Re: [PHP] Object Overloading in PHP5
Daniel Schierbeck wrote:
Stefan wrote:
It's a bug.
* Siehe http://bugs.php.net/bug.php?id=28444 ... und ...
* http://news.php.net/php.bugs/63652
A workaround is possible using __call( $name, $args) { return(
$this-__get( $name)); }. But it sucks, since constructs using array
indices are impossible as $obj-not_existing_attr()[0]
regards
Daniel Schierbeck wrote:
Do you guys have any idea why this code:
?php
class Foo
{
private $elem = array();
public function __get ($prop)
{
if (isset($this-elem[$prop])) {
return $this-elem[$prop];
} else {
trigger_error(Property '$prop' not defined,
E_USER_ERROR);
}
}
public function __set ($prop, $val)
{
$this-elem[$prop] = $val;
}
}
$obj = new Foo;
$obj-a = new Foo;
$obj-a-b = Foobar;
?
returns this:
Fatal error: Cannot access undefined property for object with
overloaded property access in ... on line 24
Where line 24 is:
$obj-a-b = Foobar;
?
%!#%%(/)((%%!#%%#!%#!
Calm down, calm down... it's not good for your health :D
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Re: [PHP] Why won't my echo won't work? [newbie question]
John Nichel wrote: [EMAIL PROTECTED] wrote: The first two of these 3 echo statements work. But my last echo doesn't. 'username' is the name of the element I want to echo. To the right of each is what I see echoed. echo $_SERVER['REQUEST_METHOD']; echos - POST echo $_POST; echos - Array echo $_POST['username']; echos - nothing How are you setting $_POST['username']? Let's see the code for the form. Members in $_POST array are set (mostly) by submitting a form with POST method, make sure your form is not submitting by GET. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Dynamic HTML Creation
Sam Hobbs wrote: Ramil Sagum [EMAIL PROTECTED] wrote in message news:[EMAIL PROTECTED] Ah. You should have said this in your first mail (which was confusing). It now becomes clear. I think what you are looking for is a template engine, like smarty http://smarty.php.net/ If Smarty is a good solution that the other osCommerce users and developers agree is useful, then yes, I should have said more in my original question. If however Smarty is not a good solution for osCommerce, then explaining that I am modifying osCommerce would have been confusing and distracting. I like the idea of separating the UI from the program. Programmers and software designers have been doing that for many years. It is usually easier to keep the UI separate from the processing and then have tags of some type in the UI that allows the processing to put data into the UI and pluck it out. That type of thing can be done using HTML too. There are some disadvantages of using HTML and the DOM but I suspect there are limitations of Smarty too. If it is possible to use HTML and the DOM then there are significant advantages to using an existing standard that is in common use. If a web site is hosted in a server owned by someone else and if the server's owner (which includes the employees) must install Smarty befor it can be used, then that is a critical disadvantage of Smarty. So do you know of specific advantages of Smarty compated to using the HTML and DOM standards? Without spending a lot of time to learn Smarty, it is difficult for me to see the advantages. Smarty is a template engine, you can download it and embed it in your application, it's not necessary to 'install' it on the server. I suggest you read some overview of Smarty, you'll get the idea really fast. It's easy to understand... -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Re: attaching a custom icon to a file on server side
[EMAIL PROTECTED] wrote: I want to attach a custom icon to a dynamically created text file on the server-side when the user downloads the file to his desktop, there is a custom icon...ico file attached to it... is this possible ? g nah, you can't embed binary data (icon file) into text file... -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] User email changes verification strategy?
Hello, I'm adding some verification into my user database manager. After a while I come up with some ideas about asking user to verify their email address when they change their email address. But, the strategy is a lil confusing for me. When they change the email address. Where should the verification code be emailed to? Of course it's not the new addy, but what will happen if their old addy became unusable (so they change), can you guys come up with some ideas? I'm confusing... TIA -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] SOAP speed
Hello, I'm developing some site that will share the same UserDB, because these site are quite large in scale so I decided to host it on different servers. Each site will have it own cache of active user on the site, so the user wont' have to be authenticated every request (will be a pain in the a$$ I'm sure), the cache will be cleared when the session time out. But since I don't have much experience with these kind of distributed authenticate process with SOAP, so I wonder how long it will take to receive the response from the UserDB server using SOAP. There's a change that the site server will be located @ Europe, while the UserDB server will be located @ US (for global access). If the transmission time is about 1, 2 or even 3 secs, I think it acceptable. btw, do you have any experience about this? TIA -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] recompile your PHP installation with --with-mysql optio
Why did you set the dir to /usr/local/sql??? Did you have mysql there??? It's not the normal installation dir of mysql... Long P Nguyen wrote: I recompiled PHP with --with-mysql=/usr/local/sql and still got the following errors: Checking PHP configuration settings PHP version... success [4.2.2] DOMXML extension... success [2.4.23] MySQL extension failure [required-extension not installed] recompile your PHP installation with --with-mysql option -Original Message- From: John Nichel [mailto:[EMAIL PROTECTED] Sent: Monday, June 21, 2004 1:58 PM To: php-general Mailing List Subject: Re: [PHP] recompile your PHP installation with --with-mysql option Nguyen, Long P (Mission Systems) wrote: How do you recompile your PHP installation with --with-mysql option?? In the PHP source tree $ ./configure --with-mysql[=dir] --with-other-options $ make $ make install I'm sure this will bring a few questions. ;) -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] protecting your source code?
Surely you can't include files that way, that php file will be process and you will end up include its result. Try include using file system path instead, it will work... About your question about source code protecting, try Turck MMCache, it's a optimizer (the best I known) plus it have encode ability... finally, it's free :P~ Edward Peloke wrote: Thanks James, I have played with the Zend IDE a little...but will take a look. On a simpler scale, I usually have one main directory which then holds the subdirectories for classes, header, etc. then use includes to pull in header, classes, etc. I tried to call my classes from an external folder but can instantiate them..why? I seem to be able to pull them in...example include_once(http://www.peloke.com/myfolder/src/classes/classname.class.php ); but when I try to instantiate it, get an error that I can't $classname=new Classname(); Why? Thanks, Eddie -Original Message- From: James Harrell [mailto:[EMAIL PROTECTED] Sent: Monday, June 14, 2004 3:55 PM To: Edward Peloke; Php-General Subject: RE: [PHP] protecting your source code? Hi Edward, Check out the Zend Encoder: www.zend.com To run encoded/compiled programs, the server will need the (free) Zend Optimizer, available for download at the same location. Zend has a small-business program that if your yearly revenues are less than some magic number, you get a major discount on the Zend Suite which includes the encoder and the development environment. The Zend Development Environment is fantastic- includes a debugger and profiler, code completion, etc. After 10+ years as a vi-guy, I actually made the switch recently. :) James -Original Message- From: Edward Peloke [mailto:[EMAIL PROTECTED] Sent: Monday, June 14, 2004 3:50 PM To: Php-General Subject: [PHP] protecting your source code? I wrote a bunch of code that will be used for a local site. I usually do all my hosting with a friend who I trust...the new site will be hosted by another company in town (not my choosing) who I don't necessarily trust to not copy the code and reuse it for other sites. How can I protect the code? I know there are some encoders but I have never used them. Thanks, Eddie WARNING: The information contained in this message and any attachments is intended only for the use of the individual or entity to which it is addressed. This message may contain information that is privileged, confidential and exempt from disclosure under applicable law. It may also contain trade secrets and other proprietary information for which you and your employer may be held liable for disclosing. You are hereby notified that any unauthorized dissemination, distribution or copying of this communication is strictly prohibited. If you have received this communication in error, please notify [EMAIL PROTECTED] by E-Mail and then destroy this communication in a manner appropriate for privileged information. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Behaviour of get_class_methods() and get_class_vars()
This copy directly from my bug report, someone here do you know any way
around for this problem.
--
Description:
When get_class_vars() return every properties of the class, private and
protected members are mark with [Class Name] and * before its name, well
it better being mark with + or - or # (like UML standard).
Also, this function shouldn't return value of the property as private
and protected can only be expose in the scope that have access
permission.
Next, get_class_methods() also return every methods the class have,
without any marking method?!?! What's the point doing that if I can't
figure out if I can access the class's method or not.
I suggest these two function should return all attributes and methods
with its access marking.
And another function, maybe get_class_vars_value() to expose default
value of attributes in the class, this function should return value of
accessible attribute, too.
Reproduce code:
---
?php
class ClassA
{
private $PrivateVar = null;
protected $ProtectedVar = null;
public $PublicVar = null;
private function PrivateFunc()
{}
protected function ProtectedFunc()
{}
public function PublicFunc()
{}
}
var_dump(get_class_vars('ClassA'));
var_dump(get_class_methods('ClassA'));
?
Expected result:
array(3) {
[PrivateVar] = string(1) -
[ * ProtectedVar] = string(1) #
[PublicVar] = string(1) +
}
array(3) {
[PrivateFunc] = string(1) -
[ProtectedFunc] = string(1) #
[PublicFunc] = string(1) +
}
Actual result:
--
array(3) {
[ ClassA PrivateVar] = NULL
[ * ProtectedVar] = NULL
[PublicVar] = NULL
}
array(3) {
[0]= string(11) PrivateFunc
[1]= string(13) ProtectedFunc
[2]= string(10) PublicFunc
}
--
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[PHP] [PHP5] Super constructor?
Hi guys, hey don't laugh at the subject, in fact I don't what to call
it, so let's call it super constructor :D
Let's see following code...
class Base
{
__construct()
{
// Do something
}
}
class One extends Base
{
__construct()
{
// Do nothing
}
}
class OneMore extends One
{
__construct()
{
// Do things :D
}
}
So when I create an instance of OneMore class by:
$OneMoreInstance = new OneMore()
The __construct() method of class OneMore will be called, not the one of
One and Base, right?
So is there any way around to make the Base class have a contructor that
will be called everytime one of its child initialize?
My problem, I want all of the classes in my object are extend from one
base class, so they are all have some common properties and function,
but PHP won't implicit call the contructor (that's the right way)...
btw, in my case, this is bad, as bad as every constructor would be called...
Well, hope you understand what I'm trying to say...
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Re: [PHP] [PHP5] Super constructor?
Yeah you understood me, thanks god :D but not fully :(
But the problem is right in your code (sorry :D)
What if I create an instance of ChildClass, its constructor won't be
called (since it commented out), but if I un-comment its constructor, it
will be called even if I create an instance of GrandChildClass?
Let me make some simple diagram ;)
Class1 -- Class2 -- Class3 -- Class4
If I create an instance of Class4, then Class4's constructor and
Class1's constructor must be called, neither Class3 nor Class2.
You can see that Class1's constructor will always be called, and the
constructor of the lowest class in the class tree will be called.
I think this is a bit complex, I can define a final function in Class1,
and call it in every deriver class constructor, it will solve the
problem (I think) but it's not convenience, I want it done automatically...
Any idea are welcome :D
Chris wrote:
FrzzMan wrote:
Hi guys, hey don't laugh at the subject, in fact I don't what to call
it, so let's call it super constructor :D
Let's see following code...
class Base
{
__construct()
{
// Do something
}
}
class One extends Base
{
__construct()
{
// Do nothing
}
}
class OneMore extends One
{
__construct()
{
// Do things :D
}
}
So when I create an instance of OneMore class by:
$OneMoreInstance = new OneMore()
The __construct() method of class OneMore will be called, not the one
of One and Base, right?
So is there any way around to make the Base class have a contructor
that will be called everytime one of its child initialize?
My problem, I want all of the classes in my object are extend from one
base class, so they are all have some common properties and function,
but PHP won't implicit call the contructor (that's the right way)...
btw, in my case, this is bad, as bad as every constructor would be
called...
Well, hope you understand what I'm trying to say...
I'm not positive I understand you correctly, but I think this will
answer your question.
Example Classes:
class ParentClass
{
function __construct()
{
echo 'ParentClass::__construct()',\r\n;
}
}
class ChildClass extends ParentClass
{
/*
function __construct()
{
parent::__construct();
echo 'ChildClass::__construct()',\r\n;
}
//*/
}
class GrandChildClass extends ChildClass
{
function __construct()
{
parent::__construct();
echo 'GrandChildClass::__construct()',\r\n;
}
}
__construct is just like any other method, if you overload it (redefine
it in a child class), the parent method will not be called
automatically, so, if you want the functionality of both, you can call
the parent constructor from the childs constructor. If the direct parent
doesn't have a constructor, the next parent's constructor is checked and
so on.
In the above example when defining a GrandChildClass, its constructor
and the ParentClass::__construct() are will both run. If you uncomment
ChildClass::__construct(), it will run as well.
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Re: [PHP] [PHP5] Super constructor?
Try var_dump($GrandChildClass) or print_r($GrandChildClass) everytime
you need to inspect variable content. Not echo...
PS: Hi there Vietnamese guy, same here ;)
Chris wrote:
Because /$GrandChildClass;/ Is an object. So when you go to echo it, PHP
tries to convert it to a string.
Pham Cong Dinh wrote:
Hi all,
I tested Chris's code:
?php
class *ParentClass*
{
function __construct()
{
echo 'ParentClass::__construct()',\r\n;
}
}
class *ChildClass *extends ParentClass
{
/*
function __construct()
{
parent::__construct();
echo 'ChildClass::__construct()',\r\n;
}
//*/
}
class *GrandChildClass *extends ChildClass
{
function __construct()
{
parent::__construct();
echo 'GrandChildClass::__construct()',\r\n;
}
}
$GrandChildClass = new GrandChildClass();
echo $GrandChildClass;
?
It resulted:
ParentClass::__construct()
GrandChildClass::__construct()
Object id #1
Could anyone kindly tell me why the string Object id #1 is printed?
Thanks
Dinh
Chris wrote:
FrzzMan wrote:
Hi guys, hey don't laugh at the subject, in fact I don't what to
call it, so let's call it super constructor :D
Let's see following code...
class Base
{
__construct()
{
// Do something
}
}
class One extends Base
{
__construct()
{
// Do nothing
}
}
class OneMore extends One
{
__construct()
{
// Do things :D
}
}
So when I create an instance of OneMore class by:
$OneMoreInstance = new OneMore()
The __construct() method of class OneMore will be called, not the
one of One and Base, right?
So is there any way around to make the Base class have a contructor
that will be called everytime one of its child initialize?
My problem, I want all of the classes in my object are extend from
one base class, so they are all have some common properties and
function, but PHP won't implicit call the contructor (that's the
right way)... btw, in my case, this is bad, as bad as every
constructor would be called...
Well, hope you understand what I'm trying to say...
I'm not positive I understand you correctly, but I think this will
answer your question.
Example Classes:
class ParentClass
{
function __construct()
{
echo 'ParentClass::__construct()',\r\n;
}
}
class ChildClass extends ParentClass
{
/*
function __construct()
{
parent::__construct();
echo 'ChildClass::__construct()',\r\n;
}
//*/
}
class GrandChildClass extends ChildClass
{
function __construct()
{
parent::__construct();
echo 'GrandChildClass::__construct()',\r\n;
}
}
__construct is just like any other method, if you overload it
(redefine it in a child class), the parent method will not be called
automatically, so, if you want the functionality of both, you can
call the parent constructor from the childs constructor. If the
direct parent doesn't have a constructor, the next parent's
constructor is checked and so on.
In the above example when defining a GrandChildClass, its constructor
and the ParentClass::__construct() are will both run. If you
uncomment ChildClass::__construct(), it will run as well.
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