[GnuWin32-Users] [gnuwin32 - Help] Absolute filename syntax including drive id

2009-08-26 Thread SourceForge.net

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https://sourceforge.net/forum/message.php?msg_id=7585336
By: kbroadey

I've come across several comments on the web showing that you can include a
drive letter in an absolute filename using this syntax:-

\\.\X:

where X is the drive letter.  Try as I might, I can't find a bit of GnuWin32
documentation describing this syntax.  Can someone point me in the right 
direction,
please?

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[GnuWin32-Users] [gnuwin32 - Help] RE: Absolute filename syntax including drive id

2009-08-26 Thread SourceForge.net

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By: tml1024

What makes you think there would need to be any gnuwin32-specific documentation
for this?

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[GnuWin32-Users] [gnuwin32 - Help] Verifying checksum of a CD

2009-08-26 Thread SourceForge.net

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By: kbroadey

I have an ISO file that I've burned to a CD.  I know its md5 checksum.  On my
Ubuntu 9.04 system I can do

dd if=/dev/cdrom | md5sum

and I get the same checksum as for the original ISO file.  However, on my 
Windows
XP machine with CoreUtils 5.3.0, when I do

dd if=\\.\D: 2nul: | md5sum

I get a different checksum (D: is the drive letter for the CDROM).  I get the
same result if I drop the 2nul:, but the stderr text gets from dd gets mixed
with stdout from md5sum so it's more tricky to read the checksum.

Can anyone see what I'm doing wrong?

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[GnuWin32-Users] [gnuwin32 - Help] RE: Absolute filename syntax including drive id

2009-08-26 Thread SourceForge.net

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By: kbroadey

Well I haven't some across this syntax before, so I guessed it was 
GnuWin32-specific.
Having spent entirely too long on Google today, though, it seems I guessed 
wrong,
as it's a variation on the UNC format - \\server\sharename\...

So it looks like . means this machine and DRIVE: can be used in place
of sharename to identify the drive.

Am I right?

Apparently there's also a long unc format e.g. 
\\?\UNC\server\sharename\path
or \\?\Device\CdRom0 but I guess GnuWin32 doesn't support that, as it doesn't
work for me.

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[GnuWin32-Users] [gnuwin32 - Help] RE: Verifying checksum of a CD

2009-08-26 Thread SourceForge.net

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https://sourceforge.net/forum/message.php?msg_id=7586250
By: kbroadey

md5sum is part of CoreUtils 5.3.0, as is dd.

The reason for the extra pipe is that I found a hint somewhere on the worldwide
web that piping dd into md5sum was the way to get a CD checksum, because you
want to be summing the entire ISO image of the disk, not just the disk contents.

But you're right - md5sum /dev/cdrom works on Ubuntu, giving the correct answer,
and md5sum \\.\D: with GnuWin32 gives the same wrong answer on Windows, do the
dd is superfluous.

One thing I have noticed is that df on both Ubuntu and Windows reports the
CD size as 476630 1K blocks.  However, dd bs=1k on Ubuntu reports that it
has processed 476930 blocks (300 more than there are on the CD) while on Windows
it reports 476630.

Also, if I do dd bs=1k count=476630 on Ubuntu, I get the same checksum as
I do on Windows.  Which means that Ubuntu is finding 300K more on the CD that
Windows is seeing.

Am I runnning into some bizarre blocksize issue?  Or does \\.\D: on Windows
give me the mounted contents of the ISO 9660 image, while /dev/cdrom on Ubuntu
gives me the raw disk image (which is what I need).

So the bottom line seems to be - how do I get at the raw CD disk image in 
Windows,
because \\.\D: isn't giving it to me.

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Re: [GnuWin32-Users] [gnuwin32 - Help] RE: Verifying checksum of a CD

2009-08-26 Thread Jason H
Just a guess albeit a very intelligent one:

by using /dev/cdrom, you use a block device,
including the partition table and MBR if any. By using D:\ you skip the
partition table and MBR, and check only the mounted partition. 

If
you want to see the device overall, I'd think you have to use something
like \PhysicalDevice\DiskDrive01\yadda\yadda. I don't know the proper
path, but I think it can be done.


- Original Message 
From: SourceForge.net nore...@sourceforge.net
To: nore...@sourceforge.net
Sent: Wednesday, August 26, 2009 9:55:08 AM
Subject: [GnuWin32-Users] [gnuwin32 - Help] RE: Verifying checksum of a CD


Read and respond to this message at: 
https://sourceforge.net/forum/message.php?msg_id=7586250
By: kbroadey

md5sum is part of CoreUtils 5.3.0, as is dd.

The reason for the extra pipe is that I found a hint somewhere on the worldwide
web that piping dd into md5sum was the way to get a CD checksum, because you
want to be summing the entire ISO image of the disk, not just the disk contents.

But you're right - md5sum /dev/cdrom works on Ubuntu, giving the correct answer,
and md5sum \\.\D: with GnuWin32 gives the same wrong answer on Windows, do the
dd is superfluous.

One thing I have noticed is that df on both Ubuntu and Windows reports the
CD size as 476630 1K blocks.  However, dd bs=1k on Ubuntu reports that it
has processed 476930 blocks (300 more than there are on the CD) while on Windows
it reports 476630.

Also, if I do dd bs=1k count=476630 on Ubuntu, I get the same checksum as
I do on Windows.  Which means that Ubuntu is finding 300K more on the CD that
Windows is seeing.

Am I runnning into some bizarre blocksize issue?  Or does \\.\D: on Windows
give me the mounted contents of the ISO 9660 image, while /dev/cdrom on Ubuntu
gives me the raw disk image (which is what I need).

So the bottom line seems to be - how do I get at the raw CD disk image in 
Windows,
because \\.\D: isn't giving it to me.

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