Re: [Matplotlib-users] Contour Plotting of Varied Data on a Shape

2010-03-10 Thread Ian Thomas
Chris Barker wrote:
 I think it would be great to have in MPL.

 What code are you using for the triangulation? Does it do constrained
 delauney?

My code only does the contouring; you have to input the triangulation.
 In the examples included with the code I used matplotlib.delaunay to
do the triangulations so as not to reinvent the wheel.

To include it in MPL, I would need to improve it somewhat (there are a
couple of known bugs and insufficient documentation) and there would
need to be a discussion of the API.  At the moment I am using

tricontour(x, y, triangulation_indices, z, optional_mask)

followed by the usual contour args (N or V) and kwargs.  Is this OK?
I've also written utility plotting functions triplot, trifill and
tripcolor; are these wanted?

In terms of implementation, at the python level I have a TriContourSet
class which is the same as the existing ContourSet apart from a few
lines that deal with input arguments and calling the appropriate
underlying C++ code.  Ideally it would be sensible to refactor the
common python code into a new class (BaseContourSet?) and have
relatively thin derived ContourSet and TriContourSet classes.  But I'm
not sure you'd like a relatively new mpl contributor to change such
important code...

Ian

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Re: [Matplotlib-users] grey scale line plots

2010-03-10 Thread Alan G Isaac
  On Mar 9, 2010, at 9 Mar, 1:52 PM, Alan G Isaac wrote:
  I need a figure containing color line plots to
  be changed to grayscale, cycling through line
  styles instead of colors.  How?

On 3/9/2010 10:45 PM, Chloe Lewis wrote:
  Here's a skeleton, for a series of lines that get darker and more
  solid (from past to present, as I use it):


Hi Chloe.  I deduce from your approach that there is nothing
built in.  I am surprised: are most people able to publish color
plots in their articles these days, so that the needed for a
cycle of greyscale linestyles is too rare to make it into
Matplotlib?

Thanks!
Alan



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Re: [Matplotlib-users] Doc suggestion

2010-03-10 Thread Michael Droettboom
Thanks.  That's a good suggestion.  It's been applied to SVN, and will 
make it on to the website the next time the website is updated.

Mike

David Arnold wrote:
 All,

 The linebuilder program on: 
  http://matplotlib.sourceforge.net/users/event_handling.html

 Needs two extra lines, one at the beginning and one at the end. Their 
 absence, particularly the second one, can cause confusion.

 import matplotlib.pyplot as plt

 class LineBuilder:
 def __init__(self, line):
 self.line = line
 self.xs = list(line.get_xdata())
 self.ys = list(line.get_ydata())
 self.cid = 
 line.figure.canvas.mpl_connect('button_press_event', self)

 def __call__(self, event):
 print 'click', event
 if event.inaxes!=self.line.axes: return
 self.xs.append(event.xdata)
 self.ys.append(event.ydata)
 self.line.set_data(self.xs, self.ys)
 self.line.figure.canvas.draw()

 fig = plt.figure()
 ax = fig.add_subplot(111)
 ax.set_title('click to build line segments')
 line, = ax.plot([0], [0])  # empty line
 linebuilder = LineBuilder(line)

 plt.show()

 

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Re: [Matplotlib-users] shiftgrid 'cyclic point not included' error

2010-03-10 Thread Jeff Whitaker
Anton Vasilescu wrote:
 Hi Jeff,

 Thank you for looking at the code for me! It works perfect for the 
 first image but when it tries to do the second it errors out saying: 
 lon0 outside of range of lonsin. Any idea why is that happening? Is 
 it happening for you too?

 Thanks,
 Anton

Anton: Probably because the original value of lons has been overwritten 
with the shifted grid longitudes.  You need to save the original lons 
array to pass to shiftgrid for the second grid.

-Jeff

 
 *From:* Jeff Whitaker jsw...@fastmail.fm
 *To:* antonv vasilescu_an...@yahoo.com
 *Cc:* matplotlib-users@lists.sourceforge.net
 *Sent:* Mon, March 8, 2010 12:50:48 PM
 *Subject:* Re: [Matplotlib-users] shiftgrid 'cyclic point not 
 included' error

 antonv wrote:
  Hi Jeff,
 
  Here is the whole script: 
 http://old.nabble.com/file/p27826457/_test_shiftgrid.py 
 _test_shiftgrid.py http://_test_shiftgrid.py And here are the grib 
 data files:
  http://socalscubainfo.com/downloads/GRIB2_files.zip
 
  Also, if there is not too much to ask, is there a sample anywhere 
 that shows
  how to use shiftgrid for a mercator projection? If you look at the 
 script, I
  was initially trying to make the images using the mercator 
 projection (there
  is a commented basemap function there) but it would display just the 
 data
  starting from the origin. I was wondering how would I be able to display
  let's say the whole globe but shift the grid 180 so that great 
 britain would
  be in the center of the map rather than being cut at the edge.
 
  Thanks,
  Anton 

 Anton:  You weren't updating the lons and lats to be consistent with 
 the shifted grid.  I changed the lines

   #z, lons[i] = shiftgrid(180.0, z, lons[i], start=False, 
 cyclic=360.0)
   #zq, lons_a[i] = shiftgrid(180.0, zq, lons_a[i], start=False, 
 cyclic=360.0)

 in your script to

   lons1 = lons[0,:]
   z, lonsnew = shiftgrid(180.0, z, lons1, start=False)
   zq, lonsnew = shiftgrid(180.0, zq, lons1, start=False)
   lons, lonsnew = shiftgrid(180.0, lons, lons1, start=False)
   lats, lonsnew = shiftgrid(180.0, lats, lons1, start=False)

 and it works fine.

 -Jeff
 
 
 
  Jeff Whitaker wrote:
  
  antonv wrote:

  Hi Jeff,
 
  Thanks for the quick reply! I've updated to the latest shiftgrid 
 and now
  I
  get the chart :D
  I still have a small issue as there is a half degree sliver 
 missing from
  the
  mapping at the greenwich meridian. Any idea how to solve that issue?
  Here is an image showing that (above england):
  http://old.nabble.com/file/p27824785/Global-HTSGW_DIRPW-0.png
  Thanks,
  Anton

  Anton:  Looks like the values at the Greenwich meridian got messed 
 up somehow.  Can you post your script somewhere so I can try it out?
 
  -Jeff

  Jeff Whitaker wrote:

  antonv wrote:

  Hi all,
 
  I am getting a 'cyclic point not included' error using shiftgrid 
 on a
  grib
  file from NOAA. I've checked and it seems that the file has the lons
  from
  0
  to 359.5 every .5 degree but I get that error whenever I try to run
  this.
  What I need to achieve is to shift the grid from 0 / 360 to -180 
 / 180
  so
  that I can create a map over Great Britain. I am using a Cassini
  projection.
  
  Anton:  You can add the wraparound, or cyclic point using the 
 addcyclic function.  Or, you can update to the latest svn version of 
 basemap which does not have this restriction.
 
 
  -Jeff
 
 
  -- Jeffrey S. WhitakerPhone  : (303)497-6313
  Meteorologist  FAX: (303)497-6449
  NOAA/OAR/PSD  R/PSD1Email  : jeffrey.s.whita...@noaa.gov 
 mailto:jeffrey.s.whita...@noaa.gov
  325 BroadwayOffice : Skaggs Research Cntr 1D-113
  Boulder, CO, USA 80303-3328 Web: http://tinyurl.com/5telg
 
 
  
 --
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 mailto:jeffrey.s.whita...@noaa.gov
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  Try the new software 

Re: [Matplotlib-users] shiftgrid 'cyclic point not included' error

2010-03-10 Thread Anton Vasilescu
You're right, the lons was getting overwritten! Thanks again for the help!

Anton





From: Jeff Whitaker jsw...@fastmail.fm
To: Anton Vasilescu vasilescu_an...@yahoo.com
Cc: matplotlib-users@lists.sourceforge.net
Sent: Wed, March 10, 2010 8:57:16 AM
Subject: Re: [Matplotlib-users] shiftgrid 'cyclic point not included' error

Anton Vasilescu wrote:
 Hi Jeff,
 
 Thank you for looking at the code for me! It works perfect for the first 
 image but when it tries to do the second it errors out saying: lon0 outside 
 of range of lonsin. Any idea why is that happening? Is it happening for you 
 too?
 
 Thanks,
 Anton

Anton: Probably because the original value of lons has been overwritten with 
the shifted grid longitudes.  You need to save the original lons array to pass 
to shiftgrid for the second grid.

-Jeff
 
 
 *From:* Jeff Whitaker jsw...@fastmail.fm
 *To:* antonv vasilescu_an...@yahoo.com
 *Cc:* matplotlib-users@lists.sourceforge.net
 *Sent:* Mon, March 8, 2010 12:50:48 PM
 *Subject:* Re: [Matplotlib-users] shiftgrid 'cyclic point not included' error
 
 antonv wrote:
  Hi Jeff,
 
  Here is the whole script: 
  http://old.nabble.com/file/p27826457/_test_shiftgrid.py 
  _test_shiftgrid.pyhttp://_test_shiftgrid.py And here are the grib data 
  files:
  http://socalscubainfo.com/downloads/GRIB2_files.zip
 
  Also, if there is not too much to ask, is there a sample anywhere that shows
  how to use shiftgrid for a mercator projection? If you look at the script, I
  was initially trying to make the images using the mercator projection (there
  is a commented basemap function there) but it would display just the data
  starting from the origin. I was wondering how would I be able to display
  let's say the whole globe but shift the grid 180 so that great britain would
  be in the center of the map rather than being cut at the edge.
 
  Thanks,
  Anton 
 Anton:  You weren't updating the lons and lats to be consistent with the 
 shifted grid.  I changed the lines
 
   #z, lons[i] = shiftgrid(180.0, z, lons[i], start=False, cyclic=360.0)
   #zq, lons_a[i] = shiftgrid(180.0, zq, lons_a[i], start=False, 
 cyclic=360.0)
 
 in your script to
 
   lons1 = lons[0,:]
   z, lonsnew = shiftgrid(180.0, z, lons1, start=False)
   zq, lonsnew = shiftgrid(180.0, zq, lons1, start=False)
   lons, lonsnew = shiftgrid(180.0, lons, lons1, start=False)
   lats, lonsnew = shiftgrid(180.0, lats, lons1, start=False)
 
 and it works fine.
 
 -Jeff
 
 
 
  Jeff Whitaker wrote:
   antonv wrote:
 Hi Jeff,
 
  Thanks for the quick reply! I've updated to the latest shiftgrid and now
  I
  get the chart :D
  I still have a small issue as there is a half degree sliver missing from
  the
  mapping at the greenwich meridian. Any idea how to solve that issue?
  Here is an image showing that (above england):
  http://old.nabble.com/file/p27824785/Global-HTSGW_DIRPW-0.png
  Thanks,
  Anton
 Anton:  Looks like the values at the Greenwich meridian got 
  messed up somehow.  Can you post your script somewhere so I can try it 
  out?
 
  -Jeff
 Jeff Whitaker wrote:
 antonv wrote:
 Hi all,
 
  I am getting a 'cyclic point not included' error using shiftgrid on a
  grib
  file from NOAA. I've checked and it seems that the file has the lons
  from
  0
  to 359.5 every .5 degree but I get that error whenever I try to run
  this.
  What I need to achieve is to shift the grid from 0 / 360 to -180 / 180
  so
  that I can create a map over Great Britain. I am using a Cassini
  projection.
   Anton:  You can add the wraparound, or cyclic 
  point using the addcyclic function.  Or, you can update to the latest 
  svn version of basemap which does not have this restriction.
 
 
  -Jeff
 
 
  -- Jeffrey S. WhitakerPhone  : (303)497-6313
  Meteorologist  FAX: (303)497-6449
  NOAA/OAR/PSD  R/PSD1Email  : jeffrey.s.whita...@noaa.gov 
  mailto:jeffrey.s.whita...@noaa.gov
  325 BroadwayOffice : Skaggs Research Cntr 1D-113
  Boulder, CO, USA 80303-3328 Web: http://tinyurl.com/5telg
 
 
  --
  Download Intel® Parallel Studio Eval
  Try the new software tools for yourself. Speed compiling, find bugs
  proactively, and fine-tune applications for parallel performance.
  See why Intel Parallel Studio got high marks during beta.
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  mailto:Matplotlib-users@lists.sourceforge.net
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-- Jeffrey S. WhitakerPhone  : 
  (303)497-6313
  Meteorologist  FAX: (303)497-6449
  NOAA/OAR/PSD  R/PSD1Email  : 

[Matplotlib-users] GTK+ config on Fedora 12.... change in filesystem structure?

2010-03-10 Thread Johann Cohen-Tanugi
Hi there, I am not sure whether I am the only one to experience that but 
on my new FEDORA 12  box GTK+ is shipped with the following structure 
for the headers : /usr/include/gtk-1.2/gtk/gtk.h
This does not seem to be expected by matplotlib setup.cfg , or am I 
missing something?
thanks,
Johann

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[Matplotlib-users] plot a lambda function?

2010-03-10 Thread max ulidtko
Hi.

Is it possible to plot arbitrary lambda function with matplotlib? Say, if i
have f = lambda x: x*sin(x), can i just plot it without building
argument-value arrays? It would be a very convenient and useful feature.


--
Sincerely,
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[Matplotlib-users] Making tick marks of a secondary axis line up with the primary axis

2010-03-10 Thread Alex S

Hi there,
I'm trying to make a plot with two y axes.  I'm able to do that no problem,
but what I'd really like to do now is make the tick marks line up for them
both so that they both use the same grid.  Is there a simple way to do this?  
Basically, I want to force the number of tick marks on the right hand axis
to be the same as on the left hand axis, and I'd like it to select nice
numbers to do so (ie not intervals of .358 or something).  

Also, on a somewhat related note, is there a simple way to force the y ticks
to start at 0 rather than some other value?

Thanks a lot,
Alex
-- 
View this message in context: 
http://old.nabble.com/Making-tick-marks-of-a-secondary-axis-line-up-with-the-primary-axis-tp27854166p27854166.html
Sent from the matplotlib - users mailing list archive at Nabble.com.


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Re: [Matplotlib-users] plot a lambda function?

2010-03-10 Thread Chloe Lewis
You'd always have to specify the domain, so

plot(map(lambda x:x**2, range(1,10)))

shouldn't be much longer than the minimal command.

C


On Mar 10, 2010, at 10:12 AM, max ulidtko wrote:

 Hi.

 Is it possible to plot arbitrary lambda function with matplotlib?  
 Say, if i have f = lambda x: x*sin(x), can i just plot it without  
 building argument-value arrays? It would be a very convenient and  
 useful feature.


 --
 Sincerely,
 max ulidtko
 --
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Re: [Matplotlib-users] plot a lambda function?

2010-03-10 Thread Roban Hultman Kramer
How about this (though it is getting a little clunky):

plot(*transpose(map(lambda x:(x,sin(x**2)/x**3), arange(3,6, 0.01



On Wed, Mar 10, 2010 at 7:57 PM, Chloe Lewis chle...@berkeley.edu wrote:
 ...although

  plot(map(lambda x:x**2, range(5,15)))

 probably doesn't do exactly what you want; is the idea that

  plot(range(5,15),lambda x:x**2) #DOESN'T WORK

 should automatically work like

  plot(range(5,15), map(lambda x:x**2, range(5,15)))

 by recognizing that the second argument is a function rather than a
 list?

 C


 On Mar 10, 2010, at 10:47 AM, Chloe Lewis wrote:

 You'd always have to specify the domain, so

 plot(map(lambda x:x**2, range(1,10)))

 shouldn't be much longer than the minimal command.

 C


 On Mar 10, 2010, at 10:12 AM, max ulidtko wrote:

 Hi.

 Is it possible to plot arbitrary lambda function with matplotlib?
 Say, if i have f = lambda x: x*sin(x), can i just plot it without
 building argument-value arrays? It would be a very convenient and
 useful feature.


 --
 Sincerely,
 max ulidtko
 --
 Download Intel#174; Parallel Studio Eval
 Try the new software tools for yourself. Speed compiling, find bugs
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 Matplotlib-users mailing list
 Matplotlib-users@lists.sourceforge.net
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Re: [Matplotlib-users] Making tick marks of a secondary axis line up with the primary axis

2010-03-10 Thread PHobson


 -Original Message-
 From: Alex S [mailto:schmitt.happ...@gmail.com]
 Hi there,
 I'm trying to make a plot with two y axes.  I'm able to do that no
 problem,
 but what I'd really like to do now is make the tick marks line up for
 them
 both so that they both use the same grid.  Is there a simple way to do
 this?
 Basically, I want to force the number of tick marks on the right hand
 axis
 to be the same as on the left hand axis, and I'd like it to select nice
 numbers to do so (ie not intervals of .358 or something).

Hey Alex, 

I always just figure this out on my own. There might exist a more elegant way 
though.
Starting with this:

import matplotlib.pyplot as plt
fig = plt.figure()
ax1 = fig.add_subplot(111)
ax2 = ax1.twinx()
# plot stuff

# So then you could do something like:
ytx1 =  ax1.get_yticks()


...and then use to len(ytx1) and range() to ax2.set_yticks(blahblah).
The tricky part is picking a max for your range() so that your stepsize 
produces nice numbers.


 Also, on a somewhat related note, is there a simple way to force the y
 ticks
 to start at 0 rather than some other value?

ax1.set_ylim(ymin=0)

HTH,
-paul h.

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[Matplotlib-users] turn off tick reflection

2010-03-10 Thread Matthew MacLeod
Dear matplotlib users,

I'm trying to make a plot that shares the x axis, but that have two 
different y scales. I can do this, almost, I say almost because I don't 
know how to turn off the reflection of my y ticks, so they are reflected 
and obscure the scale on the other side, if the scales aren't similar.

I looked at the example
http://matplotlib.sourceforge.net/plot_directive/mpl_examples/api/two_scales.py

and it hints at a solution (Hint: use the xaxis instance and call 
tick_bottom and tick_top in place of tick_left and tick_right.), but this 
doesn't make any sense to me. I think I need to

Turn the axes rectangular frame off on the 2nd axes to keep it from 
obscuring the first.

but I'm not sure if this is what I need to do, if it is, I'm also not sure 
how to do this.


Thanks for any ideas,
Matthew


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