Re: [PHP] mail command failing
On Tue, 2010-06-29 at 10:00 -0700, Mike Wright wrote:
Hi all,
I'm very puzzled by this. I've been using the php mail command for
years but now I can't get it to work and can't figure out how to
diagnose the problem.
The code below was copied from the manual (addresses changed, etc);
php.ini has safe_mode off; binary is at /usr/sbin/sendmail.
?php
ini_set(SMTP,localhost );
ini_set('sendmail_from', 'mike.wri...@mailinator.com');
$name = Mike Wright; //senders name
$email = mike.wri...@mailinator.com; //senders e-mail adress
$recipient = mike.wri...@mailinator.com; //recipient
$body = The text for the mail...; //mail body
$subject = Subject for review; //subject
$header = From: $name $email\r\n; //optional headerfields
$echo = mail($recipient, $subject, $body, $header) ? 'success':'fail';
echo br/br/$echo;
I can access the mail server with /usr/bin/mailx and by telnet
localhost 25. I can also send mail using php by using 'exec ( echo
$body | mailx -s $subject $recipient)'.
php-5.2.29 on fedora10 with apache 2.2.14. Can this be selinux related?
Any ideas or troubleshooting tips?
Thanks,
Mike Wright
The first ini_set variable you're setting I believe will only work for a
Windows server.
Aside from that, yes SELinux does prevent the mail command from sending
mail by default. I'm using Fedora 11, so I assume it will be similar;
there are config tools for setting SELinux policies, or you could even
turn it off (not advised on a live server). As a test, try turning it
off temporarily just to see if it is the culprit, then you can determine
what policy changes need to be made.
Thanks,
Ash
http://www.ashleysheridan.co.uk
Re: [PHP] mail command failing
Ashley Sheridan wrote: On Tue, 2010-06-29 at 10:00 -0700, Mike Wright wrote: Hi all, I'm very puzzled by this. I've been using the php mail command for years but now I can't get it to work and can't figure out how to diagnose the problem. php-5.2.29 on fedora10 with apache 2.2.14. Can this be selinux related? The first ini_set variable you're setting I believe will only work for a Windows server. Aside from that, yes SELinux does prevent the mail command from sending mail by default. I'm using Fedora 11, so I assume it will be similar; there are config tools for setting SELinux policies, or you could even turn it off (not advised on a live server). As a test, try turning it off temporarily just to see if it is the culprit, then you can determine what policy changes need to be made. Thanks, Ash, but no cigar. Selinux is set disabled. Absolutely baffled and confounded that there doesn't seem to be a way to diagnose the problem. Mike -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] mail command failing
From: Ashley Sheridan
On Tue, 2010-06-29 at 10:00 -0700, Mike Wright wrote:
Hi all,
I'm very puzzled by this. I've been using the php mail command for
years but now I can't get it to work and can't figure out how to
diagnose the problem.
The code below was copied from the manual (addresses changed, etc);
php.ini has safe_mode off; binary is at /usr/sbin/sendmail.
?php
ini_set(SMTP,localhost );
ini_set('sendmail_from', 'mike.wri...@mailinator.com');
$name = Mike Wright; //senders name
$email = mike.wri...@mailinator.com; //senders e-mail adress
$recipient = mike.wri...@mailinator.com; //recipient
$body = The text for the mail...; //mail body
$subject = Subject for review; //subject
$header = From: $name $email\r\n; //optional headerfields
$echo = mail($recipient, $subject, $body, $header) ?
'success':'fail';
echo br/br/$echo;
I can access the mail server with /usr/bin/mailx and by telnet
localhost 25. I can also send mail using php by using 'exec (
echo
$body | mailx -s $subject $recipient)'.
php-5.2.29 on fedora10 with apache 2.2.14. Can this be selinux
related?
Any ideas or troubleshooting tips?
The first ini_set variable you're setting I believe will
only work for a Windows server.
Aside from that, yes SELinux does prevent the mail command from
sending
mail by default. I'm using Fedora 11, so I assume it will be similar;
there are config tools for setting SELinux policies, or you could even
turn it off (not advised on a live server). As a test, try turning it
off temporarily just to see if it is the culprit, then you can
determine
what policy changes need to be made.
Don't turn it off, set it for Permissive mode. It will both allow the
connection and log why it wouldn't allow it in normal operation. Then
you can review the logs and make the necessary adjustments.
Bob McConnell
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Re: [PHP] mail command failing
On Tue, 2010-06-29 at 10:27 -0700, Mike Wright wrote: Ashley Sheridan wrote: On Tue, 2010-06-29 at 10:00 -0700, Mike Wright wrote: Hi all, I'm very puzzled by this. I've been using the php mail command for years but now I can't get it to work and can't figure out how to diagnose the problem. php-5.2.29 on fedora10 with apache 2.2.14. Can this be selinux related? The first ini_set variable you're setting I believe will only work for a Windows server. Aside from that, yes SELinux does prevent the mail command from sending mail by default. I'm using Fedora 11, so I assume it will be similar; there are config tools for setting SELinux policies, or you could even turn it off (not advised on a live server). As a test, try turning it off temporarily just to see if it is the culprit, then you can determine what policy changes need to be made. Thanks, Ash, but no cigar. Selinux is set disabled. Absolutely baffled and confounded that there doesn't seem to be a way to diagnose the problem. Mike I can only guess that PHP somehow isn't seeing the sendmail program for some reason. Have you compared the output of a phpinfo() call on this system and another where it is working to see if there are any obvious differences in the server setups? Thanks, Ash http://www.ashleysheridan.co.uk
Re: [PHP] Mail Command Body Issue - Trying to use 'do while' loop
On Sep 12, 2009, at 3:47 PM, c...@hosting4days.com wrote:
I'm having a problem with mail body issue trying to use 'do while'
loop in the $mail_body var.
this line:
do { echo $row_get1['name'] } while ($row_get1 = mysql_fetch_assoc
($get1))
will show ok when it's on the page elsewhere (not in the $mail_body
var) but typed like:
--- ok on web page (not email)
?php do {
echo $row_get1['vt_name']; } while ($row_get1 = mysql_fetch_assoc
($get1)); ?
Q: i want TEXT LOOP TEXT - AM I MISSING some syntax characters
like(; or??) somewhere or
THANKS for your help - dave
I got it working like this
?php
$loop1 = '';
do {
$loop1 = $loop1.\n.$row_get1['vt_name'].' - ';
} while ($row_get1 = mysql_fetch_assoc($get1));
$mail_body = test \n\n.test2 .$loop1.Thanks
test xxx; ?
Q: is this the best way?
- full email code
?php
$mail_body = test \n\n.test2.do { echo 'test' } while
($row_get1 = mysql_fetch_assoc($get1)).Thanks
test xxx; ?
?php
$Name = test; //senders name
$email = t...@test.com; //senders e-mail adress
$recipientname = t...@test.com;
$recipient = t...@test.com; //recipient
$subject = test.
$header = From: . $Name . . $email . \r\n; //optional
headerfields
$fullto = $recipientname . . $recipient . ;
//$fullto = $recipientname . . $recipient . ., .$recip2;
ini_set('sendmail_from', 't...@test.com');
mail($fullto, $subject, $mail_body, $header); //mail command :)
?
Thanks,
c...@hosting4days.com
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Thanks,
c...@hosting4days.com
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Re: [PHP] Execute command line as a different user
On Tue, Jul 1, 2008 at 1:17 PM, Matt palermo [EMAIL PROTECTED] wrote: My PHP is running as a user with limited rights. I'd like to execute a command line as a different user. I'm trying to delete a file and the PHP user doesn't have access to do this. I know the username and password for the admin user that has rights to delete a file. Is there a command I can use to make PHP run a delete command as the admin user? If so, how can I do this? You can always create a script and have crond handle it running as the admin user, if you're on *NIX. Otherwise, check into the Winblows command `AT`. -- /Daniel P. Brown Dedicated Servers - Intel 2.4GHz w/2TB bandwidth/mo. starting at just $59.99/mo. with no contract! Dedicated servers, VPS, and hosting from $2.50/mo. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Execute command line as a different user
On Tue, Jul 1, 2008 at 1:17 PM, Matt palermo [EMAIL PROTECTED] wrote: My PHP is running as a user with limited rights. I'd like to execute a command line as a different user. I'm trying to delete a file and the PHP user doesn't have access to do this. I know the username and password for the admin user that has rights to delete a file. Is there a command I can use to make PHP run a delete command as the admin user? If so, how can I do this? Thanks, Matt -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php I did a quick check on php.net, there is a post on there that talks about using sudo: @exec(echo 'apache' | /usr/bin/sudo -u mail -S /var/www/html/mailset.sh $name); You may want to read thru it, php.net/exec, go to the user notes. -- -Dan Joseph www.canishosting.com - Plans start @ $1.99/month. Build a man a fire, and he will be warm for the rest of the day. Light a man on fire, and will be warm for the rest of his life.
Re: [PHP] Execute command from web browser
Well, you're missing a semi-colin after the exec() statement, and the echo.
If it wasn't the syntax error, make sure the program exists with file_exists();
- Craige
On Sat, May 3, 2008 at 11:28 PM, [EMAIL PROTECTED] wrote:
Hi all
I try write a code to execute service in my server from web browser
I write next
/var/www/html/squidup.html
?
exec ('/usr/bin/squid/sbin/squid')
echo Squid UP
?
but, don't work from web browser.
What is wrong
Thanks,
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Re: [PHP] Execute command from web browser
On 5/3/08, [EMAIL PROTECTED] [EMAIL PROTECTED] wrote:
Hi all
I try write a code to execute service in my server from web browser
I write next
/var/www/html/squidup.html
Should it be... squidup.php?
?
exec ('/usr/bin/squid/sbin/squid')
echo Squid UP
?
but, don't work from web browser.
What is wrong
Thanks,
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Re: [PHP] simple command help
Daniel Brown wrote: On Fri, Feb 29, 2008 at 5:22 AM, Shelley [EMAIL PROTECTED] wrote: Hi all, What's the command to use if I want to remove all the directories and files except 'a.gz' under a directory? There isn't a command in PHP to do this. You'd have to write a script to handle that processing. If you're looking for general Unix/Linux commands, you're in the wrong place, but here's one possible way to do it: sudo chattr +i /path/to/a.gz rm -fR /path sudo chattr -i /path/to/a.gz If you have sudo access (or straight root access, in which case you can su - to root and skip the 'sudo' part of the command), that will set the file attribute to immutable, which means no one - including root or the system itself - can modify or delete that file unless they have the CAP_LINUX_IMMUTABLE capability (such as root) and issue the 'chattr -i filename' command. That's what I wanted. Thanks. I have full priviledge of the directory. -- Cheers, Shelley -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] simple command help
What's the command to use if I want to remove all the directories and
files except 'a.gz' under a directory?
There isn't one. If you're using *nix, you could try this:
exec('find ! -name a.gz -maxdepth 1 -exec rm -rf {} \;');
Or something like that. If you're on Windows you'll need someone else... :-)
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Re: [PHP] simple command help
On Fri, Feb 29, 2008 at 5:22 AM, Shelley [EMAIL PROTECTED] wrote:
Hi all,
What's the command to use if I want to remove all the directories and
files except 'a.gz' under a directory?
There isn't a command in PHP to do this. You'd have to write a
script to handle that processing.
If you're looking for general Unix/Linux commands, you're in the
wrong place, but here's one possible way to do it:
sudo chattr +i /path/to/a.gz
rm -fR /path
sudo chattr -i /path/to/a.gz
If you have sudo access (or straight root access, in which case
you can su - to root and skip the 'sudo' part of the command), that
will set the file attribute to immutable, which means no one -
including root or the system itself - can modify or delete that file
unless they have the CAP_LINUX_IMMUTABLE capability (such as root) and
issue the 'chattr -i filename' command.
--
/Dan
Daniel P. Brown
Senior Unix Geek
? while(1) { $me = $mind--; sleep(86400); } ?
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Re: [PHP] system command runs application, but application doesn't work correctly
On Jan 16, 2008 7:56 PM, Apple [EMAIL PROTECTED] wrote: Hello, I'm trying to run mencoder command line utility to encode videos. When I use these two command in terminal (through SSH), everything works fine. But when I run them from PHP script with system command, it doesn't work. [snip] Try replacing system() with die() and letting it print out the information full command string. That may give you an idea of a variable that's either incorrect or undefined. If you copy and paste it and run the command from the command line and it works, then it may be permissions issues. One part of the snipped content that I noticed kept repeating is the following (and actually ending with this line): 'VDecoder init failed :( Read DOCS/HTML/en/codecs.html' Did you follow the advice and read that document? Beyond that, it's a question that should probably instead be asked on a mencoder mailing list, since PHP's system() function is working correctly, but apparently isn't getting the information it needs to pass stuff back-and-forth with the system. -- /Dan Daniel P. Brown Senior Unix Geek and #1 Rated Year's Coolest Guy By Self Since Nineteen-Seventy-[mumble]. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] system command
Maybe something to do with the last line (but I get several lines)
Return Values
Returns the last line of the command output on success, and FALSE on failure.
I have within a web page:
$a=system('/usr/bin/lynx -dump http://api.hostip.info/country.php?ip='.$aa);
?
.
later I pickup the variable $a again ...
The problem for me is that the line $a=system('/usr/bin/lynx -dump
http://api.hostip.info/country.php?ip='.$aa); prints (before ) the
result ($a). I need the variable within the program, but do not want to
display it. It seems that 'system' includes an 'echo'
I always go back to the manual:
http://php.net/system
Maybe that built-in echo is related to this:
The system() call also tries to automatically flush the web server's output
buffer after each line of output if PHP is running as a server module.
Check out the other Program Execution Functions functions http://php.net/exec
particularly http://php.net/manual/en/function.exec.php
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RE: [PHP] system command
Use double quotes to get the value of $a or else you get the literal string
$a.
$aa=system(lynx -dump http://api.hostip.info/country.php?ip=$a,$location);
or
$aa=system('lynx -dump http://api.hostip.info/country.php?ip='.$a,$location);
Thanks! 1st solution did not work for me, but the second one did.
I still have a problem with it. It prints the info to the page. Can I
suppress this somehow?
man lynx
?
I don't use lynx and I don't know what you mean by info to the page.
I tried
lynx -dump http://www.google.com
to try to see what you mean.
Maybe something to do with the last line (but I get several lines)
Return Values
Returns the last line of the command output on success, and FALSE on failure.
Sorry.
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Re: [PHP] system command
Instruct ICC wrote:
Use double quotes to get the value of $a or else you get the literal string
$a.
$aa=system(lynx -dump http://api.hostip.info/country.php?ip=$a,$location);
or
$aa=system('lynx -dump http://api.hostip.info/country.php?ip='.$a,$location);
Thanks! 1st solution did not work for me, but the second one did.
I still have a problem with it. It prints the info to the page. Can I
suppress this somehow?
man lynx
?
I don't use lynx and I don't know what you mean by info to the page.
I tried
lynx -dump http://www.google.com
to try to see what you mean.
Maybe something to do with the last line (but I get several lines)
Return Values
Returns the last line of the command output on success, and FALSE on failure.
I have within a web page:
?php
$a=system('/usr/bin/lynx -dump http://api.hostip.info/country.php?ip='.$aa);
?
H1 .
later I pickup the variable $a again ...
The problem for me is that the line $a=system('/usr/bin/lynx -dump
http://api.hostip.info/country.php?ip='.$aa); prints (before H1) the
result ($a). I need the variable within the program, but do not want to
display it. It seems that 'system' includes an 'echo'
bye
Ronald
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Re: [PHP] system command
Instruct ICC wrote:
Date: Thu, 25 Oct 2007 09:43:14 +0800
From: [EMAIL PROTECTED]
To: php-general@lists.php.net
Subject: [PHP] system command
I tried:
$a=$_SERVER[REMOTE_ADDR];
echo pREMOTE_ADDR=$abr;
if($a=192.168.250.108) {
$a=61.64.101.101;
}
$aa=system('lynx -dump http://api.hostip.info/country.php?ip=$a',$location);
echo pa=$abraa=$aabrlocation=$locationbr;
$aa=system('lynx -dump
http://api.hostip.info/country.php?ip=61.64.101.101',$location);
echo pa=$abraa=$aabrlocation=$locationbr;
I get:
REMOTE_ADDR=192.168.250.108
XX
a=61.64.101.101
aa=XX
location=0
TW
a=61.64.101.101
aa=TW
location=0
as you can see, if I put the IP address in, I get the right answer (TW).
What am I doing wrong?
bye
Ronald
Use double quotes to get the value of $a or else you get the literal string
$a.
$aa=system(lynx -dump http://api.hostip.info/country.php?ip=$a,$location);
or
$aa=system('lynx -dump http://api.hostip.info/country.php?ip='.$a,$location);
Thanks! 1st solution did not work for me, but the second one did.
I still have a problem with it. It prints the info to the page. Can I
suppress this somehow?
bye
Ronald
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RE: [PHP] system command
Date: Thu, 25 Oct 2007 09:43:14 +0800
From: [EMAIL PROTECTED]
To: php-general@lists.php.net
Subject: [PHP] system command
I tried:
$a=$_SERVER[REMOTE_ADDR];
echo pREMOTE_ADDR=$abr;
if($a=192.168.250.108) {
$a=61.64.101.101;
}
$aa=system('lynx -dump http://api.hostip.info/country.php?ip=$a',$location);
echo pa=$abraa=$aabrlocation=$locationbr;
$aa=system('lynx -dump
http://api.hostip.info/country.php?ip=61.64.101.101',$location);
echo pa=$abraa=$aabrlocation=$locationbr;
I get:
REMOTE_ADDR=192.168.250.108
XX
a=61.64.101.101
aa=XX
location=0
TW
a=61.64.101.101
aa=TW
location=0
as you can see, if I put the IP address in, I get the right answer (TW).
What am I doing wrong?
bye
Ronald
Use double quotes to get the value of $a or else you get the literal string
$a.
$aa=system(lynx -dump http://api.hostip.info/country.php?ip=$a,$location);
or
$aa=system('lynx -dump http://api.hostip.info/country.php?ip='.$a,$location);
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Re: [PHP] IF command
On Oct 18, 2007, at 9:50 PM, Bastien Koert wrote:
Are you sure that the value is a string? If its numeric, then try
the check without the quotes around the value
http://www.php.net/manual/en/language.operators.comparison.php
If you compare an integer with a string, the string is converted to
a number. If you compare two numerical strings, they are compared as
integers.
?php
$component_reference = 5;
if ( ($component_reference != 5) AND ($component_reference !=
19) ) {
echo(I am not a 5 or a 19br);
}
else
echo(I am a 5 or a 19br);
$component_reference = 5;
if ( ($component_reference != 5) AND ($component_reference !=
19) ) {
echo(I am not a 5 or a 19br);
}
else
echo(I am a 5 or a 19br);
$component_reference = 3;
if ( ($component_reference != 5) AND ($component_reference !=
19) ) {
echo(I am not a 5 or a 19br);
}
else
echo(I am a 5 or a 19br);
$component_reference = 3;
if ( ($component_reference != 5) AND ($component_reference !=
19) ) {
echo(I am not a 5 or a 19br);
}
else
echo(I am a 5 or a 19br);
?
The results:
I am a 5 or a 19
I am a 5 or a 19
I am not a 5 or a 19
I am not a 5 or a 19
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RE: [PHP] IF command
Are you sure that the value is a string? If its numeric, then try the check
without the quotes around the value
bastien From: [EMAIL PROTECTED] To: php-general@lists.php.net Date: Thu, 18
Oct 2007 19:49:55 -0500 Subject: [PHP] IF command When $component_reference
is 5 or 19 I don't want the echo statement to output to the screen. What is
the correct syntax? What I have below isn't working. Thanks for your help.
Ron if ( ($component_reference != 5) OR ($component_reference != 19) )
{ echo lia href=\index.php?request= . $request . \ .
$component_name . /a; } -- PHP General Mailing List
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Re: [PHP] IF command
Hi, here is the code:
if ( ($component_reference != 5) AND ($component_reference != 19) ) {
echo lia href=\index.php?request= . $request . \ .
$component_name . /a;
}
2007/10/19, ron.php [EMAIL PROTECTED]:
When $component_reference is 5 or 19 I don't want the echo statement to
output to the screen. What is the correct syntax? What I have below isn't
working. Thanks for your help. Ron
if ( ($component_reference != 5) OR ($component_reference != 19) ) {
echo lia href=\index.php?request= . $request . \ .
$component_name . /a;
}
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Re: [PHP] IF command
if (!in_array($component_reference, array(5,17)))
// ...
More compact.
On Oct 18, 2007, at 5:49 PM, ron.php [EMAIL PROTECTED]
wrote:
When $component_reference is 5 or 19 I don't want the echo statement
to
output to the screen. What is the correct syntax? What I have
below isn't
working. Thanks for your help. Ron
if ( ($component_reference != 5) OR ($component_reference !=
19) ) {
echo lia href=\index.php?request= . $request . \ .
$component_name . /a;
}
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RE: [PHP] PHP Command line script
Check the error from mysqli:
http://fi.php.net/manual/en/function.mysqli-error.php
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-Original Message-
From: Nathaniel Hall [mailto:[EMAIL PROTECTED]
Sent: Tuesday, May 01, 2007 10:13 PM
To: php-general@lists.php.net
Subject: [PHP] PHP Command line script
I am attempting to run a script that will run from the command line
nightly to update a field in a database. I already created a script
that would access the database and insert most of the information when a
webpage is visited and I had no problems with it. The command line
script appears to fail on the prepare. I have echo'ed the SQL statement
to the screen, copied it, and run it on the MySQL server with no
problems. Any ideas?
?php
$mysqli = new mysqli('localhost', 'root', 'abc123', 'mydb');
if (mysqli_connect_errno()) {
echo Unable to connect to database.\n;
exit;
} else {
$login = date('m\-d\-Y');
if ($logout = $mysqli-prepare(UPDATE `mydb`.`authlog`
SET `logout` = ? WHERE `login` LIKE '$login%')) { // --- Will not go
any further than here, even when hard coding the information.
$logout-bind_param(s, date('m\-d\-
Y\TH\:i\:s'));
$logout-execute();
$logout-close();
}
}
$mysqli-close();
?
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Re: [PHP] PHP Command line script
Greg Donald wrote:
On 5/1/07, Nathaniel Hall [EMAIL PROTECTED] wrote:
I am attempting to run a script that will run from the command line
nightly to update a field in a database. I already created a script
that would access the database and insert most of the information when a
webpage is visited and I had no problems with it. The command line
script appears to fail on the prepare. I have echo'ed the SQL statement
to the screen, copied it, and run it on the MySQL server with no
problems. Any ideas?
?php
$mysqli = new mysqli('localhost', 'root', 'abc123', 'mydb');
if (mysqli_connect_errno()) {
echo Unable to connect to database.\n;
exit;
} else {
$login = date('m\-d\-Y');
if ($logout = $mysqli-prepare(UPDATE `mydb`.`authlog`
SET `logout` = ? WHERE `login` LIKE '$login%')) { // --- Will not go
any further than here, even when hard coding the information.
$logout-bind_param(s,
date('m\-d\-Y\TH\:i\:s'));
$logout-execute();
$logout-close();
}
}
$mysqli-close();
?
Add full error reporting, then make sure you can see the errors, then
test to see if you have the mysqli extension:
error_reporting( E_ALL );
ini_set( 'display_errors', 1 );
ini_set( 'log_errors', 1 );
if( !in_array( 'mysqli', get_loaded_extensions() ) )
{
die( 'no mysqli found' );
}
I get no errors and I have verified that mysqli is loaded.
Also, why do you need to escape the dashes in the date() calls?
php -r 'echo date(Y-m-d);'
2007-05-01
Habit.
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Re: [PHP] PHP Command line script
On Tue, May 1, 2007 3:13 pm, Nathaniel Hall wrote:
?php
$mysqli = new mysqli('localhost', 'root', 'abc123', 'mydb');
if (mysqli_connect_errno()) {
echo Unable to connect to database.\n;
exit;
} else {
$login = date('m\-d\-Y');
if ($logout = $mysqli-prepare(UPDATE
`mydb`.`authlog`
SET `logout` = ? WHERE `login` LIKE '$login%')) { // --- Will not
go
any further than here, even when hard coding the information.
$logout-bind_param(s,
date('m\-d\-Y\TH\:i\:s'));
$logout-execute();
$logout-close();
}
//ALWAYS do your error-checking!!!
else{
die(mysqli_error());
}
//You may want to put the query in $query so you can print that
//as part of the 'die' output
}
$mysqli-close();
?
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Re: [PHP] PHP Command line script
First and foremost, it's a VERY BAD idea to use root for MySQL. If your
code isn't perfect (and even sometimes if it is), arbitrary commands and SQL
injection attacks could lead to migraines that no Tylenol will ever be able
to alleviate.
Secondly, what error is the CLI kicking out when you run it from the
command line?
On 5/1/07, Nathaniel Hall [EMAIL PROTECTED] wrote:
I am attempting to run a script that will run from the command line
nightly to update a field in a database. I already created a script
that would access the database and insert most of the information when a
webpage is visited and I had no problems with it. The command line
script appears to fail on the prepare. I have echo'ed the SQL statement
to the screen, copied it, and run it on the MySQL server with no
problems. Any ideas?
?php
$mysqli = new mysqli('localhost', 'root', 'abc123', 'mydb');
if (mysqli_connect_errno()) {
echo Unable to connect to database.\n;
exit;
} else {
$login = date('m\-d\-Y');
if ($logout = $mysqli-prepare(UPDATE `mydb`.`authlog`
SET `logout` = ? WHERE `login` LIKE '$login%')) { // --- Will not go
any further than here, even when hard coding the information.
$logout-bind_param(s,
date('m\-d\-Y\TH\:i\:s'));
$logout-execute();
$logout-close();
}
}
$mysqli-close();
?
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[mobile] (570-) 766-8107
Re: [PHP] PHP Command line script
Daniel Brown wrote:
First and foremost, it's a VERY BAD idea to use root for MySQL.
If your code isn't perfect (and even sometimes if it is), arbitrary
commands and SQL injection attacks could lead to migraines that no
Tylenol will ever be able to alleviate.
I changed the user I was connecting as in order to post. I don't use
root in the real code.
Secondly, what error is the CLI kicking out when you run it from
the command line?
It doesn't give an error. The only thing it does is continue on through
the IF statement, which goes nowhere. I have added an ELSE to the
script and run it. It ends up running the code in the ELSE.
$login = date('m\-d\-Y');
if ($logout = $mysqli-prepare(UPDATE `mydb`.`authlog` SET
`logout` = ? WHERE `login` LIKE '$login%')) { // --- Will not
go any further than here, even when hard coding the information.
$logout-bind_param(s, date('m\-d\-Y\TH\:i\:s'));
$logout-execute();
$logout-close();
}
--
Nathaniel Hall, GSEC GCFW GCIA GCIH GCFA
Spider Security
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Re: [PHP] PHP Command line script
On 5/1/07, Nathaniel Hall [EMAIL PROTECTED] wrote:
I am attempting to run a script that will run from the command line
nightly to update a field in a database. I already created a script
that would access the database and insert most of the information when a
webpage is visited and I had no problems with it. The command line
script appears to fail on the prepare. I have echo'ed the SQL statement
to the screen, copied it, and run it on the MySQL server with no
problems. Any ideas?
?php
$mysqli = new mysqli('localhost', 'root', 'abc123', 'mydb');
if (mysqli_connect_errno()) {
echo Unable to connect to database.\n;
exit;
} else {
$login = date('m\-d\-Y');
if ($logout = $mysqli-prepare(UPDATE `mydb`.`authlog`
SET `logout` = ? WHERE `login` LIKE '$login%')) { // --- Will not go
any further than here, even when hard coding the information.
$logout-bind_param(s, date('m\-d\-Y\TH\:i\:s'));
$logout-execute();
$logout-close();
}
}
$mysqli-close();
?
Add full error reporting, then make sure you can see the errors, then
test to see if you have the mysqli extension:
error_reporting( E_ALL );
ini_set( 'display_errors', 1 );
ini_set( 'log_errors', 1 );
if( !in_array( 'mysqli', get_loaded_extensions() ) )
{
die( 'no mysqli found' );
}
Also, why do you need to escape the dashes in the date() calls?
php -r 'echo date(Y-m-d);'
2007-05-01
--
Greg Donald
http://destiney.com/
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Re: [PHP] HELO command when sending email using PHP
please check the RFC 821, it shows the SMTP protocol. HELO domain.com it should fill your Mail server domain in order to prevent email going through most of anti-spam. - Original Message - From: Angelo Zanetti [EMAIL PROTECTED] To: php-general@lists.php.net Sent: Wednesday, March 28, 2007 5:10 PM Subject: [PHP] HELO command when sending email using PHP Hi all. I am sending emails using the SMTP connection with PHP using the HTMLMimeMail class. Now there is a setting there for the HELO command text, can anyone explain to me what this is and what it should be set to? TIA. -- Angelo Zanetti Systems developer *Telephone:* +27 (021) 469 1052 *Mobile:* +27 (0) 72 441 3355 *Fax:*+27 (0) 86 681 5885 * Web:* http://www.zlogic.co.za *E-Mail:* [EMAIL PROTECTED] mailto:[EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] HELO command when sending email using PHP
demo wrote: please check the RFC 821, it shows the SMTP protocol. HELO domain.com it should fill your Mail server domain in order to prevent email going through most of anti-spam. Thanks, so if Im running localhost, the HELO command will also be localhost? -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] HELO command when sending email using PHP
by the way, here is php issues maillist not EMAIL issues:) if any problem with SMTP or email, please contact me directly -- http://tssoft.3322.org:8080/2.1/ demo:demodemo it's my email server developped by MSVC - Original Message - From: Angelo Zanetti [EMAIL PROTECTED] To: demo [EMAIL PROTECTED] Cc: php-general@lists.php.net Sent: Wednesday, March 28, 2007 5:33 PM Subject: Re: [PHP] HELO command when sending email using PHP demo wrote: please check the RFC 821, it shows the SMTP protocol. HELO domain.com it should fill your Mail server domain in order to prevent email going through most of anti-spam. Thanks, so if Im running localhost, the HELO command will also be localhost? -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] HELO command when sending email using PHP
localhost is ok if u just send mail in the LAN. if you send mail in the internet, it may not be ok, bcoz it will be cut by anti-spam. most smtp servers always validate your HELO area and your DNS and check if them match. - Original Message - From: Angelo Zanetti [EMAIL PROTECTED] To: demo [EMAIL PROTECTED] Cc: php-general@lists.php.net Sent: Wednesday, March 28, 2007 5:33 PM Subject: Re: [PHP] HELO command when sending email using PHP demo wrote: please check the RFC 821, it shows the SMTP protocol. HELO domain.com it should fill your Mail server domain in order to prevent email going through most of anti-spam. Thanks, so if Im running localhost, the HELO command will also be localhost? -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] shell command
John Taylor-Johnston wrote: Hi, I want to echo the location of head.jpg hidden in some deep dark recess of my server, unbeknownst to me. Which shell command do I use? How do I echo it? John While this isn't really a PHP question... On my machine, the following would work. I can't speak for your machine, though. cd /; find -name head.jpg -- Jasper Bryant-Greene General Manager Album Limited +64 21 708 334 [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] shell command
On Sat, 2005-11-19 at 13:02, Jasper Bryant-Greene wrote: John Taylor-Johnston wrote: Hi, I want to echo the location of head.jpg hidden in some deep dark recess of my server, unbeknownst to me. Which shell command do I use? How do I echo it? John While this isn't really a PHP question... On my machine, the following would work. I can't speak for your machine, though. cd /; find -name head.jpg Under linux: locate head.jpg This is better than find usually since the filesystem is usually indexed nightly making lookup fast. If you just added the file though... you'll need to use the aforementioned method :) Cheers, Rob. -- .. | InterJinn Application Framework - http://www.interjinn.com | :: | An application and templating framework for PHP. Boasting | | a powerful, scalable system for accessing system services | | such as forms, properties, sessions, and caches. InterJinn | | also provides an extremely flexible architecture for | | creating re-usable components quickly and easily. | `' -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Error Command failed for target 'ext/xml/xml.lo' during make process (Solaris 8)
On Tue, Nov 15, 2005 at 09:20:54PM +0100, Age Bosma wrote: Hi, I'm trying to compile php 4.4.1 on Solaris 8 but I'm getting the error Command failed for target 'ext/xml/xml.lo' during the make process. [snip] /nfs/dm11-fs22/work/training/dj365/php-4.4.1/ext/xml/xml.c:1582: `XML_Char' undeclared (first use in this function) ... make: Fatal error: Command failed for target 'ext/xml/xml.lo' If I look in the 'ext/xml/' folder, there's no file called 'xml.lo'. What can be the problem here? It is trying to make the xml.lo file, the errors prior to that explain why. I used the following configuration with gcc 3.2.3: configure --prefix=/work/training/dg432/servsoft/php4 --with-apxs2=/work/training/dg432/servsoft/apache2/bin/apxs --with-mysql=/work/training/dg432/servsoft/mysql4 --enable-calendar --enable-ftp --with-gettext --with-iconv --with-dom=/work/training/dg432/servsoft --with-dom-xslt=/work/training/dg432/servsoft This is an odd configure line, i'm guessing this is some sort of package thing. At first glance at the the errors above, i would guess that this package has some version issues. Except for gettext and iconv I manually compiled all packaged myself. In addition to this, I got two warnings during the configuration process: configure: warning: You will need bison 1.28 and configure: warning: You will need bison 1.28 if you want to regenerate the Zend parser (found 1.27) Could this have anything to do with it? most likely not. Curt. -- -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] exec command fails in php, works in the command line
[EMAIL PROTECTED] wrote: I have two programs on two servers, and they both have similar problems. In each one, I use 'exec' to call a helper program. In one case, it is ecasound, which I use to resample an mp3. In the other, it is convert, which creates a thumbnail of a very large image the user has uploaded. In both cases, the exec command fails. Not all the time, but some times. In both cases, the command that is being called by exec will work fine at the command line. I assume that there is some memory / resource limit that is being breached when this happens, but I don't know what it is, or how to tell php to allow my programs to run. Any ideas? Is it a disallowed function you your php.ini? -- John C. Nichel ÜberGeek KegWorks.com 716.856.9675 [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] exec command fails in php, works in the command line
[EMAIL PROTECTED] wrote: I have two programs on two servers, and they both have similar problems. In each one, I use 'exec' to call a helper program. In one case, it is ecasound, which I use to resample an mp3. In the other, it is convert, which creates a thumbnail of a very large image the user has uploaded. In both cases, the exec command fails. Not all the time, but some times. In both cases, the command that is being called by exec will work fine at the command line. I assume that there is some memory / resource limit that is being breached when this happens, but I don't know what it is, or how to tell php to allow my programs to run. Any ideas? Or is save mode on? -- John C. Nichel ÜberGeek KegWorks.com 716.856.9675 [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] exec command fails in php, works in the command line
Please reply to the list. [EMAIL PROTECTED] wrote: No, all of these things your are bringing up would cause the programs to NEVER work, not work some of the time or when the data they are processing is small. Depends on the install. My cli uses a different php.ini than the web one. Did you check permissions? Does the user which your web server is running as have execute permission on the app? On Wed, 21 Sep 2005, John Nichel wrote: [EMAIL PROTECTED] wrote: I have two programs on two servers, and they both have similar problems. In each one, I use 'exec' to call a helper program. In one case, it is ecasound, which I use to resample an mp3. In the other, it is convert, which creates a thumbnail of a very large image the user has uploaded. In both cases, the exec command fails. Not all the time, but some times. In both cases, the command that is being called by exec will work fine at the command line. I assume that there is some memory / resource limit that is being breached when this happens, but I don't know what it is, or how to tell php to allow my programs to run. Any ideas? Or is save mode on? -- John C. Nichel ÜberGeek KegWorks.com 716.856.9675 [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php New Disorder Records - ten years of something: Coming soon, new Power Struggle CD. * Free Email with 5 megs, no ads * Internet Radio Station - upload your music, we'll put it in rotation * 100's of CDs for sale * videos, message board, byofl http://www.newdisorder.com -- John C. Nichel ÜberGeek KegWorks.com 716.856.9675 [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] exec command fails in php, works in the command line
I don't want to crowd the list up with dead ends, so I was trying to
respond only to you.
I'm not calling a php program from exec, I'm calling ecasound and
convert. For example, in the php code:
exec(convert $internalpath/$filename -resize
{$thumbWidth}x{$thumbHeight} $internalpath/$thumbname, $out, $err);
doesn't always work, but with variables substituted on the command line:
bash:~ convert futon.jpg -resize 240x180 futon_thumb.jpg
will always work.
The same is true, on a different server, of my exec that calls ecasound,
an mp3 processing utility. Both of these could conceivably use a lot of
resources, which is why I think php is killing them off some of the time.
On Wed, 21 Sep 2005, John Nichel wrote:
Please reply to the list.
[EMAIL PROTECTED] wrote:
No, all of these things your are bringing up would cause the programs to
NEVER work, not work some of the time or when the data they are processing
is small.
Depends on the install. My cli uses a different php.ini than the web one.
Did you check permissions? Does the user which your web server is running as
have execute permission on the app?
On Wed, 21 Sep 2005, John Nichel wrote:
[EMAIL PROTECTED] wrote:
I have two programs on two servers, and they both have similar problems.
In each one, I use 'exec' to call a helper program. In one case, it is
ecasound, which I use to resample an mp3. In the other, it is convert,
which creates a thumbnail of a very large image the user has uploaded.
In both cases, the exec command fails. Not all the time, but some times.
In both cases, the command that is being called by exec will work fine at
the command line. I assume that there is some memory / resource limit
that is being breached when this happens, but I don't know what it is, or
how to tell php to allow my programs to run. Any ideas?
Or is save mode on?
--
John C. Nichel
ÜberGeek
KegWorks.com
716.856.9675
[EMAIL PROTECTED]
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Re: [PHP] exec command fails in php, works in the command line
[EMAIL PROTECTED] wrote:
I don't want to crowd the list up with dead ends, so I was trying to
respond only to you.
snip
You'll get more chances at finding the solution to this with the list's
eyes on it rather than just myself. Plus, it provides an archive of the
problem and the (if we find it) solution to the next person who comes along.
/snip
I'm not calling a php program from exec, I'm calling ecasound and
convert. For example, in the php code:
snip
Understood, but if the web server doesn't have permission to execute the
app, it won't.
/snip
exec(convert $internalpath/$filename -resize
{$thumbWidth}x{$thumbHeight} $internalpath/$thumbname, $out, $err);
doesn't always work, but with variables substituted on the command line:
snip
Are you sure that the variables have value, and it is the value you
want? What is stored in $err when you try to execute this? Echo that
out, and it may tell you exactly what's going wrong.
/snip
bash:~ convert futon.jpg -resize 240x180 futon_thumb.jpg
will always work.
The same is true, on a different server, of my exec that calls ecasound,
an mp3 processing utility. Both of these could conceivably use a lot of
resources, which is why I think php is killing them off some of the time.
snip
Try increasing the memory limit in your script with ini_set.
--
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KegWorks.com
716.856.9675
[EMAIL PROTECTED]
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Re: [PHP] exec command fails in php, works in the command line
If the web server didn't have permission to execute the app, it would
NEVER execute the app, not execute it some of the time. In fact, it
ALWAYS executes the app, it just doesn't always allow it to finish.
I log all attempts to run these apps in order to debug, so I know that
the command as passed from php will work in the command line. I copy and
paste the command from the log and it runs, even though it didn't complete
execution when called from php.
I have increased several parameters in php.ini, including memory limit
and allowed execution time. Nothing has helped. The only thing that
helps is if I wrap the app I want to run in a perl script and call the
perl script from php. That works more of the time, though it still often
breaks.
On
Wed, 21 Sep 2005, John Nichel wrote:
[EMAIL PROTECTED] wrote:
I don't want to crowd the list up with dead ends, so I was trying to
respond only to you.
snip
You'll get more chances at finding the solution to this with the list's eyes
on it rather than just myself. Plus, it provides an archive of the problem
and the (if we find it) solution to the next person who comes along.
/snip
I'm not calling a php program from exec, I'm calling ecasound and
convert. For example, in the php code:
snip
Understood, but if the web server doesn't have permission to execute the app,
it won't.
/snip
exec(convert $internalpath/$filename -resize {$thumbWidth}x{$thumbHeight}
$internalpath/$thumbname, $out, $err);
doesn't always work, but with variables substituted on the command line:
snip
Are you sure that the variables have value, and it is the value you want?
What is stored in $err when you try to execute this? Echo that out, and it
may tell you exactly what's going wrong.
/snip
bash:~ convert futon.jpg -resize 240x180 futon_thumb.jpg
will always work.
The same is true, on a different server, of my exec that calls ecasound, an
mp3 processing utility. Both of these could conceivably use a lot of
resources, which is why I think php is killing them off some of the time.
snip
Try increasing the memory limit in your script with ini_set.
--
John C. Nichel
ÜberGeek
KegWorks.com
716.856.9675
[EMAIL PROTECTED]
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Coming soon, new Power Struggle CD.
* Free Email with 5 megs, no ads
* Internet Radio Station - upload your music, we'll put it in rotation
* 100's of CDs for sale
* videos, message board, byofl
http://www.newdisorder.com
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Re: [PHP] exec command fails in php, works in the command line
[EMAIL PROTECTED] wrote: If the web server didn't have permission to execute the app, it would NEVER execute the app, not execute it some of the time. In fact, it ALWAYS executes the app, it just doesn't always allow it to finish. I log all attempts to run these apps in order to debug, so I know that the command as passed from php will work in the command line. I copy and paste the command from the log and it runs, even though it didn't complete execution when called from php. What do the logs say?? I have increased several parameters in php.ini, including memory limit and allowed execution time. Nothing has helped. The only thing that helps is if I wrap the app I want to run in a perl script and call the perl script from php. That works more of the time, though it still often breaks. Maybe the problem's not php but Apache (or whatever webserver you're using), as it has limits in place for these items too. -- John C. Nichel ÜberGeek KegWorks.com 716.856.9675 [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] exec command fails in php, works in the command line
the logs say things like: /kunden/homepages/12/d117065027/htdocs/software/ImageMagick-6.2.3/utilities/convert ib_images/Other_Spices_Basic_004.jpg -resize 180x120 ib_images/Other_Spices_Basic_004_thumb.jpg this is a command I'm trying to get php to run. I then cut and paste it to the command line, and it works fine. the paths are fine too, otherwise it would never run, not run some of the time. Can you give me an example of an apache directive that would restrict php? On Wed, 21 Sep 2005, John Nichel wrote: [EMAIL PROTECTED] wrote: If the web server didn't have permission to execute the app, it would NEVER execute the app, not execute it some of the time. In fact, it ALWAYS executes the app, it just doesn't always allow it to finish. I log all attempts to run these apps in order to debug, so I know that the command as passed from php will work in the command line. I copy and paste the command from the log and it runs, even though it didn't complete execution when called from php. What do the logs say?? I have increased several parameters in php.ini, including memory limit and allowed execution time. Nothing has helped. The only thing that helps is if I wrap the app I want to run in a perl script and call the perl script from php. That works more of the time, though it still often breaks. Maybe the problem's not php but Apache (or whatever webserver you're using), as it has limits in place for these items too. -- John C. Nichel ÜberGeek KegWorks.com 716.856.9675 [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php New Disorder Records - ten years of something: Coming soon, new Power Struggle CD. * Free Email with 5 megs, no ads * Internet Radio Station - upload your music, we'll put it in rotation * 100's of CDs for sale * videos, message board, byofl http://www.newdisorder.com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] exec command fails in php, works in the command line
[EMAIL PROTECTED] wrote: the logs say things like: /kunden/homepages/12/d117065027/htdocs/software/ImageMagick-6.2.3/utilities/convert ib_images/Other_Spices_Basic_004.jpg -resize 180x120 ib_images/Other_Spices_Basic_004_thumb.jpg this is a command I'm trying to get php to run. I then cut and paste it to the command line, and it works fine. the paths are fine too, otherwise it would never run, not run some of the time. Can you give me an example of an apache directive that would restrict php? Timeout On Wed, 21 Sep 2005, John Nichel wrote: [EMAIL PROTECTED] wrote: If the web server didn't have permission to execute the app, it would NEVER execute the app, not execute it some of the time. In fact, it ALWAYS executes the app, it just doesn't always allow it to finish. I log all attempts to run these apps in order to debug, so I know that the command as passed from php will work in the command line. I copy and paste the command from the log and it runs, even though it didn't complete execution when called from php. What do the logs say?? I have increased several parameters in php.ini, including memory limit and allowed execution time. Nothing has helped. The only thing that helps is if I wrap the app I want to run in a perl script and call the perl script from php. That works more of the time, though it still often breaks. Maybe the problem's not php but Apache (or whatever webserver you're using), as it has limits in place for these items too. -- John C. Nichel ÜberGeek KegWorks.com 716.856.9675 [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php New Disorder Records - ten years of something: Coming soon, new Power Struggle CD. * Free Email with 5 megs, no ads * Internet Radio Station - upload your music, we'll put it in rotation * 100's of CDs for sale * videos, message board, byofl http://www.newdisorder.com -- John C. Nichel ÜberGeek KegWorks.com 716.856.9675 [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] exec command fails in php, works in the command line
timeout isn't being used on either of these machines, and as far as I read it, the timeout directive would make the web server fail, producing an apache error or some strange behaviour on the client end. Neither of these happens, the php script completes normally, but the exec command (and only these exec commands, I'm using others in the script that work fine) doesn't always complete. Even if timeout was set to its normal default of 300 seconds, this all happens way before 300 seconds have passed. The whole process takes about 20 or 30 seconds. On Wed, 21 Sep 2005, John Nichel wrote: [EMAIL PROTECTED] wrote: the logs say things like: /kunden/homepages/12/d117065027/htdocs/software/ImageMagick-6.2.3/utilities/convert ib_images/Other_Spices_Basic_004.jpg -resize 180x120 ib_images/Other_Spices_Basic_004_thumb.jpg this is a command I'm trying to get php to run. I then cut and paste it to the command line, and it works fine. the paths are fine too, otherwise it would never run, not run some of the time. Can you give me an example of an apache directive that would restrict php? Timeout On Wed, 21 Sep 2005, John Nichel wrote: [EMAIL PROTECTED] wrote: If the web server didn't have permission to execute the app, it would NEVER execute the app, not execute it some of the time. In fact, it ALWAYS executes the app, it just doesn't always allow it to finish. I log all attempts to run these apps in order to debug, so I know that the command as passed from php will work in the command line. I copy and paste the command from the log and it runs, even though it didn't complete execution when called from php. What do the logs say?? I have increased several parameters in php.ini, including memory limit and allowed execution time. Nothing has helped. The only thing that helps is if I wrap the app I want to run in a perl script and call the perl script from php. That works more of the time, though it still often breaks. Maybe the problem's not php but Apache (or whatever webserver you're using), as it has limits in place for these items too. -- John C. Nichel ÜberGeek KegWorks.com 716.856.9675 [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php New Disorder Records - ten years of something: Coming soon, new Power Struggle CD. * Free Email with 5 megs, no ads * Internet Radio Station - upload your music, we'll put it in rotation * 100's of CDs for sale * videos, message board, byofl http://www.newdisorder.com -- John C. Nichel ÜberGeek KegWorks.com 716.856.9675 [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php New Disorder Records - ten years of something: Coming soon, new Power Struggle CD. * Free Email with 5 megs, no ads * Internet Radio Station - upload your music, we'll put it in rotation * 100's of CDs for sale * videos, message board, byofl http://www.newdisorder.com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] exec command fails in php, works in the command line
[EMAIL PROTECTED] wrote: timeout isn't being used on either of these machines, and as far as I read it, the timeout directive would make the web server fail, producing an apache error or some strange behaviour on the client end. Neither of How is timeout _not_ being used? It's a core directive. If the timeout is reached, the thread dies, along with anything running with it. these happens, the php script completes normally, but the exec command (and only these exec commands, I'm using others in the script that work fine) doesn't always complete. Even if timeout was set to its normal default of 300 seconds, this all happens way before 300 seconds have passed. The whole process takes about 20 or 30 seconds. Just to make sure I'm understanding you, you're hitting the php page in a browser, right? Like you're going to http://www.yourhost.com/page.php where page.php contains somthing like... ?php exec ( '/path/myapp', $out, $res ); ? Right? -- John C. Nichel ÜberGeek KegWorks.com 716.856.9675 [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] exec command fails in php, works in the command line
as I said, the default timout is 300 seconds, a lot longer than my program takes to run, and I am pretty certain that if timeout were triggered, I'd see it in the client. Yeah, I'm using a browser on the php page, and everything seems to function fine from the browser to the server, it's after the server gets the uploaded file and begins to play with it that things become weird. On Wed, 21 Sep 2005, John Nichel wrote: [EMAIL PROTECTED] wrote: timeout isn't being used on either of these machines, and as far as I read it, the timeout directive would make the web server fail, producing an apache error or some strange behaviour on the client end. Neither of How is timeout _not_ being used? It's a core directive. If the timeout is reached, the thread dies, along with anything running with it. these happens, the php script completes normally, but the exec command (and only these exec commands, I'm using others in the script that work fine) doesn't always complete. Even if timeout was set to its normal default of 300 seconds, this all happens way before 300 seconds have passed. The whole process takes about 20 or 30 seconds. Just to make sure I'm understanding you, you're hitting the php page in a browser, right? Like you're going to http://www.yourhost.com/page.php where page.php contains somthing like... ?php exec ( '/path/myapp', $out, $res ); ? Right? -- John C. Nichel ÜberGeek KegWorks.com 716.856.9675 [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php New Disorder Records - ten years of something: Coming soon, new Power Struggle CD. * Free Email with 5 megs, no ads * Internet Radio Station - upload your music, we'll put it in rotation * 100's of CDs for sale * videos, message board, byofl http://www.newdisorder.com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] exec command fails in php, works in the command line
[EMAIL PROTECTED] wrote: as I said, the default timout is 300 seconds, a lot longer than my program takes to run, and I am pretty certain that if timeout were triggered, I'd see it in the client. Yeah, I'm using a browser on the php page, and everything seems to function fine from the browser to the server, it's after the server gets the uploaded file and begins to play with it that things become weird. What's the output of... $output = shell_exec ( '/path/to/your/app' ); echo ( pre . $output . /pre ); ...when it doesn't work? On Wed, 21 Sep 2005, John Nichel wrote: [EMAIL PROTECTED] wrote: timeout isn't being used on either of these machines, and as far as I read it, the timeout directive would make the web server fail, producing an apache error or some strange behaviour on the client end. Neither of How is timeout _not_ being used? It's a core directive. If the timeout is reached, the thread dies, along with anything running with it. these happens, the php script completes normally, but the exec command (and only these exec commands, I'm using others in the script that work fine) doesn't always complete. Even if timeout was set to its normal default of 300 seconds, this all happens way before 300 seconds have passed. The whole process takes about 20 or 30 seconds. Just to make sure I'm understanding you, you're hitting the php page in a browser, right? Like you're going to http://www.yourhost.com/page.php where page.php contains somthing like... ?php exec ( '/path/myapp', $out, $res ); ? Right? -- John C. Nichel ÜberGeek KegWorks.com 716.856.9675 [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php New Disorder Records - ten years of something: Coming soon, new Power Struggle CD. * Free Email with 5 megs, no ads * Internet Radio Station - upload your music, we'll put it in rotation * 100's of CDs for sale * videos, message board, byofl http://www.newdisorder.com -- John C. Nichel ÜberGeek KegWorks.com 716.856.9675 [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] exec command fails in php, works in the command line
convert doesn't produce any output regardless of whether it works or not. Ecasound produces output when it works, but when it doesn't, it produces no output. Using php tricks to capture standard error also produces no output. On Wed, 21 Sep 2005, John Nichel wrote: [EMAIL PROTECTED] wrote: as I said, the default timout is 300 seconds, a lot longer than my program takes to run, and I am pretty certain that if timeout were triggered, I'd see it in the client. Yeah, I'm using a browser on the php page, and everything seems to function fine from the browser to the server, it's after the server gets the uploaded file and begins to play with it that things become weird. What's the output of... $output = shell_exec ( '/path/to/your/app' ); echo ( pre . $output . /pre ); ...when it doesn't work? On Wed, 21 Sep 2005, John Nichel wrote: [EMAIL PROTECTED] wrote: timeout isn't being used on either of these machines, and as far as I read it, the timeout directive would make the web server fail, producing an apache error or some strange behaviour on the client end. Neither of How is timeout _not_ being used? It's a core directive. If the timeout is reached, the thread dies, along with anything running with it. these happens, the php script completes normally, but the exec command (and only these exec commands, I'm using others in the script that work fine) doesn't always complete. Even if timeout was set to its normal default of 300 seconds, this all happens way before 300 seconds have passed. The whole process takes about 20 or 30 seconds. Just to make sure I'm understanding you, you're hitting the php page in a browser, right? Like you're going to http://www.yourhost.com/page.php where page.php contains somthing like... ?php exec ( '/path/myapp', $out, $res ); ? Right? -- John C. Nichel ÜberGeek KegWorks.com 716.856.9675 [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php New Disorder Records - ten years of something: Coming soon, new Power Struggle CD. * Free Email with 5 megs, no ads * Internet Radio Station - upload your music, we'll put it in rotation * 100's of CDs for sale * videos, message board, byofl http://www.newdisorder.com -- John C. Nichel ÜberGeek KegWorks.com 716.856.9675 [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php New Disorder Records - ten years of something: Coming soon, new Power Struggle CD. * Free Email with 5 megs, no ads * Internet Radio Station - upload your music, we'll put it in rotation * 100's of CDs for sale * videos, message board, byofl http://www.newdisorder.com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] exec command fails in php, works in the command line
[EMAIL PROTECTED] wrote: convert doesn't produce any output regardless of whether it works or not. Ecasound produces output when it works, but when it doesn't, it produces no output. Using php tricks to capture standard error also produces no output. Hopefully somebody else on the list can help. Without any output/error messages, it's kind of hard to know what the problem is. -- John C. Nichel ÜberGeek KegWorks.com 716.856.9675 [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] exec command fails in php, works in the command line
You're telling me. That's why I think php or apache kills it. On Wed, 21 Sep 2005, John Nichel wrote: [EMAIL PROTECTED] wrote: convert doesn't produce any output regardless of whether it works or not. Ecasound produces output when it works, but when it doesn't, it produces no output. Using php tricks to capture standard error also produces no output. Hopefully somebody else on the list can help. Without any output/error messages, it's kind of hard to know what the problem is. -- John C. Nichel ÜberGeek KegWorks.com 716.856.9675 [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php New Disorder Records - ten years of something: Coming soon, new Power Struggle CD. * Free Email with 5 megs, no ads * Internet Radio Station - upload your music, we'll put it in rotation * 100's of CDs for sale * videos, message board, byofl http://www.newdisorder.com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] exec command fails in php, works in the command line
[EMAIL PROTECTED] wrote: You're telling me. That's why I think php or apache kills it. I didn't really follow this, but typically you can debug exec problems from the command line by switching to the web server user id and running the exact same command. -Rasmus -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] exec command fails in php, works in the command line
Yes, but that's been done. Since these are shared servers, on one I am logged in as the user the web server is running as, on the other I can't su to nobody, but were there permissions errors, I would have been able to capture them. If permissions caused this, it would fail every time, since I'm always writing to the same directory. Instead it only fails some of the time. On Wed, 21 Sep 2005, Rasmus Lerdorf wrote: [EMAIL PROTECTED] wrote: You're telling me. That's why I think php or apache kills it. I didn't really follow this, but typically you can debug exec problems from the command line by switching to the web server user id and running the exact same command. -Rasmus New Disorder Records - ten years of something: Coming soon, new Power Struggle CD. * Free Email with 5 megs, no ads * Internet Radio Station - upload your music, we'll put it in rotation * 100's of CDs for sale * videos, message board, byofl http://www.newdisorder.com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] exec command fails in php, works in the command line
I am assuming that you get hold of the file through uploading it, correct? So, when it fails maybe another upload (i.e. script invocation) is happening and the previous file gets lost/corrupted/whatever. Try to move the file to another dir (maybe /tmp) with a random name and see what happens. Anyway, I think that this kind of thing should really be delegated to a cronjob. -Stathis On Wednesday 21 September 2005 20:45, [EMAIL PROTECTED] wrote: Yes, but that's been done. Since these are shared servers, on one I am logged in as the user the web server is running as, on the other I can't su to nobody, but were there permissions errors, I would have been able to capture them. If permissions caused this, it would fail every time, since I'm always writing to the same directory. Instead it only fails some of the time. On Wed, 21 Sep 2005, Rasmus Lerdorf wrote: [EMAIL PROTECTED] wrote: You're telling me. That's why I think php or apache kills it. I didn't really follow this, but typically you can debug exec problems from the command line by switching to the web server user id and running the exact same command. -Rasmus New Disorder Records - ten years of something: Coming soon, new Power Struggle CD. * Free Email with 5 megs, no ads * Internet Radio Station - upload your music, we'll put it in rotation * 100's of CDs for sale * videos, message board, byofl http://www.newdisorder.com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] exec command fails in php, works in the command line
php places uploaded files in the /tmp directory with a unique name, and when I copy them to my directory, I also guarantee a unique name for them. I have verified that this is all working. I've patched this with a cron job that runs every minute, but it really should happen in php, so that the user can get immediate feedback on how the thumbnail looks or how the mp3 file sounds. On Wed, 21 Sep 2005, rouvas wrote: I am assuming that you get hold of the file through uploading it, correct? So, when it fails maybe another upload (i.e. script invocation) is happening and the previous file gets lost/corrupted/whatever. Try to move the file to another dir (maybe /tmp) with a random name and see what happens. Anyway, I think that this kind of thing should really be delegated to a cronjob. -Stathis On Wednesday 21 September 2005 20:45, [EMAIL PROTECTED] wrote: Yes, but that's been done. Since these are shared servers, on one I am logged in as the user the web server is running as, on the other I can't su to nobody, but were there permissions errors, I would have been able to capture them. If permissions caused this, it would fail every time, since I'm always writing to the same directory. Instead it only fails some of the time. On Wed, 21 Sep 2005, Rasmus Lerdorf wrote: [EMAIL PROTECTED] wrote: You're telling me. That's why I think php or apache kills it. I didn't really follow this, but typically you can debug exec problems from the command line by switching to the web server user id and running the exact same command. -Rasmus New Disorder Records - ten years of something: Coming soon, new Power Struggle CD. * Free Email with 5 megs, no ads * Internet Radio Station - upload your music, we'll put it in rotation * 100's of CDs for sale * videos, message board, byofl http://www.newdisorder.com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php New Disorder Records - ten years of something: Coming soon, new Power Struggle CD. * Free Email with 5 megs, no ads * Internet Radio Station - upload your music, we'll put it in rotation * 100's of CDs for sale * videos, message board, byofl http://www.newdisorder.com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] exec command fails in php, works in the command line
did you tried to run the script from the shell as www-data user ? (if not su www-data) an then run the script may be something regarding permission hth 2005/9/21, John Nichel [EMAIL PROTECTED]: [EMAIL PROTECTED] wrote: I have two programs on two servers, and they both have similar problems. In each one, I use 'exec' to call a helper program. In one case, it is ecasound, which I use to resample an mp3. In the other, it is convert, which creates a thumbnail of a very large image the user has uploaded. In both cases, the exec command fails. Not all the time, but some times. In both cases, the command that is being called by exec will work fine at the command line. I assume that there is some memory / resource limit that is being breached when this happens, but I don't know what it is, or how to tell php to allow my programs to run. Any ideas? Or is save mode on? -- John C. Nichel ÜberGeek KegWorks.com 716.856.9675 [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] exec command fails in php, works in the command line
yeah, if you look at the thread you will see that I've already done this. On Wed, 21 Sep 2005, adriano ghezzi wrote: did you tried to run the script from the shell as www-data user ? (if not su www-data) an then run the script may be something regarding permission hth 2005/9/21, John Nichel [EMAIL PROTECTED]: [EMAIL PROTECTED] wrote: I have two programs on two servers, and they both have similar problems. In each one, I use 'exec' to call a helper program. In one case, it is ecasound, which I use to resample an mp3. In the other, it is convert, which creates a thumbnail of a very large image the user has uploaded. In both cases, the exec command fails. Not all the time, but some times. In both cases, the command that is being called by exec will work fine at the command line. I assume that there is some memory / resource limit that is being breached when this happens, but I don't know what it is, or how to tell php to allow my programs to run. Any ideas? Or is save mode on? -- John C. Nichel ÜberGeek KegWorks.com 716.856.9675 [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php New Disorder Records - ten years of something: Coming soon, new Power Struggle CD. * Free Email with 5 megs, no ads * Internet Radio Station - upload your music, we'll put it in rotation * 100's of CDs for sale * videos, message board, byofl http://www.newdisorder.com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Split command problem
On Monday 11 April 2005 09:27, Russ wrote:
I have been trying to get the following code working. I keep getting an
error on line nine.
And the error is?
It looks simular to the example in the PHP online
manual. If I substitute a print command for line nine I get the correct
information from $_POST[username]. I must be missing or have an extra a
quote but I cannot figure out where.
name($fname, $lname) = split('[/\s+/]', $_POST[username]);
split() probably uses POSIX regex and hence knows nothing about '\s'. Use
preg_split() instead:
list($fname, $lname) = preg_split('/\s+/', $_POST['username']);
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Open Source Software Systems Integrators
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Re: [PHP] Split command problem
I guess you are trying to create an array by the name 'name' and assign two
elements to it by calling name($fname, $lname). Am I correct?
I think it does not work that way. Try list($fname, $lname) = ..
Then the variable $fname and $lname will contain the first and last names.
list($fname, $lname) = split('[/\s+/]', $_POST[username]);
Cheers,
Prathap
-- Original Message ---
From: Russ [EMAIL PROTECTED]
To: PHP General php-general@lists.php.net
Sent: Sun, 10 Apr 2005 18:27:34 -0700
Subject: [PHP] Split command problem
I have been trying to get the following code working. I keep getting
an error on line nine. It looks simular to the example in the PHP
online manual. If I substitute a print command for line nine I get
the correct information from $_POST[username]. I must be missing or
have an extra a quote but I cannot figure out where.
?php
//check for required fields from the form
if ((!$_POST[username]) || (!$_POST[password])) {
header(Location: memberlogin15.7.php);
exit;
}
if(preg_match(/[A-Z]/, substr($_POST[username], 0, 1)))
{
name($fname, $lname) = split('[/\s+/]', $_POST[username]);
//echo First Name: $fname; Last Name: $lname\n;
echo first letter is uppercase;
}
else
{
echo first letter is not uppercase;
}
Any help will be appreciated.
--
Russ
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--- End of Original Message ---
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Re: [PHP] Split command problem
On Apr 10, 2005 8:27 PM, Russ [EMAIL PROTECTED] wrote:
I have been trying to get the following code working. I keep getting an error
on line nine. It looks simular to the example in the PHP online manual. If I
substitute a print command for line nine I get the correct information from
$_POST[username]. I must be missing or have an extra a quote but I cannot
figure out where.
?php
//check for required fields from the form
if ((!$_POST[username]) || (!$_POST[password])) {
header(Location: memberlogin15.7.php);
exit;
}
if(preg_match(/[A-Z]/, substr($_POST[username], 0, 1)))
{
name($fname, $lname) = split('[/\s+/]', $_POST[username]);
Where is your 'name' function and what does it do?
I'd do:
$name = explode( ' ', $_POST[ 'username' ] );
echo First Name: $name[0] Last Name: $name[1];
//echo First Name: $fname; Last Name: $lname\n;
echo first letter is uppercase;
}
else
{
echo first letter is not uppercase;
}
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Greg Donald
Zend Certified Engineer
http://destiney.com/
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Re: [PHP] exec command
You might find that get_current_user() is easier...
http://www.php.net/manual/en/function.get-current-user.php
On Wed, 6 Apr 2005, cragland wrote:
when running a simple php script, below, with exec, I recieve:
sh: /whoami: No such file or directory
?php
// outputs the username that owns the running php/httpd process
// (on a system with the whoami executable in the path)
echo exec('whoami');
?
Thanks very much,
cole
mailto:[EMAIL PROTECTED]
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RE: [PHP] exec command
when running a simple php script, below, with exec, I recieve:
sh: /whoami: No such file or directory
?php
// outputs the username that owns the running php/httpd
process // (on a system with the whoami executable in the
path) echo exec('whoami'); ?
You may want to try using the full path to the whoami command.
Try
echo exec('/usr/bin/whoami');
Or wherever it sits on your machine.
If you don't know the user that PHP runs as, how do you know what it's PATH
variable is...
-M
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RE: [PHP] php command
I think what you need to do is look at the sockets section of the manual. Regards, Mikey -Original Message- From: D A GERM [mailto:[EMAIL PROTECTED] Sent: 23 March 2005 14:46 To: php-general@lists.php.net Subject: [PHP] php command is there a command that will allow me to connect to another box and execute commands? for instance, I want to create an automated php script that will connect to a unix box and run a series of commands. I believe that ssh2_exec() and ssh2_shell() are not supported in the 4.3.4 version of php I am running. I thought of exec(); i could telnet in to the box but I didn't know if another exec() statement would pass the aurguments to the original telnet session set up in a previous exec() statement. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] setcookie command
On Mon, 24 Jan 2005 07:24:19 -0800 (PST), Reza Milan [EMAIL PROTECTED] wrote: Dear sir, When I use setcookie command I recieve the following message error: Warning: Cannot modify header information - headers already sent by (output started at C:\Inetpub\wwwroot\test.php:9) in C:\Inetpub\wwwroot\test.php on line 15 Do not set cookies after you have ouput anything, set them before. Or use the output buffering functions. -- Greg Donald Zend Certified Engineer http://destiney.com/ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] setcookie command
Reza Milan wrote: Dear sir, When I use setcookie command I recieve the following message error: Warning: Cannot modify header information - headers already sent by (output started at C:\Inetpub\wwwroot\test.php:9) in C:\Inetpub\wwwroot\test.php on line 15 WinXp - IE 6 On Localhost and Server When a web page is sent from the web server to the browser, there are *TWO* distinct sections sent out. First, is the 'headers', which are called 'headers' because they come at the head (beginning) of the data. Then comes a blank line, to signify the END of headers. Finally, the 'body' comes out, which is what you see when you do View Source -- It's the actual HTML. Headers include meta-information such as the type of Content (text/html or image/jpeg or image/gif or ...) In your case, test.php has something on line 9 that is sending out some HTML (or blank lines or ...) Once that happens, PHP has to dump out all the headers collected so far, and then a blank line, and then start your content. If you try to set a cookie *AFTER* that, when the headers are already gone, and the blank line has gone out to signify the end of headers, IT'S TOO LATE. You have to re-arrange your code to get the Cookies and any other headers to happen *FIRST* and then your HTML after that. You can cheat and turn on output buffering, but that comes with its own performance penalties and issues. You'll probably have a cleaner, more clear, more easily maintained body of PHP code if you arrange your headers to come out first anyway. -- Like Music? http://l-i-e.com/artists.htm -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Executing command in Linux
Rosen wrote: Hi, I have this problem: Linux Red Hat 7.3 server and PHP 4.3.8 MySQL 4. When I Try to execute linux command - nothing happens and in Apache logs I see Access denied. This is about permissions in executing this command. My question is can I execute a linux command via PHP ( this is command allowed only for root user ) ? P.S. I own this server - i.e. I have user pass for root. The PHP user is not root. The PHP user should *NOT* be root. Either make that command available to the PHP user, or don't use that command. Options for making that command available to the PHP user abound, and include: chmod so 'w'orld can eXecute. Add 'php' group w/ PHP user in it, and chgrp/chmod so 'g'roup can execute. Use sudo to allow PHP user to run that one command. Exactly how you choose to do this depends more on your risk assessment, skill level, and what you are doing than anything else -- None of which are PHP-related strictly-speaking. -- Like Music? http://l-i-e.com/artists.htm -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Executing command in Linux
On Sat, 2005-01-15 at 11:57, Rosen wrote: Hi, I have this problem: Linux Red Hat 7.3 server and PHP 4.3.8 MySQL 4. When I Try to execute linux command - nothing happens and in Apache logs I see Access denied. This is about permissions in executing this command. My question is can I execute a linux command via PHP ( this is command allowed only for root user ) ? P.S. I own this server - i.e. I have user pass for root. I use sudo for these situations. use visudo to establish that the user that owns the apache process ( I can't remember if RHL 7.3 was nobody or if the had switched to apache by then ). THen you can use exec(sudo yourCommandThatMustBeRunAsRoot arg1 arg2); man pages for sudo, sudoers and visudo are good resources. I am pretty sure 7.3 had the rpm available. visudo MUST be used to edit the sudoers file. you can add the following line to get you started apache ALL=(root) NOPASSWD:yourCommandThatMustBeRunAsRoot, someotherCmd What this says is let the user apache run yourCommandThatMustBeRunAsRoot and someotherCmd without having to enter a passwd. There are some things you can do to limit the arguments that can be passed to the commands see the man pages. Very cool stuff with finegrained permission on what can be run by who. Bret -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Exec() command on UNIX
On Wed, 1 Dec 2004 16:18:01 +0700, Sitthipong Thuetham [EMAIL PROTECTED] wrote: Dear PHP support, I have a question on an exec() command, if I would like to switch user right on Unix server, what command should I use? example: on the UNIX shell will be like below $su root Password:'password' but when I tried running exec() command on PHP, I couldn't do that exec(su root); I can't sent a password thru the exec() command, any way to do that? You might want to look at sudo, you can provide temporary root access with no password. -- Greg Donald Zend Certified Engineer http://gdconsultants.com/ http://destiney.com/ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Exec() command on UNIX
Sitthipong Thuetham wrote: I have a question on an exec() command, if I would like to switch user right on Unix server, what command should I use? example: on the UNIX shell will be like below $su root Password:'password' but when I tried running exec() command on PHP, I couldn't do that exec(su root); I can't sent a password thru the exec() command, any way to do that? Probably best to use 'sudo' in the shell to make the script run with the rights of the user you want, or some similar shell-action. You may also want to examine the Apache 2 directives that let a Module (EG PHP) run as a specific user under certain circumstances. I have not investigated this avenue myself, but would surmise that you could restrict this to a specific script in a specific directory, and could give over the PHP thread to be run by some special user. While I'm not certain, I'd be willing to bet cold hard cash that doing this and using root as that special user is a REALLY BAD IDEA. You'd need to set up a new user with *JUST* enough permission on the system to do the bare minimum of what you need that user to do to get the task accomplished. If, however, you are stuck on a server where you don't HAVE access to a shell and/or httpd.conf... Well, first, start looking for a new host where you DO have access to a shell, at least. In the meantime, you can sometimes do like this: exec(echo _password_ | command $arg1 $arg2); Note, however, that su itself specifically prohibits doing this from a non TTY shell (EG from PHP) to prevent you from doing this inherently very dangerous action. Also note that depending on the version of PHP and other factors I never quite figured out back in the day (PHP 3 PHP 4) sometimes stdout/stdin were bound up by PHP and sometimes not, so that the shell echo and | trick would only work on some versions/servers. Some PHP Developers claimed this was simply not true, however, despite my experience. YMMV. :-) -- Like Music? http://l-i-e.com/artists.htm -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] php command to open a url?
header (Location: ./); exit; I use the above at the end of a authorization script, to direct back to a page. On Oct 31, 2004, at 12:03 PM, Ken Tozier wrote: I've been looking around in the php documentation for a couple of hours now but can't seem to find any functions to open a url in the current browser window. Does php allow this? If so, could someone point me to a link? Basically what I'm trying to do is loop back in a login form until a user enters a valid username/password and then redirect to that user's personal info page. Thanks for any help Ken -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] PHP Command Line Scripts 'Aborting' at end ...
* Thus wrote Marc G. Fournier: Note that the following is based on php installed via the FreeBSD ports system ... I'm getting a core file, but if I try: gdb /usr/local/bin/php php.core ... its definitely not looking good: s# gdb /usr/local/bin/php php.core ... Core was generated by `php'. Program terminated with signal 6, Abort trap. Reading symbols from /usr/lib/libcrypt.so.2...done. Reading symbols from /usr/lib/libm.so.2...done. Reading symbols from /usr/lib/libc.so.4...done. Reading symbols from /usr/local/lib/php/20020429/interbase.so...done. Reading symbols from /usr/local/firebird/lib/libfbembed.so.1...Deprecated bfd_read called at /usr/src/gnu/usr.bin/binutils/gdb/../../../../contrib/gdb/gdb/dwarf2read.c line 3049 in dwarf2_read_section Error while reading shared library symbols: Dwarf Error: Cannot handle DW_FORM_strp in DWARF reader. Reading symbols from /usr/lib/libncurses.so.5...done. Error while reading shared library symbols: ì: No such file or directory. Error while reading shared library symbols: ynamic: No such file or directory. Segmentation fault (core dumped) Interesting core dump :) Try running php directly from gdb instead of reading the core file: % gdb /usr/loca/bin/php ... run script.php ... bt See if that produces a better backtrace. mod_php4 appears to work fine, just the command line version seems to be off ... and its running, producing expected output, its just that last 'Abort' that tends to screw things up a bit ... My bet is you have a buggy library somewhere, ncurses being a viable candidate since it does not get loaded in mod_php4. Curt -- Quoth the Raven, Nevermore. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] PHP Command Line Scripts 'Aborting' at end ...
On Wed, 27 Oct 2004 13:44:54 -0300 (ADT), Marc G. Fournier [EMAIL PROTECTED] wrote: Not sure how to debug ... help? You said you installed in via ports, so did you happen to check the 'debug' option when you installed it? [ ] DEBUG Enable debug Just a question.. as that might help explain more what's going on. -- Greg Donald Zend Certified Engineer http://gdconsultants.com/ http://destiney.com/ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] PHP Command Line Scripts 'Aborting' at end ...
On Wed, 27 Oct 2004 13:44:54 -0300 (ADT), Marc G. Fournier [EMAIL PROTECTED] wrote: I have a really simple PHP script that, when you run it, generates an Abort at the end of it: ams# /tmp/test.php testAbort (core dumped) I just installed php4-cgi on a FreeBSD 4.10 system I have. The same test.php script runs fine for me. cat test.php #!/usr/local/bin/php ?php echo test; ? ./test.php Content-type: text/html X-Powered-By: PHP/4.3.9 test -- Greg Donald Zend Certified Engineer http://gdconsultants.com/ http://destiney.com/ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] PHP Command Line Scripts 'Aborting' at end ...
I just did a reinstall from ports, and it works now as well ... maybe a stale library for one of hte modules :( thanks ... On Wed, 27 Oct 2004, Greg Donald wrote: On Wed, 27 Oct 2004 13:44:54 -0300 (ADT), Marc G. Fournier [EMAIL PROTECTED] wrote: I have a really simple PHP script that, when you run it, generates an Abort at the end of it: ams# /tmp/test.php testAbort (core dumped) I just installed php4-cgi on a FreeBSD 4.10 system I have. The same test.php script runs fine for me. cat test.php #!/usr/local/bin/php ?php echo test; ? ./test.php Content-type: text/html X-Powered-By: PHP/4.3.9 test -- Greg Donald Zend Certified Engineer http://gdconsultants.com/ http://destiney.com/ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php Marc G. Fournier Hub.Org Networking Services (http://www.hub.org) Email: [EMAIL PROTECTED] Yahoo!: yscrappy ICQ: 7615664 -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] System Command and snmp commands
Tring Tring .
Just to ring please help me.
I am giving to out print_r($ret) then it returns 1 at
exec(' snmpget -v 2c -c public 10.103.16.14 sysUpTime.0',$ret);
--Nikhil
-Original Message-
From: Mulley, Nikhil [mailto:[EMAIL PROTECTED]
Sent: Tuesday, October 26, 2004 12:41 PM
To: [EMAIL PROTECTED]
Subject: [PHP] System Command and snmp commands
Hi All,
I want to use system command to perform snmp queries on a remote machine and the
problem is that I want to store the output /result in an Array , so that I can later
use it for parsing purposes.I know I could use exec and passthru statements
actually,But I am unable to store the result in the array or I am unsure whether the
result is not getting stored in the array
Here is the code
?php
exec(' snmpget -v 2c -c public 10.103.16.14 sysUpTime.0',$ret);
list($a)=split('[,]',$ret);
echo $a[0];
?
Point me , if any thing wrong in the code
Please help me.
Thanks,
Nikhil.
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Re: [PHP] system command
Ron Clark wrote: Capture the output in the $output variable then ob_clean to empty the output buffer before printing the the desired message. ob_get_clean() is preferable: $output = ob_get_clean(); // Gets the buffered output and cleans the buffer -- Daniel Schierbeck -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] system command
Daniel Schierbeck wrote: Ron Clark wrote: Capture the output in the $output variable then ob_clean to empty the output buffer before printing the the desired message. ob_get_clean() is preferable: $output = ob_get_clean(); // Gets the buffered output and cleans the buffer Didn't need the contents of the buffer. All I needed was the last line which was contained in $output = system(). -- Ron Clark System Administrator/Web Coordinator Armstrong Atlantic State University 11935 Abercorn Street Savannah, Ga 31419 Phone: 912 961 3234 Fax: 912 927 5353 -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] system command
Ron Clark wrote: Daniel Schierbeck wrote: Ron Clark wrote: Capture the output in the $output variable then ob_clean to empty the output buffer before printing the the desired message. ob_get_clean() is preferable: $output = ob_get_clean(); // Gets the buffered output and cleans the buffer Didn't need the contents of the buffer. All I needed was the last line which was contained in $output = system(). Sorry, my bad... -- Daniel Schierbeck -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] system command
From: ron clark [EMAIL PROTECTED] I an trying to add virus scanning to the file upload section of our portal using uvscan. The virus scanning is working properly using a system call , but I am having problems with formatting the output. I need to check the return value and if it is not a 0, I want to create a custom message. The problem is, when using system the output of the call is flushed to the browser before I can write the custom message so I have the uvscan message and then my custom message. You can use output_buffering to capture the output, or use a different method to make the call, i.e. backticks or exec(), which allow you to capture the output before it's displayed. ---John Holmes... -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] system command
On Tuesday 24 August 2004 03:49, ron clark wrote: I an trying to add virus scanning to the file upload section of our portal using uvscan. The virus scanning is working properly using a system call , but I am having problems with formatting the output. I need to check the return value and if it is not a 0, I want to create a custom message. The problem is, when using system the output of the call is flushed to the browser before I can write the custom message so I have the uvscan message and then my custom message. The system() function has a few siblings, check them out. -- Jason Wong - Gremlins Associates - www.gremlins.biz Open Source Software Systems Integrators * Web Design Hosting * Internet Intranet Applications Development * -- Search the list archives before you post http://marc.theaimsgroup.com/?l=php-general -- /* Democracy is a process by which the people are free to choose the man who will get the blame. -- Laurence J. Peter */ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Re:[PHP] system command
John Holmes wrote: From: ron clark [EMAIL PROTECTED] I an trying to add virus scanning to the file upload section of our portal using uvscan. The virus scanning is working properly using a system call , but I am having problems with formatting the output. I need to check the return value and if it is not a 0, I want to create a custom message. The problem is, when using system the output of the call is flushed to the browser before I can write the custom message so I have the uvscan message and then my custom message. You can use output_buffering to capture the output, or use a different method to make the call, i.e. backticks or exec(), which allow you to capture the output before it's displayed. ---John Holmes... Thanks John. Was a simple fix. Turn output buffering on to prevent the output of the system command going to the browser. Capture the output in the $output variable then ob_clean to empty the output buffer before printing the the desired message. -- Ron Clark System Administrator/Web Coordinator Armstrong Atlantic State University 11935 Abercorn Street Savannah, Ga 31419 Phone: 912 961 3234 Fax: 912 927 5353 -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] Linux command in PHP
[snip] Today I tried to add another option, that gives sound and send email. The script works ok when I run from shell. But when I add the code to cronjob, the email is send but NO SOUND. Any ideas what can cause such problem? # Below the code that start the xmms sound $alert = /usr/bin/xmms /home/mike/Desktop/song1.mp3; `$alert'; [/snip] The problem is caused by bad code. See http://www.php.net/exec -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Linux command in PHP
* Thus wrote Mike Mapsnac ([EMAIL PROTECTED]): I have script that basically process a file. If something found in the file, the script send email. Today I tried to add another option, that gives sound and send email. The script works ok when I run from shell. But when I add the code to cronjob, the email is send but NO SOUND. Any ideas what can cause such problem? # Below the code that start the xmms sound $alert = /usr/bin/xmms /home/mike/Desktop/song1.mp3; `$alert'; This is an X problem, not php. xmms has no clue what :display to run xmms on. Curt -- I used to think I was indecisive, but now I'm not so sure. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] system command?
On Monday 10 May 2004 23:00, Jas wrote: I didn't sent off list, always to php.general in reply to whatever message thread I am in. In any event, I have tried safe mode = On and safe mode = Off with the 4 commands I listed in my last thread and my actual code is using an echo = textarea$tailed/textarea; echo = textarea$tailed/textarea; is not good code. Please learn some basic PHP first! I even tried to remove the -f and replaced it with a -n 600 (for six hundred lines to be output) and it still wont place the $tailed var into the textarea. It will output to the screen but not to the textarea, I am just going to scrap it and try it a different way. Each of the 4 commands I listed in my last thread has a different functionality. As you have noted one of them just outputs directly whatever system function is being executed. Read the descriptions of the 'commands' carefully and choose the one appropriate for the job. -- Jason Wong - Gremlins Associates - www.gremlins.biz Open Source Software Systems Integrators * Web Design Hosting * Internet Intranet Applications Development * -- Search the list archives before you post http://marc.theaimsgroup.com/?l=php-general -- /* We don't know who it was that discovered water, but we're pretty sure that it wasn't a fish. -- Marshall McLuhan */ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] system command?
[snip]
Anyone know what this wouldn't work? I have tried using a couple of
functions defined at http://us2.php.net/manual/en/ref.exec.php and none
seem to have the desired effect.
?php
$tailed = shell_exec('tail -f /path/to/log');
//$tailed = exec('tail -f /path/to/log');
//$tailed = system('tail -f /path/to/log');
print = textarea$tailed/textarea;
?
[/snip]
Is PHP running in safe mode?
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Re: [PHP] system command?
I believe when you add the -f flag, the tail command doesn't exit, it
just keeps printing as data is appended to the log, did you try dropping
the -f flag?
On Mon, 2004-05-10 at 10:15, Jas wrote:
Anyone know what this wouldn't work? I have tried using a couple of
functions defined at http://us2.php.net/manual/en/ref.exec.php and none
seem to have the desired effect.
?php
$tailed = shell_exec('tail -f /path/to/log');
//$tailed = exec('tail -f /path/to/log');
//$tailed = system('tail -f /path/to/log');
print = textarea$tailed/textarea;
?
Thanks in advance,
Jas
--
Adam Voigt
[EMAIL PROTECTED]
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RE: [PHP] system command?
[snip]
Anyone know what this wouldn't work? I have tried using a couple of
functions defined at http://us2.php.net/manual/en/ref.exec.php and
none
seem to have the desired effect.
?php
$tailed = shell_exec('tail -f /path/to/log');
//$tailed = exec('tail -f /path/to/log');
//$tailed = system('tail -f /path/to/log');
print = textarea$tailed/textarea;
?
[/snip]
Take a look at your print statement, print =
textarea$tailed/textarea;
That should throw a parse error. Try print(textarea . $tailed .
/textarea); HTH!
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Re: [PHP] system command?
Jas wrote:
Anyone know what this wouldn't work? I have tried using a couple of
functions defined at http://us2.php.net/manual/en/ref.exec.php and none
seem to have the desired effect.
?php
$tailed = shell_exec('tail -f /path/to/log');
//$tailed = exec('tail -f /path/to/log');
//$tailed = system('tail -f /path/to/log');
print = textarea$tailed/textarea;
?
Thanks in advance,
Jas
'tail -f' won't exit.
--
John C. Nichel
KegWorks.com
716.856.9675
[EMAIL PROTECTED]
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RE: [PHP] system command?
[snip]
It is now... but it still doesn't work. I have tried passthru(),
exec(), shell_exec() system() trying to tail -f a log file into a
textarea box and I get nothing or the output is put in the headers and
stops the rest of the page from loading. I am at a loss.
Jay Blanchard wrote:
[snip]
Anyone know what this wouldn't work? I have tried using a couple of
functions defined at http://us2.php.net/manual/en/ref.exec.php and
none
seem to have the desired effect.
?php
$tailed = shell_exec('tail -f /path/to/log');
//$tailed = exec('tail -f /path/to/log');
//$tailed = system('tail -f /path/to/log');
print = textarea$tailed/textarea;
?
[/snip]
Is PHP running in safe mode?
[/snip]
a. safe mode must be OFF
b. you must remove the = from the print statement, should be thrwoing
a syntax erro
c. get rid of the -f as it will not continue to update the text area
d. do not reply off-list unless requested
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Re: [PHP] system command?
I didn't sent off list, always to php.general in reply to whatever
message thread I am in. In any event, I have tried safe mode = On and
safe mode = Off with the 4 commands I listed in my last thread and my
actual code is using an echo = textarea$tailed/textarea;
I even tried to remove the -f and replaced it with a -n 600 (for six
hundred lines to be output) and it still wont place the $tailed var into
the textarea. It will output to the screen but not to the textarea, I
am just going to scrap it and try it a different way.
Cheers,
Jas
Jay Blanchard wrote:
[snip]
It is now... but it still doesn't work. I have tried passthru(),
exec(), shell_exec() system() trying to tail -f a log file into a
textarea box and I get nothing or the output is put in the headers and
stops the rest of the page from loading. I am at a loss.
Jay Blanchard wrote:
[snip]
Anyone know what this wouldn't work? I have tried using a couple of
functions defined at http://us2.php.net/manual/en/ref.exec.php and
none
seem to have the desired effect.
?php
$tailed = shell_exec('tail -f /path/to/log');
//$tailed = exec('tail -f /path/to/log');
//$tailed = system('tail -f /path/to/log');
print = textarea$tailed/textarea;
?
[/snip]
Is PHP running in safe mode?
[/snip]
a. safe mode must be OFF
b. you must remove the = from the print statement, should be thrwoing
a syntax erro
c. get rid of the -f as it will not continue to update the text area
d. do not reply off-list unless requested
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RE: [PHP] system command?
[snip]
I didn't sent off list, always to php.general in reply to whatever
message thread I am in. In any event, I have tried safe mode = On and
safe mode = Off with the 4 commands I listed in my last thread and my
actual code is using an echo = textarea$tailed/textarea;
?php
$tailed = shell_exec('tail -f /path/to/log');
//$tailed = exec('tail -f /path/to/log');
//$tailed = system('tail -f /path/to/log');
print = textarea$tailed/textarea;
?
[/snip]
?php
$tailed = shell_exec('tail /path/to/log');
print = textarea$tailed/textarea;
?
I can only think that it must be a permissions issue. What happens if
you run the script from the command line?
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RE: [PHP] system command?
[snip] I didn't sent off list [/snip] I am in an relatively crappy mood this day, you may want to NOT refute something I have said and in essence call me a liar. You'll get little help that way. P.S. Stop top posting too. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] system command?
lol On Mon, 2004-05-10 at 11:16, Jay Blanchard wrote: [snip] I didn't sent off list [/snip] I am in an relatively crappy mood this day, you may want to NOT refute something I have said and in essence call me a liar. You'll get little help that way. P.S. Stop top posting too. -- Adam Voigt [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] system command?
[snip]
?php
$tailed = shell_exec('tail /path/to/log');
print = textarea$tailed/textarea;
?
[/snip]
I forgot to take out the =
?php
$tailed = shell_exec('tail /path/to/log');
print = textarea$tailed/textarea;
?
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Re: [PHP] Str_Replace Command
On Tuesday 03 February 2004 00:14, Christopher J. Crane wrote:
$StockURL =
http://finance.yahoo.com/d/quotes.txt?s=xrx,ikn,dankyf=sl1e=.txt;;
$StockResults = implode('', file($StockURL));
$Rows = split(\n, $StockResults);
foreach($Rows as $Row) { echo str_replace('',,$Row).br\n; }
foreach($Rows as $Row) { str_replace('',,$Row); echo $Row.br\n; }
str_replace() RETURNS the replaced string. It does not alter $Row.
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Re: [PHP] Str_Replace Command
Ok I got around it by the following, but now I have a new problem. I can not
get the two dimensional array working. I want to later be able to output a
variable like this $TickerData[IKN] and it will output the associated
$Price.
$StockURL =
http://finance.yahoo.com/d/quotes.txt?s=xrx,ikn,dankyf=sl1e=.txt;;
$StockResults = implode('', file($StockURL));
$Rows = split(\n, $StockResults);
foreach($Rows as $Row) {
list($Symbol, $Price) = split(,, $Row);
$Symbol = str_replace('', , $Symbol);
$TickerData = array($Symbol=$Ticker);
}
print_r($TickerData);
echo $TickerData[IKN].br\n;
Jason Wong [EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]
On Tuesday 03 February 2004 00:14, Christopher J. Crane wrote:
$StockURL =
http://finance.yahoo.com/d/quotes.txt?s=xrx,ikn,dankyf=sl1e=.txt;;
$StockResults = implode('', file($StockURL));
$Rows = split(\n, $StockResults);
foreach($Rows as $Row) { echo str_replace('',,$Row).br\n; }
foreach($Rows as $Row) { str_replace('',,$Row); echo
$Row.br\n; }
str_replace() RETURNS the replaced string. It does not alter $Row.
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Open Source Software Systems Integrators
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Re: [PHP] Str_Replace Command
On Tuesday 03 February 2004 00:52, Christopher J. Crane wrote: Ok I got around it by the following, but now I have a new problem. I can not get the two dimensional array working. I want to later be able to output a variable like this $TickerData[IKN] and it will output the associated $Price. print_r($TickerData); So what does the above show? If it isn't what you expect, figure out *why*. Like how is $TickerData being assigned. -- Jason Wong - Gremlins Associates - www.gremlins.biz Open Source Software Systems Integrators * Web Design Hosting * Internet Intranet Applications Development * -- Search the list archives before you post http://marc.theaimsgroup.com/?l=php-general -- /* We have phasers, I vote we blast 'em! -- Bailey, The Corbomite Maneuver, stardate 1514.2 */ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Str_Replace Command
Well this is it and it is really got me...
Echoing out the $Symbol and $Price works just fine one row about the
$TickerData array assignment. Yet it outputs nothing.
Array ( [] = ) is what I get. If I change the line to
$TickerData = array ($Symbol = $Price); I get nothing, or the same
result. If I change the line to
$TickerData = array ('$Symbo'l = '$Price'); I get the following
Array ( [$Symbol] = $Price ) which tells me the assignment works, but it
seems like the $Symbol and $Price variable are blank when assigning to the
array. I know that they are not blank since they echoed out just fine one
line above.GRR
$StockURL =
http://finance.yahoo.com/d/quotes.txt?s=xrx,ikn,dankyf=sl1e=.txt;;
$StockResults = implode('', file($StockURL));
$Rows = split(\n, $StockResults);
foreach($Rows as $Row) {
list($Symbol, $Price) = split(,, $Row);
$Symbol = str_replace('', , $Symbol);
echo $Symbol. - .$Price.br\n;
$TickerData = array ($Symbol = $Price);
}
print_r($TickerData);
Jason Wong [EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]
On Tuesday 03 February 2004 00:52, Christopher J. Crane wrote:
Ok I got around it by the following, but now I have a new problem. I can
not get the two dimensional array working. I want to later be able to
output a variable like this $TickerData[IKN] and it will output the
associated $Price.
print_r($TickerData);
So what does the above show? If it isn't what you expect, figure out
*why*.
Like how is $TickerData being assigned.
--
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Open Source Software Systems Integrators
* Web Design Hosting * Internet Intranet Applications Development *
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Re: [PHP] Str_Replace Command
On Tuesday 03 February 2004 01:09, Christopher J. Crane wrote:
Well this is it and it is really got me...
Echoing out the $Symbol and $Price works just fine one row about the
$TickerData array assignment. Yet it outputs nothing.
Array ( [] = ) is what I get. If I change the line to
$TickerData = array ($Symbol = $Price); I get nothing, or the same
result. If I change the line to
$TickerData = array ('$Symbo'l = '$Price'); I get the following
Array ( [$Symbol] = $Price ) which tells me the assignment works, but it
seems like the $Symbol and $Price variable are blank when assigning to the
array. I know that they are not blank since they echoed out just fine one
line above.GRR
Are you sure that the line: echo $Symbol ...
is displaying something sensible for each $Row?
You're overwriting $TickerData at each iteration of the foreach-loop thus if
your last $Row doesn't contain something sensible neither would $TickerData.
You probably want to use this assignment instead:
$TickerData[$Symbol] = $Price;
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Open Source Software Systems Integrators
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Re: [PHP] Str_Replace Command
snip
$StockURL =
http://finance.yahoo.com/d/quotes.txt?s=xrx,ikn,dankyf=sl1e=.txt;;
$StockResults = implode('', file($StockURL));
$Rows = split(\n, $StockResults);
foreach($Rows as $Row) {
list($Symbol, $Price) = split(,, $Row);
$Symbol = str_replace('', , $Symbol);
echo $Symbol. - .$Price.br\n;
$TickerData = array ($Symbol = $Price);
}
print_r($TickerData);
/snip
why not replace:
$TickerData = array ($Symbol = $Price);
that line reassigns $TickerData to a array with one element in it
everytime you call it. The last time through your loop, $Symbol = ''
and $Price = '', so you get Array ( [] = ) when you print_r
with this:
$TickerData[$Symbol] = $Price;
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