Re: Index merge optimization (with OR) and table joins

2006-05-23 Thread Stuart Brooks
Thanks for the reply, it's much appreciated. I'll have another look at
the tables, although my criteria were such that the query should have
only returned a tiny fraction (<0.1%) of the rows (which is why I was
confused). If I get any closer to a solution I'll try and post with a
bit more info.

And next time I'll try and remember to send the SHOW CREATE TABLE
statements as well:)

Kind regards
 Stuart


On 5/4/06, sheeri kritzer <[EMAIL PROTECTED]> wrote:
> (again, apologies for the lateness...)
>
> MySQL has a cost-based optimizer.  If it's deciding that a full-table
> scan is appropriate, there's a reason.  If more than 30% (approx) of
> the table would be returned in a range query, the optimizer reasons
> that it's LESS expensive to just do a full table scan.  Otherwise, if
> say you're returning 50% of the rows, you have to find the pointer to
> the row using the index, then go to the row.  Doing a table scan
> eliminates needing that extra step of the index.
>
> Next time full SHOW CREATE TABLE statements would be useful.
>
> -Sheeri
>
> On 4/11/06, Stuart Brooks <[EMAIL PROTECTED]> wrote:
> > Hi,
> >
> > I have been having a hassle getting the index_merge to work as
expected
> > when I am joining 2 tables on MySQL 5.0.19. The following example
should
> > make it clear:
> >
> > Table A
> >   key1 (primary key)
> >   key2
> >   some_data
> >
> > Table B
> >   key1 (indexed)
> >   key2 (indexed)
> >   more_data
> >
> > SELECT a.key1,a.key2,b.more_data
> > FROM A as a JOIN B as b ON ((a.key1=b.key1) OR (a.key2=b.key2))
> > WHERE (a.key1=10);
> >
> > This works as expected. An EXPLAIN yields :
> >   a | const| PRIMARY
> >   b | index_merge  | key1,key2
> >
> > However if I make the WHERE clause a range (or remove it
altogether):
> >
> > SELECT a.key1,a.key2,b.more_data
> > FROM A as a JOIN B as b ON ((a.key1=b.key1) OR (a.key2=b.key2))
> > WHERE (a.key1<10) #optional
> >
> > I end up with...
> > a | range | PRIMARY
> > b | ALL   | none
> >
> > which is a brute force attack on table b. Am I missing something
here, I
> > would have expected it to use an index merge on table b in both
cases.
> > Is there a way to force it to use the index merge?
> >
> > Regards
> >  Stuart
> >
> >
> >
> > --
> > MySQL General Mailing List
> > For list archives: http://lists.mysql.com/mysql
> > To unsubscribe:
http://lists.mysql.com/[EMAIL PROTECTED]
> >
> >
>



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Re: Index merge optimization (with OR) and table joins

2006-05-04 Thread sheeri kritzer

On 5/4/06, sheeri kritzer <[EMAIL PROTECTED]> wrote:

(again, apologies for the lateness...)

MySQL has a cost-based optimizer.  If it's deciding that a full-table
scan is appropriate, there's a reason.  If more than 30% (approx) of
the table would be returned in a range query, the optimizer reasons
that it's LESS expensive to just do a full table scan.  Otherwise, if
say you're returning 50% of the rows, you have to find the pointer to
the row using the index, then go to the row.  Doing a table scan
eliminates needing that extra step of the index.

Next time full SHOW CREATE TABLE statements would be useful.

-Sheeri

On 4/11/06, Stuart Brooks <[EMAIL PROTECTED]> wrote:
> Hi,
>
> I have been having a hassle getting the index_merge to work as expected
> when I am joining 2 tables on MySQL 5.0.19. The following example should
> make it clear:
>
> Table A
>   key1 (primary key)
>   key2
>   some_data
>
> Table B
>   key1 (indexed)
>   key2 (indexed)
>   more_data
>
> SELECT a.key1,a.key2,b.more_data
> FROM A as a JOIN B as b ON ((a.key1=b.key1) OR (a.key2=b.key2))
> WHERE (a.key1=10);
>
> This works as expected. An EXPLAIN yields :
>   a | const| PRIMARY
>   b | index_merge  | key1,key2
>
> However if I make the WHERE clause a range (or remove it altogether):
>
> SELECT a.key1,a.key2,b.more_data
> FROM A as a JOIN B as b ON ((a.key1=b.key1) OR (a.key2=b.key2))
> WHERE (a.key1<10) #optional
>
> I end up with...
> a | range | PRIMARY
> b | ALL   | none
>
> which is a brute force attack on table b. Am I missing something here, I
> would have expected it to use an index merge on table b in both cases.
> Is there a way to force it to use the index merge?
>
> Regards
>  Stuart
>
>
>
> --
> MySQL General Mailing List
> For list archives: http://lists.mysql.com/mysql
> To unsubscribe:http://lists.mysql.com/[EMAIL PROTECTED]
>
>



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Re: Index merge optimization (with OR) and table joins

2006-05-04 Thread sheeri kritzer

(again, apologies for the lateness...)

MySQL has a cost-based optimizer.  If it's deciding that a full-table
scan is appropriate, there's a reason.  If more than 30% (approx) of
the table would be returned in a range query, the optimizer reasons
that it's LESS expensive to just do a full table scan.  Otherwise, if
say you're returning 50% of the rows, you have to find the pointer to
the row using the index, then go to the row.  Doing a table scan
eliminates needing that extra step of the index.

Next time full SHOW CREATE TABLE

On 4/11/06, Stuart Brooks <[EMAIL PROTECTED]> wrote:

Hi,

I have been having a hassle getting the index_merge to work as expected
when I am joining 2 tables on MySQL 5.0.19. The following example should
make it clear:

Table A
  key1 (primary key)
  key2
  some_data

Table B
  key1 (indexed)
  key2 (indexed)
  more_data

SELECT a.key1,a.key2,b.more_data
FROM A as a JOIN B as b ON ((a.key1=b.key1) OR (a.key2=b.key2))
WHERE (a.key1=10);

This works as expected. An EXPLAIN yields :
  a | const| PRIMARY
  b | index_merge  | key1,key2

However if I make the WHERE clause a range (or remove it altogether):

SELECT a.key1,a.key2,b.more_data
FROM A as a JOIN B as b ON ((a.key1=b.key1) OR (a.key2=b.key2))
WHERE (a.key1<10) #optional

I end up with...
a | range | PRIMARY
b | ALL   | none

which is a brute force attack on table b. Am I missing something here, I
would have expected it to use an index merge on table b in both cases.
Is there a way to force it to use the index merge?

Regards
 Stuart



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Index merge optimization (with OR) and table joins

2006-04-11 Thread Stuart Brooks
Hi,

I have been having a hassle getting the index_merge to work as expected
when I am joining 2 tables on MySQL 5.0.19. The following example should
make it clear:

Table A
  key1 (primary key)
  key2
  some_data

Table B
  key1 (indexed)
  key2 (indexed)
  more_data

SELECT a.key1,a.key2,b.more_data
FROM A as a JOIN B as b ON ((a.key1=b.key1) OR (a.key2=b.key2))
WHERE (a.key1=10);

This works as expected. An EXPLAIN yields :
  a | const| PRIMARY
  b | index_merge  | key1,key2

However if I make the WHERE clause a range (or remove it altogether):

SELECT a.key1,a.key2,b.more_data
FROM A as a JOIN B as b ON ((a.key1=b.key1) OR (a.key2=b.key2))
WHERE (a.key1<10) #optional

I end up with...
a | range | PRIMARY
b | ALL   | none

which is a brute force attack on table b. Am I missing something here, I
would have expected it to use an index merge on table b in both cases.
Is there a way to force it to use the index merge?

Regards
 Stuart



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