[PHP] Using PHP4 4.3.4 as a CGI
Debian testing system with a recent update to php-cgi 4.3.4. I have been using the /usr/bin/php4 binary as a some.cgi with a shbang line of "#!/usr/bin/php4" which worked fine up until this recent 4.3.4 update. Now the new 4.3.4 php4 binary does not produce a "Content-type: index/html\n\n" header nor does it receive any GPC (GET POST etc) variables at all. I've been throught the new php.ini and I cannot see any parameters or advice as to what may have changed. Could anyone advise me how to re-enable receiving incoming variables for a /usr/bin/php4 binary used as a CGI please ? --markc -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] default and another constructor
On Wed, 12 May 2004 11:27 pm, Rudy Metzger wrote: > On Wed, 2004-05-12 at 15:18, Mark Constable wrote: > > You can at least make the below work by removing the first > > forum() instance and using > > > > function forum($naam=NULL,$tijd=NULL,$tekst=NULL) > > > > and test the incoming variables with isset() before attempting > > to use any of them. > > If you assign default values to the method arguments, you cannot test > them with isset() anymore, as they will be set. # cat null_test.php # php null_test.php 'hi' NULL NULL --markc -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] default and another constructor
On Wed, 12 May 2004 10:43 pm, Lieve Vissenaeken wrote:
> Please ,could anybody help me ? I'm not so familiar with PHP.
>
> I've the following problem with my code when I try to make an object from
> the class "forum" with the code "$test=new forum()". I always get a
> warning on this: "Warning: Missing argument 1 for forum() in
> /lvdata/www/tennis/php/sql.inc"
> Is it not possible to just make a default constructor and an other
> constructor like in JAVA ?
> Thanks for helping
No, you cannot do this kind of method overloading, not like
this anyway. If you are using PHP5 you can kind of emulate
overloading by using the __call() function... some googling
will find examples.
You can at least make the below work by removing the first
forum() instance and using
function forum($naam=NULL,$tijd=NULL,$tekst=NULL)
and test the incoming variables with isset() before attempting
to use any of them.
> class forum
> {
> var $naam;
> var $tijd;
> var $tekst;
>
> function forum()
> {
> }
>
> function forum($naam,$tijd,$tekst)
> {
> $this->naam=$naam;
> $this->tijd=$tijd;
> $this->tekst=$tekst;
> }
> }
>
>
> $test=new forum();
--markc
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Re: [PHP] parsing value by URL
On Wed, 12 May 2004 09:42 pm, gowthaman ramasamy wrote:
> I have a problem in passing the value to another PHP script from the
> first one. can any one help me to debug it.
>
> ENCTYPE="text/plain">
> if(isset($_POST['submit']))
> {
> does many things
>
> $detail_file='testrun_hetero_srtdout';
> echo " HREF=\"http:/gowtham/forphp/detailedresults.php?name=$detail_file&firstfile
>=$files\"> clik to see detailed page" }
> second script ... that is detailedresults.php
>print $name;
> print "$name";
> ?>
Perhaps "register_globals = Off" ? Here is one debugging hint...
';
// do whatever else
?>
and view the source of the resulting page. Assumes PHP v4.1.0+
--markc
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Re: [PHP] Methods for instatiating an object
On Wed, 12 May 2004 08:41 pm, Jordi Canals wrote: > A)$object = new MyClass; > B)$object =& new MyClass; > 1) In case A, PHP creates a new object and returns a Copy of this new > object, so really I will have the object two instances for the object in > memory ... > > 2) In case B, PHP creates a noew object and returns a reference to this > newly created object. In this case there is only one instance of the > object. > > Does it works that way? If not, What is exactly the difference? You are quite correct... http://php.net/references --markc -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Using PHP4 4.3.4 as a CGI
Debian testing system with a recent update to php-cgi 4.3.4. I have been using the /usr/bin/php4 binary as a some.cgi with a shbang line of "#!/usr/bin/php4" which worked fine up until this recent 4.3.4 update. Now the new 4.3.4 php4 binary does not produce a "Content-type: index/html\n\n" header nor does it receive any GPC (GET POST etc) variables at all. I've been throught the new php.ini and I cannot see any parameters or advice as to what may have changed. Could anyone advise me how to re-enable receiving incoming variables for a /usr/bin/php4 binary used as a CGI please ? --markc -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
