Re: Configure multi-field multi-select form in Django Admin
Tim, Thanks for the response. That is what I was looking for. I got it working now, just needed a little hint. Found the User Admin stuff (in contrib) and was able to follow that. As far as the "id" columns.I adapted Django to an existing system so that is why the models don't necessarily match the Django norm. Reed On Nov 24, 7:41 pm, Tim Valenta wrote: > > The javascript will be found somewhere under django/contrib/admin/media/js. > > To be clear, rc, although the javascript is of course available for > viewing, you should only need to put that attribute > "filter_horizontal" on your ModelAdmin. There shouldn't be any need > for inserting any custom javascript commands anywhere. That one > attribute does it all. > > And... this might pose a problem, but I don't see any ManyToManyFields > in your models. It won't work unless you're using those, instead of > ForeignKeys. > > For the extra mile, you shouldn't need those various "_id = > models.AutoField(primary_key=True)" parts. Django does that > automatically, but names each one just "id", instead of "[modelname] > _id". Unless you specifically want them to be named differently than > "id", you don't have to specify it, which helps it be more readable. > But it's of course your own project :) Do it however you wish! > > Tim > > On Nov 24, 6:01 pm, Karen Tracey wrote: > > > On Tue, Nov 24, 2009 at 12:32 PM, rc wrote: > > > As I mentioned, the Django admin has exactly what I want with the user > > > permission form (auth_user, auth_permissions and > > > auth_user_user_permission). Does anyone know where that code is > > > located in the Django environment? > > > That's done with javascript, activated by listing the fields in: > > >http://docs.djangoproject.com/en/dev/ref/contrib/admin/#django.contri... > > > The javascript will be found somewhere under django/contrib/admin/media/js. > > > Karen -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
Re: Configure multi-field multi-select form in Django Admin
> The javascript will be found somewhere under django/contrib/admin/media/js. To be clear, rc, although the javascript is of course available for viewing, you should only need to put that attribute "filter_horizontal" on your ModelAdmin. There shouldn't be any need for inserting any custom javascript commands anywhere. That one attribute does it all. And... this might pose a problem, but I don't see any ManyToManyFields in your models. It won't work unless you're using those, instead of ForeignKeys. For the extra mile, you shouldn't need those various "_id = models.AutoField(primary_key=True)" parts. Django does that automatically, but names each one just "id", instead of "[modelname] _id". Unless you specifically want them to be named differently than "id", you don't have to specify it, which helps it be more readable. But it's of course your own project :) Do it however you wish! Tim On Nov 24, 6:01 pm, Karen Tracey wrote: > On Tue, Nov 24, 2009 at 12:32 PM, rc wrote: > > As I mentioned, the Django admin has exactly what I want with the user > > permission form (auth_user, auth_permissions and > > auth_user_user_permission). Does anyone know where that code is > > located in the Django environment? > > That's done with javascript, activated by listing the fields in: > > http://docs.djangoproject.com/en/dev/ref/contrib/admin/#django.contri... > > The javascript will be found somewhere under django/contrib/admin/media/js. > > Karen -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
Re: Configure multi-field multi-select form in Django Admin
On Tue, Nov 24, 2009 at 12:32 PM, rc wrote: > As I mentioned, the Django admin has exactly what I want with the user > permission form (auth_user, auth_permissions and > auth_user_user_permission). Does anyone know where that code is > located in the Django environment? > > That's done with javascript, activated by listing the fields in: http://docs.djangoproject.com/en/dev/ref/contrib/admin/#django.contrib.admin.ModelAdmin.filter_horizontal The javascript will be found somewhere under django/contrib/admin/media/js. Karen -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
Re: Configure multi-field multi-select form in Django Admin
As I mentioned, the Django admin has exactly what I want with the user permission form (auth_user, auth_permissions and auth_user_user_permission). Does anyone know where that code is located in the Django environment? On Nov 24, 10:13 am, rc wrote: > What I want to do is have a form with one field that allows you to > select a profile. Once this profile is selected there will be two > windows below that show available tests and selected tests. The Django > admin interface for the user permissions uses this format. Not sure > what it is called in Django. > > My current models are listed below. I have a joining table called > Testsuite that joins tests to profiles. It works now, but the admin is > not very easy to add or remove tests to a testsuite since you have to > add one at a time. If someone can point me in the right direction I > would appreciate it. > > Anyway I have the following models: > --- > Models > -- > > class Profile(models.Model): > profile_id = models.AutoField(primary_key=True) > profile_name = models.CharField(max_length=75) > description = models.CharField(max_length=1500, blank=True) > def __unicode__(self): > return self.profile_name > class Meta: > db_table = u'profile' > > class Testcase(models.Model): > test_id = models.AutoField(primary_key=True) > test_name = models.CharField(max_length=300) > src = models.ForeignKey(Source, null=True, blank=True) > bitrate = models.IntegerField(null=True, blank=True) > test_type = models.CharField(max_length=300) > output_resolution = models.CharField(max_length=15, blank=True) > description = models.CharField(max_length=3000, blank=True) > ref_file = models.CharField(max_length=765, blank=True) > ref_encode_filesize = models.IntegerField(null=True, blank=True) > ref_y_psnr = models.DecimalField(null=True, max_digits=7, > decimal_places=2, blank=True) > ref_u_psnr = models.DecimalField(null=True, max_digits=7, > decimal_places=2, blank=True) > ref_v_psnr = models.DecimalField(null=True, max_digits=7, > decimal_places=2, blank=True) > ref_yuv_psnr = models.DecimalField(null=True, max_digits=7, > decimal_places=2, blank=True) > highmark_version = models.CharField(max_length=60, blank=True) > def __unicode__(self): > return self.test_name > class Meta: > db_table = u'testcase' > > class Testsuite(models.Model): > testsuite_id = models.AutoField(primary_key=True) > profile = models.ForeignKey(Profile, related_name='profile') > test = models.ForeignKey(Testcase, related_name='test') > #def __unicode__(self): > # return > self.testsuite_id > def __unicode__(self): > return '%s,%s' % (self.profile, self.test) > class Meta: > db_table = u'testsuite' -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
Configure multi-field multi-select form in Django Admin
What I want to do is have a form with one field that allows you to select a profile. Once this profile is selected there will be two windows below that show available tests and selected tests. The Django admin interface for the user permissions uses this format. Not sure what it is called in Django. My current models are listed below. I have a joining table called Testsuite that joins tests to profiles. It works now, but the admin is not very easy to add or remove tests to a testsuite since you have to add one at a time. If someone can point me in the right direction I would appreciate it. Anyway I have the following models: --- Models -- class Profile(models.Model): profile_id = models.AutoField(primary_key=True) profile_name = models.CharField(max_length=75) description = models.CharField(max_length=1500, blank=True) def __unicode__(self): return self.profile_name class Meta: db_table = u'profile' class Testcase(models.Model): test_id = models.AutoField(primary_key=True) test_name = models.CharField(max_length=300) src = models.ForeignKey(Source, null=True, blank=True) bitrate = models.IntegerField(null=True, blank=True) test_type = models.CharField(max_length=300) output_resolution = models.CharField(max_length=15, blank=True) description = models.CharField(max_length=3000, blank=True) ref_file = models.CharField(max_length=765, blank=True) ref_encode_filesize = models.IntegerField(null=True, blank=True) ref_y_psnr = models.DecimalField(null=True, max_digits=7, decimal_places=2, blank=True) ref_u_psnr = models.DecimalField(null=True, max_digits=7, decimal_places=2, blank=True) ref_v_psnr = models.DecimalField(null=True, max_digits=7, decimal_places=2, blank=True) ref_yuv_psnr = models.DecimalField(null=True, max_digits=7, decimal_places=2, blank=True) highmark_version = models.CharField(max_length=60, blank=True) def __unicode__(self): return self.test_name class Meta: db_table = u'testcase' class Testsuite(models.Model): testsuite_id = models.AutoField(primary_key=True) profile = models.ForeignKey(Profile, related_name='profile') test = models.ForeignKey(Testcase, related_name='test') #def __unicode__(self): # return self.testsuite_id def __unicode__(self): return '%s,%s' % (self.profile, self.test) class Meta: db_table = u'testsuite' -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
