Brad,
Have you defined the database variable you are connecting to?
ie: $DB="your_database_name"; and then connecting:
if(!($testResult = mysql_query($DB, "SELECT * FROM login_table where Pass =
password('$password')")))
try the code snippet below and see if it spits an error at you - you will
need to define the $DB variable.
%s\n", $message);
}
//begin query
if(!($testResult = mysql_query($DB, "SELECT * FROM login_table where Pass =
password('$password')")))
//if we get an error print it
{
DisplayErrMsg(sprintf("internal error %d:%s\n",
mysql_errno(), mysql_error()));
exit();
}
$num_rows = mysql_num_rows($testResult);
print "$num_rows";
exit();
mysql_free_result($testResult);
?>
-Original Message-
From: Brad Wright [mailto:[EMAIL PROTECTED]]
Sent: 17 July 2001 06:31
To: [EMAIL PROTECTED]
Subject: [PHP-DB] mysql_query troubles
Hi all',
I have a mysql_query that reads:
$testResult = mysql_query("SELECT * FROM login_table where Pass =
password('$password')") or die ("ouch");
$num_rows = mysql_num_rows($testResult);
the problem is that I keep getting a value of 0 for $num_rows when I know
the table has 1 entry for PAss which equals password('$password'). The
password I have used is just 'a' (before pasing throught the password
function in the insert).
I DO have a table named login_table
I KNOW that there is an entry that matches 'password('$password)'.. ( i
checked using phpMyAdmin)
can anyone help??
Thanks in advance,
brad
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