Re: Always corrupted after restart server

2010-08-25 Thread Michael Dykman
How are you shutting down the server during the restart..  have you
checked the logs?  Might you be issuing a kill and crashing it?
MyISAM doesnot dealwith crashes very elegantly.

Also, what is some reason?  Might thereason you need to restart be related?

 - michael dykman


On Tue, Aug 24, 2010 at 11:13 PM, sangprabv sangpr...@gmail.com wrote:
 Hi List,
 I have a very big size MyISAM table. For some reason I need to restart the 
 server periodically. But After restarting the server, the table always get 
 corrupt, and always need to run myisamchk. Don't know what cause the problem. 
 But it will be very helpful if somebody can give me some tips to avoid this 
 problem. Thanks alot.



 sangprabv
 sangpr...@gmail.com
 http://www.petitiononline.com/froyo/



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calculating memory size

2010-08-25 Thread Geoff Galitz

Hello,

We are having issues with one of our servers sometimes hanging up and when 
attempting to shutdown the DB, we get cannot create thread errors.

This server has 6GB of RAM and no swap.  According to some reasearch I was 
doing I found this formula for calculating memory size:
key_buffer_size + (read_buffer_size + sort_buffer_size)*max_connections = (in 
your case) 384M + (64M + 2M)*1000 = 66384M That come directly from this old 
post:  http://bugs.mysql.com/bug.php?id=5656In our case, the result is just 
below 6GB and then accounting for other apps, we would certainly exceed that.  
So, my question is simply: is that forumula accurate for determinning potential 
mysql memory allocation? Thanks!  

Re: How many pager command within mysql command line client?

2010-08-25 Thread Moon's Father
I know, all the shell command can do this. Thanks.

2010/8/25 Moon's Father yueliangdao0...@gmail.com

 Hi.
For example, entering mysql command line client,
mysql pager more ( or pager md5sum and so on.)

I want to know how many command the 'pager' follows?   Any reply will be
 big appreciated.



calculating memory size (again)

2010-08-25 Thread Geoff Galitz
Re-sending... my mail client or server somehow mangled my original 
message... sorry.



--

Hello,

We are having issues with one of our servers sometimes hanging up and when 
attempting to shutdown the DB, we get cannot create thread errors.


This server has 6GB of RAM and no swap.  According to some reasearch I was 
doing I found this formula for calculating memory size:


key_buffer_size + (read_buffer_size + sort_buffer_size)*max_connections = 
(in your case) 384M + (64M + 2M)*1000 = 66384M


That come directly from this old post: 
http://bugs.mysql.com/bug.php?id=5656


In our case, the result is just below 6GB and then accounting for other 
apps, we would certainly exceed that.  So, my question is simply: is that 
forumula accurate for determinning potential mysql memory allocation?


Thanks!




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Re: Complex Select Query

2010-08-25 Thread Ashish Mukherjee
Alternatively, you could just code a recursive function to do the same
instead of doing it in SQL or stored procs.

On Tue, Aug 24, 2010 at 11:01 AM, Victor Subervi victorsube...@gmail.comwrote:

 On Tue, Aug 24, 2010 at 1:43 PM, Peter Brawley
 peter.braw...@earthlink.netwrote:

  What I'm trying to accomplish is to order the results such that after
  stacking the data for all results for a certain category, that the next
  results to be stacked should be those whose parent = the former
 category,
  then move on to the next category, etc. How do I do this?
 
  It's a tree. See
  http://www.artfulsoftware.com/mysqlbook/sampler/mysqled1ch20.html and
  http://www.artfulsoftware.com/infotree/treequeryperformance.pdf.
 
 
 How do I cut down the tree? That stuff is *way* too complex for my needs. I
 just thought I'd make my presentation of data a little cleaner but frankly
 it ain't worth going through all that learning and experimentation to do
 it.
 If there isn't another way I'll just forget about it. Any other suggestions
 would be nice.
 TIA.
 Victor

  -
 
  -Original Message-
  From: Victor Subervi victorsube...@gmail.com
  Sent: Aug 24, 2010 1:14 PM
  To: mysql@lists.mysql.com
  Subject: Complex Select Query
  
  Hi;
  I have the following query:
  
  select * from spreadsheets s join products p on p.Item=s.Item join
  categories c on p.Category=c.ID where s.Client=%s order by p.category,
  c.parent;
  
  mysql describe products;
  +-+--+--+-+-++
  | Field   | Type | Null | Key | Default | Extra  |
  +-+--+--+-+-++
  | ID  | int(4)   | NO   | PRI | NULL| auto_increment |
  | Category| int(3)   | YES  | | NULL||
  | Item| varchar(20)  | YES  | UNI | NULL||
  | Description | varchar(255) | YES  | | NULL||
  | UOM | varchar(20)  | YES  | | NULL||
  | Cost| float(7,2)   | YES  | | NULL||
  +-+--+--+-+-++
  6 rows in set (0.00 sec)
  
  mysql describe categories;
  +--+-+--+-+-++
  | Field| Type| Null | Key | Default | Extra  |
  +--+-+--+-+-++
  | ID   | int(3)  | NO   | PRI | NULL| auto_increment |
  | Category | varchar(20) | YES  | UNI | NULL||
  | Parent   | varchar(20) | YES  | | NULL||
  +--+-+--+-+-++
  
  What I'm trying to accomplish is to order the results such that after
  stacking the data for all results for a certain category, that the next
  results to be stacked should be those whose parent = the former
 category,
  then move on to the next category, etc. How do I do this?
  TIA,
  Victor
 
 



Re: Always corrupted after restart server

2010-08-25 Thread Jangita

On 25/08/2010 8:05 a, Michael Dykman wrote:

How are you shutting down the server during the restart..  have you
checked the logs?  Might you be issuing a kill and crashing it?
MyISAM doesnot dealwith crashes very elegantly.

Also, what is some reason?  Might thereason you need to restart be related?

  - michael dykman
On Tue, Aug 24, 2010 at 11:13 PM, sangprabvsangpr...@gmail.com  wrote:

Hi List,
I have a very big size MyISAM table. For some reason I need to restart the 
server periodically. But After restarting the server, the table always get 
corrupt, and always need to run myisamchk. Don't know what cause the problem. 
But it will be very helpful if somebody can give me some tips to avoid this 
problem. Thanks alot.

To unsubscribe:http://lists.mysql.com/mysql?unsub=mdyk...@gmail.com


Maybe you need to check *why* you have to keep on restarting the server? 
Cure the disease, not the symptoms? We have a particular mysql server 
that has been up the last 8 months with no downtime...


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Re: calculating memory size

2010-08-25 Thread Jangita

On 25/08/2010 8:23 a, Geoff Galitz wrote:


Hello,

We are having issues with one of our servers sometimes hanging up and when attempting to 
shutdown the DB, we get cannot create thread errors.

This server has 6GB of RAM and no swap.  According to some reasearch I was 
doing I found this formula for calculating memory size:
key_buffer_size + (read_buffer_size + sort_buffer_size)*max_connections = (in 
your case) 384M + (64M + 2M)*1000 = 66384M That come directly from this old 
post:  http://bugs.mysql.com/bug.php?id=5656In our case, the result is just 
below 6GB and then accounting for other apps, we would certainly exceed that.  
So, my question is simply: is that forumula accurate for determinning potential 
mysql memory allocation? Thanks!

Are you running a 64bit OS/MySQL?
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Retrieve three columns in sub query

2010-08-25 Thread Tompkins Neil
Hi

Is it possible in MySQL 5.1 to retrieve three columns in a select sub-query
like below :

SELECT student_age, SELECT (student_subjects_id, random_mark, subject FROM
student_subjects ORDER BY RAND(), LIMIT 1)
FROM students
WHERE student_age  10
ORDER BY RAND()
LIMIT 1

I've looked and tried everything, but nothing seems to work...

Cheers
Neil


Re: Retrieve three columns in sub query

2010-08-25 Thread Jo�o C�ndido de Souza Neto
As far as I know sub-queries intends to be an only one column and row 
result.

-- 
João Cândido de Souza Neto

Tompkins Neil neil.tompk...@googlemail.com escreveu na mensagem 
news:aanlkti=djkujcsg=kf29sjsp0yllhmhb02mqzdvzd...@mail.gmail.com...
 Hi

 Is it possible in MySQL 5.1 to retrieve three columns in a select 
 sub-query
 like below :

 SELECT student_age, SELECT (student_subjects_id, random_mark, subject FROM
 student_subjects ORDER BY RAND(), LIMIT 1)
 FROM students
 WHERE student_age  10
 ORDER BY RAND()
 LIMIT 1

 I've looked and tried everything, but nothing seems to work...

 Cheers
 Neil
 



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Re: Retrieve three columns in sub query

2010-08-25 Thread Tompkins Neil
I thought as much, if anyone else can shed some light that would be great.
 If not, I'm going to have to write an additional query.

2010/8/25 João Cândido de Souza Neto j...@consultorweb.cnt.br

 As far as I know sub-queries intends to be an only one column and row
 result.

 --
 João Cândido de Souza Neto

 Tompkins Neil neil.tompk...@googlemail.com escreveu na mensagem
 news:aanlkti=djkujcsg=kf29sjsp0yllhmhb02mqzdvzd...@mail.gmail.com...
  Hi
 
  Is it possible in MySQL 5.1 to retrieve three columns in a select
  sub-query
  like below :
 
  SELECT student_age, SELECT (student_subjects_id, random_mark, subject
 FROM
  student_subjects ORDER BY RAND(), LIMIT 1)
  FROM students
  WHERE student_age  10
  ORDER BY RAND()
  LIMIT 1
 
  I've looked and tried everything, but nothing seems to work...
 
  Cheers
  Neil
 



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RE: Retrieve three columns in sub query

2010-08-25 Thread misiaQ
select ci.*, ct.* from (select name, countrycode from city) ci, country ct
where ci.countrycode = ct.code

Regards,
m

-Original Message-
From: Tompkins Neil [mailto:neil.tompk...@googlemail.com] 
Sent: Wednesday, August 25, 2010 1:23 PM
To: [MySQL]
Subject: Retrieve three columns in sub query

Hi

Is it possible in MySQL 5.1 to retrieve three columns in a select sub-query
like below :

SELECT student_age, SELECT (student_subjects_id, random_mark, subject FROM
student_subjects ORDER BY RAND(), LIMIT 1)
FROM students
WHERE student_age  10
ORDER BY RAND()
LIMIT 1

I've looked and tried everything, but nothing seems to work...

Cheers
Neil


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Sprawdz najlepsze oferty  http://linkint.pl/f27c4


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Re: Retrieve three columns in sub query

2010-08-25 Thread Jo�o C�ndido de Souza Neto
Not tested, but i think it could work for you:

SELECT
student_age,
(SELECT
student_subjects_id
FROM
student_subjects
ORDER BY
RAND()
LIMIT 1) as subject_id,
(SELECT
random_mark
FROM
student_subjects
having
student_subject_id = subject_id) as random_mark,
(SELECT
subject
FROM
student_subjects
having
student_subject_id = subject_id) as subject
FROM
students
WHERE
student_age  10
ORDER
BY RAND()
LIMIT 1

-- 
João Cândido de Souza Neto

Tompkins Neil neil.tompk...@googlemail.com escreveu na mensagem 
news:aanlkti=ecibcm3kcj7kizprnrkat=nnasfndw5srm...@mail.gmail.com...
I thought as much, if anyone else can shed some light that would be great.
 If not, I'm going to have to write an additional query.

2010/8/25 João Cândido de Souza Neto j...@consultorweb.cnt.br

 As far as I know sub-queries intends to be an only one column and row
 result.

 --
 João Cândido de Souza Neto

 Tompkins Neil neil.tompk...@googlemail.com escreveu na mensagem
 news:aanlkti=djkujcsg=kf29sjsp0yllhmhb02mqzdvzd...@mail.gmail.com...
  Hi
 
  Is it possible in MySQL 5.1 to retrieve three columns in a select
  sub-query
  like below :
 
  SELECT student_age, SELECT (student_subjects_id, random_mark, subject
 FROM
  student_subjects ORDER BY RAND(), LIMIT 1)
  FROM students
  WHERE student_age  10
  ORDER BY RAND()
  LIMIT 1
 
  I've looked and tried everything, but nothing seems to work...
 
  Cheers
  Neil
 



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Re: Retrieve three columns in sub query

2010-08-25 Thread Tompkins Neil
Hi M,

This appears to do exactly what I require.  Thank you !

Cheers
Neil

On Wed, Aug 25, 2010 at 1:43 PM, misiaQ mis...@poczta.fm wrote:

 select ci.*, ct.* from (select name, countrycode from city) ci, country ct
 where ci.countrycode = ct.code

 Regards,
 m

 -Original Message-
 From: Tompkins Neil [mailto:neil.tompk...@googlemail.com]
 Sent: Wednesday, August 25, 2010 1:23 PM
 To: [MySQL]
 Subject: Retrieve three columns in sub query

 Hi

 Is it possible in MySQL 5.1 to retrieve three columns in a select sub-query
 like below :

 SELECT student_age, SELECT (student_subjects_id, random_mark, subject FROM
 student_subjects ORDER BY RAND(), LIMIT 1)
 FROM students
 WHERE student_age  10
 ORDER BY RAND()
 LIMIT 1

 I've looked and tried everything, but nothing seems to work...

 Cheers
 Neil


 --
 Kup wlasne mieszkanie za 72 tys. zl.
 Sprawdz najlepsze oferty  http://linkint.pl/f27c4




Table design question

2010-08-25 Thread Tompkins Neil
Hi,

I'm creating a application which hosts football matches and I want to record
the player appearances, goals etc.  I was thinking of having a record for
each player as follows :

appearance_id
season_id
player_id
team_id
competition_id
appearance
goals
yellow_card
red_card
date_played

Is this the sort of standard layout, recommended for such application.
From here, I can then count number of appearances, goals scored etc within a
season or for a team_id ?

Cheers
Neil


To join or not to join?

2010-08-25 Thread Chris W
I need a single row from 2 different tables.  It is rather trivial to 
create a join that will join these two tables and give me all the 
information I want in one query.  It is also fairly easy to just execute 
two different queries with out any join and get the data I need.  Since 
the both single table queries or the join query will always only return 
a single row, I was wondering if there was a performance hit doing it 
one way or the other.  On one table the where clause is on the primary 
key on the other table there where clause is on a single column that is 
indexed but not unique.  However in this situation it will be unique.  I 
can't put a unique key on this field in the second table because there 
are other applications of the second table where I do need it to non 
unique. 


Hope that makes sense.

Chris W

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Re: Calculating table standings

2010-08-25 Thread Tompkins Neil
Travis

Do you think it would be better if I stored the information in
a separate table, rather than using unions etc - to make the searching,
counting etc easier ?  Or is this method a standard way of dealing with this
sort of data.

Cheers
Neil

On Tue, Aug 24, 2010 at 5:43 PM, Travis Ard travis_...@hotmail.com wrote:

 I think your match table has all the information necessary to display the
 results you want.  Since each record contains data for two teams (home and
 away), you'd probably need to select each separately and union the results
 together before summarizing.  Your query might look something like the
 following:

 select
seasons_id
,team_id
,count(*) as games_played
,sum(home) as home_games_played
,sum(away) as away_games_played
,sum(won_home) as won_home
,sum(draw_home) as draw_home
,sum(lost_home) as lost_home
,sum(scored_home) as scored_home
,sum(conceded_home) as conceded_home
,sum(won_away) as won_away
,sum(draw_away) as draw_away
,sum(lost_away) as lost_away
,sum(scored_away) as scored_away
,sum(conceded_away) as conceded_away
 from
 (select
seasons_id
,home_team_id as team_id
,1 as home
,0 as away
,if(home_goals  away_goals, 1, 0) as won_home
,if(home_goals = away_goals, 1, 0) as draw_home
,if(home_goals  away_goals, 1, 0) as lost_home
,home_goals as scored_home
,away_goals as conceded_home
,0 as won_away
,0 as draw_away
,0 as lost_away
,0 as scored_away
,0 as conceded_away
 from matches
 union all
 select
seasons_id
,away_team_id as team_id
,0 as home
,1 as away
,0 as won_home
,0 as draw_home
,0 as lost_home
,0 as scored_home
,0 as conceded_home
,if(away_goals  home_goals, 1, 0) as won_away
,if(away_goals = home_goals, 1, 0) as draw_away
,if(away_goals  home_goals, 1, 0) as lost_away
,away_goals as scored_away
,home_goals as conceded_away
 from matches) s1
 group by seasons_id, team_id;

 -Original Message-
 From: Tompkins Neil [mailto:neil.tompk...@googlemail.com]
 Sent: Tuesday, August 24, 2010 7:45 AM
 To: [MySQL]
 Subject: Calculating table standings

 Hi,

 I wondered if anyone can offer me some help with regards the following
 issue
 I'm having.  Basically, I've the following table structure containing rows
 of results between two football teams.  The fields are

 match_id
 seasons_id
 week_number
 home_team_id
 away_team_id
 home_goals
 away_goals

 Based on the above information, I'm wanting to generate a league table
 listing showing

 games_played
 won_home
 draw_home
 lost_home
 scored_home
 conceded_home
 won_away
 draw_away
 lost_away
 scored_away
 conceded_away

 Finally I also want a tally for the number of points e.g 3 points for win,
 1
 point for a draw.  Do you think this is possible with the basic table I
 have, or should I consider putting the result data in a leagues table
 working out the fields I have listed above, and then just calculating it
 and
 display it ?

 Thanks for any advice.

 Cheers
 Neil




Re: How many pager command within mysql command line client?

2010-08-25 Thread Dan Nelson
In the last episode (Aug 25), Moon's Father said:
 Hi.
For example, entering mysql command line client,
mysql pager more ( or pager md5sum and so on.)
 
I want to know how many command the 'pager' follows?   Any reply will
 be big appreciated.

Any command can be used as a pager.  Some commands are less useful than
others, though :)

PAGER set to 'cat -n'
mysql select hello;
 1  +---+
 2  | hello |
 3  +---+
 4  | hello |
 5  +---+
1 row in set (0.01 sec)

mysql pager date
PAGER set to 'date'
mysql select hello;
Wed Aug 25 15:43:46 CDT 2010
1 row in set (0.00 sec)

mysql 


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Re: calculating memory size (again)

2010-08-25 Thread Baron Schwartz
Hi Geoff,

 This server has 6GB of RAM and no swap.  According to some reasearch I was
 doing I found this formula for calculating memory size:

 key_buffer_size + (read_buffer_size + sort_buffer_size)*max_connections =
 (in your case) 384M + (64M + 2M)*1000 = 66384M

 That come directly from this old post: http://bugs.mysql.com/bug.php?id=5656

 In our case, the result is just below 6GB and then accounting for other
 apps, we would certainly exceed that.  So, my question is simply: is that
 forumula accurate for determinning potential mysql memory allocation?

No, it is not at all.  It never was, and many people have had trouble
with it just as you have.  There really is no way to do what that
formula tries to do.

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Complicated SQL Query

2010-08-25 Thread Jacob Steinberger
I have a requirement to keep track of a set of data, and all changes  
that might occur. In order to do this, for each field of the data set,  
I've created a table that keeps track of the version, the value, the  
time the change was made, and a linking number that links all the  
different tables back to a single record. I'm assuming, hoping, and  
believe this is a very common setup.


What I'm having trouble with is queries that aren't nested  
sub-selects, or joins that won't show NULL data. For example ...


select rsi.value, rsi.record_id, ssn.value as serviceseqnum, esn.value  
as eventseqnum from record_set_id as rsi LEFT JOIN serviceseqnum as  
ssn ON rsi.record_id = ssn.record_id LEFT JOIN eventseqnum as esn ON  
ssn.record_id = esn.record_id


Will join the tables, but doesn't take the version information into  
consideration. If I add a where to include the maximum version, to get  
the most recent value, it won't show anything if one of the values  
happens to be NULL.


Using sub-selects generally causes long query time ...

select rsi.value, rsi.record_id ( select value from serviceseqnum  
where record_id = rsi.record and version = ( select max(version) from  
serviceseqnum where record_id = rsi.record_id ) ) from record_set_id )  
from record_set_id as rsi


... especially when trying to get a dozen values strung together so  
they appear as one record.


Is there a better way to handle these queries that I'm just not thinking of?

Jacob


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Re: Complicated SQL Query

2010-08-25 Thread Jacob Steinberger
I found an answer without having to worry about complicated SQL  
statements - it's more about managing the tables than the SQL.


Jacob

Quoting Jacob Steinberger trefal...@realitybytes.net:


I have a requirement to keep track of a set of data, and all changes
that might occur. In order to do this, for each field of the data set,
I've created a table that keeps track of the version, the value, the
time the change was made, and a linking number that links all the
different tables back to a single record. I'm assuming, hoping, and
believe this is a very common setup.

What I'm having trouble with is queries that aren't nested sub-selects,
or joins that won't show NULL data. For example ...

select rsi.value, rsi.record_id, ssn.value as serviceseqnum, esn.value
as eventseqnum from record_set_id as rsi LEFT JOIN serviceseqnum as ssn
ON rsi.record_id = ssn.record_id LEFT JOIN eventseqnum as esn ON
ssn.record_id = esn.record_id

Will join the tables, but doesn't take the version information into
consideration. If I add a where to include the maximum version, to get
the most recent value, it won't show anything if one of the values
happens to be NULL.

Using sub-selects generally causes long query time ...

select rsi.value, rsi.record_id ( select value from serviceseqnum where
record_id = rsi.record and version = ( select max(version) from
serviceseqnum where record_id = rsi.record_id ) ) from record_set_id )
from record_set_id as rsi

... especially when trying to get a dozen values strung together so
they appear as one record.

Is there a better way to handle these queries that I'm just not thinking of?

Jacob


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