Hi,
I've following select, and I expect to receive a single record as result from it:
select c.id
from copie as c
where c.enum=46857 and
c.condizio_prestito = 'A' and
c.id not in (select id_copia from testi_fermi_prenotati) and
c.id not in (select id_copia from prestiti);
but it doesn't give me any records at all.
Following there is table descriptions:
CREATE TABLE copie (
id serial NOT NULL primary key,
enum integer,
id_biblioteca integer NOT NULL,
serie text,
collocazione text,
note text,
condizio_prestito character(1) DEFAULT 'A'::bpchar,
ctime date DEFAULT now(),
mtime date,
inventario integer
);
CREATE TABLE prestiti (
id serial NOT NULL,
inizio date DEFAULT now(),
id_libro text,
id_utente text,
fine date,
scadenza date NOT NULL,
stato smallint DEFAULT 1,
id_copia integer references copie(id)
);
CREATE TABLE testi_fermi_prenotati (
id_copia integer NOT NULL references copie(id),
id_prenotazione integer NOT NULL,
fermato_il timestamp without time zone DEFAULT now() NOT NULL,
scadenza timestamp without time zone,
stato character(1) DEFAULT 'a'::bpchar
);
and some usefull query results:
prove= select * from copie where enum=46857;
id | enum | id_biblioteca | serie | collocazione | note |
condizio_prestito | ctime| mtime | inventario
---+---+---+---+--+--+---++---+
37163 | 46857 | 1 | | F RRN MAY| | A
| 2004-05-03 | | 41576
(1 row)
(SEE THE FOLLOWING QUERY AND RESULT)
prove= select * from prestiti where id_copia=37163;
id | inizio | id_libro | id_utente | fine | scadenza | stato | id_copia
++--+---+--+--+---+--
(0 rows)
prove= select * from testi_fermi_prenotati where id_copia=37163;
id_copia | id_prenotazione | fermato_il | scadenza | stato
--+-++--+---
(0 rows)
prove= select c.id
from copie as c
where c.enum=46857 and
c.condizio_prestito = 'A' and
c.id not in (select id_copia from testi_fermi_prenotati) and
c.id not in (select id_copia from prestiti);
id
(0 rows)
prove= select c.id
from copie as c
where c.enum=46857 and
c.condizio_prestito = 'A' and
c.id not in (select id_copia from testi_fermi_prenotati);
id
---
37163
(1 row)
prove= select c.id
from copie as c
where c.enum=46857 and
c.condizio_prestito = 'A' and
c.id not in (select id_copia from prestiti);
id
(0 rows)
prove= explain analyze select c.id
from copie as c
where c.enum=46857 and
c.condizio_prestito = 'A' and
c.id not in (select id_copia from testi_fermi_prenotati) and
c.id not in (select id_copia from prestiti);
QUERY PLAN
-
Seq Scan on copie c (cost=0.00..14587.17 rows=1 width=4) (actual
time=15.82..15.82 rows=0 loops=1)
Filter: ((enum = 46857) AND (condizio_prestito = 'A'::bpchar) AND (subplan)
AND (subplan))
SubPlan
- Seq Scan on testi_fermi_prenotati (cost=0.00..0.00 rows=1 width=4)
(actual time=0.00..0.00 rows=0 loops=1)
- Seq Scan on prestiti (cost=0.00..23.41 rows=1241 width=4) (actual
time=0.01..10.21 rows=1241 loops=1)
Total runtime: 15.95 msec
(6 rows)
prove= explain select c.id
from copie as c
where c.enum=46857 and
c.condizio_prestito = 'A' and
c.id not in (select id_copia from testi_fermi_prenotati) and
c.id not in (select id_copia from prestiti);
QUERY PLAN
--
Seq Scan on copie c (cost=0.00..14587.17 rows=1 width=4)
Filter: ((enum = 46857) AND (condizio_prestito = 'A'::bpchar) AND (subplan)
AND (subplan))
SubPlan
- Seq Scan on testi_fermi_prenotati (cost=0.00..0.00 rows=1 width=4)
- Seq Scan on prestiti (cost=0.00..23.41 rows=1241 width=4)
(5 rows)
If you want to play with these data:
http://diff.homeunix.net/anomalia.sql.gz
then
gzip -d anomalias.sql
createdb anydb
psql -f anomalia.sql anydb
Best wishes, \ferz
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