RE: [PHP] Looping Addition
- Original Message -
From: Chris Wesley [EMAIL PROTECTED]
To: PHP List [EMAIL PROTECTED]
On Wed, 4 Dec 2002, Stephen wrote:
This is only a snippet, there is more to it but for simplicities
sake...
Then I calculate it. My question is, how would I loop the adding? I
hope
you
understand this now...
Ah!, I think I understand better now. You want to add num1, num2,
num3,
... numN, which are inputs from the second form in your sequence.
Gotcha.
If you name /all/ the form elements as nums[] instead of
individually as
num${current}, the numbers put into the form will all be accessible
in
one array to the PHP script that does the adding. Then you can just
loop
over the array of numbers.
In your second form, change this:
input name=num?php echo $current; ? type=text id=vars
value=0
size=25
To this:
input name=nums[] type=text id=vars value=0 size=25
Then in the script that adds the numbers:
$total = 0;
foreach( $_POST['nums'] as $number ){
$total += $number;
}
Or even $total = array_sum($_POST['nums'])
Cheers!
Mike
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Re: [PHP] Looping Addition
One more question... If I then wanted to do this for the other operations
(such as multiplication, division, etc), how would I do that?
- Original Message -
From: John W. Holmes [EMAIL PROTECTED]
To: 'Stephen' [EMAIL PROTECTED]; 'Chris Wesley'
[EMAIL PROTECTED]
Cc: 'PHP List' [EMAIL PROTECTED]
Sent: Wednesday, December 04, 2002 9:01 PM
Subject: RE: [PHP] Looping Addition
Let me explain this as best I can. The user enters how many numbers he
wants
to add. This form goes to another page. This page loops a form field
and
it's name is num and after num is the number it is currently on.
Here's
the code:
form name=add method=post action=?php $_SERVER['PHP_SELF'];
?
tr
td width=35%How many numbers to add:/td
tdinput name=vars type=text id=vars value=2 size=10
maxlength=2/td
/tr
tr
td colspan=2div align=center
input name=submit type=submit id=submit value=Next
gt;
/div/td
/tr
/form
?php
}
else
{
if(!is_numeric($_POST['vars']) || $_POST['vars'] = 1)
{
echo a href=\javascript:history.back(-1)\Go back/a and enter
a
number or something greater then 1. DO NOT enter a letter or symbol.;
}
else
{
?
form name=add action=module.php?id=?php echo
$HTTP_GET_VARS['id'];
?show=calculate method=post
input type=hidden name=vars value=?php echo $_POST['vars'];
?
?php
$current = 1;
do
{
?
tr
td width=35%?php echo Number .$current.:; ?/td
tdinput name=num?php echo $current; ? type=text
id=vars
value=0 size=25/td
/tr
?php
$current++;
} while($current = $_POST['vars'])
?
Change the above to:
?php
for($x=0;$x$_POST['vars'];$x++)
{
?
tr
td width=35%Number ?php echo $x; ?:/td
tdinput name=num[] type=text id=vars value=0 size=25/td
?php } ?
tr
td colspan=2div align=center
input name=add type=submit id=add value=Next gt;
/div/td
/tr
/form
This is only a snippet, there is more to it but for simplicities
sake...
Then I calculate it. My question is, how would I loop the adding? I
hope
you
understand this now...
And to do the addition...
$sum = array_sum($_POST['num']);
---John Holmes...
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Re: [PHP] Looping Addition
One more question... If I then wanted to do this for the other operations
(such as multiplication, division, etc), how would I do that?
Assuming you've figured out how to do an array...
You'll have to loop through the values like in the code that others posted.
foreach($_POST['number'] as $num)
{ //calculate total here with $num }
* = multiplication
/ = divide
---John Holmes...
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Re: [PHP] Looping Addition
So would I just put this?
foreach(%_POST['number'] as $num)
{
$output *= $num;
}
echo $output;
That's for multiplication.
- Original Message -
From: 1LT John W. Holmes [EMAIL PROTECTED]
To: Stephen [EMAIL PROTECTED]
Cc: PHP List [EMAIL PROTECTED]
Sent: Thursday, December 05, 2002 8:24 AM
Subject: Re: [PHP] Looping Addition
One more question... If I then wanted to do this for the other
operations
(such as multiplication, division, etc), how would I do that?
Assuming you've figured out how to do an array...
You'll have to loop through the values like in the code that others
posted.
foreach($_POST['number'] as $num)
{ //calculate total here with $num }
* = multiplication
/ = divide
---John Holmes...
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Re: [PHP] Looping Addition
On Thursday 05 December 2002 23:05, Stephen wrote:
So would I just put this?
foreach(%_POST['number'] as $num)
{
$output *= $num;
}
echo $output;
That's for multiplication.
Yes. Wouldn't it have been quicker for you to try it than to ask?
BTW make sure that none of $num is zero.
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Re: [PHP] Looping Addition
Continuing this even more...how would I use this same method only to
subtract?
What I'm doing right now would result in the following sitution.
The user types in 5 as their first number. The second number is 4. Instead
of returnin 1, it returns -9. It's subtracting the first number from 0, then
taking 4 and subtracting that from -5. How can I fix this keeping in mind
the user may type in more then two numbers?
- Original Message -
From: Chris Wesley [EMAIL PROTECTED]
To: PHP List [EMAIL PROTECTED]
Cc: Stephen [EMAIL PROTECTED]
Sent: Wednesday, December 04, 2002 8:42 PM
Subject: Re: [PHP] Looping Addition
On Wed, 4 Dec 2002, Stephen wrote:
This is only a snippet, there is more to it but for simplicities sake...
Then I calculate it. My question is, how would I loop the adding? I hope
you
understand this now...
Ah!, I think I understand better now. You want to add num1, num2, num3,
... numN, which are inputs from the second form in your sequence. Gotcha.
If you name /all/ the form elements as nums[] instead of individually as
num${current}, the numbers put into the form will all be accessible in
one array to the PHP script that does the adding. Then you can just loop
over the array of numbers.
In your second form, change this:
input name=num?php echo $current; ? type=text id=vars value=0
size=25
To this:
input name=nums[] type=text id=vars value=0 size=25
Then in the script that adds the numbers:
$total = 0;
foreach( $_POST['nums'] as $number ){
$total += $number;
}
Hopefully I understood your problem this time! Let me know if I missed
again.
g.luck,
~Chris
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Re: [PHP] Looping Addition
You simply need the absolute value of the difference. So taking Stephen's
example below..
$total = 0;
foreach( $_POST['nums'] as $number )
{
$total -= $number;// if users inputs 5 as first value result equals -5
$total = abs($total); // result now equals 5
}
- Original Message -
From: Stephen [EMAIL PROTECTED]
To: Chris Wesley [EMAIL PROTECTED]
Cc: PHP List [EMAIL PROTECTED]
Sent: Thursday, December 05, 2002 12:33 PM
Subject: Re: [PHP] Looping Addition
Continuing this even more...how would I use this same method only to
subtract?
What I'm doing right now would result in the following sitution.
The user types in 5 as their first number. The second number is 4. Instead
of returnin 1, it returns -9. It's subtracting the first number from 0,
then
taking 4 and subtracting that from -5. How can I fix this keeping in mind
the user may type in more then two numbers?
- Original Message -
From: Chris Wesley [EMAIL PROTECTED]
To: PHP List [EMAIL PROTECTED]
Cc: Stephen [EMAIL PROTECTED]
Sent: Wednesday, December 04, 2002 8:42 PM
Subject: Re: [PHP] Looping Addition
On Wed, 4 Dec 2002, Stephen wrote:
This is only a snippet, there is more to it but for simplicities
sake...
Then I calculate it. My question is, how would I loop the adding? I
hope
you
understand this now...
Ah!, I think I understand better now. You want to add num1, num2, num3,
... numN, which are inputs from the second form in your sequence.
Gotcha.
If you name /all/ the form elements as nums[] instead of individually
as
num${current}, the numbers put into the form will all be accessible in
one array to the PHP script that does the adding. Then you can just
loop
over the array of numbers.
In your second form, change this:
input name=num?php echo $current; ? type=text id=vars
value=0
size=25
To this:
input name=nums[] type=text id=vars value=0 size=25
Then in the script that adds the numbers:
$total = 0;
foreach( $_POST['nums'] as $number ){
$total += $number;
}
Hopefully I understood your problem this time! Let me know if I missed
again.
g.luck,
~Chris
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Re: [PHP] Looping Addition
But then, if the user entered 5 - 6, it should be -1 but it'd return
positive one... Is there another way?
- Original Message -
From: Kevin Stone [EMAIL PROTECTED]
To: Stephen [EMAIL PROTECTED]; Chris Wesley [EMAIL PROTECTED]
Cc: PHP List [EMAIL PROTECTED]
Sent: Thursday, December 05, 2002 2:51 PM
Subject: Re: [PHP] Looping Addition
You simply need the absolute value of the difference. So taking Stephen's
example below..
$total = 0;
foreach( $_POST['nums'] as $number )
{
$total -= $number;// if users inputs 5 as first value result
equals -5
$total = abs($total); // result now equals 5
}
- Original Message -
From: Stephen [EMAIL PROTECTED]
To: Chris Wesley [EMAIL PROTECTED]
Cc: PHP List [EMAIL PROTECTED]
Sent: Thursday, December 05, 2002 12:33 PM
Subject: Re: [PHP] Looping Addition
Continuing this even more...how would I use this same method only to
subtract?
What I'm doing right now would result in the following sitution.
The user types in 5 as their first number. The second number is 4.
Instead
of returnin 1, it returns -9. It's subtracting the first number from 0,
then
taking 4 and subtracting that from -5. How can I fix this keeping in
mind
the user may type in more then two numbers?
- Original Message -
From: Chris Wesley [EMAIL PROTECTED]
To: PHP List [EMAIL PROTECTED]
Cc: Stephen [EMAIL PROTECTED]
Sent: Wednesday, December 04, 2002 8:42 PM
Subject: Re: [PHP] Looping Addition
On Wed, 4 Dec 2002, Stephen wrote:
This is only a snippet, there is more to it but for simplicities
sake...
Then I calculate it. My question is, how would I loop the adding? I
hope
you
understand this now...
Ah!, I think I understand better now. You want to add num1, num2,
num3,
... numN, which are inputs from the second form in your sequence.
Gotcha.
If you name /all/ the form elements as nums[] instead of
individually
as
num${current}, the numbers put into the form will all be accessible
in
one array to the PHP script that does the adding. Then you can just
loop
over the array of numbers.
In your second form, change this:
input name=num?php echo $current; ? type=text id=vars
value=0
size=25
To this:
input name=nums[] type=text id=vars value=0 size=25
Then in the script that adds the numbers:
$total = 0;
foreach( $_POST['nums'] as $number ){
$total += $number;
}
Hopefully I understood your problem this time! Let me know if I
missed
again.
g.luck,
~Chris
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Re: [PHP] Looping Addition
But then, if the user entered 5 - 6, it should be -1 but it'd return
positive one... Is there another way?
Come on, man... this is addition and subtraction. You can't figure it out?
You simply need the absolute value of the difference. So taking
Stephen's
example below..
$total = 0;
Look, right here, you're setting the total to zero, so now everything will
be subtracted from zero. If you want everything to be subtracted from the
first number, the set $total equal to the first number and loop through the
remainder.
$total = $_POST['nums'][0];
$cnt = count($_POST['nums']);
for($x=1;$x$cnt;$x++)
{ $total -= $_POST['nums'][$x]; }
And I'm sure your next post will be but how will I use that if I want to go
back to addition/multiplication/division???;
Here, assuming $mode can be set to add,sub,mul or div:
$total = $_POST['nums'][0];
$cnt = count($_POST['nums']);
for($x=1;$x$cnt;$x++)
{
switch($mode)
{
case add: $total += $_POST['nums'][$x]; break;
case sub: $total -= $_POST['nums'][$x]; break;
case mul: $total *= $_POST['nums'][$x]; break;
case div: $total /= $_POST['nums'][$x]; break;
}
}
echo $total;
Plenty of other ways to do it, too, that may be more efficient. And I
couldn't honestly tell you if *= and /= work and I don't want to go see.
Hope that helps. Good luck.
---John Holmes...
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Re: [PHP] Looping Addition
No, I wasn't going to ask that. But thanks for the info. :P
- Original Message -
From: 1LT John W. Holmes [EMAIL PROTECTED]
To: Stephen [EMAIL PROTECTED]; Kevin Stone [EMAIL PROTECTED]
Cc: PHP List [EMAIL PROTECTED]
Sent: Thursday, December 05, 2002 3:14 PM
Subject: Re: [PHP] Looping Addition
But then, if the user entered 5 - 6, it should be -1 but it'd return
positive one... Is there another way?
Come on, man... this is addition and subtraction. You can't figure it out?
You simply need the absolute value of the difference. So taking
Stephen's
example below..
$total = 0;
Look, right here, you're setting the total to zero, so now everything will
be subtracted from zero. If you want everything to be subtracted from the
first number, the set $total equal to the first number and loop through
the
remainder.
$total = $_POST['nums'][0];
$cnt = count($_POST['nums']);
for($x=1;$x$cnt;$x++)
{ $total -= $_POST['nums'][$x]; }
And I'm sure your next post will be but how will I use that if I want to
go
back to addition/multiplication/division???;
Here, assuming $mode can be set to add,sub,mul or div:
$total = $_POST['nums'][0];
$cnt = count($_POST['nums']);
for($x=1;$x$cnt;$x++)
{
switch($mode)
{
case add: $total += $_POST['nums'][$x]; break;
case sub: $total -= $_POST['nums'][$x]; break;
case mul: $total *= $_POST['nums'][$x]; break;
case div: $total /= $_POST['nums'][$x]; break;
}
}
echo $total;
Plenty of other ways to do it, too, that may be more efficient. And I
couldn't honestly tell you if *= and /= work and I don't want to go see.
Hope that helps. Good luck.
---John Holmes...
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[PHP] Looping Addition
Sorry for the uncontrolable emaling to the list but I'm in rather a stump.
You may be hearing a lot from me over the next few days too.
Anyway, I mentioned before my form with the addition that loops to the
number of numbers the user wants to add. Now to the part of the actual
addition, how could I loop that out also?
Here's what I'm trying to do right now but naturally, it doesn't work:
$output = 0;
$current = 1;
do
{
$output .= $num.$current +
$current++;
} while($current = $_POST['vars']);
Any help would be great! Thanks!
Thanks,
Stephen Craton
http://www.melchior.us
What is a dreamer that cannot persevere? -- http://www.melchior.us
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Re: [PHP] Looping Addition
What type is $_POST['vars']? I think that it is a string...you might
have to convert it to an integer...
if( is_numeric( $_POST['vars'] ) )
{
$vars = (int)$_POST['vars'];
}
else
{
echo Error: \$_POST['vars'] is not an integer.;
}
On Wed, 2002-12-04 at 14:26, Stephen wrote:
Sorry for the uncontrolable emaling to the list but I'm in rather a stump.
You may be hearing a lot from me over the next few days too.
Anyway, I mentioned before my form with the addition that loops to the
number of numbers the user wants to add. Now to the part of the actual
addition, how could I loop that out also?
Here's what I'm trying to do right now but naturally, it doesn't work:
$output = 0;
$current = 1;
do
{
$output .= $num.$current +
$current++;
} while($current = $_POST['vars']);
Any help would be great! Thanks!
Thanks,
Stephen Craton
http://www.melchior.us
What is a dreamer that cannot persevere? -- http://www.melchior.us
__
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Re: [PHP] Looping Addition
I already have that. $_POST['vars'] is a number and I already check that you
on a page before. All I need to know is how to keep adding numbers until
there are no more to add...
- Original Message -
From: Ray Hunter [EMAIL PROTECTED]
To: Stephen [EMAIL PROTECTED]
Cc: PHP List [EMAIL PROTECTED]
Sent: Wednesday, December 04, 2002 4:33 PM
Subject: Re: [PHP] Looping Addition
What type is $_POST['vars']? I think that it is a string...you might
have to convert it to an integer...
if( is_numeric( $_POST['vars'] ) )
{
$vars = (int)$_POST['vars'];
}
else
{
echo Error: \$_POST['vars'] is not an integer.;
}
On Wed, 2002-12-04 at 14:26, Stephen wrote:
Sorry for the uncontrolable emaling to the list but I'm in rather a
stump.
You may be hearing a lot from me over the next few days too.
Anyway, I mentioned before my form with the addition that loops to the
number of numbers the user wants to add. Now to the part of the actual
addition, how could I loop that out also?
Here's what I'm trying to do right now but naturally, it doesn't work:
$output = 0;
$current = 1;
do
{
$output .= $num.$current +
$current++;
} while($current = $_POST['vars']);
Any help would be great! Thanks!
Thanks,
Stephen Craton
http://www.melchior.us
What is a dreamer that cannot persevere? -- http://www.melchior.us
__
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Re: [PHP] Looping Addition
On Wed, 4 Dec 2002, Stephen wrote:
I already have that. $_POST['vars'] is a number and I already check that you
on a page before. All I need to know is how to keep adding numbers until
there are no more to add...
If you mean that $_POST['vars'] is an array of numbers:
$total = 0;
foreach( $_POST['vars'] as $number ){
$total += $number;
}
If you mean that all vars in the POST data are numbers you want to add:
$total = 0;
foreach( $_POST as $number ){
$total += $number;
}
g.luck,
~Chris
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Re: [PHP] Looping Addition
Let me explain this as best I can. The user enters how many numbers he wants
to add. This form goes to another page. This page loops a form field and
it's name is num and after num is the number it is currently on. Here's
the code:
form name=add method=post action=?php $_SERVER['PHP_SELF']; ?
tr
td width=35%How many numbers to add:/td
tdinput name=vars type=text id=vars value=2 size=10
maxlength=2/td
/tr
tr
td colspan=2div align=center
input name=submit type=submit id=submit value=Next gt;
/div/td
/tr
/form
?php
}
else
{
if(!is_numeric($_POST['vars']) || $_POST['vars'] = 1)
{
echo a href=\javascript:history.back(-1)\Go back/a and enter a
number or something greater then 1. DO NOT enter a letter or symbol.;
}
else
{
?
form name=add action=module.php?id=?php echo $HTTP_GET_VARS['id'];
?show=calculate method=post
input type=hidden name=vars value=?php echo $_POST['vars']; ?
?php
$current = 1;
do
{
?
tr
td width=35%?php echo Number .$current.:; ?/td
tdinput name=num?php echo $current; ? type=text id=vars
value=0 size=25/td
/tr
?php
$current++;
} while($current = $_POST['vars'])
?
tr
td colspan=2div align=center
input name=add type=submit id=add value=Next gt;
/div/td
/tr
/form
This is only a snippet, there is more to it but for simplicities sake...
Then I calculate it. My question is, how would I loop the adding? I hope you
understand this now...
- Original Message -
From: Chris Wesley [EMAIL PROTECTED]
To: PHP List [EMAIL PROTECTED]
Cc: Stephen [EMAIL PROTECTED]
Sent: Wednesday, December 04, 2002 7:44 PM
Subject: Re: [PHP] Looping Addition
On Wed, 4 Dec 2002, Stephen wrote:
I already have that. $_POST['vars'] is a number and I already check that
you
on a page before. All I need to know is how to keep adding numbers until
there are no more to add...
If you mean that $_POST['vars'] is an array of numbers:
$total = 0;
foreach( $_POST['vars'] as $number ){
$total += $number;
}
If you mean that all vars in the POST data are numbers you want to add:
$total = 0;
foreach( $_POST as $number ){
$total += $number;
}
g.luck,
~Chris
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Re: [PHP] Looping Addition
Hi,
Thursday, December 5, 2002, 7:26:57 AM, you wrote:
S Sorry for the uncontrolable emaling to the list but I'm in rather a stump.
S You may be hearing a lot from me over the next few days too.
S Anyway, I mentioned before my form with the addition that loops to the
S number of numbers the user wants to add. Now to the part of the actual
S addition, how could I loop that out also?
S Here's what I'm trying to do right now but naturally, it doesn't work:
S $output = 0;
S $current = 1;
S do
S {
S $output .= $num.$current +
S $current++;
S } while($current = $_POST['vars']);
S Any help would be great! Thanks!
S Thanks,
S Stephen Craton
S http://www.melchior.us
S What is a dreamer that cannot persevere? -- http://www.melchior.us
something like
$output = 0;
$current = 1;
do
{
$x = 'num'.$current;
if(isset($_POST[$x])){
$output += $_POST[$x];
}
$current++;
} while($current = $_POST['vars']);
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Tom
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Re: [PHP] Looping Addition
On Wed, 4 Dec 2002, Stephen wrote:
This is only a snippet, there is more to it but for simplicities sake...
Then I calculate it. My question is, how would I loop the adding? I hope you
understand this now...
Ah!, I think I understand better now. You want to add num1, num2, num3,
... numN, which are inputs from the second form in your sequence. Gotcha.
If you name /all/ the form elements as nums[] instead of individually as
num${current}, the numbers put into the form will all be accessible in
one array to the PHP script that does the adding. Then you can just loop
over the array of numbers.
In your second form, change this:
input name=num?php echo $current; ? type=text id=vars value=0
size=25
To this:
input name=nums[] type=text id=vars value=0 size=25
Then in the script that adds the numbers:
$total = 0;
foreach( $_POST['nums'] as $number ){
$total += $number;
}
Hopefully I understood your problem this time! Let me know if I missed
again.
g.luck,
~Chris
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Re: [PHP] Looping Addition
Thank you! This is actually what I was wanting to do all along but I'm
rather noobish when it comes to arrays. I can get by with them on MySQL and
anything else, I suck at. Thanks again!
- Original Message -
From: Chris Wesley [EMAIL PROTECTED]
To: PHP List [EMAIL PROTECTED]
Cc: Stephen [EMAIL PROTECTED]
Sent: Wednesday, December 04, 2002 8:42 PM
Subject: Re: [PHP] Looping Addition
On Wed, 4 Dec 2002, Stephen wrote:
This is only a snippet, there is more to it but for simplicities sake...
Then I calculate it. My question is, how would I loop the adding? I hope
you
understand this now...
Ah!, I think I understand better now. You want to add num1, num2, num3,
... numN, which are inputs from the second form in your sequence. Gotcha.
If you name /all/ the form elements as nums[] instead of individually as
num${current}, the numbers put into the form will all be accessible in
one array to the PHP script that does the adding. Then you can just loop
over the array of numbers.
In your second form, change this:
input name=num?php echo $current; ? type=text id=vars value=0
size=25
To this:
input name=nums[] type=text id=vars value=0 size=25
Then in the script that adds the numbers:
$total = 0;
foreach( $_POST['nums'] as $number ){
$total += $number;
}
Hopefully I understood your problem this time! Let me know if I missed
again.
g.luck,
~Chris
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RE: [PHP] Looping Addition
Let me explain this as best I can. The user enters how many numbers he
wants
to add. This form goes to another page. This page loops a form field
and
it's name is num and after num is the number it is currently on.
Here's
the code:
form name=add method=post action=?php $_SERVER['PHP_SELF'];
?
tr
td width=35%How many numbers to add:/td
tdinput name=vars type=text id=vars value=2 size=10
maxlength=2/td
/tr
tr
td colspan=2div align=center
input name=submit type=submit id=submit value=Next
gt;
/div/td
/tr
/form
?php
}
else
{
if(!is_numeric($_POST['vars']) || $_POST['vars'] = 1)
{
echo a href=\javascript:history.back(-1)\Go back/a and enter
a
number or something greater then 1. DO NOT enter a letter or symbol.;
}
else
{
?
form name=add action=module.php?id=?php echo
$HTTP_GET_VARS['id'];
?show=calculate method=post
input type=hidden name=vars value=?php echo $_POST['vars'];
?
?php
$current = 1;
do
{
?
tr
td width=35%?php echo Number .$current.:; ?/td
tdinput name=num?php echo $current; ? type=text
id=vars
value=0 size=25/td
/tr
?php
$current++;
} while($current = $_POST['vars'])
?
Change the above to:
?php
for($x=0;$x$_POST['vars'];$x++)
{
?
tr
td width=35%Number ?php echo $x; ?:/td
tdinput name=num[] type=text id=vars value=0 size=25/td
?php } ?
tr
td colspan=2div align=center
input name=add type=submit id=add value=Next gt;
/div/td
/tr
/form
This is only a snippet, there is more to it but for simplicities
sake...
Then I calculate it. My question is, how would I loop the adding? I
hope
you
understand this now...
And to do the addition...
$sum = array_sum($_POST['num']);
---John Holmes...
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