ID: 19943
Comment by: [EMAIL PROTECTED]
Reported By: [EMAIL PROTECTED]
Status: Critical
Bug Type: Arrays related
Operating System: Win2K
PHP Version: 4.3.0-dev
New Comment:
I think this is pretty much invalid.
[EMAIL PROTECTED] posted 2 examples. Only 1 is correct, or infact, valid
code.
In the first example, you have the following 2 array assignments.
$ragged[$count]= 'single '.$count;
$ragged[$count]['idx'] = 'ragged '.$count;
In this, you assign a string to $ragged[$count], then, you turn it into
an array using $regged[$count]['idx'].
This is invlaid in most languages.
In the $ragged[$count], $ragged['idx'][$count] method, no type changes
are taking place.
Previous Comments:
[2002-10-16 22:51:14] [EMAIL PROTECTED]
A pretty interesting bug this is, there appear to be 2 possible
behaviours that can happen here and only 1 is correct.
?php
$ar = array();
for ( $count = 0; $count 10; $count++ )
{
$ar[$count]= $count;
$ar[$count]['idx'] = $count;
}
for ( $count = 0; $count 10; $count++ )
{
echo $ar[$count]. -- .$ar[$count]['idx'].\n;
}
?
The code above will output:
t 0 -- t
t 1 -- t
t 2 -- t
t 3 -- t
t 4 -- t
t 5 -- t
t 6 -- t
t 7 -- t
t 8 -- t
t 9 -- t
/home/rei/PHP_CVS/php4/Zend/zend_operators.c(1008) : Freeing
0x08369384 (6 bytes), script=a.php
Last leak repeated 9 times
If the around the $count variable are removed then the script
reports:
Warning: Cannot use a scalar value as an array in
/home/rei/PHP_CVS/php4/a.php on line 7
/home/rei/PHP_CVS/php4/a.php(7) : Warning - Cannot use a scalar value
as an array
for every assignment and does no initialize any of the
$ar[$count]['idx'] values.
[2002-10-16 19:54:16] [EMAIL PROTECTED]
However, the following codes does work, even though the array is still
ragged:
?
$ragged = array();
for ( $count = 0; $count 10; $count++ )
{
$ragged['idx'][$count] = 'ragged '.$count;
$ragged[$count]= 'single '.$count;
}
?
htmlhead/headbody
table border=1
tr
tdExpected/tdtdActual/td
tdExpected IDX/tdtdActual IDX/td
/tr
?
for ( $count = 0; $count 10; $count++ )
{
?
tr
td ?= 'single '.$count ? /tdtd ?= $ragged[$count] ? /td
td ?= 'ragged '.$count ? /tdtd ?= $ragged['idx'][$count] ?
/td
/tr
? } ?
/table/body/html
[2002-10-16 19:50:57] [EMAIL PROTECTED]
When using an array that has ragged indices, the value in the array is
undefined. Well, actually it can be defined, but it is unexpected. No
errors or warnings are reported. Sample Code:
?
$ragged = array();
for ( $count = 0; $count 10; $count++ )
{
$ragged[$count]= 'single '.$count;
$ragged[$count]['idx'] = 'ragged '.$count;
}
?
htmlhead/headbody
table border=1
tr
tdExpected/tdtdActual/td
tdExpected IDX/tdtdActual IDX/td
/tr
?
for ( $count = 0; $count 10; $count++ )
{
?
tr
td ?= 'single '.$count ? /tdtd ?= $ragged[$count] ? /td
td ?= 'ragged '.$count ? /tdtd ?= $ragged[$count]['idx'] ?
/td
/tr
? } ?
/table/body/html
--
Edit this bug report at http://bugs.php.net/?id=19943edit=1
