Re: [julia-users] Re: Debug printing a “value” and its “symbol”
Have you met @show?
On 4 January 2015 at 11:10, wrote:
> I think you need a macro, something like:
>
> macro printvar(var)
>return :(print($(string(var))); print("="); println($var))
> end
>
> julia> a=2
> 2
>
> julia> @printvar a
> a=2
>
> Cheers
> Lex
>
> On Sunday, January 4, 2015 8:48:27 PM UTC+10, Arch Call wrote:
>>
>> I frequently find myself writing Julia snippet scripts like this:
>>
>>
>> vara = 33
>>
>> varb = vara * 14
>>
>> varc = varb * 77
>>
>> println(“varb = “, varb) #--debug print
>>
>> println(“varc = “, varc) #--debug print
>>
>>
>> I would like to eliminate having to enter the variable name twice
>>
>> in the debug print lines by using a function.
>>
>>
>> I have tried all kinds of variations of a debug print function like:
>>
>>
>> function debugprint(somevar)
>>
>> println(“ = ”, somevar)
>>
>> end
>>
>>
>> What can I put in place of “” to get the actual Symbol of the
>> variable being passed to debugprint?
>>
>
Re: [julia-users] Re: Debug printing a “value” and its “symbol”
julia> begin
@show vara = 33
@show varb = vara * 14
@show varc = varb * 77
end
vara = 33 = 33
varb = vara * 14 = 462
varc = varb * 77 = 35574
35574
On Sun, Jan 4, 2015 at 5:47 AM, Mike Innes wrote:
> Have you met @show?
>
> On 4 January 2015 at 11:10, wrote:
>
>> I think you need a macro, something like:
>>
>> macro printvar(var)
>>return :(print($(string(var))); print("="); println($var))
>> end
>>
>> julia> a=2
>> 2
>>
>> julia> @printvar a
>> a=2
>>
>> Cheers
>> Lex
>>
>> On Sunday, January 4, 2015 8:48:27 PM UTC+10, Arch Call wrote:
>>>
>>> I frequently find myself writing Julia snippet scripts like this:
>>>
>>>
>>> vara = 33
>>>
>>> varb = vara * 14
>>>
>>> varc = varb * 77
>>>
>>> println(“varb = “, varb) #--debug print
>>>
>>> println(“varc = “, varc) #--debug print
>>>
>>>
>>> I would like to eliminate having to enter the variable name twice
>>>
>>> in the debug print lines by using a function.
>>>
>>>
>>> I have tried all kinds of variations of a debug print function like:
>>>
>>>
>>> function debugprint(somevar)
>>>
>>> println(“ = ”, somevar)
>>>
>>> end
>>>
>>>
>>> What can I put in place of “” to get the actual Symbol of the
>>> variable being passed to debugprint?
>>>
>>
>
Re: [julia-users] Re: Debug printing a “value” and its “symbol”
Reading the code, there is also a `indent` option, i thought it accepted a
boolean, but not, I find it very unintuitive:
dump(io::IO, x, n::Int, indent) = xdump(dump, io, x, n, indent)
julia> dump(:(1 + 1 * 3 - 4^7), 10, false)
Expr
false head: Symbol call
false args: Array(Any,(3,))
false1: Symbol -
false2: Expr
false head: Symbol call
false args: Array(Any,(3,))
false1: Symbol +
false2: Int32 1
false3: Expr
false head: Symbol call
false args: Array(Any,(3,))
false1: Symbol *
false2: Int32 1
false3: Int32 3
false typ: Any
false typ: Any
false3: Expr
false head: Symbol call
false args: Array(Any,(3,))
false1: Symbol ^
false2: Int32 4
false3: Int32 7
false typ: Any
false typ: Any
And once can't use this argument, as a keyword argument:
julia> dump(:(1 + 1 * 3 - 4^7), indent="--->")
ERROR: function dump does not accept keyword arguments
Keyword arguments are slow? Or why are the not used that much throughout
the API?
El domingo, 4 de enero de 2015 09:53:35 UTC-6, Ismael VC escribió:
>
> julia> begin
>@show vara = 33
>@show varb = vara * 14
>@show varc = varb * 77
>end
> vara = 33 = 33
> varb = vara * 14 = 462
> varc = varb * 77 = 35574
> 35574
>
>
> On Sun, Jan 4, 2015 at 5:47 AM, Mike Innes wrote:
>
>> Have you met @show?
>>
>> On 4 January 2015 at 11:10, wrote:
>>
>>> I think you need a macro, something like:
>>>
>>> macro printvar(var)
>>>return :(print($(string(var))); print("="); println($var))
>>> end
>>>
>>> julia> a=2
>>> 2
>>>
>>> julia> @printvar a
>>> a=2
>>>
>>> Cheers
>>> Lex
>>>
>>> On Sunday, January 4, 2015 8:48:27 PM UTC+10, Arch Call wrote:
I frequently find myself writing Julia snippet scripts like this:
vara = 33
varb = vara * 14
varc = varb * 77
println(“varb = “, varb) #--debug print
println(“varc = “, varc) #--debug print
I would like to eliminate having to enter the variable name twice
in the debug print lines by using a function.
I have tried all kinds of variations of a debug print function like:
function debugprint(somevar)
println(“ = ”, somevar)
end
What can I put in place of “” to get the actual Symbol of the
variable being passed to debugprint?
>>>
>>
>
