Re: [PHP] Re: date problem
Isn't DATEDIFF() a MySQL 4.x function? The server I'm using has 3.x and I can't upgrade... - Original Message - From: Jasper Bryant-Greene [EMAIL PROTECTED] To: php-general@lists.php.net Sent: Wednesday, June 29, 2005 7:49 AM Subject: Re: [PHP] Re: date problem Mario netMines wrote: Hi Jasper and thanks for the quick reply. something tells me it's not a straightforward SQL query that I have to use here but a logic using PHP and SQL. Please don't top-post. It can be done in SQL quite easily, as can many things people use PHP for. Go to the MySQL manual at http://dev.mysql.com/ and read up on Date/Time functions, specifically the DATEDIFF() function. IIRC, it returns the difference between two dates. You can perform many types of arithmetic on the return value of the function which should help to get the result you want. Try the MySQL mailing lists if you can't figure it out, or if you're completely stuck and are *convinced* it's a PHP problem (which I doubt, but I could be wrong) then by all means come back! Cheers Jasper -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Re: date problem
Firstly, this shouldn't be in the PHP list, as you're asking for help with SQL. Mario netMines wrote: carrental_from (datetime field) carrental_to (datetime field) carrental_price (datetime field) [rates are per hour] carrental_price shouldn't be a datetime field, as it isn't a datetime value. The values I have are like: -00-00 00:00:00,-00-00 07:00:00,10 (all year around 00:00-07:00) -00-00 07:00:00,-00-00 00:00:00,20 (all year around 07:00-00:00) 2005-12-22 07:00:00,2006-01-02 00:00:00,15 (christmas period 00:00-07:00) 2005-12-22 00:00:00,2006-01-02 07:00:00,25 (christmas period 07:00-00:00) The user selects dates ($from - $to) to rent a car and he gets the price accordingly. I can do a (($to-$from)/60/60) and get the total number of hours but depending on the date and time you get a different result. Can anyone help with the SQL? Read up on the MySQL DATEDIFF() function, if you are using MySQL. Other DBMSs should have an equiv. function. Jasper -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Re: date problem
Hi Jasper and thanks for the quick reply. something tells me it's not a straightforward SQL query that I have to use here but a logic using PHP and SQL. Mario - Original Message - From: Jasper Bryant-Greene [EMAIL PROTECTED] To: php-general@lists.php.net Sent: Wednesday, June 29, 2005 4:28 AM Subject: [PHP] Re: date problem Firstly, this shouldn't be in the PHP list, as you're asking for help with SQL. Mario netMines wrote: carrental_from (datetime field) carrental_to (datetime field) carrental_price (datetime field) [rates are per hour] carrental_price shouldn't be a datetime field, as it isn't a datetime value. The values I have are like: -00-00 00:00:00,-00-00 07:00:00,10 (all year around 00:00-07:00) -00-00 07:00:00,-00-00 00:00:00,20 (all year around 07:00-00:00) 2005-12-22 07:00:00,2006-01-02 00:00:00,15 (christmas period 00:00-07:00) 2005-12-22 00:00:00,2006-01-02 07:00:00,25 (christmas period 07:00-00:00) The user selects dates ($from - $to) to rent a car and he gets the price accordingly. I can do a (($to-$from)/60/60) and get the total number of hours but depending on the date and time you get a different result. Can anyone help with the SQL? Read up on the MySQL DATEDIFF() function, if you are using MySQL. Other DBMSs should have an equiv. function. Jasper -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Re: date problem
Mario netMines wrote: Hi Jasper and thanks for the quick reply. something tells me it's not a straightforward SQL query that I have to use here but a logic using PHP and SQL. Please don't top-post. It can be done in SQL quite easily, as can many things people use PHP for. Go to the MySQL manual at http://dev.mysql.com/ and read up on Date/Time functions, specifically the DATEDIFF() function. IIRC, it returns the difference between two dates. You can perform many types of arithmetic on the return value of the function which should help to get the result you want. Try the MySQL mailing lists if you can't figure it out, or if you're completely stuck and are *convinced* it's a PHP problem (which I doubt, but I could be wrong) then by all means come back! Cheers Jasper -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Re: date problem
For me, on Windows, it won't work because Windows won't do anything prior to 1970. On linux, I get 17 as the result. If I change the year to 2000, then I get 08 on both. John Shaun [EMAIL PROTECTED] wrote in message news:[EMAIL PROTECTED] Hi, Why does the following code print '00', surely it should print '08', I'm baffled! date(H, mktime(8, 0, 0, 0, 0, 0)); Thanks for your help -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Re: date problem
From the documentation: http://ca2.php.net/manual/en/function.mktime.php Date with year, month and day equal to zero is considered illegal (otherwise it what be regarded as 30.11.1999, which would be strange behavior). I think the point here to think about is that the date(), time(), and mktime() functions all work with timestamps which happen to all function with respect to the Unix Epoch (January 1 1970) Cheers, Rob. On Wed, 2003-09-24 at 13:26, John wrote: For me, on Windows, it won't work because Windows won't do anything prior to 1970. On linux, I get 17 as the result. If I change the year to 2000, then I get 08 on both. John Shaun [EMAIL PROTECTED] wrote in message news:[EMAIL PROTECTED] Hi, Why does the following code print '00', surely it should print '08', I'm baffled! date(H, mktime(8, 0, 0, 0, 0, 0)); Thanks for your help -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- .. | InterJinn Application Framework - http://www.interjinn.com | :: | An application and templating framework for PHP. Boasting | | a powerful, scalable system for accessing system services | | such as forms, properties, sessions, and caches. InterJinn | | also provides an extremely flexible architecture for | | creating re-usable components quickly and easily. | `' -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Re: date problem
Try:
$ts = time();
$i = 0;
while( $i 2 ) {
$day = date(dS, $ts + $i * 86400);
print(td$day/td);
$i++;
}
On Wed, 19 Mar 2003, shaun wrote:
hi,
using date(dS); how can i can increase the days so that it shows
19th 20th 21st
I have tried
while ($i 2){
$day++;
echo' td'.$day.'/td';
$i++;
}
but i get:
19th 19ti 19tj
thanks for your help
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[PHP] Re: date problem
$date_array=explode(-,$newdate); $day = $date_array[2]; $month = $date_array[1]; $year = $date_array[0]; Or, $timestamp - strtotime($newdate); $today = getdate($timestamp); $month = $today['month']; $mday = $today['mday']; $year = $today['year']; Alexander Tsonev [EMAIL PROTECTED] wrote in message news:[EMAIL PROTECTED] Hello, I would ask you a question about date type if I have a variable from date type ($newdate) such as 2003-02-17 how can I separate $newdate into 3 different variables? I want to create such variables: $day=17 $month=2 $year=2003 I searched a lot, but I didn't find how to do this. I'll be very happy if someone helps! Thanks in advance, Alexander Tsonev -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Re: Date() Problem
Hi, im making a tab/lyric portal, and for viewing tabs i want to display the time the lyric/tab was submitted. So I retrive it from a MySQL database (as a timestamp) and format it using the date function. The problem is, that the date: 19-01-2038 04:14:07 is allways returned, even though in the `date` field the timestamp says (as an actual example) 20020723200919. Here is a shortened version of the script: ?php $submitdate = date(d-m-Y H:i:s, $values[4]); echo(Submitted on $submitdate); ? Hi Tony, the date() function in PHP does _only_ take UNIX timestamps as an argument which means that you can not run such a timestamp as the above. I recommend that you have a look at http://www.mysql.com/doc/D/a/Date_and_time_functions.html which describes the built-in functions for date-handling in MySQL. A function to look at could be DATE_FORMAT(). Regards, Jome -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Re: Date() Problem
Yeh, ive allready looked at that before, but where and when do i use DATE_FORMAT() ? When im inserting the row or selecting it? Jome [EMAIL PROTECTED] wrote in message [EMAIL PROTECTED]">news:[EMAIL PROTECTED]... Hi, im making a tab/lyric portal, and for viewing tabs i want to display the time the lyric/tab was submitted. So I retrive it from a MySQL database (as a timestamp) and format it using the date function. The problem is, that the date: 19-01-2038 04:14:07 is allways returned, even though in the `date` field the timestamp says (as an actual example) 20020723200919. Here is a shortened version of the script: ?php $submitdate = date(d-m-Y H:i:s, $values[4]); echo(Submitted on $submitdate); ? Hi Tony, the date() function in PHP does _only_ take UNIX timestamps as an argument which means that you can not run such a timestamp as the above. I recommend that you have a look at http://www.mysql.com/doc/D/a/Date_and_time_functions.html which describes the built-in functions for date-handling in MySQL. A function to look at could be DATE_FORMAT(). Regards, Jome -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Re: Date() Problem
Yeh, ive allready looked at that before, but where and when do i use DATE_FORMAT() ? When im inserting the row or selecting it? Replace your existent query with this one and try: SELECT `artist_id`,`title`,`content`,`user_id`,DATE_FORMAT(date,'%d-%m-%Y %H:%i:%s'),`type`,`views` FROM `resources` WHERE `id` = $id Regards, Jome -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Re: Date() Problem
Alternativly you could store the dates as UNIX timestamps. That is what I do. It is then eaiser to do certian things(ie show stuff released in the last month) -- JJ Harrison [EMAIL PROTECTED] www.tececo.com Tony Harrison [EMAIL PROTECTED] wrote in message [EMAIL PROTECTED]">news:[EMAIL PROTECTED]... Yeh, ive allready looked at that before, but where and when do i use DATE_FORMAT() ? When im inserting the row or selecting it? Jome [EMAIL PROTECTED] wrote in message [EMAIL PROTECTED]">news:[EMAIL PROTECTED]... Hi, im making a tab/lyric portal, and for viewing tabs i want to display the time the lyric/tab was submitted. So I retrive it from a MySQL database (as a timestamp) and format it using the date function. The problem is, that the date: 19-01-2038 04:14:07 is allways returned, even though in the `date` field the timestamp says (as an actual example) 20020723200919. Here is a shortened version of the script: ?php $submitdate = date(d-m-Y H:i:s, $values[4]); echo(Submitted on $submitdate); ? Hi Tony, the date() function in PHP does _only_ take UNIX timestamps as an argument which means that you can not run such a timestamp as the above. I recommend that you have a look at http://www.mysql.com/doc/D/a/Date_and_time_functions.html which describes the built-in functions for date-handling in MySQL. A function to look at could be DATE_FORMAT(). Regards, Jome -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Re: Date() Problem
I tried using UNIX stamps but it dont work, and why the hell does it default to that date anyway? I thought it was supposed to default to the current time? Jj Harrison [EMAIL PROTECTED] wrote in message [EMAIL PROTECTED]">news:[EMAIL PROTECTED]... Alternativly you could store the dates as UNIX timestamps. That is what I do. It is then eaiser to do certian things(ie show stuff released in the last month) -- JJ Harrison [EMAIL PROTECTED] www.tececo.com Tony Harrison [EMAIL PROTECTED] wrote in message [EMAIL PROTECTED]">news:[EMAIL PROTECTED]... Yeh, ive allready looked at that before, but where and when do i use DATE_FORMAT() ? When im inserting the row or selecting it? Jome [EMAIL PROTECTED] wrote in message [EMAIL PROTECTED]">news:[EMAIL PROTECTED]... Hi, im making a tab/lyric portal, and for viewing tabs i want to display the time the lyric/tab was submitted. So I retrive it from a MySQL database (as a timestamp) and format it using the date function. The problem is, that the date: 19-01-2038 04:14:07 is allways returned, even though in the `date` field the timestamp says (as an actual example) 20020723200919. Here is a shortened version of the script: ?php $submitdate = date(d-m-Y H:i:s, $values[4]); echo(Submitted on $submitdate); ? Hi Tony, the date() function in PHP does _only_ take UNIX timestamps as an argument which means that you can not run such a timestamp as the above. I recommend that you have a look at http://www.mysql.com/doc/D/a/Date_and_time_functions.html which describes the built-in functions for date-handling in MySQL. A function to look at could be DATE_FORMAT(). Regards, Jome -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Re: Date() Problem
I store all dates in unix timestamp format. It's the easiest one to work with, and it's easy to do things like date + three days, because it's just a case of adding the right number of seconds to the current stamp. You don't have to split anything, or get substr()'s of anything... and since date() accepts unix timestamps AND is the easiest way to get date formats (for me), I reckon it's the best way to go. Justin -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] Re: Date() Problem
I store all dates in unix timestamp format. It's the easiest one to work with, and it's easy to do things like date + three days, because it's just a case of adding the right number of seconds to the current stamp. You don't have to split anything, or get substr()'s of anything... and since date() accepts unix timestamps AND is the easiest way to get date formats (for me), I reckon it's the best way to go. Well, I've got to butt in on this one and put in a big DISAGREE. Use whatever is easiest for you, but MySQL provides a very rich assortment of date and time manipulation functions that are a lot better than PHPs (without any added classes). For example, to get everything from your database that was inserted three days ago, you'd use: SELECT * FROM your_table WHERE your_date_column = CURDATE() - INTERVAL 3 DAY; Now, much of this is MySQL specific, though. I only use MySQL right now, so it's not an issue, but it can be for some of you. Bottom line is use whatever is easiest for you, but realize that there are a ton of Date and Time functions built into MySQL. Anything you can do with a PHP function you can do with a MySQL function. You are also not completely lost if you're storing things as Unixtimstamps. You can convert from and to unixtimestamps and still make use of all of the MySQL functions... ---John Holmes... -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Re: date problem
You can include date formatting function in your SQL statement: DATE_FORMAT(date,format) http://www.mysql.com/doc/D/a/Date_and_time_functions.html -- Kind regards, Yuri. www.AceHoster.com Quality web hosting Nick Wilson [EMAIL PROTECTED] ???/ ? ?: [EMAIL PROTECTED]">news:[EMAIL PROTECTED]... -BEGIN PGP SIGNED MESSAGE- Hash: SHA1 Hi all I have a field in MySQL db like this: date TIMESTAMP, and it looks pretty regular like this: 20020428011911 when I come to use php date(D M Y, $myTimeStamp) though I get TUE JAN 2038! I see something in the manual re this date but I'm afraid I still can't work it out so some advice/help would be greatly appreciated :-) - -- Nick Wilson // www.explodingnet.com -BEGIN PGP SIGNATURE- Version: GnuPG v1.0.6 (GNU/Linux) iD4DBQE8y++SHpvrrTa6L5oRAh3xAJ9lfFdB1VW3KUHCWxnnksN+Uw950QCYpfg6 OCdApC0Nh/8hi8MYQY3OTQ== =FnlM -END PGP SIGNATURE- -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Re: date problem
Mysql? INSERT INTO table VALUES (NOW()); -- Julio Nobrega. Um dia eu chego lá: http://sourceforge.net/projects/toca Ajudei? Salvei? Que tal um presentinho? http://www.submarino.com.br/wishlistclient.asp?wlid=664176742884 Eoghan [EMAIL PROTECTED] wrote in message [EMAIL PROTECTED]">news:[EMAIL PROTECTED]... hello i am running into some trouble with a very basic problem. i want to insert the current date/time into my db. i have the field set up as a datetime field. when i submit info, i just get a blank date, i mean it all zeros, like -00-00 00.00:00:00. how do i insert the current datetime into my db? i tried using a hidden field with a foramtted gmt date value, but its not working... any help thanks - eoghan -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Re: Date Problem
you can use the MySql's function: DATE_ADD(datefield, INTERVAL 3 MONTH) Mindhunter [EMAIL PROTECTED] wrote in message [EMAIL PROTECTED]">news:[EMAIL PROTECTED]... Hi, I am reading a date from an input in format 'DD-MM-' ex. 10-11-2001. Now I want to add 3 months to the date. I have tested mktime and strftime etc and no matter what I do I get the year as 1970. (Systemdate works fine). How would I go about adding 3 months to a date in that format? Thanks MH -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
[PHP] Re: Date Problem
On Wed, 21 Nov 2001 09:31:33 +0200, [EMAIL PROTECTED] (Mindhunter) wrote: I am reading a date from an input in format 'DD-MM-' ex. 10-11-2001. Now I want to add 3 months to the date. I have tested mktime and strftime etc and no matter what I do I get the year as 1970. (Systemdate works fine). How would I go about adding 3 months to a date in that format? Though not the most elegant solution by far .. You could explode the data the increment the second element of the array. If gt 12 subtract 12 and increment the year .. Sorry .. the date functions still get me. DSig -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
[PHP] Re: Date Problem
Mindhunter wrote:
Hi,
I am reading a date from an input in format 'DD-MM-' ex. 10-11-2001.
Now I want to add 3 months to the date. I have tested mktime and strftime
etc and no matter what I do I get the year as 1970. (Systemdate works
fine). How would I go about adding 3 months to a date in that format?
Thanks
MH
The following works for me:
$mydate = '10-11-2001';
list($myday,$mymonth,$myyear) = explode('-',$mydate);
$mymktime = mktime(0,0,0,3 + $mymonth,$myday,$myyear);
$newdate = date('d-m-Y',$mymktime);
newdate is then 10-02-2002
You might check :
1. You always use a 4 digit year
2. mktime order of arguments i.e. hours,minutes,seconds,months,days,years
3. Output date format on date() function
4. There are problems with dates pre 1970 AND pre 1901, (pre 1970 is pre unixtime, pre
1901 is pre
phptime). I had problems with pre 1901 dates which the calendar module solved ( see
jdtojulian,
juliantojd)
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[PHP] Re: date problem
date() shoudl give you the time in your timezone, gmdate() should give you the time in the GMT timezone. I would check your server and make sure the timezone is correctly set. -- Chris Lee [EMAIL PROTECTED] Steve Tsai [EMAIL PROTECTED] wrote in message news:none... For reference: OS: OpenBSD 2.9 Web Server: Apache1.3.19 PHP Version: 4.0.6 My problem is that date() and all the other time functions return GMT instead of localtime. system(date) returns the correct localtime. Those functions used to return localtime since GMT. The problem seems to have started after daylight savings time changed. I hope someone has an idea of what's wrong and how to fix it. As for now, I'm adding time() - 3600 * 8 to all my scripts right now. Steve -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
