
struct Q
{
Object s;
}
which is too general as s can be things that are not of type
S!*.
Is this possible?
I don't know if this is exactly what you want:
=
import std.traits: hasMember;
struct Q(T)
if (hasMember!(T, "x"))
{
T s;
@property auto x() { return s.x; }
}
auto makeQ(T)(auto ref T val)
{
return Q!T(val);
}
auto s = myTypeWithFieldX();
auto q = makeQ(s);
assert(q.x == s.x);
=
`Q` can store any type with an `x` field and gives access to
it. The auxiliary function `makeQ` acts as a constructor for
`Q` with template parameter deduction.
The only problem is Q is still defined by T. Your makeQ then
requires the type implicitly, which I don't necessarily have.
You've simply added complexity to the problem but the issue is
still there.
I realize now that D simply cannot do what I ask directly because
It's type parameters are part of the type. It can't be told that
in some cases they are not. Any use of the parameters, as I am
using them, will result in this issue.
I'm now trying a different method which builds the based types
using partial oop and partial CT code. The CT code is only for
performance and convenience anyways.
Re: Template type reduction
On Tuesday, 16 August 2016 at 19:23:51 UTC, Engine Machine wrote:
On Tuesday, 16 August 2016 at 17:39:14 UTC, Lodovico Giaretta
wrote:
On Monday, 15 August 2016 at 19:31:14 UTC, Engine Machine
wrote:
[...]
I don't know if this is exactly what you want:
=
import std.traits: hasMember;
struct Q(T)
if (hasMember!(T, "x"))
{
T s;
@property auto x() { return s.x; }
}
auto makeQ(T)(auto ref T val)
{
return Q!T(val);
}
auto s = myTypeWithFieldX();
auto q = makeQ(s);
assert(q.x == s.x);
=
`Q` can store any type with an `x` field and gives access to
it. The auxiliary function `makeQ` acts as a constructor for
`Q` with template parameter deduction.
I realize now that D simply cannot do what I ask directly
because It's type parameters are part of the type. It can't be
told that in some cases they are not. Any use of the
parameters, as I am using them, will result in this issue.
I'm now trying a different method which builds the based types
using partial oop and partial CT code. The CT code is only for
performance and convenience anyways.
You are right in that it is not possible to strip part of the
type informations.
The only problem is Q is still defined by T. Your makeQ then
requires the type implicitly, which I don't necessarily have.
You've simply added complexity to the problem but the issue is
still there.
How is it possible that you don't have T? Your variable will
surely have a type! Can you provide more background? Because
maybe I'm not completely getting your point here...
