Michael,
You were right my markup was a little messed up. I cleaned it up and used
$('#master').children().size()
and it worked for what I needed. Thanks for your quick response and you
detailed explanation.
Thanks again,
Ronn
On Thu, Sep 4, 2008 at 11:44 AM, Michael Geary <[EMAIL PROTECTED]> wrote:
> Ronn, your description doesn't match your code. The description says you
> want to "count the 'group#' divs inside of the 'master' div", but the code
> counts the immediate children of the #master div.
>
> Now, given the HTML you posted, those happen to be the same value, since
> the only immediate children of #master are the group divs. Just checking
> that this assumption will remain valid.
>
> Assuming that you actually want to count the immediate children of
> div#master, your code looks like it should work. What result does it give
> you?
>
> I would probably do it this way:
>
> var ct = $('#master > *').length;
>
> But that should give the same result. (You might try it just for
> comparison.)
>
> Can you post a link to a test page? It's hard to tell what might be wrong
> without seeing it in action.
>
> And do you have Firebug? You can open your page and try stuff out in the
> Firebug console (click in the single line at the bottom of the console to
> enter JavaScript code). Try these and see what you get (you can use the up
> arrow key to bring back a previous entry, so you don't have to retype the
> whole thing each time):
>
> $('#master')
>
> $('#master').children()
>
> $('#master').children().size()
>
> $('#master > *')
>
> $('#master > *').length
>
> -Mike
>
> --
> *From:* Ronn Ross
> Hello all
> I have seen examples of counting children of an element like a div. I have
> tried to customize those examples to work for my situation, but with no
> success. What I'm trying to accomplish seems simple, but I have not been
> able to make it happen. I'm simply trying to count the 'group#' divs inside
> of the 'master' div. I was hoping that something like:
>
>var ct = $('#master').children().size();
>
> would work, but being new to JQuery I have not been able to find a
> solution.
> Thanks in advance,
>
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