[jQuery] Re: "$(document).ready(function() {" giving error "$ is not a function" - what am I doing wrong?
On Fri, May 9, 2008 at 10:21 AM, Fred P <[EMAIL PROTECTED]> wrote:
>
> A little more specific:
>
> You're using jQuery.noConflict() which allows you to use the variable
> jQuery
Pardon me for being a little pedantic: jQuery.noConflict does not allow you
to use the variable jQuery. The jQuery variable is there either way. If not,
you couldn't call jQuery.noConflict() ;)
jQuery.noConflict allows you to use the $ alias for something other than
jQuery, by returning it to its previously defined value.
Another option should be mentioned (for completeness). If you have a bunch
of javascript/jQuery code that's already written to use the $, and you don't
want to search and replace the $ with jQuery, you can use the following
pattern to have the $ alias be jQuery inside a block with all your jQuery
code, after calling jQuery.noConflict:
(function($) {
// Inside this block, $ is the jQuery object
// not the other $
})(jQuery);
- Richard
[jQuery] Re: "$(document).ready(function() {" giving error "$ is not a function" - what am I doing wrong?
A little more specific:
You're using jQuery.noConflict() which allows you to use the variable
jQuery
"
jQuery(document).ready( function() {
jQuery("#sliding_cart").css({ display: "none"});
});
"
then later in your doc, you're using $ which is the same thing, if
you're not using jQuery.noConflict(). However, it's one or the other,
not both.
"
$(document).ready(function() {
$("a").click(function(){
alert("Thanks for visiting!");
});
});
"
If you're using Prototype.js or any other JS Library that may use $,
then you need noConflict. If you're sure you'll never use any other JS
Library, then drop the noConflict and use $ instead of jQuery variable
everywhere.
If you're using some plugins or third party script asking you to use
noConflict for any reason, then use jQuery instead of $ (like those
guys:
http://blog.evaria.com/wp-content/themes/blogvaria/jquery/index-multi.php).
Fred
[jQuery] Re: "$(document).ready(function() {" giving error "$ is not a function" - what am I doing wrong?
You are using jQuery.noConflict() which unbinds the jquery object from
the $ namespace so jQuery('a') still works on your site just $('a')
does not
from a cursory glace i cant see any reason for using the noConflict
function, remove that and your code will work.
On May 9, 12:11 pm, "[EMAIL PROTECTED]" <[EMAIL PROTECTED]>
wrote:
> Test page here -http://www.justice.net.nz/static.html
>
> Jquery is definitely being loaded - I'm currently pulling it from
> jquery.com, and Firebug is showing that it has loaded.
>
> Any ideas? This is my first attempt at jquery and I'm falling at the
> first hurdle :<
[jQuery] Re: "$(document).ready(function() {" giving error "$ is not a function" - what am I doing wrong?
cherry austin - good idea, but not quite :)
Kenthumphrey,
You've declared jQuery.noConflict(); . This reverts $ back to its
previous value, in this case undefined. Either remove
jQuery.noConflict() or replace $(document).read(function(){}); with
jQuery(document).ready(function($){});
On May 8, 8:11 pm, "[EMAIL PROTECTED]" <[EMAIL PROTECTED]>
wrote:
> Test page here -http://www.justice.net.nz/static.html
>
> Jquery is definitely being loaded - I'm currently pulling it from
> jquery.com, and Firebug is showing that it has loaded.
>
> Any ideas? This is my first attempt at jquery and I'm falling at the
> first hurdle :<
[jQuery] Re: "$(document).ready(function() {" giving error "$ is not a function" - what am I doing wrong?
Line 135: jQuery.noConflict(); This turns off the $ alias in case you're using jQuery with another library that wants it. Simply use jQuery in place of each $. Or, if you don't need it, remove the noConflict call. - Richard On Thu, May 8, 2008 at 8:11 PM, [EMAIL PROTECTED] < [EMAIL PROTECTED]> wrote: > > Test page here - http://www.justice.net.nz/static.html > > Jquery is definitely being loaded - I'm currently pulling it from > jquery.com, and Firebug is showing that it has loaded. > > Any ideas? This is my first attempt at jquery and I'm falling at the > first hurdle :< >
[jQuery] Re: "$(document).ready(function() {" giving error "$ is not a function" - what am I doing wrong?
Hi, Kent. I'm a beginner myself, so I'm replying to you in the hope that one of this group's more-experienced gurus will pick up! It looks to me like you've bunged jQuery in the middle of a bunch of other javascript (some of which was actually meant to work with jQuery; it won't do too well outside your "document.ready" function). The jQuery call is equivalent to .onload in that it begins when the DOM has fully loaded. You probably already read this: http://docs.jquery.com/How_jQuery_Works#Launching_Code_on_Document_Ready Why not try putting all of your javascript calls INSIDE the jQuery function, and see what happens? And hope somebody better-qualified than me replies to your post ;) Cherry. On May 9, 1:11 am, "[EMAIL PROTECTED]" <[EMAIL PROTECTED]> wrote: > Test page here -http://www.justice.net.nz/static.html > > Jquery is definitely being loaded - I'm currently pulling it from > jquery.com, and Firebug is showing that it has loaded. > > Any ideas? This is my first attempt at jquery and I'm falling at the > first hurdle :<
