[julia-users] Re: Debug printing a “value” and its “symbol”
I think you need a macro, something like: macro printvar(var) return :(print($(string(var))); print(=); println($var)) end julia a=2 2 julia @printvar a a=2 Cheers Lex On Sunday, January 4, 2015 8:48:27 PM UTC+10, Arch Call wrote: I frequently find myself writing Julia snippet scripts like this: vara = 33 varb = vara * 14 varc = varb * 77 println(“varb = “, varb) #--debug print println(“varc = “, varc) #--debug print I would like to eliminate having to enter the variable name twice in the debug print lines by using a function. I have tried all kinds of variations of a debug print function like: function debugprint(somevar) println(“ = ”, somevar) end What can I put in place of “” to get the actual Symbol of the variable being passed to debugprint?
[julia-users] Re: Debug printing a “value” and its “symbol”
Thanks so much Lex .. That works ... Arch On Sunday, January 4, 2015 5:48:27 AM UTC-5, Arch Call wrote: I frequently find myself writing Julia snippet scripts like this: vara = 33 varb = vara * 14 varc = varb * 77 println(“varb = “, varb) #--debug print println(“varc = “, varc) #--debug print I would like to eliminate having to enter the variable name twice in the debug print lines by using a function. I have tried all kinds of variations of a debug print function like: function debugprint(somevar) println(“ = ”, somevar) end What can I put in place of “” to get the actual Symbol of the variable being passed to debugprint?
Re: [julia-users] Re: Debug printing a “value” and its “symbol”
Have you met @show? On 4 January 2015 at 11:10, ele...@gmail.com wrote: I think you need a macro, something like: macro printvar(var) return :(print($(string(var))); print(=); println($var)) end julia a=2 2 julia @printvar a a=2 Cheers Lex On Sunday, January 4, 2015 8:48:27 PM UTC+10, Arch Call wrote: I frequently find myself writing Julia snippet scripts like this: vara = 33 varb = vara * 14 varc = varb * 77 println(“varb = “, varb) #--debug print println(“varc = “, varc) #--debug print I would like to eliminate having to enter the variable name twice in the debug print lines by using a function. I have tried all kinds of variations of a debug print function like: function debugprint(somevar) println(“ = ”, somevar) end What can I put in place of “” to get the actual Symbol of the variable being passed to debugprint?
Re: [julia-users] Re: Debug printing a “value” and its “symbol”
julia begin @show vara = 33 @show varb = vara * 14 @show varc = varb * 77 end vara = 33 = 33 varb = vara * 14 = 462 varc = varb * 77 = 35574 35574 On Sun, Jan 4, 2015 at 5:47 AM, Mike Innes mike.j.in...@gmail.com wrote: Have you met @show? On 4 January 2015 at 11:10, ele...@gmail.com wrote: I think you need a macro, something like: macro printvar(var) return :(print($(string(var))); print(=); println($var)) end julia a=2 2 julia @printvar a a=2 Cheers Lex On Sunday, January 4, 2015 8:48:27 PM UTC+10, Arch Call wrote: I frequently find myself writing Julia snippet scripts like this: vara = 33 varb = vara * 14 varc = varb * 77 println(“varb = “, varb) #--debug print println(“varc = “, varc) #--debug print I would like to eliminate having to enter the variable name twice in the debug print lines by using a function. I have tried all kinds of variations of a debug print function like: function debugprint(somevar) println(“ = ”, somevar) end What can I put in place of “” to get the actual Symbol of the variable being passed to debugprint?
Re: [julia-users] Re: Debug printing a “value” and its “symbol”
Reading the code, there is also a `indent` option, i thought it accepted a boolean, but not, I find it very unintuitive: dump(io::IO, x, n::Int, indent) = xdump(dump, io, x, n, indent) julia dump(:(1 + 1 * 3 - 4^7), 10, false) Expr false head: Symbol call false args: Array(Any,(3,)) false1: Symbol - false2: Expr false head: Symbol call false args: Array(Any,(3,)) false1: Symbol + false2: Int32 1 false3: Expr false head: Symbol call false args: Array(Any,(3,)) false1: Symbol * false2: Int32 1 false3: Int32 3 false typ: Any false typ: Any false3: Expr false head: Symbol call false args: Array(Any,(3,)) false1: Symbol ^ false2: Int32 4 false3: Int32 7 false typ: Any false typ: Any And once can't use this argument, as a keyword argument: julia dump(:(1 + 1 * 3 - 4^7), indent=---) ERROR: function dump does not accept keyword arguments Keyword arguments are slow? Or why are the not used that much throughout the API? El domingo, 4 de enero de 2015 09:53:35 UTC-6, Ismael VC escribió: julia begin @show vara = 33 @show varb = vara * 14 @show varc = varb * 77 end vara = 33 = 33 varb = vara * 14 = 462 varc = varb * 77 = 35574 35574 On Sun, Jan 4, 2015 at 5:47 AM, Mike Innes mike.j.in...@gmail.com wrote: Have you met @show? On 4 January 2015 at 11:10, ele...@gmail.com wrote: I think you need a macro, something like: macro printvar(var) return :(print($(string(var))); print(=); println($var)) end julia a=2 2 julia @printvar a a=2 Cheers Lex On Sunday, January 4, 2015 8:48:27 PM UTC+10, Arch Call wrote: I frequently find myself writing Julia snippet scripts like this: vara = 33 varb = vara * 14 varc = varb * 77 println(“varb = “, varb) #--debug print println(“varc = “, varc) #--debug print I would like to eliminate having to enter the variable name twice in the debug print lines by using a function. I have tried all kinds of variations of a debug print function like: function debugprint(somevar) println(“ = ”, somevar) end What can I put in place of “” to get the actual Symbol of the variable being passed to debugprint?
[julia-users] Re: Debug printing a “value” and its “symbol”
Thanks Mike, I have used show before, but not @show...Arch On Sunday, January 4, 2015 5:48:27 AM UTC-5, Arch Call wrote: I frequently find myself writing Julia snippet scripts like this: vara = 33 varb = vara * 14 varc = varb * 77 println(“varb = “, varb) #--debug print println(“varc = “, varc) #--debug print I would like to eliminate having to enter the variable name twice in the debug print lines by using a function. I have tried all kinds of variations of a debug print function like: function debugprint(somevar) println(“ = ”, somevar) end What can I put in place of “” to get the actual Symbol of the variable being passed to debugprint?
