Re: [PHP] Odd behaviour of non-existent keys?
Thanks for your help, everyone, especially Michael Sims. I've reported the bug: http://bugs.php.net/bug.php?id=29848 -- Geoff Caplan Vario Software Ltd (+44) 121-515 1154 -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] Odd behaviour of non-existent keys?
Geoff Caplan wrote: > Michael Sims wrote: >> IMHO what you have described is a bug in PHP, and if I were you, >> I'd report it as such. If it's not a bug it at least has a very >> high WTF factor. > > Problem with reporting is that I am using Debian Test and the current > PHP version is too old to report. If someone with an current PHP > version could replicate the problem, let me know and I will report it. > Here is the code: [snip] I've replicated it in version 4.3.8, as well as five other previous versions (I always keep my build directories around for a while on my development server.) Here's a suggestion so that you don't have to depend on other people to reproduce it for you (and in case one of the PHP maintainers asks you to try a snapshot): Download the PHP tarball you want to test with (4.3.8 or snapshot or whatever) and extract it in your home directory, then configure it and run "make". Then create your test script as a CLI script and make the shebang line: #!/home//php-/sapi/cli/php This allows you to test with whatever version you wish without having to actually install it. FWIW... -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Odd behaviour of non-existent keys?
Hi folks,
Michael Sims wrote:
MS> IMHO what you have described is a bug in PHP, and if I were you,
MS> I'd report it as such. If it's not a bug it at least has a very
MS> high WTF factor.
Problem with reporting is that I am using Debian Test and the current
PHP version is too old to report. If someone with an current PHP
version could replicate the problem, let me know and I will report it.
Here is the code:
$foo = '' ;
$foo['one']['two'] = 'test-value' ;
print( 'Running tests for one non-existent key' ) ;
// Test isset() for non-existent key
if( isset( $foo['one']['two']['three'] ) )
{
print( "Unexpected isset(): evaluated to TRUE" ) ;
}
else
{
print( "Expected isset(): evaluated to FALSE" ) ;
}
// Use var_dump() to find out what is going on
// Expected: evaluate to NULL
// Actual: evaluated to 'string(1) "t"'
// ("x" is the first char of "test-value")
print( 'var_dump() output (expecting NULL):' ) ;
var_dump( $foo['one']['two']['three'] ) ;
// Add another non-existent key and things
// work as expected
print( 'Running tests for two non-existent keys' ) ;
if( isset( $foo['one']['two']['three']['four'] ) )
{
print( "Unexpected isset(): evaluated to TRUE" ) ;
}
else
{
print( "Expected isset(): evaluated to FALSE" ) ;
}
print( 'var_dump() output (expecting NULL):' ) ;
var_dump( $foo['one']['two']['three']['four'] ) ;
--
Geoff Caplan
Vario Software Ltd
(+44) 121-515 1154
--
PHP General Mailing List (http://www.php.net/)
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[PHP] Re [PHP] Odd behaviour of non-existent keys?
Michael, MS> IMHO what you have described is a bug in PHP, and if I were you, I'd report it as MS> such. If it's not a bug it at least has a very high WTF factor. You are right - it does seem like a bug. But I assumed that something as basic as this would have been spotted by now. I don't suppose it would do any harm for me to report it, though, now there are at least 2 of us that think it looks odd. -- Geoff Caplan Vario Software Ltd (+44) 121-515 1154 -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Odd behaviour of non-existent keys?
From: "Geoff Caplan" <[EMAIL PROTECTED]> Getting a result I don't understand. Why does the non-existent key in the array below evaluate to the first char of the array value? $foo = '' ; $foo['one']['two'] = 'test-value' ; // Evaluates to: string(1) "t" var_dump( $foo['one']['two']['three'] ) ; // Evaluates to NULL, as expected var_dump($foo['one']['two']['three']['four'] ) ; Can anyone enlighten me? Strings are arrays. PHP probably takes the string 'three' and converts it to a integer to see what "key" of the string you're requesting. $foo = 'bar'; echo $foo[1]; //should echo 'a' Does that help or do you need a deeper explanation (that I probably can't provide!) ;) ---John Holmes... -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
