Re: [EM] Proportional Representation from Ratings Ballots

2009-11-19 Thread Raph Frank
On Thu, Nov 19, 2009 at 4:51 AM, Brian Olson b...@bolson.org wrote:
 Oh, that is a problem. It gets the right answer if I use L1 norm instead of
 L2. I think L2 norm is going to work better for single-seat IRNR but L1 norm
 better for multi-seat. L2 inflates the amount of vote that winds up getting
 applied to multiple choices.

The L1 norm mean that each voter always gets to cast exactly 1 vote
(ratings add to 1).  Thus the total number of votes cast is always
constant.  This means that a quota can be easily determined.

You could use a different rule for eliminating than you use for
electing (and I think that is a good idea anyway).

For example, for electing, each ballot is scaled so that

w(a)*r(a) + w(b)*r(b) + . = 1

All eliminated candidates have a w(x) = 0 and all non-elected
candidates have a weighting of 1.
Elected candidates have weighting so that they have exactly a quota of
the votes.

If any candidate meets the Droop quota, that candidate is declared
elected and the next round is started.

If no candidate is elected, a different rule is used, each ballot is
scaled so that

[w(a)*r(a)]^2 + [w(b)*r(b)]^2 + ... = 1

The running candidate the the lowest score is then eliminated.

(The weights are based on the L1 calculation)

This process has the nice feature that a group of voters equal to a
Droop quota will decide their candidate using the L2 single seat (L2)
version of the process.  (This assumes that they rate all non-party
candidates at zero and all voters outside the group rate their
candidates at zero).

Also, there is also a question if the weights assigned in step 1 will
always yield a unique set of weights.  Hopefully there is a Meek's
method like proof.

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Re: [EM] Proportional Representation from Ratings Ballots

2009-11-19 Thread Raph Frank
Stealing the Meek's method proof :).

This is the existance proof:

A weighting vector is defined as feasible if all elected candidates
have a score = the quota (Q)

A candidate receives from each ballot (B) a score (S) equal to
 S(B) = r(c)*w(c)/(sum_over_x(r(x)*w(x))

r(x) is the rating for the candidate on that ballot
w(x) is the global weighting of that candidate

The candidate's total T(c) is the sum of the vote received from each ballot

Theorom: Replacing an elected candidate's weight by w(c)*k will not
convert a feasible vector into an non-feasible one, if k=Q/T(c)

Proof:  The candidate will receive from each ballot

 S_new(B) = r(c)*w_new(c)/(sum_over_x(r(x)*w_new(x))

Only 1 term has changed in the sum

Since w_old(x) = w_new(c) and r(c) = 0, then the sum cannot increase, i.e.

sum_over_x(r(x)*w_new(x)) = sum_over_x(r(x)*w_old(x))

Thus,

S_new(B) = r(c)*w_new(c)/(sum_over_x(r(x)*w_old(x))

replacing w_new(c) with w_old(c)*k as required, gives

S_new(B) = r(c)*w_old(c)*k/(sum_over_x(r(x)*w_old(x))

Re-arranging:

S_new(B) = k*[r(c)*w_old(c)/(sum_over_x(r(x)*w_old(x))

S_new(B) = k*S_old(B)

Thus, the candidate will receive form each ballot a score that is at
least k times as large as before the change.

Thus,

T_new(c) = T_old(c)*k

Assuming, k=Q/T_old(c)

T_new(c) = T_old(c)*[Q/T_old(c)]

T_new(c) = Q

Thus, the candidate in question who had his weighting decreased will
still have at least a quota.  All other candidates will at worst have
their vote totals
remain static, and will likely increase.  (The same proof, except
their weight doesn't actually decrease).

This means that if the vector was feasible initially, then it will
still be feasible after updating the weight of candidate c.

This means that the process can be applied over and over.  In each
step, the weighting of one of the elected candidates will be
decreased, but never increase.  This means that the total vote held by
the elected candidates will decrease.

This also gives an algorithm.  You can apply that rule to each elected
candidate in turn.

In fact, you can update them all in 1 go (set a weights w(c) = Q/T(c)
for elected candidates).  If you update them in order, then all the
other candidate's who haven't being reduced yet will have totals that
will have increased slightly (or stayed the same).  Thus, k = Q/T(c)
for all the other candidates will drop (or stay the same).

If you use the k from before the update, it will still be greater or
equal to the k that would have been used if they were done in order,
which is all that is required.

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Re: [EM] Proportional Representation from Ratings Ballots

2009-11-19 Thread Raph Frank
On Thu, Nov 19, 2009 at 12:49 PM, Raph Frank raph...@gmail.com wrote:
 If no candidate is elected, a different rule is used, each ballot is
 scaled so that

 [w(a)*r(a)]^2 + [w(b)*r(b)]^2 + ... = 1

 The running candidate the the lowest score is then eliminated.

Stage 1, (Election stage) select k1 so that

k1*[ w(a)*r(a) + w(b)*r(b) + . ] = 1

Each candidate gets

k1*w(x)*r(x)

Stage 2, (Elimination stage) select k2 so that

k2*(w(c)*r(c)^2 + w(d)*r(d)^2 + ... ) = 1 - k1*[w(a)*r(a) + w(b)*r(b)]

Each candidate gets

k2*w(x)*r(x)^2

Eliminate the remaining candidate who scores the lowest.

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Re: [EM] Dectecting Clone Sets

2009-11-19 Thread Juho

On Nov 18, 2009, at 11:33 PM, fsimm...@pcc.edu wrote:


How's this for making Kemeny clone free?

Ballots are ordinal with equal rankings and truncation allowed.

The distance between two candidates is the number of ballots on  
which they are
distinguished, i.e. one ranked and one not, or both ranked but not  
equal.


In normal Kemeny the distance between two ballots is the minimum  
number of
transpositions to convert one ballot into the other.  My suggestion  
is to modify
this count by giving each transposition a weight proportional to the  
distance

between the two candidates involved.

The Kemeny order is the permutation of the candidates whose average  
Kemeny
distance to the ballots is minimum.  I claim that if the suggested  
modified

Kemeny distance is used, then the method is clone free.


How about this example.

1: AB
1: BA
= a tie

1: A1A2B
1: BA1A2

It seems that the method elects now A1. Introduction of a clone would  
thus change the balance. Did I get the definition right? (= for each  
vote if some pair is not ordered right in the result then add as many  
points as the distance between the candidates is in this vote)




Kemeny is NP hard because there are so many permutations to check,  
not because

the distances are hard to calculate.

So I suggest that various standard permutations always be checked  
along with
each ballot order, as well as as many other orders as anybody wants  
to nominate.


Yes, it'd be easy to allow anyone to run some generic optimization  
procedures themselves and propose solutions (also and maybe especially  
after the votes are already known). The official calculation  
procedure could also use some monte carlo optimization and thus  
include also whatever random permutations. It would be enough to  
define the criterion that can be used to identify the best result and  
accept any methods to be used to find it (also to make sure that the  
best result will not fall outside of the accepted calculation rules).


Juho




The ballot orders that have truncations or equal rankings should be  
completed in
various ways (for this purpose only, not for use in the distance or  
average
distance computations) if a complete ordering of the candidates is  
desired.


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Re: [EM] Another auto districting proposal (Crystal districting?)

2009-11-19 Thread Juho

On Nov 19, 2009, at 5:35 PM, Kristofer Munsterhjelm wrote:


Juho wrote:
Well, this approach is also complex in the sense that the general  
optimization algorithms may be as complex as you want, but the  
optimization algorithms are totally independent of the politics and  
the basic rules that determine what the final outcome should be  
(the criterion) can be quite simple and intuitive.
(Additional criteria like favouring border lines that follow the  
borders of states or rivers etc. can be easily included in the  
agreed criterion. Maybe even higher cost of splitting cities etc.)


Splitline works because it's recursive. Any sort of divison  
algorithm where you can smoothly control the relative sizes of the  
two districts will work, also. Just subdivide into two, then freeze  
one and subdivide the other. After you're done, unfreeze the first  
(and so on). It may not produce the best result if the borders can  
move on the unfrozen areas, but should work.


As for general optimization, if you're dealing with an election  
method, then the optimization's approximation to the optimum (you  
can't ensure it'll reach the true optimum if there are multiple  
local optima and no additional structure) becomes a different rule  
itself. For instance, Borda is a 5-approximation to the optimal  
Kemeny ordering, but Borda is a completely different method from  
Kemeny.


If you're dealing with redistricting, the competition solution that  
you mentioned could work, but it might well be that, for  
redistricting, capturing the exact tradeoff between looking like  
communities of interest and being completely neutral is a task  
best left to an independent commission. Of course, one can also  
dissolve the problem rather than solve it, and employ some PR method  
which would greatly diminish the incentive to do any gerrymandering  
in the first place.


My thinking is that it might be easier to agree about the targets  
rather than the whole procedure. The targets can be simpler to define.  
Following Raph Franks model it would be thus enough to say that any N  
points and the kn values and then derive the border lines and the  
jointly agreed value of the solution from this data. That would not  
leave much space for strategies and gerrymandering. The proposed  
solutions would be evaluated and the one with best value would be  
declared the winner.


The optimization procedures may not find the global optimum (but only  
one of the local optima), but if there is an algorithm that can find  
the global optimum then that solution will also be found. It is  
possible that some party (that runs some optimization procedures)  
would not publish the best solution it found (since the second best is  
better to this party) but the field would be free for anyone else to  
find that even better result. At some point one must freeze the  
solution and ignore any better solution that someone might find later.  
In most cases I guess it is quite improbable that better solutions  
would be found later. And if they are found then they might not be  
much better (probably true for most sensible criteria). No rules are  
needed for the optimization algorithm (= just let the scientists and  
politicians and private citizens do their best + maybe arrange some  
official calculations too to make sure that at least someone makes a  
serious attempt to find the best solution).


Juho





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Re: [EM] Another auto districting proposal (Crystal districting?)

2009-11-19 Thread Kristofer Munsterhjelm

Juho wrote:
Well, this approach is also complex in the sense that the general 
optimization algorithms may be as complex as you want, but the 
optimization algorithms are totally independent of the politics and the 
basic rules that determine what the final outcome should be (the 
criterion) can be quite simple and intuitive.


(Additional criteria like favouring border lines that follow the borders 
of states or rivers etc. can be easily included in the agreed criterion. 
Maybe even higher cost of splitting cities etc.)


Splitline works because it's recursive. Any sort of divison algorithm 
where you can smoothly control the relative sizes of the two districts 
will work, also. Just subdivide into two, then freeze one and subdivide 
the other. After you're done, unfreeze the first (and so on). It may not 
produce the best result if the borders can move on the unfrozen areas, 
but should work.


As for general optimization, if you're dealing with an election method, 
then the optimization's approximation to the optimum (you can't ensure 
it'll reach the true optimum if there are multiple local optima and no 
additional structure) becomes a different rule itself. For instance, 
Borda is a 5-approximation to the optimal Kemeny ordering, but Borda is 
a completely different method from Kemeny.


If you're dealing with redistricting, the competition solution that you 
mentioned could work, but it might well be that, for redistricting, 
capturing the exact tradeoff between looking like communities of 
interest and being completely neutral is a task best left to an 
independent commission. Of course, one can also dissolve the problem 
rather than solve it, and employ some PR method which would greatly 
diminish the incentive to do any gerrymandering in the first place.


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Re: [EM] Another auto districting proposal (Crystal districting?)

2009-11-19 Thread Raph Frank
On Thu, Nov 19, 2009 at 4:00 PM, Juho juho4...@yahoo.co.uk wrote:
 My thinking is that it might be easier to agree about the targets rather
 than the whole procedure. The targets can be simpler to define. Following
 Raph Franks model it would be thus enough to say that any N points and the
 kn values and then derive the border lines and the jointly agreed value of
 the solution from this data. That would not leave much space for strategies
 and gerrymandering. The proposed solutions would be evaluated and the one
 with best value would be declared the winner.

Well, ideally the method should be a well defined process rather than
an optimisation method.  It would take as its input a set of points
and output a map.  Splitline also requires a description of the State
boundary.

However, it would be perfectly valid to give a measure and then allow
anyone submit a map districting.

I think that if the block boundaries are decided before the census and
the number of blocks is large enough (say 100-300 people per block on
average), then it would be hard to gerrymander using block boundaries.

The process could be something like

- based on the old census, define the blocks for the new census
-- A group of contiguous old blocks with population  500 may be
combined into a new block
-- Old blocks may be split into pieces
 (if  1000*N, it must be split into N+1 parts)
-- otherwise, the blocks shall remain the same as previously

- Geographic data is released

- Hold census

- Population data is released

- Format for maps is published

- Anyone can submit a map

- best map after 6 months wins.

Ofc, that requires that the SC is able to determine which map wins
based on the description of the measure in the legislation.

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Re: [EM] Another auto districting proposal (Crystal districting?)

2009-11-19 Thread Juho

On Nov 19, 2009, at 6:55 PM, Raph Frank wrote:


On Thu, Nov 19, 2009 at 4:00 PM, Juho juho4...@yahoo.co.uk wrote:
My thinking is that it might be easier to agree about the targets  
rather
than the whole procedure. The targets can be simpler to define.  
Following
Raph Franks model it would be thus enough to say that any N points  
and the
kn values and then derive the border lines and the jointly agreed  
value of
the solution from this data. That would not leave much space for  
strategies
and gerrymandering. The proposed solutions would be evaluated and  
the one

with best value would be declared the winner.


Well, ideally the method should be a well defined process rather than
an optimisation method.


This is true from the point of view that it would be good to have a  
known algorithm that can automatically (and in reasonable time) find  
the best result. On the other hand the optimization approach is a  
superset of the procedural approach. The optimization approach works  
also in the case where finding the best answer (or proving that some  
answer is the best) is not computationally feasible (but when  
optimization can find good enough answers).


It may also be easier to define and agree just the targets /  
criterion. I also like the idea of defining the ideal outcome instead  
of defining a procedure (that might or might not yield a good result)  
(the agreed criterion is closer to defining the actual targets).



 It would take as its input a set of points
and output a map.  Splitline also requires a description of the State
boundary.


I think the optimization approach that I proposed would as well  
require very similar data, except that the points could be picked at  
random and not given as input.




However, it would be perfectly valid to give a measure and then allow
anyone submit a map districting.


Yes, for splitlines one could e.g. just set a requirement that the  
borders should be straight lines and there should be n-1 lines (to get  
n districts) (+ the border length and even population distribution  
requirements).




I think that if the block boundaries are decided before the census and
the number of blocks is large enough (say 100-300 people per block on
average), then it would be hard to gerrymander using block boundaries.


Yes, some suitably small size should be set to reduce gerrymandering.



The process could be something like

- based on the old census, define the blocks for the new census
-- A group of contiguous old blocks with population  500 may be
combined into a new block
-- Old blocks may be split into pieces
 (if  1000*N, it must be split into N+1 parts)
-- otherwise, the blocks shall remain the same as previously


Yes. In the case that they are already small enough there would not  
even be any interest to find politically appropriate blocks.




- Geographic data is released

- Hold census

- Population data is released

- Format for maps is published

- Anyone can submit a map

- best map after 6 months wins.


Yes. With computers (and if working sw is already available to all and  
all the rules are already well known) also shorter period should be  
enough.




Ofc, that requires that the SC is able to determine which map wins
based on the description of the measure in the legislation.


Yes, the comparison method should be well defined and feasible to  
compute. The optimization algorithms should be able call this  
subroutine thousands of times.


Juho





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Re: [EM] Proportional Representation from Ratings Ballots

2009-11-19 Thread Raph Frank
(Ahem), actually it's:

 Stage 1, (Election stage) select k1 so that

 k1*[ w(a)*r(a) + w(b)*r(b) + . ] = 1

 Each candidate gets

 k1*w(x)*r(x)

 Stage 2, (Elimination stage) select k2 so that

 (k2)^2 * ([w(c)*r(c)]^2 + [w(d)*r(d)]^2 + ... ) = 1 - k1*[w(a)*r(a) +
w(b)*r(b)]

 Each candidate gets

 k2*[w(x)*r(x)]

 Eliminate the remaining candidate who scores the lowest.

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Re: [EM] A Proportionally Fair Consensus Lottery for which Sincere Range Ballots are Optimal

2009-11-19 Thread Raph Frank
On Thu, Nov 19, 2009 at 8:08 PM,  fsimm...@pcc.edu wrote:
 If the circled name on the randomly drawn ballot has a rating above the 
 random
 favorite rating expectation, on any ballot (including the one in play), then
 another ballot is drawn, and the indicated favorite of the second ballot is 
 elected.

 Otherwise, the proposed consensus candidate whose name was circled on the 
 first
 drawn ballot is elected.

Effectively, a random voter proposes a consensus candidate.

The random ballot probabilities are determined and each voter is given
the option to vote Yes/No to the consensus candidate.

Unless all prefer the consensus candidate to the expected utility of
the random ballot, the random ballot method is used.

It is clear that honest range is the best plan as it doesn't affect
anything else.

Likewise, you might as well pick your favourite as favourite.

The consensus candidate is different.  It is inherently strategic.

There is the possibility for group chicken effects.  For example, a
party could say that all of their supporters are going to rate
candidate X at minimum, so there is no point in nominating that
candidate.  This could cause the other partys' supporters to disregard
that candidate as a potential consensus candidate.

Also, I wonder if it might be worth having a rule that allows
additional consensus attempts.

For example, if 10% refuse, then the other 90% would be given the
option of choosing the consensus candidate.  The 2 choices in that
case would be

Option 1)
Full random ballot

Option 2)
90% chance of consensus candidate
10% chance of random ballot (only the ballots outside the 90% are considered)

This would probably break the strategic purity of the single stage method.

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Re: [EM] What does proportional representation MEAN? And list of known PR methods (know any more?)

2009-11-19 Thread fsimmons
Here's another idea for PR:

First use MCA ballots (Majority Choice Approval, where favorites and also
approved are indicated) to get a distance between pairs of candidates.  The
distance between two candidates is the number  of ballots on which just one of
the two is neither favorite nor also approved.

Next do a cluster analysis of the candidates by one of the standard methods that
yields a binary tree as output.

Initialize a system for labeling each node of the tree by labeling each branch
with both the number of candidates that it (the branch) leads to and the total
number of favorites garnered by all of those candidates.

One by one send each seat down the tree until it reaches a candidate.

At each node a decision must be made.  Which of the two branches will get the 
seat?

Send the seat down the branch with the greatest favorite label.

Then make the following label adjustments:

We decrement (i.e. subtract one from) the number of candidates label, and then
reduce the number of  favorites label by the number of voters a seat is supposed
to represent.  If this last number is still positive when the candidate number
reaches zero, then the remainder is transferred proportionately to the
favorite totals of the branches of the sub-tree beginning at the other branch.

If there is only one seat, then at each node it goes according to the majority
in the sub-tree for which that node is the root.

If any candidate is majority favorite, then that candidate will win the one 
seat.

If the clusters are arranged along a line without overlapping, then the median
voter candidate on that line will get the seat.  So the method picks the
Condorcet winner for one dimensional issue spaces.




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Re: [EM] What does proportional representation MEAN? And list of known PR methods (know any more?) correction

2009-11-19 Thread fsimmons
  If the clusters are arranged along a line without overlapping,  then the
median voter candidate on that line will get the seat.  So the method  picks
the Condorcet winner for one dimensional issue spaces.

Sorry,

This last statement is wrong!

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[EM] Does this method have a name, pt II

2009-11-19 Thread Kristofer Munsterhjelm
As part of coding my simulator, I have implemented a Condorcet method 
that goes like this:


A candidate X's victory score is equal to the sum of all victories of X 
against other candidates. If the pairwise matrix is d, and d[A,B] is the 
number of voters preferring A to B, then the victory of X against Y is:

If WV, 0 if d[X,Y] = d[Y,X], otherwise d[X,Y]
If margins, max(0, d[X,Y] - d[Y,X]).

The candidate with the greatest victory score is the winner.

-

I've called this method Offensive L-R, because it's like 
least-reversal, only instead of awarding the first place to the one with 
the least defeat sum (defensive), it awards it to the one with the 
greatest victory sum (offensive).


Does the method have a name already? It's so simple I can't but think 
it's already been invented.


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Re: [EM] A Proportionally Fair Consensus Lottery for which Sincere Range Ballots are Optimal

2009-11-19 Thread Jobst Heitzig
Dear folks,

although Forest's posting comes along so matter-of-factly, let's make it
absolutely clear that it is an

ENORMOUS MILESTONE!

Why so?

He describes a very SIMPLE, EFFICIENT, and FAIR method which

REVEALS THE TRUE UTILITY VALUES

of all voters who are rational in the sense of von Neumann and Morgenstern.

The only other known methods which have this revelation property are not
only more artificial and complex but are much less efficient or require
monetary taxes to be paid and destroyed (like the Clarke tax).

Very simple proof that sincere ratings are optimal:

My ratings are only relevant in a specific situation. In this situation
a fall-back lottery has already been determined from all the labels
(thus not dependent on my ratings), and a possible consensus option has
been nominated from the circle on a drawn ballot (thus also
independently from my ratings). If my ratings are relevant, they will
decide between this given fall-back lottery and this given nominated
consensus option, but I will not know beforehand which lottery and which
nominated option they will be (except if I knew all other ballots, which
is impossible in a secret poll). So the only way to make sure that my
ratings will lead to the fall-back lottery when I prefer it over the
nominated consensus option, and that they will lead to the nominated
consensus option when I prefer it to the fall-back lottery, is to give
ratings that reflect my true preferences, in other words, to specify a
set of sincere utility values.

Note that this is not only true in some equilibrium situation but NO
MATTER HOW THE OTHERS VOTE! In other words, it is always a dominant
strategy.

Now, that does not mean, however, that the whole method is
strategy-free, since the other part of the ballot, namely the circle and
the label, are strategic. I may, for example, have incentives to label a
more extreme option as favourite than my true favourite, in order to
lower the expected rating of the fall-back lottery and make a consensus
more probable. However, every such strategic behaviour would be visible
from the ballot since the labelled favourite would not have the highest
rating. That is a very interesting property which I have never seen
before in any method: you have the incentive to vote strategically, but
you cannot hide if you do so!

My guess is that we will soon find a similar method in which a single
voter cannot prevent the consensus completely but only lower its
probability...

Forest: EXCEPTIONALLY WELL-DONE!

Jobst


fsimm...@pcc.edu schrieb:
 A proportionally fair lottery is a lottery method in a which any faction of 
 the
 voters can unilaterally guarantee that their common favorite will be elected
 with a probability proportional to the size of their faction.
 
 A consensus candidate is any candidate that would be liked at least as much as
 the random favorite by 100 percent of the voters (assuming all voters to be
 rational).
 
 A consensus lottery is a method that elects consensus candidates with 
 certainty
 (again, assuming rational voters).
 
 I won't attempt to define sincere range ballot here, but the meaning will be
 apparent from this method:
 
 Ballots are range style (i.e. cardinal ratings).
 
 Each voter rates the candidates, circles one of the names as a proposed
 consensus candidate, and labels another (or perhaps the same) name as 
 favorite
 or favourite.
 
 Have I overlooked anything?
 
 The ballots are collected and the probabilities in the random favorite 
 lottery
 are determined.
 
 These probabilities are used to determine and mark a random favorite rating
 expectation on each range ballot.
 
 A ballot is then drawn at random.
 
 If the circled name on the randomly drawn ballot has a rating above the 
 random
 favorite rating expectation, on any ballot (including the one in play), then
 another ballot is drawn, and the indicated favorite of the second ballot is 
 elected.
 
 Otherwise, the proposed consensus candidate whose name was circled on the 
 first
 drawn ballot is elected.
 
 That's it.
 
 Note that any voter has the power to turn the election into random favorite 
 by
 giving only one candidate (favorite=consensus) a positive non-zero rating.  
 But
 whenever that is optimal rational strategy, sincere range yields the same
 expectation, and is therefore optimal, too.
 
 
 
 
 
 
 

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Re: [EM] A Proportionally Fair Consensus Lottery for which Sincere Range Ballots are Optimal

2009-11-19 Thread Jobst Heitzig
Dear Raph,

you wrote:
 Likewise, you might as well pick your favourite as favourite.

This is, unfortunately, not true: The labelled favourite influences the
expected ratings against which possible consensus options are compared
on each ballot, so you can have the incentive to exaggerate by labelling
a more extreme candidate than your true favourite in order to lower
those ratings and make your preferred consensus more likely! But this, I
guess, will not decrease but rather increase the method's efficiency in
realistic examples.

 The consensus candidate is different.  It is inherently strategic.
 
 There is the possibility for group chicken effects.  For example, a
 party could say that all of their supporters are going to rate
 candidate X at minimum, so there is no point in nominating that
 candidate.  This could cause the other partys' supporters to disregard
 that candidate as a potential consensus candidate.
 
 Also, I wonder if it might be worth having a rule that allows
 additional consensus attempts.
 
 For example, if 10% refuse, then the other 90% would be given the
 option of choosing the consensus candidate.  The 2 choices in that
 case would be
 
 Option 1)
 Full random ballot
 
 Option 2)
 90% chance of consensus candidate
 10% chance of random ballot (only the ballots outside the 90% are considered)
 
 This would probably break the strategic purity of the single stage method.

I guess so, too, but I think we can overcome the unanimity requirement
in a different way. Let me think about it...

Yours, Jobst

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Re: [EM] A Proportionally Fair Consensus Lottery for which Sincere Range Ballots are Optimal

2009-11-19 Thread fsimmons
Thanks for the encouragement, Jobst, and for supplying the proof.

It was your strategy free Condorcet method that led me in this direction:

I simply adapted it to your Proportionally Fair Consensus Lottery ideas using
range ballots instead of  taking a second head count after the choice was put to
the voters.

Most of the credit should be yours; in fact, the proof and all of the
ingredients are yours.  I hurried to post the message this morning, because I
was sure that you were going to beat me to it!  I would certainly believe you if
you said that you had already thought of the same thing but didn't have time to
post the message before I did.



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Re: [EM] What does proportional representation MEAN? And list of known PR methods (know any more?)

2009-11-19 Thread Andrew Myers

Warren Smith wrote:

Kristofer Munsterhjelm asked me what proportional representation (PR) means.

At this time it is probably unwise to make a too-precise definition
since every PR voting method seems to obey a different proportionality
theorem.  I say you should just assess each theorem on a case by case
basis to see if you like it.

But a somewhat imprecise definition is: ...

HERE'S MY LIST OF KNOWN PR VOTING METHODS:
...

That's my list.  Is anybody aware of any other PR methods?
  
Yes, the CIVS voting system implements a Condorcet PR method that I came 
up with. It seems to work well in practice, having been used for dozens 
if not hundreds of elections/polls. In the k=1 case it devolves to 
regular Condorcet. There is a description of it on the CIVS web site:


http://www.cs.cornell.edu/w8/~andru/civs/proportional.html

-- Andrew

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