Using named groups from choices

[Timbadu]

I'm trying to use the named group from nested choices in my model as
part of the url.
I currently have:

model.py
class Project(models.Model):
PROJECT_CHOICES = (
('Residential', (
('public', 'Public Houses'),
('private', 'Private Houses'),
('extensions', 'Extensions'),
)
 ('Public', (
  
)

type = models.CharField(max_length=1, choices=PROJECT_CHOICES)
title = models.CharField(max_length=100, verbose_name="Project Name",
unique=True)

def get_absolute_url(self):
return "/projects/%s/%s/" % (self.type, self.title)

This works but I'd like to use the named group to produce urls like:
.../projects/residential/private/boldt-castle

Obviously, I can do this manually but there should be a way of
accessing the named group

Thanks.

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Simple 'static' sitemap

[Timbadu]

For anyone looking for the most basic "static" sitemap you could use:

Views.
def dlsitemap(request):
sitemap_data = open('path/to/templates/sitemap.xml',).read()
return HttpResponse(sitemap_data, mimetype="text/xml")

URLS
(r'^sitemap\.xml$', 'dlsitemap'),

All the examples I found where for dynamic sitemaps.
(Please correct any errors)
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Re: Simple Sitemap

[Timbadu]

Thanks Adam.

I've had a look at the django.contrib.sitemaps process but all
examples I've found relate to dynamic sitemaps created for ever
changing blogs etc.
Most of the info gives an example of a file to create but not what to
call it or where to put it.
So, using my limited knowledge of django and python i cobble something
together and get
... an Unhandled exception.
Arg.



On 12 Oct, 20:30, Adam N <a...@varud.com> wrote:
> You might as well use django.contrib.sitemaps.
>
> It's not difficult to use that app so there's no more efficient way to
> do this unless you happen to have the sitemaps.xml file already.
>
> On Oct 12, 11:32 am, Timbadu <t...@soundslikedesign.co.uk> wrote:
>
> > I need a simple sitemap for 5 URLs. The django sitemaps app seams a
> > bit overkill for such a simple xml file.
> > What's the best way of doing this?
> > Can i simply upload a sitemaps.xml and point to it?
> > Or should i use the django.contrib.sitemaps?
>
> > Thanks,
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Simple Sitemap

[Timbadu]

I need a simple sitemap for 5 URLs. The django sitemaps app seams a
bit overkill for such a simple xml file.
What's the best way of doing this?
Can i simply upload a sitemaps.xml and point to it?
Or should i use the django.contrib.sitemaps?

Thanks,
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Re: meta or QuerySet - I don't know

[Timbadu]

Thanks Tim,

I wrapped it in a div and daisy-chained some filters so as to allow
the js file find the class tags.

  {% for genre in genre_list %}
  
{{ genre.genre_type }}

{% for credit in genre.credit_set.all %}
{{ credit.title }}
{% endfor %}


{% endfor %}
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meta or QuerySet - I don't know

[Timbadu]

Hi folks,

(New to databasing)

I'm looking for a solution for presenting MySQL.
I want to display my data grouped by a colmn value in the MySQL table.
So my model is:

from django.db import models

class Genre(models.Model):
genre_type = models.CharField(max_length=40)
def __unicode__(self):
return self.genre_type

class Credit(models.Model):
date = models.DateField()
title = models.CharField(max_length=80)
company = models.CharField(max_length=80, blank=True, null=True)
genre = models.ForeignKey(Genre)
underwater = models.BooleanField('Underwater credit')
latest_tag = models.BooleanField('Display as recent credit')
def __unicode__(self):
return self.title

I want to extract all the "credits" and group them into genre and
display them inside a div with h5 both showing the genre:


Commercials

Lidl
Flybe
Arnold Clark
Wholesale Domestic
Evening Times
Daily Record


to look like this:
http://www.davidlees.tv/lightingcameraman/

I've tried all sorts of stuff in my views.py file and it wont work.
Any help or pointers would be great. Thanks
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Tutorial 3 templates

[Timbadu]

Hi folks,

I'm working throu the Django Tutorials and am on no. 3.

No matter where I put my 404.html and 500.html template files I am
always getting this traceback:

Traceback (most recent call last):

  File "C:\Python26\lib\site-packages\django\core\servers
\basehttp.py", line 278, in run
self.result = application(self.environ, self.start_response)

  File "C:\Python26\lib\site-packages\django\core\servers
\basehttp.py", line 635, in __call__
return self.application(environ, start_response)

  File "C:\Python26\lib\site-packages\django\core\handlers\wsgi.py",
line 239, in __call__
response = self.get_response(request)

  File "C:\Python26\lib\site-packages\django\core\handlers\base.py",
line 116, in get_response
return self.handle_uncaught_exception(request, resolver,
sys.exc_info())

  File "C:\Python26\lib\site-packages\django\core\handlers\base.py",
line 160, in handle_uncaught_exception
return callback(request, **param_dict)

  File "C:\Python26\lib\site-packages\django\views\defaults.py", line
23, in server_error
t = loader.get_template(template_name) # You need to create a
500.html template.

  File "C:\Python26\lib\site-packages\django\template\loader.py", line
80, in get_template
source, origin = find_template_source(template_name)

  File "C:\Python26\lib\site-packages\django\template\loader.py", line
73, in find_template_source
raise TemplateDoesNotExist, name

TemplateDoesNotExist: 500.html

I've been strugglin with this for a while now but can't work it out.
Can anyone see what I'm doing wrong?

Thanks,
Tim

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