Which version of PHP are you running? Versions before 4.1.0 don't have
the $_* variables. $_FILES may be an exception, it might be only
available in 4.2.0 and later, but I'm not sure about that.
Sander
On 2002.05.27 19:47 Daniel CAstro wrote:
My code is much more extense than this, but I guess this is the source
of my
problem.
arquivo is a member of a form, it is a file type, declared like
input
type=file name=arquivo...
I need to know if there is a file selected or not, that is the reason
of the
bug.
When I run this code, through the form it does not print anything,
even when
I choose a file on the previous html (html with a form, with an action
calling this script...) My version of PHP is 4.x
?php
$nome = $_POST['nome'];
$des = $_POST['des'];
$eng = $_POST['eng'];
$id = $_POST['id'];
$tabela= $_POST['tabela'];
$tabela_nova = $_POST['dd_tipo'];
$arquivo = $_FILES['arquivo']['name'];
//Conexao com BD...
printf(%s,$arquivo);
?
Why it is happenig???
_
Daniel Castro ICQ#: 12919017
[EMAIL PROTECTED]
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