php-general Digest 21 Aug 2007 20:20:28 -0000 Issue 4974
php-general Digest 21 Aug 2007 20:20:28 - Issue 4974
Topics (messages 261069 through 261092):
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261069 by: php
Re: Pass $_GET to php cli.
261070 by: Per Jessen
Re: Declare variables in advance question
261071 by: Colin Guthrie
261074 by: Stut
261075 by: shiplu
Re: LDAP
261072 by: Colin Guthrie
261078 by: Alain Roger
261085 by: Dan Shirah
261086 by: Daniel Brown
261088 by: Dan Shirah
Re: php 4.4.7 make install with pear causes zend freeing errors
261073 by: M. Sokolewicz
261089 by: John Mendenhall
oracle instantclient 10 problem
261076 by: Rainhard
Server error
261077 by: Humani Power
261079 by: Borokov Smith
keeping fields moving forward
261080 by: Mike Ryan
261081 by: Chris Boget
261083 by: Jim Lucas
261084 by: Mike Ryan
261087 by: Jim Lucas
261092 by: brian
Re: About Session And Cookies
261082 by: Michelle Konzack
php to generate java-script
261090 by: Jas
LDAP ***RESOLVED***
261091 by: Dan Shirah
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--
---BeginMessage---
eehdga otjcpm
exqko bbrgkf---End Message---
---BeginMessage---
N0K wrote:
But if it run in the browser, i think it have to run in cli, dont you
think ?
No, certainly not by default. They are very different environments, as
you have already found out.
/Per Jessen, Zürich
---End Message---
---BeginMessage---
nitrox . wrote:
I want to declare these variables Game_id and Member_id in advance. Following
the suggestionfrom one of my books can I do something like this:
$expected = array('Game_id', 'Member_id');foreach($expected AS $key) {if
( !empty($_POST[$key])) { ${$key} = $_POST[$key];}else {
${$key} = NULL;}} case addmember: switch ($_GET['type']) {
case membergame: $sql = INSERT INTO xsm_membergames
(Game_id,Member_id) VALUES
(' . mysql_real_escape_string((int)$_POST[Game_id])) . ',
' . mysql_real_escape_string((int)$_POST[Member_id])) .
'); break; } break;
My concern is did I achieve anything with the code I just added to declare
the variables? Is it actually being passed to this: case addmember:
switch ($_GET['type']) {case membergame: $sql = INSERT
INTO xsm_membergames(Game_id,
Member_id) VALUES(' .
mysql_real_escape_string((int)$_POST[Game_id]) . ','
. mysql_real_escape_string((int)$_POST[Member_id]) . '); break;
} break;
I did add this and tested it on my server and I didnt recieve any errors. So
how can I be sure its doing what I intended?
_
See what you’re getting into…before you go there
http://newlivehotmail.com/?ocid=TXT_TAGHM_migration_HM_viral_preview_0507
Your code is not formatted very nicly in your mail which makes it very
hard to read, but it's also invalid. There is a case statement in there
without a switch to control it twice.
Col
---End Message---
---BeginMessage---
Colin Guthrie wrote:
nitrox . wrote:
I want to declare these variables Game_id and Member_id in advance. Following
the suggestionfrom one of my books can I do something like this:
$expected = array('Game_id', 'Member_id');foreach($expected AS $key) {if ( !empty($_POST[$key])) { ${$key} = $_POST[$key];}else { ${$key} = NULL;}} case addmember: switch ($_GET['type']) {case membergame: $sql = INSERT INTO xsm_membergames(Game_id,Member_id) VALUES(' . mysql_real_escape_string((int)$_POST[Game_id])) . ',' . mysql_real_escape_string((int)$_POST[Member_id])) . '); break; } break;
My concern is did I achieve anything with the code I just added to declare the variables? Is it actually being passed to this: case addmember: switch ($_GET['type']) {case membergame: $sql = INSERT INTO xsm_membergames(Game_id,Member_id) VALUES(' . mysql_real_escape_string((int)$_POST[Game_id]) . ',' . mysql_real_escape_string((int)$_POST[Member_id]) . '); break; } break;
I did add this and tested it on my server and I didnt recieve any errors. So how can I be sure its doing what I intended?
[PHP] LDAP
Hi, I have a stupid issue with ldap_connect. i've reinstalled PHP, postgreSQL and restore my data (web files) after reinstalling my PC. now, when i try : $ds = ldap_connect($ldaphost, $ldapport) or die(Could not connect to $ldaphost); nothing works. i wrote before error_reporting(E_ALL); in order to check which error message i get, but nothing is return as error. what could be the problem ? thx. -- Alain Windows XP SP2 PostgreSQL 8.2.3 Apache 2.2.4 PHP 5.2.3
[PHP] Re: Declare variables in advance question
nitrox . wrote:
I want to declare these variables Game_id and Member_id in advance. Following
the suggestionfrom one of my books can I do something like this:
$expected = array('Game_id', 'Member_id');foreach($expected AS $key) {if
( !empty($_POST[$key])) { ${$key} = $_POST[$key];}else {
${$key} = NULL;}} case addmember: switch ($_GET['type']) {
case membergame: $sql = INSERT INTO xsm_membergames
(Game_id,Member_id) VALUES
(' . mysql_real_escape_string((int)$_POST[Game_id])) . ',
' . mysql_real_escape_string((int)$_POST[Member_id])) .
'); break; } break;
My concern is did I achieve anything with the code I just added to declare
the variables? Is it actually being passed to this: case addmember:
switch ($_GET['type']) {case membergame: $sql = INSERT
INTO xsm_membergames(Game_id,
Member_id) VALUES(' .
mysql_real_escape_string((int)$_POST[Game_id]) . ','
. mysql_real_escape_string((int)$_POST[Member_id]) . '); break;
} break;
I did add this and tested it on my server and I didnt recieve any errors. So
how can I be sure its doing what I intended?
_
See what you’re getting into…before you go there
http://newlivehotmail.com/?ocid=TXT_TAGHM_migration_HM_viral_preview_0507
Your code is not formatted very nicly in your mail which makes it very
hard to read, but it's also invalid. There is a case statement in there
without a switch to control it twice.
Col
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[PHP] Re: LDAP
Alain Roger wrote: Hi, I have a stupid issue with ldap_connect. i've reinstalled PHP, postgreSQL and restore my data (web files) after reinstalling my PC. now, when i try : $ds = ldap_connect($ldaphost, $ldapport) or die(Could not connect to $ldaphost); nothing works. i wrote before error_reporting(E_ALL); in order to check which error message i get, but nothing is return as error. what could be the problem ? Silly question but is the PHP you installed exactly the same as the previous one or did you select a different package? Perhaps PHP is compiled without ldap support or perhaps you've not installed the subpackage needed to enable ldap support. For me I have to install php-ldap subpackage. I would expect to see a fatal error saying no such function etc. so this is perhaps not the problem, but worth a look. Col -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Pass $_GET to php cli.
N0K wrote: But if it run in the browser, i think it have to run in cli, dont you think ? No, certainly not by default. They are very different environments, as you have already found out. /Per Jessen, Zürich -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Re: Declare variables in advance question
Colin Guthrie wrote:
nitrox . wrote:
I want to declare these variables Game_id and Member_id in advance. Following
the suggestionfrom one of my books can I do something like this:
$expected = array('Game_id', 'Member_id');foreach($expected AS $key) {if ( !empty($_POST[$key])) { ${$key} = $_POST[$key];}else { ${$key} = NULL;}} case addmember: switch ($_GET['type']) {case membergame: $sql = INSERT INTO xsm_membergames(Game_id,Member_id) VALUES(' . mysql_real_escape_string((int)$_POST[Game_id])) . ',' . mysql_real_escape_string((int)$_POST[Member_id])) . '); break; } break;
My concern is did I achieve anything with the code I just added to declare the variables? Is it actually being passed to this: case addmember: switch ($_GET['type']) {case membergame: $sql = INSERT INTO xsm_membergames(Game_id,Member_id) VALUES(' . mysql_real_escape_string((int)$_POST[Game_id]) . ',' . mysql_real_escape_string((int)$_POST[Member_id]) . '); break; } break;
I did add this and tested it on my server and I didnt recieve any errors. So how can I be sure its doing what I intended?
_
See what you’re getting into…before you go there
http://newlivehotmail.com/?ocid=TXT_TAGHM_migration_HM_viral_preview_0507
Your code is not formatted very nicly in your mail which makes it very
hard to read, but it's also invalid. There is a case statement in there
without a switch to control it twice.
That being the case the fact that you didn't get any errors indicates
that you have PHP configured to not show errors, warnings and notices. I
strongly recommend you modify your php.ini and set display_errors to on
and error_reporting to E_ALL. Then restart your web server and try your
script again. You should then see lots of errors.
-Stut
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Re: [PHP] php 4.4.7 make install with pear causes zend freeing errors
Chris wrote: M. Sokolewicz wrote: Chris wrote: John Mendenhall wrote: Is the only valid response to problems with php4 to upgrade to php5? Or, are there still some people out there still using php4 and possibly have had problems with install such as the following? If php5 is the only answer, I guess we'll just have to go with what we have and limp along until we can get everything converted to work on php5. I sent this to the php-install list. Try the -internals list. I don't think the php-internals folks would appreciate such emails. For problems with the install, first make sure it's not your fault (sounds stupid, but usually is), and if it's a bug, report it via the bugtracker. There is no need to bother the PHP developers with such things. The compiler complaining about free'ing memory is something they should pay attention to as far as I'm concerned. *shrug* Clearly I should've read the thread better, somehow I missed that entirely -.- sorry bout that :) anyway, first thing to do before posting is cutting down on your config options to the bare minimum to see if it's due to the core engine or some kind of extension, I'm sure they would appreciate it. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Re: Declare variables in advance question
use
#php -s
command to indend your source file
On 8/21/07, Colin Guthrie [EMAIL PROTECTED] wrote:
nitrox . wrote:
I want to declare these variables Game_id and Member_id in advance.
Following the suggestionfrom one of my books can I do something like this:
$expected = array('Game_id', 'Member_id');foreach($expected AS $key) {
if ( !empty($_POST[$key])) { ${$key} = $_POST[$key];}else {
${$key} = NULL;}} case addmember: switch ($_GET['type']) {
case membergame: $sql = INSERT INTO xsm_membergames
(Game_id,Member_id)
VALUES(' .
mysql_real_escape_string((int)$_POST[Game_id])) . ',
' . mysql_real_escape_string((int)$_POST[Member_id])) . ');
break; } break;
My concern is did I achieve anything with the code I just added to declare
the variables? Is it actually being passed to this: case addmember:
switch ($_GET['type']) {case membergame: $sql =
INSERT INTO xsm_membergames(Game_id,
Member_id) VALUES(' .
mysql_real_escape_string((int)$_POST[Game_id]) . ',
' . mysql_real_escape_string((int)$_POST[Member_id]) . ');
break; } break;
I did add this and tested it on my server and I didnt recieve any errors.
So how can I be sure its doing what I intended?
_
See what you're getting into…before you go there
http://newlivehotmail.com/?ocid=TXT_TAGHM_migration_HM_viral_preview_0507
Your code is not formatted very nicly in your mail which makes it very
hard to read, but it's also invalid. There is a case statement in there
without a switch to control it twice.
Col
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[PHP] oracle instantclient 10 problem
Ehlo, I compiled php-5.2.3 with the --with-oci8=instantclient,/opt/instantclient_10_2/ switch and it completed with no errors. First it seems to work well, but now, sometimes i get the infamous - OCIEnvNlsCreate() failed check LD_LIBRARY_PATH - error. The funny thing is, those variables are all set. I dont have really a clue why this appears now. versions in use apache 2.2.4 php 5.2.3 instantclient 10.2.0.3 These parameters are set before the apache is started ORACLE_BASE=/opt/instantclient_10_2 ORACLE_HOME=$ORACLE_BASE NLS_LANG=GERMAN_GERMANY.WE8ISO8859P9 PATH=$PATH:$ORACLE_BASE LD_LIBRARY_PATH=$ORACLE_BASE TNS_ADMIN=/etc ORACLE_SID=SID Any suggestions would be much appreciated. TIA Rainhard -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Server error
Hi everybody. I have a Fedora Core 7 with php 5, and I want to upload an image. The funniest thing is that my script works fine in other computer but not in this one. I look for the error in /var/log/httpd/error.log and I found this [Tue Aug 21 15:52:46 2007] [notice] caught SIGTERM, shutting down [Tue Aug 21 15:55:32 2007] [notice] suEXEC mechanism enabled (wrapper: /usr/sbin/suexec) [Tue Aug 21 15:55:32 2007] [notice] Digest: generating secret for digest authentication ... [Tue Aug 21 15:55:32 2007] [notice] Digest: done [Tue Aug 21 15:55:33 2007] [notice] mod_python: Creating 4 session mutexes based on 256 max processes and 0 max threads. [Tue Aug 21 15:55:33 2007] [notice] mod_python: using mutex_directory /tmp [Tue Aug 21 15:55:34 2007] [notice] Apache/2.2.4 (Unix) DAV/2 PHP/5.2.2 mod_python/3.3.1 Python/2.5 mod_ssl/2.2.4 OpenSSL/0.9.8b mod_perl/2.0.3 Perl/v5.8.8 configured -- resuming normal operations I know that this is PHP forum, but dont know if it is related. Thanks for your help
Re: [PHP] Re: LDAP
I found what was the problem :-( in PHP.ini the Temp directory was not setup the same. i do not know what is the link with LDAP module, but since i updated php.ini, it works correctly. Alain On 8/21/07, Colin Guthrie [EMAIL PROTECTED] wrote: Alain Roger wrote: Hi, I have a stupid issue with ldap_connect. i've reinstalled PHP, postgreSQL and restore my data (web files) after reinstalling my PC. now, when i try : $ds = ldap_connect($ldaphost, $ldapport) or die(Could not connect to $ldaphost); nothing works. i wrote before error_reporting(E_ALL); in order to check which error message i get, but nothing is return as error. what could be the problem ? Silly question but is the PHP you installed exactly the same as the previous one or did you select a different package? Perhaps PHP is compiled without ldap support or perhaps you've not installed the subpackage needed to enable ldap support. For me I have to install php-ldap subpackage. I would expect to see a fatal error saying no such function etc. so this is perhaps not the problem, but worth a look. Col -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- Alain Windows XP SP2 PostgreSQL 8.2.3 Apache 2.2.4 PHP 5.2.3
Re: [PHP] Server error
Hi dr Nick, The $_FILES autoglobal contains an error code if something went wrong. What is the code set to ? Regards, boro Humani Power schreef: Hi everybody. I have a Fedora Core 7 with php 5, and I want to upload an image. The funniest thing is that my script works fine in other computer but not in this one. I look for the error in /var/log/httpd/error.log and I found this [Tue Aug 21 15:52:46 2007] [notice] caught SIGTERM, shutting down [Tue Aug 21 15:55:32 2007] [notice] suEXEC mechanism enabled (wrapper: /usr/sbin/suexec) [Tue Aug 21 15:55:32 2007] [notice] Digest: generating secret for digest authentication ... [Tue Aug 21 15:55:32 2007] [notice] Digest: done [Tue Aug 21 15:55:33 2007] [notice] mod_python: Creating 4 session mutexes based on 256 max processes and 0 max threads. [Tue Aug 21 15:55:33 2007] [notice] mod_python: using mutex_directory /tmp [Tue Aug 21 15:55:34 2007] [notice] Apache/2.2.4 (Unix) DAV/2 PHP/5.2.2 mod_python/3.3.1 Python/2.5 mod_ssl/2.2.4 OpenSSL/0.9.8b mod_perl/2.0.3 Perl/v5.8.8 configured -- resuming normal operations I know that this is PHP forum, but dont know if it is related. Thanks for your help -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] keeping fields moving forward
I am creating a series of forms that collect information this covers 3 screens before I want to write it out to the database. when I go from one screen to the next I have tried hidden and readonly input boxes but the data in the hidden and readonly fields from screen one do not make it to the final page. Is there a way to get the data from page one without letting the users modify the information. I guess I could write the data to the database but how do I find the record number of the data I just wrote so that I can update the information, will php tell me the record number? I am using php 5.2.1 and mysql 5.x thanks for your help. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] keeping fields moving forward
Is there a way to get the data from page one without letting the users modify the information. I guess I could write the data to the database Or you could store the data in the session space... thnx, Chris -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Re: About Session And Cookies
Am 2007-08-17 22:07:47, schrieb Bastien Koert: If cookies are not available, you can either hide the id in the hidden form field element or enable trans_sid to automatically pass the session id in the url This will be a security risk since Session-Hijacker can grap the URL Greetings Michelle Konzack Systemadministrator Tamay Dogan Network Debian GNU/Linux Consultant -- Linux-User #280138 with the Linux Counter, http://counter.li.org/ # Debian GNU/Linux Consultant # Michelle Konzack Apt. 917 ICQ #328449886 50, rue de Soultz MSN LinuxMichi 0033/6/6192519367100 Strasbourg/France IRC #Debian (irc.icq.com) signature.pgp Description: Digital signature
Re: [PHP] keeping fields moving forward
Mike Ryan wrote: I am creating a series of forms that collect information this covers 3 screens before I want to write it out to the database. when I go from one screen to the next I have tried hidden and readonly input boxes but the data in the hidden and readonly fields from screen one do not make it to the final page. Is there a way to get the data from page one without letting the users modify the information. I guess I could write the data to the database but how do I find the record number of the data I just wrote so that I can update the information, will php tell me the record number? I am using php 5.2.1 and mysql 5.x thanks for your help. Are working with the data from Form 1 before going to form 2 and so forth? If you are not, then you could look into a three layered div with tabs and keep it all on one page. -- Jim Lucas Some men are born to greatness, some achieve greatness, and some have greatness thrust upon them. Twelfth Night, Act II, Scene V by William Shakespeare -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] keeping fields moving forward
Jim Lucas [EMAIL PROTECTED] wrote in message news:[EMAIL PROTECTED] Mike Ryan wrote: I am creating a series of forms that collect information this covers 3 screens before I want to write it out to the database. when I go from one screen to the next I have tried hidden and readonly input boxes but the data in the hidden and readonly fields from screen one do not make it to the final page. Is there a way to get the data from page one without letting the users modify the information. I guess I could write the data to the database but how do I find the record number of the data I just wrote so that I can update the information, will php tell me the record number? I am using php 5.2.1 and mysql 5.x thanks for your help. Are working with the data from Form 1 before going to form 2 and so forth? If you are not, then you could look into a three layered div with tabs and keep it all on one page. -- Jim Lucas Some men are born to greatness, some achieve greatness, and some have greatness thrust upon them. Twelfth Night, Act II, Scene V by William Shakespeare yes I get information from form one transfers to form two ok but then does not show up on form 3. form 1 and 2 do not then save to the database after the last page of form 3. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] LDAP
Okay, hopefully someone can help me out here. I've gone over ldap at
php.net and multiple other sites but can't get it to work. Everytime I run
the query my results are 0 entries returned.
My AD tree is: CN=Users,DC=domain,DC=us. I have the AD Server set so that
anonymous access to retrieve information is enabled.
Below is my code. Any ideas?
?php
$ldap_host = AD Server;
$ldap_port = 389;
$base_dn = DC=domain,DC=us;
$filter = (CN=users);
$connect = ldap_connect( $ldap_host, $ldap_port);
ldap_set_option($connect, LDAP_OPT_PROTOCOL_VERSION, 3);
$bind = ldap_bind($connect);
$read = ldap_search($connect, $base_dn, $filter);
$info = ldap_get_entries($connect, $read);
echo $info[count]. entries returnedBRBR;
for($row = 0; $row$info[count]; $row++)
{
for($column = 0; $column$info[$row][count]; $column++)
{
$data = $info[$row][$column];
echo $data.:.$info[$row][$data][0].BR;
}
echo BR;
}
ldap_close($connect);
?
Re: [PHP] LDAP
On 8/21/07, Dan Shirah [EMAIL PROTECTED] wrote:
Okay, hopefully someone can help me out here. I've gone over ldap at
php.net and multiple other sites but can't get it to work. Everytime I run
the query my results are 0 entries returned.
My AD tree is: CN=Users,DC=domain,DC=us. I have the AD Server set so that
anonymous access to retrieve information is enabled.
Below is my code. Any ideas?
?php
$ldap_host = AD Server;
$ldap_port = 389;
$base_dn = DC=domain,DC=us;
$filter = (CN=users);
$connect = ldap_connect( $ldap_host, $ldap_port);
ldap_set_option($connect, LDAP_OPT_PROTOCOL_VERSION, 3);
$bind = ldap_bind($connect);
$read = ldap_search($connect, $base_dn, $filter);
$info = ldap_get_entries($connect, $read);
echo $info[count]. entries returnedBRBR;
for($row = 0; $row$info[count]; $row++)
{
for($column = 0; $column$info[$row][count]; $column++)
{
$data = $info[$row][$column];
echo $data.:.$info[$row][$data][0].BR;
}
echo BR;
}
ldap_close($connect);
?
This may be kind of a dumb question but did you check your
firewall settings?
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[office] (570-) 587-7080 Ext. 272
[mobile] (570-) 766-8107
Hey, PHP-General list
50% off for life on web hosting plans $10/mo. or more at
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Re: [PHP] keeping fields moving forward
Mike Ryan wrote: yes I get information from form one transfers to form two ok but then does not show up on form 3. form 1 and 2 do not then save to the database after the last page of form 3. That wasn't my question. Again, when you submit form 1, do you do any processing of the data that came in from form 1 and then place that data inside form 2, and then when form 2 is submitted do you process the data in any way before inserting it into form 3? I understand what you are doing with form 3, but I am wondering about form 1 and form 2. Do you process any of the data from form 1 2 before submitting all the data with form 3? -- Jim Lucas Some men are born to greatness, some achieve greatness, and some have greatness thrust upon them. Twelfth Night, Act II, Scene V by William Shakespeare -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] LDAP
Nothing is being blocked since both servers are inside the DMZ.
On 8/21/07, Daniel Brown [EMAIL PROTECTED] wrote:
On 8/21/07, Dan Shirah [EMAIL PROTECTED] wrote:
Okay, hopefully someone can help me out here. I've gone over ldap at
php.net and multiple other sites but can't get it to work. Everytime I
run
the query my results are 0 entries returned.
My AD tree is: CN=Users,DC=domain,DC=us. I have the AD Server set so
that
anonymous access to retrieve information is enabled.
Below is my code. Any ideas?
?php
$ldap_host = AD Server;
$ldap_port = 389;
$base_dn = DC=domain,DC=us;
$filter = (CN=users);
$connect = ldap_connect( $ldap_host, $ldap_port);
ldap_set_option($connect, LDAP_OPT_PROTOCOL_VERSION, 3);
$bind = ldap_bind($connect);
$read = ldap_search($connect, $base_dn, $filter);
$info = ldap_get_entries($connect, $read);
echo $info[count]. entries returnedBRBR;
for($row = 0; $row$info[count]; $row++)
{
for($column = 0; $column$info[$row][count]; $column++)
{
$data = $info[$row][$column];
echo $data.:.$info[$row][$data][0].BR;
}
echo BR;
}
ldap_close($connect);
?
This may be kind of a dumb question but did you check your
firewall settings?
--
Daniel P. Brown
[office] (570-) 587-7080 Ext. 272
[mobile] (570-) 766-8107
Hey, PHP-General list
50% off for life on web hosting plans $10/mo. or more at
http://www.pilotpig.net/.
Use the coupon code phpgeneralaug07
Register domains for about $0.01 more than what it costs me at
http://domains.pilotpig.net/.
Re: [PHP] php 4.4.7 make install with pear causes zend freeing errors
The compiler complaining about free'ing memory is something they should pay attention to as far as I'm concerned. *shrug* Clearly I should've read the thread better, somehow I missed that entirely -.- sorry bout that :) anyway, first thing to do before posting is cutting down on your config options to the bare minimum to see if it's due to the core engine or some kind of extension, I'm sure they would appreciate it. I was assisted by Johannes Schl?ter. He told me the -enable-debug configure option was causing these error messages to be displayed. I removed that option and the error messages were no longer displayed. I am working towards getting all of our customers off of php4 now. Thanks for your assistance and pointers. JohnM -- john mendenhall [EMAIL PROTECTED] surf utopia internet services -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] php to generate java-script
Anyone have a good method of grabbing the current page and reading data
from it?
For example:
?PHP
// find all form fields for current page
function FindFormFields( $page ) {
if( empty( $page ) ) {
$data = -1;
} else {
if( ( $fh = @fopen( $page, r ) ) === FALSE ) {
$data = -1;
} else {
while( !feof( $fh ) ) {
$line = fgets( $fh, 512 );
if( eregi( input type=\, $line ) ) {
$data[] = $line;
}
}
fclose( $fh );
}
}
return $data;
}
echo FindFormFields( http://php.net; );
?
The above code would output the following:
Array
(
[0] =input type=text name=pattern value= size=30
accesskey=s /
[1] =input type=image
)
Now for the problem I am having and a description of what I am trying to
accomplish:
I want to dynamically generate a form and in doing so I would like to
dynamically generate the following javascript features for said page
- javascript form validation
- javascript form field focus
The problem is if I call the current page that is being generated such as
?PHP
echo FindFormFields( http://; . $_SERVER['SERVER_NAME'] .
$_SERVER['REQUEST_URI'] );
?
Not only does it take a helluva long time to load the page but it also
creates a nested array with duplicate values.
My best guess is that the order in which the page is being generated has
something to do with the lag as well as the nested array with duplicate
values.
Could anyone help me or point me in a better direction for performing
these actions?
Thanks in advance,
Jas
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[PHP] LDAP ***RESOLVED***
Apparently even though our Domain Administrator said anonymous access is
enabled for the server, it still did not like me trying to query AD
anonymously. I created a username/password with limited priviledges to AD
and now it works like a charm.
Below you will find my finished code:
?php
$base_dn=CN=users,DC=domain,DC=us;
$ldap_host=AD server;
$ldap_port=389;
$ldap_user=CN=username, CN=Users, DC=domain, DC=us;
$ldap_pass=password;
$filter=((objectclass=user)(Description=My Organization)(cn=*));
$connect = ldap_connect( $ldap_host, $ldap_port)
or exit(Could not connect to LDAP server);
ldap_set_option($connect, LDAP_OPT_PROTOCOL_VERSION, 3);
ldap_set_option($connect, LDAP_OPT_REFERRALS, 0);
$bind = ldap_bind($connect, $ldap_user, $ldap_pass)
or exit(Could not bind to $ldap_host);
$read = ldap_search($connect, $base_dn, $filter)
or exit(Unable to search ldap server);
$info = ldap_get_entries($connect, $read);
echo $info[count]. entries returnedp;
$ii=0;
for ($i=0; $ii$info[$i][count]; $ii++){
$data = $info[$i][$ii];
echo $data.:nbsp;nbsp;.$info[$i][$data][0].br;
}
ldap_close($connect);
?
Re: [PHP] keeping fields moving forward
Mike Ryan wrote: I am creating a series of forms that collect information this covers 3 screens before I want to write it out to the database. when I go from one screen to the next I have tried hidden and readonly input boxes but the data in the hidden and readonly fields from screen one do not make it to the final page. Is there a way to get the data from page one without letting the users modify the information. I guess I could write the data to the database but how do I find the record number of the data I just wrote so that I can update the information, will php tell me the record number? I am using php 5.2.1 and mysql 5.x I'd write a class to handle the submissions; I pretty much always do this with forms. Instantiate the object on the first submit, populate with whatever from form 1, do your validation, store the object in the session and display form 2. Repeat. You could give the class methods to handle setting each field and validation methods for each form. When all is done, call persist() and you're done. Just remember to include() your class file before calling session_start(). As an aside, whenever i'm displaying a form i instantiate the class first. This way, my form markup can have, eg: input type=text name=foo value=?= my_class-getFoo() ? / so that on the first pass the empty object returns NULL. When i want to re-display the form (because there was an error somewhere) the already-populated vars are written back to the form. brian -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] php to generate java-script
Jas wrote:
Anyone have a good method of grabbing the current page and reading data
from it?
For example:
?PHP
// find all form fields for current page
function FindFormFields( $page ) {
if( empty( $page ) ) {
$data = -1;
} else {
if( ( $fh = @fopen( $page, r ) ) === FALSE ) {
$data = -1;
} else {
while( !feof( $fh ) ) {
$line = fgets( $fh, 512 );
if( eregi( input type=\, $line ) ) {
$data[] = $line;
}
}
fclose( $fh );
}
}
return $data;
}
echo FindFormFields( http://php.net; );
?
The above code would output the following:
Array
(
[0] =input type=text name=pattern value= size=30
accesskey=s /
[1] =input type=image
)
Now for the problem I am having and a description of what I am trying to
accomplish:
I want to dynamically generate a form and in doing so I would like to
dynamically generate the following javascript features for said page
- javascript form validation
- javascript form field focus
The problem is if I call the current page that is being generated such as
?PHP
echo FindFormFields( http://; . $_SERVER['SERVER_NAME'] .
$_SERVER['REQUEST_URI'] );
?
Not only does it take a helluva long time to load the page but it also
creates a nested array with duplicate values.
I'm not surprised it's taking a while to load in your browser. I think
you have a serious nested loop issue there. What you're doing is telling
the PHP engine to load the same page again. When it does that it's going
to call your function *again* on the same page. Rinse and repeat.
But i don't understand what putting those tags in an array is going to
accomplish. Perhaps there's a lot more to this, but i'd be inclined to
set up my validation in a more targetted manner.
brian
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[PHP] php/mysql - getting ID of query
This is as much a mysql question as it is php. What is the most reliable way to retrieve an auto_increment key/id for a query you just inserted? In other words, I compile all my data, insert it into a new row, and now I want to retrieve the ID it created for it in the ID/key field. Without turning around and searching for the values I just inserted, is there a way to get the ID? The ID is the only field that is guaranteed to be unique in each data set, which makes it questionable to search for the data you just inserted, unless you searched for the *whole* data set. Thanks John
Re: [PHP] php/mysql - getting ID of query
mysql_insert_id() mysqli_insert_id() http://us.php.net/mysql is your friend :) http://us.php.net/mysqli too! On 8/21/07, John Pillion [EMAIL PROTECTED] wrote: This is as much a mysql question as it is php. What is the most reliable way to retrieve an auto_increment key/id for a query you just inserted? In other words, I compile all my data, insert it into a new row, and now I want to retrieve the ID it created for it in the ID/key field. Without turning around and searching for the values I just inserted, is there a way to get the ID? The ID is the only field that is guaranteed to be unique in each data set, which makes it questionable to search for the data you just inserted, unless you searched for the *whole* data set. Thanks John -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Re: php/mysql - getting ID of query
John Pillion wrote: This is as much a mysql question as it is php. What is the most reliable way to retrieve an auto_increment key/id for a query you just inserted? In other words, I compile all my data, insert it into a new row, and now I want to retrieve the ID it created for it in the ID/key field. Without turning around and searching for the values I just inserted, is there a way to get the ID? The ID is the only field that is guaranteed to be unique in each data set, which makes it questionable to search for the data you just inserted, unless you searched for the *whole* data set. Thanks John mysql_insert_id() mysqli::insert_id PDO::lastInsertId() depending on the way you access it. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Re: keeping fields moving forward
I think I have it fixed I had some code wrong in my input hidden variable this worked and did the job for me I am an old time type of programmer who is not very good with the object oriented programming and have not taken the time to learn some new tricks. one day I will. Mike Ryan [EMAIL PROTECTED] wrote in message news:[EMAIL PROTECTED] I am creating a series of forms that collect information this covers 3 screens before I want to write it out to the database. when I go from one screen to the next I have tried hidden and readonly input boxes but the data in the hidden and readonly fields from screen one do not make it to the final page. Is there a way to get the data from page one without letting the users modify the information. I guess I could write the data to the database but how do I find the record number of the data I just wrote so that I can update the information, will php tell me the record number? I am using php 5.2.1 and mysql 5.x thanks for your help. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] RE: php/mysql - getting ID of query
Thanks guys, that's exactly what I was looking for J -Original Message- From: M. Sokolewicz [mailto:[EMAIL PROTECTED] Sent: Tuesday, August 21, 2007 4:51 PM To: John Pillion Cc: php-general@lists.php.net Subject: Re: php/mysql - getting ID of query John Pillion wrote: This is as much a mysql question as it is php. What is the most reliable way to retrieve an auto_increment key/id for a query you just inserted? In other words, I compile all my data, insert it into a new row, and now I want to retrieve the ID it created for it in the ID/key field. Without turning around and searching for the values I just inserted, is there a way to get the ID? The ID is the only field that is guaranteed to be unique in each data set, which makes it questionable to search for the data you just inserted, unless you searched for the *whole* data set. Thanks John mysql_insert_id() mysqli::insert_id PDO::lastInsertId() depending on the way you access it. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Programmer in the US?
Hi there!
I spent the last 4 Years ('03-'07) as an Officer with the German Air Force
collecting massive experience with large university networks (programming,
maintenance) and on electronic warfare live training exercises (management,
IT Officer), but I studied Space and Aeronautics and did not finish. I have
programming experience in C/C++ since '99 and PHP/html/jscript since '01. I
do not have a diploma or degree or anything. Only a military record that
tells what I did, and that I did it good! ;-)
Sine I see from some of your signatures that some of you are working at US
based companies, do you have any tips or experiences how to start off as a
programmer or technical manager with such a bad starting position?
Getting a greencard once I got a job shouldn't be a problem since I'm
cleared up to NATO-Secret. (if that helps)
Thank you very much for any help, tips, experiences ...
Best Regards,
Jan
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Re: [PHP] php to generate java-script
i agree with brian.
i still need to enhance my skills w/ javascirpt, but i think in the case of
validation, a simple
solution is to write generic validation components in javascript. then
simply dynamically
include the ones you need for a particular form.
as far as the javascript knowing how to locate the form fields i think its a
matter of defining
a naming convention w/in your system.
-nathan
On 8/21/07, brian [EMAIL PROTECTED] wrote:
Jas wrote:
Anyone have a good method of grabbing the current page and reading data
from it?
For example:
?PHP
// find all form fields for current page
function FindFormFields( $page ) {
if( empty( $page ) ) {
$data = -1;
} else {
if( ( $fh = @fopen( $page, r ) ) === FALSE ) {
$data = -1;
} else {
while( !feof( $fh ) ) {
$line = fgets( $fh, 512 );
if( eregi( input type=\, $line ) ) {
$data[] = $line;
}
}
fclose( $fh );
}
}
return $data;
}
echo FindFormFields( http://php.net; );
?
The above code would output the following:
Array
(
[0] =input type=text name=pattern value= size=30
accesskey=s /
[1] =input type=image
)
Now for the problem I am having and a description of what I am trying to
accomplish:
I want to dynamically generate a form and in doing so I would like to
dynamically generate the following javascript features for said page
- javascript form validation
- javascript form field focus
The problem is if I call the current page that is being generated such
as
?PHP
echo FindFormFields( http://; . $_SERVER['SERVER_NAME'] .
$_SERVER['REQUEST_URI'] );
?
Not only does it take a helluva long time to load the page but it also
creates a nested array with duplicate values.
I'm not surprised it's taking a while to load in your browser. I think
you have a serious nested loop issue there. What you're doing is telling
the PHP engine to load the same page again. When it does that it's going
to call your function *again* on the same page. Rinse and repeat.
But i don't understand what putting those tags in an array is going to
accomplish. Perhaps there's a lot more to this, but i'd be inclined to
set up my validation in a more targetted manner.
brian
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Re: [PHP] Re: About Session And Cookies
Hello, thanks for all the replies. However, since I'm not very familiar with trans_sid I'll do some research on that. Michelle Konzack, if hiding the id in hidden form field element or enabling trans_sid could lead to security risks, what would you recommend as an alternative method to safely transfer user information across different pages in a website? Thank you. On 8/18/07, Michelle Konzack [EMAIL PROTECTED] wrote: Am 2007-08-17 22:07:47, schrieb Bastien Koert: If cookies are not available, you can either hide the id in the hidden form field element or enable trans_sid to automatically pass the session id in the url This will be a security risk since Session-Hijacker can grap the URL Greetings Michelle Konzack Systemadministrator Tamay Dogan Network Debian GNU/Linux Consultant -- Linux-User #280138 with the Linux Counter, http://counter.li.org/ # Debian GNU/Linux Consultant # Michelle Konzack Apt. 917 ICQ #328449886 50, rue de Soultz MSN LinuxMichi 0033/6/6192519367100 Strasbourg/France IRC #Debian (irc.icq.com)
