[PHP] Why this doesn't work ?
Hi, Why this doesn't work ? --- $query = SELECT COUNT (login) FROM WHERE login = '$login'; $result = mysql_query($query); mysql_fetch_row($result); --- It gives me Warning: mysql_fetch_row(): supplied argument is not a valid MySQL result resource in /var/www/html/registar_action.php on line 22 Any help would be apreciated. Warm Regards, Mário Gamito -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Why this doesn't work ?
It looks to me like you forgot to specify the table in your query: SELECT COUNT (login) FROM TABLENAME GOES HERE WHERE login = '$login' Hi, Why this doesn't work ? --- $query = SELECT COUNT (login) FROM WHERE login = '$login'; $result = mysql_query($query); mysql_fetch_row($result); --- It gives me Warning: mysql_fetch_row(): supplied argument is not a valid MySQL result resource in /var/www/html/registar_action.php on line 22 Any help would be apreciated. Warm Regards, Mário Gamito -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php Thank you, Colin Shreffler Principal 303.349.9010 - cell 928.396.1099 - fax [EMAIL PROTECTED] Warp 9 Software, LLC. 6791 Halifax Avenue Castle Rock, CO 80104 Confidentiality Notice: The information in this e-mail may be confidential and/or privileged. This e-mail is intended to be reviewed by only the individual or organization named in the e-mail address. If you are not the intended recipient, you are hereby notified that any review, dissemination or copying of this e-mail and attachments, if any, or the information contained herein, is strictly prohibited. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Why this doesn't work ?
Hi, Sorry, i do have the table name. It just passed me while transcripting. The code is: --- $query = SELECT COUNT (login) FROM formacao WHERE login = '$login'; $result = mysql_query($query); mysql_fetch_row($result); --- It works perfectly on MySQL prompt. Regards, Mário Gamito Colin Shreffler wrote: It looks to me like you forgot to specify the table in your query: SELECT COUNT (login) FROM TABLENAME GOES HERE WHERE login = '$login' Hi, Why this doesn't work ? --- $query = SELECT COUNT (login) FROM WHERE login = '$login'; $result = mysql_query($query); mysql_fetch_row($result); --- It gives me Warning: mysql_fetch_row(): supplied argument is not a valid MySQL result resource in /var/www/html/registar_action.php on line 22 Any help would be apreciated. Warm Regards, Mário Gamito -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php Thank you, Colin Shreffler Principal 303.349.9010 - cell 928.396.1099 - fax [EMAIL PROTECTED] Warp 9 Software, LLC. 6791 Halifax Avenue Castle Rock, CO 80104 Confidentiality Notice: The information in this e-mail may be confidential and/or privileged. This e-mail is intended to be reviewed by only the individual or organization named in the e-mail address. If you are not the intended recipient, you are hereby notified that any review, dissemination or copying of this e-mail and attachments, if any, or the information contained herein, is strictly prohibited. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] Why this doesn't work ?
[snip] --- $query = SELECT COUNT (login) FROM formacao WHERE login = '$login'; $result = mysql_query($query); mysql_fetch_row($result); --- [/snip] mysql_query() requires a connections resource $result = mysql_query($query, $myConnection); -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] Why this doesn't work ?
[snip] --- $query = SELECT COUNT (login) FROM formacao WHERE login = '$login'; $result = mysql_query($query); mysql_fetch_row($result); --- [/snip] mysql_query() requires a connections resource $result = mysql_query($query, $myConnection); The connection resource is optional. It will use the most recent connection if not specified. JM -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Why this doesn't work ?
$query = SELECT COUNT (login) FROM formacao WHERE login = '$login'; $result = mysql_query($query); Make this line instead $result = mysql_query($query) or die(mysql_error() . with the query $query; and you'll likely see the error. -- Scott Noyes [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] Why this doesn't work ?
[snip] $query = SELECT COUNT (login) FROM formacao WHERE login = '$login'; $result = mysql_query($query); mysql_fetch_row($result); The connection resource is optional. It will use the most recent connection if not specified. [/snip] Then try this $query = SELECT COUNT (login) FROM formacao WHERE login = '.$login.'; -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Why this doesn't work ?
Hi, Make this line instead $result = mysql_query($query) or die(mysql_error() . with the query $query; and you'll likely see the error. Here it goes: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '(login) FROM formacao WHERE login = 'a'' at line 1 Regards, Mário Gamito -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Why this doesn't work ?
why don't you just echo your $query to see if it is coming out correctly, before even trying to mess with mysql_query()? I think you should be able to see the problem from there. Jordan On Oct 24, 2005, at 12:44 PM, Mário Gamito wrote: Hi, Make this line instead $result = mysql_query($query) or die(mysql_error() . with the query $query; and you'll likely see the error. Here it goes: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '(login) FROM formacao WHERE login = 'a'' at line 1 Regards, Mário Gamito -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] Why this doesn't work ?
Hi, Make this line instead $result = mysql_query($query) or die(mysql_error() . with the query $query; and you'll likely see the error. Here it goes: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '(login) FROM formacao WHERE login = 'a'' at line 1 Apparently, $login does not contain the text you think it does. Either echo $login to see, or echo $query to see what is actually being passed to mysql. JM -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Why this doesn't work ?
ah! remove the whitespace between the COUNT and () : COUNT(login) instead of COUNT () ... Hi, Make this line instead $result = mysql_query($query) or die(mysql_error() . with the query $query; and you'll likely see the error. Here it goes: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '(login) FROM formacao WHERE login = 'a'' at line 1 Regards, Mário Gamito -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Why this doesn't work ?
On Mon, October 24, 2005 12:25 pm, Mário Gamito wrote: --- $query = SELECT COUNT (login) FROM WHERE login = '$login'; $result = mysql_query($query); mysql_fetch_row($result); --- It gives me Warning: mysql_fetch_row(): supplied argument is not a valid MySQL result resource in /var/www/html/registar_action.php on line 22 First, I'm going to give you a fish: ... FROM WHERE ... Which MySQL database TABLE is it that you think you are looking in? You have to tell it which table to look in. Now I'm gonna teach you to catch fish: Change your middle line to: $result = mysql_query($query) or die(br /$querybr / . mysql_error()); That will get PHP and MySQL to TELL YOU what's wrong, instead of just saying Something's wrong -- Like Music? http://l-i-e.com/artists.htm -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Why this doesn't work ?
Hi, Hi have this bit of code: - echo script language=\JavaScript\ window.location=\valid_cv_insert.php?email=$email\ /script; - but when passing to file valid_cv_insert.php, $email value doesn't go along. The page that has this code knows tha value of $email variable. How can i turn this around ? Thanking you in advance. Warm regards, Mário Gamito -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Why this doesn't work ?
Mário Gamito wrote: Hi, Hi have this bit of code: - echo script language=\JavaScript\ window.location=\valid_cv_insert.php?email=$email\ /script; - but when passing to file valid_cv_insert.php, $email value doesn't go along. The page that has this code knows tha value of $email variable. Echo out $email to see if what you think is there actually is. -- John C. Nichel ÜberGeek KegWorks.com 716.856.9675 [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Why this doesn't work ?
Ave,
I tried:
forminput type=text name=emailINPUT type=submit value=SUbmit
name=Submit/form
?php
if($Submit) {
echo
script language=\JavaScript\
window.location=\delete.php?email=$email\
/script;
}
?
In a simple page. It worked absolutely fine... The value of $email was
passed along to delete.php
I don't think there's something wrong with your code below.. There might be
some other reason affecting the transfer of the $email variable value.
Rahul S. Johari
Coordinator, Internet Administration
Informed Marketing Services Inc.
251 River Street
Troy, NY 12180
Tel: (518) 266-0909 x154
Fax: (518) 266-0909
Email: [EMAIL PROTECTED]
http://www.informed-sources.com
On 5/24/05 8:24 AM, Mário Gamito [EMAIL PROTECTED] wrote:
Hi,
Hi have this bit of code:
-
echo
script language=\JavaScript\
window.location=\valid_cv_insert.php?email=$email\
/script;
-
but when passing to file valid_cv_insert.php, $email value doesn't go along.
The page that has this code knows tha value of $email variable.
How can i turn this around ?
Thanking you in advance.
Warm regards,
Mário Gamito
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Re: [PHP] Why this doesn't work ?
Mário Gamito wrote: Hi, hi, the subject line of your post is not so good - make the subject relevant to your question, asking 'why doesn't this work' is like asking 'why are we here'. its liable to get you either: a, no answers. b, answers like this one. c, really useful answer like '42' ok on with the show Hi have this bit of code: - echo script language=\JavaScript\ window.location=\valid_cv_insert.php?email=$email\ /script; - but when passing to file valid_cv_insert.php, $email value doesn't go along. inside valid_cv_insert.php $email will only be set by the GET query if the ini setting register_globals is on. try doing this inside valid_cv_insert.php: ? var_dump( $_GET, $GET['email'] ); ? (depending on your version of php $_GET may or not exist in any case check this out (read it carefully!): http://php.net/en/language.variables.predefined as a sidenote, make sure you're doing some dumb like: ? $email = 'x'; echo $emial; ? ... its the kind fo thing I have wasted literally days on in the past. The page that has this code knows tha value of $email variable. how does it know it? possibly because you do something like?: ? $email = [EMAIL PROTECTED]; ? How can i turn this around ? you won't find much useful info on the back of your monitor ;-) it wasn't too clear exactly what you were looking for but the gist seems to be that you need to read up a bit on what register_globals is, the fact that the default has gone from 'On' to 'Off' somewhere in the not so distance past and what the consequences are for your code. still stuck? go read the manual a bit... then come back and ask some more. :-) good luck. Thanking you in advance. Warm regards, Mário Gamito -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] why this doesn't work as an external file but does inte rnally?
Perhaps you fixed things but they all appeared to work for me (at least mostly). https://celestica.tristarpromotions.com/NEW/index3.php This last one, seemed to not do the mouseout on the contact button, but all three seemed to work. Good job, Warren Vail -Original Message- From: John Nichel [mailto:[EMAIL PROTECTED] Sent: Tuesday, October 05, 2004 8:20 PM To: 'PHP Mailing Lists' Subject: Re: [PHP] why this doesn't work as an external file but does internally? Aaron Wolski wrote: Ok.. here are 3 links: https://celestica.tristarpromotions.com/NEW/index2.php This link... you'll see that the rollover effects on the top menu work. The external JS file (called: jsstuffnew.php) has code that looks like: img1on = new Image(); img1on.src = ?php echo $base_url; ?Graphics/home_on.gif; https://celestica.tristarpromotions.com/NEW/index.php This link... you'll see that the rollover effects on the top menu DO NOT work. The external JS file (called: jsstuff.php) has code that looks like: img1on = new Image(); img1on.src = ?php echo $base_url; ?Graphics/?php echo $img_home_on; ?; As you can see, the difference between the two is the fact that the image FILE NAME is hard coded into the file as opposed to calling. https://celestica.tristarpromotions.com/NEW/index3.php This link... you'll see that the rollover effects work as well. Instead of having an external file I have embedded the JS code directly into the page. Additionally, I have use code that looks like: img1on = new Image(); img1on.src = ?php echo $base_url; ?Graphics/?php echo $img_home_on; ?; Having visuals... does that help communicate what the problem is? Yes, the output of your JavaScript in the second example is missing $img_home_on (it's outputting nothing). Where does this variable get set? How about posting the php code for https://celestica.tristarpromotions.com/NEW/jsstuff.php -- By-Tor.com It's all about the Rush http://www.by-tor.com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] why this doesn't work as an external file but does internally?
Hi guys,
I have this code Javascript code:
if (document.images) {
img1on = new Image(); img1on.src = ?php echo $base_url;
?Graphics/?php echo $img_home_on; ?;
img2on = new Image(); img2on.src = ?php echo $base_url;
?Graphics/?php echo $img_programdetails_on; ?;
img3on = new Image(); img3on.src = ?php echo $base_url;
?Graphics/?php echo $img_products_on; ?;
img4on = new Image(); img4on.src = ?php echo $base_url;
?Graphics/?php echo $img_featuredproducts_on; ?;
img5on = new Image(); img5on.src = ?php echo $base_url;
?Graphics/?php echo $img_faq_on; ?;
img6on = new Image(); img6on.src = ?php echo $base_url;
?Graphics/?php echo $img_contact_on; ?;
img1off = new Image(); img1off.src = ?php echo $base_url;
?Graphics/?php echo $img_home_off; ?;
img2off = new Image(); img2off.src = ?php echo $base_url;
?Graphics/?php echo $img_programdetails_off; ?;
img3off = new Image(); img3off.src = ?php echo $base_url;
?Graphics/?php echo $img_products_off; ?;
img4off = new Image(); img4off.src = ?php echo $base_url;
?Graphics/?php echo $img_featuredproducts_off; ?;
img5off = new Image(); img5off.src = ?php echo $base_url;
?Graphics/?php echo $img_faq_off; ?;
img6off = new Image(); img6off.src = ?php echo
{$base_url}Graphics/{$img_contact_off}; ?;
}
When I include it in the main page it works without any problems. When I
link it as an external file it doesn't work.
As a side note, the following code example works in an external JS file:
img1off = new Image(); img1off.src = ?php echo $base_url;
?Graphics/home_off.gif;
Anyone know why the external file with two variables is not working but
it does work with one variable?
Thanks! I appreciate the help!
Regards,
Aaron
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Re: [PHP] why this doesn't work as an external file but does internally?
Aaron Wolski wrote: Hi guys, I have this code Javascript code: snip When I include it in the main page it works without any problems. When I link it as an external file it doesn't work. As a side note, the following code example works in an external JS file: img1off = new Image(); img1off.src = ?php echo $base_url; ?Graphics/home_off.gif; Anyone know why the external file with two variables is not working but it does work with one variable? What is doesn't work? Does it not output the second variable? Does it output php code? -- John C. Nichel ÜberGeek KegWorks.com 716.856.9675 [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] why this doesn't work as an external file but does internally?
[snip] I have this code Javascript code: [/snip] And the web has these JavaScript lists! Quaint, no? Anyhow, to make this work you will need to generate your JavaScript code with PHP. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] why this doesn't work as an external file but does internally?
-Original Message- From: Jay Blanchard [mailto:[EMAIL PROTECTED] Sent: October 5, 2004 3:52 PM To: [EMAIL PROTECTED] Subject: RE: [PHP] why this doesn't work as an external file but does internally? [snip] And the web has these JavaScript lists! Quaint, no? [/snip] If you look closely, it's tied in with PHP. But thanks your help! [snip] Anyhow, to make this work you will need to generate your JavaScript code with PHP. [/snip] If that was true then why does this work: img1off = new Image(); img1off.src = ?php echo $base_url; ?Graphics/home_off.gif; I certainly didn't generate it with PHP and it was included as an external file. Thanks! A -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] why this doesn't work as an external file but does internally?
[snip] If that was true then why does this work: img1off = new Image(); img1off.src = ?php echo $base_url; ?Graphics/home_off.gif; I certainly didn't generate it with PHP and it was included as an external file. [/snip] If this is true then your problem is solved. if not echo img1off = new Image(); img1off.src = . $base_url . Graphics/home_off.gif; I think I have the syntax correct -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] why this doesn't work as an external file but does internally?
Please reply to the list, and not just an individual person. Aaron Wolski wrote: -Original Message- From: John Nichel [mailto:[EMAIL PROTECTED] Sent: October 5, 2004 3:51 PM To: [EMAIL PROTECTED] Subject: Re: [PHP] why this doesn't work as an external file but does internally? What is doesn't work? Does it not output the second variable? Does it output php code? When I say it doesn't work, the images don't appear. It's a simply mouseover effect: image on and image off type of thing. When the page loads... the main image (the off image) is visible but when I move the mouse over an image it just shows blank (an X). Does that make it more clear? Sorry. No. I turn my radio on, but it doesn't work, what's the problem? See what I mean? The question doesn't supply enough information to make an educated guess as to what the problem may be. What error messages are produced? What does the remotely included file output? Does the second variable have value? Can you provide a link to where we can see the issue at play? So on, and so forth. Look at the source of your page that doesn't work, where the JS is supposed to be, and chances are, you'll see the problem. -- John C. Nichel ÜberGeek KegWorks.com 716.856.9675 [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] why this doesn't work as an external file but does internally?
Hi guys,
I have this code Javascript code:
if (document.images) {
img1on = new Image(); img1on.src = ?php echo $base_url;
?Graphics/?php echo $img_home_on; ?;
img2on = new Image(); img2on.src = ?php echo $base_url;
?Graphics/?php echo $img_programdetails_on; ?;
snip
Regards,
Aaron
When you mix PHP and javascript together in an external file, the file
needs to be PHP and you should include it with PHP. I just recently went
through this. I had an external javascript file with some PHP in it. It
was originally called into the index.php page as:
script type=text/javascript src=includes/links.js
But none of the PHP in the links.js worked.
So I renamed the file to links.php and called it in index.php like so:
?php include 'includes/links.php'; ?
And everything worked perfectly.
--
--Matthew Sims
--http://killermookie.org
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RE: [PHP] why this doesn't work as an external file but does inte rnally?
Right on, a .js file is probably not processed by the PHP engine, but while it's imbedded in a .php file, it is. Apples and Oranges, no? Warren Vail -Original Message- From: Aaron Wolski [mailto:[EMAIL PROTECTED] Sent: Tuesday, October 05, 2004 1:01 PM To: 'Jay Blanchard'; [EMAIL PROTECTED] Subject: RE: [PHP] why this doesn't work as an external file but does internally? -Original Message- From: Jay Blanchard [mailto:[EMAIL PROTECTED] Sent: October 5, 2004 3:52 PM To: [EMAIL PROTECTED] Subject: RE: [PHP] why this doesn't work as an external file but does internally? [snip] And the web has these JavaScript lists! Quaint, no? [/snip] If you look closely, it's tied in with PHP. But thanks your help! [snip] Anyhow, to make this work you will need to generate your JavaScript code with PHP. [/snip] If that was true then why does this work: img1off = new Image(); img1off.src = ?php echo $base_url; ?Graphics/home_off.gif; I certainly didn't generate it with PHP and it was included as an external file. Thanks! A -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] why this doesn't work as an external file but does internally?
File with the JS code is called: jsstuff.php Aaron -Original Message- From: Vail, Warren [mailto:[EMAIL PROTECTED] Sent: October 5, 2004 4:12 PM To: 'Aaron Wolski'; 'Jay Blanchard'; [EMAIL PROTECTED] Subject: RE: [PHP] why this doesn't work as an external file but does internally? Right on, a .js file is probably not processed by the PHP engine, but while it's imbedded in a .php file, it is. Apples and Oranges, no? Warren Vail -Original Message- From: Aaron Wolski [mailto:[EMAIL PROTECTED] Sent: Tuesday, October 05, 2004 1:01 PM To: 'Jay Blanchard'; [EMAIL PROTECTED] Subject: RE: [PHP] why this doesn't work as an external file but does internally? -Original Message- From: Jay Blanchard [mailto:[EMAIL PROTECTED] Sent: October 5, 2004 3:52 PM To: [EMAIL PROTECTED] Subject: RE: [PHP] why this doesn't work as an external file but does internally? [snip] And the web has these JavaScript lists! Quaint, no? [/snip] If you look closely, it's tied in with PHP. But thanks your help! [snip] Anyhow, to make this work you will need to generate your JavaScript code with PHP. [/snip] If that was true then why does this work: img1off = new Image(); img1off.src = ?php echo $base_url; ?Graphics/home_off.gif; I certainly didn't generate it with PHP and it was included as an external file. Thanks! A -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] why this doesn't work as an external file but does internally?
-Original Message- From: John Nichel [mailto:[EMAIL PROTECTED] Sent: October 5, 2004 4:06 PM To: PHP Mailing Lists Subject: Re: [PHP] why this doesn't work as an external file but does internally? Please reply to the list, and not just an individual person. No. I turn my radio on, but it doesn't work, what's the problem? See what I mean? The question doesn't supply enough information to make an educated guess as to what the problem may be. What error messages are produced? What does the remotely included file output? Does the second variable have value? Can you provide a link to where we can see the issue at play? So on, and so forth. Look at the source of your page that doesn't work, where the JS is supposed to be, and chances are, you'll see the problem. Ok.. here are 3 links: https://celestica.tristarpromotions.com/NEW/index2.php This link... you'll see that the rollover effects on the top menu work. The external JS file (called: jsstuffnew.php) has code that looks like: img1on = new Image(); img1on.src = ?php echo $base_url; ?Graphics/home_on.gif; https://celestica.tristarpromotions.com/NEW/index.php This link... you'll see that the rollover effects on the top menu DO NOT work. The external JS file (called: jsstuff.php) has code that looks like: img1on = new Image(); img1on.src = ?php echo $base_url; ?Graphics/?php echo $img_home_on; ?; As you can see, the difference between the two is the fact that the image FILE NAME is hard coded into the file as opposed to calling. https://celestica.tristarpromotions.com/NEW/index3.php This link... you'll see that the rollover effects work as well. Instead of having an external file I have embedded the JS code directly into the page. Additionally, I have use code that looks like: img1on = new Image(); img1on.src = ?php echo $base_url; ?Graphics/?php echo $img_home_on; ?; Having visuals... does that help communicate what the problem is? In terms of what errors I am seeing, etc... I cannot tell you that because NO errors come up at all, even with the external pages. Thanks John. Hope I explained it a bit better this time around. Regards, Aaron -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] why this doesn't work as an external file but does internally?
* Thus wrote Aaron Wolski:
What error messages are produced?
What does the remotely included file output?
Does the second variable have value?
Can you provide a link to where we can see the issue at play?
So on, and so forth.
Look at the source of your page that doesn't work, where the JS is
supposed to be, and chances are, you'll see the problem.
Ok.. here are 3 links:
https://celestica.tristarpromotions.com/NEW/index2.php
This link... you'll see that the rollover effects on the top menu work.
The external JS file (called: jsstuffnew.php) has code that looks like:
img1on = new Image(); img1on.src = ?php echo $base_url;
?Graphics/home_on.gif;
https://celestica.tristarpromotions.com/NEW/index.php
This link... you'll see that the rollover effects on the top menu DO NOT
work. The external JS file (called: jsstuff.php) has code that looks
like:
img1on = new Image(); img1on.src = ?php echo $base_url;
?Graphics/?php echo $img_home_on; ?;
$base_url and $img_home_on have no value in jsstuff.php thus you
have a javascript that results in:
img1on.src = Graphics/
Also, you should also send a javascript header with the jsstuff.php
file:
header('Content-Type: application/x-javascript');
Curt
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Re: [PHP] why this doesn't work as an external file but does internally?
Aaron Wolski wrote: Ok.. here are 3 links: https://celestica.tristarpromotions.com/NEW/index2.php This link... you'll see that the rollover effects on the top menu work. The external JS file (called: jsstuffnew.php) has code that looks like: img1on = new Image(); img1on.src = ?php echo $base_url; ?Graphics/home_on.gif; https://celestica.tristarpromotions.com/NEW/index.php This link... you'll see that the rollover effects on the top menu DO NOT work. The external JS file (called: jsstuff.php) has code that looks like: img1on = new Image(); img1on.src = ?php echo $base_url; ?Graphics/?php echo $img_home_on; ?; As you can see, the difference between the two is the fact that the image FILE NAME is hard coded into the file as opposed to calling. https://celestica.tristarpromotions.com/NEW/index3.php This link... you'll see that the rollover effects work as well. Instead of having an external file I have embedded the JS code directly into the page. Additionally, I have use code that looks like: img1on = new Image(); img1on.src = ?php echo $base_url; ?Graphics/?php echo $img_home_on; ?; Having visuals... does that help communicate what the problem is? Yes, the output of your JavaScript in the second example is missing $img_home_on (it's outputting nothing). Where does this variable get set? How about posting the php code for https://celestica.tristarpromotions.com/NEW/jsstuff.php -- By-Tor.com It's all about the Rush http://www.by-tor.com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Why PHP doesn't work with Apache2?
Just to add a little fuel to the fire, the only way I've seen or been able to get PHP and Apache 2 working together is by installing each from my Red Hat 8.0 CD's. When I tried to compile each together, I got many an error. When I start doing some actually web work on my testing server, I imagine I'll uninstall Apache 2, and go with some version of 1.3 -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Why PHP doesn't work with Apache2?
Ok I am hearing a bad rumor that Red Hat 8.0 and the Mac xserve both come with Apache 2.. now is this a rumor or is this true? If it's true.. why? And does anybody have any experience in uninstalling Apache 2 on the xserve and does it break anything? Cheers! Rick Don't walk in front of me, I may not follow, Don't walk behind me, I may not lead, Just walk beside me, and be my friend. - Unknown From: Tim Thorburn [EMAIL PROTECTED] Date: Thu, 23 Jan 2003 05:03:00 -0500 To: [EMAIL PROTECTED] Subject: Re: [PHP] Why PHP doesn't work with Apache2? Just to add a little fuel to the fire, the only way I've seen or been able to get PHP and Apache 2 working together is by installing each from my Red Hat 8.0 CD's. When I tried to compile each together, I got many an error. When I start doing some actually web work on my testing server, I imagine I'll uninstall Apache 2, and go with some version of 1.3 -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Why PHP doesn't work with Apache2?
Well, I don't know about trying to uninstall it, but RH8.0 does come with Apache 2 It works fine and I have not ran into a reason why I should use the older version for this. Granted I only use it for testing, my live server is RH7.2 which uses Apache 1 - Original Message - From: Richard Baskett [EMAIL PROTECTED] To: PHP General [EMAIL PROTECTED] Sent: Thursday, January 23, 2003 2:28 PM Subject: Re: [PHP] Why PHP doesn't work with Apache2? Ok I am hearing a bad rumor that Red Hat 8.0 and the Mac xserve both come with Apache 2.. now is this a rumor or is this true? If it's true.. why? And does anybody have any experience in uninstalling Apache 2 on the xserve and does it break anything? Cheers! Rick Don't walk in front of me, I may not follow, Don't walk behind me, I may not lead, Just walk beside me, and be my friend. - Unknown From: Tim Thorburn [EMAIL PROTECTED] Date: Thu, 23 Jan 2003 05:03:00 -0500 To: [EMAIL PROTECTED] Subject: Re: [PHP] Why PHP doesn't work with Apache2? Just to add a little fuel to the fire, the only way I've seen or been able to get PHP and Apache 2 working together is by installing each from my Red Hat 8.0 CD's. When I tried to compile each together, I got many an error. When I start doing some actually web work on my testing server, I imagine I'll uninstall Apache 2, and go with some version of 1.3 -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Why PHP doesn't work with Apache2?
Albert Camus. Your sig has a quote attributed to unknown. It was Albert Camus. Don't walk in front of me, I may not follow, Don't walk behind me, I may not lead, Just walk beside me, and be my friend. -Albert Camus On Thursday 23 January 2003 12:28 pm, Richard Baskett wrote: Ok I am hearing a bad rumor that Red Hat 8.0 and the Mac xserve both come with Apache 2.. now is this a rumor or is this true? If it's true.. why? And does anybody have any experience in uninstalling Apache 2 on the xserve and does it break anything? Cheers! Rick Don't walk in front of me, I may not follow, Don't walk behind me, I may not lead, Just walk beside me, and be my friend. - Unknown From: Tim Thorburn [EMAIL PROTECTED] Date: Thu, 23 Jan 2003 05:03:00 -0500 To: [EMAIL PROTECTED] Subject: Re: [PHP] Why PHP doesn't work with Apache2? Just to add a little fuel to the fire, the only way I've seen or been able to get PHP and Apache 2 working together is by installing each from my Red Hat 8.0 CD's. When I tried to compile each together, I got many an error. When I start doing some actually web work on my testing server, I imagine I'll uninstall Apache 2, and go with some version of 1.3 -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Why PHP doesn't work with Apache2?
On Thu, 23 Jan 2003 12:28:21 -0800, Richard Baskett wrote: Ok I am hearing a bad rumor that Red Hat 8.0 and the Mac xserve both come with Apache 2.. now is this a rumor or is this true? If it's true.. why? And does anybody have any experience in uninstalling Apache 2 on the xserve and does it break anything? Cheers! Rick Don't walk in front of me, I may not follow, Don't walk behind me, I may not lead, Just walk beside me, and be my friend. - Unknown From: Tim Thorburn [EMAIL PROTECTED] Date: Thu, 23 Jan 2003 05:03:00 -0500 To: [EMAIL PROTECTED] Subject: Re: [PHP] Why PHP doesn't work with Apache2? Just to add a little fuel to the fire, the only way I've seen or been able to get PHP and Apache 2 working together is by installing each from my Red Hat 8.0 CD's. When I tried to compile each together, I got many an error. When I start doing some actually web work on my testing server, I imagine I'll uninstall Apache 2, and go with some version of 1.3 I also uninstalled apache 2 from Redhat 8.0. Just go and grab the latest apache 1.3 source rpm from 7.3, rebuild the rpm and install that. Works like a charm. I could also never get php to build against Apache2 on Redhat 8.0. http://iptrack.sourceforge.net -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Why PHP doesn't work with Apache2?
I don't want to start a flame-war here, just asking for specifics on a question I have :) I know that PHP and Apache 2 (on Linux anyway) have some problems working together. I was just wondering, for my own education, why is that? Is it a problem in Apache 2 or in PHP? (Not that I want to lay blame, just wondering). Can someone point me to some ressource explaining the main points of why PHP won't work with Apache 2 just yet? Thanks. Jc -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] Why PHP doesn't work with Apache2?
Apache2 now work with php in aspx (PHP is as a module) -Original Message- From: Jean-Christian Imbeault [mailto:[EMAIL PROTECTED]] Sent: Wednesday, January 22, 2003 6:06 PM To: [EMAIL PROTECTED] Subject: [PHP] Why PHP doesn't work with Apache2? I don't want to start a flame-war here, just asking for specifics on a question I have :) I know that PHP and Apache 2 (on Linux anyway) have some problems working together. I was just wondering, for my own education, why is that? Is it a problem in Apache 2 or in PHP? (Not that I want to lay blame, just wondering). Can someone point me to some ressource explaining the main points of why PHP won't work with Apache 2 just yet? Thanks. Jc -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Why PHP doesn't work with Apache2?
Henry wrote: Apache2 now work with php in aspx (PHP is as a module) Really!? I was sure there were still some issues ... Jc -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] Why PHP doesn't work with Apache2?
what issues for example? I do know I can successful install php in module with apache2.0.43 without error messages, also execution was successful can you tell me what issues did you see? -Original Message- From: Jean-Christian Imbeault [mailto:[EMAIL PROTECTED]] Sent: Wednesday, January 22, 2003 7:11 PM To: [EMAIL PROTECTED] Subject: Re: [PHP] Why PHP doesn't work with Apache2? Henry wrote: Apache2 now work with php in aspx (PHP is as a module) Really!? I was sure there were still some issues ... Jc -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Why PHP doesn't work with Apache2?
Henry wrote: what issues for example? I do know I can successful install php in module with apache2.0.43 without error messages, also execution was successful can you tell me what issues did you see? A successful install means nothing. My question is basically, does Apache2 work with PHP 100% or is it still recommend to use Apache 1.3.27? If it is still not recommended to use Apache2, why? If you think Apache2 and PHP work perfectly well together can you point me to some info that says so? I can't see anywhere on the PHP web site that recommends using Apache2. Jc -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Why PHP doesn't work with Apache2?
it depends on you your aim u can consider your criterias between php with apache 1.3X apache 2 if u try to use pragmatism about it ... maybe u can find the result that php with apache 2 is better ? so don't you need more argument ? one more . now i'm pleasure of apache2's performancesecurity on win32 platform ( should i use 'even' ? : )... ) -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Why PHP doesn't work with Apache2?
Yasin Inat wrote: it depends on you your aim Ok, to put it more simply, Are there cases where something would work in Apache 1.3.27 + PHP that would break in Apache2 + PHP?? A simple yes or no will suffice. If the answer is no, I am curious as to why not ... Thanks, Jc -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Why PHP doesn't work with Apache2?
Henry wrote: what issues for example? I do know I can successful install php in module with apache2.0.43 without error messages, also execution was successful can you tell me what issues did you see? A successful install means nothing. My question is basically, does Apache2 work with PHP 100% or is it still recommend to use Apache 1.3.27? If it is still not recommended to use Apache2, why? Because the server doesn't work very well yet. There are issues in the filter api and you can't really uses a threaded mpm as many of the 3rd-party libraries that are commonly linked into PHP are simply not threadsafe. The first issue can be fixed, the second issue is handled by only running Apache2 in prefork mode which makes the server look like Apache1. If you have to run Apache2 looking like Apache1 the benefits are minor, so the motivation for people to put a whole lot of effort into fixing issue #1 is minimal. -Rasmus -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Why PHP doesn't work with Apache2?
Rasmus Lerdorf wrote: Because the server doesn't work very well yet. There are issues in the filter api and you can't really uses a threaded mpm as many of the 3rd-party libraries that are commonly linked into PHP are simply not threadsafe. Thank you! That's the kind of answer I was looking for. If I understand correctly PHP will not work correctly because some parts of it are not thread-safe. Is the PHP team working on getting PHP to be thread-safe? Does it look promising? Might version 5 be thread-safe? Thanks again, Jc -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Why PHP doesn't work with Apache2?
On Thu, 23 Jan 2003, Jean-Christian Imbeault wrote: Rasmus Lerdorf wrote: Because the server doesn't work very well yet. There are issues in the filter api and you can't really uses a threaded mpm as many of the 3rd-party libraries that are commonly linked into PHP are simply not threadsafe. Thank you! That's the kind of answer I was looking for. If I understand correctly PHP will not work correctly because some parts of it are not thread-safe. No, you didn't understand correctly. I specifically said the thread safety issues were in 3rd party libraries and not in PHP. This is not going to be solved anytime soon since it isn't really something we can fix. We can hack around it and add mutexes and stuff to protect ourselves from broken libraries, but in the end that just brings us closer to the non-threaded model that we already have with Apache-1.3, so there is very little motivation to even go through this bit of pain. Why exactly are you asking? Is there some feature in Apache2 that you need that is not available in Apache-1.3? -Rasmus -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Why PHP doesn't work with Apache2?
Rasmus Lerdorf wrote: No, you didn't understand correctly. I specifically said the thread safety issues were in 3rd party libraries and not in PHP. Sorry, I thought by 3rd party libraries you meant libraries that PHP is dependent upon. Do you mean libraries used by PHP or Apache. And if these are libraries used by PHP, do you mean library that as in the multi-byte library (i.e. libraries that add functionality to PHP), or do you mean C libraries used when compiling PHP. Why exactly are you asking? Is there some feature in Apache2 that you need that is not available in Apache-1.3? I don't want to move from Apache 1-3 to Apache. I just keep hearing that PHP is not ready for Apache2 yet and I wanted to educate myself as to why. I don't like just being told something and not understanding the reason behind the answer. So this boils down to Apache2 using threads and PHP not being thread-safe? And the reason that PHP is not thread-safe is that some 3rd party libraries PHP used are not thread-safe. Now the only two questions I have left are : #1 what those libraries are used for. I.e. are they part of PHP or libraries that are used to compile PHP? If they are libraries used to compile PHP, I would assume that Apache2 must have faced similar issues when going from a forking model to a threaded model? #2 Is there progress being made towards having PHP work with Apache2. And who is working on this (if not the PHP team). Thanks again for the clarifications! Jc -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Why PHP doesn't work with Apache2?
On Thu, 23 Jan 2003, Jean-Christian Imbeault wrote: Rasmus Lerdorf wrote: No, you didn't understand correctly. I specifically said the thread safety issues were in 3rd party libraries and not in PHP. Sorry, I thought by 3rd party libraries you meant libraries that PHP is dependent upon. Do you mean libraries used by PHP or Apache. And if these are libraries used by PHP, do you mean library that as in the multi-byte library (i.e. libraries that add functionality to PHP), or do you mean C libraries used when compiling PHP. Common libraries such as gdbm or c-client, for example. So this boils down to Apache2 using threads and PHP not being thread-safe? No And the reason that PHP is not thread-safe is that some 3rd party libraries PHP used are not thread-safe. No If they are libraries used to compile PHP, I would assume that Apache2 must have faced similar issues when going from a forking model to a threaded model? Why? Apache by itself doesn't need to talk to anywhere near the same number of 3rd-party things that PHP commonly talks to. #2 Is there progress being made towards having PHP work with Apache2. And who is working on this (if not the PHP team). Nobody really is. And I don't see this changing until there are some really compelling features in Apache2 to warrant the massive effort it would take. And yes, a working perchild mpm may be that compelling feature, but we don't have one of those. All of this stuff is available by reading the PHP and Apache dev lists, by the way. They are archived and not that hard to find. -Rasmus -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Why it doesn't work?
Hi to all,
I found this error in my code:
class BaseForm {
var $_fields;
var $_method;
var $_postedData;
var $_formAction;
function init($eMsgFile,$method,$formAction) {
...
...
$this-_method=strtoupper($method);
- Why next line gives me the error variable _POST is undefined ??? --
$this-_postedData=${_.$this-_method};
$this-_formAction=(empty($formAction))?basename($_SERVER['PHP_SELF']):$formAction;
}
Is it normal
Thank you a lot!
KidA
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[PHP] Why while doesn't work?
Although the table con_inf in db sbwresearch contains 3 records with
username as the first column, the following short script generates a blank
page:
?php
$connection=mysql_connect(localhost,wagner,xyz) or die (No
connection!);
$db=mysql_select_db(sbwresearch,$connection) or die (No database!);
$qry_1=select * from con_inf;
$result_1=mysql_query($qry_1,$connection) or die (No query # 1!);
while ($row_1=mysql_fetch_array($result_1,mysql_assoc))
{
$username=$row_1[username];
echo $username;
};
mysql_free_result($result_1);
mysql_close($connection);
exit;
?
Why? I've use the statement in other scripts and it works!
Thanks!
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RE: [PHP] Why while doesn't work?
If you only want the associative array, just use mysql_fetch_array($result). If you're using the constant MYSQL_ASSOC, uppercase it, and don't quote it. Although the table con_inf in db sbwresearch contains 3 records with username as the first column, the following short script generates a blank page: mysql_fetch_array($result_1,mysql_assoc)) -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
