[jQuery] Re: $.ajax bug ?!? Maybe i've not understand somethings ....
On 28 Gen, 17:03, Ricardo Tomasi ricardob...@gmail.com wrote:
It isn't possible to have error/success callbacks for JSONP. You can't
cancel the request either. Once you add a script tag to the head,
the browser fires a GET request and it can't be interrupted - even if
you remove the script before the response comes, the script will still
run.
ok. got it!
(the only event that fires on the script tag is 'onload', but it only
tells you if the content has successfully loaded, not the opposite.
There is no way to know if an error happened)
Also, you're misunderstanding the way JSONP works - there is no need
for a 'success' function, that is the callback function which will be
called when the response is loaded. Thats 'jsonFlickerFeed' in my
example.
Ok i've understood how jsonp work, but there's something that i can't
understand.
I try to explain better i can (sorry for my bad english)
1)Using the $.ajax method, an example:
$.ajax({
type: methodType,
url: theURL,
data: params,
dataType:jsonp,
success: function(data){
console.log(onClick success);
}
});
in the jquery core is built a temporary jsonp function to handle the
data returned by the server, if the succes function is defined the
temporary function call the succe function and pass the returned
data ... specifically at line 3314 of the jquery.1.3.1.js :
// Handle JSONP-style loading
window[ jsonp ] = function(tmp){
data = tmp;
success();
complete();
// Garbage collect
window[ jsonp ] = undefined;
try{ delete window[ jsonp ]; } catch(e){}
if ( head )
head.removeChild( script );
};
the tmp is the data returned by the server.
Now in your example you use the jsonFlickrFeed function but without
handling the returned data from the server:
jsonFlickrFeed = function(){ alert('flickr loaded'); };
$.jsonp({
url: 'http://api.flickr.com/services/feeds/photos_public.gne?
tags=hackdayindialang=en-usformat=jsoncallback=jsonFlickrFeed',
timeout: 10,
onTimeout: function(url){ console.error('jsonp script timed out:
'+url) }
});
how to access the data returned from the server? How to modify the
$.jsonp function to call the success function defined and pass in the
data returned from the server ... this is sure possible case jquery in
$.ajax call do it, but i don't know how :-/
Many thanks, really!
I hope i've been clear, sorry for my english!
[jQuery] Re: $.ajax bug ?!? Maybe i've not understand somethings ....
We can't access the success function of the $.ajax call without
messing with jQuery source code, because the vars that name it are
inside the jQuery function scope.
In JSONP, the JSON object is passed as an argument to the callback
function. In the example I posted:
jsonFlickrFeed = function(data){ //do something with data };
On Jan 30, 7:28 am, Stefano Corallo stefan...@gmail.com wrote:
On 28 Gen, 17:03, Ricardo Tomasi ricardob...@gmail.com wrote:
It isn't possible to have error/success callbacks for JSONP. You can't
cancel the request either. Once you add a script tag to the head,
the browser fires a GET request and it can't be interrupted - even if
you remove the script before the response comes, the script will still
run.
ok. got it!
(the only event that fires on the script tag is 'onload', but it only
tells you if the content has successfully loaded, not the opposite.
There is no way to know if an error happened)
Also, you're misunderstanding the way JSONP works - there is no need
for a 'success' function, that is the callback function which will be
called when the response is loaded. Thats 'jsonFlickerFeed' in my
example.
Ok i've understood how jsonp work, but there's something that i can't
understand.
I try to explain better i can (sorry for my bad english)
1)Using the $.ajax method, an example:
$.ajax({
type: methodType,
url: theURL,
data: params,
dataType:jsonp,
success: function(data){
console.log(onClick success);
}
});
in the jquery core is built a temporary jsonp function to handle the
data returned by the server, if the succes function is defined the
temporary function call the succe function and pass the returned
data ... specifically at line 3314 of the jquery.1.3.1.js :
// Handle JSONP-style loading
window[ jsonp ] = function(tmp){
data = tmp;
success();
complete();
// Garbage collect
window[ jsonp ] = undefined;
try{ delete window[ jsonp ]; } catch(e){}
if ( head )
head.removeChild( script );
};
the tmp is the data returned by the server.
Now in your example you use the jsonFlickrFeed function but without
handling the returned data from the server:
jsonFlickrFeed = function(){ alert('flickr loaded'); };
$.jsonp({
url: 'http://api.flickr.com/services/feeds/photos_public.gne?
tags=hackdayindialang=en-usformat=jsoncallback=jsonFlickrFeed',
timeout: 10,
onTimeout: function(url){ console.error('jsonp script timed out:
'+url) }
});
how to access the data returned from the server? How to modify the
$.jsonp function to call the success function defined and pass in the
data returned from the server ... this is sure possible case jquery in
$.ajax call do it, but i don't know how :-/
Many thanks, really!
I hope i've been clear, sorry for my english!
[jQuery] Re: $.ajax bug ?!? Maybe i've not understand somethings ....
On 30 Gen, 19:25, Ricardo Tomasi ricardob...@gmail.com wrote:
We can't access the success function of the $.ajax call without
messing with jQuery source code, because the vars that name it are
inside the jQuery function scope.
ok
In JSONP, the JSON object is passed as an argument to the callback
function. In the example I posted:
jsonFlickrFeed = function(data){ //do something with data };
i've tried but data is always undefined,take a look:
http://jsbin.com/ajimu/edit
On Jan 30, 7:28 am, Stefano Corallo stefan...@gmail.com wrote:
On 28 Gen, 17:03, Ricardo Tomasi ricardob...@gmail.com wrote:
It isn't possible to have error/success callbacks for JSONP. You can't
cancel the request either. Once you add a script tag to the head,
the browser fires a GET request and it can't be interrupted - even if
you remove the script before the response comes, the script will still
run.
ok. got it!
(the only event that fires on the script tag is 'onload', but it only
tells you if the content has successfully loaded, not the opposite.
There is no way to know if an error happened)
Also, you're misunderstanding the way JSONP works - there is no need
for a 'success' function, that is the callback function which will be
called when the response is loaded. Thats 'jsonFlickerFeed' in my
example.
Ok i've understood how jsonp work, but there's something that i can't
understand.
I try to explain better i can (sorry for my bad english)
1)Using the $.ajax method, an example:
$.ajax({
type: methodType,
url: theURL,
data: params,
dataType:jsonp,
success: function(data){
console.log(onClick success);
}
});
in the jquery core is built a temporary jsonp function to handle the
data returned by the server, if the succes function is defined the
temporary function call the succe function and pass the returned
data ... specifically at line 3314 of the jquery.1.3.1.js :
// Handle JSONP-style loading
window[ jsonp ] = function(tmp){
data = tmp;
success();
complete();
// Garbage collect
window[ jsonp ] = undefined;
try{ delete window[ jsonp ]; } catch(e){}
if ( head )
head.removeChild( script );
};
the tmp is the data returned by the server.
Now in your example you use the jsonFlickrFeed function but without
handling the returned data from the server:
jsonFlickrFeed = function(){ alert('flickr loaded'); };
$.jsonp({
url: 'http://api.flickr.com/services/feeds/photos_public.gne?
tags=hackdayindialang=en-usformat=jsoncallback=jsonFlickrFeed',
timeout: 10,
onTimeout: function(url){ console.error('jsonp script timed out:
'+url) }
});
how to access the data returned from the server? How to modify the
$.jsonp function to call the success function defined and pass in the
data returned from the server ... this is sure possible case jquery in
$.ajax call do it, but i don't know how :-/
Many thanks, really!
I hope i've been clear, sorry for my english!
[jQuery] Re: $.ajax bug ?!? Maybe i've not understand somethings ....
Ah, an oversight of mine. I forgot to add the parameter when rewriting
the callback.
Fixed as you can see at http://jsbin.com/eliwu
Never use someone else's code without inspection ;)
On Jan 30, 4:34 pm, Stefano Corallo stefan...@gmail.com wrote:
On 30 Gen, 19:25, Ricardo Tomasi ricardob...@gmail.com wrote:
We can't access the success function of the $.ajax call without
messing with jQuery source code, because the vars that name it are
inside the jQuery function scope.
ok
In JSONP, the JSON object is passed as an argument to the callback
function. In the example I posted:
jsonFlickrFeed = function(data){ //do something with data };
i've tried but data is always undefined,take a look:
http://jsbin.com/ajimu/edit
On Jan 30, 7:28 am, Stefano Corallo stefan...@gmail.com wrote:
On 28 Gen, 17:03, Ricardo Tomasi ricardob...@gmail.com wrote:
It isn't possible to have error/success callbacks for JSONP. You can't
cancel the request either. Once you add a script tag to the head,
the browser fires a GET request and it can't be interrupted - even if
you remove the script before the response comes, the script will still
run.
ok. got it!
(the only event that fires on the script tag is 'onload', but it only
tells you if the content has successfully loaded, not the opposite.
There is no way to know if an error happened)
Also, you're misunderstanding the way JSONP works - there is no need
for a 'success' function, that is the callback function which will be
called when the response is loaded. Thats 'jsonFlickerFeed' in my
example.
Ok i've understood how jsonp work, but there's something that i can't
understand.
I try to explain better i can (sorry for my bad english)
1)Using the $.ajax method, an example:
$.ajax({
type: methodType,
url: theURL,
data: params,
dataType:jsonp,
success: function(data){
console.log(onClick success);
}
});
in the jquery core is built a temporary jsonp function to handle the
data returned by the server, if the succes function is defined the
temporary function call the succe function and pass the returned
data ... specifically at line 3314 of the jquery.1.3.1.js :
// Handle JSONP-style loading
window[ jsonp ] = function(tmp){
data = tmp;
success();
complete();
// Garbage collect
window[ jsonp ] = undefined;
try{ delete window[ jsonp ]; } catch(e){}
if ( head )
head.removeChild( script );
};
the tmp is the data returned by the server.
Now in your example you use the jsonFlickrFeed function but without
handling the returned data from the server:
jsonFlickrFeed = function(){ alert('flickr loaded'); };
$.jsonp({
url: 'http://api.flickr.com/services/feeds/photos_public.gne?
tags=hackdayindialang=en-usformat=jsoncallback=jsonFlickrFeed',
timeout: 10,
onTimeout: function(url){ console.error('jsonp script timed out:
'+url) }
});
how to access the data returned from the server? How to modify the
$.jsonp function to call the success function defined and pass in the
data returned from the server ... this is sure possible case jquery in
$.ajax call do it, but i don't know how :-/
Many thanks, really!
I hope i've been clear, sorry for my english!
[jQuery] Re: $.ajax bug ?!? Maybe i've not understand somethings ....
:) in effect i've investigated but i'm not a guru of js so i need some
help ... thanks.
last but not least :D can you explain this code:
self[callback] = window[callback];
window[callback] = (function(callback){
return function(data){
(window[callback] = self[callback])(data);
delete self[callback];
clearTimeout(timer);
};
})(callback);
On 30 Gen, 23:57, Ricardo Tomasi ricardob...@gmail.com wrote:
Ah, an oversight of mine. I forgot to add the parameter when rewriting
the callback.
Fixed as you can see athttp://jsbin.com/eliwu
Never use someone else's code without inspection ;)
On Jan 30, 4:34 pm, Stefano Corallo stefan...@gmail.com wrote:
On 30 Gen, 19:25, Ricardo Tomasi ricardob...@gmail.com wrote:
We can't access the success function of the $.ajax call without
messing with jQuery source code, because the vars that name it are
inside the jQuery function scope.
ok
In JSONP, the JSON object is passed as an argument to the callback
function. In the example I posted:
jsonFlickrFeed = function(data){ //do something with data };
i've tried but data is always undefined,take a look:
http://jsbin.com/ajimu/edit
On Jan 30, 7:28 am, Stefano Corallo stefan...@gmail.com wrote:
On 28 Gen, 17:03, Ricardo Tomasi ricardob...@gmail.com wrote:
It isn't possible to have error/success callbacks for JSONP. You can't
cancel the request either. Once you add a script tag to the head,
the browser fires a GET request and it can't be interrupted - even if
you remove the script before the response comes, the script will still
run.
ok. got it!
(the only event that fires on the script tag is 'onload', but it only
tells you if the content has successfully loaded, not the opposite.
There is no way to know if an error happened)
Also, you're misunderstanding the way JSONP works - there is no need
for a 'success' function, that is the callback function which will be
called when the response is loaded. Thats 'jsonFlickerFeed' in my
example.
Ok i've understood how jsonp work, but there's something that i can't
understand.
I try to explain better i can (sorry for my bad english)
1)Using the $.ajax method, an example:
$.ajax({
type: methodType,
url: theURL,
data: params,
dataType:jsonp,
success: function(data){
console.log(onClick success);
}
});
in the jquery core is built a temporary jsonp function to handle the
data returned by the server, if the succes function is defined the
temporary function call the succe function and pass the returned
data ... specifically at line 3314 of the jquery.1.3.1.js :
// Handle JSONP-style loading
window[ jsonp ] = function(tmp){
data = tmp;
success();
complete();
// Garbage collect
window[ jsonp ] = undefined;
try{ delete window[ jsonp ]; }
catch(e){}
if ( head )
head.removeChild( script );
};
the tmp is the data returned by the server.
Now in your example you use the jsonFlickrFeed function but without
handling the returned data from the server:
jsonFlickrFeed = function(){ alert('flickr loaded'); };
$.jsonp({
url: 'http://api.flickr.com/services/feeds/photos_public.gne?
tags=hackdayindialang=en-usformat=jsoncallback=jsonFlickrFeed',
timeout: 10,
onTimeout: function(url){ console.error('jsonp script timed out:
'+url) }
});
how to access the data returned from the server? How to modify the
$.jsonp function to call the success function defined and pass in the
data returned from the server ... this is sure possible case jquery in
$.ajax call do it, but i don't know how :-/
Many thanks, really!
I hope i've been clear, sorry for my english!
[jQuery] Re: $.ajax bug ?!? Maybe i've not understand somethings ....
That's a closure to save the 'callback' variable in it's own scope.
Actually it's not needed :)
The way that works is we create an anonymous function that will run
immediately, accepting as a parameter the callback name, and then
return a function which will be assigned to window[callback];
Like
myFunctionWithBeef = (function(x){
//'beef' is available in here in the var 'x';
return function(){...}; //this function will be stored in the
'myFunctionWithBeef' variable, and will have access to all vars in
this scope
})('beef');
Here is how it looks without it:
self.timeout = function(){
if (self[callback]){
window[callback] = function(){};
s.onTimeout(s.url);
$('head script[src$='+s.url+']').remove();
delete self[callback];
};
};
The function is already declared in the scope where 'callback' is
available, so that closure is unnecessary. I think I left it that way
because it was originally inside a timeout, which runs in the global
scope.
One thing you must be aware of is that this script will not allow two
consecutive ajax calls with the same callback function, 'cause one
will overwrite the other.
cheers,
- ricardo
On 30 jan, 22:14, Stefano Corallo stefan...@gmail.com wrote:
:) in effect i've investigated but i'm not a guru of js so i need some
help ... thanks.
last but not least :D can you explain this code:
self[callback] = window[callback];
window[callback] = (function(callback){
return function(data){
(window[callback] = self[callback])(data);
delete self[callback];
clearTimeout(timer);
};
})(callback);
On 30 Gen, 23:57, Ricardo Tomasi ricardob...@gmail.com wrote:
Ah, an oversight of mine. I forgot to add the parameter when rewriting
the callback.
Fixed as you can see athttp://jsbin.com/eliwu
Never use someone else's code without inspection ;)
On Jan 30, 4:34 pm, Stefano Corallo stefan...@gmail.com wrote:
On 30 Gen, 19:25, Ricardo Tomasi ricardob...@gmail.com wrote:
We can't access the success function of the $.ajax call without
messing with jQuery source code, because the vars that name it are
inside the jQuery function scope.
ok
In JSONP, the JSON object is passed as an argument to the callback
function. In the example I posted:
jsonFlickrFeed = function(data){ //do something with data };
i've tried but data is always undefined,take a look:
http://jsbin.com/ajimu/edit
On Jan 30, 7:28 am, Stefano Corallo stefan...@gmail.com wrote:
On 28 Gen, 17:03, Ricardo Tomasi ricardob...@gmail.com wrote:
It isn't possible to have error/success callbacks for JSONP. You
can't
cancel the request either. Once you add a script tag to the head,
the browser fires a GET request and it can't be interrupted - even
if
you remove the script before the response comes, the script will
still
run.
ok. got it!
(the only event that fires on the script tag is 'onload', but it
only
tells you if the content has successfully loaded, not the opposite.
There is no way to know if an error happened)
Also, you're misunderstanding the way JSONP works - there is no need
for a 'success' function, that is the callback function which will
be
called when the response is loaded. Thats 'jsonFlickerFeed' in my
example.
Ok i've understood how jsonp work, but there's something that i can't
understand.
I try to explain better i can (sorry for my bad english)
1)Using the $.ajax method, an example:
$.ajax({
type: methodType,
url: theURL,
data: params,
dataType:jsonp,
success: function(data){
console.log(onClick
success);
}
});
in the jquery core is built a temporary jsonp function to handle the
data returned by the server, if the succes function is defined the
temporary function call the succe function and pass the returned
data ... specifically at line 3314 of the jquery.1.3.1.js :
// Handle JSONP-style loading
window[ jsonp ] = function(tmp){
data = tmp;
success();
complete();
// Garbage collect
window[ jsonp ] = undefined;
try{ delete window[ jsonp ]; }
catch(e){}
if ( head )
head.removeChild( script );
};
the tmp is the data returned by the server.
Now in your example you
[jQuery] Re: $.ajax bug ?!? Maybe i've not understand somethings ....
thank's i'll give it a try ... stay tuned :D On 27 Gen, 22:45, Ricardo Tomasi ricardob...@gmail.com wrote: Hi Stefano, I think I found a solution. All you need to do is check if the callback has been called after your specified timeout. If it has not been called yet, overwrite it with an empty function, else do nothing. That will mess up with any further usage of the callback, but it works for this case anyway, take a look: http://jsbin.com/ukehu/http://jsbin.com/ukehu/edit Change the timeout: 1 in the $.jsonp() call to a short/long value to test it. I made the callback and timeout callback Firebug logs also. cheers, - ricardo On Jan 27, 5:01 pm, Ricardo Tomasi ricardob...@gmail.com wrote: Unless you remove the script tag after the 'timeout', of couse. On Jan 27, 9:59 am, Mike Alsup mal...@gmail.com wrote: ah and there is no way to simulate that? You can simulate a timeout in your code by using setTimeout, but it's not the same as when the XHR is used for the request. With XHR jQuery can invoke the abort fn to cancel the request. There is no such option for the jsonp script injection method. So you can not close the connection or do anything particularly useful other than assume your timeout is being called because the request failed. But then you're only guessing, and the response may return the moment after you time it out.
[jQuery] Re: $.ajax bug ?!? Maybe i've not understand somethings ....
Ok perfect :) Many thanks. So if i've understand the request continue loading and when server send back the response (if any) if the timeout as occured there is no callback set on window and do nothing else do the job have any sense try to shutdown the request? Is possible? Anyway thanks a lot. On 28 Gen, 09:23, Stefano Corallo stefan...@gmail.com wrote: thank's i'll give it a try ... stay tuned :D On 27 Gen, 22:45, Ricardo Tomasi ricardob...@gmail.com wrote: Hi Stefano, I think I found a solution. All you need to do is check if the callback has been called after your specified timeout. If it has not been called yet, overwrite it with an empty function, else do nothing. That will mess up with any further usage of the callback, but it works for this case anyway, take a look: http://jsbin.com/ukehu/http://jsbin.com/ukehu/edit Change the timeout: 1 in the $.jsonp() call to a short/long value to test it. I made the callback and timeout callback Firebug logs also. cheers, - ricardo On Jan 27, 5:01 pm, Ricardo Tomasi ricardob...@gmail.com wrote: Unless you remove the script tag after the 'timeout', of couse. On Jan 27, 9:59 am, Mike Alsup mal...@gmail.com wrote: ah and there is no way to simulate that? You can simulate a timeout in your code by using setTimeout, but it's not the same as when the XHR is used for the request. With XHR jQuery can invoke the abort fn to cancel the request. There is no such option for the jsonp script injection method. So you can not close the connection or do anything particularly useful other than assume your timeout is being called because the request failed. But then you're only guessing, and the response may return the moment after you time it out.
[jQuery] Re: $.ajax bug ?!? Maybe i've not understand somethings ....
Hi Riccardo,
i've a problem in the example you posted you do:
$.jsonp({
url: 'http://api.flickr.com/services/feeds/photos_public.gne?
tags=hackdayindialang=en-usformat=jsoncallback=jsonFlickrFeed',
timeout: 1,
onTimeout: function(url){ console.error('jsonp script timed out:
'+url) }
});
how about the success function? and the error one etc etc ?!?!
I'm tring to something like this :
.jsonp({
type: GET,
url: some.php,
data: name=Johnlocation=Boston,
timeout: 1, // in seconds
success: function(msg){
alert( Data Saved: + msg );
},
error:function(request, errorType, errorThrown){
alert(oppps );
},
onTimeout:function(url){ console.error('jsonp script timed out:
'+url) }
});
the success function is never executed (timeout or not).
In your example you've defined a function before the $.jsonp call (the
jsonFlickrFeed) and added in the url of the request ... why the
success function is not working? I've forgotten something?
Thanks.
On 28 Gen, 10:15, Stefano Corallo stefan...@gmail.com wrote:
Ok perfect :) Many thanks.
So if i've understand the request continue loading and when server
send back the response (if any) if the timeout as occured there is no
callback set on window and do nothing else do the job have any
sense try to shutdown the request? Is possible?
Anyway thanks a lot.
On 28 Gen, 09:23, Stefano Corallo stefan...@gmail.com wrote:
thank's i'll give it a try ... stay tuned :D
On 27 Gen, 22:45, Ricardo Tomasi ricardob...@gmail.com wrote:
Hi Stefano, I think I found a solution. All you need to do is check if
the callback has been called after your specified timeout. If it has
not been called yet, overwrite it with an empty function, else do
nothing. That will mess up with any further usage of the callback, but
it works for this case anyway, take a look:
http://jsbin.com/ukehu/http://jsbin.com/ukehu/edit
Change the timeout: 1 in the $.jsonp() call to a short/long value to
test it. I made the callback and timeout callback Firebug logs also.
cheers,
- ricardo
On Jan 27, 5:01 pm, Ricardo Tomasi ricardob...@gmail.com wrote:
Unless you remove the script tag after the 'timeout', of couse.
On Jan 27, 9:59 am, Mike Alsup mal...@gmail.com wrote:
ah and there is no way to simulate that?
You can simulate a timeout in your code by using setTimeout, but it's
not the same as when the XHR is used for the request. With XHR jQuery
can invoke the abort fn to cancel the request. There is no such
option for the jsonp script injection method. So you can not close
the connection or do anything particularly useful other than assume
your timeout is being called because the request failed. But then
you're only guessing, and the response may return the moment after you
time it out.
[jQuery] Re: $.ajax bug ?!? Maybe i've not understand somethings ....
It isn't possible to have error/success callbacks for JSONP. You can't
cancel the request either. Once you add a script tag to the head,
the browser fires a GET request and it can't be interrupted - even if
you remove the script before the response comes, the script will still
run.
(the only event that fires on the script tag is 'onload', but it only
tells you if the content has successfully loaded, not the opposite.
There is no way to know if an error happened)
Also, you're misunderstanding the way JSONP works - there is no need
for a 'success' function, that is the callback function which will be
called when the response is loaded. Thats 'jsonFlickerFeed' in my
example.
cheers,
- ricardo
On Jan 28, 10:07 am, Stefano Corallo stefan...@gmail.com wrote:
Hi Riccardo,
i've a problem in the example you posted you do:
$.jsonp({
url: 'http://api.flickr.com/services/feeds/photos_public.gne?
tags=hackdayindialang=en-usformat=jsoncallback=jsonFlickrFeed',
timeout: 1,
onTimeout: function(url){ console.error('jsonp script timed out:
'+url) }
});
how about the success function? and the error one etc etc ?!?!
I'm tring to something like this :
.jsonp({
type: GET,
url: some.php,
data: name=Johnlocation=Boston,
timeout: 1, // in seconds
success: function(msg){
alert( Data Saved: + msg );
},
error:function(request, errorType, errorThrown){
alert(oppps );
},
onTimeout:function(url){ console.error('jsonp script timed out:
'+url) }
});
the success function is never executed (timeout or not).
In your example you've defined a function before the $.jsonp call (the
jsonFlickrFeed) and added in the url of the request ... why the
success function is not working? I've forgotten something?
Thanks.
On 28 Gen, 10:15, Stefano Corallo stefan...@gmail.com wrote:
Ok perfect :) Many thanks.
So if i've understand the request continue loading and when server
send back the response (if any) if the timeout as occured there is no
callback set on window and do nothing else do the job have any
sense try to shutdown the request? Is possible?
Anyway thanks a lot.
On 28 Gen, 09:23, Stefano Corallo stefan...@gmail.com wrote:
thank's i'll give it a try ... stay tuned :D
On 27 Gen, 22:45, Ricardo Tomasi ricardob...@gmail.com wrote:
Hi Stefano, I think I found a solution. All you need to do is check if
the callback has been called after your specified timeout. If it has
not been called yet, overwrite it with an empty function, else do
nothing. That will mess up with any further usage of the callback, but
it works for this case anyway, take a look:
http://jsbin.com/ukehu/http://jsbin.com/ukehu/edit
Change the timeout: 1 in the $.jsonp() call to a short/long value to
test it. I made the callback and timeout callback Firebug logs also.
cheers,
- ricardo
On Jan 27, 5:01 pm, Ricardo Tomasi ricardob...@gmail.com wrote:
Unless you remove the script tag after the 'timeout', of couse.
On Jan 27, 9:59 am, Mike Alsup mal...@gmail.com wrote:
ah and there is no way to simulate that?
You can simulate a timeout in your code by using setTimeout, but
it's
not the same as when the XHR is used for the request. With XHR
jQuery
can invoke the abort fn to cancel the request. There is no such
option for the jsonp script injection method. So you can not close
the connection or do anything particularly useful other than assume
your timeout is being called because the request failed. But then
you're only guessing, and the response may return the moment after
you
time it out.
[jQuery] Re: $.ajax bug ?!? Maybe i've not understand somethings ....
In this case the execution stop because the return statement and there
is no way to setup the onreadystatefunction and other stuff coded down
after the statement
if ( s.dataType == script type == GET parts
( parts[1] parts[1] != location.protocol ||
parts[2] !=
location.host )){
This in my case generate a non correct handling of the timeout lookup
but maybe there are other problem i'm not able to see.
Thank's for help and clarifications.
This is because ajax can not be used x-domain due to browser security.
http://docs.jquery.com/Ajax/jQuery.ajax#options
[jQuery] Re: $.ajax bug ?!? Maybe i've not understand somethings ....
yes ok but i've set the jsonp option to avoid this problem like
explained in
http://bob.pythonmac.org/archives/2005/12/05/remote-json-jsonp/
that i've found http://docs.jquery.com/Ajax/jQuery.ajax#options
i'm wrong?
On 27 Gen, 12:06, Mike Alsup mal...@gmail.com wrote:
In this case the execution stop because the return statement and there
is no way to setup the onreadystatefunction and other stuff coded down
after the statement
if ( s.dataType == script type == GET parts
( parts[1] parts[1] != location.protocol ||
parts[2] !=
location.host )){
This in my case generate a non correct handling of the timeout lookup
but maybe there are other problem i'm not able to see.
Thank's for help and clarifications.
This is because ajax can not be used x-domain due to browser security.
http://docs.jquery.com/Ajax/jQuery.ajax#options
[jQuery] Re: $.ajax bug ?!? Maybe i've not understand somethings ....
With the jsonp option i'm able to do cross domain request but i can't
control the timeout and i'm wondering about why?
On 27 Gen, 12:22, Stefano Corallo stefan...@gmail.com wrote:
yes ok but i've set the jsonp option to avoid this problem like
explained in
http://bob.pythonmac.org/archives/2005/12/05/remote-json-jsonp/
that i've foundhttp://docs.jquery.com/Ajax/jQuery.ajax#options
i'm wrong?
On 27 Gen, 12:06, Mike Alsup mal...@gmail.com wrote:
In this case the execution stop because the return statement and there
is no way to setup the onreadystatefunction and other stuff coded down
after the statement
if ( s.dataType == script type == GET parts
( parts[1] parts[1] != location.protocol ||
parts[2] !=
location.host )){
This in my case generate a non correct handling of the timeout lookup
but maybe there are other problem i'm not able to see.
Thank's for help and clarifications.
This is because ajax can not be used x-domain due to browser security.
http://docs.jquery.com/Ajax/jQuery.ajax#options
[jQuery] Re: $.ajax bug ?!? Maybe i've not understand somethings ....
With the jsonp option i'm able to do cross domain request but i can't control the timeout and i'm wondering about why? On 27 Gen, 12:22, Stefano Corallo stefan...@gmail.com wrote: yes ok but i've set the jsonp option to avoid this problem like explained in http://bob.pythonmac.org/archives/2005/12/05/remote-json-jsonp/ that i've foundhttp://docs.jquery.com/Ajax/jQuery.ajax#options This is because ajax is not being used. There are no readystatechange callbacks and there is no way to cancel an outstanding jsonp request. In other words, there is no way to reliably implement timeout.
[jQuery] Re: $.ajax bug ?!? Maybe i've not understand somethings ....
ah and there is no way to simulate that? i want close the connection with the server if the request take a long time, and do something default like a message or other stuff ... what can i do? On 27 Gen, 12:30, Mike Alsup mal...@gmail.com wrote: With the jsonp option i'm able to do cross domain request but i can't control the timeout and i'm wondering about why? On 27 Gen, 12:22, Stefano Corallo stefan...@gmail.com wrote: yes ok but i've set the jsonp option to avoid this problem like explained in http://bob.pythonmac.org/archives/2005/12/05/remote-json-jsonp/ that i've foundhttp://docs.jquery.com/Ajax/jQuery.ajax#options This is because ajax is not being used. There are no readystatechange callbacks and there is no way to cancel an outstanding jsonp request. In other words, there is no way to reliably implement timeout.
[jQuery] Re: $.ajax bug ?!? Maybe i've not understand somethings ....
ah and there is no way to simulate that? You can simulate a timeout in your code by using setTimeout, but it's not the same as when the XHR is used for the request. With XHR jQuery can invoke the abort fn to cancel the request. There is no such option for the jsonp script injection method. So you can not close the connection or do anything particularly useful other than assume your timeout is being called because the request failed. But then you're only guessing, and the response may return the moment after you time it out.
[jQuery] Re: $.ajax bug ?!? Maybe i've not understand somethings ....
Unless you remove the script tag after the 'timeout', of couse. On Jan 27, 9:59 am, Mike Alsup mal...@gmail.com wrote: ah and there is no way to simulate that? You can simulate a timeout in your code by using setTimeout, but it's not the same as when the XHR is used for the request. With XHR jQuery can invoke the abort fn to cancel the request. There is no such option for the jsonp script injection method. So you can not close the connection or do anything particularly useful other than assume your timeout is being called because the request failed. But then you're only guessing, and the response may return the moment after you time it out.
[jQuery] Re: $.ajax bug ?!? Maybe i've not understand somethings ....
Hi Stefano, I think I found a solution. All you need to do is check if the callback has been called after your specified timeout. If it has not been called yet, overwrite it with an empty function, else do nothing. That will mess up with any further usage of the callback, but it works for this case anyway, take a look: http://jsbin.com/ukehu/ http://jsbin.com/ukehu/edit Change the timeout: 1 in the $.jsonp() call to a short/long value to test it. I made the callback and timeout callback Firebug logs also. cheers, - ricardo On Jan 27, 5:01 pm, Ricardo Tomasi ricardob...@gmail.com wrote: Unless you remove the script tag after the 'timeout', of couse. On Jan 27, 9:59 am, Mike Alsup mal...@gmail.com wrote: ah and there is no way to simulate that? You can simulate a timeout in your code by using setTimeout, but it's not the same as when the XHR is used for the request. With XHR jQuery can invoke the abort fn to cancel the request. There is no such option for the jsonp script injection method. So you can not close the connection or do anything particularly useful other than assume your timeout is being called because the request failed. But then you're only guessing, and the response may return the moment after you time it out.
[jQuery] Re: $.ajax bug ?!? Maybe i've not understand somethings ....
Hi Stefano, I think I found a solution. All you need to do is check if the callback has been called after your specified timeout. If it has not been called yet, overwrite it with an empty function, else do nothing. That will mess up with any further usage of the callback, but it works for this case anyway, take a look: Cool idea, Ricardo. :-)
