Hi Josh,
I am really sorry to bother you again and I promise
to buy a book after this problem is solved and
stop asking these beginners' questions.
But the last example-Query you sent me does not
work, it produces:
ERROR: parser: parse error at or near (
and I am sure, I entered it correctly.
(I also tried on PostgreSQL Versions 7.0.3 and
7.1.3)
Thank you very much,
Frederick
--- Josh Berkus [EMAIL PROTECTED] wrote:
Frederick,
Mary Stuart correctly. But such a query also
seems to get results that contain only one
of the search_attributes.
e.g. a 32 Peter Smith who e.g. just has an entry
24 32 hair brown (and no mice hobby) is also
found.
I need to get only results that match the search
completely.
I would be happy if you could help me again.
Thanks, Frederick
Oops. You are quite correct. Unfortunately, the
query that you need is
somewhat more complicated:
SELECT people.people_id, people.name,
people.address,
people_attributes.attribute_name,
people_attributes.attribute_value
FROM people, people_attributes,
( SELECT people_id, count(*) as match_count
FROM people_attributes, search_attributes
WHERE search_id = 31
AND people_attributes.attribute_name =
search_attributes.attribute_name
AND people_attributes.attribute_value ~*
search_attributes.attribute_value )
matches,
( SELECT count(*) as attribute_count
FROM search_attributes
WHERE search_id = 31 ) searched
WHERE people.people_id = people_attributes.people_id
AND people.people_id = matches.people_id
AND matches.match_count =
searched.attribute_count;
This structure will also allow you to search for,
say, 4 out of 5 items
by changing the last line to:
AND matches.match_count =
(searched.attribute_count - 1);
Also, if you re-arrange the query slightly, you can
turn it into a view.
The trick is to have the search_id as an output
column rather than a
WHERE clause item in the sub-selects.
Have fun!
-Josh
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[EMAIL PROTECTED]
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