[PHP] Re: .htpasswd and PayPal generated passwords

2003-02-17 Thread Rob Packer
Hi David,
When using the IPN feature that PayPal offers, you can optionally have
them generate a username:password pair for you. That way it will be stored
at paypal and the user can check their history to retrieve it anytime.

Robert


David Duong [EMAIL PROTECTED] wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
 btw - What do you mean by paypal generated passwords?  I am interested in
 using PayPal as an alternative to my current credit card handler.

 Just a link is appreciated.

 - David


 Rob Packer [EMAIL PROTECTED] wrote in message
 [EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
  I use PayPal to generate a username and password and then write them
 to
  the .htpasswd file. If I were to switch to using a database (because
  .htaccess seems to always prompt twice!) how would I perform the
 comparison
  for the passwords? It would seem that everytime you generate an
encrypted
  password it's different. So how would you compare them? Also, does
anyone
  know what the encryption method used by PayPal is?
 
  Thanks for any help...
 
  Robert Packer
 
 





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[PHP] .htpasswd and PayPal generated passwords

2003-02-15 Thread Rob Packer
I use PayPal to generate a username and password and then write them to
the .htpasswd file. If I were to switch to using a database (because
.htaccess seems to always prompt twice!) how would I perform the comparison
for the passwords? It would seem that everytime you generate an encrypted
password it's different. So how would you compare them? Also, does anyone
know what the encryption method used by PayPal is?

Thanks for any help...

Robert Packer



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[PHP] check expiration date

2003-02-15 Thread Rob Packer
anyone know of a script for getting the current date and then calculating
when a provided expiration date would be?



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Re: [PHP] Test links?

2002-11-30 Thread Rob Packer
Well, the reason I didn't do that at first was that I could have done any of
the methods that I've tried incorrectly, which is why I figured I'd ask what
works and then focus on that method... but, I've tried to ping them, use
fopen, and use fsocketopen... but nothing says that I've used any of them
the way I should have :)  I also tried to use the scripts that I found at
hotscripts.com but I always seem to get inconsistent results and it must be
accurate.


Jason Wong [EMAIL PROTECTED] wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
 On Saturday 30 November 2002 06:53, Rob Packer wrote:
  First, I'd like to say that I'm not asking for anyone to write a
script...
  how would I go about checking a MySQL database of links to see if any
are
  down?
 
  I've had some varying results with all the methods I've tried, so would
  like to see if anyone has a proven method for doing this.

 Why don't you briefly summarise what methods you have tried? That way
people
 won't reply with methods that you already know of.

 --
 Jason Wong - Gremlins Associates - www.gremlins.biz
 Open Source Software Systems Integrators
 * Web Design  Hosting * Internet  Intranet Applications Development *

 /*
 Between grand theft and a legal fee, there only stands a law degree.
 */




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Re: [PHP] Test links?

2002-11-30 Thread Rob Packer
Okay, I'm confused... file, fopen, and fsockopen seem to say not found on
alot valid URLs...  does this look to be correct usage?
$url = $row[0]; // just get the url from the db
$fp = implode ('', file ($url));
 if (!$fp) {echo font color=redbUnable to access file/b/font; }
 else { fclose($fp); echo The link is working!; }

It seems I always get this warning...

Warning: Supplied argument is not a valid File-Handle resource in
/web/home/nrc.net/www/robert/links4.php on line 11

If someone can tell me what I'm doing wrong, I'd appreciate it.

Thanks,
Robert



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Re: [PHP] Test links?

2002-11-30 Thread Rob Packer
Thanks for the help and suggestions everybody!
I think some of my problems stemmed from the affiliate links being
redirected and PHP saw that as dead(so to speak)... but I think I got it
now. I made another column in the database to note a redirection for ones
that the url fails but the $url[host] passes.

Robert Packer


Chris Hewitt [EMAIL PROTECTED] wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
 Rob Packer wrote:

 Okay, I'm confused... file, fopen, and fsockopen seem to say not found on
 alot valid URLs...  does this look to be correct usage?
 $url = $row[0]; // just get the url from the db
 $fp = implode ('', file ($url));
  if (!$fp) {echo font color=redbUnable to access file/b/font; }
  else { fclose($fp); echo The link is working!; }
 
 It seems I always get this warning...
 
 Warning: Supplied argument is not a valid File-Handle resource in
 /web/home/nrc.net/www/robert/links4.php on line 11
 
 I think you have assigned $fp to be the imploded string, not a file
 pointer. Thus fclose($fp) would generate an error. Given this, I'm not
 sure what  if (!$fp) would mean.

 HTH
 Chris





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[PHP] Test links?

2002-11-29 Thread Rob Packer
First, I'd like to say that I'm not asking for anyone to write a script...
how would I go about checking a MySQL database of links to see if any are
down?

I've had some varying results with all the methods I've tried, so would like
to see if anyone has a proven method for doing this.

Thanks,
Robert




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[PHP] Insert an array into MySQL

2002-06-23 Thread Rob Packer

Hi, I've seen a few post for this same thing but I can't seem to get it
working. What I'm doing is taking a form with check boxes and putting them
into an array. Then I'm attempting to INSERT them into the db, one checkbox
value per row.

Okay,  well I've tries 2 ways that I think should work and they only insert
the first value. They both produce this error Duplicate entry '0' for key
1 (which I don't understand) Anyway here is the code I'm trying...

(I'm not trying to use both blocks of code, just one or the other)

// First code
while(list($key,$value)=each($pagetype)){
//echo $value.br;//test
$links=INSERT INTO $username_links (links) VALUES ('$value');
$insert=mysql_query($links,$connection);

}

// Second code attempt
$number=count($pagetype);
for($a=0;$a$number;$a++){
$links=INSERT INTO $username_links (links) VALUES ('$pagetype[$a]');
$insert=mysql_query($links) or die(mysql_error());
//echo $pagetype[$a];//test
}




Thanks in advance...Robert



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Re: [PHP] Insert an array into MySQL

2002-06-23 Thread Rob Packer


John Holmes [EMAIL PROTECTED] wrote in message
001201c21ab5$0df073a0$b402a8c0@mango">news:001201c21ab5$0df073a0$b402a8c0@mango...
 Your second method should work, but it's dependent on what your form
 looks like and how your table was created. You obviously have a key set
 for this column and you're trying to insert the same value twice, which
 makes an error.

 Show us what your form looks like, not the whole thing, just for the
 checkboxes. Also, what does your CREATE TABLE look like for the table
 your trying to insert this data into?

 ---John Holmes...

  -Original Message-
  From: Rob Packer [mailto:[EMAIL PROTECTED]]
  Sent: Sunday, June 23, 2002 7:50 AM
  To: [EMAIL PROTECTED]
  Subject: [PHP] Insert an array into MySQL
 
  Hi, I've seen a few post for this same thing but I can't seem to get
 it
  working. What I'm doing is taking a form with check boxes and putting
 them
  into an array. Then I'm attempting to INSERT them into the db, one
  checkbox
  value per row.
 
  Okay,  well I've tries 2 ways that I think should work and they only
  insert
  the first value. They both produce this error Duplicate entry '0' for
 key
  1 (which I don't understand) Anyway here is the code I'm trying...
 
  (I'm not trying to use both blocks of code, just one or the other)
 
  // First code
  while(list($key,$value)=each($pagetype)){
  //echo $value.br;//test
  $links=INSERT INTO $username_links (links) VALUES ('$value');
  $insert=mysql_query($links,$connection);
 
  }
 
  // Second code attempt
  $number=count($pagetype);
  for($a=0;$a$number;$a++){
  $links=INSERT INTO $username_links (links) VALUES ('$pagetype[$a]');
  $insert=mysql_query($links) or die(mysql_error());
  //echo $pagetype[$a];//test
  }
 
 
 
 
  Thanks in advance...Robert
 
 
 
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Re: [PHP] Insert an array into MySQL

2002-06-23 Thread Rob Packer

oops, sorry about the other post (I've got a baby that likes the
keyboard)...

Hi,

This is the form, which I had doubts about, but it seemed to put things into
the array correctly when I tested it by printing it out.
I can't see how, it will print
key=0
value=index.html
key=1
value=about.html
key=2
value=whats_new.html
when I test it and then have a duplicate key. It's saying that I have 2
$pagetype[0] correct? Anyhow, here's the form...

INPUT TYPE=hidden NAME=pagetype[] VALUE='index.html'Home Page br
INPUT TYPE=checkbox NAME=pagetype[] VALUE='about.html'About Page  br
INPUT TYPE=checkbox NAME=pagetype[] VALUE='whats_new.html'What's New
Pagebr
INPUT TYPE=checkbox NAME=pagetype[] VALUE='contact.html'Contact Pagebr
INPUT TYPE=checkbox NAME=pagetype[] VALUE='favorite_links.html'Favorite
Links br


The CREATE TABLE is this:
I define the table name from user input.

 $query_links=CREATE TABLE $username_links (id INT(4) not null, links
VARCHAR(20) not null, UNIQUE (id));
 if(mysql_query($query_links,$connection)){
  echo Links table created!br;
 }else{
  echo no links table madeBR;
 }




thanks,
 Rob




John Holmes [EMAIL PROTECTED] wrote in message
001201c21ab5$0df073a0$b402a8c0@mango">news:001201c21ab5$0df073a0$b402a8c0@mango...
 Your second method should work, but it's dependent on what your form
 looks like and how your table was created. You obviously have a key set
 for this column and you're trying to insert the same value twice, which
 makes an error.

 Show us what your form looks like, not the whole thing, just for the
 checkboxes. Also, what does your CREATE TABLE look like for the table
 your trying to insert this data into?

 ---John Holmes...

  -Original Message-
  From: Rob Packer [mailto:[EMAIL PROTECTED]]
  Sent: Sunday, June 23, 2002 7:50 AM
  To: [EMAIL PROTECTED]
  Subject: [PHP] Insert an array into MySQL
 
  Hi, I've seen a few post for this same thing but I can't seem to get
 it
  working. What I'm doing is taking a form with check boxes and putting
 them
  into an array. Then I'm attempting to INSERT them into the db, one
  checkbox
  value per row.
 
  Okay,  well I've tries 2 ways that I think should work and they only
  insert
  the first value. They both produce this error Duplicate entry '0' for
 key
  1 (which I don't understand) Anyway here is the code I'm trying...
 
  (I'm not trying to use both blocks of code, just one or the other)
 
  // First code
  while(list($key,$value)=each($pagetype)){
  //echo $value.br;//test
  $links=INSERT INTO $username_links (links) VALUES ('$value');
  $insert=mysql_query($links,$connection);
 
  }
 
  // Second code attempt
  $number=count($pagetype);
  for($a=0;$a$number;$a++){
  $links=INSERT INTO $username_links (links) VALUES ('$pagetype[$a]');
  $insert=mysql_query($links) or die(mysql_error());
  //echo $pagetype[$a];//test
  }
 
 
 
 
  Thanks in advance...Robert
 
 
 
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Re: [PHP] Insert an array into MySQL

2002-06-23 Thread Rob Packer

Nevermind, I got it. I had Unique for a field which made it mad.




Rob Packer [EMAIL PROTECTED] wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
 oops, sorry about the other post (I've got a baby that likes the
 keyboard)...

 Hi,

 This is the form, which I had doubts about, but it seemed to put things
into
 the array correctly when I tested it by printing it out.
 I can't see how, it will print
 key=0
 value=index.html
 key=1
 value=about.html
 key=2
 value=whats_new.html
 when I test it and then have a duplicate key. It's saying that I have 2
 $pagetype[0] correct? Anyhow, here's the form...

 INPUT TYPE=hidden NAME=pagetype[] VALUE='index.html'Home Page br
 INPUT TYPE=checkbox NAME=pagetype[] VALUE='about.html'About Page  br
 INPUT TYPE=checkbox NAME=pagetype[] VALUE='whats_new.html'What's New
 Pagebr
 INPUT TYPE=checkbox NAME=pagetype[] VALUE='contact.html'Contact Pagebr
 INPUT TYPE=checkbox NAME=pagetype[] VALUE='favorite_links.html'Favorite
 Links br


 The CREATE TABLE is this:
 I define the table name from user input.

  $query_links=CREATE TABLE $username_links (id INT(4) not null, links
 VARCHAR(20) not null, UNIQUE (id));
  if(mysql_query($query_links,$connection)){
   echo Links table created!br;
  }else{
   echo no links table madeBR;
  }




 thanks,
  Rob




 John Holmes [EMAIL PROTECTED] wrote in message
 001201c21ab5$0df073a0$b402a8c0@mango">news:001201c21ab5$0df073a0$b402a8c0@mango...
  Your second method should work, but it's dependent on what your form
  looks like and how your table was created. You obviously have a key set
  for this column and you're trying to insert the same value twice, which
  makes an error.
 
  Show us what your form looks like, not the whole thing, just for the
  checkboxes. Also, what does your CREATE TABLE look like for the table
  your trying to insert this data into?
 
  ---John Holmes...
 
   -Original Message-----
   From: Rob Packer [mailto:[EMAIL PROTECTED]]
   Sent: Sunday, June 23, 2002 7:50 AM
   To: [EMAIL PROTECTED]
   Subject: [PHP] Insert an array into MySQL
  
   Hi, I've seen a few post for this same thing but I can't seem to get
  it
   working. What I'm doing is taking a form with check boxes and putting
  them
   into an array. Then I'm attempting to INSERT them into the db, one
   checkbox
   value per row.
  
   Okay,  well I've tries 2 ways that I think should work and they only
   insert
   the first value. They both produce this error Duplicate entry '0' for
  key
   1 (which I don't understand) Anyway here is the code I'm trying...
  
   (I'm not trying to use both blocks of code, just one or the other)
  
   // First code
   while(list($key,$value)=each($pagetype)){
   //echo $value.br;//test
   $links=INSERT INTO $username_links (links) VALUES ('$value');
   $insert=mysql_query($links,$connection);
  
   }
  
   // Second code attempt
   $number=count($pagetype);
   for($a=0;$a$number;$a++){
   $links=INSERT INTO $username_links (links) VALUES ('$pagetype[$a]');
   $insert=mysql_query($links) or die(mysql_error());
   //echo $pagetype[$a];//test
   }
  
  
  
  
   Thanks in advance...Robert
  
  
  
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[PHP] not so

2002-06-08 Thread Rob Packer

[0] would match the whole ip, I was hoping [1] and[2] would echo the next 2
found, but it doesn't
Thanks



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Re: [PHP] not so

2002-06-08 Thread Rob Packer

oops, no coffee yet

Jason Wong [EMAIL PROTECTED] wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
 On Saturday 08 June 2002 22:36, Rob Packer wrote:
  [0] would match the whole ip, I was hoping [1] and[2] would echo the
next 2
  found, but it doesn't

 1) Could you not start a new thread each time? It makes it difficult for
 people to help because your responses and their repsonses are all over the
 place.

 And a subject which matches the discussion in hand would be appreciated.
When
 people search through the archives and come across a thread named not
so,
 what on earth are they supposed to make of that?

 2) I asked you to show the format of your input file. Without knowing what
it
 looks like there's not much anyone can do to help you.

 --
 Jason Wong - Gremlins Associates - www.gremlins.com.hk
 Open Source Software Systems Integrators
 * Web Design  Hosting * Internet  Intranet Applications Development *

 /*
 Memory fault -- core...uh...um...core... Oh dammit, I forget!
 */




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[PHP] make hitting enter in a text box = br

2002-05-13 Thread Rob Packer

I have a simple script for a newsletter, with a text area box for someone to
type in their newsletter. Is it possible to make it so when someone hits
enter with the text box it will equal br?

TIA

Robert

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Re: [PHP] php in a layer trouble

2002-04-25 Thread Rob Packer

Yep, you guys are right! Thanks for the help

Robert



Justin French [EMAIL PROTECTED] wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
 I don't believe there is such a problem, because

 DIV? echo foo; ?/DIV

 will get replaced with DIVfoo/DIV by the PHP parser.   Thus by the
 time the content gets to the browser, it ISN'T PHP anymore -- it's HTML,
or
 text.

 What you should do is view the source of your processed page, to ensure
that
 your HTML around the problem area is valid, and correctly parsed.  You may
 even want to run a HTML validator over it.


 Remember, once the page hits the browser, the code is the RESULT of the
PHP
 code, not the php code itself, thus, PHP code that produces correctly
 formatted HTML should not break any page.  PHP code that creates poorly
 formatted or invalid HTML will break a page, just as if you did it
yourself
 with a text editor on a raw HTML page.


 Good luck.


 Justin French
 
 Creative Director
 http://Indent.com.au
 



 on 25/04/02 4:52 AM, Robert ([EMAIL PROTECTED]) wrote:

  Has anyone ever had trouble with Netscape not displaying a layer with
you
  put any php code in it? Anyone know a source for reading more about it?
 
 




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Re: [PHP] Can't get this code to work...

2002-04-06 Thread Rob Packer

Dan,
Really, thanks for the help. Yeah, as you know I'm not experienced near
enough with PHP. Maybe you could provide me with an e-mail and prices for
consultation(I suppose this is what  'Analysis  Solutions' does?)

Regards,
Robert Packer
Analysis  Solutions [EMAIL PROTECTED] wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
 On Sat, Apr 06, 2002 at 12:32:33AM -0500, Analysis  Solutions wrote:
 
  input type=checkbox name=checkbox['Name'] value=validate /

 And following up to my own following up...  As I shut down the computer,
 I realized I made a boo boo.  The single quotes shouldn't be there.  So,
 make that:
   input type=checkbox name=checkbox[Name] value=validate /

 Later,

 --Dan

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[PHP] getting slash with single quotes in form mail

2002-04-05 Thread Rob Packer

Hi,
I have a contact form and when someone fills it out, all the single
quotes (apostrophes) end up having a slash in front of them in the e-mail,
like this:

 I\'m

 Can someone tell me how to stop this? Thanks you.
Rob



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[PHP] Can't get this code to work...

2002-04-05 Thread Rob Packer

Sorry for the vague Subject, but I have this code that looks fine to me.
There's some logical error, because I can't get to the second if statement,
although when I echo \$.$cb[$i] I get $checkboxName. If I hard code
$checkboxName it will work though. Anyone know why? TIA!

$num_fields= 8 ;//the number of fields on the form!
$cb=array(Name, Address, State, Zip, Phone, Email, Comments,
Fax);
for($i=0; $i$num_fields; $i++){

if (\$.$cb[$i] !=)
{
 // CAN GET HERE
 if (\$checkbox.$cb[$i]==validate)
  {echocan NOT get here;// HINT, HINT
  $form_write_msg .=
   'if (!$cb[$i])
   {$error_msg.=Your  . $cb[$i] .  .\n;}
   if (\$.$cb[$i]){
  $msg.=\$.$cb[$i].: \t . $cb[$i] .  . \n;}
   '
  ;}elseif(\$checkbox.$cb[$i]==no)
   {$form_write_msg.=
   'if (\$.$cb[$i]){
  $msg.=$cb[$i]  .: \t  .$cb[$i].  . \n;}
   '
  ;}
;}



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[PHP] escape characters

2002-04-03 Thread Rob Packer

In the following statement, can someone tell me what I would need to escape
out if I were to put it all into a variable (I know the quotes, but that's
all) :
if (!$name){
 $error_msg.=Your Name \n;
}

Thanks,
Rob



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