cvs access
Hi folks! I would like to know if it's possible that some have read access to MySQL cvs repository? If yes, how may i have read acces (like an anonymous account). Other question: Which CVS TAGS MySQL uses for production environment? STABLE , CURRENT? (FreeBSD Project uses STABLE for production boxes). Thanks a lot for your time and cooperation. -- For I perceive that behind this seemingly unrelated sequence of events, there lurks a singular, sinister attitude of mind. Whose? MINE! HA-HA! - Before posting, please check: http://www.mysql.com/manual.php (the manual) http://lists.mysql.com/ (the list archive) To request this thread, e-mail [EMAIL PROTECTED] To unsubscribe, e-mail [EMAIL PROTECTED] Trouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php
mysql is hanging my connections
Dear gentleman, I am running mysql over FreeBSD and when i issue a "show logs" query to mysql, my connection is droped (cause the process is killed). Take a closer look: mysql show logs; ERROR 2013: Lost connection to MySQL server during query mysql select user(); ERROR 2006: MySQL server has gone away No connection. Trying to reconnect... Connection id:1 Current database: mysql ++ | user() | ++ | root@localhost | ++ 1 row in set (0.03 sec) mysql I realized (using top) that my mysql daemon died and another instance of the process began execution. These are what i got from etosha.log: /usr/local/libexec/mysqld: pronto para conexoes mysqld got signal 11; The manual section 'Debugging a MySQL server' tells you how to use a stack trace and/or the core file to produce a readable backtrace that may help in finding out why mysqld died 010313 17:56:05 mysqld restarted /usr/local/libexec/mysqld: pronto para conexoes My some tell me if 3.23.33-log is a stable version of mysql? Have anyone else faced such errors ? What is the reason? Thanks a lot for your time and cooperation. - Before posting, please check: http://www.mysql.com/manual.php (the manual) http://lists.mysql.com/ (the list archive) To request this thread, e-mail [EMAIL PROTECTED] To unsubscribe, e-mail [EMAIL PROTECTED] Trouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php
Re: Embedded MySQL: Opinion Please
Benjamin Pflugmann wrote: Or, should I drop Linux and go with Windows CE, or some other RTOS? Well, I am biased there, but I would really avoid Windows. ;-) Other RTOS are probably a good idea, as someone else already said. Or, should I stop being a software developing and become a sheepherder? A RTOS? I would go for QNX, better yet: Neutrino (this is a really weird RTOS) No comment. ;-) Bye, Benjamin. - Before posting, please check: http://www.mysql.com/manual.php (the manual) http://lists.mysql.com/ (the list archive) To request this thread, e-mail [EMAIL PROTECTED] To unsubscribe, e-mail [EMAIL PROTECTED] Trouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php - Before posting, please check: http://www.mysql.com/manual.php (the manual) http://lists.mysql.com/ (the list archive) To request this thread, e-mail [EMAIL PROTECTED] To unsubscribe, e-mail [EMAIL PROTECTED] Trouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php
C program warnning (Just a test i try to understand C in order to build my mysql client program)
Hi folks, I am trying to compile a simple program to play with mysql. But i am running into single problems, but i guess easy to solve by too many of the wizards here. I am too paranoic when compiling my programs, so i activate all warnning (at least i try) flags to gnu c compiler. The problem occurs when type conversion: type conversion is automatic when a functions takes a single pointer to const anything, but when there is a double pointer to a const type and i pass double pointer to a non const type i run into problem? Why in the later case conversion is not automatic? the former is. Here is the simple code (just to test): #include stdio.h int t(const int *i) { printf("%d\n", *i); return 0; } void c(const char **reg) { while (*reg) printf("%s\n", *reg++); } int main(int argc, char *argv[]) { int i; char*reg[] = { "Gustavo", "Vieira", "Goncalves", "Coelho", "Rios", NULL}; i = 10; (void) t(i); c(reg); return 0; } But when compiling: grios@etosha$ cc -ansi -pedantic -Wconversion -Wall -Werror t.c cc1: warnings being treated as errors t.c: In function `main': t.c:30: warning: passing arg 1 of `c' from incompatible pointer type grios@etosha$ Why there is no problem when i pass a int * to as an argument to a function that requires a const int * but when the argument is a double pointer to a const it complains if i pass a double pointer to a non const type. This warnnings always happen even if the argument requirement is of type const [int|float|double|any_thing] ** and the value passed is [int|float|double|any_thing] **. Why automatic conversion does not take place here too ? Thanks a lot for your time and cooperation. - Before posting, please check: http://www.mysql.com/manual.php (the manual) http://lists.mysql.com/ (the list archive) To request this thread, e-mail [EMAIL PROTECTED] To unsubscribe, e-mail [EMAIL PROTECTED] Trouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php