Re: [Numpy-discussion] The NumPy Mandelbrot code 16x slower than Fortran

2012-01-27 Thread Stéfan van der Walt
Hey, Ondřej

2012/1/21 Ondřej Čertík ondrej.cer...@gmail.com:
 I read the Mandelbrot code using NumPy at this page:

 http://mentat.za.net/numpy/intro/intro.html

I wrote this as a tutorial for beginners, so the emphasis is on
simplicity.  Do you have any suggestions on how to improve the code
without obfuscating the tutorial?

Stéfan
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Re: [Numpy-discussion] The NumPy Mandelbrot code 16x slower than Fortran

2012-01-25 Thread Ondřej Čertík
On Tue, Jan 24, 2012 at 4:33 PM, Mark Wiebe mwwi...@gmail.com wrote:
 2012/1/21 Ondřej Čertík ondrej.cer...@gmail.com

 snip


 Let me know if you figure out something. I think the mask thing is
 quite slow, but the problem is that it needs to be there, to catch
 overflows (and it is there in Fortran as well, see the
 where statement, which does the same thing). Maybe there is some
 other way to write the same thing in NumPy?


 In the current master, you can replace

     z[mask] *= z[mask]
     z[mask] += c[mask]
 with
     np.multiply(z, z, out=z, where=mask)
     np.add(z, c, out=z, where=mask)

I am getting:

Traceback (most recent call last):
  File b.py, line 19, in module
np.multiply(z, z, out=z, where=mask)
TypeError: 'where' is an invalid keyword to ufunc 'multiply'

I assume it is a new feature in numpy?


 The performance of this alternate syntax is still not great, but it is
 significantly faster than what it replaces. For a particular choice of mask,
 I get

 In [40]: timeit z[mask] *= z[mask]

 10 loops, best of 3: 29.1 ms per loop

 In [41]: timeit np.multiply(z, z, out=z, where=mask)

 100 loops, best of 3: 4.2 ms per loop

That looks like 7x faster to me. If it works for you, can
you run the mandelbrot example with and without your patch?

That way we'll know the actual speedup.

Ondrej
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Re: [Numpy-discussion] The NumPy Mandelbrot code 16x slower than Fortran

2012-01-24 Thread Mark Wiebe
2012/1/21 Ondřej Čertík ondrej.cer...@gmail.com

 snip

 Let me know if you figure out something. I think the mask thing is
 quite slow, but the problem is that it needs to be there, to catch
 overflows (and it is there in Fortran as well, see the
 where statement, which does the same thing). Maybe there is some
 other way to write the same thing in NumPy?


In the current master, you can replace

z[mask] *= z[mask]
z[mask] += c[mask]
with
np.multiply(z, z, out=z, where=mask)
np.add(z, c, out=z, where=mask)

The performance of this alternate syntax is still not great, but it is
significantly faster than what it replaces. For a particular choice of
mask, I get

In [40]: timeit z[mask] *= z[mask]

10 loops, best of 3: 29.1 ms per loop

In [41]: timeit np.multiply(z, z, out=z, where=mask)

100 loops, best of 3: 4.2 ms per loop


-Mark


 Ondrej
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Re: [Numpy-discussion] The NumPy Mandelbrot code 16x slower than Fortran

2012-01-23 Thread Sturla Molden
Den 23.01.2012 10:04, skrev Dag Sverre Seljebotn:
 On 01/23/2012 05:35 AM, Jonathan Rocher wrote:
 Hi all,

 I was reading this while learning about Pytables in more details and the
 origin of its efficiency. This sounds like a problem where out of core
 computation using pytables would shine since the dataset doesn't fit
 into CPU cache: http://www.pytables.org/moin/ComputingKernel. Of course
 C/Cythonizing the problem would be another good way...
 Well, since the data certainly fits in RAM, one would use numexpr
 directly (which is what pytables also uses).



Personally I feel this debate is asking the wrong question.

It is not uncommon for NumPy code to be 16x slower than C or Fortran. 
But that is not really interesting.

This is what I think matters:

- Is the NumPy code FAST ENOUGH?  If not, then go ahead and optimize. If 
it's fast enough, then just leave it.

In this case, it seems Python takes ~13 seconds compared to ~1 second 
for Fortran. Sure, those extra 12 seconds could be annoying. But how 
much coding time should we spend to avoid them? 15 minutes? An hour? Two 
hours?

Taking the time spent optimizing into account, then perhaps Python is 
'faster' anyway? It is common to ask what is fastest for the computer. 
But we should really be asking what is fastest for our selves.

For example: I have a computation that will take a day in Fortran or a 
month in Python (estimated). And I am going to run this code several 
times (20 or so, I think). In this case, yes, coding the bottlenecks in 
Fortran matters to me. But 13 seconds versus 1 second? I find that 
hardly interesting.

Sturla

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Re: [Numpy-discussion] The NumPy Mandelbrot code 16x slower than Fortran

2012-01-23 Thread Sebastian Haase
On Mon, Jan 23, 2012 at 12:23 PM, Sturla Molden stu...@molden.no wrote:
 Den 23.01.2012 10:04, skrev Dag Sverre Seljebotn:
 On 01/23/2012 05:35 AM, Jonathan Rocher wrote:
 Hi all,

 I was reading this while learning about Pytables in more details and the
 origin of its efficiency. This sounds like a problem where out of core
 computation using pytables would shine since the dataset doesn't fit
 into CPU cache: http://www.pytables.org/moin/ComputingKernel. Of course
 C/Cythonizing the problem would be another good way...
 Well, since the data certainly fits in RAM, one would use numexpr
 directly (which is what pytables also uses).



 Personally I feel this debate is asking the wrong question.

 It is not uncommon for NumPy code to be 16x slower than C or Fortran.
 But that is not really interesting.

 This is what I think matters:

 - Is the NumPy code FAST ENOUGH?  If not, then go ahead and optimize. If
 it's fast enough, then just leave it.

 In this case, it seems Python takes ~13 seconds compared to ~1 second
 for Fortran. Sure, those extra 12 seconds could be annoying. But how
 much coding time should we spend to avoid them? 15 minutes? An hour? Two
 hours?

 Taking the time spent optimizing into account, then perhaps Python is
 'faster' anyway? It is common to ask what is fastest for the computer.
 But we should really be asking what is fastest for our selves.

 For example: I have a computation that will take a day in Fortran or a
 month in Python (estimated). And I am going to run this code several
 times (20 or so, I think). In this case, yes, coding the bottlenecks in
 Fortran matters to me. But 13 seconds versus 1 second? I find that
 hardly interesting.

 Sturla


I would think that interactive zooming would be quite nice
(illuminating)   and for that 13 secs would not be tolerable
Well... it's not at the top of my priority list ... ;-)

-Sebastian Haase
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Re: [Numpy-discussion] The NumPy Mandelbrot code 16x slower than Fortran

2012-01-23 Thread Dag Sverre Seljebotn
On 01/23/2012 12:23 PM, Sturla Molden wrote:
 Den 23.01.2012 10:04, skrev Dag Sverre Seljebotn:
 On 01/23/2012 05:35 AM, Jonathan Rocher wrote:
 Hi all,

 I was reading this while learning about Pytables in more details and the
 origin of its efficiency. This sounds like a problem where out of core
 computation using pytables would shine since the dataset doesn't fit
 into CPU cache: http://www.pytables.org/moin/ComputingKernel. Of course
 C/Cythonizing the problem would be another good way...
 Well, since the data certainly fits in RAM, one would use numexpr
 directly (which is what pytables also uses).



 Personally I feel this debate is asking the wrong question.

 It is not uncommon for NumPy code to be 16x slower than C or Fortran.
 But that is not really interesting.

 This is what I think matters:

 - Is the NumPy code FAST ENOUGH?  If not, then go ahead and optimize. If
 it's fast enough, then just leave it.

 In this case, it seems Python takes ~13 seconds compared to ~1 second
 for Fortran. Sure, those extra 12 seconds could be annoying. But how
 much coding time should we spend to avoid them? 15 minutes? An hour? Two
 hours?

 Taking the time spent optimizing into account, then perhaps Python is
 'faster' anyway? It is common to ask what is fastest for the computer.
 But we should really be asking what is fastest for our selves.

 For example: I have a computation that will take a day in Fortran or a
 month in Python (estimated). And I am going to run this code several
 times (20 or so, I think). In this case, yes, coding the bottlenecks in
 Fortran matters to me. But 13 seconds versus 1 second? I find that
 hardly interesting.

You, me, Ondrej, and many more are happy to learn 4 languages and use 
them where they are most appropriate.

But most scientists only want to learn and use one tool. And most 
scientists have both problems where performance doesn't matter, and 
problems where it does. So as long as examples like this exists, many 
people will prefer Fortran for *all* their tasks.

(Of course, that's why I got involved in Cython...)

Dag Sverre
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Re: [Numpy-discussion] The NumPy Mandelbrot code 16x slower than Fortran

2012-01-23 Thread Sturla Molden
Den 23.01.2012 13:09, skrev Sebastian Haase:

 I would think that interactive zooming would be quite nice
 (illuminating)   and for that 13 secs would not be tolerable
 Well... it's not at the top of my priority list ... ;-)


Sure, that comes under the 'fast enough' issue. But even Fortran might 
be too slow here?

For zooming Mandelbrot I'd use PyOpenGL and a GLSL fragment shader 
(which would be a text string in Python):

madelbrot_fragment_shader = 

uniform sampler1D tex;
uniform vec2 center;
uniform float scale;
uniform int iter;
void main() {
 vec2 z, c;
 c.x = 1. * (gl_TexCoord[0].x - 0.5) * scale - center.x;
 c.y = (gl_TexCoord[0].y - 0.5) * scale - center.y;
 int i;
 z = c;
 for(i=0; iiter; i++) {
 float x = (z.x * z.x - z.y * z.y) + c.x;
 float y = (z.y * z.x + z.x * z.y) + c.y;
 if((x * x + y * y)  4.0) break;
 z.x = x;
 z.y = y;
 }
 gl_FragColor = texture1D(tex, (i == iter ? 0.0 : float(i)) / 100.0);
}



The rest is just boiler-plate OpenGL...

Sources:

http://nuclear.mutantstargoat.com/articles/sdr_fract/

http://pyopengl.sourceforge.net/context/tutorials/shader_1.xhtml


Sturla
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Re: [Numpy-discussion] The NumPy Mandelbrot code 16x slower than Fortran

2012-01-23 Thread Robert Cimrman
On 01/23/12 13:51, Sturla Molden wrote:
 Den 23.01.2012 13:09, skrev Sebastian Haase:

 I would think that interactive zooming would be quite nice
 (illuminating)   and for that 13 secs would not be tolerable
 Well... it's not at the top of my priority list ... ;-)


 Sure, that comes under the 'fast enough' issue. But even Fortran might
 be too slow here?

 For zooming Mandelbrot I'd use PyOpenGL and a GLSL fragment shader
 (which would be a text string in Python):

 madelbrot_fragment_shader = 

 uniform sampler1D tex;
 uniform vec2 center;
 uniform float scale;
 uniform int iter;
 void main() {
   vec2 z, c;
   c.x = 1. * (gl_TexCoord[0].x - 0.5) * scale - center.x;
   c.y = (gl_TexCoord[0].y - 0.5) * scale - center.y;
   int i;
   z = c;
   for(i=0; iiter; i++) {
   float x = (z.x * z.x - z.y * z.y) + c.x;
   float y = (z.y * z.x + z.x * z.y) + c.y;
   if((x * x + y * y)   4.0) break;
   z.x = x;
   z.y = y;
   }
   gl_FragColor = texture1D(tex, (i == iter ? 0.0 : float(i)) / 100.0);
 }

 

 The rest is just boiler-plate OpenGL...

 Sources:

 http://nuclear.mutantstargoat.com/articles/sdr_fract/

 http://pyopengl.sourceforge.net/context/tutorials/shader_1.xhtml

Off-topic comment: Or use some algorithmic cleverness, see [1]. I recall Xaos 
had interactive, extremely fast a fluid fractal zooming more than 10 (or 15?) 
years ago (- on a laughable hardware by today's standards).

r.

[1] http://wmi.math.u-szeged.hu/xaos/doku.php
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Re: [Numpy-discussion] The NumPy Mandelbrot code 16x slower than Fortran

2012-01-23 Thread Samuel John
I'd like to add 
http://git.tiker.net/pyopencl.git/blob/HEAD:/examples/demo_mandelbrot.py to the 
discussion, since I use pyopencl  (http://mathema.tician.de/software/pyopencl) 
with great success in my daily scientific computing. Install with pip.

PyOpenCL does understand numpy arrays. You write a kernel (small c-program) 
directly into a python triple quoted strings and get a pythonic way to program 
GPU and core i5 and i7 CPUs with python Exception if something goes wrong. 
Whenever I hit a speed bottleneck that I cannot solve with pure numpy, I code a 
little part of the computation for GPU. The compilation is done just in time 
when you run the python code.

Especially for the mandelbrot this may be a _huge_ gain in speed since its 
embarrassingly parallel.

Samuel


On 23.01.2012, at 14:02, Robert Cimrman wrote:

 On 01/23/12 13:51, Sturla Molden wrote:
 Den 23.01.2012 13:09, skrev Sebastian Haase:
 
 I would think that interactive zooming would be quite nice
 (illuminating)   and for that 13 secs would not be tolerable
 Well... it's not at the top of my priority list ... ;-)
 
 
 Sure, that comes under the 'fast enough' issue. But even Fortran might
 be too slow here?
 
 For zooming Mandelbrot I'd use PyOpenGL and a GLSL fragment shader
 (which would be a text string in Python):
 
 madelbrot_fragment_shader = 
 
 uniform sampler1D tex;
 uniform vec2 center;
 uniform float scale;
 uniform int iter;
 void main() {
  vec2 z, c;
  c.x = 1. * (gl_TexCoord[0].x - 0.5) * scale - center.x;
  c.y = (gl_TexCoord[0].y - 0.5) * scale - center.y;
  int i;
  z = c;
  for(i=0; iiter; i++) {
  float x = (z.x * z.x - z.y * z.y) + c.x;
  float y = (z.y * z.x + z.x * z.y) + c.y;
  if((x * x + y * y)   4.0) break;
  z.x = x;
  z.y = y;
  }
  gl_FragColor = texture1D(tex, (i == iter ? 0.0 : float(i)) / 100.0);
 }
 
 
 
 The rest is just boiler-plate OpenGL...
 
 Sources:
 
 http://nuclear.mutantstargoat.com/articles/sdr_fract/
 
 http://pyopengl.sourceforge.net/context/tutorials/shader_1.xhtml
 
 Off-topic comment: Or use some algorithmic cleverness, see [1]. I recall Xaos 
 had interactive, extremely fast a fluid fractal zooming more than 10 (or 15?) 
 years ago (- on a laughable hardware by today's standards).
 
 r.
 
 [1] http://wmi.math.u-szeged.hu/xaos/doku.php
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Re: [Numpy-discussion] The NumPy Mandelbrot code 16x slower than Fortran

2012-01-22 Thread Sebastian Haase
How does the algorithm and timing compare to this one:

http://code.google.com/p/priithon/source/browse/Priithon/mandel.py?spec=svna6117f5e81ec00abcfb037f0f9da2937bb2ea47fr=a6117f5e81ec00abcfb037f0f9da2937bb2ea47f

The author of original version is  Dan Goodman
# FAST FRACTALS WITH PYTHON AND NUMPY


-Sebastian Haase

2012/1/22 Ondřej Čertík ondrej.cer...@gmail.com

 Hi,

 I read the Mandelbrot code using NumPy at this page:

 http://mentat.za.net/numpy/intro/intro.html

 but when I run it, it gives me integer overflows. As such, I have
 fixed the code, so that it doesn't overflow here:

 https://gist.github.com/1655320

 and I have also written an equivalent Fortran program.

 You can compare both source codes to see
 that that it is pretty much one-to-one translation.
 The main idea in the above gist is to take an
 algorithm written in NumPy, and translate
 it directly to Fortran, without any special
 optimizations. So the above is my first try
 in Fortran. You can plot the result
 using this simple script (you
 can also just click on this gist to
 see the image there):

 https://gist.github.com/1655377

 Here are my timings:

               Python  Fortran Speedup
 Calculation     12.749  00.784  16.3x
 Saving  01.904  01.456  1.3x
 Total          14.653   02.240  6.5x

 I save the matrices to disk in an ascii format,
 so it's quite slow in both cases. The pure computation
 is however 16x faster in Fortran (in gfortran,
 I didn't even try Intel Fortran, that will probably be
 even faster).

 As such, I wonder how the NumPy version could be sped up?
 I have compiled NumPy with Lapack+Blas from source.

 Would anyone be willing to run the NumPy version? Just copy+paste
 should do it.

 If you want to run the Fortran version, the above gist uses
 some of my other modules that I use in my other programs, my goal
 was to see how much more complicated the Fortran code gets,
 compared to NumPy. As such, I put here

 https://gist.github.com/1655350

 a single file
 with all the dependencies, just compile it like this:

 gfortran -fPIC -O3 -march=native -ffast-math -funroll-loops mandelbrot.f90

 and run:

 $ ./a.out
 Iteration 1
 Iteration 2
 ...
 Iteration 100
  Saving...
  Times:
  Calculation:  0.748045999
  Saving:   1.36408502
  Total:   2.11213102


 Let me know if you figure out something. I think the mask thing is
 quite slow, but the problem is that it needs to be there, to catch
 overflows (and it is there in Fortran as well, see the
 where statement, which does the same thing). Maybe there is some
 other way to write the same thing in NumPy?

 Ondrej
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Re: [Numpy-discussion] The NumPy Mandelbrot code 16x slower than Fortran

2012-01-22 Thread Dag Sverre Seljebotn
On 01/22/2012 04:55 AM, Ondřej Čertík wrote:
 Hi,

 I read the Mandelbrot code using NumPy at this page:

 http://mentat.za.net/numpy/intro/intro.html

 but when I run it, it gives me integer overflows. As such, I have
 fixed the code, so that it doesn't overflow here:

 https://gist.github.com/1655320

 and I have also written an equivalent Fortran program.

 You can compare both source codes to see
 that that it is pretty much one-to-one translation.
 The main idea in the above gist is to take an
 algorithm written in NumPy, and translate
 it directly to Fortran, without any special
 optimizations. So the above is my first try
 in Fortran. You can plot the result
 using this simple script (you
 can also just click on this gist to
 see the image there):

 https://gist.github.com/1655377

 Here are my timings:

 Python  Fortran Speedup
 Calculation 12.749  00.784  16.3x
 Saving  01.904  01.456  1.3x
 Total  14.653   02.240  6.5x

 I save the matrices to disk in an ascii format,
 so it's quite slow in both cases. The pure computation
 is however 16x faster in Fortran (in gfortran,
 I didn't even try Intel Fortran, that will probably be
 even faster).

 As such, I wonder how the NumPy version could be sped up?
 I have compiled NumPy with Lapack+Blas from source.

This is a pretty well known weakness with NumPy. In the Python code at 
least, each of c and z are about 15 MB, and the mask about 1 MB. So that 
doesn't fit in CPU cache, and so each and every statement you do in the 
loop transfer that data in and out of CPU cache the memory bus.

There's no quick fix -- you can try to reduce the working set so that it 
fits in CPU cache, but then the Python overhead often comes into play. 
Solutions include numexpr and Theano -- and as often as not, Cython and 
Fortran.

It's a good example, thanks!,

Dag Sverre
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Re: [Numpy-discussion] The NumPy Mandelbrot code 16x slower than Fortran

2012-01-22 Thread Ondřej Čertík
On Sun, Jan 22, 2012 at 3:13 AM, Sebastian Haase seb.ha...@gmail.com wrote:
 How does the algorithm and timing compare to this one:

 http://code.google.com/p/priithon/source/browse/Priithon/mandel.py?spec=svna6117f5e81ec00abcfb037f0f9da2937bb2ea47fr=a6117f5e81ec00abcfb037f0f9da2937bb2ea47f

 The author of original version is  Dan Goodman
 # FAST FRACTALS WITH PYTHON AND NUMPY

Thanks Sebastian. This one is much faster  2.7s on my laptop with
the same dimensions/iterations.

It uses a better datastructures -- it only keeps track of points that
still need to be iterated --- very clever.
If I have time, I'll try to provide an equivalent Fortran version too,
for comparison.

Ondrej
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Re: [Numpy-discussion] The NumPy Mandelbrot code 16x slower than Fortran

2012-01-22 Thread Chris Barker
2012/1/22 Ondřej Čertík ondrej.cer...@gmail.com:
 If I have time, I'll try to provide an equivalent Fortran version too,
 for comparison.

 Ondrej

here is a Cython example:

http://wiki.cython.org/examples/mandelbrot

I haven't looked to see if it's the same algorithm, but it may be
instructive, none the less.

-Chris

-- 
--

Christopher Barker, Ph.D.
Oceanographer

Emergency Response Division
NOAA/NOS/ORR            (206) 526-6959   voice
7600 Sand Point Way NE   (206) 526-6329   fax
Seattle, WA  98115       (206) 526-6317   main reception

chris.bar...@noaa.gov
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Re: [Numpy-discussion] The NumPy Mandelbrot code 16x slower than Fortran

2012-01-22 Thread Jonathan Rocher
Hi all,

I was reading this while learning about Pytables in more details and the
origin of its efficiency. This sounds like a problem where out of core
computation using pytables would shine since the dataset doesn't fit into
CPU cache: http://www.pytables.org/moin/ComputingKernel. Of course
C/Cythonizing the problem would be another good way...

HTH,
Jonathan

2012/1/22 Ondřej Čertík ondrej.cer...@gmail.com

 On Sun, Jan 22, 2012 at 3:13 AM, Sebastian Haase seb.ha...@gmail.com
 wrote:
  How does the algorithm and timing compare to this one:
 
 
 http://code.google.com/p/priithon/source/browse/Priithon/mandel.py?spec=svna6117f5e81ec00abcfb037f0f9da2937bb2ea47fr=a6117f5e81ec00abcfb037f0f9da2937bb2ea47f
 
  The author of original version is  Dan Goodman
  # FAST FRACTALS WITH PYTHON AND NUMPY

 Thanks Sebastian. This one is much faster  2.7s on my laptop with
 the same dimensions/iterations.

 It uses a better datastructures -- it only keeps track of points that
 still need to be iterated --- very clever.
 If I have time, I'll try to provide an equivalent Fortran version too,
 for comparison.

 Ondrej
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-- 
Jonathan Rocher, PhD
Scientific software developer
Enthought, Inc.
jroc...@enthought.com
1-512-536-1057
http://www.enthought.com
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[Numpy-discussion] The NumPy Mandelbrot code 16x slower than Fortran

2012-01-21 Thread Ondřej Čertík
Hi,

I read the Mandelbrot code using NumPy at this page:

http://mentat.za.net/numpy/intro/intro.html

but when I run it, it gives me integer overflows. As such, I have
fixed the code, so that it doesn't overflow here:

https://gist.github.com/1655320

and I have also written an equivalent Fortran program.

You can compare both source codes to see
that that it is pretty much one-to-one translation.
The main idea in the above gist is to take an
algorithm written in NumPy, and translate
it directly to Fortran, without any special
optimizations. So the above is my first try
in Fortran. You can plot the result
using this simple script (you
can also just click on this gist to
see the image there):

https://gist.github.com/1655377

Here are my timings:

   Python  Fortran Speedup
Calculation 12.749  00.784  16.3x
Saving  01.904  01.456  1.3x
Total  14.653   02.240  6.5x

I save the matrices to disk in an ascii format,
so it's quite slow in both cases. The pure computation
is however 16x faster in Fortran (in gfortran,
I didn't even try Intel Fortran, that will probably be
even faster).

As such, I wonder how the NumPy version could be sped up?
I have compiled NumPy with Lapack+Blas from source.

Would anyone be willing to run the NumPy version? Just copy+paste
should do it.

If you want to run the Fortran version, the above gist uses
some of my other modules that I use in my other programs, my goal
was to see how much more complicated the Fortran code gets,
compared to NumPy. As such, I put here

https://gist.github.com/1655350

a single file
with all the dependencies, just compile it like this:

gfortran -fPIC -O3 -march=native -ffast-math -funroll-loops mandelbrot.f90

and run:

$ ./a.out
Iteration 1
Iteration 2
...
Iteration 100
 Saving...
 Times:
 Calculation:  0.748045999
 Saving:   1.36408502
 Total:   2.11213102


Let me know if you figure out something. I think the mask thing is
quite slow, but the problem is that it needs to be there, to catch
overflows (and it is there in Fortran as well, see the
where statement, which does the same thing). Maybe there is some
other way to write the same thing in NumPy?

Ondrej
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