RE: [PHP-DB] Corn job anomaly
> -Original Message- > From: Karl DeSaulniers [mailto:k...@designdrumm.com] > Sent: 25 September 2016 09:59 > To: PHP List Database <php-db@lists.php.net> > Subject: Re: [PHP-DB] Corn job anomaly > > Now I am getting an error with mysql syntax. > > "SELECT otn.*, cf.* FROM ".ORDER_TABLE." otn LEFT JOIN ".FIELDS_TABLE." cf > ON cf.Order_ID = otn.Order_ID WHERE cf.Earliest_Pickup >= DATE(NOW()) AND > cf.Earliest_Pickup <= DATE(NOW() + INTERVAL ".($Num_Days_Away+1)." DAY) AND > otn.Order_Status != 'Shipping' AND otn.Order_Status != 'Completed'" > > is giving me this error: > You have an error in your SQL syntax; check the manual that > corresponds to your MySQL server version for the right syntax to use near > '\"Shipping\" AND otn.Order_Status != \"Completed\"' at line 1 I don't think INTERVAL works like that - you probably need something like: ... cf.Earliest_Pickup <= DATE_ADD(CURDATE(), INTERVAL ".($Num_Days_Away+1)." DAY) AND ... Incidentally, as I understand it CURDATE() does exactly the same as DATE(NOW()), and is probably more readable. Cheers! Mike -- Mike Ford, Electronic Information Developer, Libraries and Learning Innovation, 110 Queen Square House, 80 Woodhouse Lane, Leeds Beckett University, Leeds LS2 8NU, United Kingdom E & S4B: m.f...@leedsbeckett.ac.uk T: +44 113 812 4730 To view the terms under which this email is distributed, please go to:- http://disclaimer.leedsbeckett.ac.uk/disclaimer/disclaimer.html -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Newbie Question $2
Oh a few quick things. First, you can use substr to break up the phone instead of grabbing characters- might be a little easier to read long term. Secondly, mysql_real_escape_string will return the cleaned string, but doesn't change the original variable. So you'll need $phn = mysql_real_escape_string($phn); Thirdly anytime you use a single quote the strong is interpreted literally. You'll want to switch out the single quotes with double quotes, and then wrap $phn in single quotes in order to not break your query. Select ... Where phn = '$phn' I'd also really suggest looking at using PDO or even the mysqli extension tho instead of just plain mysql (believe this has been deprecated). Sorry for the quick reply, on mobile. But feel free to email me directly and I'll be happy to help out more. - Mike Sent from my iPhone On Jun 16, 2014, at 7:58 PM, Ethan Rosenberg erosenb...@hygeiabiomedical.com wrote: Dear List - I have the following code: The input from the form is a 10 digit string [1234567890] which is converted to phone number format [123-456-7890] $phn = $_POST[phone]; $phn = (string)$phn; $dsh = '-'; $Phn = $phn[0].$phn[1].$phn[2].$dsh.$phn[3].$phn[4].$phn[5].$dsh.$phn[6].$phn[7].$phn[8].$phn[9]; echo $Phn; // this is folded by Thunderbird. In the script, it is //all on one line mysql_real_escape_string($Phn); $sql1 ='select Lname, Fname from Customers where Phone = $Phn '; echo $sql1; //this always shows $phn as Phn and not as a numerical //string. $result1 = mysqli_query($cxn, $sql1); TIA Ethan -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] Re: Formatting
-Original Message- From: Karl DeSaulniers [mailto:k...@designdrumm.com] Sent: 26 November 2012 08:48 To: php-db@lists.php.net Subject: Re: [PHP-DB] Re: Formatting Ethan, is this valid PHP? What is the ampersand for? What is it doing? Just curious. $args[] = $_POST[$k]; // Note the addition of the ampersand here That's a perfectly valid reference assignment. Please see the Fine Manual at: http://php.net/manual/language.references.whatdo.php Cheers! Mike -- Mike Ford, Electronic Information Developer, Libraries and Learning Innovation, Portland PD507, City Campus, Leeds Metropolitan University, Portland Way, LEEDS, LS1 3HE, United Kingdom E: m.f...@leedsmet.ac.uk T: +44 113 812 4730 To view the terms under which this email is distributed, please go to http://disclaimer.leedsmet.ac.uk/email.htm -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] SELECT
-Original Message- From: tamouse mailing lists [mailto:tamouse.li...@gmail.com] Sent: 20 October 2011 21:37 On Tue, Oct 18, 2011 at 5:36 AM, Ford, Mike m.f...@leedsmet.ac.uk wrote: -Original Message- From: Ron Piggott [mailto:ron.pigg...@actsministries.org] Sent: 17 October 2011 18:38 What I am storing in the table is the start month # (1 to 12) and day # (1 to 31) and then the finishing month # (1 to 12) and the finishing day # (1 to 31) This is a little bit of a tricky one, as you have to consider both start_month and end_month as special cases - so you need a three- part conditional, for the start month, the end month, and the months in between. Something like this: SELECT * FROM `introduction_messages` WHERE (month`start_month` AND month`end_month`) OR (month=`start_month AND day=`start_day`) OR (month=`end_month` AND day=`end_day`); This still suffers from the problem in Jim's offer -- wrap of year and wrap of month Look again. Month wrap *is* handled by the specific tests for start_month and end_month. As to year-wrap, Ron's original post said: ... The reason I didn’t use ‘DATE’ is because the same message will be displayed year after year, depending on the date range. so I didn't bother about year-wrap, assuming he would include a range with start_date of 1/1 and another with end_date of 31/12. Cheers! Mike -- Mike Ford, Electronic Information Developer, Libraries and Learning Innovation, Portland PD507, City Campus, Leeds Metropolitan University, Portland Way, LEEDS, LS1 3HE, United Kingdom E: m.f...@leedsmet.ac.uk T: +44 113 812 4730 But in the case of years actually mattering then, yes, the above would not work To view the terms under which this email is distributed, please go to http://disclaimer.leedsmet.ac.uk/email.htm
RE: [PHP-DB] SELECT
-Original Message- From: Ron Piggott [mailto:ron.pigg...@actsministries.org] Sent: 17 October 2011 18:38 I need help creating a mySQL query that will select the correct introduction message for a website I am making. The way I have designed the table I can’t wrap my mind around the SELECT query that will deal with the day # of the month. The part of the SELECT syntax I am struggling with is when the introduction message is to change mid month. The reason I am struggling with this is because I haven’t used ‘DATE’ for the column type. The reason I didn’t use ‘DATE’ is because the same message will be displayed year after year, depending on the date range. What I am storing in the table is the start month # (1 to 12) and day # (1 to 31) and then the finishing month # (1 to 12) and the finishing day # (1 to 31) This is a little bit of a tricky one, as you have to consider both start_month and end_month as special cases - so you need a three-part conditional, for the start month, the end month, and the months in between. Something like this: SELECT * FROM `introduction_messages` WHERE (month`start_month` AND month`end_month`) OR (month=`start_month AND day=`start_day`) OR (month=`end_month` AND day=`end_day`); Cheers! Mike -- Mike Ford, Electronic Information Developer, Libraries and Learning Innovation, Portland PD507, City Campus, Leeds Metropolitan University, Portland Way, LEEDS, LS1 3HE, United Kingdom E: m.f...@leedsmet.ac.uk T: +44 113 812 4730 To view the terms under which this email is distributed, please go to http://disclaimer.leedsmet.ac.uk/email.htm
RE: [PHP-DB] Configuring PHP with GD and JPEG support
Just tried it with the following but still fails. All I'm getting is a blank
page.
php?
function create_image()
{
//Let's generate a totally random string using md5
$md5_hash = md5(rand(0,999));
//We don't need a 32 character long string so we trim it down to 5
$security_code = substr($md5_hash, 15, 5);
//Set the session to store the security code
$_SESSION[security_code] = $security_code;
//Set the image width and height
$width = 100;
$height = 20;
//Create the image resource
$image = ImageCreate($width, $height);
//We are making three colors, white, black and gray
$white = ImageColorAllocate($image, 255, 255, 255);
$black = ImageColorAllocate($image, 0, 0, 0);
$grey = ImageColorAllocate($image, 204, 204, 204);
//Make the background black
ImageFill($image, 0, 0, $black);
//Add randomly generated string in white to the image
ImageString($image, 3, 30, 3, $security_code, $white);
//Throw in some lines to make it a little bit harder for any bots to break
ImageRectangle($image,0,0,$width-1,$height-1,$grey);
imageline($image, 0, $height/2, $width, $height/2, $grey);
imageline($image, $width/2, 0, $width/2, $height, $grey);
//Tell the browser what kind of file is come in
header(Content-Type: image/jpeg);
//Output the newly created image in jpeg format
ImageJpeg($image);
//Free up resources
ImageDestroy($image);
}
create_image();
?
From: k...@designdrumm.com
Date: Mon, 10 Jan 2011 17:10:35 -0600
To: php-db@lists.php.net
Subject: Re: [PHP-DB] Configuring PHP with GD and JPEG support
On Jan 10, 2011, at 9:35 AM, mike dorian wrote:
Hello,
Questions with regards to compiling PHP to support GD with JPEG on
64-bit CentOS 5.5.
1) Specifying folder for jpeg library
When I execute the following command, am I saying the full path to
libdir is at /usr/source/lib64?
./configure --with-apxs2=/usr/local/apache2/bin/apxs --with-gd --
with-jpeg-dir=/usr/source --with-libdir=lib64
Should I have done the following instead?
./configure --with-apxs2=/usr/local/apache2/bin/apxs --with-gd --
with-jpeg-dir=/usr/source/lib64
2) After copying the compiled JPEG libraries to the the lib64
directory, PHP is still unable to call the GD functions (ie
ImageCreateFromJpeg) properly.
Once I've done the following.
./configure --enable-shared
make
make install
I have the following files installed. Meanwhile the /usr/local/
lib64 directory doesn't have these files. Despite copying the
whole set to /usr/local/lib64, the above configure command still
doesn't work.
/usr/local/lib/libjpeg.a
/usr/local/lib/libjpeg.la
/usr/local/lib/libjpeg.so - libjpeg.so.8.0.2
/usr/local/lib/libjpeg.so.8 - libjpeg.so.8.0.2
/usr/local/lib/libjpeg.so.8.0.2
The following displays a blank page on my Firefox.
?php
header('Content-Type: image/jpeg');
$image_file_path = '/usr/local/apache2/htdocs/image.jpg';
$image_file_path;
$im = @ImageCreateFromJpeg($image_file_path);
echo $im;
imagejpeg($im);
echo End: imagedestroy($im);
?
Hi Mike,
Dont know about your server config, but maybe try using this create
image script and see.
function create_image()
{
//Let's generate a totally random string using md5
$md5_hash = md5(rand(0,999));
//We don't need a 32 character long string so we trim it down to 5
$security_code = substr($md5_hash, 15, 5);
//Set the session to store the security code
$_SESSION[security_code] = $security_code;
//Set the image width and height
$width = 100;
$height = 20;
//Create the image resource
$image = ImageCreate($width, $height);
//We are making three colors, white, black and gray
$white = ImageColorAllocate($image, 255, 255, 255);
$black = ImageColorAllocate($image, 0, 0, 0);
$grey = ImageColorAllocate($image, 204, 204, 204);
//Make the background black
ImageFill($image, 0, 0, $black);
//Add randomly generated string in white to the image
ImageString($image, 3, 30, 3, $security_code, $white);
//Throw in some lines to make it a little bit harder for any
bots to break
ImageRectangle($image,0,0,$width-1,$height-1,$grey);
imageline($image, 0, $height/2, $width, $height/2, $grey);
imageline($image, $width/2, 0, $width/2, $height, $grey);
//Tell the browser what kind of file is come in
header(Content-Type: image/jpeg);
//Output the newly created image in jpeg format
ImageJpeg($image);
//Free up resources
ImageDestroy($image);
}
Was taken from the WebCheatSheet.com - Create CAPTCHA Protection.
Namely to see how they are using the ImageJpeg, not the whole code.
But, at least you will have a code you know produces an image
[PHP-DB] Configuring PHP with GD and JPEG support
Hello,
Questions with regards to compiling PHP to support GD with JPEG on 64-bit
CentOS 5.5.
1) Specifying folder for jpeg library
When I execute the following command, am I saying the full path to libdir is at
/usr/source/lib64?
./configure --with-apxs2=/usr/local/apache2/bin/apxs --with-gd
--with-jpeg-dir=/usr/source --with-libdir=lib64
Should I have done the following instead?
./configure --with-apxs2=/usr/local/apache2/bin/apxs --with-gd
--with-jpeg-dir=/usr/source/lib64
2) After copying the compiled JPEG libraries to the the lib64 directory, PHP is
still unable to call the GD functions (ie ImageCreateFromJpeg) properly.
Once I've done the following.
./configure --enable-shared
make
make install
I have the following files installed. Meanwhile the /usr/local/lib64 directory
doesn't have these files. Despite copying the whole set to /usr/local/lib64,
the above configure command still doesn't work.
/usr/local/lib/libjpeg.a
/usr/local/lib/libjpeg.la
/usr/local/lib/libjpeg.so - libjpeg.so.8.0.2
/usr/local/lib/libjpeg.so.8 - libjpeg.so.8.0.2
/usr/local/lib/libjpeg.so.8.0.2
The following displays a blank page on my Firefox.
?php
header('Content-Type: image/jpeg');
$image_file_path = '/usr/local/apache2/htdocs/image.jpg';
$image_file_path;
$im = @ImageCreateFromJpeg($image_file_path);
echo $im;
imagejpeg($im);
echo End: imagedestroy($im);
?
RE: [PHP-DB] Re: Stuck in apostrophe hell
-Original Message- From: Simcha Younger [mailto:sim...@syounger.com] Sent: 04 August 2010 08:19 paul_s_john...@mnb.uscourts.gov wrote: THE INPUT: $sql_insert_registration = sprintf(INSERT INTO Registrations ( Class_ID, prid, Registrant, Company, Phone, Email ) VALUES ( $_POST[Class_ID], $_POST[prid], '%s',. You need double-quotes here, \%s\, No, he doesn't. Single quotes are fine. Doubles would more than likely be a SQL error. parseNull($_POST['Company'])., '$_POST[Phone]', '$_POST[Email]' ), mysql_real_escape_string($_POST['Registrant'])); -- Simcha Younger sim...@syounger.com Cheers! Mike -- Mike Ford, Electronic Information Developer, Libraries and Learning Innovation, Leeds Metropolitan University, C507 City Campus, Woodhouse Lane, LEEDS, LS1 3HE, United Kingdom Email: m.f...@leedsmet.ac.uk Tel: +44 113 812 4730 To view the terms under which this email is distributed, please go to http://disclaimer.leedsmet.ac.uk/email.htm -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] losing MySQL resource
-Original Message- From: Nehemias Duarte [mailto:ndua...@aflac.com] Sent: 11 November 2009 14:25 To: Stan; php-db@lists.php.net Subject: RE: [PHP-DB] losing MySQL resource I was under the impression that session_start() had to be the FIRST thing ran in the script. Is this incorrect? Yes. It has to be before any actual *output*, but it would be perfectly valid to have umpteen thousand lines of PHP before session_start() so long as all the output came after it. Cheers! Mike -- Mike Ford, Electronic Information Developer, Libraries and Learning Innovation, Leeds Metropolitan University, C507, Civic Quarter Campus, Woodhouse Lane, LEEDS, LS1 3HE, United Kingdom Email: m.f...@leedsmet.ac.uk Tel: +44 113 812 4730 To view the terms under which this email is distributed, please go to http://disclaimer.leedsmet.ac.uk/email.htm -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] newbie: how to return one iteration *per unique date (DAY!)* in a timestamp column?
-Original Message- From: Govinda [mailto:govinda.webdnat...@gmail.com] Sent: 05 August 2009 01:41 Taking this: SELECT count(*) AS `CountUniqueDatesInMyTbl`, date(solarAWDateTime) AS `uniqueDate`, 'aweber_7solar_aw' AS `tableAlias` FROM aweber_7solar_aw GROUP BY DATE(solarAWDateTime) Just one other tiny point of style here: having given the expression date(solarAWDateTime) the alias uniqueDate, you should probably use that alias to refer to the same thing elsewhere in your query, such as in the GROUP BY column. So: SELECT count(*) AS `CountUniqueDatesInMyTbl`, date(solarAWDateTime) AS `uniqueDate`, 'aweber_7solar_aw' AS `tableAlias` FROM aweber_7solar_aw GROUP BY `uniqueDate`; That's how I'd write it, anyway. Cheers! Mike -- Mike Ford, Electronic Information Developer, Libraries and Learning Innovation, Leeds Metropolitan University, C507, Civic Quarter Campus, Woodhouse Lane, LEEDS, LS1 3HE, United Kingdom Email: m.f...@leedsmet.ac.uk Tel: +44 113 812 4730 To view the terms under which this email is distributed, please go to http://disclaimer.leedsmet.ac.uk/email.htm -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] Postgres query failing, not enough info for debugging...
On 16 June 2009 15:57, Carol Walter advised:
Hello,
I'm using PHP 5 and PostgreSQL 8.3.6. I have a query that is failing
and I don't know how to troubleshoot the problem. The error message
that it is giving is quite vague. The error message is as follows:
Warning: pg_query_params() [function.pg-query-params]: Query failed:
ERROR: syntax error at end of input at character 156 in /home/walterc/
ssl/PHP/km_input_test2c.php on line 631
ERROR: syntax error at end of input at character 156
The query that is failing looks like this...
$pg_pres_ins6 = pg_query_params(INSERT INTO \brdgMediaCallsEvents
\ (\mediumId\, \eventId\, rank) VALUES
((currval('\tblMedia_mediumId_seq\'),
(currval('\tblCallsEvents_eventId_seq\'), $1), array($ev_rank));
echo pg_last_error($pg_connection);
You have 2 more opening parentheses than close parentheses in that SQL
-- in both cases, the parenthesis immediately preceding currval should
be omitted.
Also, to ameliorate your quote hell, you might consider using a heredoc
(http://php.net/manual/language.types.string.php#language.types.string.s
yntax.heredoc) for this:
$pg_pres_ins6 = pg_query_params(SQL
INSERT INTO brdgMediaCallsEvents (mediumId, eventId, rank)
VALUES (currval('tblMedia_mediumId_seq'),
currval('tblCallsEvents_eventId_seq'), $1)
SQL
, array($ev_rank));
Cheers!
Mike
--
Mike Ford, Electronic Information Developer,
C507, Leeds Metropolitan University, Civic Quarter Campus,
Woodhouse Lane, LEEDS, LS1 3HE, United Kingdom
Email: m.f...@leedsmet.ac.uk
Tel: +44 113 812 4730
To view the terms under which this email is distributed, please go to
http://disclaimer.leedsmet.ac.uk/email.htm
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RE: [PHP-DB] Re: PHP and table/view names with '$'
On 23 April 2009 11:36, Mark Casson advised: Hi Guys, Thanks to you both - you are spot on! Shame this is not better documented somewhere. I don't know how much better documented it can be than at http://php.net/language.types.string ... ;) Cheers! Mike -- Mike Ford, Electronic Information Developer, C507, Leeds Metropolitan University, Civic Quarter Campus, Woodhouse Lane, LEEDS, LS1 3HE, United Kingdom Email: m.f...@leedsmet.ac.uk Tel: +44 113 812 4730 To view the terms under which this email is distributed, please go to http://disclaimer.leedsmet.ac.uk/email.htm -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Building WHERE SQL clauses
Chris [EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]
Mike Sullivan wrote:
Hi all thanks for the responses! What I have is a 6 table db that has
each
table created from the output of 6 identical laboratory machines (chico,
harpo, ...). The out put is a text file which I import as a table named
after the machine. I do realize that one solution is to add the machine
name as a attribute and concatenate the tables together. I'm going to
weigh
that change against Bastien's suggestion of UNIONing the selects.
I must admit that I'm still rather weak in the SQL department and did try
a
solution of:
SELECT * FROM (chico UNION harpo) WHERE operator = Bill OR operator =
Jessica but that apparently is a SQL syntax error.
Thanks again for the insight and any other suggestions you might
have. --- Mike
A UNION combines the results from query 1 and query 2 together.
For example:
select * from chico where operator in ('Bill', 'Jessica')
union
select * from harpo in ('Bill', 'Jessica')
will:
- get all rows from the chico table where the operator is Bill or Jessica
- get all rows from the harpo table where the operator is Bill or Jessica
- remove duplicate results
- return the results
A UNION ALL will skip the 'remove duplicates' step:
- get all rows from the chico table where the operator is Bill or Jessica
- get all rows from the harpo table where the operator is Bill or Jessica
- return the results
If query 1 AND query 2 don't return the results you want, then a union
is the wrong type of query to run.
http://dev.mysql.com/doc/refman/5.0/en/union.html
I'm confused about what you're trying to get out of the results, can you
explain further and give an example of the data you have, and the result
you want to return?
--
Postgresql php tutorials
http://www.designmagick.com/
From what I've experimented around with from the suggestions gathered here,
a union is what I want. and had tried that but using table names as the
parameters to UNION not the results of query's as you show above. I've got
a prototype like this now working but I've pretty much decided to go back
and redo the java program that parses the text files and builds the
LOAD-able files so that it adds a machine name attribute and concatenates
the data in one file.
--- Mike
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Re: [PHP-DB] Building WHERE SQL clauses
Hi all thanks for the responses! What I have is a 6 table db that has each
table created from the output of 6 identical laboratory machines (chico,
harpo, ...). The out put is a text file which I import as a table named
after the machine. I do realize that one solution is to add the machine
name as a attribute and concatenate the tables together. I'm going to weigh
that change against Bastien's suggestion of UNIONing the selects.
I must admit that I'm still rather weak in the SQL department and did try a
solution of:
SELECT * FROM (chico UNION harpo) WHERE operator = Bill OR operator =
Jessica but that apparently is a SQL syntax error.
Thanks again for the insight and any other suggestions you might have. ---
Mike
Bastien Koert [EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]
On Mon, Sep 15, 2008 at 1:33 PM, Stephen Wellington
[EMAIL PROTECTED] wrote:
You probably want something like this:
SELECT * FROM chico as c, harpo as h WHERE c.operator = Bill OR
c.operator =
Jessica OR h.operator = Bill OR h.operator =Jessica
However if those tables really are identical I would suggest having a
good look at your
database design to see if it can be normalised or something...
Stephen Wellington
On Mon, Sep 15, 2008 at 4:06 PM, Mike Sullivan [EMAIL PROTECTED] wrote:
Hello all. I'm using PHP to build a query for a database that consists
of
multiple tables, all with identical attribues. A typical syntax try
looks
like this: SELECT * FROM chico, harpo WHERE operator = Bill OR
operator =
Jessica
MySQL responds with this: Couldn't execute query.Column 'operator' in
where
clause is ambiguous
I was hoping that since the tables are identical all I would need to do
is
list the attribute values not have to append them to the table names.
Is
there any way to do this? Perhaps with a setting in MySQL or a
different
syntax (JOIN, UNION, ...)? If not are there available some canned code
snippets that build these types of strings from values passed in the
$_POST
array. Thanks for any insights on this. --- Mike
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if the structures and fields are truly the same you can UNION the queries
select * from chico where operator in('Jessica','William')
union
select * from harpo where operator in('Jessica','William')
But as suggested, if they are truly similar, the db needs to be looked for
design
--
Bastien
Cat, the other other white meat
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[PHP-DB] Building WHERE SQL clauses
Hello all. I'm using PHP to build a query for a database that consists of multiple tables, all with identical attribues. A typical syntax try looks like this: SELECT * FROM chico, harpo WHERE operator = Bill OR operator = Jessica MySQL responds with this: Couldn't execute query.Column 'operator' in where clause is ambiguous I was hoping that since the tables are identical all I would need to do is list the attribute values not have to append them to the table names. Is there any way to do this? Perhaps with a setting in MySQL or a different syntax (JOIN, UNION, ...)? If not are there available some canned code snippets that build these types of strings from values passed in the $_POST array. Thanks for any insights on this. --- Mike -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] ? SELECT TABLE Command
Chris wrote (in news:[EMAIL PROTECTED]):
It is an SQL query (probably MySQL, but perhaps SQLite or possibly even
PGSQL or mSQL):
The line after $query should tell you what uses it ;)
Sorry, I meant the book may have been about any of those; I was skimming through
a bunch of SQL books at that time and dont know which one I got it from.
$query=SELECT TABLE $tablename;;
if (mysql_query($query, $link)) {
echo($indent.The table, '$tablename', was successfully opened.br
/\n); }
To make things even stranger, it works fine in the original program that I
put it in (although what, if anything, it does is beyond me), but fails
when I try it in another program (yes, I took care of $tablename).
What's the exact query that's run? Maybe $tablename contains more than just a
table name.
Nope, its just
SELECT TABLE lyrics;
Different mysql version? Maybe it was in an older version of mysql but they
removed it.
It doesn't work in mysql5 or mysql4.0, maybe it does in an older version
though.
Looks like you're trying to check that the mysql user you connected as has
access to that table.
It really feels like a command I may have used in the SQLite analyzer or
something. However, Im sure I copied it from an example script in a book. I
ve put holds on all the books on PHP and (My)SQL at the library and will check
them all.
--
Mike W.
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Re: [PHP-DB] date problems
It's much better to use add_date instead of to_days since mysql isn't smart enough to do it for you. Such as: SELECT yourEventFields FROM theTable WHERE theEventDate BETWEEN now() AND date_add(now(), INTERVAL 21 DAYS; This way mysql will calc the now() and date_add and will essentially convert them to static values. If there's an index on theEventDate it will be used. Mike... Instruct ICC wrote: From: rDubya [EMAIL PROTECTED] My problem is that I have events dated for Sep 2007 and on, and yet they all come up as being on Dec 7 to 9, 2006.. any ideas? rDubya How about having MySQL only return the events you are interested in? SELECT yourEventFields FROM theTable WHERE TO_DAYS( theEventDate ) = TO_DAYS( NOW() ) AND TO_DAYS( theEventDate ) = TO_DAYS( NOW() ) + 21 I like theEventDate to be in the format -MM-DD http://dev.mysql.com/doc/refman/5.0/en/date-and-time-functions.html#function_to-days _ A place for moms to take a break! http://www.reallivemoms.com?ocid=TXT_TAGHMloc=us -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] date problems
Argh, make sure you add the closing paren for the date_add since I forgot it. Mike... Mike Gohlke wrote: It's much better to use add_date instead of to_days since mysql isn't smart enough to do it for you. Such as: SELECT yourEventFields FROM theTable WHERE theEventDate BETWEEN now() AND date_add(now(), INTERVAL 21 DAYS; This way mysql will calc the now() and date_add and will essentially convert them to static values. If there's an index on theEventDate it will be used. Mike... Instruct ICC wrote: From: rDubya [EMAIL PROTECTED] My problem is that I have events dated for Sep 2007 and on, and yet they all come up as being on Dec 7 to 9, 2006.. any ideas? rDubya How about having MySQL only return the events you are interested in? SELECT yourEventFields FROM theTable WHERE TO_DAYS( theEventDate ) = TO_DAYS( NOW() ) AND TO_DAYS( theEventDate ) = TO_DAYS( NOW() ) + 21 I like theEventDate to be in the format -MM-DD http://dev.mysql.com/doc/refman/5.0/en/date-and-time-functions.html#function_to-days _ A place for moms to take a break! http://www.reallivemoms.com?ocid=TXT_TAGHMloc=us -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] Re: [PHP] Re: [PHP-DB] Re: [PHP] Passing variables to a PHP script on clicking a hyperlink
On 8/26/07, Richard Lynch [EMAIL PROTECTED] wrote: This is *SO* not correct at all! $_REQUEST[] is merely array_merge($_GET, $_POST, $_COOKIE); Yes and it mimics being lazy - allowing overriding values from $_POST vs. $_GET vs. $_COOKIE depending on what the programmer wants to trust It encourages poor practices. There is no reason to not name the proper source of data - i.e. i want it from POST not GET It is *NOT* in any way, shape, or form, polluting the global namespace of all your variables, which is what register_globals is. That is why I said it was *one* reason register_globals was disabled - global namespace was probably the biggest reason, but also variable overriding and sloppyness allowing for exploits was probably up there too. There could easily be a script written which is expected to respond to GET or POST data in the same way, particularly a simplistic web-service that doesn't really care if the web Designers prefer to have buttons or links or CSS links that look like buttons or CSS buttons that look like links or rabid squirrels that send the GET and/or POST data to make the HTTP request. Yes, there could. But part of that would rely on a *very* motivated end-user (or we'll call them hacker) - they would probably find a way in or do what they want either way. There's no reason to make it easier just because well they can hack something up to do that anyway - that's a Microsoft approach to security. Whatever happened to people at least trying to discourage abuse or issues. I have never used $_REQUEST and my applications don't seem to have any issues. Obviously someone could have tried to switch POST/GET on me, but I still ensure proper bounds checking/sanity checking/type checking/etc. But I would not allow someone to issue a GET variable to override a cookie value without having to make the extra effort (and furthermore understand how the variables work on the server side to make it actually work how they want.) Use $_POST when you expect the data to always be in POST data. correct. Use $_GET when you expect the data to alwasy be in GET data. correct. If you actually want to accept HTTP requests of either kind for flexibility to an external user, by all means use REQUEST. In my opinion a properly coded web application shouldn't be lazy and should know the source of data. So I consider this incorrect. -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] Re: [PHP] Re: [PHP-DB] Re: [PHP] Passing variables to a PHP script on clicking a hyperlink
I'll say it again: regsiter_globals has *NOTHING* to do with $_REQUEST. Zero. Zilch. Nada. Zip. To me it allows for the same [lazy] behavior. Period. I've had other people agree. Say what you want about it. No, it only relies on one Designer who wants their request to look like a FORM and another Designer who wants their request to look like a link. I've never had to write an app where I allow GET and POST. Either way can be created using a form, a button, a link, etc. Pick one and stick with it. And I don't really *CARE* if the search terms (or whatever input it its) comes from GET versus POST as there is NO Security difference whatsoever. They need equal filtration. Agreed The point is that GET and/or POST are equally tainted data, and that I wish to provide the same services to either kind of request, and there is NO DIFFERENCE between them for this service. I disagree with that approach to a web application. You're still not getting the point. No, I get it. I was too vague in my original message. To me newbies picked up PHP easily because hey, this query string variable is $foo just like when I do a post variable of $foo! and $_REQUEST to them is their way to get around a register_globals = off installation. I've seen it many times with people just learning PHP. I associate the use of $_REQUEST with people new to PHP, because I've seen it many times. Also when told about $_GET, $_POST, $_COOKIE, etc... they realized how much cleaner that is and adjust appropriately. There *ARE* valid reasons for allowing GET and POST to be used inter-changably. Consider a stupid simple web service that lets you look up Longitude, Latitude by zip code from their own website. Do you really CARE if they use a link or a form to REQUEST the long/lat with the zip input? No. You don't. You're right - I don't. But I tell them to use GET or POST and they prepare their client-side code appropriately. Both ways can be done. I don't make my applications lazy and then allow two interfaces to them when one is perfectly fine and allows for one consistent interaction method. But please do NOT spread mis-information that using $_REQUEST un-does what turning register_globals off does. Because that is simply not factually correct, no matter how you feel about $_REQUEST. Eh, you call it mis-information. I call it advising on how to code a tighter web application. -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] Re: [PHP] Passing variables to a PHP script on clicking a hyperlink
On 8/23/07, Suamya Srivastava [EMAIL PROTECTED] wrote: Hello, How can I pass variables on clicking a hyperlink to a PHP script? I have 5 hyperlinks, all pointing to the same PHP script. However, on clicking each hyperlink a different value of the variable needs to be passed to the PHP script. i.e. I have 5 databases from which I want to obtain information, however the information should be displayed only when the user clicks on the hyperlink for that database. How can I pass the database name to the PHP script? How would the script know which database to get information from? I am new to PHP so any help would be greatly appreciated. I hope my question is clear. use GET foo.php?param=value or you could use POST by using some client-side javascript to do a form submit with key/value pairs. this is a *very* simple operation... all web-enabled languages understand HTTP POST/GET/etc. - those are the main ways of exchanging data between client/server. -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Re: [PHP] Passing variables to a PHP script on clicking a hyperlink
On 8/24/07, Goltsios Theodore [EMAIL PROTECTED] wrote: the posted or got option buy using the $_REQUEST array ($_GET and $_POST are included in that like a less lame solution). Let's say you have a Please do not encourage the use of $_REQUEST. You might as well just tell people to enable register_globals again. Use $_GET, $_POST, $_SESSION, $_COOKIE, $_SERVER, etc. for the appropriate source of data. $_REQUEST is laziness and introduces most of the same issues that was the reasoning behind disabling register_globals to begin with. (As for dropdowns, that's just an in-browser method of collecting data and sending the key/value pairs in POST or GET... IMHO the HTML portion should already be known before someone steps into the realm of PHP and server-side programming) - mike -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] Re: [PHP] Re: [PHP-DB] Re: [PHP] Passing variables to a PHP script on clicking a hyperlink
On 8/24/07, Suamya Srivastava [EMAIL PROTECTED] wrote: Hi.. in the settings, session.use_cookies is turned ON but session.trans_sid is turned OFF. do i need to enable this as well? by doing this can i disable the register_globals? - suamya You need to make sure session_start() is called on all pages to be able to read/write the session data. This is probably the case. I have never needed to use trans_sid. It introduces some complexities that I don't think are needed. $_REQUEST is basically a new way of doing register_globals, which is a security issue. register_globals can allow a savvy user to overwrite a variable with another source - say you wanted a POST variable, a user could supply GET instead. or if you want it to come from a cookie using $_COOKIE it could be overridden using GET. If that makes sense. There's a lot of information about it. It was disabled by default a while back. Never enable it. You do not need it, period. Anyone telling you to enable it or reading somewhere you need to enable it is *absolutely* incorrect. -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Read more link with HTML code
Hello: EG: iThe community of Gbongay, Sierra Leone, suffered greatly after the country's civil war, and had aspirations of starting a beekeeping operation to improve their situation. That's when they turned to NABUUR for assistance. But with Neighbours living all over the world and a Facilitator with no knowledge of bees, could this dream ever become a reality?/ibr /br /bThe challenge/bbr /Gbongay, a rural village situated in southeast Sierra Leone, lost everything after the civil war -- the school and hospital were destroyed, and its inhabitants no longer had access to safe water. To try to overcome this tragedy, the community decided it needed to raise money, which could be used to create a small, sustainable business.br /br /Beekeeping seemed to be a promising option, since it required only a small investment and had the potential for a high return -- and the proof was in the neighbouring village, which already had a successful honey business.br /br /bA real leader/bbr /What really got this project started was the project's Facilitator, Raul Alberto Caceres. Born in Colombia, Raul moved to Australia for a post-graduate programme. He now works as a chemical engineerbr /in the food industry and recently joined NABUUR.br /br /As the leader of the beekeeping project, Raul designed a detailed plan. He knew they needed to research as much as possible about starting and running a beekeeping operation, and that the assistance of thebr /Neighbours was going to be essential.br /br /The Neighbours -- from more than ten countries -- were involved at different stages of the project depending on their expertise. Somebr /volunteers helped with general tasks, like Internet research, letter writing and contacting organisations for information, while others helped with more specific assignments that pertained to beekeepingbr /itself.br /br /bQuick success/bbr /Gbongay's beekeeping operation progressed quickly -- and it couldn't have been done without Raul's impressive leadership abilities. He showed enthusiasm on the website and was able to mobilisebr /volunteers all over the world, including Turkey, Ghana, Canada and the Netherlands. Because NABUUR volunteers often never have the chance to meet in person, it's essential that a project's Facilitator be an organised and enthusiastic leader. Fortunately for the community of Gbongay, Raul was just that!br /br /bBeekeeping today/bbr /img src=http://www.nabuur.com/uploads/img_4512900141172.jpg; align=right hspace=15 alt= /The beekeeping operation in Gbongay has further expanded and now includes a beekeeping school. After some research, the Neighbours and local community decided this would be a great way tobr /ensure the future of the beekeeping business. In March 2006, everyone began work on the school.br /br /Today, things are looking better for the village of Gbongay. The community's first water pump has been installed, the first 35 beekeepers have graduated from the new school -- and, best of all,br /the first customers are buying honey!br /br /bBonus/bbr /Gbongay has been rewarded by nature. It wasbr /given the local bee, which is extremely prolific, anbr /abundance of bee flora and a favourable climatebr /for beekeeping -- making this initiative a lucrativebr /one.br /br /Mariama Fawundu, Local Representativebr /br / With kind regards Mike Medusa, Media Usage Advice B.V. Science Park Eindhoven 5216 5692 EG SON tel: 040-24 57 024 fax: 040-29 63 567 url: www.medusa.nl mail: [EMAIL PROTECTED] Uw bedrijf voor Multimedia op Maat Rafael Costa Pimenta schreef: could you show some example? 2007/5/7, Mike van Hoof [EMAIL PROTECTED] mailto:[EMAIL PROTECTED]: Hello list, I got a problem with displaying content in a read more block which contains HTML code. The problem is as followes: I got a large piece of content, which contains HTML code (bui etc), but after 200 characters a read more link appears. At the moment I strip al the HTML out of this piece of content, and display the full set off content on another page. But now i also want to display the bold text etc. in the first (200 chrs) content block. The only problem i have here, is that when I got a bold tag opend in the first 200 chrs, and it's closed after 400 chrs, then the rest off the page is also bold. somebody got a solution ? Thanks for reading. Mike -- Medusa, Media Usage Advice B.V. Science Park Eindhoven 5216 5692 EG SON tel: 040-24 57 024 fax: 040-29 63 567 url: www.medusa.nl http://www.medusa.nl mail: [EMAIL PROTECTED] mailto:[EMAIL PROTECTED] Uw bedrijf voor Multimedia op Maat -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- Atenciosamente, Rafael C. Pimenta Programador - CTT Integration Group
Re: [PHP-DB] Re: Read more link with HTML code
Hey, a client can type anything in the field, so all kind of HTML tags can be inserted... - Mike Medusa, Media Usage Advice B.V. Science Park Eindhoven 5216 5692 EG SON tel: 040-24 57 024 fax: 040-29 63 567 url: www.medusa.nl mail: [EMAIL PROTECTED] Uw bedrijf voor Multimedia op Maat bedul schreef: i prefer u use the prefix.. but it very advance.. can u spesific more.. client able to type what tag (u must consider lock other than what u type earlier) anyway.. using a table is a good idea.. actualy if your client type using table.. what should u do?? - Original Message - From: itoctopus [EMAIL PROTECTED] To: php-db@lists.php.net Sent: Tuesday, May 08, 2007 7:26 AM Subject: [PHP-DB] Re: Read more link with HTML code Put your 200 characters in a table block: table tr td Your 200 characters /td /tr /table -- itoctopus - http://www.itoctopus.com Mike van Hoof [EMAIL PROTECTED] wrote in message news:[EMAIL PROTECTED] Hello list, I got a problem with displaying content in a read more block which contains HTML code. The problem is as followes: I got a large piece of content, which contains HTML code (bui etc), but after 200 characters a read more link appears. At the moment I strip al the HTML out of this piece of content, and display the full set off content on another page. But now i also want to display the bold text etc. in the first (200 chrs) content block. The only problem i have here, is that when I got a bold tag opend in the first 200 chrs, and it's closed after 400 chrs, then the rest off the page is also bold. somebody got a solution ? Thanks for reading. Mike -- Medusa, Media Usage Advice B.V. Science Park Eindhoven 5216 5692 EG SON tel: 040-24 57 024 fax: 040-29 63 567 url: www.medusa.nl mail: [EMAIL PROTECTED] Uw bedrijf voor Multimedia op Maat -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Read more link with HTML code
Hey,
thanks for the help everyone, but after reading all the answers i
decided to do some regexp thingies. Came up with this:
function readMore_closedtags($text, $length) {
preg_match_all('/(.*?)/s',substr(stripslashes($text), 0,
$length),$out);
foreach($out[1] as $key2 = $val2){
if(
!preg_match(/br.*/, $val2)
!empty($val2)
){
$val2_arr = explode( , $val2);
$val2 = $val2_arr[0];
if(preg_match(/^\//, $val2))
$html_arr_close[] = strtolower($val2);
else
$html_arr_open[] = strtolower($val2);
}
}
$not_closed_tags = array();
foreach($html_arr_open as $tag){
$key = array_search(/ . $tag, $html_arr_close);
if($key !== false){
unset($html_arr_close[$key]);
} else {
$not_closed_tags[] = $tag;
}
}
$closed_tags_str = '';
foreach($not_closed_tags as $tag){
$closed_tags_str .= / . $tag . ;
}
return $closed_tags_str;
}
Mike
Medusa, Media Usage Advice B.V.
Science Park Eindhoven 5216
5692 EG SON
tel: 040-24 57 024
fax: 040-29 63 567
url: www.medusa.nl
mail: [EMAIL PROTECTED]
Uw bedrijf voor Multimedia op Maat
Mike van Hoof schreef:
Hello:
EG:
iThe community of Gbongay, Sierra Leone, suffered greatly after the
country's civil war, and had aspirations of starting a beekeeping
operation to improve their situation. That's when they turned to
NABUUR for assistance. But with Neighbours living all over the world
and a Facilitator with no knowledge of bees, could this dream ever
become a reality?/ibr /br /bThe challenge/bbr /Gbongay, a
rural village situated in southeast Sierra Leone, lost everything
after the civil war -- the school and hospital were destroyed, and its
inhabitants no longer had access to safe water. To try to overcome
this tragedy, the community decided it needed to raise money, which
could be used to create a small, sustainable business.br /br
/Beekeeping seemed to be a promising option, since it required only a
small investment and had the potential for a high return -- and the
proof was in the neighbouring village, which already had a successful
honey business.br /br /bA real leader/bbr /What really got
this project started was the project's Facilitator, Raul Alberto
Caceres. Born in Colombia, Raul moved to Australia for a post-graduate
programme. He now works as a chemical engineerbr /in the food
industry and recently joined NABUUR.br /br /As the leader of the
beekeeping project, Raul designed a detailed plan. He knew they needed
to research as much as possible about starting and running a
beekeeping operation, and that the assistance of thebr /Neighbours
was going to be essential.br /br /The Neighbours -- from more than
ten countries -- were involved at different stages of the project
depending on their expertise. Somebr /volunteers helped with general
tasks, like Internet research, letter writing and contacting
organisations for information, while others helped with more specific
assignments that pertained to beekeepingbr /itself.br /br
/bQuick success/bbr /Gbongay's beekeeping operation progressed
quickly -- and it couldn't have been done without Raul's impressive
leadership abilities. He showed enthusiasm on the website and was able
to mobilisebr /volunteers all over the world, including Turkey,
Ghana, Canada and the Netherlands. Because NABUUR volunteers often
never have the chance to meet in person, it's essential that a
project's Facilitator be an organised and enthusiastic leader.
Fortunately for the community of Gbongay, Raul was just that!br /br
/bBeekeeping today/bbr /img
src=http://www.nabuur.com/uploads/img_4512900141172.jpg;
align=right hspace=15 alt= /The beekeeping operation in Gbongay
has further expanded and now includes a beekeeping school. After some
research, the Neighbours and local community decided this would be a
great way tobr /ensure the future of the beekeeping business. In
March 2006, everyone began work on the school.br /br /Today,
things are looking better for the village of Gbongay. The community's
first water pump has been installed, the first 35 beekeepers have
graduated from the new school -- and, best of all,br /the first
customers are buying honey!br /br /bBonus/bbr /Gbongay has
been rewarded by nature. It wasbr /given the local bee, which is
extremely prolific, anbr /abundance of bee flora and a favourable
climatebr /for beekeeping -- making this initiative a lucrativebr
/one.br /br /Mariama Fawundu, Local Representativebr /br /
With kind regards
Mike
Medusa, Media Usage Advice B.V.
Science Park Eindhoven 5216
5692 EG SON
tel: 040-24 57 024 fax: 040-29 63 567
url: www.medusa.nl
mail: [EMAIL PROTECTED]
Uw bedrijf voor Multimedia op Maat
Rafael Costa Pimenta
[PHP-DB] Read more link with HTML code
Hello list, I got a problem with displaying content in a read more block which contains HTML code. The problem is as followes: I got a large piece of content, which contains HTML code (bui etc), but after 200 characters a read more link appears. At the moment I strip al the HTML out of this piece of content, and display the full set off content on another page. But now i also want to display the bold text etc. in the first (200 chrs) content block. The only problem i have here, is that when I got a bold tag opend in the first 200 chrs, and it's closed after 400 chrs, then the rest off the page is also bold. somebody got a solution ? Thanks for reading. Mike -- Medusa, Media Usage Advice B.V. Science Park Eindhoven 5216 5692 EG SON tel: 040-24 57 024 fax: 040-29 63 567 url: www.medusa.nl mail: [EMAIL PROTECTED] Uw bedrijf voor Multimedia op Maat -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] variable with NULL value
On 03 May 2007 16:22, OKi98 wrote: Hi, one more question. Why the variable, that contains NULL value appears to be not set. U -- because that's how it's defined?? (http://php.net/isset) Cheers! Mike - Mike Ford, Electronic Information Services Adviser, JG125, The Headingley Library, James Graham Building, Leeds Metropolitan University, Headingley Campus, LEEDS, LS6 3QS, United Kingdom Email: [EMAIL PROTECTED] Tel: +44 113 812 4730 Fax: +44 113 812 3211 To view the terms under which this email is distributed, please go to http://disclaimer.leedsmet.ac.uk/email.htm
Re: [PHP-DB] weird comparsion
http://nl3.php.net/manual/en/language.operators.comparison.php try using === (3x =) for comparison - Mike OKi98 schreef: Hello, Why does anything compared to 0 return true? I know it might seem to be a bit off-topic, but for me it is important for detecting if NULL value in table has been changed (for example NULL is changed to 0). if (foo==0) echo(foo equals to 0); OKi98 -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] weird comparsion
On 03 May 2007 12:30, OKi98 wrote: I know about identity operator (===) but with == operator 0 is false and foo is true No, that's not correct. , try this: $foo=0; $bar=bar; if ($foo) echo($foo is true, ); else echo($foo is false, ); if ($bar) echo($bar is true, ); else echo($bar is false, ); if ($foo==$bar) echo($foo==$bar); returns 0 is false, bar is true, 0==$bar That's because you've got loads of implicit type conversions going on there, so you're not comparing like with like. For if ($foo) ... and if ($bar) ...: within the context of the if(), both $foo and $bar are implicitly converted to Boolean: - (bool)0 is FALSE - (bool)any non-empty() string is TRUE On the other hand, for if ($foo==$bar) ...: in the context of the == comparison, $bar is converted to a number, and any string not beginning with a numeric character converts to numeric zero -- so you get a comparison of zero with zero, which is, of course, TRUE! Or, in other words, (bool)$foo!==(bool)$bar, BUT (int)$foo===(int)$bar It's exactly when you *don't* want this kind of automatic type-conversion shenanigans going on that you should use the === operator to make your intent entirely clear -- otherwise you have to be extremely aware of the context in which you are evaluating your variables in order to avoid hidden surprises like this. Cheers! Mike - Mike Ford, Electronic Information Services Adviser, JG125, The Headingley Library, James Graham Building, Leeds Metropolitan University, Headingley Campus, LEEDS, LS6 3QS, United Kingdom Email: [EMAIL PROTECTED] Tel: +44 113 812 4730 Fax: +44 113 812 3211 To view the terms under which this email is distributed, please go to http://disclaimer.leedsmet.ac.uk/email.htm
Re: [PHP-DB] PHP_AUTH_USER .htaccess
This must be set on On, because in a directory where the .htaccess file doesn't exist it works, or can that setting also be set to on? - Mike bedul schreef: - Original Message - From: Mike van Hoof [EMAIL PROTECTED] To: php-db@lists.php.net Sent: Tuesday, March 06, 2007 3:02 PM Subject: [PHP-DB] PHP_AUTH_USER .htaccess Hello, I've got a really strange problem, and hope this is the right list to post to. I got a website with a login, which uses a .htaccess file for autentication. That part works like a charm. But when i want to read the loggin details with PHP, the variable $_SERVER['|PHP_AUTH_USER'] isn't set (in the directory where i logged into) when i go a directory back, and view a phpinfo() there i see |$_SERVER['|PHP_AUTH_USER']|| is set, so i do a phpinfo() in the directory with the .htaccess and it is gone. Had anyone ever had experience with this, because i can't find a solution. - Mike| i do believe this can only be answer by your webadmin.. since this might not your local but using web right?? try ask to them are the php_auth_user is set ON
[PHP-DB] Re: SQL Query - Using variable from another SQL Query
I think you don't need to break this into two queries... this is really a SQL
question,
not a PHP question...
Just do a join on the two tables:
* where table1.cal_id = table2.cal_id
and then have a where clause that does all your filtering:
* and table1.Date now() and table2.cal_category='501'
Using SQL instead of code is almost always the right thing to do. Learning how
to
do more sophisticated queries will pay off big time in the long run... and good
tutorials are widely and freely available...
From: Matthew Ferry [EMAIL PROTECTED]
To: php-db@lists.php.net
Date sent: Mon, 12 Feb 2007 11:14:32 -0500
Subject:SQL Query - Using variable from another SQL Query
Hello Everyone
Got a simple / stupid question.
Worked on this all night. I'm over looking something very basic here.
The query event_time brings back the calendar id for each event that is
pending in the future.
ie 12, 13, 14, 26 (There could be 100 of them out there)
The second query events needs to meet both reqirements.
1 - cal_category='501'
2 - cal_id= a number from the event_time query
I think i need to do a loop inside of a loop
Thanks...
Matt
Here is my code:
?php
$todays_year = date(Y);
$todays_month = date(m);
$todays_day = date(d);
$tstamp = mktime(0, 0, 0, $todays_month, $todays_day, $todays_year);
$event_time = mysql_query(SELECT cal_id FROM egw_cal_dates where cal_start
$tstamp, $db);
$events = mysql_query(SELECT * FROM egw_cal WHERE cal_category='501' and
cal_id='$event_time'\n, $db);
if ($event = mysql_fetch_array($events)) {
echo center\n;
echo HR\n;
do {
echo BFont
Size='10'$event[cal_title]nbsp;nbsp;nbsp;nbsp;-nbsp;nbsp;nbsp;$event[cal_location]/B/Font\n;
echo BR\n;
echo $event[cal_description];
echo BR\n;
echo HR\n;
} while ($event = mysql_fetch_array($events));
} else {
echo No Public Events Are Currently Scheduled...;
}
?
[PHP-DB] MYSQL REGEXP question
Hello, i am try to make a regular expression work, but keep getting an error message does anyone know how i can make it work? The query is: SELECT 'boer bv' REGEXP '[ b|^b](?![v$|v ])'; So it has to match each starting 'b' and all the b's pf following words. But now followed by a v(line end) or a v followed by a space. so it should match: 'b test' 'test b' 'test b bv' 'bv b test' and NOT 'test bv' 'bv test' Any idea's?! Thanks, mike -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php ** IMPORTANT NOTICE This communication is for the exclusive use of the intended recipient(s) named above. If you receive this communication in error, you should notify the sender by e-mail or by telephone (+44) 191 224 4461, delete it and destroy any copies of it. This communication may contain confidential information and material protected by copyright, design right or other intellectual property rights which are and shall remain the property of Piranha Studios Limited. Any form of distribution, copying or other unauthorised use of this communication or the information in it is strictly prohibited. Piranha Studios Limited asserts its rights in this communication and the information in it and reserves the right to take action against anyone who misuses it or the information in it. Piranha Studios Limited cannot accept any liability sustained as a result of software viruses and would recommend that you carry out your own virus checks before opening any attachment. GWAVAsigAdmID:FB05127CFE0569CA76887DED108E0F2F ** IMPORTANT NOTICE This communication is for the exclusive use of the intended recipient(s) named above. If you receive this communication in error, you should notify the sender by e-mail or by telephone (+44) 191 224 4461, delete it and destroy any copies of it. This communication may contain confidential information and material protected by copyright, design right or other intellectual property rights which are and shall remain the property of Piranha Studios Limited. Any form of distribution, copying or other unauthorised use of this communication or the information in it is strictly prohibited. Piranha Studios Limited asserts its rights in this communication and the information in it and reserves the right to take action against anyone who misuses it or the information in it. Piranha Studios Limited cannot accept any liability sustained as a result of software viruses and would recommend that you carry out your own virus checks before opening any attachment. GWAVAsig -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] MYSQL REGEXP question
Hello, i am try to make a regular expression work, but keep getting an error message does anyone know how i can make it work? The query is: SELECT 'boer bv' REGEXP '[ b|^b](?![v$|v ])'; So it has to match each starting 'b' and all the b's pf following words. But now followed by a v(line end) or a v followed by a space. so it should match: 'b test' 'test b' 'test b bv' 'bv b test' and NOT 'test bv' 'bv test' Any idea's?! Thanks, mike -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] detecting negative numbers
On 17 July 2006 01:07, Dave W wrote: No, I get it. I just thought that there might have been some built in function like if(neg_num($quant - $amount)) or something like that. I know how to do it, but I thought that there might have been an alternate method. Just because I asked a simple question doesn't mean I'm stupid, I'm just curious if there is a simpler way to do an already simple task. The absolute simplest way to do this is what you originally had. I would not look further than if ($quant$amount) // $quant-$amount is negative If I were reading your code, I would find both if(($quant-$amount)0) and if(neg_num($quant-$amount)) more obfuscating than if($quant$amount). Cheers! Mike - Mike Ford, Electronic Information Services Adviser, Learning Support Services, Learning Information Services, JG125, James Graham Building, Leeds Metropolitan University, Headingley Campus, LEEDS, LS6 3QS, United Kingdom Email: [EMAIL PROTECTED] Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211 To view the terms under which this email is distributed, please go to http://disclaimer.leedsmet.ac.uk/email.htm -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] Need Help Compiling PHP5 With MS SQL Support
I am new to Linux and have NEVER compiled PHP. I have PHP 5 and need to compile it with MS SQL support. Per PHP docs, I installed FreeTDS and tested it and it works. Now I need to (re)compile PHP to get the support I need to access MS SQL databases. I am on a Ubuntu 6.06 version of Linux. Again, PLEASE keep in mind that I am new to all of this. I tread VERY softly doing this! (I am on a VMWare virtual server and have made a clone drive as a backup.) Am I correct that my first step is to see what is already compiled into my version of PHP using php -m? I have that list. I assume that my next step is to get the PHP source for PHP 5.1.4. From here on I do not understand clearly by reading the docs I have searched for on the Internet through Google. Is there a place that has a VERY clear, step by step process to compile PHP? Any and all help is GREATLY appreciated. TIA. Mike -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] PHPSESSID how to append and access
On 25 May 2006 12:12, Girish Agarwal wrote: Hi All, I am using header(Location: http://dv-medical/phpscripts/test.php;) function to hop from one Page to Another in My Web Application My Problem is I have been unable to get the exact syntax to append the Session ID to the URL specified in the header so that it is available header(Location: http://dv-medical/phpscripts/test.php?.SID) That's what the SID constant is for. You can even use it with impunity when cookies are in use, since it is set to the empty string in that case. Cheers! Mike - Mike Ford, Electronic Information Services Adviser, Learning Support Services, Learning Information Services, JG125, James Graham Building, Leeds Metropolitan University, Headingley Campus, LEEDS, LS6 3QS, United Kingdom Email: [EMAIL PROTECTED] Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211 To view the terms under which this email is distributed, please go to http://disclaimer.leedsmet.ac.uk/email.htm -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] Displaying results from a query properly.
On 24 March 2006 16:40, Alex Major wrote:
Thanks, works like a charm (had to make is -2 instead of -1
as it added a
space after each result). Hadn't thought of something so simple.
On 24/3/06 16:22, Bastien Koert [EMAIL PROTECTED] wrote:
Build it up as a string and remove the trailing comma at the end of
the loop
do { $sHTML .= ''.$administrators['username'].', ';}
while ($administrators = mysql_fetch_assoc($administrators_result))
$sHTML = substr($sHTML, 0, strlen($sHTML)-1);
You don't need a strlen() call here, as substr understands count from the
right notation:
$sHTML = substr($sHTML, 0, -1);
... or, with Alex's correction:
$sHTML = substr($sHTML, 0, -2);
Cheers!
Mike
-
Mike Ford, Electronic Information Services Adviser,
Learning Support Services, Learning Information Services,
JG125, James Graham Building, Leeds Metropolitan University,
Headingley Campus, LEEDS, LS6 3QS, United Kingdom
Email: [EMAIL PROTECTED]
Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211
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RE: [PHP-DB] Quick question
On 08 December 2005 20:53, Chris Payne wrote: Hi there everyone, How do I set the following items with ini_set()? I looked at the manual but when I try nothing happens: * file_uploads * upload_max_filesize * max_input_time * memory_limit * max_execution_time * post_max_size Apart from max_execution_time, the things affected by those settings all take place before your script even gains control -- so changing them in the script can never have any useful effect. To do any good, they must be set in an appropriate config file (php.ini, httpd.conf, .htaccess, etc.) as permitted. Cheers! Mike - Mike Ford, Electronic Information Services Adviser, Learning Support Services, Learning Information Services, JG125, James Graham Building, Leeds Metropolitan University, Headingley Campus, LEEDS, LS6 3QS, United Kingdom Email: [EMAIL PROTECTED] Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211 To view the terms under which this email is distributed, please go to http://disclaimer.leedsmet.ac.uk/email.htm -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] problem of transmiting variabl into another page?
On 02 December 2005 13:06, Bastien Koert wrote:
?php for ($j=ord('A'); $j = ord('Z'); $j++) {
echo | ba
href='alpha.php?artist=.chr($j).'.chr($j)./a/b ;
} ?
You need to use the ORD function to get the numerical ascii
equivalent of the letter and the CHR function to go back the other
way.
Gak! That's almost worse than the original!!
Bastien
From: Mohamed Yusuf [EMAIL PROTECTED]
To: php-db@lists.php.net
Subject: [PHP-DB] problem of transmiting variabl into another page?
Date: Fri, 2 Dec 2005 12:30:12 +0200
I am transmitting variable from one of my pages and I would like to
match that variable into mysql data. it won't return data.
my code is this.
?php for ($j=A; $j = Z; $j++) {
echo | ba href='alpha.php?artist=$j'$j/a/b |;
if ($j == Z) {
break;
}
} ?
1. You have unquoted strings -- should be 'A' and 'Z'.
2. The test condition in your for is wrong (and either that or the break is
redundant).
Here's how I'd write it:
for ($j='A'; $j!='AA'; $j++):
echo | ba href='alpha.php?artist=$j'$j/a/b |;
endfor;
Cheers!
Mike
-
Mike Ford, Electronic Information Services Adviser,
Learning Support Services, Learning Information Services,
JG125, James Graham Building, Leeds Metropolitan University,
Headingley Campus, LEEDS, LS6 3QS, United Kingdom
Email: [EMAIL PROTECTED]
Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211
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Re: [PHP-DB] pg_insert tyro question
I certainly agree with that Micah. array_pop only removes that last
item. If you are in a an open environment you definitely want to
include security checks and form validation.
-mike
On Aug 22, 2005, at 4:07 PM, Micah Stevens wrote:
This is tenuous and insecure, you have no control over the $_POST
array, only
the submitting page does, I'd do a sanity check, and assign the values
needed
into another array before submitting to the database.
This is also primed for a SQL injection attack.
Bad idea.. IMHO..
-Micah
On Monday 22 August 2005 3:52 pm, Jon Crump wrote:
Thanks mike! that did the trick. This works:
array_pop($_POST);
/* this gets rid of the last element of $_POST which is 'addentry'
from
the form's submit button. $_POST now containes ONLY the values
expected by
pg_insert. By the way, the order of the values in $_POST does not
seem to
matter, only that there are exactly as many as there are columns in
the
table and their names match the columns exactly.*/
$res = pg_insert($db, 'foo', $_POST);
if ($res) {
echo You're a Genius;
} else {
print pg_last_error ($db);
exit;
}
On Mon, 22 Aug 2005, mike burnard wrote:
It very likely is the error. you can use array_pop($_POST); to
remove
that last line. You can always have your insert function return an
error
on failure. snip /
By the way Bastian and John, thanks for responding to my pg_connect
question some days ago. Installing Marc Liyanage's distribution did
the
trick!
Thanks too to Bastian and Micah.
Or if you need to store all the values, you could normalize the table
field
into another table.
-Micah
On Monday 22 August 2005 3:19 pm, Bastien Koert wrote:
To further append the previous note,
if you want to insert the array, you need to serialize it
(www.php.net/serialize) to make the array db safe
if you want to insert the individual specific values, you will need
to
implode the array with separators (and check the data in the correct
order
for the field list) or you will need to supply a field list that
matches
the array list to ensure the data elements are placed into the
correct
columns
Bastien
I'm not sure what any of this means, but it didn't turn out to be
necessary.
Jon
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Re: [PHP-DB] mysql INNER JOIN
have a look at http://www.webmasterworld.com/forum88/3653.htm hope this helps! Mike ioannes wrote: I usually use INNER JOIN to link tables together in a straight line, like a branch. Can I use it to link tables like twigs stemming off the branch. If so, do I use: SELECT TABLE1.FIELD, TABLE2.FIELD, TABLE3.FIELD FROM ( TABLE1 INNER JOIN TABLE2 ON TABLE1.FIELD =TABLE2.FIELD ) INNER JOIN TABLE3 ON TABLE1.FIELD=TABLE3.FIELD or if the join has to be in the middle: SELECT TABLE_1.FIELD, TABLE_2.FIELD, TABLE_3.FIELD, TABLE_4.FIELD FROM TABLE_1 INNER JOIN ( TABLE_2 INNER JOIN TABLE_3 ON TABLE_2.FIELD =TABLE_3.FIELD ) ON TABLE_1.FIELD=TABLE_2.FIELD INNER JOIN TABLE_4 ON TABLE1.FIELD=TABLE3.FIELD John -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] Problem with foreach looping...
From: NIPP, SCOTT V (SBCSI) [mailto:[EMAIL PROTECTED]
I am attempting to use a simple foreach loop on a query result,
and I am only getting the first element of the array back.
Here is the
code...
$exclude_query = SELECT hostname FROM exclusion;
$exclude_results = mysql_query($exclude_query, $Prod);
$exclude = mysql_fetch_array($exclude_results, MYSQL_NUM);
foreach ($exclude as $row) {
echo $row\n;
}
I don't understand how I am just getting a single item back from
this. The query actually returns all 13 entries in the
exclusion table.
I have tested the query via the mysql client. I also get all 13
elements back if I loop via the following.
while ($test = mysql_fetch_array($results, MYSQL_NUM)) {
echo $test[0]\n;
}
Is my PHP somehow broke, or am I just missing something here?
Thanks.
mysql_fetch_array() only fetches one record of the result set at a time.
Thus, the code's doing what you told it to. The while() loop is what you
want. Why do you need to use a foreach() loop? At that point, there's
nothing to foreach() through. No array has been constructed.
HTH!
--
Mike Johnson Smarter Living, Inc.
Web Developerwww.smartertravel.com
[EMAIL PROTECTED] (617) 886-5539
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[PHP-DB] MYSQL row position.. is it possible (urgent)
Let's say I have a database and I want to find the position of a row when it is ordered by a specific column before a sort: UNIQUE ID | SCORE 1 | 100 2 | 50 3 | 30 4 | 80 5 | 50 after sort: UNIQUE ID | SCORE 1 | 100 4 | 80 2 | 50 5 | 50 3 | 30 is it posible to find the position of 4 with a query or mysql function? Normally I'd just 'SELECT unique_id FROM table ORDER DESC' then loop through the results looking for a matching id, however my table contains thousands of entries, and it's simply not possible do do it that way. Thanks Mike
[PHP-DB] How-to pass informational mysql messages to the browser
Hello everyone, My PHP/mysql pages are working perfectly, the problem is users don't know if what they are doing is working. I have a system that adds and deletes tape id's from mysql via a PHP front end. I would like to pass the same success/failure messages that I would get if I performed the add/delete directly within mysql. For example, If I delete a tape from the db within mysql, after I hit enter I get the following message: mysql delete from tape_tracking_test where media_id like 'TR44'; Query OK, 1 row affected (0.01 sec) I would like to display this message to the browser: Query OK, 1 row affected (0.01 sec) Any help would be appreciated, Thanks, Mike -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] How-to pass informational mysql messages to the browser
Hello everyone, My PHP/mysql pages are working perfectly, the problem is users don't know if what they are doing is working. I have a system that adds and deletes tape id's from mysql via a PHP front end. I would like to pass the same success/failure messages that I would get if I performed the add/delete directly within mysql. For example, If I delete a tape from the db within mysql, after I hit enter I get the following message: mysql delete from tape_tracking_test where media_id like 'TR44'; Query OK, 1 row affected (0.01 sec) I would like to display this message to the browser: Query OK, 1 row affected (0.01 sec) Any help would be appreciated, Thanks, Mike -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] Re: boolean values in postgresql
On 21 Feb 2005 at 20:54, Bret Hughes said about boolean values in postgresql: Question: Assuming the above assumption is correct, what is the most efficient way to define a column that will take only two values who's values will evaluate as intended in php? How about a CHAR(1) with Y/N (or T/F) and use a trigger to enforce it. Or you could use the small int and have 0/1... the validating trigger's the point... Mike Morris The Music Place 1617 Willowhurst Avenue San Jose, CA 95125 (408) 445-ARTS (2787) Your Free Quote: And that, in my view, is what the whole controversy comes down to: Are you entitled to the fruits of your own labor, or does government have some presumptive right to spend and spend and spend? Ronald Reagan, 1981 -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] Re: Newbie Setup Trouble
Hello list, I'd just like to thank everyone who jumped right in with their insights and suggestions to my troubles. There's a lot to get me going there! Every one of those posts was helpful. I have downloaded XAMPP and am going to install it here in a minute. Armed with that, and the use of search as Jerry suggested, I bet all will go much more smoothely now, hehe. Just wanted to affirm to you all that your assistance was appreciated :) ~Mike -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] timestamp
To view the terms under which this email is distributed, please go to http://disclaimer.leedsmet.ac.uk/email.htm -Original Message- From: Balwant Singh [mailto:[EMAIL PROTECTED] Sent: 01 February 2005 08:08 on echoing $timestamp i m getting Fri Jan 28 19:53:09 2005 but on echoing $date i m getting 1970-01-01. also i m getting full info. by phpinfo() i m using php 4.2.2 , apache 2.0 and rad hat 9. The Change Log includes this line for version 4.3.3: Fixed bug #13142 (strtotime not handling M d H:i:s Y format). (Ilia) So I guess you need at least PHP 4.3.3 for this to work correctly for you. Cheers! Mike - Mike Ford, Electronic Information Services Adviser, Learning Support Services, Learning Information Services, JG125, James Graham Building, Leeds Metropolitan University, Headingley Campus, LEEDS, LS6 3QS, United Kingdom Email: [EMAIL PROTECTED] Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211 -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] mysql - image storing
To view the terms under which this email is distributed, please go to http://disclaimer.leedsmet.ac.uk/email.htm On 18 January 2005 17:11, Joseph Crawford wrote: Jason, can you explain why stripslashes should not be used on data taken from the db? when you store data in the db i thought it was good practice to addslashes, when you retrieve from the db, you will need to use stripslashes to remove the extra \ It's simple. Suppose you have a script that looks a bit like this (but hopefully with more input validation and error checking!): $value = addslashes($_POST['text']); // magic_quotes_gpc off $sql = INSERT INTO tbl SET fld = '$value'; database_execute($sql); Now suppose the user types this into the 'text' form field: Here's an apostrophe Here's what happens: PHP does this: $value is set to: Here\'s an apostrophe $sql becomes: INSERT INTO tbl SET fld = 'Here\'s an apostrophe' Which is sent to the database via database_execute() The DATABASE now does this: Receives the SQL statement: INSERT INTO tbl SET fld = 'Here\'s an apostrophe' (Note how the \ escape is required here to stop the field value from terminating prematurely -- but this escape is aimed at the *database*, and is not a PHP escape. A lot of confusion seems to arise here for databases which use the same \ escape character as PHP.) Extracts the value: Here\'s an apostrophe and de-escapes it to give:Here's an apostrophe Which gets inserted into the database. So the value inserted into the database is the unescaped original, and on retrieval there are no \ characters in the retrieved value to be stripslashes()ed. Hope that's clearer than mud, and helps you understand what's going on better. Cheers! Mike - Mike Ford, Electronic Information Services Adviser, Learning Support Services, Learning Information Services, JG125, James Graham Building, Leeds Metropolitan University, Headingley Campus, LEEDS, LS6 3QS, United Kingdom Email: [EMAIL PROTECTED] Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211 -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] php latest release!
To view the terms under which this email is distributed, please go to http://disclaimer.leedsmet.ac.uk/email.htm On 10 January 2005 09:28, JeRRy wrote: With PHP latest release from http://php.net/ do we require to update Zend Optimizer? Yes. People are claiming some scripts previously that worked in a previous version of PHP works and not with the new version. There are several bug reports on bugs.php.net about this. Also see the red warning text on http://php.net/downloads.php Why is it required to update Zend? Earlier versions are incompatible with PHP 4.3.10, and exhibit various incorrect behaviours -- in particular, foreach produces the wrong results. Cheers! Mike - Mike Ford, Electronic Information Services Adviser, Learning Support Services, Learning Information Services, JG125, James Graham Building, Leeds Metropolitan University, Headingley Campus, LEEDS, LS6 3QS, United Kingdom Email: [EMAIL PROTECTED] Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211 -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] Trying to connext to MySQL with PEAR
To view the terms under which this email is distributed, please go to http://disclaimer.leedsmet.ac.uk/email.htm On 06 January 2005 21:10, Norland, Martin wrote: -Original Message- From: Ford, Mike [mailto:[EMAIL PROTECTED] Sent: Thursday, January 06, 2005 1:13 PM Subject: RE: [PHP-DB] Trying to connext to MySQL with PEAR [snip] Oh dear, as a fully-paid-up pedant, I'm afriad I can't resist this one: Doesn't affect the answer, but this occurrence of 'effect' should be 'affect'. ;) Cheers! Mike * Joining in on the fun * I'm afraid you spelled afraid incorrectly. I'll be sending you the bill for my services related to this matter. Please send it to Mr Murphy, who obviously insinuated one of his pet gremlins into my keyboard for those few moments...! ;) Cheers! Mike - Mike Ford, Electronic Information Services Adviser, Learning Support Services, Learning Information Services, JG125, James Graham Building, Leeds Metropolitan University, Headingley Campus, LEEDS, LS6 3QS, United Kingdom Email: [EMAIL PROTECTED] Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211 -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] PHP query to mysql database returns emtpy data, but Query Browser shows records
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On 07 January 2005 03:25, Jason Walker wrote:
Graeme - you were moving in the right direction. Since the
data in the field
is varchar(250), the only thing that changes is the fact that the last
number is 3 digits. Other page queries were also affected
with 4 x 2 digit
numbers in the category field (eg. '37 48 49 52').
By adding '%' between each number and using 'LIKE' as opposed
to '=', the
queries through PHP return the correct value.
I think is very strange as 3x numbers work fine when using
spaces (' ')
between each criteria (as in '37 48 53').
The change would look something like:
SELECT description from cpProducts where category like '39%47%48%172'
That's not a good idea, as it would also match entries like:
391 247 48 172
39 147 148 172
395 347 1486 1172
etc.
I think you really need to find out exactly what's in those failing records,
and why it's not matching your query.
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RE: [PHP-DB] Trying to connext to MySQL with PEAR
To view the terms under which this email is distributed, please go to http://disclaimer.leedsmet.ac.uk/email.htm On 06 January 2005 16:39, Jochem Maas wrote: Hutchins, Richard wrote: echo $dsn; $isPersistant = TRUE; doesn't effect the code but 'Persistant' is spelled 'Persistent' Oh dear, as a fully-paid-up pedant, I'm afriad I can't resist this one: Doesn't affect the answer, but this occurrence of 'effect' should be 'affect'. ;) Cheers! Mike - Mike Ford, Electronic Information Services Adviser, Learning Support Services, Learning Information Services, JG125, James Graham Building, Leeds Metropolitan University, Headingley Campus, LEEDS, LS6 3QS, United Kingdom Email: [EMAIL PROTECTED] Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211 -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Filling Drop-Down Box.
Hello All, I want to fill drop-down box from mysql table, if any body be kind to tell me a sample code :) e.g: In my application i want to gather subject list from current semester-subject table of a student. TIA -- Nayyar Ahmad You know that the HTML code for the drop-down is: SELECT NAME=SAMPLE OPTION VALUE=1Whatever 1/OPTION OPTION VALUE=2Whatever 2/OPTION /SELECT Here's some pseudo-code remarks that should help you with your coding: - whatever.html - Drop-down: SELECT NAME=sample ?php // connect to your database - if you haven't already // construct a query to pull the records you want, and // in the order you want to display them // execute the query // loop through the results, building an OPTIONwhatever/OPTION // for each element in the drop-down. You can get creative // here if you need to. Like: // OPTION VALUE=##whatever/OPTION // where ## is the key field, and whatever is another //(descriptive) field in your query // close your database connection (or later, if needed) ?/SELECT Try to fill in the actual code yourself. If you get stuck, you can look at: http://www.netmask.com/php-db/sample-dropdown.html Good luck! :Mike S. :Austin TX USA -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] data is not entering in created database
hallo ,
i have wriiten simple php script , below.
created databse dollar1_allinfo with table 'totalinfo'
but on clicking submit button ,
information entered is not entering in database.
also, echo statements are also not displaying after submit
?php
if ($submit)
{
$db = mysql_connect(localhost,root);
mysql_select_db(dollar1_allinfo,$db);
mysql_query(INSERT INTO totalinfo (username,password,) VALUES
('$loginusername','$loginpassword'));
echo 'thank you';
echo 'So Hurry Up';
}
?
thank you.
Because your query and echoes are within an if block, I'd say that
$submit is evaluating to FALSE, and thus not executing the query and
echoes.
Add (before the if statement):
echo Submit = $submit;
Make sure that $submit is evaluating to TRUE.
To All Beginning Programmers (Newbies), or just people who want to
easily debug their code:
Try adding debugging statements to help you find problems. A few echoes
or prints in selected locations will help identify the issue. Make sure
your variables are evaluating to values that you think they should be.
If you want to keep the debugging statements in your code and just
activate them when you need to see them, do something like:
// near the top of your code
$debug=TRUE;
// and anywehere in your code
if ($debug) {
echo DEBUG: Submit = $submitBR\n;
}
// or whatever echo might help you nail down the problem. Put as many of
these in your code and you can turm them ON and OFF very easily, by
changing one line of code.
OR for even quicker debugging, replace $debug=TRUE; with
$debug=$_GET['debug'];
and then you can turn it on in by adding ?debug=TRUE at the end of the
URL. Example: http://www.php.net/path/my.html?debug=TRUE
or: http://www.php.net/path/my.html?debug=1
**DISCLAIMER** Using the URL method is NOT a secure way to do this!!!
And I'm sure there's plenty of folks groaning out there because it is a
BIG security hole. You really would want to do this on a development
machine and network, and remove the debug code for production. That
really should go without saying.
Good luck.
:Mike S.
:Austin TX USA
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RE: [PHP-DB] _POST, _GET, _REQUEST not working
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On 23 December 2004 01:12, Keane, Warren A FIN:EX wrote:
I did try
if (empty($_GET)) { parse_str($_SERVER['QUERY_STRING'],$_GET); }
which worked so I guess I should be able to come up with an
equivalent for _POST using argv, argc.
I am guessing but I also think the problem is to do with the fact
that the CGI sapi is being used.
I am using the CLI SAPI, I checked using php_sapi_name(). Is this
causing the problem?
Absolutely -- this is the Command-Line Interface. As this is intended for
command-line scripting, it has no notion of being used in a Web context and
does not even attempt to fill the $_POST or $_GET (or most of the other $_)
arrays. You need to use either the CGI SAPI, or the Apache module.
Cheers!
Mike
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RE: [PHP-DB] still Parse errors ,,, can you. impart me about it.
To view the terms under which this email is distributed, please go to http://disclaimer.leedsmet.ac.uk/email.htm On 23 December 2004 18:04, amol patil wrote: hallo Mike, thanks for reply, but i want a bit more help, again Please keep this on-list -- someone else may have time to reply before I can (especially as I am about to go home for my tea and a well-earned sleep!). i know these parse errors are generally typing mistakes , but i have checked for it , but still i am getting errors. i have attached files with their codes , can you go through it to find what is going wrong Parse error: parse error, unexpected '' in /home/dollar1/public_html/signup.php on line 263 parse error, unexpected '' in /home/dollar1/public_html/login.php on line 94 Parse error: parse error, unexpected T_STRING in /home/dollar1/public_html/addfunds.php on line 91 then on 102 thank you. Ford, Mike [EMAIL PROTECTED] wrote: To view the terms under which this email is distributed, please go to http://disclaimer.leedsmet.ac.uk/email.htm On 21 December 2004 07:58, amol patil wrote: hallo friend, i have developed simple and small database website using php ,html and java script. but i am getting these three parse errors on clicking , i have checked 3-4 imes on these line numbers, but there wasn't any $ variable. php script is also correctly written. what is this T_STRING error. can you help me regarding this. thank you. errors: Parse error: parse error, unexpected $ in /home/dollar1/public_html/signup.php3 on line 379 $ in PHP's error messages represents the end of the file, so PHP has reached the end of signup.php3 when it's still expecting more program. This means you have an error somewhere in the preceding 378 lines -- most likely a missing }. (If PHP was complaining about a variable reference, the message would refer to unexpected T_VARIABLE.) Cheers! Mike - Mike Ford, Electronic Information Services Adviser, Learning Support Services, Learning Information Services, JG125, James Graham Building, Leeds Metropolitan University, Headingley Campus, LEEDS, LS6 3QS, United Kingdom Email: [EMAIL PROTECTED] Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211 Do you Yahoo!? Jazz up your holiday email with celebrity designs. Learn more. -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] Parse errors ,,, can you. impart me about it.
To view the terms under which this email is distributed, please go to http://disclaimer.leedsmet.ac.uk/email.htm On 21 December 2004 07:58, amol patil wrote: hallo friend, i have developed simple and small database website using php ,html and java script. but i am getting these three parse errors on clicking , i have checked 3-4 imes on these line numbers, but there wasn't any $ variable. php script is also correctly written. what is this T_STRING error. can you help me regarding this. thank you. errors: Parse error: parse error, unexpected $ in /home/dollar1/public_html/signup.php3 on line 379 $ in PHP's error messages represents the end of the file, so PHP has reached the end of signup.php3 when it's still expecting more program. This means you have an error somewhere in the preceding 378 lines -- most likely a missing }. (If PHP was complaining about a variable reference, the message would refer to unexpected T_VARIABLE.) Cheers! Mike - Mike Ford, Electronic Information Services Adviser, Learning Support Services, Learning Information Services, JG125, James Graham Building, Leeds Metropolitan University, Headingley Campus, LEEDS, LS6 3QS, United Kingdom Email: [EMAIL PROTECTED] Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211 -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] _POST, _GET, _REQUEST not working
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On 20 December 2004 21:50, Warren wrote:
Hello,
I am running PHP 4.39 as a CGI under Tomcat 5.025, Linux 2.4.20-31.9.
Configure = './configure' '--with-java=/usr/java/j2sdk1.4.2_04'
'--with-servlet=/home/www/jakarta-tomcat-5.0.25' '--with-mysql'
I cannot get the _GET function or _REQUEST functions to pick
up values from
a form generating even though I can see the query string
values in the URL
as in:
http://localhost:8080/ip7/httptest.php?var1=212122var2=343434
My HTML is very simple:
form action=http://localhost:8080/ip7/httptest.php; method=get
input type=text name=var1
input type=text name=var2
input type=submit
/form
The PHP program httptest.php is also very simple:
?PHP
global $_SERVER, $_GET, $_POST, $_REQUEST, $_SESSION, $_COOKIE;
if(!empty($_REQUEST['var1'])) { $var1 = $_REQUEST['var1']; }
else { $var1 ='undefined'; }
if(!empty($_GET['var2'])) { $var2 = $_GET['var2']; }
else $var2 ='undefined';
// Various HMTL tags removed for simplicity
echo $var1
echo $var1
Is this a direct paste from your original? If so, there's an obvious error
here -- one of those should be $var2,'cos as it is you're never even echoing
the value of the $_GET parameter.
Cheers!
Mike
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JG125, James Graham Building, Leeds Metropolitan University,
Headingley Campus, LEEDS, LS6 3QS, United Kingdom
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RE: [PHP-DB] date conversions
To view the terms under which this email is distributed, please go to http://disclaimer.leedsmet.ac.uk/email.htm On 16 December 2004 06:00, neil wrote: Hi I am needing to convert a d/m/y date such as 30/11/2004 into the format that mysql can use ie. 2004-11-20 If I try the following: $testdate=30/11/2004; echo date(Y-m-d, strtotime($testdate)); the result is - 2006-06-11 strtotime() is, unfortunately, a little American biased and only recognises the mm/dd/ numeric format (using slashes). So the above is returning the equivalent of the 11th day of the 30th month of 2004! You can use other PHP functions, as has been suggested, but you might also investigate the mySQL date formatting functions, as I believe they work perfectly well on input dates as well as output ones. Cheers! Mike - Mike Ford, Electronic Information Services Adviser, Learning Support Services, Learning Information Services, JG125, James Graham Building, Leeds Metropolitan University, Headingley Campus, LEEDS, LS6 3QS, United Kingdom Email: [EMAIL PROTECTED] Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211 -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] PHP 4.3.10RC2 - Any change in the way rows are fetch ed ?
To view the terms under which this email is distributed, please go to http://disclaimer.leedsmet.ac.uk/email.htm On 16 December 2004 12:51, Vincent KONIECZEK wrote: Hi there, I was testing PHP 4.3.10RC2 with a well-tested web application when I saw it failed badly. After a little debug, I have found that the problem comes from this SQL query: SELECT CONCAT(num) AS k FROM user WHERE uid LIKE '%%' where user is a table with num as the PK and uid as a VARCHAR(128). I expect a result like this one (var_export-like display) of the fetched row (with mysql_fetch_array()): ([0] = 67,[k] = 67) But mysql_fetch_array() gives me: ([0] = ([0] = 67,[k] = 67)) For me, it is a really big problem. I do not have it with PHP 4.3.8. I did not take the time to test with PHP 4.3.9 nor 4.3.10 but I took a look at the documentation web sites, the latest Changelogs and made a search on the mailing lists but found nothing about it. Similar problems have been reported to the bugs database, and have been traced to an old version of the Zend Optimiser -- if you are using this, try disabling it, and if your application then works ok upgrade to the latest version. Cheers! Mike - Mike Ford, Electronic Information Services Adviser, Learning Support Services, Learning Information Services, JG125, James Graham Building, Leeds Metropolitan University, Headingley Campus, LEEDS, LS6 3QS, United Kingdom Email: [EMAIL PROTECTED] Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211 -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] mysql_array_array
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On 03 December 2004 13:15, Yemi Obembe wrote:
$sql = SELECT * FROM arcadia WHERE email=$v;
$sql_in = INSERT INTO arcadia ('email') VALUES ('$v');
Spot the difference: you have quoted the email value $v in the INSERT
(correct) but not in the SELECT (wrong). This means that:
$res = mysql_query( $sql ) ;
is failing with a SQL error, so $res is not being set to a valid MySQL
result resource, so that when you execute:
if (list($row) = mysql_fetch_array($res)) {
The mysql_fetch_array() complains with the error you have seen.
After any database operation, you should check for failure and echo out any
error message -- see mysql_errno() (http://php.net/mysql_errno) and
mysql_error() (http://php.net/mysql_error).
Cheers!
Mike
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Learning Support Services, Learning Information Services,
JG125, James Graham Building, Leeds Metropolitan University,
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RE: [PHP-DB] Question: For no results
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On 03 December 2004 14:39, Stuart Felenstein wrote:
I want to send back a message when no matches are
found on my search page. Basically No matches
found. I assumed that mysql_fetch_assoc would be the
determining factor on whether any rows will come back.
As you can see below I do a if ($row_rsCS == false).
Apparently though (while the message is sharp and
centered ;)), it is not to right place, since it sends
the message and exits whether records / matches exist or not. Any
suggestions ?
Thank you
Stuart
$query_limit_rsCS = sprintf(%s LIMIT %d, %d,
$query_rsCS, $startRow_rsCS, $maxRows_rsCS);
//print_r($query_limit_rsCS);
$rsCS = mysql_query($query_limit_rsCS, $Pmmodel) or
die(mysql_error()); //print_r($rsCS);
$row_rsCS = mysql_fetch_assoc($rsCS);
if ($row_rsCS == false)
?
The closing ? of a PHP segment also implies an end-of-statement semicolon
-- so the above is equivalent to:
if ($row_rsCS == false) ;
?
Which, of course, means that the scope of the if doesn't extend to anything
beyond this point.
You need to mark the block controlled by the if, using either {-} or
:-endif, according to your taste.
Cheers!
Mike
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JG125, James Graham Building, Leeds Metropolitan University,
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Email: [EMAIL PROTECTED]
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RE: [PHP-DB] Question: For no results
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On 03 December 2004 15:06, Stuart Felenstein wrote:
The closing ? of a PHP segment also implies an
end-of-statement semicolon
-- so the above is equivalent to:
if ($row_rsCS == false) ;
?
Which, of course, means that the scope of the if
doesn't extend to anything
beyond this point.
You need to mark the block controlled by the if,
using either {-} or
:-endif, according to your taste.
The reason the close is there is because the next line
of code is the print_r , and I put some html in there.
Nothing wrong with having the closing ? there -- please re-read my
response. If it's still unclear to you, please ask specific questions.
Cheers!
Mike
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JG125, James Graham Building, Leeds Metropolitan University,
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RE: [PHP-DB] Question: For no results
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On 03 December 2004 15:16, Stuart Felenstein wrote:
--- Stuart Felenstein [EMAIL PROTECTED] wrote:
The reason the close is there is because the next
line
of code is the print_r , and I put some html in
there.
So this works great:
if ($row_rsCS == false) {
print_r (No Matches Found);
exit;
}
But because I want to have some html formatting around
the print_r, I closed the tags.
Yes, but you didn't include the { } to indicate the scope of the if -- so it
terminated at the ?.
I'm not sure how to use the endif.
Well, your taste seems to be to use { }, so :-endif is irrelevant.
Cheers!
Mike
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JG125, James Graham Building, Leeds Metropolitan University,
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RE: [PHP-DB] Question: For no results
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On 03 December 2004 15:26, Stuart Felenstein wrote:
--- Ford, Mike [EMAIL PROTECTED] wrote:
Well, your taste seems to be to use { }, so :-endif is irrelevant.
Alright it's Friday, I'm punchy but we're all in a
good mood !
Yes, I like the closing curlies
So, then where do these lovely ladies go here ?
if ($row_rsCS == false) {
?
p align=centerstrong?php print_r (No Matches Found);?
/strong/p
?php
exit;
}
Just put the PHP tags in as indicated and you'll be good to go.
Cheers!
Mike
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RE: [PHP-DB] Question: For no results
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On 03 December 2004 15:26, Stuart Felenstein wrote:
--- Ford, Mike [EMAIL PROTECTED] wrote:
Well, your taste seems to be to use { }, so :-endif is irrelevant.
Alright it's Friday, I'm punchy but we're all in a
good mood !
Yes, I like the closing curlies
So, then where do these lovely ladies go here ?
if ($row_rsCS == false) {
p align=centerstrong?php print_r (No Matches Found);?
/strong/p exit;
}
And, by the way, why on earth are you using a print_r an a straight literal
string? Seems to me you could just put that text in as part of the HTML:
if ($row_rsCS == false) {
?
p align=centerstrongNo Matches Found/strong/p
?php
exit;
}
Cheers!
Mike
-
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Email: [EMAIL PROTECTED]
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RE: [PHP-DB] Multi-User Update Problem
To view the terms under which this email is distributed, please go to http://disclaimer.leedsmet.ac.uk/email.htm On 30 November 2004 14:45, SCALES, Andrew wrote: Thanks very much for your help. The main difficulty I was having really was unlocking the record again if the user crashed out or just closed down their browser/computer (something they have a bad habit of doing) but storing the time the record was locked and ignoring the lock if it's over that time sounds interesting. I may try storing the data in a session variable and then comparing that to the database before the updated data is inserted into the record as Bastien suggested. We wanted to keep hits on the db to a minimum, but seen as some extra traffic will be necessary anyway I may just try that. Another approach to this might be: Keep a column in your database table for time of last update of each record. When a user reads a record for update, don't lock it at this point, but save the time at which it was read into the user's session (or somewhere in the database). On receiving a potential update, check the time the record was read (as recorded above) and the last update time of the record (lock the record as part of this query) -- if the update time is later then the read time, someone else has updated in the interim and you should abandon ship; otherwise, update the record including a new last-updated value; in either case, unlock the record. This methodology keeps both the lock and unlock in the same script (and potentially within a single database transaction), so no need for any external checks for locked records, and minimizes the amount of time for which any one record is locked. Cheers! Mike - Mike Ford, Electronic Information Services Adviser, Learning Support Services, Learning Information Services, JG125, James Graham Building, Leeds Metropolitan University, Headingley Campus, LEEDS, LS6 3QS, United Kingdom Email: [EMAIL PROTECTED] Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211 -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] Error Help
From: Chris Payne [mailto:[EMAIL PROTECTED]
I do have a final question, had a look online but couldn't find
what I needed. It's hard to explain why, but basically
individuals have my program on their HD, the DB is on their HD
etc And it connects on startup to a remote server to check
the latest version number so they can then download if a new
one is available (Which I package using MS.net's installer
system for distribution), Anyway, what I want to know is, how
can I get a NICE error message IF they aren't connected to the
net when they launch the software on their machine? Currently
I get a nasty message, but I'd like to replace it with
something like Please make sure you are connected to the
Internet or something like that? I know the OR DIE command,
but that doesn't work with connection failures.
I think what you're looking to do is suppress the PHP/DB error and
supply your own. What you want to do is preprend the db connection
function with `@' and add your own upon failure -- something like this:
?
$dbh = @mysql_connect($dbhost, $dbuser, $dbpass);
if (!$dbh) {
echo Please make sure you are connected to the Internet;
exit;
}
?
The only problem with this is that it'll fail with the same error
message if their internet connection is fine but $dbhost is unavailable.
I'm not entirely certain if PHP can gracefully detect a local internet
connection, actually. For your purposes, though, this should do the job.
HTH!
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RE: [PHP-DB] Transaction suddenly not working
To view the terms under which this email is distributed, please go to http://disclaimer.leedsmet.ac.uk/email.htm On 29 November 2004 13:19, Stuart Felenstein wrote: Now the printout of the query is this: 0: INSERT INTO Table1 (LurkID, ProfileName, Edu, WorkAuth, WorkExp, CarLev, Secu, Confi, Relo, Telecomu, City1, State1, City2, State2, TravelPref, SalaryAnnual, SalaryHourly, Available) VALUES (47, '', 7, 2, 1015, 5, , '', '', '', 'fds', 5, '', You have 2 successive commas in this last line, with no value in between -- this is your syntax error. , 4, 26, , 2004-02-02)01062 : Duplicate entry '0-f' for key 1 And again on this line -- twice, in fact, since the previous line ends with a comma, too. Track down whatever is outputting these null values, fix it, and you should be good to go (well, at least less bad!). Cheers! Mike - Mike Ford, Electronic Information Services Adviser, Learning Support Services, Learning Information Services, JG125, James Graham Building, Leeds Metropolitan University, Headingley Campus, LEEDS, LS6 3QS, United Kingdom Email: [EMAIL PROTECTED] Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211 -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] PHP / Javascript question
To view the terms under which this email is distributed, please go to http://disclaimer.leedsmet.ac.uk/email.htm On 16 November 2004 03:03, Chris Payne wrote: This is OT, really, but because it's an easy answer: if ( document.removeitems.del.value == ) BUT because the tickboxes information is stored in a PHP Array called del[] I am having major problems getting it to work. You shouldn't be, since any good JavaScript text will tell you that, by definition, x.y is identical to x['y']; so: document.removeitems['del[]'] will get you started. Cheers! Mike - Mike Ford, Electronic Information Services Adviser, Learning Support Services, Learning Information Services, JG125, James Graham Building, Leeds Metropolitan University, Headingley Campus, LEEDS, LS6 3QS, United Kingdom Email: [EMAIL PROTECTED] Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211 -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] Re: Subject: Javascript Question (Was PHP / Javascri pt question)
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On 16 November 2004 15:12, Neil Smith wrote:
That
if (df[i].checked=true) {
should of course read
if (df[i].checked==true) {
No it shouldn't -- it should read
if (df[i].checked) {
More efficient, more readable, and, more important, The Right Way (TM)! ;)
Cheers!
Mike
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Learning Support Services, Learning Information Services,
JG125, James Graham Building, Leeds Metropolitan University,
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RE: [PHP-DB] Persistent Connections to Oracle databases
To view the terms under which this email is distributed, please go to http://disclaimer.leedsmet.ac.uk/email.htm On 11 November 2004 19:11, Patrick David wrote: My understanding of persistent connections was that using the ociplogon function a connection would be opened to the database and all other connections to the same database (with the same username and password) would use the first one previously opened, which mean I would have only 1 connection to the database. I know this is a late response, but I haven't seen anybody point this out yet: that's 1 connection *per Apache child process*, since each process still has to have its own connection. But in fact it is not what is happening, every time I submit the page to the same database a new connection is opened. Which is a little bit annoying if I submit this one 100 times (100 connections at the end). Potentially, if you have Apache configured to run 100 children or more. If you configure it to run only 50 children, that's the maximum number of Oracle connections you will get. Cheers! Mike - Mike Ford, Electronic Information Services Adviser, Learning Support Services, Learning Information Services, JG125, James Graham Building, Leeds Metropolitan University, Headingley Campus, LEEDS, LS6 3QS, United Kingdom Email: [EMAIL PROTECTED] Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211 -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] IIS and php sessions
I'm pretty sure this is enabled by default in PHP for Windows, I think you'll need to check the IUSR_[machine_name] persmissions on the sessions folder. I'm headed in the other direction. I'm re-writing an app with a database abstraction layer with hopes of moving to postgres. -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] Forms list from database
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On 01 November 2004 21:11, Jason T. Davidson wrote:
Here is the code:
form name=form1 method=post action=staff_code/add_code.php
table width=600 border=0 align=center cellpadding=0
cellspacing=0 tr bgcolor=#CC
td colspan=3 bgcolor=#FFdiv align=center
select name=controller id=controller
option /option
option
?
while ($check=mysql_fetch_array($result)){
print $check[LNAME],$check[FNAME]($check[CID]);
}
/option
/select
/div/td
/tr
I think you're missing some option/option tags -- these should be
present around each value extracted from the database, so:
while ($check=mysql_fetch_array($result)){
print
option{$check['LNAME']},{$check['FNAME']}({$check['CID']})/option\n;
}
Cheers!
Mike
-
Mike Ford, Electronic Information Services Adviser,
Learning Support Services, Learning Information Services,
JG125, James Graham Building, Leeds Metropolitan University,
Headingley Campus, LEEDS, LS6 3QS, United Kingdom
Email: [EMAIL PROTECTED]
Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211
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RE: [PHP-DB] Problems with mysql_num-rows()
To view the terms under which this email is distributed, please go to http://disclaimer.leedsmet.ac.uk/email.htm On 01 November 2004 05:01, Doug Thompson wrote: The variables are not being expanded. As a minimum, you need to escape the single quotes. $query = SELECT * from user where name=\'$userid\' and pass=password(\'$password\') This is complete BS. The whole string is in double quotes -- the presence of single quotes within it has no effect whatsoever on the expansion of variables, nor is it necessary to escape them. Cheers! Mike - Mike Ford, Electronic Information Services Adviser, Learning Support Services, Learning Information Services, JG125, James Graham Building, Leeds Metropolitan University, Headingley Campus, LEEDS, LS6 3QS, United Kingdom Email: [EMAIL PROTECTED] Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211 -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] can i display an image _directly_ from postgres db storage?
Philip, Typically, it's infinitely more performance-friendly to simply store your files on the hard disk and use the database to refer to that location. For instance, assume your root web dir is /www. Inside there you have an /images directory. If you religiously put all files inside of /images you can store the file name inside the DB and simply have your code output the proper HTML. Or, if you have to actually do image processing, you can have your code query the DB and then read the file into an image handler for GD or whatever you're using to do the processing. Either way, it's usually encouraged not to store BLOBs whenever possible due to the performance hit that's usually associated with that. -M -Original Message- From: P. George [mailto:[EMAIL PROTECTED] Sent: Monday, November 01, 2004 10:36 PM To: [EMAIL PROTECTED] Subject: [PHP-DB] can i display an image _directly_ from postgres db storage? i know that postgres has a raw binary datatype called bytea for storing pictures and whatnot, but i'm having trouble finding an example of displaying an image on a web page with php that is pulled directly from the database? is this possible? if so, how? thanks. - philip -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] php code on sqlite
Add
?
}
}
?
after your closing /html
On Wed, 20 Oct 2004 11:50:29 -0700 (PDT), Aravalli Sai
[EMAIL PROTECTED] wrote:
hi
this is php code for inventory management system
which is done using SQLite.this is an user
interface where an user wil giv values to the text
boxes and it should be saved in the backend database
which is sqlite..
but when i run this code on browser it is giving an
error ... Parse error: parse error in
/home/saravall/.HTML/inv.php on line 81
HTML
HEAD
/HEAD
body
?php
$db =/home/saravall/office.db;
$handle = sqlite_open($db) or die(could not open
database);
if(isset($_POST['submit'])) {
if (!empty($_post['tagno']) !empty
($_post['desc'])
!empty ($_post['acqdt']) !empty
($_post['manufacturer']) !empty
($_post['model']) !empty($_post['serialid'])
!empty( $_post
['custloc']) !empty($_post['totcost']))
{
$insquery = insert into inventory
(tagno,desc,acqdt,manufacturer,model, serial
id,custloc,totcost) values (\.sqlite_escape_string(
$_post['tagno']).\,\.sqlite_escape_string($_post['desc']).\,\
.sqlite_escape_string($_post['serialid']).\,\.sqlite_escape_string($_post
['custloc']).\,\.sqlite_escape_string($_post['totcost']).\);
$insresult = sqlite_query($handle,$insquery) or
die(error:.sqlite_error_string(sqlite_last_error($handle)));
echo isuccessfully inserted!/ip /;
}
else {
echo iincomplete from input!/ip /;
$query = SELECT * FROM inventory ;
$result = sqlite_query($handle,$query) or
die(err:.sqlite_error_string(sqlite_last_error($handle)));
if (sqlite_num_rows($result) 0)
{
echo table cellpadding=20 border=1;
while ($row = sqlite_fetch_array($result))
{
echo tr;
echo td.$row[0]./td;
echo td.$row[1]./td;
echo td.$row[2]./td;
echo td.$row[3]./td;
echo td.$row[4]./td;
echo td.$row[5]./td;
echo td.$row[6]./td;
echo td.$row[7]./td;
echo td.$row[8]./td;
echo td.$row[9]./td;
echo /tr;
}
echo /table;
}
sqlite_close($handle);
?
p
h2
enter new record:/h2
form method=post action=?php echo
$_server['php_self'];?
Tag number:input type=text name=number
br/
desc:input type=text name=desc
br/
acq date:input type=text name=date
br/
manufacturer:input type=text name=manufacturer
br/
model:input type=text name=model
br/
serial id:input type=text name=serial id
br/
custodian location:input type=text
name=custodian
br/
sum cost:input type=text name=cost
br/
input type=submit name=submit value =save
/p
/form
/body
/HTML
i would appreciate if you can help me in correcting
this error..
thanks in advance..
sai
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[PHP-DB] Re: Safe / Secure Login Script
These are not PHP specific suggestions, but I see two big problems: 5.) Password is then encrypted using base64_encode() 6.) You've confused encryption and encoding. Base64 encoding is trivial to decode, and fairly obvious to spot as well. All this achieves is that someone can't accidentally - before they avert their eyes - read the password while doing a view source. But anyone who wants it can get it if they're given the base64 encoded representation. I wouldn't use this method - or a website that did. 8.) If No username is found, Message is sent to end user stating username does not exist. Don't tell them whether it was the username or the password that was wrong. Doing so lets a hacker decompose a complex problem into two simpler problems. With your method, I would first keep trying until you confirm that I've guessed a valid username, then I can go about guessing the password. If I don't know which is wrong, the number of possibilities is increased geometrically. Mike Morris The Music Place 1617 Willowhurst Avenue San Jose, CA 95125 (408) 445-ARTS (2787) Your Free Historical Quote: Finally, it is my most fervent prayer to that Almighty Being before whom I now stand, and who has kept us in His hands from the infancy of our Republic to the present day, that He will so overrule all my intentions and actions and inspire the hearts of my fellow-citizens that we may be preserved from dangers of all kinds and continue forever a united and happy people. - Andrew Jackson, Second Inaugural Address, March 4, 1833 -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] SSL connection between PHP4 PostgreSQL ???
Hi, I've setup a postgres server (7.4) and confirmed that SSL is enabled - I can successfully connect via tcp socket over SSL using the psql client. From PHP4, how can I get the pg_connect function to negotiate an SSL connection? I gather from researching the issue that pg_connect uses the same libraries as psql, so that this should be possible. But I've tried every syntax I can think of... the options parameter to pg_connect is not well documented. I've played with all varieties of requiressl or ssl, alone or as a boolean, e.g., requiressl=true, etc... If not possible in PHP4, is it in PHP5? Any help greatly appreciated! MikeM Mike Morris The Music Place 1617 Willowhurst Avenue San Jose, CA 95125 (408) 445-ARTS (2787) Your Free Historical Quote: Above all, I know there is a Supreme Being who rules the affairs of men and whose goodness and mercy have always followed the American people, and I know He will not turn from us now if we humbly and reverently seek His powerful aid. - Grover Cleveland, Second Inaugural Address, March 4, 1893 -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] What is PHPBB?
Google is your friend: http://www.google.com/search?hl=enie=UTF-8q=PHPBBbtnG=Google+Search -Original Message- From: Lic. Daniel Alfredo Betancourt Reboso [mailto:[EMAIL PROTECTED] Sent: Saturday, October 02, 2004 9:22 AM To: '[PHP-DB] Mailing List' Subject: [PHP-DB] What is PHPBB? Hi folks!!!: Somebody wrote: for example, the phpBB web app, multiple people log into the bulletin board. but the account that is used to connect to the MYSQL (in this case) backend is a single account that is created when you first install phpBB. phpBB then uses this account to do all the work needed and logs that into a table so you know who posted (or edit or deleted) what post on the forum. All I wanna know is what is PHPBB?. Is it some PHP thing that deals with Database directly or is it another PHP relese? Thank´s Regards... Daniel.. Please excuse my englsih grammar. INFOSOL Webmail http://webmail.gtm.sld.cu/imp/ -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] Convert plain text to HTML tagged text
On 28 September 2004 18:15, [EMAIL PROTECTED] wrote: To the list: I've googled and searched the manual, but I'm still looking for a simple solution to a simple problem. I have a MySQL database of text stories in longtext MySQL fields. These stories have simple returns (\r) in them and no other formatting. I need to use these stories both for web and print production, so I need to be able to get the text out of MySQL via PHP and have those returns change to P tags. But I also need to keep those extra P tags out of the database file so the text can be exported and poured into a layout program. HTMLspecialchars and HTMLentities don't seem like the right solution, but maybe I'm missing something. Do I have to use regular expressions in PHP as the text is pulled from the database? http://www.php.net/str_replace should be all you need -- no need for regexps for such a simple replace. Cheers! Mike - Mike Ford, Electronic Information Services Adviser, Learning Support Services, Learning Information Services, JG125, James Graham Building, Leeds Metropolitan University, Headingley Campus, LEEDS, LS6 3QS, United Kingdom Email: [EMAIL PROTECTED] Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211 -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] MultSelect ListBox hell!
On 23 September 2004 20:53, Stuart Felenstein wrote:
So here is what I have:
//Here is defines the field variable and uses
//CodeCharge function to grab the variable
$s_Industry = CCGetParam(s_Industry, );
$s_LocationState = CCGetParam(s_LocationState, );
$s_TaxTerm = CCGetParam(s_TaxTerm, );
//Here is the parsing of the array. I'm not sure
what the $proj variable is for. I gather it's a
holder for the array values
if (count($s_Industry) 0 AND is_array($s_Industry)) {
foreach ($s_Industry as $key = $value) {
if ($Proj1 != ) $Proj1 = $Proj1.,;
$Proj1 = $Proj1.'.$value.';
}
}
$Proj1 now contains a comma-separated list of the values passed to
$s_Industry, which was filled by the CCGetParam() above. The above code
block is equivalent to (and would be better coded as):
if (count($s_Industry) 0 AND is_array($s_Industry)) {
$Proj1 = '.implode(',', $s_Industry).';
}
which may look somewhat familiar to you!
//Parsing next array
if (count($s_LocationState) 0 AND
is_array($s_LocationState))
{
foreach ($s_LocationState as $key = $value) {
if ($Proj2 != ) $Proj2 = $Proj2.,;
$Proj2 = $Proj2.'.$value.';
}
}
//Parsing file array
if (count($s_TaxTerm) 0 AND is_array($s_TaxTerm)) {
foreach ($s_TaxTerm as $key = $value) {
if ($Proj3 != ) $Proj3 = $Proj3.,;
$Proj3 = $Proj3.'.$value.';
}
}
These two blocks are similar for the other two parameters, $s_LocationState
and $s_TaxTerm
Here is what will be the death of me :)
First the where condition below is being appended to
anoher file in my main sql statement (don't ask:))
CC keeps their code in various sections and files.
Anyway , if you remember yesterday, it was determined
that I needed the where condition to be dynamically
created based on the user input.
Obviously the code below does nothing of that sort.
Obviously it does, using the lists of values built above.
So as a start, I'm trying to figure out what I can do
with this section here (since this is really what
needs to be changed, I think) to make it all right.
if ($Proj1)
$VendorJobs-ds-SQL.= AND (`VendorJobs`.Industry IN (.$Proj1.));
Plug the value for $Proj1 built above into this, and again you have
something that may look very familiar to you. It's the very same IN clause
I was urging you to use yesterday! ;)
if ($Proj2)
$VendorJobs-ds-SQL.= AND
(`VendorJobs`.LocationState IN (.$Proj2.));
if ($Proj3)
$VendorJobs-ds-SQL.= AND (VendorJobs.TaxTerm IN (.$Proj3.));
echo SQL:. $VendorJobs-ds-SQL.br;
So you now have a dynamically built portion of SQL, in $VendorJobs-ds-SQL,
that has a clause like AND x IN ('a','b','c') for each input field that
has any values set. According to your specs, this could be anywhere up to
six separate clauses. This seems to be exactly what you wanted, so your
code looks good to go.
To help you understand exactly what's going on here, or in any script or
program you're struggling to interpret, I would recommend two time-honoured
techniques:
(i) Dry running: get out your genuine old-fashioned pen and paper, pretend
you're the PHP interpreter processing this program, and write down the value
of each variable as you work through the code. Yes, it can be quite
long-winded and tedious, but you really get a tremendous feel for exactly
what's going on. The number of times I've done this and cursed myself as
I've watched a value going out of range, or not getting set at all, I
couldn't begin to count.
(ii) As a variation of the above, put *lots* of debugging echos in your
script: echo the value of every variable frequently and redundantly -- it
can help sometimes just to have the reassurance that a value really hasn't
changed, even though you know it absolutely shouldn't!! Again, if you're
struggling with how a script operates this can help you see how values are
built up, and can often show you exactly where a wrong value gets calculated
(and how, and maybe even why). It's especially important to echo your final
complete SQL statement just before it's executed, so that if it produces an
error message you've got the actual relevant SQL right in front of you.
Hope this helps.
Cheers!
Mike
-
Mike Ford, Electronic Information Services Adviser,
Learning Support Services, Learning Information Services,
JG125, James Graham Building, Leeds Metropolitan University,
Headingley Campus, LEEDS, LS6 3QS, United Kingdom
Email: [EMAIL PROTECTED]
Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211
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RE: [PHP-DB] MultSelect ListBox hell!
On 22 September 2004 18:45, Stuart Felenstein wrote:
Just to confirm,
This is what I'm going to start with:
Yeah, I'd say you've pretty much got it, except...
//base sql statement
$sql = select * from jobs where record_deleted = 'NO' ;
if (isset($_POST['states'])){
Your SQL is going to need some sort of conjunction here, as your WHERE phrase already
has an initial condition in it. I'm guessing you'll want an AND, so:
$sql .= 'AND ';
//check to see if the states is an array
// multiple items or just one
if (is_array($_POST['state']))
You've switched from $_POST['states'] to $_POST['state'] -- fix whichever is wrong ;)
$sql .= state='.implode(' OR state=',
$_POST['state']).';
Given the conditions you want your WHERE phrase to test, you're going to need more
parentheses to force the ORs to be evaluated before the ANDs; this is where the IN
syntax, IMO, is more readable. So you want either:
$sql .= (state='.implode(' OR state=',$_POST['state']).');
or:
$sql .= state IN ('.implode(',',$_POST['state']).');
}else{
//$_POST['state'] is not an array
$sql .= state = '.$_POST['state'].' ;
}//end if
if (isset($_POST['job'])){
if (isset($_POST['state'])){ $sql .= AND ; }
And throughout this second block you've used a cut'n'paste of the first block without
altering ['state'] to ['job'] -- just the sort of oversight that can give you the
raving heebie-jeebies somewhere down the line if you fail to fix it! ;)
//add in the AND if the state is set
//check to see if the states is an array
//multiple items or just one
if (is_array($_POST['state']))
$sql .= state='.implode(' OR state=',
$_POST['state']).';
$sql .= );
}else{
$_POST['job'] is not an array
$sql .= job = '.$_POST['job'].' ;
}
//end if
Given the moderate complexity of this code, I'd strongly recommend echo-ing out $sql
immediately before it's used whilst you're in testing mode. When your query fails,
you'll already be one step ahead in working out what the problem is.
Cheers!
Mike
-
Mike Ford, Electronic Information Services Adviser,
Learning Support Services, Learning Information Services,
JG125, James Graham Building, Leeds Metropolitan University,
Headingley Campus, LEEDS, LS6 3QS, United Kingdom
Email: [EMAIL PROTECTED]
Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211
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RE: [PHP-DB] Using PHP to generate SQL statement
On 23 September 2004 07:47, Ed Lazor wrote:
I keep looking at the following code and thinking there's
gotta be a better
way. I've been in front of the computer all day tho and I'm drawing
a blank. Any ideas?
Seems to me we've just answered a very similar question to this (and I'd be
surprised it there weren't several relevant threads in the list archives).
Nonetheless:
$sql = select ID from products where ;
if ($webpage-parameter_isset(CategoryID)) {
Two possible approaches that spring to mind are:
$sql = select ID from products where 1=1;
if ($webpage-parameter_isset(CategoryID)) {
$sql .= AND CategoryID = '{$webpage-CategoryID}';
}
if ($webpage-parameter_isset(CompanyID)) {
$sql .= AND CompanyID = '{$webpage-CompanyID}';
}
if ($webpage-parameter_isset(SettingID)) {
$sql .= AND SettingID = '{$webpage-SettingID}';
}
if ($webpage-parameter_isset(SystemID)) {
$sql .= AND SystemID = '{$webpage-SystemID}';
}
Or:
$where = ''
foreach (array('CategoryID', 'CompanyID', 'SettingID', 'SystemID')
as $field):
if ($webpage-parameter_isset($field)):
$where .= ($where?' AND':''). $field = '{$webpage-$field}';
endif;
endforeach;
if ($where):
$sql = select ID from products where$where;
...
else:
// no where information -- major error
endif;
Cheers!
Mike
-
Mike Ford, Electronic Information Services Adviser,
Learning Support Services, Learning Information Services,
JG125, James Graham Building, Leeds Metropolitan University,
Headingley Campus, LEEDS, LS6 3QS, United Kingdom
Email: [EMAIL PROTECTED]
Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211
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RE: [PHP-DB] MultSelect ListBox hell!
-Original Message-
From: Bastien Koert [mailto:[EMAIL PROTECTED]
Sent: 22 September 2004 15:27
[]
//base sql statement
$sql = select * from jobs where record_deleted = 'NO' ;
if (isset($_POST['states'])){
//check to see if the states is an array (multiple items
or just one
This check isn't really necessary in PHP, since $_POST['state'] will *always* be an
array if the form field has NAME='state[]', even if only 1 is selected.
if (is_array($_POST['state'])){
$sql .= (;
$x = 0;
foreach ($_POST['state'] as $state)
if ($x == 0){
$sql.= state = '$state' ;
$x=1;
}else{
$sql .= OR state = '$state' ;
}
$sql .= );
PHP has the very nice implode function to make this much easier:
$sql = state='.implode(' OR state=', $_POST['state']).';
(If your database supports the IN operator, this is probably even better:
$sql = state IN ('.implode(',', $_POST['state']).'); )
}else{
//$_POST['state'] is not an array
$sql .= state = '.$_POST['state'].' ;
}//end if
if (isset($_POST['job'])){
if (isset($_POST['state'])){ $sql .= AND ; } //add in
the AND if the
state is set
//check to see if the states is an array (multiple items or just one
if (is_array($_POST['job'])){
$sql .= (;
$x = 0;
foreach ($_POST['job'] as $job )
if ($x == 0){
$sql.= job = '$job ;
$x=1;
}else{
$sql .= OR job = '$job ;
}
$sql .= );
}else{
//$_POST['job'] is not an array
$sql .= job = '.$_POST['job'].' ;
}//end if
Ditto for the job field.
Cheers!
Mike
-
Mike Ford, Electronic Information Services Adviser,
Learning Support Services, Learning Information Services, JG125, James Graham
Building, Leeds Metropolitan University, Headingley Campus, LEEDS, LS6 3QS, United
Kingdom
Email: [EMAIL PROTECTED]
Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211
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RE: [PHP-DB] MultSelect ListBox hell!
-Original Message-
From: John Holmes [mailto:[EMAIL PROTECTED]
Sent: 22 September 2004 16:39
From: Ford, Mike [EMAIL PROTECTED]
if (is_array($_POST['state'])){
This check isn't really necessary in PHP, since
$_POST['state'] will
*always* be an array if the form field has NAME='state[]', even if
only 1 is selected.
But remember that the form comes from the client. Just
because you create
the form with state[], that doesn't mean I'm going to send
it that way. ;)
Yeah, true -- I have a very bad tendency to forget about security considerations like
that until someone reminds me (often a posting on this list does it ;). Just because
I have a well-defined set of well-behaved users...!!
Cheers!
Mike
-
Mike Ford, Electronic Information Services Adviser,
Learning Support Services, Learning Information Services, JG125, James Graham
Building, Leeds Metropolitan University, Headingley Campus, LEEDS, LS6 3QS, United
Kingdom
Email: [EMAIL PROTECTED]
Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211
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RE: [PHP-DB] MultSelect ListBox hell!
-Original Message-
From: Stuart Felenstein [mailto:[EMAIL PROTECTED]
Sent: 22 September 2004 16:45
--- Ford, Mike [EMAIL PROTECTED] wrote:
if (is_array($_POST['state'])){
$sql .= (;
$x = 0;
foreach ($_POST['state'] as $state)
if ($x == 0){
$sql.= state = '$state' ;
$x=1;
}else{
$sql .= OR state = '$state' ;
}
$sql .= );
PHP has the very nice implode function to make this
much easier:
$sql = state='.implode(' OR state=', $_POST['state']).';
(If your database supports the IN operator, this is
probably even better:
$sql = state IN ('.implode(',', $_POST['state']).'); )
Sorry, cause I know this is probably a stupid
question, but what block of code does the implode
statement replace ?
Everything inside the if(is_array()). Ummm, that should probably still be a
.= operator, then. There's also some quotes missing in the original
version, so:
if (is_array($_POST['state']))
$sql .= state='.implode(' OR state=', $_POST['state']).';
Cheers!
Mike
-
Mike Ford, Electronic Information Services Adviser,
Learning Support Services, Learning Information Services, JG125, James
Graham Building, Leeds Metropolitan University, Headingley Campus, LEEDS,
LS6 3QS, United Kingdom
Email: [EMAIL PROTECTED]
Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211
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[PHP-DB] where can I post some mysql related questions?
hi, I've currently been looking for a mysql news server where I could post some questions on mysql database design (cause they shurely wouldn't fit here) and I have yet to find one. Can anyone help? -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] Re: Checkboxes in a table
-Original Message- From: Ford, Mike [LSS] Sent: 21/08/04 01:57 foreach ($_POST['checkbox'] as $key=$irrelevant): // checkbox[$key] was checked endif; OK, it's 2a.m. here and I'm about asleep, whioch is why that last line didn't read endforeach; !!! Cheers! Mike -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] Inserting a ' into mySQL
-Original Message- From: Ron Piggott Sent: 21/08/04 01:53 [] One of the problems I am now having is if the user types an ' into their entry --- these ones do not get saved into the mySQL database. [] I can look at this and understand that if an ' is keyed why it wouldn't save and that line would create an error --- How do you work around this? That's what mysql_real_escape_string() is for -- http://www.php.net/mysql_real_escape_string. Cheers! Mike -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] I have a CR-LF problem when pulling stuff out of my DB
On 19 August 2004 17:02, Michael Cortes wrote: ctrl-m is a carriage return. Does anyone know what ctrl seqence is line feed? ctrl-j (CR and LF are ASCII codes 13 and 10, so ctrl+ the 13th and 10th letters of the alphabet respectively!) Cheers! Mike - Mike Ford, Electronic Information Services Adviser, Learning Support Services, Learning Information Services, JG125, James Graham Building, Leeds Metropolitan University, Headingley Campus, LEEDS, LS6 3QS, United Kingdom Email: [EMAIL PROTECTED] Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211 -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] Check Boxes
On 18 August 2004 11:24, randy wrote:
$chkboxes = $_POST['ch'];
$sql = 'SELECT ';
foreach($chkboxes as $k = $v)
{
$sql .= $v;
if($k (sizeof($chkboxes) - 1))
{
$sql .= ', ';
}
}
$sql .= ' FROM form';
$sql = 'SELECT ' . implode(', ', $chkboxes) . 'FROM form';
Cheers!
Mike
-
Mike Ford, Electronic Information Services Adviser,
Learning Support Services, Learning Information Services,
JG125, James Graham Building, Leeds Metropolitan University,
Headingley Campus, LEEDS, LS6 3QS, United Kingdom
Email: [EMAIL PROTECTED]
Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211
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RE: [PHP-DB] Check Boxes
On 18 August 2004 15:53, John Holmes wrote:
Ford, Mike [LSS] wrote:
$chkboxes = $_POST['ch'];
$sql = 'SELECT ';
foreach($chkboxes as $k = $v)
{
$sql .= $v;
if($k (sizeof($chkboxes) - 1))
{
$sql .= ', ';
}
}
$sql .= ' FROM form';
$sql = 'SELECT ' . implode(', ', $chkboxes) . 'FROM form';
Just note that with either solution, someone can post a value of *
FROM table WHERE 1# and see everything in any table in your database.
I was waiting for someone to come in with a security warning, but knew that whoever it
was would express it much better than I could ;) -- so, a gold medal to John!!
Cheers!
Mike
-
Mike Ford, Electronic Information Services Adviser,
Learning Support Services, Learning Information Services,
JG125, James Graham Building, Leeds Metropolitan University,
Headingley Campus, LEEDS, LS6 3QS, United Kingdom
Email: [EMAIL PROTECTED]
Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211
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RE: [PHP-DB] OCI8
On 13 August 2004 13:29, yannick wrote:
I have some trouble with Oracle Database and php...
see this code:
?
while (1) {
$conn=OCILogon($username,$password,$database);
Try OCIPLogon() rather than OCILogon().
$stmt=OCIParse($conn,select 50 as toto from dual);
OCIDefineByName($stmt,TOTO,$total);
Not related to your problem, but you don't need that -- in fact, it's deprecated and
may, one day, cause a parse error.
OCIExecute($stmt);
OCIFetch($stmt);
echo :::$total:::\n;
OCILogoff($conn);
$err=OCIError($conn);
OCILogoff($conn);
sleep(10);
}
when i execute it, the number of fd on ocius.msg is growing. but
there is only 1 connection at database.
Can someone help me ?
Cheers!
Mike
-
Mike Ford, Electronic Information Services Adviser,
Learning Support Services, Learning Information Services,
JG125, James Graham Building, Leeds Metropolitan University,
Headingley Campus, LEEDS, LS6 3QS, United Kingdom
Email: [EMAIL PROTECTED]
Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211
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RE: [PHP-DB] Date problem: data is current as of yesterday
-Original Message- From: Karen Resplendo To: [EMAIL PROTECTED] Sent: 02/07/04 19:36 Subject: [PHP-DB] Date problem: data is current as of yesterday The database queries all the sources at night after everyone has gone home. That means the data was current as of yesterday. This little snippet below returns yesterday's date, except that the first day of the month returns 0 for the day. Now, I know why this is happening, but I can't find out how to fix it (in VBA or SQL Server I would just say, date()-1: $today = getdate(); $month = $today['month'] ; $mday = $today['mday'] -1; $year = $today['year']; echo Data is current as of b$month $mday, $year/bbr; -- The mktime() function is your friend for this kind of date arithmetic. For example, this is one possible way to do what you want: $yesterday = mktime(12, 0, 0, $today['mon'], $today['mday']-1, $today['year']); echo Data is current as of b.date(F j, Y, $yesterday); (Note the use of time 12:00:00 to avoid daylight savings oddities!) The examples on the date() and mktime() manual pages may suggest other possibilities to you. Cheers! Mike - Do you Yahoo!? New and Improved Yahoo! Mail - 100MB free storage! -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] More problems with searching
On 01 July 2004 18:36, Justin Patrin wrote:
On Thu, 1 Jul 2004 12:28:46 -0500, Shiloh Madsen
[EMAIL PROTECTED] wrote:
After the very kind help i was given last night I have the query
being built right, however the query does not work. Just to
refresh, the gentlemen who had helped me suggested creation of a
query that looks like:
SELECT * FROM table1 where 1 or cat or dog...and so forth. Now,
this query is building fine, but the where 1 is causing it to
return rows even if it has none of the search terms. When i run it
in sql without the where 1 it works as it should, but with that, i
get all rows returned. Is there a way i can reword this query or am
I doing something wrong?
this was Mr Holmes's solution (in part):
$query = SELECT * FROM keyword WHERE 1
$words = explode(' ',$_GET['search_text']);
foreach($words as $word)
{ $query .= AND keyword = '$word' ; }
Shouldn't that be OR?
... and, if it should, that should be a 0 instead of a 1 (although I'm not a huge fan
of this technique!).
Cheers!
Mike
-
Mike Ford, Electronic Information Services Adviser,
Learning Support Services, Learning Information Services,
JG125, James Graham Building, Leeds Metropolitan University,
Headingley Campus, LEEDS, LS6 3QS, United Kingdom
Email: [EMAIL PROTECTED]
Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211
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RE: [PHP-DB] [PHP]: session problem
On 24 June 2004 16:44, H. J. Wils wrote:
this is the code, but this code works on my hosting provider but not
on my own server. I think i have to change settings in php.ini but
dont know which...
first page:
session_start();
include connect.php;
include functions.php;
$user= $_GET[email];
$ww = $_GET[ww];
$check_user_query = select id,email, password from user where
email='$user' and password='$ww';
$check_user_res = mysql_query($check_user_query) or
die(mysql_error().: $check_user_query);
if (mysql_num_rows($check_user_res) == 1){
//user is ingelogd
$userdata =
mysql_fetch_array($check_user_res);
$sid=session_id();
$uid=$userdata[id];
$_SESSION['logged_in'] = true;
$_SESSION['sid'] = $sid;
$_SESSION['user'] = $uid;
$dt = date(Y-m-d H:i:s);
header(location: user.php?action=0);
}else{
header(location: user.php?action=9);
}
Redirecting like this will not pass the session id in the URL if that is
necessary, which it would be if cookies are not being used. Since you say
it works for you from your provider's system but not your local one, this
suggests that your provider has session.use_cookies turned on, but you have
it turned off.
If this is so, you can solve your immediate problem by turning that option
on in your php.ini, but the redirects will still not work correctly for
anyone who has cookies turned off in their browser. If you are bothered
about this, you need to make use of the handy-dandy SID constant that PHP
helpfully provides, thusly:
header(Location: user.php?action=0.SID);
or, if you're a tidy-URL geek, something like:
header(Location: user.php?action=0.(SID?.SID:));
(BTW, notice the correct spelling of the Location header, with a capital
L; and, yes, others are right when they say it should be a full absolute
URL. These things have been known to matter to some browsers, so it's best
to make a habit of getting them right!)
Cheers!
Mike
-
Mike Ford, Electronic Information Services Adviser,
Learning Support Services, Learning Information Services,
JG125, James Graham Building, Leeds Metropolitan University,
Headingley Campus, LEEDS, LS6 3QS, United Kingdom
Email: [EMAIL PROTECTED]
Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211
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[PHP-DB] Sample Code
Hello all, I was wondering if anyone had some sample code that I could use for a small project. What I would like to do is select data in a date field, like: From: 6-1-04 To: 6-15-04 Then output to a text file. I have other selections within this data that I will make, and I think can figure out. The part I'm having trouble with is exporting the data and selecting between two dates. I'm running PHP4 and MySQL 4.1. Thank in advance for your help. Mike -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
