RE: [SPAM] [flexcoders] Re: Flexbuilder doesn't give compile error when using a undeclared variable, methods
An associative array has nothing to do with Array. It was a bad choice of names, they should have just called it a hash table. Tracy Spratt, Lariat Services, development services available _ From: flexcoders@yahoogroups.com [mailto:flexcod...@yahoogroups.com] On Behalf Of benjamine_df Sent: Friday, October 30, 2009 10:20 AM To: flexcoders@yahoogroups.com Subject: [SPAM] [flexcoders] Re: Flexbuilder doesn't give compile error when using a undeclared variable, methods Compile time we don't need to check for data, we only need to check for declared variable, method class etc. So I am in favour for what java is doing. It will help to catch the errors during compile time I think flex allows this because of associative arrays. var data:object = new Object(); new data.length means data['length'] Is there any way I can tell flex compiler that don't assume objects as associative array unless I specifically declare as Array.
[flexcoders] Re: Flexbuilder doesn't give compile error when using a undeclared variable, methods
Compile time we don't need to check for data, we only need to check for declared variable, method class etc. So I am in favour for what java is doing. It will help to catch the errors during compile time I think flex allows this because of associative arrays. var data:object = new Object(); new data.length means data['length'] Is there any way I can tell flex compiler that don't assume objects as associative array unless I specifically declare as Array.
[flexcoders] Re: Flexbuilder doesn't give compile error when using a undeclared variable, methods
I wanted to clarify more on my other response.
As Amy referred this does not happen to Dictionary object alone. create an
instance of any object , then call a non existing method and you won't get
compile time errors.
Example
var data:Array = new Array()
data.xyz() //xyz method does not exist in Array, but still no compile time
errors.
Without compile time errors, when things don't work in run time, it wastes lot
of my time to find the problem.
Any help from Flex gurus are appreciated.
Thanks
Ben
--- In flexcoders@yahoogroups.com, droponrcll amyblankens...@... wrote:
--- In flexcoders@yahoogroups.com, benjamine_df benjamine_df@ wrote:
Hello,
I am new to flex and I make lot of mistakes by calling a method or
field in an object which does not exist. But flex builder 3 doesn't
seem to throw a compile error when I do this. In java it would be a
quick compile error. Is there any flex builder setting I can set to
give compile errors.
Example
var data:Dictionary = new Dictionary();
data.length //no compile error for this
data[indexint] //no compile error
Create your own typed objects if you want type checking:
public clas YourClass {
public var indexInt:int;
public var length:int;
}
var yourClass:YourClass = newYourClass();
var foo:String = YourClass.foo; //compiler error
I'm pretty sure Java wouldn't throw a compiler error if you add or access a
previously nonexistent key to a Dictionary, either, since that's pretty much
the point of a Dictionary in most languages, isn't it?
-Amy
[flexcoders] Re: Flexbuilder doesn't give compile error when using a undeclared variable, methods
--- In flexcoders@yahoogroups.com, benjamine_df benjamine...@... wrote:
Hello,
I am new to flex and I make lot of mistakes by calling a method or
field in an object which does not exist. But flex builder 3 doesn't
seem to throw a compile error when I do this. In java it would be a
quick compile error. Is there any flex builder setting I can set to
give compile errors.
Example
var data:Dictionary = new Dictionary();
data.length //no compile error for this
data[indexint] //no compile error
Create your own typed objects if you want type checking:
public clas YourClass {
public var indexInt:int;
public var length:int;
}
var yourClass:YourClass = newYourClass();
var foo:String = YourClass.foo; //compiler error
I'm pretty sure Java wouldn't throw a compiler error if you add or access a
previously nonexistent key to a Dictionary, either, since that's pretty much
the point of a Dictionary in most languages, isn't it?
-Amy
