Hi,
change line 170 to this:
$form_category_id[$i] = mysql_result($result_category_id, 0, 0);
In each iteration your program executes new SQL query, which
selects only one column from table, and i think, it selects only one row
too. So you have to select first column from first row. With your
code: mysql_result($result_category_id, 0, $i); you try to get value
from first row but from columns 1,2,3,4,5... etc. as for runs through
array.
Hope this helps.
Petr Tomenendal.
On Wed, 2002-10-02 at 18:57, Wilmar Perez wrote:
Hello guys.
The scenery: I've got an array with some values stored in it. I want to
retrieve the id code each value is associated to. So I just do the following:
for ($i=0; $icount($form_category);$i++)
{
$query_get_id = select cat_code from categories
where cat_name like '$form_category[$i]';
$result_category_id = mysql_query($query_get_id) or die(mysql_error());
$form_category_id[$i] = mysql_result($result_category_id, 0, $i); //This
is line
170
echo $form_category[$i]. .$form_category_id[$i].br;
}
I'm getting the following in my browser (There are some comments I just
added):
Arquitectura 2 //This is the correct category name and its ID
Warning: Bad column offset specified
in /var/www/bva/new/common/scripts/admin_functions.php on line 170
Caricatura //This is the correct category name but the ID is lost
Warning: Bad column offset specified
in /var/www/bva/new/common/scripts/admin_functions.php on line 170
Ciencias naturales //Same as before
Any idea of what I'm doing wrong?
***
Wilmar Prez
Network Administrator
Library System
Tel: ++57(4)2105145
University of Antioquia
Medelln - Colombia
2002
***
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