Re: access denied error

2008-10-10 Thread Jesse
Sorry to have bothered you.  I believe I found the problem.  I had a 1 (One) 
in the password instead of a l (L).  it was working from the command prompt, 
because I was typing it in the same way, but from the application, it was 
stored. So, basically, I had the password wrong.

Thanks,
Jesse
  - Original Message - 
  From: Jim Lyons 
  To: Jesse 
  Cc: MySQL List 
  Sent: Friday, October 10, 2008 8:28 AM
  Subject: Re: access denied error


  What is the PHP connect string?  Are you connecting to the database you have 
access to? are you connecting as the same user (myuser)?  Do other php 
applications work, so you know it's not a php-mysql issue?


  On Fri, Oct 10, 2008 at 6:59 AM, Jesse [EMAIL PROTECTED] wrote:

I have a PHP application that I inherited.  I have it running on a Ubuntu 
8.04 virtual machine.  I have set up a user to access the MySQL database, and 
from the command prompt, I can access it just fine.  For instance, from the 
Ubuntu prompt, if I type MySQL -umyuser -p, it asks me for the password and 
after typing it in, I'm in.  I can also see the only database I've given that 
user access to, and I tried a simple SELECT and it worked fine. However, when I 
access the database through the PHP application, I get the error, Access 
denied for user 'trucksma_db'@'localhost' (using password: YES)

Can anyone tell me what the issue could be here?  Why would I have access 
denied through the PHP application, but not through the MySQL client?

Thanks,
Jesse 

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  http://www.weblyons.com


How could i check the following values in MySQL Server 5.0

2008-10-10 Thread Sudhir Menon
Thanks Amit ...




Thanks  Regards
Sudhir


Re: How could i check the following values in MySQL Server 5.0

2008-10-10 Thread mos

At 09:11 AM 10/10/2008, Sudhir Menon wrote:

Thanks Amit ...




Thanks  Regards
Sudhir


Sudhir,
 What following values? I think you're missing part of your post. 
(send text only)


Mike 



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access denied error

2008-10-10 Thread Jesse
I have a PHP application that I inherited.  I have it running on a Ubuntu 
8.04 virtual machine.  I have set up a user to access the MySQL database, 
and from the command prompt, I can access it just fine.  For instance, from 
the Ubuntu prompt, if I type MySQL -umyuser -p, it asks me for the password 
and after typing it in, I'm in.  I can also see the only database I've given 
that user access to, and I tried a simple SELECT and it worked fine. 
However, when I access the database through the PHP application, I get the 
error, Access denied for user 'trucksma_db'@'localhost' (using password: 
YES)


Can anyone tell me what the issue could be here?  Why would I have access 
denied through the PHP application, but not through the MySQL client?


Thanks,
Jesse 



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Re: access denied error

2008-10-10 Thread Jim Lyons
What is the PHP connect string?  Are you connecting to the database you have
access to? are you connecting as the same user (myuser)?  Do other php
applications work, so you know it's not a php-mysql issue?

On Fri, Oct 10, 2008 at 6:59 AM, Jesse [EMAIL PROTECTED] wrote:

 I have a PHP application that I inherited.  I have it running on a Ubuntu
 8.04 virtual machine.  I have set up a user to access the MySQL database,
 and from the command prompt, I can access it just fine.  For instance, from
 the Ubuntu prompt, if I type MySQL -umyuser -p, it asks me for the password
 and after typing it in, I'm in.  I can also see the only database I've given
 that user access to, and I tried a simple SELECT and it worked fine.
 However, when I access the database through the PHP application, I get the
 error, Access denied for user 'trucksma_db'@'localhost' (using password:
 YES)

 Can anyone tell me what the issue could be here?  Why would I have access
 denied through the PHP application, but not through the MySQL client?

 Thanks,
 Jesse

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http://www.weblyons.com


RE: Finding gaps

2008-10-10 Thread Jerry Schwartz
Thanks.

 

Although I've been around SQL for quite a while, I've never really gotten
the hang of self-joins.

 

From: Peter Brawley [mailto:[EMAIL PROTECTED] 
Sent: Wednesday, October 08, 2008 8:22 PM
To: US Data Export; mysql@lists.mysql.com
Subject: Re: Finding gaps

 

Jerry,

Here is a workaround for 4.1.22:

SELECT
  a.id+1 AS 'Missing From',
  MIN(b.id) - 1 AS 'To'
FROM tbl AS a, tbl AS b
WHERE a.id  b.id
GROUP BY a.id
HAVING `Missing From`  MIN(b.id);
+--+--+
| Missing From | To   |
+--+--+
|3 |3 |
|5 |   17 |
+--+--+

PB

US Data Export wrote: 

Well, 5.x accepted the query. It's been running for awhile, now, so I'll
find out later if it did what I need.
 
  

-Original Message-
From: Peter Brawley [mailto:[EMAIL PROTECTED]
Sent: Wednesday, October 08, 2008 5:25 PM
To: Jerry Schwartz; mysql@lists.mysql.com
Subject: Re: Finding gaps
 


I must be missing something obvious; or does this not work in 4.1.22?
  

Looks like a 4.1.22 bug.
 
PB
 
Jerry Schwartz wrote:


I'm finally getting back to this issue, and I've read the bits on
artfulsoftware. The example
 
SELECT
  a.id+1 AS 'Missing From',
  MIN(b.id) - 1 AS 'To'
FROM tbl AS a, tbl AS b
WHERE a.id  b.id
GROUP BY a.id
HAVING a.id  MIN(b.id) - 1;
 
Looks like exactly what I want. However, when I try it (prod is my
  

tbl,


prod_num is my id) I get
 
mysql select a.prod_num + 1 AS `Missing From`,
-   MIN(b.prod_num - 1) AS `To`
- from prod as a, prod as b
- where a.prod_num  b.prod_num
- group by a.prod_num
- having a.prod_num  min(b.prod_num) -1 ;
ERROR 1054 (42S22): Unknown column 'a.prod_num' in 'having clause'
 
I must be missing something obvious; or does this not work in 4.1.22?
 
Regards,
 
Jerry Schwartz
The Infoshop by Global Information Incorporated
195 Farmington Ave.
Farmington, CT 06032
 
860.674.8796 / FAX: 860.674.8341
 
www.the-infoshop.com
www.giiexpress.com
www.etudes-marche.com
 
 
  

-Original Message-
From: Peter Brawley [mailto:[EMAIL PROTECTED]
Sent: Wednesday, September 17, 2008 5:26 PM
To: Stut; mysql@lists.mysql.com
Subject: Re: Finding gaps
 
 


Is there any elegant way of finding the gaps?
 
  

You'll find some ideas under (and near) Find missing numbers in a
sequence at http://www.artfulsoftware.com/infotree/queries.php.
 
PB
 
-
 
Stut wrote:
 


On 17 Sep 2008, at 22:12, Jerry Schwartz wrote:
 
  

I have records that should be sequentially (not auto-increment)
numbered,
but there are gaps. Is there any elegant way of finding the gaps?
 


Why do they need to be sequential? When this requirement comes up
  

it's


usually for illogical reasons.
 
-Stut
 

  

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RE: Trouble with large data in MySql

2008-10-10 Thread Mary Bahrami

 Maybe you can paste back the results from an 'explain' statement...also
would be helpful to see the indexes on this table.   Show create table
smas \G;

-Original Message-
From: Karthik Pattabhiraman [mailto:[EMAIL PROTECTED] 
Sent: Wednesday, October 08, 2008 3:30 AM
To: mysql@lists.mysql.com
Subject: Trouble with large data in MySql

Hi,

   We have 4 tables in which we have approximately 40 Million records
per month. We are having trouble getting results from MySql as it takes
about 4-5 hours to complete for each query. We are using this primarily
for reporting purposes.

 

My table schema is as follows

SMAS Table:

 

Column Name

Type

Key

adnetwork 

adnetworkResponse 

campaignName  

clientRequest 

logkey

loggingTime   

logmodule 

pageName  

propertyName  

requestId 

requestSystemId   

serverResponse

sessionId 

siteName  

sucess

systemId   

varchar(3999)

text 

varchar(3999)

varchar(3999)

varchar(3999)

timestamp

varchar(3999)

varchar(3999)

varchar(3999)

varchar(3999)

varchar(3999)

text 

varchar(256) 

varchar(3999)

int(11)  

varchar(3999)











 MUL













 MUL







 

Currently, SMAS table has 40Million records and our query takes 5 hours
to execute.

 

My my.cnf file is as follows and all tables are InnoDB.

 

[mysqld]

datadir=/mnt/data-store/mysql/data

socket=/var/lib/mysql/mysql.sock

user=mysql

# Default to using old password format for compatibility with mysql 3.x

# clients (those using the mysqlclient10 compatibility package).

old_passwords=1

log-error=/var/log/mysqld.log

pid-file=/var/run/mysqld/mysqld.pid

innodb_data_home_dir=/mnt/data-store/mysql/data

innodb_data_file_path=ibdata1:15G:autoextend

innodb_buffer_pool_size=3G

max_connections=200

tmpdir=/mnt/data-store/tmp

 

[mysqld_safe]

log-error=/var/log/mysqld.log

pid-file=/var/run/mysqld/mysqld.pid

 

My query is as follows on SMAS table

select campaignName, siteName, adnetwork,date_format(loggingTime
,'%d/%m/%Y') logDate, count(distinct requestid) adpages  

from  SMAS where sucess   = 1  GROUP BY 1,2,3,4;

 

Any help will be highly appreciated.

 

-Karthik

 

 


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MySQL TPC benchmark

2008-10-10 Thread Sachin Gaikwad
Hi all

Is there a MySQL TPC benchmark available to download ? If someone is
aware of such a thing, let me know.

Thanks,
Sachin

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Re: MySQL TPC benchmark

2008-10-10 Thread Sachin Gaikwad
On Fri, Oct 10, 2008 at 6:29 PM, Martin Gainty [EMAIL PROTECTED] wrote:
 Hello Sachin

 have you looked at using Benchmark Suite?
 http://dev.mysql.com/doc/refman/5.0/en/mysql-benchmarks.html

Yes, I am looking at it now.
But still I need TPC benchmark which is standard in transactions
world! If I dont get it I have to survive with sql-bench only.

Sachin

 HTH
 Martin Gainty
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 Date: Fri, 10 Oct 2008 18:21:01 -0400
 From: [EMAIL PROTECTED]
 To: mysql@lists.mysql.com
 Subject: MySQL TPC benchmark

 Hi all

 Is there a MySQL TPC benchmark available to download ? If someone is
 aware of such a thing, let me know.

 Thanks,
 Sachin

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