Re: [Gambas-user] simple replace question
Il mercoledì 4 marzo 2009 11:55:44 Bruce ha scritto: Hi guys, I'm trying to convert a string to float. The string contents are 56½. I've tried both replace(st,½,.5) and replace(st, Chr$(194), .5 ) neither helps. Any ideas? tia ted Strange. replace(st,½,.5) works on my system. Gambas 2.11.1 Saluti, Stefano --- --- Open Source Business Conference (OSBC), March 24-25, 2009, San Francisco, CA -OSBC tackles the biggest issue in open source: Open Sourcing the Enterprise -Strategies to boost innovation and cut costs with open source participation -Receive a $600 discount off the registration fee with the source code: SFAD http://p.sf.net/sfu/XcvMzF8H ___ Gambas-user mailing list Gambas-user@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/gambas-user -- Open Source Business Conference (OSBC), March 24-25, 2009, San Francisco, CA -OSBC tackles the biggest issue in open source: Open Sourcing the Enterprise -Strategies to boost innovation and cut costs with open source participation -Receive a $600 discount off the registration fee with the source code: SFAD http://p.sf.net/sfu/XcvMzF8H ___ Gambas-user mailing list Gambas-user@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/gambas-user
Re: [Gambas-user] simple replace question
Is your string UTF encoded? You should check if your character code is exactly 194 and not wider... 16 Bits perhaps? Any Hex-Viewer will help. regards Emil On Wednesday 04 March 2009 11:55:44 Bruce wrote: Hi guys, I'm trying to convert a string to float. The string contents are 56½. I've tried both replace(st,½,.5) and replace(st, Chr$(194), .5 ) neither helps. Any ideas? tia ted --- --- Open Source Business Conference (OSBC), March 24-25, 2009, San Francisco, CA -OSBC tackles the biggest issue in open source: Open Sourcing the Enterprise -Strategies to boost innovation and cut costs with open source participation -Receive a $600 discount off the registration fee with the source code: SFAD http://p.sf.net/sfu/XcvMzF8H ___ Gambas-user mailing list Gambas-user@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/gambas-user -- Open Source Business Conference (OSBC), March 24-25, 2009, San Francisco, CA -OSBC tackles the biggest issue in open source: Open Sourcing the Enterprise -Strategies to boost innovation and cut costs with open source participation -Receive a $600 discount off the registration fee with the source code: SFAD http://p.sf.net/sfu/XcvMzF8H ___ Gambas-user mailing list Gambas-user@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/gambas-user
Re: [Gambas-user] simple replace question
Bruce schrieb: On Wednesday 04 March 2009 23:00:00 Stefano Palmeri wrote: Strange. replace(st,½,.5) works on my system. Gambas 2.11.1 Saluti, Stefano Damn! And I still can't get it working. The only thing I've been able to decipher is that Len(st)=4 not 3. Using gambas 2.9.?? as its the latest available for PCLinuxOS (see below). The version will not matter, I guess. Try converting your string into ASCII before replacing: newString = Conv(st, UTF-8, ASCII) Replace(st, ½, .5) On my old ASCII-table ½ is chr$(171). So it should work with this one, as it's known in ASCII. If you get an error 32, your string wasn't UTF-8. Next idea: use String.Code to find out the Hex-code of each single character in st. Then rewrite the replace function for this combination of characters - something like Replace(st, chr$(30) chr$(1) chr$(123), .5)... Hope it helps... Rolf -- Open Source Business Conference (OSBC), March 24-25, 2009, San Francisco, CA -OSBC tackles the biggest issue in open source: Open Sourcing the Enterprise -Strategies to boost innovation and cut costs with open source participation -Receive a $600 discount off the registration fee with the source code: SFAD http://p.sf.net/sfu/XcvMzF8H ___ Gambas-user mailing list Gambas-user@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/gambas-user
Re: [Gambas-user] simple replace question
Bruce schrieb: On Thursday 05 March 2009 01:34:29 Rolf-Werner Eilert wrote: newString = Conv(st, UTF-8, ASCII) Replace(st, ½, .5) Thanks RW, That got me started at least. So far: TRY wx = Conv(lp1[5], UTF-8, ASCII) TRY wx = Replace(wx, ½, .5) TRY wx = Replace(wx, ¼, .25) TRY wx = Replace(wx, ¾, .75) seems to work. I had to put the TRY's in because 3/4 doesn't seem to handle properly otherwise. No wonder, because 3/4 doesn't exist in ASCII. This is what my character table program says about this character: UTF-8: 0xC2 0xBE UTF-16: 0x00BE C-Oktal terminiertes UTF-8: \302\276 Dezimale XML-Entität: #190; So you should look for a string consisting of C2 and BE, that is chr$(194) and chr$(190) as we can presume this is UTF-8. Try this: xStr = chr$(194) chr$(190) wx = Replace(wx, xStr, .75) Does this run? Or even wx = Replace(wx, chr$(194) chr$(190), .75) should work. At least if I'm right, but I never tried this. Rolf -- Open Source Business Conference (OSBC), March 24-25, 2009, San Francisco, CA -OSBC tackles the biggest issue in open source: Open Sourcing the Enterprise -Strategies to boost innovation and cut costs with open source participation -Receive a $600 discount off the registration fee with the source code: SFAD http://p.sf.net/sfu/XcvMzF8H ___ Gambas-user mailing list Gambas-user@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/gambas-user
Re: [Gambas-user] simple replace question
Bruce schrieb: On Thursday 05 March 2009 01:34:29 Rolf-Werner Eilert wrote: newString = Conv(st, UTF-8, ASCII) Replace(st, ½, .5) Thanks RW, That got me started at least. So far: TRY wx = Conv(lp1[5], UTF-8, ASCII) TRY wx = Replace(wx, ½, .5) TRY wx = Replace(wx, ¼, .25) TRY wx = Replace(wx, ¾, .75) seems to work. I had to put the TRY's in because 3/4 doesn't seem to handle properly otherwise. Sorry, I forgot this: you must replace 3/4 to something else before you can Conv to ASCII. Arrrgh - this will not run. Next idea: Look into the string and find out what Conv makes out of 3/4 in ASCII - maybe it just makes 3/4 out of it? This is what you will have to look for. Your thing would then read as follows: TRY wx = Conv(lp1[5], UTF-8, ASCII) TRY wx = Replace(wx, ½, .5) TRY wx = Replace(wx, ¼, .25) TRY wx = Replace(wx, 3/4, .75) We would need a String.Replace() function here... Rolf -- Open Source Business Conference (OSBC), March 24-25, 2009, San Francisco, CA -OSBC tackles the biggest issue in open source: Open Sourcing the Enterprise -Strategies to boost innovation and cut costs with open source participation -Receive a $600 discount off the registration fee with the source code: SFAD http://p.sf.net/sfu/XcvMzF8H ___ Gambas-user mailing list Gambas-user@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/gambas-user
Re: [Gambas-user] simple replace question
On Wednesday 04 March 2009, Rolf-Werner Eilert wrote: Bruce schrieb: On Thursday 05 March 2009 01:34:29 Rolf-Werner Eilert wrote: newString = Conv(st, UTF-8, ASCII) Replace(st, ½, .5) Thanks RW, That got me started at least. So far: TRY wx = Conv(lp1[5], UTF-8, ASCII) TRY wx = Replace(wx, ½, .5) TRY wx = Replace(wx, ¼, .25) TRY wx = Replace(wx, ¾, .75) seems to work. I had to put the TRY's in because 3/4 doesn't seem to handle properly otherwise. No wonder, because 3/4 doesn't exist in ASCII. This is what my character table program says about this character: UTF-8: 0xC2 0xBE UTF-16: 0x00BE C-Oktal terminiertes UTF-8: \302\276 Dezimale XML-Entität: #190; So you should look for a string consisting of C2 and BE, that is chr$(194) and chr$(190) as we can presume this is UTF-8. Try this: xStr = chr$(194) chr$(190) wx = Replace(wx, xStr, .75) Does this run? Or even wx = Replace(wx, chr$(194) chr$(190), .75) should work. At least if I'm right, but I never tried this. Rolf http://www.eki.ee/letter/chardata.cgi?ucode=00BE found in charsets: 8859-1 (BE); 8859-13 (BE); 8859-8 (BE); 8859-9 (BE); CP1116 (F3); CP1122 (B9); CP1252 (BE); CP1254 (BE); CP1255 (BE); CP1256 (BE); CP1257 (BE); CP1258 (BE); CP775 (F3); CP850 (F3); CP857 (F3); CP863 (AD); Dangerous the differences between char sets. I was suprised it is not in ASCII also. I know my Epson fX80 with IBM supplied ROM did have it. (ancient history :) ) Ron -- Open Source Business Conference (OSBC), March 24-25, 2009, San Francisco, CA -OSBC tackles the biggest issue in open source: Open Sourcing the Enterprise -Strategies to boost innovation and cut costs with open source participation -Receive a $600 discount off the registration fee with the source code: SFAD http://p.sf.net/sfu/XcvMzF8H ___ Gambas-user mailing list Gambas-user@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/gambas-user Best regards, Ron_1st -- -- Open Source Business Conference (OSBC), March 24-25, 2009, San Francisco, CA -OSBC tackles the biggest issue in open source: Open Sourcing the Enterprise -Strategies to boost innovation and cut costs with open source participation -Receive a $600 discount off the registration fee with the source code: SFAD http://p.sf.net/sfu/XcvMzF8H ___ Gambas-user mailing list Gambas-user@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/gambas-user
Re: [Gambas-user] simple replace question
Bruce schrieb: On Thursday 05 March 2009 01:34:29 Rolf-Werner Eilert wrote: newString = Conv(st, UTF-8, ASCII) Replace(st, ½, .5) Thanks RW, That got me started at least. So far: TRY wx = Conv(lp1[5], UTF-8, ASCII) TRY wx = Replace(wx, ½, .5) TRY wx = Replace(wx, ¼, .25) TRY wx = Replace(wx, ¾, .75) seems to work. I had to put the TRY's in because 3/4 doesn't seem to handle properly otherwise. Sorry, I forgot this: you must replace 3/4 to something else before you can Conv to ASCII. Arrrgh - this will not run. Next idea: Look into the string and find out what Conv makes out of 3/4 in ASCII - maybe it just makes 3/4 out of it? This is what you will have to look for. Your thing would then read as follows: TRY wx = Conv(lp1[5], UTF-8, ASCII) TRY wx = Replace(wx, ½, .5) TRY wx = Replace(wx, ¼, .25) TRY wx = Replace(wx, 3/4, .75) We would need a String.Replace() function here... Rolf String.Replace() is not needed, because there is no difference between ASCII and UTF-8 when replacing strings. There is no reason why Replace(st, ½, .5) won't work, unless the st string is not UTF-8 of course. Regards, -- Benoît -- Open Source Business Conference (OSBC), March 24-25, 2009, San Francisco, CA -OSBC tackles the biggest issue in open source: Open Sourcing the Enterprise -Strategies to boost innovation and cut costs with open source participation -Receive a $600 discount off the registration fee with the source code: SFAD http://p.sf.net/sfu/XcvMzF8H ___ Gambas-user mailing list Gambas-user@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/gambas-user
