Re: Substraction

2003-01-20 Thread Dobromir Velev
Hi,
I have the same problem the last week - I checked the manual and it seems
this is from the new way the unsigned columns are treated in MySQL 4.

Here is a quote from http://www.mysql.com/doc/en/Column_types.html

Warning: you should be aware that when you use subtraction between integer
values where one is of type UNSIGNED, the result will be unsigned!

A workaround for this problem which is described in the manual is either to
cast the column to a signed integer or to include a double value (0.0 or
something like this) in the operation.

Check http://www.mysql.com/doc/en/Cast_Functions.html for more information

HTH
Dobromir Velev
[EMAIL PROTECTED]


- Original Message -
From: Stefan Hinz, iConnect (Berlin) [EMAIL PROTECTED]
To: Brian Lindner [EMAIL PROTECTED]; Octavian Rasnita
[EMAIL PROTECTED]
Cc: MySQL [EMAIL PROTECTED]
Sent: Monday, January 20, 2003 01:09
Subject: Re: Substraction


 Brian,

   create table test(id int unsigned);
   insert into test values(10);
   select 15 - id from test;
   The result is 18446744073709551611 instead of -5.

 Trying to confirm this with MySQL 4.0.7 on a Win2K box:

 mysql create table test(id int unsigned);
 Query OK, 0 rows affected (0.56 sec)

 mysql insert into test values(10);
 Query OK, 1 row affected (0.08 sec)

 mysql select 15 - id from test;
 +-+
 | 15 - id |
 +-+
 |   5 |
 +-+
 1 row in set (0.06 sec)

 Now, once again with phpMyAdmin 2.3.3pl1:

 SELECT 15 - id
 FROM test LIMIT 0, 30
 15 - id
 5

 But with the following statement (same with phpMyAdmin):

 mysql select 5 - id from test;
 +--+
 | 5 - id   |
 +--+
 | 18446744073709551611 |
 +--+
 1 row in set (0.00 sec)

 Check the 1 in your 15. Maybe there's something wrong.

 Regards,
 --
   Stefan Hinz [EMAIL PROTECTED]
   Geschäftsführer / CEO iConnect GmbH http://iConnect.de
   Heesestr. 6, 12169 Berlin (Germany)
   Tel: +49 30 7970948-0  Fax: +49 30 7970948-3

 - Original Message -
 From: Brian Lindner [EMAIL PROTECTED]
 To: Octavian Rasnita [EMAIL PROTECTED]
 Cc: MySQL [EMAIL PROTECTED]
 Sent: Sunday, January 19, 2003 10:28 PM
 Subject: Re: Substraction


  Octavian,
 
  Sunday, January 19, 2003, 7:31:57 AM, you wrote:
   Hi all,
 
   I've tried the following query:
 
   create table test(id int unsigned);
   insert into test values(10);
   select 15 - id from test;
 
   The result is 18446744073709551611 instead of -5.
 
  I ran this.. and it worked for me
 
  MySql 4.0.7 on Linux... ran it through phpMyAdmin
 
   Am I doing something wrong?
 
   Thank you.
 
   Teddy,
   Teddy's Center: http://teddy.fcc.ro/
   Email: [EMAIL PROTECTED]
 
 
 
 
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Re: Substraction

2003-01-20 Thread Octavian Rasnita
But I don't want to perform a 15 - id, meaning 15 - 10.
I want to calculate 5 - id, meaning 5 - 10.

It should give me -5 or 5 but not | 18446744073709551611 |


Teddy,
Teddy's Center: http://teddy.fcc.ro/
Email: [EMAIL PROTECTED]

- Original Message -
From: Stefan Hinz, iConnect (Berlin) [EMAIL PROTECTED]
To: Brian Lindner [EMAIL PROTECTED]; Octavian Rasnita
[EMAIL PROTECTED]
Cc: MySQL [EMAIL PROTECTED]
Sent: Monday, January 20, 2003 1:09 AM
Subject: Re: Substraction


Brian,

  create table test(id int unsigned);
  insert into test values(10);
  select 15 - id from test;
  The result is 18446744073709551611 instead of -5.

Trying to confirm this with MySQL 4.0.7 on a Win2K box:

mysql create table test(id int unsigned);
Query OK, 0 rows affected (0.56 sec)

mysql insert into test values(10);
Query OK, 1 row affected (0.08 sec)

mysql select 15 - id from test;
+-+
| 15 - id |
+-+
|   5 |
+-+
1 row in set (0.06 sec)

Now, once again with phpMyAdmin 2.3.3pl1:

SELECT 15 - id
FROM test LIMIT 0, 30
15 - id
5

But with the following statement (same with phpMyAdmin):

mysql select 5 - id from test;
+--+
| 5 - id   |
+--+
| 18446744073709551611 |
+--+
1 row in set (0.00 sec)

Check the 1 in your 15. Maybe there's something wrong.

Regards,
--
  Stefan Hinz [EMAIL PROTECTED]
  Geschäftsführer / CEO iConnect GmbH http://iConnect.de
  Heesestr. 6, 12169 Berlin (Germany)
  Tel: +49 30 7970948-0  Fax: +49 30 7970948-3

- Original Message -
From: Brian Lindner [EMAIL PROTECTED]
To: Octavian Rasnita [EMAIL PROTECTED]
Cc: MySQL [EMAIL PROTECTED]
Sent: Sunday, January 19, 2003 10:28 PM
Subject: Re: Substraction


 Octavian,

 Sunday, January 19, 2003, 7:31:57 AM, you wrote:
  Hi all,

  I've tried the following query:

  create table test(id int unsigned);
  insert into test values(10);
  select 15 - id from test;

  The result is 18446744073709551611 instead of -5.

 I ran this.. and it worked for me

 MySql 4.0.7 on Linux... ran it through phpMyAdmin

  Am I doing something wrong?

  Thank you.

  Teddy,
  Teddy's Center: http://teddy.fcc.ro/
  Email: [EMAIL PROTECTED]




 -
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 --
  Brian
  Email: [EMAIL PROTECTED]




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Re: Substraction

2003-01-20 Thread Dobromir Velev
Hi,
There are several ways to solve the problem -
1. Check if you really need an unsigned column  - if not just alter the
column to signed
2. A simple workaround for substracting unsigned values is to add a floating
point number to the operation - then all values will be converted to float
and the negative value will be displayed. For example this should give you
what you need

select 15.0 - id from test;

3. Use CAST function. Example:

select cast(15-id as signed) from test;

HTH
Dobromir Velev
[EMAIL PROTECTED]



- Original Message -
From: Octavian Rasnita [EMAIL PROTECTED]
To: Stefan Hinz, iConnect (Berlin) [EMAIL PROTECTED]; Brian
Lindner [EMAIL PROTECTED]
Cc: MySQL [EMAIL PROTECTED]
Sent: Monday, January 20, 2003 08:22
Subject: Re: Substraction


 But I don't want to perform a 15 - id, meaning 15 - 10.
 I want to calculate 5 - id, meaning 5 - 10.

 It should give me -5 or 5 but not | 18446744073709551611 |


 Teddy,
 Teddy's Center: http://teddy.fcc.ro/
 Email: [EMAIL PROTECTED]

 - Original Message -
 From: Stefan Hinz, iConnect (Berlin) [EMAIL PROTECTED]
 To: Brian Lindner [EMAIL PROTECTED]; Octavian Rasnita
 [EMAIL PROTECTED]
 Cc: MySQL [EMAIL PROTECTED]
 Sent: Monday, January 20, 2003 1:09 AM
 Subject: Re: Substraction


 Brian,

   create table test(id int unsigned);
   insert into test values(10);
   select 15 - id from test;
   The result is 18446744073709551611 instead of -5.

 Trying to confirm this with MySQL 4.0.7 on a Win2K box:

 mysql create table test(id int unsigned);
 Query OK, 0 rows affected (0.56 sec)

 mysql insert into test values(10);
 Query OK, 1 row affected (0.08 sec)

 mysql select 15 - id from test;
 +-+
 | 15 - id |
 +-+
 |   5 |
 +-+
 1 row in set (0.06 sec)

 Now, once again with phpMyAdmin 2.3.3pl1:

 SELECT 15 - id
 FROM test LIMIT 0, 30
 15 - id
 5

 But with the following statement (same with phpMyAdmin):

 mysql select 5 - id from test;
 +--+
 | 5 - id   |
 +--+
 | 18446744073709551611 |
 +--+
 1 row in set (0.00 sec)

 Check the 1 in your 15. Maybe there's something wrong.

 Regards,
 --
   Stefan Hinz [EMAIL PROTECTED]
   Geschäftsführer / CEO iConnect GmbH http://iConnect.de
   Heesestr. 6, 12169 Berlin (Germany)
   Tel: +49 30 7970948-0  Fax: +49 30 7970948-3

 - Original Message -
 From: Brian Lindner [EMAIL PROTECTED]
 To: Octavian Rasnita [EMAIL PROTECTED]
 Cc: MySQL [EMAIL PROTECTED]
 Sent: Sunday, January 19, 2003 10:28 PM
 Subject: Re: Substraction


  Octavian,
 
  Sunday, January 19, 2003, 7:31:57 AM, you wrote:
   Hi all,
 
   I've tried the following query:
 
   create table test(id int unsigned);
   insert into test values(10);
   select 15 - id from test;
 
   The result is 18446744073709551611 instead of -5.
 
  I ran this.. and it worked for me
 
  MySql 4.0.7 on Linux... ran it through phpMyAdmin
 
   Am I doing something wrong?
 
   Thank you.
 
   Teddy,
   Teddy's Center: http://teddy.fcc.ro/
   Email: [EMAIL PROTECTED]
 
 
 
 
  -
   Before posting, please check:
  http://www.mysql.com/manual.php   (the manual)
  http://lists.mysql.com/   (the list archive)
 
   To request this thread, e-mail [EMAIL PROTECTED]
   To unsubscribe, e-mail
 [EMAIL PROTECTED]
   Trouble unsubscribing? Try:
 http://lists.mysql.com/php/unsubscribe.php
 
 
 
 
 
  --
   Brian
   Email: [EMAIL PROTECTED]
 
 
 
 
  -
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re: Re: Substraction

2003-01-20 Thread Egor Egorov
On Monday 20 January 2003 08:22, Octavian Rasnita wrote:
 But I don't want to perform a 15 - id, meaning 15 - 10.
 I want to calculate 5 - id, meaning 5 - 10.

 It should give me -5 or 5 but not | 18446744073709551611 |

The result of the above expression is UNSIGNED, because column 'id' is INT 
UNSIGNED. If you want to get -5, use CAST() function in v4.0:

mysql select CAST(5 - id AS SIGNED) from test;
++
| CAST(5 - id AS SIGNED) |
++
| -5 |
++
1 row in set (0.00 sec)

or in 3.23 you can do:

mysql select 5 - (id+0.0) from test;
+--+
| 5 - (id+0.0) |
+--+
| -5.0 |
+--+
1 row in set (0.00 sec)

For more info look at:
http://www.mysql.com/doc/en/Cast_Functions.html



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Re:Re: Substraction

2003-01-20 Thread Nasser Ossareh
 1. Check if you really need an unsigned column  - if not just alter the column to 
signed

this is the most appropriate answer.  i.e your table design should cater for the 
limited set or modulus arithmatics.  

Casting wouldn't work simply because you may really want the actual unsigned value of 
2^64 - 5 which is 18446744073709551611 in one case and the 5 - 10 = -5 in another.  If 
you cast both, it will return -5 (not a pleasant view for a very rich bank 
customer!!). 

And by the way this is not a MySQL limitation, it is a computer Science issue as 
computers can not implement infinite sets (N, R, Z, Q etc).  

Luckily, this doesn't happen in practice because database designers do allow for such 
issues in their table designs... Octavian's table is, however designed to show this 
issue and not to solve a commerical problem.

Enough is enough! Let's stop this nonsense.

Nasser.

-- Dobromir Velev [EMAIL PROTECTED] writes:

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Subject: Re: Substraction
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Hi,
There are several ways to solve the problem -
1. Check if you really need an unsigned column  - if not just alter the
column to signed
2. A simple workaround for substracting unsigned values is to add a floating
point number to the operation - then all values will be converted to float
and the negative value will be displayed. For example this should give you
what you need

select 15.0 - id from test;

3. Use CAST function. Example:

select cast(15-id as signed) from test;

HTH
Dobromir Velev
[EMAIL PROTECTED]



- Original Message -
From: Octavian Rasnita [EMAIL PROTECTED]
To: Stefan Hinz, iConnect (Berlin) [EMAIL PROTECTED]; Brian
Lindner [EMAIL PROTECTED]
Cc: MySQL [EMAIL PROTECTED]
Sent: Monday, January 20, 2003 08:22
Subject: Re: Substraction


 But I don't want to perform a 15 - id, meaning 15 - 10.
 I want to calculate 5 - id, meaning 5 - 10.

 It should give me -5 or 5 but not | 18446744073709551611 |


 Teddy,
 Teddy's Center: http://teddy.fcc.ro/
 Email: [EMAIL PROTECTED]

 - Original Message -
 From: Stefan Hinz, iConnect (Berlin) [EMAIL PROTECTED]
 To: Brian Lindner [EMAIL PROTECTED]; Octavian Rasnita
 [EMAIL PROTECTED]
 Cc: MySQL [EMAIL PROTECTED]
 Sent: Monday, January 20, 2003 1:09 AM
 Subject: Re: Substraction


 Brian,

   create table test(id int unsigned);
   insert into test values(10);
   select 15 - id from test;
   The result is 18446744073709551611 instead of -5.

 Trying to confirm this with MySQL 4.0.7 on a Win2K box:

 mysql create table test(id int unsigned);
 Query OK, 0 rows affected (0.56 sec)

 mysql insert into test values(10);
 Query OK, 1 row affected (0.08 sec)

 mysql select 15 - id from test;
 +-+
 | 15 - id |
 +-+
 |   5 |
 +-+
 1 row in set (0.06 sec)

 Now, once again with phpMyAdmin 2.3.3pl1:

 SELECT 15 - id
 FROM test LIMIT 0, 30
 15 - id
 5

 But with the following statement (same with phpMyAdmin):

 mysql select 5 - id from test;
 +--+
 | 5 - id   |
 +--+
 | 18446744073709551611 |
 +--+
 1 row in set (0.00 sec)

 Check the 1 in your 15. Maybe there's something wrong.

 Regards,
 --
   Stefan Hinz [EMAIL PROTECTED]
   Gesch䦴sf��r / CEO iConnect GmbH http://iConnect.de
   Heesestr. 6, 12169 Berlin (Germany)
   Tel: +49 30 7970948-0  Fax: +49 30 7970948-3

 - Original Message -
 From: Brian Lindner [EMAIL

Substraction

2003-01-19 Thread Octavian Rasnita
Hi all,

I've tried the following query:

create table test(id int unsigned);
insert into test values(10);
select 15 - id from test;

The result is 18446744073709551611 instead of -5.

Am I doing something wrong?

Thank you.

Teddy,
Teddy's Center: http://teddy.fcc.ro/
Email: [EMAIL PROTECTED]



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Re: Substraction

2003-01-19 Thread Brian Lindner
Octavian,

Sunday, January 19, 2003, 7:31:57 AM, you wrote:
 Hi all,

 I've tried the following query:

 create table test(id int unsigned);
 insert into test values(10);
 select 15 - id from test;

 The result is 18446744073709551611 instead of -5.

I ran this.. and it worked for me

MySql 4.0.7 on Linux... ran it through phpMyAdmin

 Am I doing something wrong?

 Thank you.

 Teddy,
 Teddy's Center: http://teddy.fcc.ro/
 Email: [EMAIL PROTECTED]



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 Brian
 Email: [EMAIL PROTECTED]




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Re:Re: Substraction

2003-01-19 Thread Nasser Ossareh
Isn't there a typo somewhere... 
Shouldn't you expect 5 instead of -5 (15 - id where id = 10)??   

Nevermind, let's assume that there is a typo somewhere and the correct expected value 
is -5... however, in the domain of unsigned arithmetics -5 is precisely 
18446744073709551611... don't you believe me:  look at this:

18446744073709551611 + 5 = 18446744073709551616 which is 2 to power 64 (2^64). Clearly 
in the architecture that you are using an unsigned int is a 64 bits integer... if you 
set all the bits to 1 you will get the largest unsigned int in your system and that is 
18446744073709551615 which is (2^64)-1.  if you increment it by one... all the bits 
switch to 0.  Hence within your architecture 2^64 = 0 and -5 is represented correctly 
by 18446744073709551611 (which is 2^64 - 5).

Nasser
sql, smallint, ...

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Octavian,

Sunday, January 19, 2003, 7:31:57 AM, you wrote:
 Hi all,

 I've tried the following query:

 create table test(id int unsigned);
 insert into test values(10);
 select 15 - id from test;

 The result is 18446744073709551611 instead of -5.

I ran this.. and it worked for me

MySql 4.0.7 on Linux... ran it through phpMyAdmin

 Am I doing something wrong?

 Thank you.

 Teddy,
 Teddy's Center: http://teddy.fcc.ro/
 Email: [EMAIL PROTECTED]



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Re: Substraction

2003-01-19 Thread Stefan Hinz, iConnect \(Berlin\)
Brian,

  create table test(id int unsigned);
  insert into test values(10);
  select 15 - id from test;
  The result is 18446744073709551611 instead of -5.

Trying to confirm this with MySQL 4.0.7 on a Win2K box:

mysql create table test(id int unsigned);
Query OK, 0 rows affected (0.56 sec)

mysql insert into test values(10);
Query OK, 1 row affected (0.08 sec)

mysql select 15 - id from test;
+-+
| 15 - id |
+-+
|   5 |
+-+
1 row in set (0.06 sec)

Now, once again with phpMyAdmin 2.3.3pl1:

SELECT 15 - id
FROM test LIMIT 0, 30
15 - id
5

But with the following statement (same with phpMyAdmin):

mysql select 5 - id from test;
+--+
| 5 - id   |
+--+
| 18446744073709551611 |
+--+
1 row in set (0.00 sec)

Check the 1 in your 15. Maybe there's something wrong.

Regards,
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  Heesestr. 6, 12169 Berlin (Germany)
  Tel: +49 30 7970948-0  Fax: +49 30 7970948-3

- Original Message -
From: Brian Lindner [EMAIL PROTECTED]
To: Octavian Rasnita [EMAIL PROTECTED]
Cc: MySQL [EMAIL PROTECTED]
Sent: Sunday, January 19, 2003 10:28 PM
Subject: Re: Substraction


 Octavian,

 Sunday, January 19, 2003, 7:31:57 AM, you wrote:
  Hi all,

  I've tried the following query:

  create table test(id int unsigned);
  insert into test values(10);
  select 15 - id from test;

  The result is 18446744073709551611 instead of -5.

 I ran this.. and it worked for me

 MySql 4.0.7 on Linux... ran it through phpMyAdmin

  Am I doing something wrong?

  Thank you.

  Teddy,
  Teddy's Center: http://teddy.fcc.ro/
  Email: [EMAIL PROTECTED]




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 --
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Re: Re:Re: Substraction

2003-01-19 Thread Adolfo Bello
On Sun, 2003-01-19 at 19:09, Nasser Ossareh wrote:
 Isn't there a typo somewhere... 
 Shouldn't you expect 5 instead of -5 (15 - id where id = 10)??   
 
 Nevermind, let's assume that there is a typo somewhere and the correct expected 
value is -5... however, in the domain of unsigned arithmetics -5 is precisely 
18446744073709551611... don't you believe me:  look at this:
 
 18446744073709551611 + 5 = 18446744073709551616 which is 2 to power 64 (2^64). 
Clearly in the architecture that you are using an unsigned int is a 64 bits 
integer... if you set all the bits to 1 you will get the largest unsigned int in your 
system and that is 18446744073709551615 which is (2^64)-1.  if you increment it by 
one... all the bits switch to 0.  Hence within your architecture 2^64 = 0 and -5 is 
represented correctly by 18446744073709551611 (which is 2^64 - 5).
 
 Nasser
 sql, smallint, ...
Beautifully explained.

Adolfo


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Re: mysql DATETIME substraction problem/?

2002-11-04 Thread gerald_clark
You can't just subtract datetime fields. Check the date and time functions
in the manual.

Jim Hogan wrote:


Hello!

I am working on an analysis that is very much dependent on calculating 
time differences in seconds.  The most simple example:

I have 3 variables: time_begin (DATETIME) time_end (DATETIME) and elapsed_ 
seconds (INT).  The data in these DATETIMES looks fine -MM-DD HH:MM:SS 
as expected and actual differences between time_end and time_begin are 
usually on the order of 20-120 seconds.

I run: UPDATE mytable SET elapsed_seconds=time_end-time_begin;

When I browse the resulting data, the elapsed seconds often do, but do  
not always, agree with my own calculation of the elapsed seconds.  For 
example, the first 12 rows look like:

My calc		elapsed_time
45		85
11		11
16		16
9		9
22		62
14		14
73		73
59		99
65		105
20		20
12		12
43		4083

That last one is a bit off!!  There appeared to be a common problem with a 
40-second difference, but obvioulsy that last one throws that pattern out 
the window!

Anyhow, I have Googled quite a bit and have looked through 
http://www.mysql.com/doc/en/Date_and_time_functions.html several times and 
did not see a different function of syntax for the UPDATE that I want to 
do.  That man page (in the section on DATE_SUB) says that as of MySQL 3.23 
I can simply use +/- operators

By way of troubleshooting, I created 6 other elapsed_time variables using
small, medium and big int, and float, double and decimal to see if the
result was different, but the result was the same for each.

I'm guessing (and hoping!!) that I am missing something *very* basic in 
the structure of my UPDATE and will absolutely appreciate any pointers 
that could fix it. 


 




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re: mysql DATETIME substraction problem/?

2002-11-04 Thread Egor Egorov
Jim,
Sunday, November 03, 2002, 8:44:43 PM, you wrote:

JH I am working on an analysis that is very much dependent on calculating 
JH time differences in seconds.  The most simple example:

JH I have 3 variables: time_begin (DATETIME) time_end (DATETIME) and elapsed_ 
JH seconds (INT).  The data in these DATETIMES looks fine -MM-DD HH:MM:SS 
JH as expected and actual differences between time_end and time_begin are 
JH usually on the order of 20-120 seconds.

JH I run: UPDATE mytable SET elapsed_seconds=time_end-time_begin;

JH When I browse the resulting data, the elapsed seconds often do, but do  
JH not always, agree with my own calculation of the elapsed seconds.  For 
JH example, the first 12 rows look like:

JH My calc elapsed_time
JH 45  85
JH 11  11
JH 16  16
JH 9   9
JH 22  62
JH 14  14
JH 73  73
JH 59  99
JH 65  105
JH 20  20
JH 12  12
JH 43  4083

JH That last one is a bit off!!  There appeared to be a common problem with a 
JH 40-second difference, but obvioulsy that last one throws that pattern out 
JH the window!

JH Anyhow, I have Googled quite a bit and have looked through 
JH http://www.mysql.com/doc/en/Date_and_time_functions.html several times and 
JH did not see a different function of syntax for the UPDATE that I want to 
JH do.  That man page (in the section on DATE_SUB) says that as of MySQL 3.23 
JH I can simply use +/- operators

JH By way of troubleshooting, I created 6 other elapsed_time variables using
JH small, medium and big int, and float, double and decimal to see if the
JH result was different, but the result was the same for each.

You can't apply arithmetic directly on DATETIME columns. You should
use
   TIME_TO_SEC(time_end)-TIME_TO_SEC(time_begin)



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NO PROBLEM: Re: mysql DATETIME substraction problem/?

2002-11-04 Thread Jim Hogan
On Mon, 4 Nov 2002, gerald_clark wrote:

 You can't just subtract datetime fields. Check the date and time 
functions
 in the manual.

Thanks,

I should know I run the risk of posting a RTFM/FAQ when I'm tired!

I got off track by misinterpreting In MySQL Version 3.23, you can use + 
and - instead of DATE_ADD() and DATE_SUB() in the manual when all I 
needed was UNIX_TIMESTAMP() (that I misinterpreted when I looked at it the 
first time).

Anyhow, I can *nearly* just subtract datetime fields and all is right 
with the world.

Jim 

On Mon, 4 Nov 2002, gerald_clark wrote:

 You can't just subtract datetime fields. Check the date and time functions
 in the manual.
 
 Jim Hogan wrote:
 
 Hello!
 
 I am working on an analysis that is very much dependent on calculating 
 time differences in seconds.  The most simple example:
 
 I have 3 variables: time_begin (DATETIME) time_end (DATETIME) and elapsed_ 
 seconds (INT).  The data in these DATETIMES looks fine -MM-DD HH:MM:SS 
 as expected and actual differences between time_end and time_begin are 
 usually on the order of 20-120 seconds.
 
 I run: UPDATE mytable SET elapsed_seconds=time_end-time_begin;
 
 When I browse the resulting data, the elapsed seconds often do, but do  
 not always, agree with my own calculation of the elapsed seconds.  For 
 example, the first 12 rows look like:
 
 My calc  elapsed_time
 45   85
 11   11
 16   16
 99
 22   62
 14   14
 73   73
 59   99
 65   105
 20   20
 12   12
 43   4083
 
 That last one is a bit off!!  There appeared to be a common problem with a 
 40-second difference, but obvioulsy that last one throws that pattern out 
 the window!
 
 Anyhow, I have Googled quite a bit and have looked through 
 http://www.mysql.com/doc/en/Date_and_time_functions.html several times and 
 did not see a different function of syntax for the UPDATE that I want to 
 do.  That man page (in the section on DATE_SUB) says that as of MySQL 3.23 
 I can simply use +/- operators
 
 By way of troubleshooting, I created 6 other elapsed_time variables using
 small, medium and big int, and float, double and decimal to see if the
 result was different, but the result was the same for each.
 
 I'm guessing (and hoping!!) that I am missing something *very* basic in 
 the structure of my UPDATE and will absolutely appreciate any pointers 
 that could fix it. 
 
 
   
 
 
 
 
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Re: mysql DATETIME substraction problem/?

2002-11-04 Thread Benjamin Pflugmann
Hello.

On Sun 2002-11-03 at 10:44:43 -0800, [EMAIL PROTECTED] wrote:
 Hello!
 
 I am working on an analysis that is very much dependent on calculating 
 time differences in seconds.  The most simple example:
 
 I have 3 variables: time_begin (DATETIME) time_end (DATETIME) and elapsed_ 
 seconds (INT).  The data in these DATETIMES looks fine -MM-DD HH:MM:SS 
 as expected and actual differences between time_end and time_begin are 
 usually on the order of 20-120 seconds.
 
 I run: UPDATE mytable SET elapsed_seconds=time_end-time_begin;

You may not use +- on timestamps (DATETIME or TIMESTAMP) directly. For
calculating differences between dates in seconds UNIX_TIMESTAMP() is
probably the most useful, i.e.

  UPDATE mytable
  SET elapsed_seconds = UNIX_TIMESTAMP(time_end) - UNIX_TIMESTAMP(time_begin);

Your method used the numer representation of the dates
(e.g. 19971231235959) and did an integer substration, which will not
take into account that seconds and minutes wrap at 60 and so on.

[...]
 http://www.mysql.com/doc/en/Date_and_time_functions.html several times and 
 did not see a different function of syntax for the UPDATE that I want to 
 do.  That man page (in the section on DATE_SUB) says that as of MySQL 3.23 
 I can simply use +/- operators

Read that again. It only says that for using INTERVAL, i.e. 

  SELECT 1997-12-31 23:59:59 + INTERVAL 1 SECOND;

is allowed instead of

  SELECT DATE_ADD(1997-12-31 23:59:59, INTERVAL 1 SECOND);

 By way of troubleshooting, I created 6 other elapsed_time variables using
 small, medium and big int, and float, double and decimal to see if the
 result was different, but the result was the same for each.
[...]

That's because your problem does not stem from your storage. Btw, you
can easily see that by using

  SELECT time_end-time_begin FROM mytable LIMIT 20;

Regards,

Benjamin.

-- 
[EMAIL PROTECTED]

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RE: mysql DATETIME substraction problem/?

2002-11-04 Thread Black, Kelly W [PCS]
More appropriately, use curdate()feature from within sql.

select * where date=  curdate()-1;

for example

~Kelly W. Black

-Original Message-
From: Benjamin Pflugmann [mailto:benjamin-mysql;pflugmann.de]
Sent: Monday, November 04, 2002 1:06 PM
To: Jim Hogan
Cc: [EMAIL PROTECTED]
Subject: Re: mysql DATETIME substraction problem/?


Hello.

On Sun 2002-11-03 at 10:44:43 -0800, [EMAIL PROTECTED] wrote:
 Hello!
 
 I am working on an analysis that is very much dependent on calculating 
 time differences in seconds.  The most simple example:
 
 I have 3 variables: time_begin (DATETIME) time_end (DATETIME) and elapsed_

 seconds (INT).  The data in these DATETIMES looks fine -MM-DD HH:MM:SS

 as expected and actual differences between time_end and time_begin are 
 usually on the order of 20-120 seconds.
 
 I run: UPDATE mytable SET elapsed_seconds=time_end-time_begin;

You may not use +- on timestamps (DATETIME or TIMESTAMP) directly. For
calculating differences between dates in seconds UNIX_TIMESTAMP() is
probably the most useful, i.e.

  UPDATE mytable
  SET elapsed_seconds = UNIX_TIMESTAMP(time_end) -
UNIX_TIMESTAMP(time_begin);

Your method used the numer representation of the dates
(e.g. 19971231235959) and did an integer substration, which will not
take into account that seconds and minutes wrap at 60 and so on.

[...]
 http://www.mysql.com/doc/en/Date_and_time_functions.html several times and

 did not see a different function of syntax for the UPDATE that I want to 
 do.  That man page (in the section on DATE_SUB) says that as of MySQL 3.23

 I can simply use +/- operators

Read that again. It only says that for using INTERVAL, i.e. 

  SELECT 1997-12-31 23:59:59 + INTERVAL 1 SECOND;

is allowed instead of

  SELECT DATE_ADD(1997-12-31 23:59:59, INTERVAL 1 SECOND);

 By way of troubleshooting, I created 6 other elapsed_time variables using
 small, medium and big int, and float, double and decimal to see if the
 result was different, but the result was the same for each.
[...]

That's because your problem does not stem from your storage. Btw, you
can easily see that by using

  SELECT time_end-time_begin FROM mytable LIMIT 20;

Regards,

Benjamin.

-- 
[EMAIL PROTECTED]

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Re: mysql DATETIME substraction problem/?

2002-11-04 Thread Benjamin Pflugmann
Hi.

On Mon 2002-11-04 at 15:24:19 -0600, [EMAIL PROTECTED] wrote:
 More appropriately, use curdate()feature from within sql.
 
 select * where date=  curdate()-1;

Two points:

- How does this relate to the origianl question? He wanted to know how
  to calculate a time interval.

- The above has no reasonable behaviour. If the current date is
  2002-10-01, you will get 20021000 as result. It's exactly the
  problem I just explained in the mail before.

Regards,

Benjamin.

[...]
 You may not use +- on timestamps (DATETIME or TIMESTAMP) directly. For
 calculating differences between dates in seconds UNIX_TIMESTAMP() is
 probably the most useful, i.e.
 
   UPDATE mytable
   SET elapsed_seconds = UNIX_TIMESTAMP(time_end) -
 UNIX_TIMESTAMP(time_begin);
 
 Your method used the numer representation of the dates
 (e.g. 19971231235959) and did an integer substration, which will not
 take into account that seconds and minutes wrap at 60 and so on.
[...]

-- 
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mysql DATETIME substraction problem/?

2002-11-03 Thread Jim Hogan
Hello!

I am working on an analysis that is very much dependent on calculating 
time differences in seconds.  The most simple example:

I have 3 variables: time_begin (DATETIME) time_end (DATETIME) and elapsed_ 
seconds (INT).  The data in these DATETIMES looks fine -MM-DD HH:MM:SS 
as expected and actual differences between time_end and time_begin are 
usually on the order of 20-120 seconds.

I run: UPDATE mytable SET elapsed_seconds=time_end-time_begin;

When I browse the resulting data, the elapsed seconds often do, but do  
not always, agree with my own calculation of the elapsed seconds.  For 
example, the first 12 rows look like:

My calc elapsed_time
45  85
11  11
16  16
9   9
22  62
14  14
73  73
59  99
65  105
20  20
12  12
43  4083

That last one is a bit off!!  There appeared to be a common problem with a 
40-second difference, but obvioulsy that last one throws that pattern out 
the window!

Anyhow, I have Googled quite a bit and have looked through 
http://www.mysql.com/doc/en/Date_and_time_functions.html several times and 
did not see a different function of syntax for the UPDATE that I want to 
do.  That man page (in the section on DATE_SUB) says that as of MySQL 3.23 
I can simply use +/- operators

By way of troubleshooting, I created 6 other elapsed_time variables using
small, medium and big int, and float, double and decimal to see if the
result was different, but the result was the same for each.

I'm guessing (and hoping!!) that I am missing something *very* basic in 
the structure of my UPDATE and will absolutely appreciate any pointers 
that could fix it. 


-- 
-*- Jim Hogan   [EMAIL PROTECTED]
Seattle, WA 


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Re: How to do substraction between two tables?

2002-02-17 Thread Arjen Lentz

Hi,

On Mon, 2002-02-18 at 00:40, [EMAIL PROTECTED] wrote:
 I want to do substraction between tables in mysql,
 MINUS not yet implemented in mysql
 
 and this not work :
 select a.* from table_a a where a in (select * from table_b)

Please post the structure of both tables. Then we can post you a
readable example of how it can be done.

The short answer is: use a join.


Regards,
Arjen.

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