Thanks for your answers. I did fool around with a popup, but it would
also overlap other windows, transient or not. Furthermore, I need it to
move relative to the window if that is moved.
Maybe it's best if I tell you what I'm trying to do in particular:
I'm working on something like a tooltip. However, I don't think I can
use normal tooltips, since I need to position it manually (actually, I
need it to move out of the way if the mouse cursor approaches it).
A popup sounds like the right way to do this, but I need to somehow wire
the popup's movement to the window's movement. Is there an easy way to
do that?
On 07/13/2011 03:53 PM, Bill Czermak wrote:
Maybe the answer to your question is simply No You are displaying
stuff in your window
Generally the windows manager decides where on the screen to put stuff,
so you can either use your existing window and allow GTK to display
things as it thinks fit, which may not be what you expect. (Note the
comments about gtk_fixed in the documentation) or open a new top-level
window set transient to the main window, which sometimes positions
things where you expect. However the window manager decides where to
put the new window and with dual screens this can be interesting.
Best approach might be to use a (possibly) modal dialog, which the user
can move out the way if he needs to. It this is not acceptable, then
your only choice is to display a complex widget on the main window,
maybe with a close button to destroy it if apprpriate
Rgds Bill
On 13/07/11 06:57, Sam Spilsbury wrote:
2011/7/13 Felix H. Dahlkef...@ubercode.de:
Hi,
I'm fairly new to GTK (using version 2.24), and I'm wondering if I can
move a widget (partly) outside the area of a window and still have it
displayed.
Consider the following code, where I've tried to use a GtkFixed to
position a label partly outside the window:
==
int main(int argc, char* argv[])
{
gtk_init(argc,argv);
GtkWidget* window = gtk_window_new(GTK_WINDOW_TOPLEVEL);
gtk_window_set_default_size(GTK_WINDOW(window), 320, 240);
gtk_container_border_width(GTK_CONTAINER(window), 10);
gtk_widget_show(window);
GtkWidget* fixed = gtk_fixed_new();
gtk_widget_set_has_window(fixed, TRUE); // Doesn't help
gtk_container_add(GTK_CONTAINER(window), fixed);
gtk_widget_show(fixed);
GtkWidget* label = gtk_label_new(Hello World);
// y = 238 should position the label partly outside the window
gtk_fixed_put((GtkFixed*) fixed, label, 0, 238);
gtk_widget_show(label);
gtk_main();
return 0;
}
==
This is how I want it to look:
---
| |
| |
| |
| |
|-- |
-||
||
--
And this is how it actually looks:
---
| |
| |
| |
|-- |
||| |
||| |
|-- |
---
As you can see from the comments, I already tried to use
gtk_widget_set_has_window(fixed, TRUE), but it didn't do the
trick. How can I do this?
I can't say I know Gtk+ in any high level of detail, but just using my
basic knowledge of X11 here, I'd say that gtk_widget_set_has_window
(fixed, TRUE); is probably only giving the widget a subwindow of the
toplevel window of your application and not another toplevel window in
and of itself
If you wanted to have that part of your widget appearing outside of
the client window you'd need to create a new GtkWindow which is
override-redirect (I believe the way to do this is to specify
GTK_WINDOW_POPUP on creation) and set the WM_TRANSIENT_FOR hint to be
your client's application window. Then you can draw whatever you want
there and it will be outside of (albeit on top of) the application.
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