[Puppet Users] Re: Wildcards in file resourses -- yet another time
On Friday, August 2, 2013 3:39:32 AM UTC-5, Ivan Lysov wrote:
>
> Hi All!
>
> I want to grant spetial permissions on some core files. So it would be
> nice to use something like
>
> file { "/var/lib/monitorium/core*" :
> mode => 0644,
> }
>
> But that obviously doesn't work. Any people with the same problem i've
> googled used some workarounds like managing directories recursively or
> writing more complicated scripts.
> I can't manage the whole directory because of many other files inside and
> i don't want to extrabloat my manifests.
> What should i do?
>
If you imagine declaring a single resource of a built-in type that
encompasses multiple files inside a given directory, then that can only be
structured as a recursive File resource aimed at the directory.
Non-recursive Files always represent exactly one file / directory / symlink.
Unfortunately, however, Puppet does not support what you are asking. The
'ignore' parameter is as close as it comes: with that you could manage all
files in a given directory *except* those matching some glob, but you want
the opposite selection criterion.
As far as I can see, your best bet for a Puppet-based solution is an Exec.
John
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[Puppet Users] Re: Wildcards in file resourses -- yet another time
Hi Ivan,
You can try putting the all file names in array variable and use that
array variable in file resource.
File resource of puppet support array structure. This might work.
On Friday, August 2, 2013 2:09:32 PM UTC+5:30, Ivan Lysov wrote:
>
> Hi All!
>
> I want to grant spetial permissions on some core files. So it would be
> nice to use something like
>
> file { "/var/lib/monitorium/core*" :
> mode => 0644,
> }
>
> But that obviously doesn't work. Any people with the same problem i've
> googled used some workarounds like managing directories recursively or
> writing more complicated scripts.
> I can't manage the whole directory because of many other files inside and
> i don't want to extrabloat my manifests.
> What should i do?
>
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Re: [Puppet Users] Re: Wildcards in file resourses -- yet another time
+1 on that. exec a shell command.
Look at it this way: How can you get the list of files without running a shell
command ?
Short answer: You cannot, so make it a chmod instead of an ls command and you
are done.
“Sometimes I think the surest sign that intelligent life exists elsewhere in
the universe is that none of it has tried to contact us.”
Bill Waterson (Calvin & Hobbes)
- Original Message -
From: "jcbollinger"
To: puppet-users@googlegroups.com
Sent: Friday, August 2, 2013 9:03:21 AM
Subject: [Puppet Users] Re: Wildcards in file resourses -- yet another time
On Friday, August 2, 2013 3:39:32 AM UTC-5, Ivan Lysov wrote:
Hi All!
I want to grant spetial permissions on some core files. So it would be nice to
use something like
file { "/var/lib/monitorium/core*" :
mode => 0644,
}
But that obviously doesn't work. Any people with the same problem i've googled
used some workarounds like managing directories recursively or writing more
complicated scripts.
I can't manage the whole directory because of many other files inside and i
don't want to extrabloat my manifests.
What should i do?
If you imagine declaring a single resource of a built-in type that encompasses
multiple files inside a given directory, then that can only be structured as a
recursive File resource aimed at the directory. Non-recursive Files always
represent exactly one file / directory / symlink.
Unfortunately, however, Puppet does not support what you are asking. The
'ignore' parameter is as close as it comes: with that you could manage all
files in a given directory except those matching some glob, but you want the
opposite selection criterion.
As far as I can see, your best bet for a Puppet-based solution is an Exec.
John
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