Re: lingo-l joining lists in lingo

2005-04-11 Thread Ozkan ALTUNER
Hello Tim,

You can do it by appending list two to list one, by using a loop and getAt(), 
getPropAt(), addProp() and addAt() methods.

repeat with i = 1 to list2.count()
  addProp(list1, getAt(list2, i)
end repeat

i'm not exatcly sure of the syntax, however, it clearly should give you an idea.

Ciao,
Ozkan


-Orjinal mesaj-
From: Tim Welford [EMAIL PROTECTED]

Date: Mon, 11 Apr 2005 14:28:10 +0300
To: lingo-l@penworks.com
Subject: lingo-l joining lists in lingo

 Greetings List...
 
 I'm sure this is a daft question, but it escapes me.
 Is there away of joining 2 lists together other than looping through the
 second list and using .add to add it to the first list.
 
 i.e.
 list1 = [1,2,3,4]
 list2 = [5,6,7,8]
 
 list1 + list2 = [1,2,3,4,5,6,7,8]
 
 rather than a result of [6,8,10,12]
 or [1,2,3,4,[5,6,7,8]]
 
 This is just an example, I actually need to do it with a list of
 property lists, whilst the list is quite complicated, the format of the
 2 lists being joined will always be exactly the same, although the
 number of elements may change.
 
 Thanks
 
 Tim
 
 
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RE: lingo-l joining lists in lingo

2005-04-11 Thread Tim Welford
Hi,

Thanks, that's similar to the method I am using at the moment. I was
hoping for some undocumented way of doing a simple join to get rid of
the repeat loop and hence improve the efficiency of the code.

-Original Message-
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] On Behalf Of Ozkan
ALTUNER
Sent: 11 April 2005 13:15
To: Lingo programming discussion list
Subject: Re: lingo-l joining lists in lingo

Hello Tim,

You can do it by appending list two to list one, by using a loop and
getAt(), getPropAt(), addProp() and addAt() methods.

repeat with i = 1 to list2.count()
  addProp(list1, getAt(list2, i)
end repeat

i'm not exatcly sure of the syntax, however, it clearly should give you
an idea.

Ciao,
Ozkan


-Orjinal mesaj-
From: Tim Welford [EMAIL PROTECTED]

Date: Mon, 11 Apr 2005 14:28:10 +0300
To: lingo-l@penworks.com
Subject: lingo-l joining lists in lingo

 Greetings List...
 
 I'm sure this is a daft question, but it escapes me.
 Is there away of joining 2 lists together other than looping through
the
 second list and using .add to add it to the first list.
 
 i.e.
 list1 = [1,2,3,4]
 list2 = [5,6,7,8]
 
 list1 + list2 = [1,2,3,4,5,6,7,8]
 
 rather than a result of [6,8,10,12]
 or [1,2,3,4,[5,6,7,8]]
 
 This is just an example, I actually need to do it with a list of
 property lists, whilst the list is quite complicated, the format of
the
 2 lists being joined will always be exactly the same, although the
 number of elements may change.
 
 Thanks
 
 Tim
 
 
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RE: lingo-l joining lists in lingo

2005-04-11 Thread Martin Pallett
Hi,
there was quite an extensive discussion of this on Direct-L a couple of 
weeks ago - go to

http://listserv.uark.edu/scripts/wa.exe?S1=direct-l
and search for subject How does one concatenate 2 lists together? 
HTH
cheers,
Martin Pallett
At 13:48 11/04/2005 +0100, you wrote:
Hi,
Thanks, that's similar to the method I am using at the moment. I was
hoping for some undocumented way of doing a simple join to get rid of
the repeat loop and hence improve the efficiency of the code.
-Original Message-
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] On Behalf Of Ozkan
ALTUNER
Sent: 11 April 2005 13:15
To: Lingo programming discussion list
Subject: Re: lingo-l joining lists in lingo
Hello Tim,
You can do it by appending list two to list one, by using a loop and
getAt(), getPropAt(), addProp() and addAt() methods.
repeat with i = 1 to list2.count()
  addProp(list1, getAt(list2, i)
end repeat
i'm not exatcly sure of the syntax, however, it clearly should give you
an idea.
Ciao,
Ozkan
Spike
Rowe House
Emson Close
Saffron Walden
UK  CB10 1HL
+44 (0) 1799 529 100
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Re: lingo-l joining lists in lingo

2005-04-11 Thread Valentin Schmidt
Hi Tim,

it won't help you in this situation, but in DMX2004 for javascript there
is the concat() function for arrays:

var a = Array(1,2,3);
var b = Array(4,5,6);
trace(a.concat(b));
// 1,2,3,4,5,6

Valentin



Tim Welford wrote:
 Hi,

 Thanks, that's similar to the method I am using at the moment. I was
 hoping for some undocumented way of doing a simple join to get rid of
 the repeat loop and hence improve the efficiency of the code.

 -Original Message-
 From: [EMAIL PROTECTED]
 [mailto:[EMAIL PROTECTED] On Behalf Of Ozkan
 ALTUNER
 Sent: 11 April 2005 13:15
 To: Lingo programming discussion list
 Subject: Re: lingo-l joining lists in lingo

 Hello Tim,

 You can do it by appending list two to list one, by using a loop and
 getAt(), getPropAt(), addProp() and addAt() methods.

 repeat with i = 1 to list2.count()
   addProp(list1, getAt(list2, i)
 end repeat

 i'm not exatcly sure of the syntax, however, it clearly should give
 you
 an idea.

 Ciao,
 Ozkan


 -Orjinal mesaj-
 From: Tim Welford [EMAIL PROTECTED]

 Date: Mon, 11 Apr 2005 14:28:10 +0300
 To: lingo-l@penworks.com
 Subject: lingo-l joining lists in lingo

 Greetings List...

 I'm sure this is a daft question, but it escapes me.
 Is there away of joining 2 lists together other than looping through
 the
 second list and using .add to add it to the first list.

 i.e.
 list1 = [1,2,3,4]
 list2 = [5,6,7,8]

 list1 + list2 = [1,2,3,4,5,6,7,8]

 rather than a result of [6,8,10,12]
 or [1,2,3,4,[5,6,7,8]]

 This is just an example, I actually need to do it with a list of
 property lists, whilst the list is quite complicated, the format of
 the
 2 lists being joined will always be exactly the same, although the
 number of elements may change.

 Thanks

 Tim


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RE: lingo-l joining lists in lingo

2005-04-11 Thread Dam
Hi Tim,
maybe this could fit

list1 = [1,2,3,4]
list2 = [5,6,7,8]
---
s1 = string(list1)
s2 = string(list2)
---
res1 = s1.char[1..s1.length - 1]
res2 = s2.char[2..s2.length]
---
put value(res1  ,  res2)
-- [1, 2, 3, 4, 5, 6, 7, 8]
 
 
Dam


On Apr 11, 2005 3:16 PM, Valentin Schmidt [EMAIL PROTECTED] wrote:
 Hi Tim,
 
 it won't help you in this situation, but in DMX2004 for javascript there
 is the concat() function for arrays:
 
 var a = Array(1,2,3);
 var b = Array(4,5,6);
 trace(a.concat(b));
 // 1,2,3,4,5,6
 
 Valentin
 
 
 Tim Welford wrote:
  Hi,
 
  Thanks, that's similar to the method I am using at the moment. I was
  hoping for some undocumented way of doing a simple join to get rid of
  the repeat loop and hence improve the efficiency of the code.
 
  -Original Message-
  From: [EMAIL PROTECTED]
  [mailto:[EMAIL PROTECTED] On Behalf Of Ozkan
  ALTUNER
  Sent: 11 April 2005 13:15
  To: Lingo programming discussion list
  Subject: Re: lingo-l joining lists in lingo
 
  Hello Tim,
 
  You can do it by appending list two to list one, by using a loop and
  getAt(), getPropAt(), addProp() and addAt() methods.
 
  repeat with i = 1 to list2.count()
addProp(list1, getAt(list2, i)
  end repeat
 
  i'm not exatcly sure of the syntax, however, it clearly should give
  you
  an idea.
 
  Ciao,
  Ozkan
 
 
  -Orjinal mesaj-
  From: Tim Welford [EMAIL PROTECTED]
 
  Date: Mon, 11 Apr 2005 14:28:10 +0300
  To: lingo-l@penworks.com
  Subject: lingo-l joining lists in lingo
 
  Greetings List...
 
  I'm sure this is a daft question, but it escapes me.
  Is there away of joining 2 lists together other than looping through
  the
  second list and using .add to add it to the first list.
 
  i.e.
  list1 = [1,2,3,4]
  list2 = [5,6,7,8]
 
  list1 + list2 = [1,2,3,4,5,6,7,8]
 
  rather than a result of [6,8,10,12]
  or [1,2,3,4,[5,6,7,8]]
 
  This is just an example, I actually need to do it with a list of
  property lists, whilst the list is quite complicated, the format of
  the
  2 lists being joined will always be exactly the same, although the
  number of elements may change.
 
  Thanks
 
  Tim
 
 
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Re: lingo-l file in RAM

2005-04-11 Thread Thomas W.J.C. McCrystal
?php
   @extract($_POST);
One thing to be aware of is that there are security implications to using 
extract(); if you use it (like here) to grab post and get variables, 
you've essentially returned to a register_globals = TRUE regime. A 
malicious user could inject suspect data into your global space, or 
overwrite legitimate globals with new data.

At the very least, use the EXTR_SKIP parameter to avoid the overwrite 
issue.

In the case of your script here, it's probably not a big deal, but in 
general, I'd avoid using extract() on untrusted data.

One other thing -- spammers are on the lookout for unauthenticated 
mailscripts like this, so you might want to throw an extra magic 
parameter to provide a deterrent to casual reuse. Something like this is 
better then nothing:

if (!($unlock_key == mySecretValue)){
exit;
}

Hope this is useful...
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Re: lingo-l joining lists in lingo

2005-04-11 Thread Roger Jones
On Apr 11, 2005, at 8:54 AM, Buzz Kettles wrote:
While the below looks good, doing the 2 list-to-string conversions 
make that approach much slower than repeat-and-append.

hth
-Buzz
Also it would fail with large lists. String to list fails if the list 
has more than 32768 entries.

rj
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Re: lingo-l SES 10 questions

2005-04-11 Thread Alex da Franca
Am 11.04.2005 um 21:36 schrieb Thomas Higgins:
Is there a new DOM replacement for 'the systemDate'? Yes, in the form 
of
_system.date(), but it does not offer 1-for-1 functionality. The older 
'the
systemDate' returned a date object whose properties you could query 
(year,
month, day) whereas the newer _system.date() returns a string that you 
must
parse once you've sorted out the expected format of the string. Ugh. 
The
decision was made back in my QA days oh so long ago (I'm joking, it 
was just
over a year ago actually) and I for one disagreed with it. So there is 
no
direct identical replacement in the new DOM world.
don't want to be a fault-finder, but isn't it that _system.date is 
rather the old the date, which always returned a localized string, 
which you had to do ugly string trickery before the systemdate was 
introduced in D8 (?), when the date object was introduced as whole new 
data type ?

the systemdate actually is NOT undocumented AFAIK, it even made its way 
into the manual.
the only thing, which is undocumented since the beginning (dunno why 
though and can't figure it either) is the VERY useful seconds property 
of the date object.

so I think the systemdate rather shares the fate of floatprecision in 
that it was forgotten to put into the _system object.

but isn't it a good idea to leave some work for upcoming releases after 
all ? I mean making a perfect product could mean unemployment for the 
talented engeneers, isn't it ?

---
  |||
a¿ex
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Re: lingo-l SES 10 questions

2005-04-11 Thread Buzz Kettles
At 10:17 PM +0200 4/11/05, you wrote:
the systemdate actually is NOT undocumented AFAIK, it even made its 
way into the manual.
the only thing, which is undocumented since the beginning (dunno why 
though and can't figure it either) is the VERY useful seconds 
property of the date object.
Not really 'undocumented' - just not described in the help entry for 
the systemDate.

What's 'left out' is that since the systemDate returns a data object 
and 2 properties of all date objects are .seconds  .minutes that 
therefore (the systemDate).seconds  (the systemDate).minutes are 
included within that returned object.

note - these props have been viewable (in action) in the list view of 
a castLib.
... member().modifiedDate()

 sure, the docs for the systemDate could include examples of this 
... (to expose this subtlety)

hth
-Buzz
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Re: lingo-l joining lists in lingo

2005-04-11 Thread Buzz Kettles
At 8:17 PM +0200 4/11/05, you wrote:
... and it's dangerous if you want to user other value types than
numbers.
as an example, try
put value( string( [1,2,3,QUOTE] ))
Valentin
I was going to mention this aspect too, but figured the performance 
difference was enough of a good enough reason.

Many people don't find out about list-to-string mutation until they 
write some big list out  then it doesn't come back as they expected 
-  then they watch the process closely  see what is really going on.

-Buzz
Buzz Kettles wrote:
 While the below looks good, doing the 2 list-to-string conversions
 make that approach much slower than repeat-and-append.
 hth
 -Buzz
 At 4:09 PM +0200 4/11/05, you wrote:
 Hi Tim,
 maybe this could fit
 
 list1 = [1,2,3,4]
 list2 = [5,6,7,8]
 ---
 s1 = string(list1)
 s2 = string(list2)
 ---
 res1 = s1.char[1..s1.length - 1]
 res2 = s2.char[2..s2.length]
 ---
 put value(res1  ,  res2)
 -- [1, 2, 3, 4, 5, 6, 7, 8]
 
 Dam
 On Apr 11, 2005 3:16 PM, Valentin Schmidt [EMAIL PROTECTED] wrote:
  Hi Tim,
  it won't help you in this situation, but in DMX2004 for javascript
  there is the concat() function for arrays:
  var a = Array(1,2,3);
  var b = Array(4,5,6);
  trace(a.concat(b));
  // 1,2,3,4,5,6
  Valentin
  Tim Welford wrote:
   Hi,
  
   Thanks, that's similar to the method I am using at the moment. I
  was  hoping for some undocumented way of doing a simple join to
  get rid of  the repeat loop and hence improve the efficiency of
  the code. 
   -Original Message-
   From: [EMAIL PROTECTED]
   [mailto:[EMAIL PROTECTED] On Behalf Of Ozkan
   ALTUNER
   Sent: 11 April 2005 13:15
   To: Lingo programming discussion list
   Subject: Re: lingo-l joining lists in lingo
  
   Hello Tim,
  
   You can do it by appending list two to list one, by using a loop
  and  getAt(), getPropAt(), addProp() and addAt() methods.
  
   repeat with i = 1 to list2.count()
 addProp(list1, getAt(list2, i)
   end repeat
  
   i'm not exatcly sure of the syntax, however, it clearly should
   give  you
an idea.
   
Ciao,
Ozkan
   
   
-Orjinal mesaj-
From: Tim Welford [EMAIL PROTECTED]
   
Date: Mon, 11 Apr 2005 14:28:10 +0300
To: lingo-l@penworks.com
Subject: lingo-l joining lists in lingo
   
Greetings List...
   
I'm sure this is a daft question, but it escapes me.
Is there away of joining 2 lists together other than looping
 through
   the
   second list and using .add to add it to the first list.
  
   i.e.
   list1 = [1,2,3,4]
   list2 = [5,6,7,8]
  
   list1 + list2 = [1,2,3,4,5,6,7,8]
  
   rather than a result of [6,8,10,12]
   or [1,2,3,4,[5,6,7,8]]
  
   This is just an example, I actually need to do it with a list of
   property lists, whilst the list is quite complicated, the
  format of  the
   2 lists being joined will always be exactly the same, although
  the  number of elements may change.
  
   Thanks
  
   Tim
  
  
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  Thanks!] 
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Re: lingo-l joining lists in lingo

2005-04-11 Thread Alex da Franca
Am 11.04.2005 um 23:42 schrieb Buzz Kettles:
I was going to mention this aspect too, but figured the performance 
difference was enough of a good enough reason.
after all I don't quite understand, what is so bad about the little 
repeat loop.
I for one like repeat loops... ;-)
if only I could collapse them in the script editor at last... :-)

---
  |||
a¿ex
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Re: lingo-l SES 10 questions

2005-04-11 Thread Sean Wilson
Hi Buzz,
the systemDate returns a data object and 2 properties of all date objects 
are .seconds  .minutes
Unfortunately, (the systemDate).minutes throws an error for me. Has this 
ever worked, or were you mis-remembering? It would be redundant anyway, as 
minutes can be calculated from seconds.

-Sean. 

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Re: lingo-l joining lists in lingo

2005-04-11 Thread Buzz Kettles
At 12:11 AM +0200 4/12/05, you wrote:
Am 11.04.2005 um 23:42 schrieb Buzz Kettles:
I was going to mention this aspect too, but figured the performance 
difference was enough of a good enough reason.
after all I don't quite understand, what is so bad about the little 
repeat loop.
I for one like repeat loops... ;-)
if only I could collapse them in the script editor at last... :-)
Hahaha - I am also a big fan of repeat loops  :)
I couldn't code w/o them  :)
but it sure would be nice if there was an appendElements function for 
lists  proplists.

listA = [2,4,6]
listB = [1,3,5]
listA.appendElements(listB)
put listA
-- [2,4,6,1,3,5]
I guess it's not a built-in Lingo function because it seems like an 
easy user-defined function.

on appendElements, listA, listB
 c = listB.count
 repeat with i = 1 to c
   listA.append(listB[i])
 end repeat
 return listA
end
hth
-Buzz

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  |||
a¿ex
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Re: lingo-l SES 10 questions

2005-04-11 Thread Buzz Kettles
At 12:11 AM +0200 4/12/05, you wrote:
Am 11.04.2005 um 23:36 schrieb Buzz Kettles:
What's 'left out' is that since the systemDate returns a data 
object and 2 properties of all date objects are .seconds  .minutes 
that therefore (the systemDate).seconds  (the systemDate).minutes 
are included within that returned object.
minutes ??
never heard of that.
is that win only ?
sorry - I mis-remembered
There's only seconds  one must use division to get minutes and hours 
out of that

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lingo-l OT: Printing from Powerpoint .PPS

2005-04-11 Thread Elvin Certeza
Hello List,
I know this is off topic. But is there a chance where I can print from a 
PowerPoint Presentation slideshow?. extension .PPS??

thanks.

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