Re: Total newbie asking for guidance

2002-11-03 Thread John Ragan

if you have a windows box that you can use as a 
front end, get a copy of corereader.

i recommend it to you because, among other 
things, it's a teaching tool.  it allows you to 
do (genuine) point and click queries.  you can do 
complex queries simply by clicking on selections. 

furthermore, you'll want to embed sql statements 
in your code.  when you get a query that you like 
in corereader, you can open its sql statement to 
cut and paste.

it will query any data source, and so far seems 
to like mysql particularly well.

corereader is totally free from 
http://corereader.com/ .  

since it's for a non-profit organization, i'll 
correspond directly to help you get started.  
data connections can be frustrating. 

please respond directly to me to avoid cluttering 
this list.  tell me what organization it is to 
insure that i am not opposed to its objectives.


 Hello.
 
 I am starting a project that requires a simple database for use as a 
 back-end to a web-accessible look-up facility.  When I say simple I 
 mean that the data is static and that the queries are done on single 
 keys.
 
 The catch is that I have zero experience in any kind of database work.  I 
 have been doing software development for 20 years and am proficient in 
 several programming languages but have never had the occasion to do any 
 database programming.
 
 I've got some latitude as to what tools are use to achieve this 
 web-accessible database goal, so I'm going with Apache + MySQL in a Linux 
 (Red Hat 7.3) environment.  (Cost is a high priority as this is being 
 done for a poverty-stricken non-profit.)  I'm very familiar with Linux, 
 somewhat familiar with Apache (v1.3.x) and have no experience whatsoever 
 with MySQL.
 
 Would some kind soul(s) please suggest books and/or websites  for the 
 MySQL newbie?  I've perused the book list at www.mysql.com, but don't 
 have a feel for the experience level that these books are oriented 
 toward.
 
 Any pointers that you could provide to this beginner would be very 
 appreciated.
 
 Thank you.
 
 



-- 
John Ragan
[EMAIL PROTECTED]
http://www.CoreReader.com/ 


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JDBC J/Connect driver is seriously slow against InnoDB

2002-11-03 Thread j.random.programmer
Hi:

Thought I'd mention this (using the latest dev
J/connect):

A)
DatabaseMetaData.getColumns() does not return the last

4 columns (SCOPE_*) but it should according to the 
API spec

B)
InnoDB, on their benchmark page, say that inserting
100,000 rows into the DB is about 5 seconds.

http://www.innodb.com/bench.html

I am finding this to be more like 300-400 seconds.
Try this:

CREATE TABLE T1 
(A INT NOT NULL AUTO_INCREMENT, B INT, PRIMARY KEY(A))
TYPE=INNODB;

CREATE TABLE T2 
(A INT NOT NULL, B INT, PRIMARY KEY(A)) TYPE=INNODB;

Now run the java driver (source shown at the end of
this
message).

This takes a long time. The innodb bench URL mentioned
above uses perl DBI has a test driver, the JDBC 
*should* be as fast if I am not missing anything (but
it's not). Once it's finally done, if you now say
(from 
the mysql client):

mysql insert into T2 select * from T1;
Query OK, 107825 rows affected (5.23 sec)
Records: 107825  Duplicates: 0  Warnings: 0

Note, this takes about 5 seconds, which shows that
the slowdown is not at the DB level but at the JDBC
driver level (mysql client even sets auto commit
to true by default, and it still takes 5 seoonds).

So why does the JDBC driver take so long ? I am
accessing the mysql machine over a private 100Mbps
connection so I don't think it's the network either.

Best regards,

--j

 java driver --

import java.sql.*;
import java.util.*;
import java.io.*;

public class insertTiming {
/* Change these as appropriate */
static String user=CHANGE_ME;
static String password=CHANGE_ME;
static String url=CHANGE_ME;

public static void main(String[] args) throws
Exception
{
Class.forName(com.mysql.jdbc.Driver);
Connection con = 
  DriverManager.getConnection(url,user,password);
Statement stmt = con.createStatement(   
ResultSet.TYPE_SCROLL_INSENSITIVE,
ResultSet.CONCUR_READ_ONLY);
/* 
Make sure table T1 has been created prior to this 
SQL command:
CREATE TABLE T1 (A INT NOT NULL AUTO_INCREMENT, B INT,
PRIMARY KEY(A)) TYPE=INNODB;
*/

con.setAutoCommit(false);   
String sql = 
INSERT INTO T1 VALUES (null, '1234567890');

for (int n = 0; n  10; n++) {
 stmt.execute(sql);
 }
con.commit();
} //~main

}  //~class
--


__
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HotJobs - Search new jobs daily now
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mysql DATETIME substraction problem/?

2002-11-03 Thread Jim Hogan
Hello!

I am working on an analysis that is very much dependent on calculating 
time differences in seconds.  The most simple example:

I have 3 variables: time_begin (DATETIME) time_end (DATETIME) and elapsed_ 
seconds (INT).  The data in these DATETIMES looks fine -MM-DD HH:MM:SS 
as expected and actual differences between time_end and time_begin are 
usually on the order of 20-120 seconds.

I run: UPDATE mytable SET elapsed_seconds=time_end-time_begin;

When I browse the resulting data, the elapsed seconds often do, but do  
not always, agree with my own calculation of the elapsed seconds.  For 
example, the first 12 rows look like:

My calc elapsed_time
45  85
11  11
16  16
9   9
22  62
14  14
73  73
59  99
65  105
20  20
12  12
43  4083

That last one is a bit off!!  There appeared to be a common problem with a 
40-second difference, but obvioulsy that last one throws that pattern out 
the window!

Anyhow, I have Googled quite a bit and have looked through 
http://www.mysql.com/doc/en/Date_and_time_functions.html several times and 
did not see a different function of syntax for the UPDATE that I want to 
do.  That man page (in the section on DATE_SUB) says that as of MySQL 3.23 
I can simply use +/- operators

By way of troubleshooting, I created 6 other elapsed_time variables using
small, medium and big int, and float, double and decimal to see if the
result was different, but the result was the same for each.

I'm guessing (and hoping!!) that I am missing something *very* basic in 
the structure of my UPDATE and will absolutely appreciate any pointers 
that could fix it. 


-- 
-*- Jim Hogan   [EMAIL PROTECTED]
Seattle, WA 


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Re: JDBC J/Connect driver is seriously slow against InnoDB

2002-11-03 Thread Mark Matthews
j.random.programmer wrote:

Hi:

Thought I'd mention this (using the latest dev
J/connect):

A)
DatabaseMetaData.getColumns() does not return the last

4 columns (SCOPE_*) but it should according to the 
API spec

I'll look into fixing this right away. You should write Sun as well, as 
their JDBC compliance testsuite doesn't look for this :(


B)
InnoDB, on their benchmark page, say that inserting
100,000 rows into the DB is about 5 seconds.

http://www.innodb.com/bench.html



Can you point out where it says this? When I look at the benchmark page, 
I see that 100,000 inserts take 25 seconds, which JDBC can pretty much 
match (read on for more).

Quoted (from the page in question):

  InnoDBMyISAM

100 000 inserts25 s. 40 s.

100 000 selects on
primary key57 s. 58 s.

100 000 selects on
secondary key  68 s. 95 s.





I am finding this to be more like 300-400 seconds.
Try this:


I think something is broken with your network, or your machine, read on 
for more


CREATE TABLE T1 
(A INT NOT NULL AUTO_INCREMENT, B INT, PRIMARY KEY(A))
TYPE=INNODB;

CREATE TABLE T2 
(A INT NOT NULL, B INT, PRIMARY KEY(A)) TYPE=INNODB;

Now run the java driver (source shown at the end of
this
message).

This takes a long time. The innodb bench URL mentioned
above uses perl DBI has a test driver, the JDBC 
*should* be as fast if I am not missing anything (but
it's not). Once it's finally done, if you now say
(from 
the mysql client):

mysql insert into T2 select * from T1;
Query OK, 107825 rows affected (5.23 sec)
Records: 107825  Duplicates: 0  Warnings: 0

This isn't the same thing as what your test program is testing. This is 
optimized by the database, it is not even close to issuing 100,000 
queries. It  moves some rows from one place to another, and only has to 
issue _one_ query.

Note, this takes about 5 seconds, which shows that
the slowdown is not at the DB level but at the JDBC
driver level (mysql client even sets auto commit
to true by default, and it still takes 5 seoonds).

So why does the JDBC driver take so long ? I am
accessing the mysql machine over a private 100Mbps
connection so I don't think it's the network either.


I would double-check your network. I just ran your code here on my 
desktop runnin Linux, which is known not to have the fastest java 
support, to my test server (100 mbit private network), and it takes 30 
seconds,
which is 5 seconds longer than 100,000 inserts using DBI (which is using 
native code to access the database, btw), but is not long enough for 
HotSpot to actually optimize the code, either.

I would guess you have I/O problems on one of your machines, or you're 
dropping a lot of packets somewhere, or you're not using the best JVM 
for your machine/OS combination.



	-Mark

--
For technical support contracts, visit https://order.mysql.com/?ref=mmma

   __  ___ ___   __
  /  |/  /_ __/ __/ __ \/ /  Mark Matthews [EMAIL PROTECTED]
 / /|_/ / // /\ \/ /_/ / /__ MySQL AB, Full-Time Developer - JDBC/Java
/_/  /_/\_, /___/\___\_\___/ Flossmoor (Chicago), IL USA
   ___/ www.mysql.com


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What if binary log's suffix number exceeds 999?

2002-11-03 Thread Michael Widenius

Hi!

 Chung == Chung Ha-nyung [EMAIL PROTECTED] writes:

Chung  Dear, 

Chung  By default, binary log file uses 3-digit number suffix as its counter.
Chung  Then, without reseting master logs suffix number may reach 999. If so,
Chung  what happens?
Chung  next suffix number is 1000 or 001? Otherwise error occurres?

Next used suffix is 1000 and there should not be any problems when
going from .999 to .1000

Regards,
Monty

-- 
For technical support contracts, goto https://order.mysql.com/
   __  ___ ___   __
  /  |/  /_ __/ __/ __ \/ /Mr. Michael Widenius [EMAIL PROTECTED]
 / /|_/ / // /\ \/ /_/ / /__   MySQL AB, CTO
/_/  /_/\_, /___/\___\_\___/   Helsinki, Finland
   ___/   www.mysql.com

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explain bug?

2002-11-03 Thread Robert Graf \(privat\)
Hi,

I've tried an EXPLAIN of the SELECT below.

Please can anyone tell me why it's
Impossible WHERE noticed after reading const tables
?

I've droped and created the table - but the error/message occurs.
When I leave '(chetPosition = 1)' away, it works!
A bug or ???

The statement works without explain!

Thx a lot,
Robert


MySql 3.23.49

mysql explain
- SELECT * FROM hmChartEntry
-   WHERE (ctId = 1) AND
- (chSubId = 1) AND
- (chetPosition = 1)
- ;
+-+
| Comment |
+-+
| Impossible WHERE noticed after reading const tables |
+-+
1 row in set (0.00 sec)

mysql desc hmChartEntry;
+--+---+--+-+-+---+
| Field| Type  | Null | Key | Default | Extra |
+--+---+--+-+-+---+
| ctId | mediumint(8) unsigned |  | PRI | 0   |   |
| chSubId  | tinyint(3) unsigned   |  | PRI | 1   |   |
| chetPosition | tinyint(3) unsigned   |  | PRI | 0   |   |
| chetArtist   | varchar(50)   | YES  | | NULL|   |
| chetTitle| varchar(80)   | YES  | | NULL|   |
| chetLabel| varchar(30)   | YES  | | NULL|   |
| coIdLabel| char(2)   | YES  | | NULL|   |
| chetDoLabelCheck | char(1)   |  | | Y   |   |
| ctIdLabel| mediumint(8) unsigned | YES  | | NULL|   |
+--+---+--+-+-+---+
9 rows in set (0.00 sec)

mysql

mysql show index from hmChartEntry;
+--++--+--+--+--
-+-+--++
-+
| Table| Non_unique | Key_name | Seq_in_index | Column_name  |
Collation | Cardinality | Sub_part | Packed | Com
ment |
+--++--+--+--+--
-+-+--++
-+
| hmChartEntry |  0 | PRIMARY  |1 | ctId | A
|  67 | NULL | NULL   |
 |
| hmChartEntry |  0 | PRIMARY  |2 | chSubId  | A
|  71 | NULL | NULL   |
 |
| hmChartEntry |  0 | PRIMARY  |3 | chetPosition | A
|1208 | NULL | NULL   |
 |
+--++--+--+--+--
-+-+--++
-+
3 rows in set (0.00 sec)

mysql


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FW: Select from mulitple tables:

2002-11-03 Thread Luka Birsa
Helllo

Im trying to run a select from 5 different tables, depending on the key
in the main one like this: 

select JOB_ASS.JOB_ASS_ID, JOB_ASS.START_DATE, JOB_ASS.STOP_DATE,
JOB_ASS.JOB_NAME, JOB_ASS.LOCATION, JOB_ASS.NOTE, JOB_ASS.ORDER_ID,
JOB_ASS.CONTRACT_VALUE, USER.SURNAME, USER.FIRSTNAME,
PROJECT.PROJECT_NUM, PROJECT.SUBMIT_DATE, COMITENT.NAME, INVESTOR.NAME 
from JOB_ASS 
left join PROJECT using(JOB_ASS.JOB_ASS_ID = PROJECT.JOB_ASS_ID) 
left join USER using(JOB_ASS.USER_ID = USER.USER_ID) 
left join INVESTOR using(JOB_ASS.INVESTOR_ID = INVESTOR.INVESTOR_ID) 
left join COMITENT using(JOB_ASS.COMITENT_ID = COMITENT.COMITENT_ID);

I did try using only join and that didn't work, so some guy pointed me
to this method. But it doesn't work!!!
I'm a sort of a  newbie to SQL and really don't know how to fix this
(nor does my book help me I).

Thanx,
Luka Birsa



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tricky problem with two db-sites

2002-11-03 Thread Andreas
Hi,

I'll soon run in a probaply pretty common problem with 2 site replication.

We currently hold our customer and buisiness data in one mysql server. 
Soon we'll get another site which basically will work on a regional 
separate project. While the set of potential costomers that overlap will 
be limited, there still will be customers that are related to both sites.

The new site will only mind operational acquisition stuff and project
related PR. Invoice management will be on the main site.
While doing that, the 2nd site will report incoming orders to the main
site and of course there will be additions and changes to shared
costomer records - like adresses, contact person, phone numbers - that
have to be synchronized both ways.

There is no online-connection planned. The synchronisation should be
made via queries that extract the changed recorddata that'll be 
transfered perhaps by email or via ssh remote login.

How could I identify, ex- and import such changed data ?
Maybe there are concurrent changes to be catched ? Like site1 changes
field1 and site2 field2 of the same record.

The whole point is to share as much data as possible so both sites
profit on additions or corrections.


Any pointer to documentation in that matter would be appreciated.


regards ... Andreas



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Help with JOIN, please!

2002-11-03 Thread Ken Chiba
Hi,

I'm having some real problems figuring out a seemingly simple join
statement.  I've looked through some of the mailing list posts, but I can't
seem to find what I'm looking for.  Here's what I have - 2 tables:

table1 (id, stimulus_number, stimulus_type)
table 2 (id, stimulus_number, stimulus_type)

Basically, all I want to do is to determine how many matches there are,
where the stimulus_number  stimulus_type are the same in both tables, based
on a certain id.  Here's a verbose example:

table 1: contains 2 entries for id=2
  -- stimulus_number=23, stimulus_type='word'
  -- stimulus_number=34, stimulus_type='image'

table 2: contains 2 entries for id=2
  -- stimulus_number=23, stimulus_type='word'
  -- stimulus_number=34, stimulus_type='word'

The desired result, should display the following:
  -- 23, word
... since that was the only entry that was common to both tables, for id=2
... note, both stimulus_number  stimulus_type have to match in both tables
(not just one or the other).

Here's what I've tried:
  -- select distinct a.stimulus_number, a.stimlus_type
   from table_1 as a
   left join table_2 as b
   on a.stimulus_type=b.stimulus_type
 and a.stimulus_number=b.stimulus_number
   where id=2;

... this looked ok to me, but it spits out any results that have common
stimulus_numbers, OR common stimulus_types.

Any help would be greatly appreciated,

Thanks in advance,

Ken

(sql)


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Help with simple JOIN

2002-11-03 Thread Ken Chiba
Hi,

I'm having some real problems figuring out a seemingly simple join
statement.  I've looked through some of the mailing list posts, but I can't
seem to find what I'm looking for.  Here's what I have - 2 tables:

table1 (id, stimulus_number, stimulus_type)
table 2 (id, stimulus_number, stimulus_type)

Basically, all I want to do is to determine how many matches there are,
where the stimulus_number  stimulus_type are the same in both tables, based
on a certain id.  Here's a verbose example:

table 1: contains 2 entries for id=2
  -- stimulus_number=23, stimulus_type='word'
  -- stimulus_number=34, stimulus_type='image'

table 2: contains 2 entries for id=2
  -- stimulus_number=23, stimulus_type='word'
  -- stimulus_number=34, stimulus_type='word'

The desired result, should display the following:
  -- 23, word
... since that was the only entry that was common to both tables, for id=2
... note, both stimulus_number  stimulus_type have to match in both tables
(not just one or the other).

Here's what I've tried:
  -- select distinct a.stimulus_number, a.stimlus_type
   from table_1 as a
   left join table_2 as b
   on a.stimulus_type=b.stimulus_type
 and a.stimulus_number=b.stimulus_number
   where id=2;

... this looked ok to me, but it spits out any results that have common
stimulus_numbers, OR common stimulus_types.

Any help would be greatly appreciated,

Thanks in advance,

Ken

(sql)


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Re: Help with simple JOIN

2002-11-03 Thread Peter Brawley
Ken,

Don't you want ...
...
INNER JOIN table_2 as b ...
...
PB

-


 I'm having some real problems figuring out a seemingly simple join
 statement.  I've looked through some of the mailing list posts, but I
can't
 seem to find what I'm looking for.  Here's what I have - 2 tables:

 table1 (id, stimulus_number, stimulus_type)
 table 2 (id, stimulus_number, stimulus_type)

 Basically, all I want to do is to determine how many matches there are,
 where the stimulus_number  stimulus_type are the same in both tables,
based
 on a certain id.  Here's a verbose example:

 table 1: contains 2 entries for id=2
   -- stimulus_number=23, stimulus_type='word'
   -- stimulus_number=34, stimulus_type='image'

 table 2: contains 2 entries for id=2
   -- stimulus_number=23, stimulus_type='word'
   -- stimulus_number=34, stimulus_type='word'

 The desired result, should display the following:
   -- 23, word
 ... since that was the only entry that was common to both tables, for id=2
 ... note, both stimulus_number  stimulus_type have to match in both
tables
 (not just one or the other).

 Here's what I've tried:
   -- select distinct a.stimulus_number, a.stimlus_type
from table_1 as a
left join table_2 as b
on a.stimulus_type=b.stimulus_type
  and a.stimulus_number=b.stimulus_number
where id=2;

 ... this looked ok to me, but it spits out any results that have common
 stimulus_numbers, OR common stimulus_types.

 Any help would be greatly appreciated,

 Thanks in advance,

 Ken

 (sql)


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help create new user

2002-11-03 Thread Bob Lockie
Does anyone know why?

create database visitor;
grant all on visitor.* to visitor_user identified by 'visitor';
use visitor;

mysql -u visitor_user -p

I get ERROR 1045: Access denied for user: 'visitor_user@localhost' 
(Using password: YES)


From Mozilla and GNU/Linux


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Re: help create new user

2002-11-03 Thread Jeremy Zawodny
On Mon, Nov 04, 2002 at 12:37:12AM -0500, Bob Lockie wrote:
 Does anyone know why?
 
 create database visitor;
 grant all on visitor.* to visitor_user identified by 'visitor';
 use visitor;
 
 mysql -u visitor_user -p
 
 I get ERROR 1045: Access denied for user: 'visitor_user@localhost' 
 (Using password: YES)

Try:

grant all on visitor.* to visitor_user@'localhost' identified by 'visitor';

Jeremy
-- 
Jeremy D. Zawodny |  Perl, Web, MySQL, Linux Magazine, Yahoo!
[EMAIL PROTECTED]  |  http://jeremy.zawodny.com/

MySQL 3.23.51: up 89 days, processed 1,867,398,195 queries (240/sec. avg)

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Re: help create new user

2002-11-03 Thread Bob Lockie
Jeremy Zawodny wrote:


On Mon, Nov 04, 2002 at 12:37:12AM -0500, Bob Lockie wrote:
 

Does anyone know why?

create database visitor;
grant all on visitor.* to visitor_user identified by 'visitor';
use visitor;

mysql -u visitor_user -p

I get ERROR 1045: Access denied for user: 'visitor_user@localhost' 
(Using password: YES)
   


Try:

grant all on visitor.* to visitor_user@'localhost' identified by 'visitor';

Jeremy
 

That fixed it, thanks.
What did it use since I didn't specify an @'localhost'?

--


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Re: help create new user

2002-11-03 Thread Jeremy Zawodny
On Mon, Nov 04, 2002 at 12:54:17AM -0500, Bob Lockie wrote:
 
 That fixed it, thanks.
 What did it use since I didn't specify an @'localhost'?

It used '%' which matches everyhing *except* localhost.  The manual
explains this.

Jeremy
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