Re: PAR fails on AS build 817
On Fri, 7 Apr 2006, Glenn Linderman wrote: Seems like AS build 817 must have a compatibility problem with PAR. I can't get PAR 0.92 (the latest) or PAR 0.85 (the oldest I had on hand) to build on AS build 817. The previous version of Perl I'd used was AS 810, both of those versions of PAR work there. Further, the PAR PPM from ActiveState also fails to function properly, although it does install. Using the fix that Rob and Jan explain in other replies, I put up a ppm package of PAR-0.92 in our http://theoryx5.uwinnipeg.ca/ppms/ repository - the package is called PAR-588, and it was built on ActivePerl 817. This probably won't work on earlier ActivePerl versions - for these, the PAR package should be used. -- best regards, Randy Kobes ___ Perl-Win32-Users mailing list Perl-Win32-Users@listserv.ActiveState.com To unsubscribe: http://listserv.ActiveState.com/mailman/mysubs
RE: PAR fails on AS build 817
On Fri, 07 Apr 2006, Glenn Linderman wrote: > Seems like AS build 817 must have a compatibility problem with PAR. I > can't get PAR 0.92 (the latest) or PAR 0.85 (the oldest I had on hand) > to build on AS build 817. The previous version of Perl I'd used was AS > 810, both of those versions of PAR work there. AFAIK this is a bug in Module::Install that has been fixed in version 0.61. http://rt.cpan.org/Public/Bug/Display.html?id=18181 As you can see this has been reported (and fixed) by ActiveState a week before 817 was release. For PAR I provided a workaround here: http://www.nntp.perl.org/group/perl.par/2312 and it is my understanding that with this fix Rob has been successful in building that latest release of PAR. All the other messages in that thread seem to involve big and unnecessary changes that have complicated matters, Anyways, I'm not aware of any incompatibilities of AP817 beyond the problem with Module::Install that really is a bug in Module::Install and not in ActivePerl. It is just that this bug had not been triggered by previous releases of ActivePerl. So you can either: * Fix the PAR distribution by removing a single line from the bundled Module::Install. * Go back to an older ActivePerl * Wait until a version of PAR with a fixed Module::Install has been released. Cheers, -Jan ___ Perl-Win32-Users mailing list Perl-Win32-Users@listserv.ActiveState.com To unsubscribe: http://listserv.ActiveState.com/mailman/mysubs
Re: PAR fails on AS build 817
- Original Message - From: "Glenn Linderman" . . > Rob (Sisyphus) was apparently eventually able to > build PAR on his home-built Perl after some patches, but not (if I > understand correctly) on AS 817. You've misunderstood me a little there (which is not surprising given the length of that thread, and the twists and turns that it takes :-) I can build PAR-0.92 straight out of the box on my home-built Perls 5.8.8 (both MinGW-built perl and VC++7-built perl). To build PAR-0.92 on AS 817 (using VC++6.0), I had to remove one line of code from inc/Module/Install.pm (in the PAR-0.92 source). That "one line of code" to be removed is: local @INC = ($path, @INC); The fact that PAR-0.92 then builds fine for me on build 817 makes it all the harder to work out why it's not building for Glenn (when he makes the same change). Cheers, Rob ___ Perl-Win32-Users mailing list Perl-Win32-Users@listserv.ActiveState.com To unsubscribe: http://listserv.ActiveState.com/mailman/mysubs
Re: Replace Leading Spaces (fwd)
Glenn Linderman wrote:
> On approximately 4/7/2006 12:11 PM, came the following characters from
> the keyboard of Nelson R. Pardee:
>
>>I've included timings for 1 iterations for each of the proposed
>>solutions.
>>
>>0.056398 s/\s(?=\s*\S)/0/og
>>0.254457 while (s/\s(?=(\d|\.))/0/ {)
>>0.094268 s/^(\s+)(?=\d)/'0'x(length $1)/e
>>0.026934 (see below) Strip front space, take length diff, replace with n x "0"
>>0.095046 s/^(\s+)/sprintf "%s", q[0]x length($1)/eg
>>0.086842 s/ (?=.*\d)/0/g
>>
>>Surprisingly, the more manual process is the fastest. This latest positive
>>lookahead is a bit slower than the first one, I'm not sure why.
>
>
> I'm not sure either, nor of your measurement technique, but I do notice
> that the top lookahead uses flags /og and the bottom one only uses /g.
> Maybe that contributes to the difference in timing?
Shouldn't matter if no $vars involved.
Rate RE2 RE5 RE3 RE4 RE1 RE1a
RE2 136761/s -- -58% -61% -64% -74% -74%
RE5 326584/s 139% -- -6% -14% -37% -37%
RE3 347705/s 154% 6% -- -9% -33% -33%
RE4 381098/s 179% 17% 10% -- -26% -26%
RE1 516529/s 278% 58% 49% 36% -- -0%
RE1a 516529/s 278% 58% 49% 36% 0% --
1 $str =~ s/\s(?=\s*\S)/0/og;
1a $str =~ s/\s(?=\s*\S)/0/g;
2 1 while ($str =~ s/\s(?=(\d|\.))/0/);
3 $str =~ s/^(\s+)(?=\d)/'0' x (length $1)/e;
4 $str =~ s/^(\s+)/sprintf "%s", q[0]x length($1)/eg;
5 $str =~ s/ (?=.*\d)/0/g;
Each RE was preceded with re-initing the string.
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RE: Replace Leading Spaces
> > Nelson, > > Please add Mark Thomas' solution to your timings to see how > it compares > to the others: > I'd be curious to see how Wags' sprintf compares as well: s/^(\s+)/sprintf "%s", q[0]x length($1)/eg; ___ Perl-Win32-Users mailing list Perl-Win32-Users@listserv.ActiveState.com To unsubscribe: http://listserv.ActiveState.com/mailman/mysubs
Re: Replace Leading Spaces (fwd)
On Fri, 7 Apr 2006, Glenn Linderman wrote:
> On approximately 4/7/2006 12:11 PM, came the following characters from
> the keyboard of Nelson R. Pardee:
> > I've included timings for 1 iterations for each of the proposed
> > solutions.
> >
> > 0.056398 s/\s(?=\s*\S)/0/og
> > 0.254457 while (s/\s(?=(\d|\.))/0/ {)
> > 0.094268 s/^(\s+)(?=\d)/'0'x(length $1)/e
> > 0.026934 (see below) Strip front space, take length diff, replace with n x
> > "0"
> > 0.095046 s/^(\s+)/sprintf "%s", q[0]x length($1)/eg
> > 0.086842 s/ (?=.*\d)/0/g
> >
> > Surprisingly, the more manual process is the fastest. This latest positive
> > lookahead is a bit slower than the first one, I'm not sure why.
>
> I'm not sure either, nor of your measurement technique, but I do notice
> that the top lookahead uses flags /og and the bottom one only uses /g.
> Maybe that contributes to the difference in timing?
I checked /o- for this regex it doesn't make much difference, although it
can indeed make a difference.
Here's the code snippet for timing- I replace the interior of the for loop
for each variation. prd uses Time::Hires gettimeofday to track time used.
The prd arguments are just stuff to print out.
$_=$val="259.00 ";
$c=1;
&prd(__LINE__." 1");
for $i(0..$c){
$_=$val;
s/\s(?=\s*\S)/0/g;
}
print "$_ ";
&prd(__LINE__.' s/\s(?=\s*\S)/0/og');
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RE: Replace Leading Spaces
May not have hit your inbox yet...
0.056398 s/\s(?=\s*\S)/0/og
0.254457 while (s/\s(?=(\d|\.))/0/ {)
0.094268 s/^(\s+)(?=\d)/'0'x(length $1)/e
0.026934 (see below) Strip front space, take length diff, replace with n x
"0"
0.095046 s/^(\s+)/sprintf "%s", q[0]x length($1)/eg
0.086842 s/ (?=.*\d)/0/g
Surprisingly, the more manual process is the fastest. This latest positive
lookahead is a bit slower than the first one, I'm not sure why.
--
($trimmed_string = $_) =~ s/^ *//; # remove leading spaces
$transformed_string = ('0' x ((length $_) - length
$trimmed_string)) . $trimmed_string;
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Re: Replace Leading Spaces
Ken Kriesel wrote: Why not the more concise $string =~ s/^(\s+)/'0'x(length $1)/e; Thanks, that is exactly the same as Paul's solution. Minus the spaces around the 'x'. -- Lyle Kopnicky Software Project Engineer Veicon Technology, Inc. ___ Perl-Win32-Users mailing list Perl-Win32-Users@listserv.ActiveState.com To unsubscribe: http://listserv.ActiveState.com/mailman/mysubs
RE: Perl-Win32-Users Digest, Vol 27, Issue 6 [Possible SPAM]
Title: Secure Message Delivery Secure Message Delivery To ensure your privacy, we are securely delivering this email message to you. Blue Cross of Idaho Health Service, Inc., is committed to protecting the privacy of our members' personal information. We adhere to strict standards of security and confidentiality with regard to personal information. This message will be available for VIEWING ONLY for a period of 60 days. If you want the message available after that time, please print it or cut and paste it into a word document. To view this message and to reply securely, please click the View Message box below. FROM: Steven Pennie SUBJECT: RE: Perl-Win32-Users Digest, Vol 27, Issue 6 [Possible SPAM] VIEW MESSAGE If you are unable to access this message by clicking on the box labeled "View Message," please copy and paste the link below into the Internet Explorer Address Bar. https://securemail.bcidaho.com/messenger/msg?x=d-286079-ZNA0tHaL ___ Perl-Win32-Users mailing list Perl-Win32-Users@listserv.ActiveState.com To unsubscribe: http://listserv.ActiveState.com/mailman/mysubs
RE: Replace Leading Spaces
Why not the more concise $string =~ s/^(\s+)/'0'x(length $1)/e; as in my $string = ' 259.00 '; print "<$string>\n"; #$string =~ s/^(\s+)(?=\d)/'0'x(length $1)/e; $string =~ s/^(\s+)/'0'x(length $1)/e; print "<$string>\n"; which outputs: < 259.00 > <0259.00 > showing same spacing fore & aft. ^\s+ alone will match any leading white-space, up to where a non-white-space character \S is encountered. Characters that can have more than one cell width, like \t, could require special handling if present. Ken At 10:56 AM 4/7/2006, Paul Sobey wrote: >> My $string = ' 259.00 '; >> >> Note that I don't want to change the trailing space character. The >> resulting string would look like: >> >> '0259.00 ' >> >> The total length of the string would remain the same after the replace >> operation. >> >> I'm just having a total brain-fade on this one. > >$string =~ s/^(\s+)/'0' x length($1)/e > >Does that do what you want? > >P. > >* >Gloucester Research Limited believes the information >provided herein is reliable. While every care has been >taken to ensure accuracy, the information is furnished >to the recipients with no warranty as to the completeness >and accuracy of its contents and on condition that any >errors or omissions shall not be made the basis for any >claim, demand or cause for action. > >The information in this email is intended only for the >named recipient. If you are not the intended recipient >please notify us immediately and do not copy, distribute >or take action based on this e-mail. > >Gloucester Research Limited, 5th Floor, Whittington House, >19-30 Alfred Place, London WC1E 7EA >* > >___ >Perl-Win32-Users mailing list >Perl-Win32-Users@listserv.ActiveState.com >To unsubscribe: http://listserv.ActiveState.com/mailman/mysubs ___ Perl-Win32-Users mailing list Perl-Win32-Users@listserv.ActiveState.com To unsubscribe: http://listserv.ActiveState.com/mailman/mysubs
RE: Replace Leading Spaces
Oops, I see I misattributed 2 lines. my $string = ' 259.00 '; print "<$string>\n"; #$string =~ s/^(\s+)(?=\d)/'0'x(length $1)/e; #Mike Arms posted $string =~ s/^(\s+)/'0'x(length $1)/e; #Paul Sobey; quicker than above line print "<$string>\n"; which outputs: < 259.00 > <0259.00 > Ken At 10:56 AM 4/7/2006, Paul Sobey wrote: >> My $string = ' 259.00 '; >> >> Note that I don't want to change the trailing space character. The >> resulting string would look like: >> >> '0259.00 ' >> >> The total length of the string would remain the same after the replace >> operation. >> >> I'm just having a total brain-fade on this one. > >$string =~ s/^(\s+)/'0' x length($1)/e > >Does that do what you want? > >P. > >* >Gloucester Research Limited believes the information >provided herein is reliable. While every care has been >taken to ensure accuracy, the information is furnished >to the recipients with no warranty as to the completeness >and accuracy of its contents and on condition that any >errors or omissions shall not be made the basis for any >claim, demand or cause for action. > >The information in this email is intended only for the >named recipient. If you are not the intended recipient >please notify us immediately and do not copy, distribute >or take action based on this e-mail. > >Gloucester Research Limited, 5th Floor, Whittington House, >19-30 Alfred Place, London WC1E 7EA >* > >___ >Perl-Win32-Users mailing list >Perl-Win32-Users@listserv.ActiveState.com >To unsubscribe: http://listserv.ActiveState.com/mailman/mysubs ___ Perl-Win32-Users mailing list Perl-Win32-Users@listserv.ActiveState.com To unsubscribe: http://listserv.ActiveState.com/mailman/mysubs
RE: Replace Leading Spaces (fwd)
I've included timings for 1 iterations for each of the proposed
solutions.
0.056398 s/\s(?=\s*\S)/0/og
0.254457 while (s/\s(?=(\d|\.))/0/ {)
0.094268 s/^(\s+)(?=\d)/'0'x(length $1)/e
0.026934 (see below) Strip front space, take length diff, replace with n x "0"
0.095046 s/^(\s+)/sprintf "%s", q[0]x length($1)/eg
0.086842 s/ (?=.*\d)/0/g
Surprisingly, the more manual process is the fastest. This latest positive
lookahead is a bit slower than the first one, I'm not sure why.
--
($trimmed_string = $_) =~ s/^ *//; # remove leading spaces
$transformed_string = ('0' x ((length $_) - length
$trimmed_string)) . $trimmed_string;
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RE: Replace Leading Spaces
Dirk Bremer - Senior Systems Engineer - ESS/AMS - NISC Lake St. Louis MO
- USA Central Time Zone
636-755-2652 fax 636-755-2503
[EMAIL PROTECTED]
www.nisc.coop
> -Original Message-
> From: [EMAIL PROTECTED]
> [mailto:[EMAIL PROTECTED] On
> Behalf Of Nelson R. Pardee
> Sent: Friday, April 07, 2006 13:20
> To: Active State Perl
> Subject: RE: Replace Leading Spaces
>
> Try # 2:
> The first is my new one using a positive lookahead assertion.
> I've included timings for 1 iterations for each of the proposed
> solutions.
>
> 0.056398 s/\s(?=\s*\S)/0/og
> 0.254457 while (s/\s(?=(\d|\.))/0/ {)
> 0.094268 s/^(\s+)(?=\d)/'0'x(length $1)/e
>
Nelson,
Please add Mark Thomas' solution to your timings to see how it compares
to the others:
s/ (?=.*\d)/0/g
Dirk Bremer - Senior Systems Engineer - ESS/AMS - NISC Lake St. Louis MO
- USA Central Time Zone
636-755-2652 fax 636-755-2503
[EMAIL PROTECTED]
www.nisc.coop
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RE: Replace Leading Spaces
> Using a regex, I want to replace each leading space-character > with a corresponding zero-character on a one-to-one basis. > For an example > string: > > My $string = ' 259.00 '; > > Note that I don't want to change the trailing space > character. The resulting string would look like: > > '0259.00 ' How about s/ (?=.*\d)/0/g; Translation: any space with a digit to its right gets replaced with a zero. -- Mark Thomas Internet Systems Architect ___ BAE SYSTEMS Information Technology 2525 Network Place Herndon, VA 20171 USA ___ Perl-Win32-Users mailing list Perl-Win32-Users@listserv.ActiveState.com To unsubscribe: http://listserv.ActiveState.com/mailman/mysubs
RE: Replace Leading Spaces
> -Original Message- > From: Thomas, Mark - BLS CTR [mailto:[EMAIL PROTECTED] > Sent: Friday, April 07, 2006 13:15 > To: Dirk Bremer; Perl-Win32-Users@listserv.ActiveState.com > Subject: RE: Replace Leading Spaces > > > Using a regex, I want to replace each leading space-character > > with a corresponding zero-character on a one-to-one basis. > > For an example > > string: > > > > My $string = ' 259.00 '; > > > > Note that I don't want to change the trailing space > > character. The resulting string would look like: > > > > '0259.00 ' > > How about > > s/ (?=.*\d)/0/g; > > Translation: any space with a digit to its right gets replaced with a > zero. > > -- > Mark Thomas Mark, I also like your solution, thanks! Dirk Bremer - Senior Systems Engineer - ESS/AMS - NISC Lake St. Louis MO - USA Central Time Zone 636-755-2652 fax 636-755-2503 [EMAIL PROTECTED] www.nisc.coop ___ Perl-Win32-Users mailing list Perl-Win32-Users@listserv.ActiveState.com To unsubscribe: http://listserv.ActiveState.com/mailman/mysubs
RE: Replace Leading Spaces
Try # 2:
The first is my new one using a positive lookahead assertion.
I've included timings for 1 iterations for each of the proposed
solutions.
0.056398 s/\s(?=\s*\S)/0/og
0.254457 while (s/\s(?=(\d|\.))/0/ {)
0.094268 s/^(\s+)(?=\d)/'0'x(length $1)/e
On Fri, 7 Apr 2006, Dirk Bremer wrote:
> > Using a regex, I want to replace each leading space-character with a
> > corresponding zero-character on a one-to-one basis. For an example
> > string:
> >
> > My $string = ' 259.00 ';
> >
> > Note that I don't want to change the trailing space character. The
> > resulting string would look like:
> >
> > '0259.00 '
> >
> > The total length of the string would remain the same after the replace
> > operation.
--Nelson R. Pardee, Support Analyst, Information Technology & Services--
--Syracuse University, 211 Machinery Hall, Syracuse, NY 13244-1260--
--(315) 443-1079 [EMAIL PROTECTED] --
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Re: Replace Leading Spaces
Dirk Bremer wrote:
All right, in the mean time, I have come up with the following:
while (s/\s(?=(\d|\.))/0/) {}
This works nicely, but I' wondering if it can be accomplished without
looping and perhaps more efficiently as well.
Your thoughts?
I think that's kind of confusing. I like Paul's suggestion. It's
short, simple, I look at it and can see what it means right away.
Here's another way, that should be pretty efficient:
my $string = ' 259.00 ';
(my $trimmed_string = $string) ~= s/^ *//; # remove leading spaces
my $transformed_string = '0' x (length $string - length $trimmed_string)
. $trimmed_string;
--
Lyle Kopnicky
Software Project Engineer
Veicon Technology, Inc.
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Re: Replace Leading Spaces
On Fri, 7 Apr 2006, Nelson R. Pardee wrote: > Don't know if this is the most efficient, but it seems to work for me... > s/^(0?\s)/0/g; Another brain fade!. This doesn't work. ___ Perl-Win32-Users mailing list Perl-Win32-Users@listserv.ActiveState.com To unsubscribe: http://listserv.ActiveState.com/mailman/mysubs
Re: Replace Leading Spaces
Don't know if this is the most efficient, but it seems to work for me... s/^(0?\s)/0/g; On Fri, 7 Apr 2006, Dirk Bremer wrote: > Using a regex, I want to replace each leading space-character with a > corresponding zero-character on a one-to-one basis. For an example > string: > > My $string = ' 259.00 '; > > Note that I don't want to change the trailing space character. The > resulting string would look like: > > '0259.00 ' > > The total length of the string would remain the same after the replace > operation. --Nelson R. Pardee, Support Analyst, Information Technology & Services-- --Syracuse University, 211 Machinery Hall, Syracuse, NY 13244-1260-- --(315) 443-1079 [EMAIL PROTECTED] -- ___ Perl-Win32-Users mailing list Perl-Win32-Users@listserv.ActiveState.com To unsubscribe: http://listserv.ActiveState.com/mailman/mysubs
RE: Replace Leading Spaces
[EMAIL PROTECTED] wrote: > Using a regex, I want to replace each leading space-character with a > corresponding zero-character on a one-to-one basis. For an example > string: > > My $string = ' 259.00 '; > > Note that I don't want to change the trailing space character. The > resulting string would look like: > > '0259.00 ' > > The total length of the string would remain the same after the replace > operation. > > I'm just having a total brain-fade on this one. It was brain fade here also, but finally found one way: #!perl use strict; use warnings; $_ = ' 259.00 '; print $_ . "\n"; s/^(\s+)/sprintf "%s", q[0]x length($1)/eg; print $_ . "\n"; Output: 259.00 00259.00 hth Wags ;) > > Dirk Bremer - Senior Systems Engineer - ESS/AMS - NISC Lake St. Louis > MO - USA Central Time Zone > 636-755-2652 fax 636-755-2503 > > [EMAIL PROTECTED] > www.nisc.coop > > ___ > Perl-Win32-Users mailing list > Perl-Win32-Users@listserv.ActiveState.com > To unsubscribe: http://listserv.ActiveState.com/mailman/mysubs *** This message contains information that is confidential and proprietary to FedEx Freight or its affiliates. It is intended only for the recipient named and for the express purpose(s) described therein. Any other use is prohibited. *** ___ Perl-Win32-Users mailing list Perl-Win32-Users@listserv.ActiveState.com To unsubscribe: http://listserv.ActiveState.com/mailman/mysubs
RE: Replace Leading Spaces
Dirk Bremer [Dirk.Bremer AT nisc.coop] wrote: > Using a regex, I want to replace each leading space-character with a > corresponding zero-character on a one-to-one basis. For an example > string: > > my $string = ' 259.00 '; > > Note that I don't want to change the trailing space character. The > resulting string would look like: > > '0259.00 ' > > The total length of the string would remain the same after the > replace operation. Hi, Dirk, You mean something like this? $string =~ s/^(\s+)(?=\d)/'0'x(length $1)/e; The power of the 'e' modifier on the substitution function. :-) -- Mike Arms ___ Perl-Win32-Users mailing list Perl-Win32-Users@listserv.ActiveState.com To unsubscribe: http://listserv.ActiveState.com/mailman/mysubs
RE: Replace Leading Spaces
> -Original Message- > From: Arms, Mike [mailto:[EMAIL PROTECTED] > Sent: Friday, April 07, 2006 11:37 > To: Perl-Win32-Users@listserv.ActiveState.com > Cc: Dirk Bremer > Subject: RE: Replace Leading Spaces > > Dirk Bremer [Dirk.Bremer AT nisc.coop] wrote: > > Using a regex, I want to replace each leading space-character with a > > corresponding zero-character on a one-to-one basis. For an example > > string: > > > > my $string = ' 259.00 '; > > > > Note that I don't want to change the trailing space character. The > > resulting string would look like: > > > > '0259.00 ' > > > > The total length of the string would remain the same after the > > replace operation. > > Hi, Dirk, > > You mean something like this? > > $string =~ s/^(\s+)(?=\d)/'0'x(length $1)/e; > > The power of the 'e' modifier on the substitution function. :-) > > -- > Mike Arms > Now that one is pretty darn cool and something I didn't know about. Thanks Mike! Dirk Bremer - Senior Systems Engineer - ESS/AMS - NISC Lake St. Louis MO - USA Central Time Zone 636-755-2652 fax 636-755-2503 [EMAIL PROTECTED] www.nisc.coop ___ Perl-Win32-Users mailing list Perl-Win32-Users@listserv.ActiveState.com To unsubscribe: http://listserv.ActiveState.com/mailman/mysubs
Re: Replace Leading Spaces
Using a regex, I want to replace each leading space-character with a corresponding zero-character on a one-to-one basis. For an example string: My $string = ' 259.00 '; Note that I don't want to change the trailing space character. The resulting string would look like: '0259.00 ' The total length of the string would remain the same after the replace operation. I'm just having a total brain-fade on this one. Perl sprintf or printf built-in function. 'perldoc -f sprintf' printf '<%06s>', 12; # prints "<12>" ___ Perl-Win32-Users mailing list Perl-Win32-Users@listserv.ActiveState.com To unsubscribe: http://listserv.ActiveState.com/mailman/mysubs
RE: Replace Leading Spaces
> -Original Message-
> From: [EMAIL PROTECTED]
> [mailto:[EMAIL PROTECTED] On
> Behalf Of Dirk Bremer
> Sent: Friday, April 07, 2006 09:52
> To: Perl-Win32-Users@listserv.ActiveState.com
> Subject: Replace Leading Spaces
>
> Using a regex, I want to replace each leading space-character with a
> corresponding zero-character on a one-to-one basis. For an example
> string:
>
> My $string = ' 259.00 ';
>
> Note that I don't want to change the trailing space character. The
> resulting string would look like:
>
> '0259.00 '
>
> The total length of the string would remain the same after the replace
> operation.
>
> I'm just having a total brain-fade on this one.
>
All right, in the mean time, I have come up with the following:
while (s/\s(?=(\d|\.))/0/) {}
This works nicely, but I' wondering if it can be accomplished without
looping and perhaps more efficiently as well.
Your thoughts?
Dirk Bremer - Senior Systems Engineer - ESS/AMS - NISC Lake St. Louis MO
- USA Central Time Zone
636-755-2652 fax 636-755-2503
[EMAIL PROTECTED]
www.nisc.coop
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RE: Replace Leading Spaces
> My $string = ' 259.00 '; > > Note that I don't want to change the trailing space character. The > resulting string would look like: > > '0259.00 ' > > The total length of the string would remain the same after the replace > operation. > > I'm just having a total brain-fade on this one. $string =~ s/^(\s+)/'0' x length($1)/e Does that do what you want? P. * Gloucester Research Limited believes the information provided herein is reliable. While every care has been taken to ensure accuracy, the information is furnished to the recipients with no warranty as to the completeness and accuracy of its contents and on condition that any errors or omissions shall not be made the basis for any claim, demand or cause for action. The information in this email is intended only for the named recipient. If you are not the intended recipient please notify us immediately and do not copy, distribute or take action based on this e-mail. Gloucester Research Limited, 5th Floor, Whittington House, 19-30 Alfred Place, London WC1E 7EA * ___ Perl-Win32-Users mailing list Perl-Win32-Users@listserv.ActiveState.com To unsubscribe: http://listserv.ActiveState.com/mailman/mysubs
Replace Leading Spaces
Using a regex, I want to replace each leading space-character with a corresponding zero-character on a one-to-one basis. For an example string: My $string = ' 259.00 '; Note that I don't want to change the trailing space character. The resulting string would look like: '0259.00 ' The total length of the string would remain the same after the replace operation. I'm just having a total brain-fade on this one. Dirk Bremer - Senior Systems Engineer - ESS/AMS - NISC Lake St. Louis MO - USA Central Time Zone 636-755-2652 fax 636-755-2503 [EMAIL PROTECTED] www.nisc.coop ___ Perl-Win32-Users mailing list Perl-Win32-Users@listserv.ActiveState.com To unsubscribe: http://listserv.ActiveState.com/mailman/mysubs
WMI Querying - Slightly OT
Using the attached WMIExplore.pl, enumerating the Win32_PerfRawData_Tcpip_NetworkInterface class on most of my servers gives information similar to the following: D:\CVS\secure\scripts\SystemsMonitoring>WMIExplore.pl Win32_PerfRawData_Tcpip_NetworkInterface l3pinfra1 Collecting WMI data from l3pinfra1 for Win32_PerfRawData_Tcpip_NetworkInterface === BytesReceivedPersec -> 791744567 -> PERF_COUNTER_COUNTER BytesSentPersec -> 1209514631 -> PERF_COUNTER_COUNTER BytesTotalPersec -> 2001259198 -> PERF_COUNTER_BULK_COUNT Caption -> -> CurrentBandwidth -> 1 -> PERF_COUNTER_RAWCOUNT Description -> -> Frequency_Object -> 0 -> Frequency_PerfTime -> 339179 -> Frequency_Sys100NS -> 1000 -> Name -> Intel[R] PRO_1000 MT Network Connection _2 -> We have a farm of servers with 4 GB NICs teamed, so that the live interface has a bandwidth of 4 GB/s. Running the same code on one of these machines shows this: D:\CVS\secure\scripts\SystemsMonitoring>WMIExplore.pl Win32_PerfRawData_Tcpip_NetworkInterface l3pcalcamd2 Collecting WMI data from l3pcalcamd2 for Win32_PerfRawData_Tcpip_NetworkInterface === BytesReceivedPersec -> 1850144995 -> PERF_COUNTER_COUNTER BytesSentPersec -> -876640650 -> PERF_COUNTER_COUNTER BytesTotalPersec -> 973504345 -> PERF_COUNTER_BULK_COUNT Caption -> -> CurrentBandwidth -> -294967296 -> PERF_COUNTER_RAWCOUNT Description -> -> Frequency_Object -> 0 -> Frequency_PerfTime -> 260600 -> Frequency_Sys100NS -> 1000 -> Name -> HP Network Team _1 -> The CurrentBandwidth property is a negative value, almost as if it is a counter that has wrapped. Does anybody know how I can process this to get the true value? Cheers, Paul * Gloucester Research Limited believes the information provided herein is reliable. While every care has been taken to ensure accuracy, the information is furnished to the recipients with no warranty as to the completeness and accuracy of its contents and on condition that any errors or omissions shall not be made the basis for any claim, demand or cause for action. The information in this email is intended only for the named recipient. If you are not the intended recipient please notify us immediately and do not copy, distribute or take action based on this e-mail. Gloucester Research Limited, 5th Floor, Whittington House, 19-30 Alfred Place, London WC1E 7EA * WMIExplore.pl Description: WMIExplore.pl ___ Perl-Win32-Users mailing list Perl-Win32-Users@listserv.ActiveState.com To unsubscribe: http://listserv.ActiveState.com/mailman/mysubs
Re: CGI OR NOT
On Apr 6, 2006, at 18:03, So Phal wrote:
Hi
I want to know whether using CGI and using pain html is faster or what?
If I use CGI to generate the html and write pain html code inside Perl
to generate Html. I believe write pain html inside Perl is more faster
then CGI generate html code.
What do you think ?
I'm not sure I understand what you want to know... what do you mean
with "pain html"? And what exactly do you mean by using "CGI"? CGI is
an interface, a set of rules, for communicating between he web server
and a server-side program.
dZ.
--
$question = ( /(bb|[^b]{2})/ );
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Re: CGI OR NOT
At 03:03 PM 4/6/2006 -0700, So Phal wrote: >I want to know whether using CGI and using pain html is faster or what? >If I use CGI to generate the html and write pain html code inside Perl to >generate Html. I believe write pain html inside Perl is more faster then CGI >generate html code. I assume u mean "plain" html. I don't think u understand what CGI is. CGI is the "gateway" that allows any script to output data through a web server to a client. In what u propose, perl is running as a CGI script. Having perl output html will be pretty fast, since it's just printing text. Having a static html document however will be even faster since there's no processing involved. If u just need to output plain text then having static files is better. -- REMEMBER THE WORLD TRADE CENTER ---=< WTC 911 >=-- "...ne cede malis" 0100 ___ Perl-Win32-Users mailing list Perl-Win32-Users@listserv.ActiveState.com To unsubscribe: http://listserv.ActiveState.com/mailman/mysubs
