Re: [Matplotlib-users] [matplotlib-devel] v1.4.3rc1
Awesome work! Full credit to Tom who has driven this release. The nbagg backend is looking great - some pretty swish new features thanks to hard work from Steven Silvester and Thomas Caswell! On 2 February 2015 at 10:58, Jens Nielsen jenshniel...@gmail.com wrote: Thanks Tom, I ran the test suite on OSX 10.10 with both python 2.7.8 and 3.4.2 including the tex and QT4 tests that are skipped on Travis. Everything passes as expected. Jens Mon Feb 02 2015 at 5:38:32 AM skrev Thomas Caswell tcasw...@gmail.com: Evening all, I have tagged the first release candidate for v1.4.3 (https://github.com/ matplotlib/matplotlib/releases/tag/v1.4.3rc1). Although this is a bug-fix release, a fair amount of work has gone into making the nbagg (interactive figures in ipython notebooks) feature complete compared to the other interactive backends. Please kick the tires and give it a try! If there are no major issues, the plan is to target 1.4.3 for next weekend. The mac build has been started and (if I understand how these things work) should be available to install via pip install -f http://wheels.scikit-image.org --pre matplotlib soon. For linux anaconda users, packages for 2.6/2.7 python on my binstar channel (conda install -c https://conda.binstar.org/tacaswell matplotlib). The py3k builds have some issue with invalid syntax in pyqt4, if some knows how to build these, please let me know. Tom -- Dive into the World of Parallel Programming. The Go Parallel Website, sponsored by Intel and developed in partnership with Slashdot Media, is your hub for all things parallel software development, from weekly thought leadership blogs to news, videos, case studies, tutorials and more. Take a look and join the conversation now. http://goparallel.sourceforge.net/ ___ Matplotlib-devel mailing list matplotlib-de...@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-devel -- Dive into the World of Parallel Programming. The Go Parallel Website, sponsored by Intel and developed in partnership with Slashdot Media, is your hub for all things parallel software development, from weekly thought leadership blogs to news, videos, case studies, tutorials and more. Take a look and join the conversation now. http://goparallel.sourceforge.net/ ___ Matplotlib-devel mailing list matplotlib-de...@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-devel -- Dive into the World of Parallel Programming. The Go Parallel Website, sponsored by Intel and developed in partnership with Slashdot Media, is your hub for all things parallel software development, from weekly thought leadership blogs to news, videos, case studies, tutorials and more. Take a look and join the conversation now. http://goparallel.sourceforge.net/___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
[Matplotlib-users] Season's greetings from matplotlib
If working on XKCD style plotting for matplotlib taught me anything, it is that playing with software in a way that it was not originally designed to do can lead to some excellent discoveries (bugs) and generate new ideas and generalisations - not to mention it being a lot of fun! So, in that vein, I wanted to put together a simple Christmas e-card using matplotlib. My main aim was to re-purpose some of the familiar matplotlib functionality to generate a simple festive animation. I decided to go for a snowy scene, with a snow-capped greeting and sprig of holly. The snow is simply a scatter plot scaled by flake size and animated to fall in a pleasing way. The text is making use of the path effects functionality extended in v1.4 to add randomised snow around the text (the same effect employed by XKCD as it happens). And the holly is a nice demonstration of the power of Paths and vector rendering in matplotlib. The source can be found at https://gist.github.com/pelson/ca795a02a420a1b9bfbc, and it requires matplotlib = v1.4. If you're impatient and don't want to run the code (don't do it), the animation is available on YouTube at https://www.youtube.com/watch?v=POnAkPpe770. Finally, to all those taking some time off this festive season, I wish you a very happy holiday and wish you all the best for the new year. Phil Elson -- Dive into the World of Parallel Programming! The Go Parallel Website, sponsored by Intel and developed in partnership with Slashdot Media, is your hub for all things parallel software development, from weekly thought leadership blogs to news, videos, case studies, tutorials and more. Take a look and join the conversation now. http://goparallel.sourceforge.net___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
Re: [Matplotlib-users] creating a path from multiple sets of xy coordinates (inner and outer outlines)
If I understand your question fully, then yes it does. Have a play, and let us know how you get on. Best, Phil On 22 December 2014 at 11:15, Denis-Alexander Engemann denis.engem...@gmail.com wrote: Thanks Phil, just to make sure I inderstand the logic of PathPatch. Does it cut out vertices / paths that are detected to be inside an outline as the star in this example? -Denis 2014-12-22 12:09 GMT+01:00 Phil Elson pelson@gmail.com: Sorry its taken so long to get an answer, but essentially you want to concatenate the outer coordinates with the inner ones (reversed) to indicate that it is a hole. There is a pretty (simple) useful example that I added a few years ago for demonstrating the use of paths for markers: http://matplotlib.org/examples/pylab_examples/marker_path.html Constructing a patch from a path is as simple as (untested): import matplotlib.patches as mpatches patch = mpatches.PathPatch(my_path, facecolor='red', edgecolor='yellow') axes.add_patch(patch) HTH, Phil On 19 December 2014 at 23:01, Denis-Alexander Engemann denis.engem...@gmail.com wrote: Dear list, I would like to create a custom image clipping mask using patches. My constraint is that my patch is required to have an outer and multiple inner outlines. To provide an analogy, think of a mask used for disguise where you leave three holes, two for the eyes, one for the mouth. I have the xy coordinates for the 'head', and the xy coordinates for each of the holes that I don't want to be hidden by the ensuing clipping mask. What's the matplotlib way to construct my desired path + patch from that? Note, it's important in my case to use a patch object. What I need to do would not work by simply masking my image using a masked array. Any pointer would be highly appreciated -- Denis -- Download BIRT iHub F-Type - The Free Enterprise-Grade BIRT Server from Actuate! Instantly Supercharge Your Business Reports and Dashboards with Interactivity, Sharing, Native Excel Exports, App Integration more Get technology previously reserved for billion-dollar corporations, FREE http://pubads.g.doubleclick.net/gampad/clk?id=164703151iu=/4140/ostg.clktrk ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users -- Dive into the World of Parallel Programming! The Go Parallel Website, sponsored by Intel and developed in partnership with Slashdot Media, is your hub for all things parallel software development, from weekly thought leadership blogs to news, videos, case studies, tutorials and more. Take a look and join the conversation now. http://goparallel.sourceforge.net___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
Re: [Matplotlib-users] creating a path from multiple sets of xy coordinates (inner and outer outlines)
Sorry its taken so long to get an answer, but essentially you want to concatenate the outer coordinates with the inner ones (reversed) to indicate that it is a hole. There is a pretty (simple) useful example that I added a few years ago for demonstrating the use of paths for markers: http://matplotlib.org/examples/pylab_examples/marker_path.html Constructing a patch from a path is as simple as (untested): import matplotlib.patches as mpatches patch = mpatches.PathPatch(my_path, facecolor='red', edgecolor='yellow') axes.add_patch(patch) HTH, Phil On 19 December 2014 at 23:01, Denis-Alexander Engemann denis.engem...@gmail.com wrote: Dear list, I would like to create a custom image clipping mask using patches. My constraint is that my patch is required to have an outer and multiple inner outlines. To provide an analogy, think of a mask used for disguise where you leave three holes, two for the eyes, one for the mouth. I have the xy coordinates for the 'head', and the xy coordinates for each of the holes that I don't want to be hidden by the ensuing clipping mask. What's the matplotlib way to construct my desired path + patch from that? Note, it's important in my case to use a patch object. What I need to do would not work by simply masking my image using a masked array. Any pointer would be highly appreciated -- Denis -- Download BIRT iHub F-Type - The Free Enterprise-Grade BIRT Server from Actuate! Instantly Supercharge Your Business Reports and Dashboards with Interactivity, Sharing, Native Excel Exports, App Integration more Get technology previously reserved for billion-dollar corporations, FREE http://pubads.g.doubleclick.net/gampad/clk?id=164703151iu=/4140/ostg.clktrk ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users -- Download BIRT iHub F-Type - The Free Enterprise-Grade BIRT Server from Actuate! Instantly Supercharge Your Business Reports and Dashboards with Interactivity, Sharing, Native Excel Exports, App Integration more Get technology previously reserved for billion-dollar corporations, FREE http://pubads.g.doubleclick.net/gampad/clk?id=164703151iu=/4140/ostg.clktrk___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
[Matplotlib-users] Bloomberg Open source sprint, London, November 29-30 2014
There will be an open source Python sprint, hosted by Bloomberg, this weekend in London. The event will be attended by core developers of many of the major scientific Python packages (IPython, numpy, scipy, pandas, scikit-learn) who will act as mentors to those who would like to get involved in the development of these important scientific tools. I will be attending as a mentor for matplotlib (if there are any other core developers who may be able to attend, the more the merrier!) and am hoping there will be many attendees who want to get a helping hand getting started with matplotlib development. We've got lots of room for improvement, from the obvious documentation enhancements right through to the nitty-gritty of improving backends such as nbagg. If you want to come along to the event, please sign-up at http://go.bloomberg.com/promo/invite/bloomberg-open-source-day-scientific-python/ . Hope you see some of you there, Phil -- Download BIRT iHub F-Type - The Free Enterprise-Grade BIRT Server from Actuate! Instantly Supercharge Your Business Reports and Dashboards with Interactivity, Sharing, Native Excel Exports, App Integration more Get technology previously reserved for billion-dollar corporations, FREE http://pubads.g.doubleclick.net/gampad/clk?id=157005751iu=/4140/ostg.clktrk___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
Re: [Matplotlib-users] FW: traceback when import matplotlib.pyplot twice
On 10 October 2014 19:10, Thomas Caswell tcasw...@gmail.com wrote: I suspect a better fix is to change all of the staticmethods - classmethods +1 -- Meet PCI DSS 3.0 Compliance Requirements with EventLog Analyzer Achieve PCI DSS 3.0 Compliant Status with Out-of-the-box PCI DSS Reports Are you Audit-Ready for PCI DSS 3.0 Compliance? Download White paper Comply to PCI DSS 3.0 Requirement 10 and 11.5 with EventLog Analyzer http://p.sf.net/sfu/Zoho___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
Re: [Matplotlib-users] xkcd
Also note, you can just call plt.xkcd() and it will turn on the setting
globally for that session.
On 4 October 2014 00:11, Paul Hobson pmhob...@gmail.com wrote:
That's what the `with` statement allows you do.
Say you have a function that does some plotting and returns a figure --
call it my_plot_func.
You can do:
fig1 = my_plot_func()
fig1.savefig('normal1.png')
with plt.xkcd():
fig2 = mu_plot_func()
fig2.savefig('xkcd.png')
fig2 = my_plot_func()
fig2.savefig('normal2.png')
And the xkcd image will be squiggly but the normal images won't.
-p
On Fri, Oct 3, 2014 at 12:40 PM, Christophe Bal projet...@gmail.com
wrote:
Hello.
I've only seen one way to use the xkcd feature. This uses a with
statement.
Is there another way to use the xkcd feature so as to easily switch
between exact plot and trembling one ?
Christophe BAL
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Re: [Matplotlib-users] Issue with basemap.plot() when lon_0 nonzero
Cool notebook. I took the liberty of giving it a go with cartopy, and you can see the results here http://nbviewer.ipython.org/gist/pelson/10822698 I'd agree that the issue you linked to does look very similar to the issue you are seeing, so I think this is very likely a bug. Cheers, On 16 April 2014 00:54, Scott Henderson st...@cornell.edu wrote: Hello, I’m trying to make a plot data on a map with the ‘cyl’ projection with a shifted centerline (lon_0=180), but I receive an error when shiftdata() is called. Since the plot works when lon_0=0, this seems to be a bug. I’ve posted the code, error, and plots here: http://nbviewer.ipython.org/gist/anonymous/cbfe6d0f66ff3a8186c8/shiftdata_issue.ipynb It might be related to this issue: https://github.com/matplotlib/basemap/issues/126 Any insight would be appreciated! Scott -- Learn Graph Databases - Download FREE O'Reilly Book Graph Databases is the definitive new guide to graph databases and their applications. Written by three acclaimed leaders in the field, this first edition is now available. Download your free book today! http://p.sf.net/sfu/NeoTech ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users -- Learn Graph Databases - Download FREE O'Reilly Book Graph Databases is the definitive new guide to graph databases and their applications. Written by three acclaimed leaders in the field, this first edition is now available. Download your free book today! http://p.sf.net/sfu/NeoTech___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
Re: [Matplotlib-users] Fwd: Strange behaviour on plotting data on Ronbinson projection using Basemap
Hi Chao, The warning you are getting: WARNING: x coordinate not monotonically increasing - contour plot may not be what you expect. If it looks odd, your can either adjust the map projection region to be consistent with your data, or (if your data is on a global lat/lon grid) use the shiftgrid function to adjust the data to be consistent with the map projection region (see examples/contour_demo.py). Is important here. It looks like the x coordinate is not in appropriate longitudes. Printing the first 5 and last 5 longitudes gives us our first clue: First 5: [-180. -178.99720764 -177.99443054 -176.99163818 -175.98886108] Last 5 : [ 175.98886108 176.9916687 177.9944458 178.9972229 180.3052] Notice that the last longitude wraps around beyond 180. So if we were to clip these numbers to -180 and +180 we will see that the warning disappears and the contour is correct. This can be achieved with: lon = np.clip(lon, -180, 180) Alternatively, we can just construct the latitudes and longitudes ourselves directly with: lon, lat = np.meshgrid(np.linspace(-180, 180, 360), np.linspace(-90, 90, 180)) Incidentally, I tried these numbers with cartopy which has been designed to handle dateline wrapping automatically, and the contour worked with the unmodified longitudes (http://nbviewer.ipython.org/gist/pelson/10830039). --- @JeffWhitaker - This looks like a bug with float tolerances in the makegrid function. It currently does: def makegrid(self,nx,ny,returnxy=False): dx = (self.urcrnrx-self.llcrnrx)/(nx-1) dy = (self.urcrnry-self.llcrnry)/(ny-1) But might be better if it did: def makegrid(self,nx,ny,returnxy=False): x = np.linspace(self.llcrnrx, self.urcrnrx, nx) y = np.linspace(self.llcrnry, self.urcrnry, ny) To avoid the multiplicative floating point drift that is currently being seen. HTH, Phil -- Learn Graph Databases - Download FREE O'Reilly Book Graph Databases is the definitive new guide to graph databases and their applications. Written by three acclaimed leaders in the field, this first edition is now available. Download your free book today! http://p.sf.net/sfu/NeoTech___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
Re: [Matplotlib-users] Matplotlib for tiles - blank lines
I fixed an issue related to this (I too was producing map tiles) in
matplotlib v1.2 I believe.
The original issue can be found at
https://github.com/matplotlib/matplotlib/pull/1591 and so I suggest this
might not be an issue with matplotlib = v1.3.
Incidentally, if you are producing map tiles you might be interested in
cartopy which will allow you to produce properly referenced geo maps (and
therefore tiles) with coastlines etc.
I've put a short-sh example in a gist () with the rendered results also
available (https://rawgithub.com/pelson/9738051/raw/map.html). I've also
got a tornado based handler version which generates the tiles upon HTTP
request rather than storing the tiles on disk (much more efficient if you
have highly dynamic data and a caching layer).
Let me know if updating your matplotlib version helps,
Cheers,
Phil
On 24 March 2014 09:45, Jesper Larsen jesper.webm...@gmail.com wrote:
Hi matplotlib users,
I am using matplotlib to produce plots (tiles) in a Web Map Service.
Unfortunately I cannot get Matplotlib to plot on the entire image. There
are one transparent (pixel) line at the bottom and one transparent line at
the right. This is of course a problem when the tiles are shown in a map.
Please see example below. Can anyone see what I am doing wrong?
Best regards,
Jesper
import numpy as np
import matplotlib as mpl
from matplotlib.figure import Figure
from matplotlib.backends.backend_agg import FigureCanvasAgg as FigureCanvas
w = 256
h = 256
dpi = 128
figsize = w/dpi, h/dpi
fig = Figure(figsize=figsize, dpi=dpi, frameon=False)
canvas = FigureCanvas(fig)
ax = fig.add_axes([0, 0, 1, 1])
x = np.arange(0, 10, 0.1)
y = np.arange(10, 20, 0.2)
X, Y = np.meshgrid(x, y)
D = np.ones((X.shape[0]-1, X.shape[1]-1))
V = np.linspace(0.0, 1.0, 10)
ax.pcolor(X, Y, D, antialiased=False)
ax.axis( [x[0], x[-1], y[0], y[-1]] )
ax.axis('off')
filename = 'testfile.png'
fig.savefig(filename, dpi=128)
# Test image
from PIL import Image
im = Image.open(filename)
print im.getcolors()
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Re: [Matplotlib-users] Runtime error
Hi Kai, I'm afraid I've never heard of this one. Do you have a full error log? Thanks, On 26 January 2014 02:40, kaiw...@genetics.ac.cn wrote: Hi, I'm trying to use matplotlib to generate pictures for my website view. The framwork I use is pyramid. But I got an error when I try to refresh my page two or more times. The message is as follow: This application has requested the Runtime to terminate it in an unusual way. Please contact the application's support team for more information. Is it a win32 error? I use python27 win32 and matplotlib 1.2. Thx Kai Wang -- CenturyLink Cloud: The Leader in Enterprise Cloud Services. Learn Why More Businesses Are Choosing CenturyLink Cloud For Critical Workloads, Development Environments Everything In Between. Get a Quote or Start a Free Trial Today. http://pubads.g.doubleclick.net/gampad/clk?id=119420431iu=/4140/ostg.clktrk ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users -- CenturyLink Cloud: The Leader in Enterprise Cloud Services. Learn Why More Businesses Are Choosing CenturyLink Cloud For Critical Workloads, Development Environments Everything In Between. Get a Quote or Start a Free Trial Today. http://pubads.g.doubleclick.net/gampad/clk?id=119420431iu=/4140/ostg.clktrk___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
Re: [Matplotlib-users] Remove backgroundimage
As with most other artists, you should be able to just call remove on the resulting artist. e.g. im = plt.imshow(...) ... im.remove() HTH On 2 January 2014 11:58, flambert franz_lambert_en...@yahoo.de wrote: Hi, Does somebody knows how can I remove a backgroundimage. I set the image with imshow. regards, flambert -- View this message in context: http://matplotlib.1069221.n5.nabble.com/Remove-backgroundimage-tp42658.html Sent from the matplotlib - users mailing list archive at Nabble.com. -- Rapidly troubleshoot problems before they affect your business. Most IT organizations don't have a clear picture of how application performance affects their revenue. With AppDynamics, you get 100% visibility into your Java,.NET, PHP application. Start your 15-day FREE TRIAL of AppDynamics Pro! http://pubads.g.doubleclick.net/gampad/clk?id=84349831iu=/4140/ostg.clktrk ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users -- CenturyLink Cloud: The Leader in Enterprise Cloud Services. Learn Why More Businesses Are Choosing CenturyLink Cloud For Critical Workloads, Development Environments Everything In Between. Get a Quote or Start a Free Trial Today. http://pubads.g.doubleclick.net/gampad/clk?id=119420431iu=/4140/ostg.clktrk___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
Re: [Matplotlib-users] font setting in matplotlib 1.3.1
Thanks for this Vlastimil, looks like there is either a subtlety beyond my font knowledge or a bug here - mdboom, did you have any ideas? Otherwise I think we need a github issue for this. Cheers, On 4 January 2014 19:37, Vlastimil Brom vlastimil.b...@gmail.com wrote: Hi all, after upgrading to matplotlib 1.3.1, I noticed some display errors on the plots with regard to accented characters (such as carons etc.). As I recall, I had similar problem in the past and could work around them by modifying rcParams, however, this fix doesn't work as expected in 1.3.1. (with python 2.7.6, 32bit on Win 7, Czech - with both WXAgg and TKAgg backends). From the usual Czech diacritics áčďéěíňóřšťúůýž some are not displayed (ďěňřťů) - replacement squares are shown instead. Simply prepending a suitable font at the beginning of the list rcParams['font.sans-serif'] doesn't help in 1.3.1. I eventually found out, that Bitstream Vera Sans (which is not installed on this computer) is somehow offending - as long as this item is in the list (even at the end), the mentioned characters aren't displayed. The problem can be observed in the following simple pylab script: == #! Python # -*- coding: utf-8 -*- # with implicit fonts ďěňřťů are not displayed properly in the plot title from matplotlib import rcParams rcParams['font.family'] = 'sans-serif' if Bitstream Vera Sans in rcParams['font.sans-serif']: rcParams['font.sans-serif'].remove(Bitstream Vera Sans) # after appending the offending font even at the end of the list (by uncommenting the following line), ďěňřťů are not displayed again # rcParams['font.sans-serif'].append(Bitstream Vera Sans) import pylab pylab.title(uabcd áčďéěíňóřšťúůýž äöüß ê xyz) pylab.show() == Is there something special in the resolution of the font items in rcParams? This individual issue seems to be fixed with removing the single font, but I'd like to understand this more generally, as the installed fonts on different computers differ. Thanks in advance Vlastimil Brom -- Rapidly troubleshoot problems before they affect your business. Most IT organizations don't have a clear picture of how application performance affects their revenue. With AppDynamics, you get 100% visibility into your Java,.NET, PHP application. Start your 15-day FREE TRIAL of AppDynamics Pro! http://pubads.g.doubleclick.net/gampad/clk?id=84349831iu=/4140/ostg.clktrk ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users -- CenturyLink Cloud: The Leader in Enterprise Cloud Services. Learn Why More Businesses Are Choosing CenturyLink Cloud For Critical Workloads, Development Environments Everything In Between. Get a Quote or Start a Free Trial Today. http://pubads.g.doubleclick.net/gampad/clk?id=119420431iu=/4140/ostg.clktrk___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
Re: [Matplotlib-users] segmentation fault and / or bus error with script that cranks out plots with TkAgg backend
This is a bit of a surprise. Sounds like it could have something to do with matplotlib's build, or that of some of its dependencies, so may need reporting to Gentoo once we've dug a little further. It could be a really tricky one to diagnose without being able to reproduce locally, but - is the loop significant? Does the number of figures matter? Essentially, try to boil it down to as little code as possible (do you need to produce a line plot to reproduce etc.). Cheers, On 6 January 2014 22:18, tenspd137 . dcday...@gmail.com wrote: Hi all, I am running a script that cranks out multiple plots in a loop. The script has plt.show() as the very last line as I think you are supposed to do. All plots show up, but I get a seg fault (sometimes a bus error - I haven't figured why it occasionally does that) when I close the last plot and the script exits. I was wondering if someone could help me figure out what info to grab to determine what is causing it. I use gentoo and recently did an upgrade world, so I am guessing some new library is not playing nicely as this always seemed to work before. Also, when I switch to Qt4Agg backend, everything works as expected, but if I can help iron out a bug, I would like to - I really think that matplotlib is an excellent piece of software. Pertinent info: uname -a: Linux dayd 3.10.15-gentoo #6 SMP Sat Dec 14 15:53:47 MST 2013 x86_64 Intel(R) Xeon(R) CPU E5-2620 0 @ 2.00GHz GenuineIntel GNU/Linux Matplotlib version - 1.3.1 matplotlibrc: backend: TkAgg (Qt4Agg works as expected) interactive: False because it segfaults python3.3 testplot.py --verbose-helpful output.txt outputs nothing gcc --version: gcc (Gentoo 4.8.2 p1.0, pie-0.5.8) 4.8.2 Copyright (C) 2013 Free Software Foundation, Inc. This is free software; see the source for copying conditions. There is NO warranty; not even for MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. script to reproduce the problem: import sys import matplotlib.pyplot as plt def main(): for x in range(6): plt.figure() plt.title(x) plt.plot([1,1],[1,1],'r.') plt.show() if __name__ == __main__: sys.exit(main()) I found some instructions on how to get debug info when you install a package in gentoo. If anyone else can recreate this or need some more info from me - please let me know. I will do what I can. Thanks! -- Rapidly troubleshoot problems before they affect your business. Most IT organizations don't have a clear picture of how application performance affects their revenue. With AppDynamics, you get 100% visibility into your Java,.NET, PHP application. Start your 15-day FREE TRIAL of AppDynamics Pro! http://pubads.g.doubleclick.net/gampad/clk?id=84349831iu=/4140/ostg.clktrk ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users -- CenturyLink Cloud: The Leader in Enterprise Cloud Services. Learn Why More Businesses Are Choosing CenturyLink Cloud For Critical Workloads, Development Environments Everything In Between. Get a Quote or Start a Free Trial Today. http://pubads.g.doubleclick.net/gampad/clk?id=119420431iu=/4140/ostg.clktrk___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
Re: [Matplotlib-users] Clipping a plot inside a polygon
Sadly each keyword is handled manually in lib/matplotlib/contour.py L690
which is why you can set keywords which are completely ignored without
getting any warning/exception.
We could add a set_clip_path keyword in that constructor, but in truth the
whole keyword handling approach in contour.py could do with an overhaul.
Looking at it, we could equally add the appropriate method on the
ContourSet object to control the clipping, which would just do the
iteration over the collections as I did in my example.
Anyway, glad my example was helpful,
Cheers,
Phil
On 2 September 2013 21:33, Alex Goodman alex.good...@colostate.edu wrote:
Actually, sorry for the triple post, but is there a reason why we can't do
something like pass in the keyword arguments directly from the call to
contourf when instantiating each collection? Then the keyword arguments for
contourf (and ContourSet) could be used for the collections directly,
including clip_path. I know a similar approach is taken for the keyword
arguments in plot, since those can be used to modify the properties of each
Line2D instance.
Thanks,
Alex
On Mon, Sep 2, 2013 at 1:09 PM, Alex Goodman
alex.good...@colostate.eduwrote:
Actually, it seems I have partially answered my own question. Since I am
calling axis('off'), I do not notice the effect of clipping the other
artists since I made a call to axis('off'). Without it the spines and axes
rectangle are still removed but the ticks are still visible. I suppose this
is fine for my own purposes of contouring within one country on a map since
I would want to use something like axis('off') anyway, but then it would
not work if I wanted to use the axes background. Another approach I have
tried is to use the clip_path keyword in the plotting functions themselves,
which works for imshow and pcolor, but not contourf. Any other ideas?
Alex
On Mon, Sep 2, 2013 at 12:18 PM, Alex Goodman alex.good...@colostate.edu
wrote:
Hi Phil,
Thanks, that is more or less what I was looking for. However, I still
think that generalizing this approach for other types of plotting functions
that don't return artists directly would be useful. Your solution gave me
another idea for doing this, which would be to iterate through all of the
child artists on the axes using the get_children() method and then calling
set_clip_path() on each artist. This would make the methodology very
general but I am not sure if there are any negative side effects to
resetting the clip path on the other artists besides the PatchCollections.
I modified my simple example script and it seems to work well for
contourf(), pcolor(), and imshow():
import numpy as np
import matplotlib.pyplot as plt
from matplotlib.patches import RegularPolygon
data = np.arange(100).reshape(10, 10)
fig = plt.figure()
ax = fig.add_subplot(111)
ax.contourf(data)
poly = RegularPolygon([ 0.5, 0.5], 6, 0.4, fc='none',
ec='k', transform=ax.transAxes)
for artist in ax.get_children():
artist.set_clip_path(poly)
ax.add_patch(poly)
ax.set_aspect('equal')
ax.axis('off')
plt.show()
Also, I appreciated the cartopy example. I think it has the potential to
be a good basemap replacement thanks to the more robust shapefile support
(which you have very elegantly shown), and I hope the development goes well.
Thanks,
Alex
On Mon, Sep 2, 2013 at 2:33 AM, Phil Elson pelson@gmail.com wrote:
Great question. The contour set itself does not have a set_clip_path
method but you can iterate over each of the contour collections and set
their respective clip paths, i.e.:
cs = plt.contourf(data)
for collection in cs.collections:
collection.set_clip_path(poly)
Of course, you can use this approach in either Basemap or cartopy, but
I've put together an example of doing it in cartopy to demonstrate the neat
Shapely integration: http://nbviewer.ipython.org/6410510
HTH,
Phil
On 2 September 2013 05:40, Alex Goodman alex.good...@colostate.eduwrote:
Hi all,
I want to be able to plot data on maps (using basemap or cartopy)
inside specific regions, eg a single state, province or country. A similar
question was asked a long time ago on the mailing list and the suggested
solution back then was to read the bounding polygon from a shapefile and
then check if each individual point was inside that polygon. Currently I
have no problem doing this if I use matplotlib.path.Path.contains_points()
to mask the original data array, but the disadvantage to this solution is
that it is very slow. Another solution that I have discovered recently is
to use the set_clip_path() method for artists. In addition to being much
faster, this also makes the areas near the polygon boundary look much
smoother since the actual items being clipped are individual pixels and
not
data points.
Here is an example script that plots an image via imshow, but the only
part of the image that gets shown is inside the hexagon.
import numpy as np
Re: [Matplotlib-users] Clipping a plot inside a polygon
Great question. The contour set itself does not have a set_clip_path method
but you can iterate over each of the contour collections and set their
respective clip paths, i.e.:
cs = plt.contourf(data)
for collection in cs.collections:
collection.set_clip_path(poly)
Of course, you can use this approach in either Basemap or cartopy, but I've
put together an example of doing it in cartopy to demonstrate the neat
Shapely integration: http://nbviewer.ipython.org/6410510
HTH,
Phil
On 2 September 2013 05:40, Alex Goodman alex.good...@colostate.edu wrote:
Hi all,
I want to be able to plot data on maps (using basemap or cartopy) inside
specific regions, eg a single state, province or country. A similar
question was asked a long time ago on the mailing list and the suggested
solution back then was to read the bounding polygon from a shapefile and
then check if each individual point was inside that polygon. Currently I
have no problem doing this if I use matplotlib.path.Path.contains_points()
to mask the original data array, but the disadvantage to this solution is
that it is very slow. Another solution that I have discovered recently is
to use the set_clip_path() method for artists. In addition to being much
faster, this also makes the areas near the polygon boundary look much
smoother since the actual items being clipped are individual pixels and not
data points.
Here is an example script that plots an image via imshow, but the only
part of the image that gets shown is inside the hexagon.
import numpy as np
import matplotlib.pyplot as plt
from matplotlib.patches import RegularPolygon
data = np.arange(100).reshape(10, 10)
fig = plt.figure()
ax = fig.add_subplot(111)
im = ax.imshow(data)
poly = RegularPolygon([ 0.5, 0.5], 6, 0.4, fc='none',
ec='k', transform=ax.transAxes)
im.set_clip_path(poly)
ax.add_patch(poly)
ax.axis('off')
plt.show()
While this does seem like an ideal solution, it doesn't work for every
type of plot. The most notable example is contourf(). It returns a
QuadContourSet instance which does not inherit from Artist, so it does not
contain the set_clip_path() method. My main question is whether there is a
mechanism in matplotlib that can convert something like a QuadContourSet
into an image so I can make use of this solution for contourf() as well. Or
better yet, is there perhaps another artist within the axes that I can use
the set_clip_path() method for and still get what I want?
Thanks,
Alex
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Graduate Research Assistant
Department of Atmospheric Science
Colorado State University
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Re: [Matplotlib-users] mpl-1.2.1: Speedup code by removing .startswith() calls and some for loops
Hi Martin, Thanks for this - we are really interested in speeding up the scatter and barchart plotting with large data sets. In fact, we've done some work ( https://github.com/matplotlib/matplotlib/pull/2156) recently to make the situation better. I'd really like to review these changes (against matplotlib master), and the best possible solution to doing this is if you were to submit a pull request. If the changes you have made are logically seperable, then I'd encourage you to make a few PRs, but otherwise, a single PR with all of these changes would be great. Would you mind turning these patches into PR(s)? ( https://github.com/matplotlib/matplotlib/compare/) Thanks! Phil On 9 August 2013 12:53, Martin Mokrejs mmokr...@fold.natur.cuni.cz wrote: Hi, I am drawing some barcharts and scatter plot and the speed for rendering is awful once you have 100 000 of dots. I ran python profiler which lead me to .startswith() calls and some for loops which append do a list repeatedly. This parts could be still sped up I think but a first attempt is here: UNPATCHED 1.2.1 real23m17.764s user13m25.880s sys 3m37.180s PATCHED: real6m59.831s user5m18.000s sys 1m40.360s The patches are simple and because I see elsewhere in the code list expansions I do not see any problems with backwards compatibility (new new python language features are required). Hope this helps, Martin -- Get 100% visibility into Java/.NET code with AppDynamics Lite! It's a free troubleshooting tool designed for production. Get down to code-level detail for bottlenecks, with 2% overhead. Download for free and get started troubleshooting in minutes. http://pubads.g.doubleclick.net/gampad/clk?id=48897031iu=/4140/ostg.clktrk ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users -- Get 100% visibility into Java/.NET code with AppDynamics Lite! It's a free troubleshooting tool designed for production. Get down to code-level detail for bottlenecks, with 2% overhead. Download for free and get started troubleshooting in minutes. http://pubads.g.doubleclick.net/gampad/clk?id=48897031iu=/4140/ostg.clktrk___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
Re: [Matplotlib-users] Bug in cbook.exception_to_str() (mpl 1.2)
Agreed. I've seen this a couple of times but never reproduced it so elegantly. Would you mind opening up an issue on github - this is definitely a bug (http://matplotlib.org/faq/troubleshooting_faq.html). Thanks! P.S. Welcome to the mailinglist :-) On 31 May 2013 16:02, Skip Montanaro s...@pobox.com wrote: I'm not sure of the correct protocol (I just subscribed to report this problem), but the documentation said to report bugs here, and I saw no mention of this in Google searches of the list archives. The exception_to_str() function was changed between mpl 1.1 and 1.2. In my installation I show it going from this: def exception_to_str(s = None): sh = StringIO.StringIO() if s is not None: print sh, s traceback.print_exc(file=sh) return sh.getvalue() to this: def exception_to_str(s=None): sh = io.StringIO() if s is not None: print(s, file=sh) traceback.print_exc(file=sh) return sh.getvalue() At first glance, the change seems innocuous enough, but I think it introduced an error. (It appears that mpl 1.2 is supposed to work on Python 2.7 and 3.x.) From a thread I started on comp.lang.python (http://thread.gmane.org/gmane.comp.python.general/733938), it appears that io.StringIO instances only accept Unicode strings as input. Unless v 1.2 is only supposed to run on Python 3 (that doesn't seem to be the case), you need to do something to convert the traceback module's output to Unicode before feeding to the io.StringIO object. Here's a simple demonstration of the problem: % python2.7 Python 2.7.5+ (2.7:93eb15779050, May 30 2013, 15:27:39) [GCC 4.4.6 [TWW]] on linux2 Type help, copyright, credits or license for more information. import traceback, StringIO, io s1 = StringIO.StringIO() traceback.print_stack(file=s1) print repr(s1.getvalue()) ' File stdin, line 1, in module\n' s2 = io.StringIO() traceback.print_stack(file=s2) Traceback (most recent call last): File stdin, line 1, in module File /home/skipm/x86_64-linux3.1/lib/python2.7/traceback.py, line 269, in print_stack print_list(extract_stack(f, limit), file) File /home/skipm/x86_64-linux3.1/lib/python2.7/traceback.py, line 23, in print_list ' File %s, line %d, in %s' % (filename,lineno,name)) File /home/skipm/x86_64-linux3.1/lib/python2.7/traceback.py, line 13, in _print file.write(str+terminator) TypeError: unicode argument expected, got 'str' Skip Montanaro s...@pobox.com -- Get 100% visibility into Java/.NET code with AppDynamics Lite It's a free troubleshooting tool designed for production Get down to code-level detail for bottlenecks, with 2% overhead. Download for free and get started troubleshooting in minutes. http://p.sf.net/sfu/appdyn_d2d_ap2 ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users -- Get 100% visibility into Java/.NET code with AppDynamics Lite It's a free troubleshooting tool designed for production Get down to code-level detail for bottlenecks, with 2% overhead. Download for free and get started troubleshooting in minutes. http://p.sf.net/sfu/appdyn_d2d_ap2___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
Re: [Matplotlib-users] Affine2D on scatter
Thanks Derek John. Very strange. Here's my setup: import matplotlib matplotlib.__version__ '1.2.0' matplotlib.get_backend() 'TkAgg' Would you mind providing all of the relevant details suggested in http://matplotlib.org/faq/troubleshooting_faq.html#troubleshooting, along with the code to reproduce the problem in a new github issue? Once I have all of the necessary details, I'd be happy to have a look into this to see if I can find a solution. Cheers, Phil On 5 April 2013 02:02, John Gleeson jdglee...@mac.com wrote: On 2013-04-04, at 10:51 AM, Derek Thomas wrote: ...screen capture of the display... grab.tiff Derek, I just tried Phil's version of the code on my Mac (MP 1.2.0), and I see exactly the same problem as in your grab.tiff. This is using the default TkAgg backend. I happen to have built MP 1.2.0 with the Qt4 backend option. When I prepend the lines from matplotlib import use use(QT4Agg) to use Qt4, I get the expected (correct) display output. Apparently this is a bug somewhere in the chain TkAgg/Tkinter/Tk. John -- Minimize network downtime and maximize team effectiveness. Reduce network management and security costs.Learn how to hire the most talented Cisco Certified professionals. Visit the Employer Resources Portal http://www.cisco.com/web/learning/employer_resources/index.html___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
Re: [Matplotlib-users] Affine2D on scatter
Hi Derek, What are we looking at here? The following code: import matplotlib.pyplot as plt import matplotlib.transforms as mtrans import numpy as np plt.figure() ax = plt.subplot(111) base_trans = ax.transData mtx = np.array([[1,1,0], [0,1,0], [0,0,1]]) tr = mtrans.Affine2D(matrix=mtx) + base_trans plt.plot([1,2,3], [1,2,3], 'gray', transform=tr) plt.scatter([1,2,3], [1,2,3], c='k', marker='D', transform=tr) plt.show() produces the following plot on v1.2.0: [image: Inline images 1] Is this unexpected or are you getting a different result to me? Regards, On 4 April 2013 17:06, Derek Thomas derekctho...@gmail.com wrote: I posted a related question on stackoverflow ( http://stackoverflow.com/questions/15815862/apply-affine-transform-to-quiver-in-python-matplotlib ) but I've produced a simple enough example with strange results that I think it merits attention here. I'm trying to apply affine transforms to quiver and scatter plots. In all cases that I've considered, the scatter and quiver plots transform opposite the regular plot. Here's a minimal case: import matplotlib as mpl from pylab import figure, subplot, plot, scatter, show, axis figure() ax = subplot(111) base_trans = ax.transData tr = mpl.transforms.Affine2D(matrix = array([[1,1,0],[0,1,0],[0,0,1]])) + base_trans plot( [1,2,3], [1,2,3], 'k.', transform = tr ) scatter( [1,2,3], [1,2,3], c = 'k', marker = 'D', transform = tr ) axis([0,7,0,7]) show() Thanks, Derek -- Minimize network downtime and maximize team effectiveness. Reduce network management and security costs.Learn how to hire the most talented Cisco Certified professionals. Visit the Employer Resources Portal http://www.cisco.com/web/learning/employer_resources/index.html ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users figure_1.png-- Minimize network downtime and maximize team effectiveness. Reduce network management and security costs.Learn how to hire the most talented Cisco Certified professionals. Visit the Employer Resources Portal http://www.cisco.com/web/learning/employer_resources/index.html___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
Re: [Matplotlib-users] MonthLocator doesn't honour rrule bymonthday -1 value for last day of month
Hi Mark,
Thanks for persevering :-)
What is it you want to achieve? Is it that you just want the last day of
each month as the located value?
Changing your locator to:
ax.xaxis.set_major_locator(MonthLocator(bymonthday = -1))
Seems to do the trick for me (I've never looked at the mpl date magic, so I
can give no guarantees).
HTH,
On 4 April 2013 17:18, Mark Lawrence breamore...@yahoo.co.uk wrote:
On 01/04/2013 14:48, Mark Lawrence wrote:
On 29/03/2013 15:49, Mark Lawrence wrote:
Hi all,
From http://labix.org/python-dateutil
To generate a rrule for the use case of a date on the specified day of
the month, unless it is beyond the end of month, in which case it will
be the last day of the month use the following:
rrule(MONTHLY, bymonthday=(some_day, -1), bysetpos=1)
This will generate a value for every calendar month regardless of the
day of the month it is started from.
Using bymonthday with MonthLocator gives ticks on the day given and the
last day of the month, which looks extremely ugly. Code below
demonstrates.
from dateutil.rrule import *
import datetime
import matplotlib.pyplot as plt
from matplotlib.ticker import FormatStrFormatter, MultipleLocator
from matplotlib.dates import DateFormatter, MonthLocator, DayLocator
start = datetime.date(2013, 3, 29)
until = datetime.date(2014, 3, 29)
dates = rrule(MONTHLY, bymonthday=(29, -1), bysetpos=1, until=until)
for d in dates:print(d)
dates = [start, until]
values = [0, 1]
plt.ylabel('Balance')
plt.grid()
ax = plt.subplot(111)
plt.plot_date(dates, values, fmt = 'rx-')
ax.xaxis.set_major_locator(MonthLocator(bymonthday = (dates[0].day,
-1)))
ax.xaxis.set_major_formatter(DateFormatter('%d/%m/%y'))
ax.yaxis.set_major_formatter(FormatStrFormatter('£%0.2f'))
ax.yaxis.set_minor_locator(MultipleLocator(5))
plt.axis(xmin=dates[0], xmax=dates[-1])
plt.setp(plt.gca().get_xticklabels(), rotation = 45, fontsize = 10)
plt.setp(plt.gca().get_yticklabels(), fontsize = 10)
plt.show()
Seems an apt date to realise that I didn't say much :(
Assuming that I'm correct would you like an issue raised on the bug
tracker? If not please correct the mistake I've made, presumably in
reading the docs, which I think are excellent by the way.
Anybody?
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Re: [Matplotlib-users] Problem with importing LaTeX package amsmath and $\text{}$
Doesn't look like you're using math.usetex therefore are not actually
using latex, but mpl's stripped down tex implementation.
Try setting usetex to True, or alternatively I think you could use \mathrm
instead of \text to get non mathematical text.
HTH
On 30 March 2013 11:43, Pawel Chojnacki chojnacki.pa...@linux.com wrote:
Hello,
I've been having some troubles with LaTeX in matplotlib. My example script:
#!/usr/bin/env python2
#-*- coding: utf-8 -*-
__author__ = 'Pawel Chojnacki'
__copyright__ ='Copyleft 2013 Pawel Chojnacki'
__version__ = '1.0'
__date__ = '29-03-2013'
__license__ = 'GPLv3'
import numpy as np
import matplotlib as mpl # Zmiana ustawien LaTeXa
mpl.rcParams['text.latex.preamble'].append(r'\usepackage{amsmath}')
#~ mpl.rcParams['text.latex.preamble'] = r'\usepackage{amsmath}'
#~ mpl.rcParams['text.latex.preamble']=[r\usepackage{amsmath}]
#~ mpl.rcParams['math.usetex'] = True
print mpl.rcParams['text.latex.preamble']
import pylab as py
py.axhspan(8400,8730,alpha=0.15)
py.title(u'Wyniki eksperymentu pomiaru gęstości ciała
stałego\n',size='large',family='serif')
py.ylabel((u'Gęstość ciała stałego ' +
r'$\frac{kg}{m^3}$'),size='large',family='serif')
#~ py.ylabel((r'$\text{lol}$'),size='large',family='serif')
py.ylabel((r'$\text{lol}$'),size='large',family='serif')
py.xlabel(u'Metoda pomiaru',size='large',family='serif')
py.grid(True)
py.show()
Gives me the following output:
['', '\\usepackage{amsmath}']
Exception in Tkinter callback
Traceback (most recent call last):
File /usr/lib/python2.7/lib-tk/Tkinter.py, line 1437, in __call__
return self.func(*args)
File
/usr/lib/pymodules/python2.7/matplotlib/backends/backend_tkagg.py, line
236, in resize
self.show()
File
/usr/lib/pymodules/python2.7/matplotlib/backends/backend_tkagg.py, line
239, in draw
FigureCanvasAgg.draw(self)
File /usr/lib/pymodules/python2.7/matplotlib/backends/backend_agg.py,
line 421, in draw
self.figure.draw(self.renderer)
File /usr/lib/pymodules/python2.7/matplotlib/artist.py, line 55, in
draw_wrapper
draw(artist, renderer, *args, **kwargs)
File /usr/lib/pymodules/python2.7/matplotlib/figure.py, line 898, in
draw
func(*args)
File /usr/lib/pymodules/python2.7/matplotlib/artist.py, line 55, in
draw_wrapper
draw(artist, renderer, *args, **kwargs)
File /usr/lib/pymodules/python2.7/matplotlib/axes.py, line 1997, in
draw
a.draw(renderer)
File /usr/lib/pymodules/python2.7/matplotlib/artist.py, line 55, in
draw_wrapper
draw(artist, renderer, *args, **kwargs)
File /usr/lib/pymodules/python2.7/matplotlib/axis.py, line 1054, in
draw
self.label.draw(renderer)
File /usr/lib/pymodules/python2.7/matplotlib/artist.py, line 55, in
draw_wrapper
draw(artist, renderer, *args, **kwargs)
File /usr/lib/pymodules/python2.7/matplotlib/text.py, line 526, in draw
bbox, info = self._get_layout(renderer)
File /usr/lib/pymodules/python2.7/matplotlib/text.py, line 309, in
_get_layout
ismath=ismath)
File /usr/lib/pymodules/python2.7/matplotlib/backends/backend_agg.py,
line 193, in get_text_width_height_descent
self.mathtext_parser.parse(s, self.dpi, prop)
File /usr/lib/pymodules/python2.7/matplotlib/mathtext.py, line 2999,
in parse
box = self._parser.parse(s, font_output, fontsize, dpi)
File /usr/lib/pymodules/python2.7/matplotlib/mathtext.py, line 2357,
in parse
self._expression.parseString(s)
File /usr/lib/pymodules/python2.7/matplotlib/pyparsing.py, line 1048,
in parseString
loc, tokens = self._parse( instring, 0 )
File /usr/lib/pymodules/python2.7/matplotlib/pyparsing.py, line 981,
in _parseCache
value = self._parseNoCache( instring, loc, doActions, callPreParse )
File /usr/lib/pymodules/python2.7/matplotlib/pyparsing.py, line 924,
in _parseNoCache
loc,tokens = self.parseImpl( instring, preloc, doActions )
File /usr/lib/pymodules/python2.7/matplotlib/pyparsing.py, line 2559,
in parseImpl
return self.expr._parse( instring, loc, doActions, callPreParse=False )
File /usr/lib/pymodules/python2.7/matplotlib/pyparsing.py, line 981,
in _parseCache
value = self._parseNoCache( instring, loc, doActions, callPreParse )
File /usr/lib/pymodules/python2.7/matplotlib/pyparsing.py, line 924,
in _parseNoCache
loc,tokens = self.parseImpl( instring, preloc, doActions )
File /usr/lib/pymodules/python2.7/matplotlib/pyparsing.py, line 2307,
in parseImpl
loc, exprtokens = e._parse( instring, loc, doActions )
File /usr/lib/pymodules/python2.7/matplotlib/pyparsing.py, line 981,
in _parseCache
value = self._parseNoCache( instring, loc, doActions, callPreParse )
File /usr/lib/pymodules/python2.7/matplotlib/pyparsing.py, line 924,
in _parseNoCache
loc,tokens = self.parseImpl( instring, preloc, doActions )
File /usr/lib/pymodules/python2.7/matplotlib/pyparsing.py, line 2672,
in parseImpl
loc, tokens =
Re: [Matplotlib-users] Feedback on an implementation of a matlab-ish datacursor
Thanks for this Joe, mpldatacursor looks like an excellent piece of work - I for one will be installing and using it regularly. Thanks for sharing! On 13 March 2013 03:58, Joe Kington joferking...@gmail.com wrote: I recently got around to polishing up a snippet I've been using for quite awhile. https://github.com/joferkington/mpldatacursor/ and I was hoping to get some feeding on the current implementation. mpldatacursor allows a user to easily click on an artist and display a customizable, interactive pop-up box displaying information about the selected artist (e.g. x y, label, z for images and collections, etc). It's a stand-alone module (and in pypi), but you could also just download the examples directory from github and copy the mpldatacursor.py file into it to try things out. A few key questions: 1. Is this something that anyone else finds useful? 2. Does it seem intuitive? 3. Does the implementation seem flexible enough for most needs? (Note that any additional kwargs are passed on to annotate to create the data cursor, so the appearance of the box is customizable through annotation kwargs.) 4. Are there any obvious features missing? 5. Any suggestions? (especially better name suggestions...) If it is something that other people find useful, I'd be happy to submit a pull request to incorporate it into matplotlib. (If I did, it would probably be best to drop the HighlightDataCursor class, as its limited in what it can do.) Thanks a bunch! -Joe -- Everyone hates slow websites. So do we. Make your web apps faster with AppDynamics Download AppDynamics Lite for free today: http://p.sf.net/sfu/appdyn_d2d_mar ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users -- Everyone hates slow websites. So do we. Make your web apps faster with AppDynamics Download AppDynamics Lite for free today: http://p.sf.net/sfu/appdyn_d2d_mar___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
Re: [Matplotlib-users] matplotlib multiple windows comparison
Hi Sudheer, Try the interactive mode ( http://matplotlib.org/api/pyplot_api.html#matplotlib.pyplot.ion): import matplotlib.pyplot as plt plt.ion() plt.plot(range(10)) [matplotlib.lines.Line2D object at 0x1c565d0] **a figure pops up here and hands you back the python command line** Regards, On 12 March 2013 00:04, Sudheer Joseph sudheer.jos...@yahoo.com wrote: Dear experts, Is there a way to get back to the prompt after a plot is made and displayed with out closing the plot? The objective is to compare to plots or check some aspect about the plot made from the loaded variables. This is the standard behavior of matlab after plotting we get the prompt and we can make another plot if we want to compare 2. I know there is subplot option but it will be of small size if I need to make a spatial map at to time intervals and compare. The detail of my matplotlib is below I use Ubuntu 12.04 64 bit version and In [3]: matplotlib.get_backend() Out[3]: 'WXAgg' In [4]: matplotlib.__version__ Out[4]: '1.2.0' with best regards, Sudheer *** Sudheer Joseph Indian National Centre for Ocean Information Services Ministry of Earth Sciences, Govt. of India POST BOX NO: 21, IDA Jeedeemetla P.O. Via Pragathi Nagar,Kukatpally, Hyderabad; Pin:5000 55 Tel:+91-40-23886047(O),Fax:+91-40-23895011(O), Tel:+91-40-23044600(R),Tel:+91-40-9440832534(Mobile) E-mail:sjo.in...@gmail.com;sudheer.jos...@yahoo.com Web- http://oppamthadathil.tripod.com *** -- *.* -- Symantec Endpoint Protection 12 positioned as A LEADER in The Forrester Wave(TM): Endpoint Security, Q1 2013 and remains a good choice in the endpoint security space. For insight on selecting the right partner to tackle endpoint security challenges, access the full report. http://p.sf.net/sfu/symantec-dev2dev ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users -- Symantec Endpoint Protection 12 positioned as A LEADER in The Forrester Wave(TM): Endpoint Security, Q1 2013 and remains a good choice in the endpoint security space. For insight on selecting the right partner to tackle endpoint security challenges, access the full report. http://p.sf.net/sfu/symantec-dev2dev___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
Re: [Matplotlib-users] basemap and imshow at high latitudes
Hi Mike, Do you have any code or an image to show the problem? Cheers, On 11 March 2013 20:44, Hearne, Mike mhea...@usgs.gov wrote: I have an issue with basemap.imshow() at higher latitudes - namely the image (high-res topography, in this case) becomes distorted with respect to the coastlines the higher I go.I assume it has to do with the image pixels becoming more non-square the higher I go in latitude. I found this discussion: http://matplotlib.1069221.n5.nabble.com/Basemap-and-imshow-td14115.html where Jeff indicates that the user is using a non-rectangular map projection. I'm thinking that is perhaps my problem (I'm using Transverse Mercator), but I'm not sure which projections Basemap supports that *are* rectangular. Or perhaps it's something else entirely. Any hints? Thanks, Mike Hearne -- Symantec Endpoint Protection 12 positioned as A LEADER in The Forrester Wave(TM): Endpoint Security, Q1 2013 and remains a good choice in the endpoint security space. For insight on selecting the right partner to tackle endpoint security challenges, access the full report. http://p.sf.net/sfu/symantec-dev2dev ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users -- Symantec Endpoint Protection 12 positioned as A LEADER in The Forrester Wave(TM): Endpoint Security, Q1 2013 and remains a good choice in the endpoint security space. For insight on selecting the right partner to tackle endpoint security challenges, access the full report. http://p.sf.net/sfu/symantec-dev2dev___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
Re: [Matplotlib-users] Plotting with WxAgg backend hangs
I don't know of any reason why one shouldn't be able to use the wxAgg
backend interactively.
This looks like a bug to me. Would you mind adding this as an issue on the
github issue tracker?
Thanks,
On 11 March 2013 19:06, Brendan Barnwell brenb...@brenbarn.net wrote:
I'm 64-bit Windows 7 with matplotlib 1.2.0 and WxPython 2.8.12.1.
I
was fiddling around with some of the different backends to see what
they look like and I found that the WxAgg backend doesn't work:
Python 2.7.3 (default, Apr 10 2012, 23:24:47) [MSC v.1500 64 bit
(AMD64)] on win
32
Type help, copyright, credits or license for more information.
import matplotlib as mpl
mpl.use('WxAgg')
from matplotlib import pyplot
pyplot.ion()
pyplot.plot([1, 2, 3])
[matplotlib.lines.Line2D object at 0x06757DA0]
When I do the plot, the figure windows appears, but it's blank
(without even a proper blank background, just a white area) and
immediately shows Not responding. I have to kill the window, and
doing so crashes the Python session. However, it works without the
ion() call: I can then call show() and see the plot fine.
I have wxPython working fine in other apps. In fact, what's
especially odd is that I actually have an app that directly uses
FigureCanvasWxAgg to embed matplotlib graphs in a GUI, and this seems
to work fine. So it seems the problem is somehow in matplotlib's own
management of the interactive figure window.
There was a previous question about a similar WxAgg issue on the
list
(
http://matplotlib.1069221.n5.nabble.com/trouble-with-show-not-drawing-in-interactive-mode-w-WxAgg-td39110.html
), but there was no real answer: the poster just decided not to use
WxAgg. But aren't we really supposed to be able to use WxAgg
interactively?
Thanks,
--
Brendan Barnwell
Do not follow where the path may lead. Go, instead, where there is
no path, and leave a trail.
--author unknown
--
Symantec Endpoint Protection 12 positioned as A LEADER in The Forrester
Wave(TM): Endpoint Security, Q1 2013 and remains a good choice in the
endpoint security space. For insight on selecting the right partner to
tackle endpoint security challenges, access the full report.
http://p.sf.net/sfu/symantec-dev2dev
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Wave(TM): Endpoint Security, Q1 2013 and remains a good choice in the
endpoint security space. For insight on selecting the right partner to
tackle endpoint security challenges, access the full report.
http://p.sf.net/sfu/symantec-dev2dev___
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Re: [Matplotlib-users] matplotlib multiple windows comparison
I hadn't spotted you were using the WxAgg backend too - this looks like the same bug that Brendan reported yesterday. The *easiest* solution would be to use another back-end until this is fixed. Do you have 'TkAgg' available? I currently do not have a wx installation to hand to try out any workarounds at the moment. Regards, On 12 March 2013 14:00, Sudheer Joseph sudheer.jos...@yahoo.com wrote: Thank you Phil, But I had tried it earlier after seeing a another mail thread. I get command prompt but no figure pops up. In [3]: import matplotlib.pyplot as plt In [4]: plt.ion() In [5]: plt.plot(range(10)) Out[5]: [matplotlib.lines.Line2D at 0x410f250] In [6]: Any way out?? with best regards, Sudheer *** Sudheer Joseph Indian National Centre for Ocean Information Services Ministry of Earth Sciences, Govt. of India POST BOX NO: 21, IDA Jeedeemetla P.O. Via Pragathi Nagar,Kukatpally, Hyderabad; Pin:5000 55 Tel:+91-40-23886047(O),Fax:+91-40-23895011(O), Tel:+91-40-23044600(R),Tel:+91-40-9440832534(Mobile) E-mail:sjo.in...@gmail.com;sudheer.jos...@yahoo.com Web- http://oppamthadathil.tripod.com *** -- *From:* Phil Elson pelson@gmail.com *To:* Sudheer Joseph sudheer.jos...@yahoo.com *Cc:* matplotlib-users@lists.sourceforge.net matplotlib-users@lists.sourceforge.net *Sent:* Tuesday, 12 March 2013 3:08 PM *Subject:* Re: [Matplotlib-users] matplotlib multiple windows comparison Hi Sudheer, Try the interactive mode ( http://matplotlib.org/api/pyplot_api.html#matplotlib.pyplot.ion): import matplotlib.pyplot as plt plt.ion() plt.plot(range(10)) [matplotlib.lines.Line2D object at 0x1c565d0] **a figure pops up here and hands you back the python command line** Regards, On 12 March 2013 00:04, Sudheer Joseph sudheer.jos...@yahoo.com wrote: Dear experts, Is there a way to get back to the prompt after a plot is made and displayed with out closing the plot? The objective is to compare to plots or check some aspect about the plot made from the loaded variables. This is the standard behavior of matlab after plotting we get the prompt and we can make another plot if we want to compare 2. I know there is subplot option but it will be of small size if I need to make a spatial map at to time intervals and compare. The detail of my matplotlib is below I use Ubuntu 12.04 64 bit version and In [3]: matplotlib.get_backend() Out[3]: 'WXAgg' In [4]: matplotlib.__version__ Out[4]: '1.2.0' with best regards, Sudheer *** Sudheer Joseph Indian National Centre for Ocean Information Services Ministry of Earth Sciences, Govt. of India POST BOX NO: 21, IDA Jeedeemetla P.O. Via Pragathi Nagar,Kukatpally, Hyderabad; Pin:5000 55 Tel:+91-40-23886047(O),Fax:+91-40-23895011(O), Tel:+91-40-23044600(R),Tel:+91-40-9440832534(Mobile) E-mail:sjo.in...@gmail.com;sudheer.jos...@yahoo.com Web- http://oppamthadathil.tripod.com *** -- *.* -- Symantec Endpoint Protection 12 positioned as A LEADER in The Forrester Wave(TM): Endpoint Security, Q1 2013 and remains a good choice in the endpoint security space. For insight on selecting the right partner to tackle endpoint security challenges, access the full report. http://p.sf.net/sfu/symantec-dev2dev ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users -- Symantec Endpoint Protection 12 positioned as A LEADER in The Forrester Wave(TM): Endpoint Security, Q1 2013 and remains a good choice in the endpoint security space. For insight on selecting the right partner to tackle endpoint security challenges, access the full report. http://p.sf.net/sfu/symantec-dev2dev___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
Re: [Matplotlib-users] why does transform=None cause a patch not to be shown?
The key thing to know about normal Artists is that they can have *just one*transform (to take an artist's coordinates into pixel space), so whilst there is no error when you do it, it is not possible to add the same artist to multiple Axes and have the desired effect. To answer your question, try creating two Rectangles and adding one to each of your Axes. HTH -- Symantec Endpoint Protection 12 positioned as A LEADER in The Forrester Wave(TM): Endpoint Security, Q1 2013 and remains a good choice in the endpoint security space. For insight on selecting the right partner to tackle endpoint security challenges, access the full report. http://p.sf.net/sfu/symantec-dev2dev___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
Re: [Matplotlib-users] View datetime corresponding to x coordinate of cursor
Sounds like a nice feature if it doesn't already exist. At first glance, I'd say this was a good candidate for the low-hanging fruit label ( https://github.com/matplotlib/matplotlib/issues?labels=low+hanging+fruitpage=1state=open) for which we have tickets which have a low matplotlib contribution experience barrier and a relatively good return on investment (in terms of time spent). Please feel free to create an issue on the github tracker if you're keen, I'd encourage you to have a go at implementing it. Cheers, On 4 March 2013 19:34, Paul Hobson pmhob...@gmail.com wrote: On Mon, Mar 4, 2013 at 11:23 AM, William Furnass w...@thearete.co.ukwrote: Several backends will show you the x and y float values that correspond to the current cursor position in a plot() but are there backends that show the _datetime_ corresponding to the x position if the plotted data is a time series (e.g. a pandas.Series object with a DatetimeIndex)? Regards, Will Will, You can use the `format_coord` method of the axes objects to do just this. -paul -- Everyone hates slow websites. So do we. Make your web apps faster with AppDynamics Download AppDynamics Lite for free today: http://p.sf.net/sfu/appdyn_d2d_feb ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users -- Everyone hates slow websites. So do we. Make your web apps faster with AppDynamics Download AppDynamics Lite for free today: http://p.sf.net/sfu/appdyn_d2d_feb___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
Re: [Matplotlib-users] depth longitude plot
Perhaps something like: from matplotlib import pyplot as plt from netCDF4 import Dataset import numpy as np url=*' http://www.marine.csiro.au/dods/nph-dods/dods-data/climatology-netcdf/levitus_monthly_temp_98.nc '* ds = Dataset(url) temp = ds.variables[*'TEMP'*] lats = ds.variables[*'**lat**'*] lons = ds.variables[*'**lon**'*] depths = ds.variables[*'z'*] # filter all but one latitude lat_index = np.where(lats[:] == 0.5)[0][0] lats = lats[lat_index] # filter a range of longitudes lon_lower_index = np.where(lons[:] == 44.5)[0][0] lon_upper_index = np.where(lons[:] == 100.5)[0][0] lons = lons[lon_lower_index:lon_upper_index] temp = temp[0, :, lat_index, lon_lower_index:lon_upper_index] plt.pcolormesh(lons, depths[:], temp) plt.gca().invert_yaxis() plt.show() The indexing approach used here is quite flakey, so I certainly wouldn't use this in anything operational. Hope this helps, Phil attachment: figure_1.png-- Everyone hates slow websites. So do we. Make your web apps faster with AppDynamics Download AppDynamics Lite for free today: http://p.sf.net/sfu/appdyn_d2d_feb___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
Re: [Matplotlib-users] depth longitude plot
Incidentally, if you wanted to do this a little more expressively than indexing, you could look into using iris ( http://scitools.org.uk/iris/docs/latest/index.html). It doesn't currently support DAP, but if you had the NetCDF file (from * http://www.marine.csiro.au/dods-data/climatology-netcdf/levitus_monthly_temp_98.nc *) you would do: import iris import iris.quickplot as qplt import matplotlib.pyplot as plt temp_cube = iris.load_cube(*'levitus_monthly_temp_98.**nc**'*) # Sort out some of the bad metadata. Firstly, set the unit, # secondly rename the dimension 1 coordinate to 'depth'. temp_cube.unit = *'C'* temp_cube.coord(dimensions=1, dim_coords=True).rename(*'depth'*) # Extract a spatial sub-domain. sub_temp_cube = temp_cube.extract(iris.Constraint(latitude=0.5, longitude=lambda v: 45 v 100)) # Iterate over all the depth-longitude sections (in this case it # iterates over time) for cross_sect_cube in sub_temp_cube.slices([*'depth'*, *'longitude'*]): qplt.pcolormesh(cross_sect_cube) plt.gca().invert_yaxis() plt.show() break [image: Inline images 1] Hope that helps! Phil On 2 March 2013 09:37, Phil Elson pelson@gmail.com wrote: Perhaps something like: from matplotlib import pyplot as plt from netCDF4 import Dataset import numpy as np url=*' http://www.marine.csiro.au/dods/nph-dods/dods-data/climatology-netcdf/levitus_monthly_temp_98.nc '* ds = Dataset(url) temp = ds.variables[*'TEMP'*] lats = ds.variables[*'**lat**'*] lons = ds.variables[*'**lon**'*] depths = ds.variables[*'z'*] # filter all but one latitude lat_index = np.where(lats[:] == 0.5)[0][0] lats = lats[lat_index] # filter a range of longitudes lon_lower_index = np.where(lons[:] == 44.5)[0][0] lon_upper_index = np.where(lons[:] == 100.5)[0][0] lons = lons[lon_lower_index:lon_upper_index] temp = temp[0, :, lat_index, lon_lower_index:lon_upper_index] plt.pcolormesh(lons, depths[:], temp) plt.gca().invert_yaxis() plt.show() The indexing approach used here is quite flakey, so I certainly wouldn't use this in anything operational. Hope this helps, Phil figure_1.png-- Everyone hates slow websites. So do we. Make your web apps faster with AppDynamics Download AppDynamics Lite for free today: http://p.sf.net/sfu/appdyn_d2d_feb___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
Re: [Matplotlib-users] changing the shade of a color depending on a value
Joe Kington's answer is the best solution I've seen to this problem: http://stackoverflow.com/questions/13622909/matplotlib-how-to-colorize-a-large-number-of-line-segments-as-independent-gradi There is also an example in the gallery: http://matplotlib.org/examples/pylab_examples/multicolored_line.html HTH On 27 February 2013 09:49, Rita rmorgan...@gmail.com wrote: Hi, I am currently plotting cpu utilization over time (plot_time). I would like the color of my line to be red when at 100%. 80-90% a bit less red, more yellow, and lower numbers will be green. Any thoughts of doing this? -- --- Get your facts first, then you can distort them as you please.-- -- Everyone hates slow websites. So do we. Make your web apps faster with AppDynamics Download AppDynamics Lite for free today: http://p.sf.net/sfu/appdyn_d2d_feb ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users -- Everyone hates slow websites. So do we. Make your web apps faster with AppDynamics Download AppDynamics Lite for free today: http://p.sf.net/sfu/appdyn_d2d_feb___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
Re: [Matplotlib-users] cross hatching in contours?
As of matplotlib v1.2.0 you can hatch a contour set directly. There is an example in the gallery: http://matplotlib.org/examples/pylab_examples/contourf_hatching.html Hope that helps, Phil On 5 December 2012 17:28, spencerahill spencerah...@gmail.com wrote: Jae-Joon Lee wrote On Thu, Sep 15, 2011 at 10:33 PM, Jonathan Slavin lt; jslavin@.harvard gt; wrote: I'm wondering if there is some way to do cross hatching as a way to fill contours rather than colors (using contourf). The only references to cross hatching I see in the documentation are for patches type objects. As far as I can tell, contour and contourf return objects of their own type (contour.QuadContourSet) that do not have hatch as an attribute. Yes, it seems that hatching is only supported in patches. You may workaround this by converting contours to multiple patches. See the attachment. Matplotlib-users mailing list Matplotlib-users@.sourceforge https://lists.sourceforge.net/lists/listinfo/matplotlib-users contour_to_hatched_patches.py (1K) lt; http://matplotlib.1069221.n5.nabble.com/attachment/23/0/contour_to_hatched_patches.pygt ; Hi Jae-Joon, Your contour_to_hatched_patches.py script works excellently. Is there a way to suppress the contour lines and filling, leaving only stippling? I have been experimenting with it but no luck. I have a contourf of a 2D variable and a separate 2D array indicating regions of statistical significance (i.e. a mask, which equals 1 in cells where the variable is significant and equals 0 else), and I want to put black hatching over the contourf where it is significant. I can get this to work, but still with a black contour line surrounding the hatched region. I'd like to remove the line, leaving just the hatching. Thanks! Best, Spencer -- View this message in context: http://matplotlib.1069221.n5.nabble.com/cross-hatching-in-contours-tp22p39945.html Sent from the matplotlib - users mailing list archive at Nabble.com. -- LogMeIn Rescue: Anywhere, Anytime Remote support for IT. Free Trial Remotely access PCs and mobile devices and provide instant support Improve your efficiency, and focus on delivering more value-add services Discover what IT Professionals Know. Rescue delivers http://p.sf.net/sfu/logmein_12329d2d ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users -- LogMeIn Rescue: Anywhere, Anytime Remote support for IT. Free Trial Remotely access PCs and mobile devices and provide instant support Improve your efficiency, and focus on delivering more value-add services Discover what IT Professionals Know. Rescue delivers http://p.sf.net/sfu/logmein_12329d2d___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
Re: [Matplotlib-users] mailing list archive broken ?
Hi Pierre, Thanks for raising this (sorry we haven't got back to you sooner). The mailing list isn't dead, but the archiving link certainly makes it look like it is. I've just submitted a pull request ( https://github.com/matplotlib/matplotlib/pull/1540) to get the mpl docs to link to the nabble archive instead (http:// matplotlib.1069221.n5.nabble.com/matplotlib-users-f3.html). FYI There are a couple of topics related to this which I will raise in the mpl-devel mailing list sortly. Thanks, Phil On 4 October 2012 08:55, Pierre Haessig pierre.haes...@crans.org wrote: Hi, Is it just my web browser getting crazy or is there a real issue with the ML archive on sourceforge: http://sourceforge.net/mailarchive/forum.php?forum_name=matplotlib-users I only see email records until July 16th 2012 !! If there is another ML archive website in better shape, it would be worth updating the link on matplotlib.org front page (Documentation/need help? section) Best, Pierre -- Don't let slow site performance ruin your business. Deploy New Relic APM Deploy New Relic app performance management and know exactly what is happening inside your Ruby, Python, PHP, Java, and .NET app Try New Relic at no cost today and get our sweet Data Nerd shirt too! http://p.sf.net/sfu/newrelic-dev2dev ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users -- Keep yourself connected to Go Parallel: INSIGHTS What's next for parallel hardware, programming and related areas? Interviews and blogs by thought leaders keep you ahead of the curve. http://goparallel.sourceforge.net___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
Re: [Matplotlib-users] aspect ratio bug ?
The original question was raised in a mpl ticket:
https://github.com/matplotlib/matplotlib/issues/1513
My original answer there (copied pasted):
The bbox_inches='tight' option to savefig does some analysis on the artists
visible on your plot and figures out the minimum bounding box needed to fit
all of the artists on the plot. In doing so, *it will reduce the size of
the outputted image, rather than keeping the size and zooming in*. A
really simple example to show this (not using basemap):
import matplotlib.pyplot as plt
fig = plt.figure(figsize=(3, 4))
ax = plt.axes([0.4, 0.4, 0.2, 0.2])
ax.plot(range(10))
plt.savefig('figsize_no_tight.png')
plt.savefig('figsize_tight.png', bbox_inches='tight')
$ file figsize_*
figsize_no_tight.png: PNG image data, 300 x 400, 8-bit/color RGBA,
non-interlaced
figsize_tight.png:PNG image data, 98 x 123, 8-bit/color RGBA, non-interlaced
*Matt has said that he doesn't think this addresses the issue *so anyone
else with any ideas, please chip in!
My suspicion is that what is being described is a combination of
bbox_inches=tight and a snapping issue relating to the fixed aspect
(snapping here could be literally mpl snapping, or could simply be floating
point problems).
Hope someone else has some ideas about what is going on.
Cheers,
Phil
On 20 November 2012 00:25, sav...@nsidc.org wrote:
Hi there,
I've boiled down a problem and while the following my look useless, I need
to understand why matplotlib is behaving like it is.
Below is code showing my issue. I don't believe the issue is with the
bbox_inches='tight', if you leave that off, my image is indeed, 800x1400,
but the last row is a row of transparent pixels(on linux/not mac). It's
difficult to see unless you use the imagemagik command display.
The basic problem is that when my data has an aspect ratio very close to
1.75, the image gets changed to one with an aspect of 1.74875.
Correct figure info 8x14@100dpi = 800x1400 = 1.75 Aspect Ratio.
Incorrect figure info = 800x1399 = 1.74875
Data that works aspect ratio: 1.7498
Data that fails aspect ratio: 1.7496
--- Srsly?! ---^
It would be great if someone could explain to me what's happening if this
is indeed working as expected. If it's not, it would be great if someone
could fix it.
Thanks in advance.
Matt
import matplotlib.pyplot as plt
def create_image():
# I want an 800x1400 image (aspect = 1400/800 = 1.75.
fig = plt.figure(1, figsize=(8, 14), frameon=False, dpi=100)
# Use the whole figure and fill with a patch.
fig.add_axes([0, 0, 1, 1])
ax = plt.gca()
limb = ax.axesPatch
limb.set_facecolor('#6587ad')
# Set some bounds with Aspects very close to the desired aspect ratios.
x1 = 0.0
y1 = 0.0
x2 = 16.
# If you un-comment out this line (and comment the one below). I get
an image I expect
# y2 = 27.994671 # produces 800 x 1400 image
# aspect = 1.7498 works
# Use this line and I get and image the wrong size (or with
transparent pixels.)
y2 = 27.994670 # produces (wrong?) 800 x 1399 image
# aspect = 1.7496 Fails? wat?
corners = ((x1, y1), (x2, y2))
ax.update_datalim(corners)
ax.set_xlim((x1, x2))
ax.set_ylim((y1, y2))
ax.set_aspect('equal', anchor='C')
ax.set_xticks([])
ax.set_yticks([])
plt.savefig('rectangle.png', pad_inches=0.0, bbox_inches='tight')
# If you use this below, the file size is correct, but there is a
single
# line transparent pixels along the bottom of the image
# plt.savefig('rectangle.png', pad_inches=0.0)
if __name__ == '__main__':
create_image()
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Re: [Matplotlib-users] Plotting a circle while also changing the limits of the axes
Hi Brad, I didn't quite follow what it was that you were trying to achieve, but the following example may be of interest to you: import matplotlib.pyplot as plt from matplotlib.patches import Ellipse, Circle import matplotlib.transforms as mtrans fig = plt.figure() ax1 = fig.add_subplot(111) x_in_axes_coords, y_in_axes_coords = 0.5, 0.5 radius_in_axes = 0.3 coords = [[x_in_axes_coords, y_in_axes_coords], [x_in_axes_coords + radius_in_axes, y_in_axes_coords]] coords = ax1.transAxes.transform(coords) x_device, y_device = coords[0, :] radius = coords[1, 0] - x_device circle = Circle((x_device, y_device), radius, transform=mtrans.IdentityTransform()) fig.artists.append(circle) plt.show() Clearly, you will always have circles with this approach (the circle is defined in device coordinates, i.e. pixels), but with the way this is implemented, it does not behave in the same way as axes coordinates do when you resize your window. I am trying to plot some small circles in my plotting window, in addition to the curves I'm already plotting. I wonder if you would mind expanding on that sentence? Does the example I provide do what you want? Thanks, Phil On 5 November 2012 20:51, Brad Malone brad.mal...@gmail.com wrote: Hello, I am trying to plot some small circles in my plotting window, in addition to the curves I'm already plotting. If I don't want to set my x- and y- axis scales equal to each other, a naive drawing of a circle results in an ellipse. To fix this problem I found some nice example code online here : http://stackoverflow.com/questions/9230389/why-is-matplotlib-plotting-my-circles-as-ovals, which solves the problem by basically plotting an ellipse, but an ellipse which will look like a circle in the display window. That works all fine for me, but then, if I change my xlim or ylim using ax1.set_xlim((something1,something2)) then the solution no longer works, and I get an ellipse. A minimal example showing the breaking behavior can be seen below. import matplotlib.pyplot as plt from matplotlib.patches import Ellipse, Circle fig = plt.figure() ax1 = fig.add_subplot(111) # uncomment the following line to see it break #ax1.set_xlim((0.2,1)) # calculate asymmetry of x and y axes: x0, y0 = ax1.transAxes.transform((0, 0)) # lower left in pixels x1, y1 = ax1.transAxes.transform((1, 1)) # upper right in pixes dx = x1 - x0 dy = y1 - y0 maxd = max(dx, dy) width = .15 * maxd / dx height = .15 * maxd / dy # a circle you expect to be a circle, but it is not ax1.add_artist(Circle((.5, .5), .15)) # an ellipse you expect to be an ellipse, but it's a circle ax1.add_artist(Ellipse((.75, .75), width, height)) plt.show() I suppose the problem is that ax1.transAxes.transform commands return the same numbers, regardless of whether I've changed the limits or not. Is there an easy and clean way to fix this (perhaps a different command for getting x0,y0,x1, and y1)? Thanks for the help! Best, Brad -- LogMeIn Central: Instant, anywhere, Remote PC access and management. Stay in control, update software, and manage PCs from one command center Diagnose problems and improve visibility into emerging IT issues Automate, monitor and manage. Do more in less time with Central http://p.sf.net/sfu/logmein12331_d2d ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users -- LogMeIn Central: Instant, anywhere, Remote PC access and management. Stay in control, update software, and manage PCs from one command center Diagnose problems and improve visibility into emerging IT issues Automate, monitor and manage. Do more in less time with Central http://p.sf.net/sfu/logmein12331_d2d___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
Re: [Matplotlib-users] Type 1 fonts with log graphs
Hi Brandon,
I notice that this is cross-posted on StackOverflow (
http://stackoverflow.com/questions/13132194/type-1-fonts-with-log-graphs).
Personally, I have no problem with cross posting, but to save two people
having to answer the same question, I would make sure it was explicit that
this had also been posted elsewhere.
Thanks,
Phil
On 30 October 2012 03:13, Brandon Heller brand...@stanford.edu wrote:
Hi,
I'm trying to use Matplotlib graphs as part of a camera-ready
submission, and the publishing house requires the use of Type 1 fonts
only.
I'm finding that the PDF backend happily outputs Type-1 fonts for
simple graphs with linear Y axes, but outputs Type-3 fonts for
logarithmic Y axes.
Using a logarithmic yscale incurs the use of mathtext, which seems to
use Type 3 fonts, presumably because of the default use of exponential
notation. I can use an ugly hack to get around this - using
pyplot.yticks() to force the axis ticks to not use exponents - but
this would require moving the plot region to accommodate large labels
(like 10 ^ 6) or writing the axes as 10, 100, 1K, etc. so they fit.
There's a minimum working example below, which I've tested with the
matplotlib master branch as of today, as well as 1.1.1, which produces
the same behavior, so I don't know that this is a bug, probably just
unexpected behavior.
#!/usr/bin/env python
# Simple program to test for type 1 fonts.
# Generate a line graph w/linear and log Y axes.
from matplotlib import rc, rcParams
#rc('font',**{'family':'sans-serif','sans-serif':['Helvetica']})
# These lines are needed to get type-1 results:
#
http://nerdjusttyped.blogspot.com/2010/07/type-1-fonts-and-matplotlib-figures.html
rcParams['ps.useafm'] = True
rcParams['pdf.use14corefonts'] = True
rcParams['text.usetex'] = False
import matplotlib.pyplot as plt
YSCALES = ['linear', 'log']
def plot(filename, yscale):
plt.figure(1)
xvals = range(1, 2)
yvals = xvals
plt.plot(xvals, yvals)
plt.yscale(yscale)
#YTICKS = [1, 10]
#plt.yticks(YTICKS, YTICKS) # locs, labels
ax = plt.gca()
#print ax.get_xticklabels()[0].get_text()
print ,.join([a.get_label() for a in ax.get_yticklabels()])
plt.savefig(filename + '.pdf')
if __name__ == '__main__':
for yscale in YSCALES:
plot('linegraph-' + yscale, yscale)
Does anyone know a clean way to get Type 1 fonts with log axes?
Thanks,
Brandon
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Re: [Matplotlib-users] Reading a remote JPG URL using imread
Good idea. If the png version works then the jpg version should also be made to work, Would you be willing to open up an issue for the feature request? : https://github.com/matplotlib/matplotlib/issues/new If your ready and willing to implement such a thing, that would be even better (just open a pull request and we can start reviewing)! All the best, Phil On 19 October 2012 15:59, Rich Signell rsign...@usgs.gov wrote: MPL folks, Would it be possible to enhance Matplotlib to allow im=imread(url) to work if url returns a JPG? Currently (it seems): 1. If the URL returns a PNG this works: im = imread(urllib2.urlopen(url)) 2. If the URL returns a JPG, this DOESN'T work: im = imread(urllib2.urlopen(url)) .. and neither does this: im = imread(urllib2.urlopen(url),format='jpg') ... but this DOES work: im = Image.open(cStringIO.StringIO(urllib.urlopen(url).read())) See an example in Ipython Notebook here: http://nbviewer.ipython.org/3918576/ So could just be hidden from the user so that im = imread(url) would just work for JPG (assuming PIL was installed)? Thanks, Rich -- Dr. Richard P. Signell USGS, 384 Woods Hole Rd. Woods Hole, MA 02543-1598 -- Everyone hates slow websites. So do we. Make your web apps faster with AppDynamics Download AppDynamics Lite for free today: http://p.sf.net/sfu/appdyn_sfd2d_oct ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users -- Everyone hates slow websites. So do we. Make your web apps faster with AppDynamics Download AppDynamics Lite for free today: http://p.sf.net/sfu/appdyn_sfd2d_oct___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
Re: [Matplotlib-users] Normalize and special scalar handling
If nothing speaks against it, i could do a pull request. If you are willing, I would encourage you to do that, or at least make a branch in your matplotlib fork and post the diff URL here. That way we can discuss the pros cons in-line, even if it means that we do no actually merge the PR (that sounds bad, but really pull requests are a great medium for discussing code). Thanks! Phil -- Everyone hates slow websites. So do we. Make your web apps faster with AppDynamics Download AppDynamics Lite for free today: http://p.sf.net/sfu/appdyn_sfd2d_oct___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
Re: [Matplotlib-users] mpl command-line utilities
I can certainly see the benefit. As Mike said, I don't think I would use it myself, but I could see non-python users finding it useful. Personally, I think this would be a nice extension that doesn't have to live in the core matplotlib code base. That way release cycles and testing can be done completely independently without complicating the matplotlib repo. Nice idea. Phil On 17 October 2012 16:20, Daπid davidmen...@gmail.com wrote: I also think that would be useful. It would, for example, allow to generate preview plots from other languages, without interfacing them to Python. It must be said that MPL is actually quite nice looking in the default settings for basic plotting, and this is an nice feature that can exploit. I have seen many pieces of code using SuperMongo for plotting. I find it absolutely ugly, and super expensive, but it is probably the easier plotting system to call from FORTRAN (or, at least, it was). On Wed, Oct 17, 2012 at 3:15 PM, Michael Droettboom md...@stsci.edu wrote: I think this could be very useful -- and might help increase the user base beyond the Python community. As I, and most of us on this list, are quite comfortable with Python, I don't think I'd use it myself, but I certainly see the utility of it. Mike On 10/17/2012 06:38 AM, Damon McDougall wrote: All, I was brain-storming yesterday and I wanted to test the waters to see if people would find it useful. Currently, GNU plotutils comes with command-line utilities such as `graph` to create quick and dirty line plots like this: http://www.gnu.org/software/gsl/manual/html_node/DWT-Examples.html. I think even gnuplot might be similar. How do people feel about perhaps adding a matplotlib version, mocking the same calling signature as graph? I think the most important question is: would it be useful? -- Everyone hates slow websites. So do we. Make your web apps faster with AppDynamics Download AppDynamics Lite for free today: http://p.sf.net/sfu/appdyn_sfd2d_oct ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users -- Everyone hates slow websites. So do we. Make your web apps faster with AppDynamics Download AppDynamics Lite for free today: http://p.sf.net/sfu/appdyn_sfd2d_oct ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users -- Everyone hates slow websites. So do we. Make your web apps faster with AppDynamics Download AppDynamics Lite for free today: http://p.sf.net/sfu/appdyn_sfd2d_oct___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
Re: [Matplotlib-users] plot() question
To plot a line using pyplot.plot you need an array/list of x coordinates and an array/list of y coordinates. So if you have: data = [[64, 13], [66, 22], [68, 9], [70, 11], [72, 8], [74, 10], [76, 11], [78, 8], [80, 9], [82, 9], [84, 15], [86, 13], [88, 5], [90, 9], [92, 13], [94, 12], [96, 7]] You can get a list of xs and a list of ys with: xs, ys = zip(*data) From that point, it is as simple as doing: import matplotlib.pyplot as plt plt.plot(xs, ys) Hope that helps, Phil On 16 October 2012 09:39, ran...@0x06.net ran...@0x06.net wrote: [[64, 13], [66, 22], [68, 9], [70, 11], [72, 8], [74, 10], [76, 11], [78, 8], [80, 9], [82, 9], [84, 15], [86, 13], [88, 5], [90, 9], [92, 13], [94, 12], [96, 7]] -- Don't let slow site performance ruin your business. Deploy New Relic APM Deploy New Relic app performance management and know exactly what is happening inside your Ruby, Python, PHP, Java, and .NET app Try New Relic at no cost today and get our sweet Data Nerd shirt too! http://p.sf.net/sfu/newrelic-dev2dev___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
Re: [Matplotlib-users] XKCD style graphs?
Nice challenge Fernando!
Damon, I love the solution! I do wonder whether we could do some
quirky transform on the lines to achieve a similar result, rather than
manipulating the data before plotting it. The benefit is that
everything should then get randomly Xkcd-ed automatically - maybe I
will save that one for a rainy day
Thanks for posting!
On 4 October 2012 11:31, Damon McDougall damon.mcdoug...@gmail.com wrote:
On Thu, Oct 4, 2012 at 10:44 AM, Damon McDougall
damon.mcdoug...@gmail.com wrote:
On Thu, Oct 4, 2012 at 10:02 AM, Pierre Haessig
pierre.haes...@crans.org wrote:
Hi Fernando,
Le 04/10/2012 09:16, Fernando Perez a écrit :
This would make for an awesome couple of examples for the gallery, the
mathematica solutions look really pretty cool:
http://mathematica.stackexchange.com/questions/11350/xkcd-style-graphs
I've never used Mathematica so that it's pretty difficult for me to
understand the following lines of code which I guess do the main job of
distorting the image
xkcdDistort[p_] := Module[{r, ix, iy},
r = ImagePad[Rasterize@p, 10, Padding - White];
{ix, iy} =
Table[RandomImage[{-1, 1}, ImageDimensions@r]~ImageConvolve~
GaussianMatrix[10], {2}];
ImagePad[ImageTransformation[r,
# + 15 {ImageValue[ix, #], ImageValue[iy, #]} , DataRange -
Full], -5]];
Is there somebody there that can describe this algorithm with words
(English or Python ;-)) ?
I feel like the key point is about adressing the rasterized plot image
r with some slightly randomized indices ix and iy. However, I
really don't get the step that generates these indices.
Best,
Pierre
I believe this is in your interests: http://i.imgur.com/5XwRO.png
Here's the code: https://gist.github.com/3832579
Disclaimer: The code is ugly; don't judge me. Also, I installed the
Humor Sans font but I couldn't get mpl to find it. Oh well :)
I got the font working :) http://i.imgur.com/Dxemm.png
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United Kingdom
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Re: [Matplotlib-users] How to modify the navigation toolbar easily in a matplotlib figure window?
Note, however, code has been improved for the 1.2.0 release to make it easier to modify the set of buttons that are used. In backend_bases.py, look for the NavigationToolbar2 class. Ah yes! I knew I did that for a good reason. :-) Good thinking Ben! -- Don't let slow site performance ruin your business. Deploy New Relic APM Deploy New Relic app performance management and know exactly what is happening inside your Ruby, Python, PHP, Java, and .NET app Try New Relic at no cost today and get our sweet Data Nerd shirt too! http://p.sf.net/sfu/newrelic-dev2dev___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
Re: [Matplotlib-users] Create a figure window without navigation toolbar
Personally, I am not a fan of adding a window specific keyword to the
figure function (although there may be some there already).
With 1.2 you can use Matthew Emmett/Paul Ivanov's awesome new context
manager to remove the toolbar for the duration of the with statement:
import matplotlib.pyplot as plt
import matplotlib as mpl
with mpl.rc_context({'toolbar':False}):
plt.plot(range(10))
plt.show()
Does that make things easier/nicer for you?
Cheers,
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Re: [Matplotlib-users] Bug when zooming on multiple lines separated by None
This works for me with 1.2 (not tested before that): import matplotlib.pyplot as plt import numpy as np x = np.array([0, 1, None, 1, 0]) y = np.array([0, 1, None, 0, 1]) plt.plot(x, y) plt.show() I get two distinct lines crossing each other at (0.5, 0.5) HTH, -- Don't let slow site performance ruin your business. Deploy New Relic APM Deploy New Relic app performance management and know exactly what is happening inside your Ruby, Python, PHP, Java, and .NET app Try New Relic at no cost today and get our sweet Data Nerd shirt too! http://p.sf.net/sfu/newrelic-dev2dev ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
Re: [Matplotlib-users] Problem with axvline in gridspec with log Y axis
Sometimes, having a point of reference really helps in tracking the issue down, particularly when complimented with the very cool bisect tool that comes with git. In this case though, I knew where the problem came in because I have been working closely in this area recently (and it's my change which has exposed the problem). I have fixed this in the pull request, and fully expect the fix to be in the next 1.2.x release candidate. If your willing and able, you could get hold of my branch until it is merged to carry on testing the release candidate. Hope that helps, All the best, Phil On 14 September 2012 17:53, Scott Lasley slas...@space.umd.edu wrote: On Sep 14, 2012, at 5:02 AM, Phil Elson pelson@gmail.com wrote: Thanks for raising this. I have simplified and opened an issue for the bug (https://github.com/matplotlib/matplotlib/issues/1246) and will be looking at this asap. All the best, Phil I don't know if this helps, but my scripts and the code snippet in my email message work without crashing using matplotlib 1.2.x compiled from github on July 23, 2012 and numpy-1.8.0.dev_63cd8f3-py2.7-macosx-10.6-intel.egg on another mac running OS X 10.8.1. Thank you for looking into this, Scott -- Live Security Virtual Conference Exclusive live event will cover all the ways today's security and threat landscape has changed and how IT managers can respond. Discussions will include endpoint security, mobile security and the latest in malware threats. http://www.accelacomm.com/jaw/sfrnl04242012/114/50122263/___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
Re: [Matplotlib-users] Problem with axvline in gridspec with log Y axis
Thanks for raising this. I have simplified and opened an issue for the bug ( https://github.com/matplotlib/matplotlib/issues/1246) and will be looking at this asap. All the best, Phil -- Got visibility? Most devs has no idea what their production app looks like. Find out how fast your code is with AppDynamics Lite. http://ad.doubleclick.net/clk;262219671;13503038;y? http://info.appdynamics.com/FreeJavaPerformanceDownload.html___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
Re: [Matplotlib-users] numpoints in legend() function for scatter plot is not working in matplotlib 1.1.0?
Ben, on master scatter legends are broken. A pull request (I can't remember which, and github is down, possibly #1176) fixes this (obviously, the PR is marked as release critical for 1.2). I have confirmed, that even once fixed on master, the scatter legend handler does not take notice of the numpoints kwarg. Hope that helps clarify the matter, Regards, Phil On 10 September 2012 14:51, Benjamin Root ben.r...@ou.edu wrote: On Mon, Sep 10, 2012 at 9:33 AM, Chao YUE chaoyue...@gmail.com wrote: Hi Ben, I think I installed this version by following the instructions on matplotlib website. But when I try to use git log, I get: chaoyue@chaoyue-Aspire-4750:/usr/local/lib/python2.7/dist-packages/matplotlib$ pwd /usr/local/lib/python2.7/dist-packages/matplotlib chaoyue@chaoyue-Aspire-4750:/usr/local/lib/python2.7/dist-packages/matplotlib$ git log fatal: Not a git repository (or any of the parent directories): .git I tried to have a look at __init__.py, it has: from __future__ import print_function __version__ = '1.2.x' __version__numpy__ = '1.4' # minimum required numpy version So it's the correct directory I am going. could you give some further instructions? Chao Which directions? We have several for different kinds of installs. We have not released v1.2.0 yet, so I was guessing you checked out mpl from github. If that is the case, then you run git log from the source directory, not the install directory. Ben On Mon, Sep 10, 2012 at 3:05 PM, Benjamin Root ben.r...@ou.edu wrote: On Mon, Sep 10, 2012 at 2:56 AM, Chao YUE chaoyue...@gmail.com wrote: Hi Ben, I tried the numpoints in legend function for scatter plot, in dev version and GTKAgg backend it works. In [3]: mat.__version__ Out[3]: '1.2.x' In [4]: mat.get_backend() Out[4]: 'GTKAgg' Chao Strange, when I tested it last night, I was using a build of mpl from master of a couple weeks ago, and I saw three markers in the legend. Now, I am trying it again with the latest master: 1478a1be70b3077b71350cecaccb774f76a76656, and I now see *zero* markers. Something is seriously broken. Can you tell me what commit (and the date for that commit) shows up at top when you run git log in the mpl source directory? Ben Root -- *** Chao YUE Laboratoire des Sciences du Climat et de l'Environnement (LSCE-IPSL) UMR 1572 CEA-CNRS-UVSQ Batiment 712 - Pe 119 91191 GIF Sur YVETTE Cedex Tel: (33) 01 69 08 29 02; Fax:01.69.08.77.16 -- Live Security Virtual Conference Exclusive live event will cover all the ways today's security and threat landscape has changed and how IT managers can respond. Discussions will include endpoint security, mobile security and the latest in malware threats. http://www.accelacomm.com/jaw/sfrnl04242012/114/50122263/ ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users -- Live Security Virtual Conference Exclusive live event will cover all the ways today's security and threat landscape has changed and how IT managers can respond. Discussions will include endpoint security, mobile security and the latest in malware threats. http://www.accelacomm.com/jaw/sfrnl04242012/114/50122263/___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
Re: [Matplotlib-users] Rectangle Bug
This seems to a be common misconception... I guess in future, we could add a check to the add_patch method to see if the given artist already has an associated Axes, and if it does, emit a warning. On 7 September 2012 07:42, Eric Firing efir...@hawaii.edu wrote: On 2012/09/06 8:35 PM, jonasr wrote: That seems to work, thank you. I would have thought that the add_patch function creates two seperate objects independent of the defined Rectangle. add_patch doesn't create any objects; it just attaches the axes to the patch in both directions: a reference to the patch object is appended to a list of axes artists, and the patch object gets a reference to the axes. Fortunately, python has garbage collection to handle such circular references. Eric greets jonas -- Live Security Virtual Conference Exclusive live event will cover all the ways today's security and threat landscape has changed and how IT managers can respond. Discussions will include endpoint security, mobile security and the latest in malware threats. http://www.accelacomm.com/jaw/sfrnl04242012/114/50122263/ ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users -- Live Security Virtual Conference Exclusive live event will cover all the ways today's security and threat landscape has changed and how IT managers can respond. Discussions will include endpoint security, mobile security and the latest in malware threats. http://www.accelacomm.com/jaw/sfrnl04242012/114/50122263/___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
Re: [Matplotlib-users] axis default formatting with strange scientific-like notation
I'm not aware of an rc param for this. The relevant github issue:
https://github.com/matplotlib/matplotlib/issues/461
Regards,
Phil
On 19 August 2012 21:27, Christopher Graves christoph.gra...@gmail.comwrote:
Using matplotlib 1.1.1.
If one runs the following code:
from pylab import *
plot([19.185,19.187],[0.0009,0.0011],'b.')
show()
The x-axis is labelled 0.0005, 0.0010, 0.0015 etc +1.9184e1
This is unreadable and does not seem like a good default behavior!
One can add
gca().xaxis.set_major_formatter(FormatStrFormatter('$%g$'))
before show()
to obtain an x-axis labelled 19.1845, 19.185, 19.1855, etc.
Can one change the default label formatting behavior with a matplotlib rc?
However, I would not want to e.g. override the 10^-3, 10^-2, etc when using
log axes.
Best regards,
Chris
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Re: [Matplotlib-users] Adding a ready figure to pyplot.
I don't have a good answer to this and have had to implement such a thing in an outstanding pull request (in my case, I have a figure which has been un-pickled and needs re-attaching to pyplot). My proposed mechanism goes something like: figure = matplotlib.figure.Figure(...) import matplotlib.pyplot as plt mgr = plt._backend_mod.new_figure_manager_given_figure(num, self) Obviously this doesn't even exist on master yet, so if you need this functionality from a version before this you will have to reverse engineer the pyplot.figure function. HTH, On 29 July 2012 13:12, Anton Akhmerov anton.akhme...@gmail.com wrote: Hi, I am writing a module which should, among other things, output images, and it should work both in interactive mode and when imported as a script. In order for the plotting behavior to be clean, I would like to prepare the figure separate from pyplot. The reason for this, is that the figure is drawn in a non-interactive loop, and I don't want to show all the steps as they go. Moreover, for some reason with ipython inline backend the figure is rendered twice for no obvious reason. So the preferred behavior of my plotting function (when pyplot output is requested) should be similar to: fig = matplotlib.figure.Figure() ax = fig.add_subplot(111) ax.plot([1,2,3]) matplotlib.pyplot.ADD_FIGURE(fig) The best approximation to this that I was able to find so far is to use the following dirty hack (although none of the attributes I use are _private!): f = plt.figure() fig.canvas = f.canvas f.canvas.figure = fig However this is still problematic: if the interactive mode is on, then rendering of the figure will still be called after these two attribute. Moreover in IPython notebook without inline plotting it will result in an opened GUI window, but GUI mainloop not running. So here's my question: what's the best way to achieve the behavior that I want? Thank you, Anton -- Live Security Virtual Conference Exclusive live event will cover all the ways today's security and threat landscape has changed and how IT managers can respond. Discussions will include endpoint security, mobile security and the latest in malware threats. http://www.accelacomm.com/jaw/sfrnl04242012/114/50122263/ ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users -- Live Security Virtual Conference Exclusive live event will cover all the ways today's security and threat landscape has changed and how IT managers can respond. Discussions will include endpoint security, mobile security and the latest in malware threats. http://www.accelacomm.com/jaw/sfrnl04242012/114/50122263/ ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
Re: [Matplotlib-users] axvspan with dates on x-axis
Luciano got in touch offline and my suggestions worked for a certain
version of Python.
Luciano, were you trying it in python3? If not, what version of Python
was it that wasn't working for you?
Thanks,
On 24 July 2012 18:26, Luciano Fleischfresser l_...@yahoo.com wrote:
Still not working. The output looks like this:
File NotasFaltasdoisgraficos.py, line 58
ax3.axvspan(*mdates.datestr2num(['05/18/2012', '06/30/2012']),
facecolor='g', alpha=0.5)
^
SyntaxError: invalid syntax
When you say ...change the months to short English form you mean in the
data file?
That is, Abr - Apr, Mai - May??? ...still did not work.
From: Phil Elson pelson@gmail.com
To: Luciano Fleischfresser l...@utfpr.edu.br
Cc: Matplotlib-users@lists.sourceforge.net
Matplotlib-users@lists.sourceforge.net
Sent: Monday, July 23, 2012 5:45 PM
Subject: Re: [Matplotlib-users] axvspan with dates on x-axis
Looks like your very close.
I needed to change the months to short English form, change the line
ax3.grid('True') to ax3.grid(True)
and add the line
ax3.axvspan(*mdates.datestr2num(['05/18/2012', '06/30/2012']),
facecolor='g', alpha=0.5)
To get the box on the lower plot.
Hope that helps,
On 23 July 2012 20:42, Luciano Fleischfresser l_...@yahoo.com wrote:
I want to place a colored vertical range on my plot and came across the
following example:
http://stackoverflow.com/questions/8270981/in-a-matplotlib-plot-can-i-highlight-specific-x-value-ranges/8271438#8271438
It shows what I am trying to do using axvspan.
However, I was not able to reproduce the second plot with dates.
Errors like 'invalid syntax' for color='red' and others prevented me from
reproducing the plot.
The demo from Matplotlib gallery worked fine for me. My plot also has
dates
on the x-axis.
I am attaching code and data file. Hope someone can point me in the right
direction.
L Fleischfresser
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Re: [Matplotlib-users] How to Change Axis Tick Mark Labels
Ah, sorry, forgot to reply to all. Please see the solution I provided to Jon. -- Forwarded message -- Date: 22 July 2012 15:08 Subject: Re: [Matplotlib-users] How to Change Axis Tick Mark Labels Sounds like you want to use a FunctionFormatter rather than modifying the ticks themselves. There is an example here (http://stackoverflow.com/questions/8271564/matplotlib-comma-separated-number-format-for-axis). Essentially: import matplotlib.pyplot as plt import matplotlib.ticker as mticker def square_braces(tick_val, tick_pos): Put square braces around the given tick_val return '%s' % tick_val ax = plt.axes() plt(range(10)) ax.yaxis.set_major_formatter(mticker.FuncFormatter(func)) plt.show() HTH, -- Live Security Virtual Conference Exclusive live event will cover all the ways today's security and threat landscape has changed and how IT managers can respond. Discussions will include endpoint security, mobile security and the latest in malware threats. http://www.accelacomm.com/jaw/sfrnl04242012/114/50122263/ ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
Re: [Matplotlib-users] axvspan with dates on x-axis
Looks like your very close.
I needed to change the months to short English form, change the line
ax3.grid('True') to ax3.grid(True)
and add the line
ax3.axvspan(*mdates.datestr2num(['05/18/2012', '06/30/2012']),
facecolor='g', alpha=0.5)
To get the box on the lower plot.
Hope that helps,
On 23 July 2012 20:42, Luciano Fleischfresser l_...@yahoo.com wrote:
I want to place a colored vertical range on my plot and came across the
following example:
http://stackoverflow.com/questions/8270981/in-a-matplotlib-plot-can-i-highlight-specific-x-value-ranges/8271438#8271438
It shows what I am trying to do using axvspan.
However, I was not able to reproduce the second plot with dates.
Errors like 'invalid syntax' for color='red' and others prevented me from
reproducing the plot.
The demo from Matplotlib gallery worked fine for me. My plot also has dates
on the x-axis.
I am attaching code and data file. Hope someone can point me in the right
direction.
L Fleischfresser
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Re: [Matplotlib-users] gallery link broken/not working
I can confirm the bad link. Would you mind opening a new issue on github for this? github.com/matplotlib/matplotlib/issues/new Thanks, On 19 July 2012 10:15, Francesco Montesano franz.berges...@gmail.com wrote: Hi, roaming through the gallery I've found that in http://matplotlib.sourceforge.net/examples/pylab_examples/demo_tight_layout_00.html http://matplotlib.sourceforge.net/examples/pylab_examples/demo_tight_layout_01.html http://matplotlib.sourceforge.net/examples/axes_grid/demo_axes_divider_01.html and maybe others do not work error: 1. Server: matplotlib.sourceforge.net 2. URL path: /examples/pylab_examples/demo_tight_layout_00.html 3. Error notes: NONE 4. Error type: 404 5. Request method: GET 6. Request query string: NONE 7. Time: 2012-07-19 09:12:32 UTC (1342689152) http://matplotlib.sourceforge.net/examples/pylab_examples/demo_tight_layout.html works fine Cheers, Francesco -- Live Security Virtual Conference Exclusive live event will cover all the ways today's security and threat landscape has changed and how IT managers can respond. Discussions will include endpoint security, mobile security and the latest in malware threats. http://www.accelacomm.com/jaw/sfrnl04242012/114/50122263/ ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users -- Live Security Virtual Conference Exclusive live event will cover all the ways today's security and threat landscape has changed and how IT managers can respond. Discussions will include endpoint security, mobile security and the latest in malware threats. http://www.accelacomm.com/jaw/sfrnl04242012/114/50122263/ ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
Re: [Matplotlib-users] path contains_point IndexError: Unexpected SeqBaseT length
I can't reproduce this on version = 1.1.0. What version of matplotlib are you using? On 11 June 2012 17:23, Gustavo Goretkin gustavo.goret...@gmail.com wrote: The problem is that the function in _path.cpp expects a path radius argument, r. Here is the signature: point_in_path(double x, double y, double r, PathIterator path, const agg::trans_affine trans) but the invocation in python looks like this: point_in_path(point[0], point[1], self, transform) On Sat, Jun 9, 2012 at 9:27 PM, Gustavo Goretkin gustavo.goret...@gmail.com wrote: I think I'm experiencing a bug. Here is a minimum example: import matplotlib.patches as mpatches path = mpatches.Rectangle((0,0),width=1,height=1).get_path() print path.contains_point(point=(.5,.5)) it raises an IndexError: Unexpected SeqBaseT length. I think this is a problem in the contains_point method which calls a C function point_in_path inside of matplotlib._path Thanks! Gustavo -- Live Security Virtual Conference Exclusive live event will cover all the ways today's security and threat landscape has changed and how IT managers can respond. Discussions will include endpoint security, mobile security and the latest in malware threats. http://www.accelacomm.com/jaw/sfrnl04242012/114/50122263/ ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users -- Live Security Virtual Conference Exclusive live event will cover all the ways today's security and threat landscape has changed and how IT managers can respond. Discussions will include endpoint security, mobile security and the latest in malware threats. http://www.accelacomm.com/jaw/sfrnl04242012/114/50122263/ ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
