[PHP] How to find the object name in a class?
I've been using a function to output HTML to the user's browser, and now my
use has made it neccessary to put it all inside a class.
All's going find and dandy and I've got it all working. However one of it's
variables is $front_page.
Now in other pages there are references to $front_page, and I want to change
them to something like $objectname->front_pagee.
The problem is that I can't know what the object will be named ahead of
time!
So my hack-around is in the class constructor I set a global variable called
$pge with the value submitted to the constructor. So someone would do this:
$somename = new Display(somename);
But if someone typos the and the name of the variable is different from the
one submitted to the constructor, all the code will break! That's because
I'm using a variable variable to refer to $front_page, like this:
${$pge}->front_page
I told you it was a hack-around, and it isn't a good one.
So is there ANY way to get the name of the object in PHP code without
knowing the name of the object ahead of time?
I'm really stumped!
--
Plutarck
Should be working on something...
...but forgot what it was.
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RE: [PHP] How to find the object name in a class?
> So is there ANY way to get the name of the object in PHP code without > knowing the name of the object ahead of time? I went through this exact thing not too long ago with an error class I wrote. Unfortunately, there is no way to know. What you can do, however, is do a check to see if that object exists before you access the variable. Other than that, I think you're outta luck. :/ Chris
Re: [PHP] How to find the object name in a class?
*sigh* I'm thinking so too ;(
Doh!
However, I have at least a usable hack around.
In the constructor of your class, add:
function Class ($object_name)
{
global $pge;
$pge = $object_name;
}
Then when you use create a new object of that type you must use:
$objectname = new Class('objectname');
Then in your code you just use ${$pge}-> to refer to it.
Sucks, doesn't it?
--
Plutarck
Should be working on something...
...but forgot what it was.
""Boget, Chris"" <[EMAIL PROTECTED]> wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
> > So is there ANY way to get the name of the object in PHP code without
> > knowing the name of the object ahead of time?
>
> I went through this exact thing not too long ago with an error class
> I wrote. Unfortunately, there is no way to know. What you can do,
> however, is do a check to see if that object exists before you access
> the variable. Other than that, I think you're outta luck. :/
>
> Chris
>
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RE: [PHP] How to find the object name in a class?
> *sigh* I'm thinking so too ;(
> Doh!
> However, I have at least a usable hack around.
> In the constructor of your class, add:
> function Class ($object_name) {
> global $pge;
> $pge = $object_name;
> }
> Then when you use create a new object of that type you must use:
> $objectname = new Class('objectname');
Heh. This is exactly what I'm doing as it was the only work around
that I could find, too.
> Then in your code you just use ${$pge}-> to refer to it.
Yup. However, before I do this, I check to make sure $pge is valid
before I use it. Otherwise, all kinds of nastiness can occur.
What I'm doing this for is my error reporting class. I'm using a
wrapper function that calls my class' errorHandler() method since
you cannot specify a class method as the handler function. Kind
of funky. But doing this was the only way I could get around it.
> Sucks, doesn't it?
Yup. But I'm sure there is a reason for it. Kind of like whatever
the reason is that we cannot actually get a variable's name.
I.E.
$joe = "bob";
we cannot get that the above variable's name is "joe".
Oh, well.
Chris
