[PHP] Adding 6 digits to a str?

2002-02-02 Thread Andy 

Hi guys,

I am trying to force a int to be 8 digits. If it is only 3 dig filling the
first ones with 0.

Anyhow I tryed it with type casting, but it does not matter what I try, I
always get an addition.

E.g:
  $member_id is: 136
   should be: 0136

Here is the code, which is still returning 136:

   for($i=0;$icount($member_id);$i++){
   $length = strlen($member_id[$i]);

settype ($member_id[$i], string);
$zero = '0';
settype ($zero, string);

$member_id[$i] = $zero + $member_id[$i];
echo $member_id[$i];
   }

Does anybody know how to solve this thing??

Thanx Andy





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Re: [PHP] Adding 6 digits to a str?

2002-02-02 Thread Jeff Sheltren 

Why is it that you want to represent an int with leading 0's?  Is it just 
to print it out that way?  If that is the case, then you can use the printf 
function for formatted printing.


Jeff

At 10:53 AM 2/2/2002 +0100, Andy wrote:
Hi guys,

I am trying to force a int to be 8 digits. If it is only 3 dig filling the
first ones with 0.

Anyhow I tryed it with type casting, but it does not matter what I try, I
always get an addition.

E.g:
   $member_id is: 136
should be: 0136

Here is the code, which is still returning 136:

for($i=0;$icount($member_id);$i++){
$length = strlen($member_id[$i]);

 settype ($member_id[$i], string);
 $zero = '0';
 settype ($zero, string);

 $member_id[$i] = $zero + $member_id[$i];
 echo $member_id[$i];
}

Does anybody know how to solve this thing??

Thanx Andy



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Re: [PHP] Adding 6 digits to a str?

2002-02-02 Thread Edward van Bilderbeek - Bean IT 

like this:

$digit = 122;
 $digits = sprintf (%08d, $digit);
 print $digits;

Greets,

Edward


- Original Message -
From: Jeff Sheltren [EMAIL PROTECTED]
To: Andy [EMAIL PROTECTED]; [EMAIL PROTECTED]
Sent: Saturday, February 02, 2002 6:41 PM
Subject: Re: [PHP] Adding 6 digits to a str?


 Why is it that you want to represent an int with leading 0's?  Is it just
 to print it out that way?  If that is the case, then you can use the
printf
 function for formatted printing.


 Jeff

 At 10:53 AM 2/2/2002 +0100, Andy wrote:
 Hi guys,
 
 I am trying to force a int to be 8 digits. If it is only 3 dig filling
the
 first ones with 0.
 
 Anyhow I tryed it with type casting, but it does not matter what I try, I
 always get an addition.
 
 E.g:
$member_id is: 136
 should be: 0136
 
 Here is the code, which is still returning 136:
 
 for($i=0;$icount($member_id);$i++){
 $length = strlen($member_id[$i]);
 
  settype ($member_id[$i], string);
  $zero = '0';
  settype ($zero, string);
 
  $member_id[$i] = $zero + $member_id[$i];
  echo $member_id[$i];
 }
 
 Does anybody know how to solve this thing??
 
 Thanx Andy



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 To unsubscribe, e-mail: [EMAIL PROTECTED]
 For additional commands, e-mail: [EMAIL PROTECTED]
 To contact the list administrators, e-mail: [EMAIL PROTECTED]




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