Re: [pygtk] no invisible cursor
John Finlay wrote:
Ionutz Borcoman wrote:
Hi,
The reference says:
To make the cursor invisible, use gtk.gdk.Cursor() to create a cursor
with no pixels in it.
When I try to use it, I get an error:
import gtk
gtk.pygtk_version
(2, 4, 1)
c = gtk.gdk.Cursor()
Traceback (most recent call last):
File stdin, line 1, in ?
TypeError: Usage:
gtk.gdk.Cursor(cursor_type)
gtk.gdk.Cursor(display, cursor_type)
gtk.gdk.Cursor(display, pixbuf, x, y)
gtk.gdk.Cusrsor(source, mask, fg, bg, x, y)
Any idea on what's wrong? Is this not supported in 2.4.1? Is it a bug?
TIA,
Try:
pix = gtk.gdk.Pixmap(window, 1, 1, 1)
color = gtk.gdk.Color()
cursor = gtk.gdk.Cursor(pix, pix, color, color, 0, 0)
John
Thanks, it should probably work, but I've already changed my code to:
def create_empty_cursor():
pix_data = /* XPM */
static char * invisible_xpm[] = {
1 1 1 1,
c None,
};
color = gtk.gdk.Color()
pix = gtk.gdk.pixmap_create_from_data(None,
pix_data, 1, 1, 1, color, color)
return gtk.gdk.Cursor(pix, pix, color, color, 0, 0)
This way I don't need the window anymore and I can create the cursor
before showing the widget (in my __init__).
I guess this should go in the standard pygtk, that is, a call to
gtk.gdk.Cursor() with no arguments should return this cursor. As I said
before, I belive hiding the cursor is a common enough operation, so it
should deserve a simpler solution.
If not, your or my solution should go in the FAQ under How do I hide
the cursor?:
How do I hide the cursor?
-
1. Create an invisible cursor with:
pix_data = /* XPM */
static char * invisible_xpm[] = {
1 1 1 1,
c None,
};
color = gtk.gdk.Color()
pix = gtk.gdk.pixmap_create_from_data(None,
pix_data, 1, 1, 1, color, color)
invisble_cursor = gtk.gdk.Cursor(pix, pix, color, color, 0, 0)
2. When you need to hide the cursor in 'some_gtk_widget', set it to the
invisble one:
some_gtk_widget.window.set_cursor(invisble_cursor)
3. To show again the cursor, set it to the old cursor or to the default one:
# set the cursor to the default one
some_gtk_widget.window.set_cursor(None)
Cheers,
--
Ionutz Borcoman
http://borco.net/
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[pygtk] no invisible cursor
Hi, The reference says: To make the cursor invisible, use gtk.gdk.Cursor() to create a cursor with no pixels in it. When I try to use it, I get an error: import gtk gtk.pygtk_version (2, 4, 1) c = gtk.gdk.Cursor() Traceback (most recent call last): File stdin, line 1, in ? TypeError: Usage: gtk.gdk.Cursor(cursor_type) gtk.gdk.Cursor(display, cursor_type) gtk.gdk.Cursor(display, pixbuf, x, y) gtk.gdk.Cusrsor(source, mask, fg, bg, x, y) Any idea on what's wrong? Is this not supported in 2.4.1? Is it a bug? TIA, -- Ionutz Borcoman http://borco.net/ ___ pygtk mailing list pygtk@daa.com.au http://www.daa.com.au/mailman/listinfo/pygtk Read the PyGTK FAQ: http://www.async.com.br/faq/pygtk/
Re: [pygtk] no invisible cursor
Le Boulanger Yann wrote: Ionutz Borcoman wrote: Le Boulanger Yann wrote: Ionutz Borcoman wrote: Hi, The reference says: To make the cursor invisible, use gtk.gdk.Cursor() to create a cursor with no pixels in it. When I try to use it, I get an error: import gtk gtk.pygtk_version (2, 4, 1) c = gtk.gdk.Cursor() Traceback (most recent call last): File stdin, line 1, in ? TypeError: Usage: gtk.gdk.Cursor(cursor_type) gtk.gdk.Cursor(display, cursor_type) gtk.gdk.Cursor(display, pixbuf, x, y) gtk.gdk.Cusrsor(source, mask, fg, bg, x, y) Any idea on what's wrong? Is this not supported in 2.4.1? Is it a bug? TIA, Have a look here[1]. you'll find informations on the way to create a Cursor. 1. http://pygtk.org/pygtk2reference/class-gdkcursor.html Please read *more carefull* my post. I sent it because the stuff from [1] are not working. Or am I missing something? TIA, gtk.gdk.Cursor() constructor takes one or more arguments, you gave it none. it's the problem. Yann We are running in circles :/ Please read again the docs. They say you can use the gtk.gdk.Cursor() *with no arguments* to create an invisible cursor. The problem is that it is not working. So it is the problem of the docs or of the library. So once again, how do I create an invisible cursor, because gtk.gdk.Cursor() *with no arguments* is not working, though this was the supposed way to do it, according to docs. TIA, -- Ionutz Borcoman http://borco.net/ ___ pygtk mailing list pygtk@daa.com.au http://www.daa.com.au/mailman/listinfo/pygtk Read the PyGTK FAQ: http://www.async.com.br/faq/pygtk/
Re: [pygtk] no invisible cursor
Ionutz Borcoman wrote: Le Boulanger Yann wrote: Ionutz Borcoman wrote: Le Boulanger Yann wrote: Ionutz Borcoman wrote: Hi, The reference says: To make the cursor invisible, use gtk.gdk.Cursor() to create a cursor with no pixels in it. When I try to use it, I get an error: import gtk gtk.pygtk_version (2, 4, 1) c = gtk.gdk.Cursor() Traceback (most recent call last): File stdin, line 1, in ? TypeError: Usage: gtk.gdk.Cursor(cursor_type) gtk.gdk.Cursor(display, cursor_type) gtk.gdk.Cursor(display, pixbuf, x, y) gtk.gdk.Cusrsor(source, mask, fg, bg, x, y) Any idea on what's wrong? Is this not supported in 2.4.1? Is it a bug? TIA, Have a look here[1]. you'll find informations on the way to create a Cursor. 1. http://pygtk.org/pygtk2reference/class-gdkcursor.html Please read *more carefull* my post. I sent it because the stuff from [1] are not working. Or am I missing something? TIA, gtk.gdk.Cursor() constructor takes one or more arguments, you gave it none. it's the problem. Yann We are running in circles :/ Please read again the docs. They say you can use the gtk.gdk.Cursor() *with no arguments* to create an invisible cursor. The problem is that it is not working. So it is the problem of the docs or of the library. So once again, how do I create an invisible cursor, because gtk.gdk.Cursor() *with no arguments* is not working, though this was the supposed way to do it, according to docs. TIA, I think the doc suggests you to use an empty pixbuf, not to run gtk.gdk.Cursors() without arguments. Maybe i'm wrong :/ Yann ___ pygtk mailing list pygtk@daa.com.au http://www.daa.com.au/mailman/listinfo/pygtk Read the PyGTK FAQ: http://www.async.com.br/faq/pygtk/
Re: [pygtk] no invisible cursor
On Mon, 2005-02-28 at 14:45 +0100, Le Boulanger Yann wrote: I think the doc suggests you to use an empty pixbuf, not to run gtk.gdk.Cursors() without arguments. Maybe i'm wrong :/ That is correct. By gtk.gdk.Cursor() the documentation meant one of the valid gtk.gdk.Cursor constructors with an empty cursor. This could probably be phrased better. Ross -- Ross Burton mail: [EMAIL PROTECTED] jabber: [EMAIL PROTECTED] www: http://www.burtonini.com./ PGP Fingerprint: 1A21 F5B0 D8D0 CFE3 81D4 E25A 2D09 E447 D0B4 33DF signature.asc Description: This is a digitally signed message part ___ pygtk mailing list pygtk@daa.com.au http://www.daa.com.au/mailman/listinfo/pygtk Read the PyGTK FAQ: http://www.async.com.br/faq/pygtk/
Re: [pygtk] no invisible cursor
Ross Burton wrote:
On Mon, 2005-02-28 at 14:45 +0100, Le Boulanger Yann wrote:
I think the doc suggests you to use an empty pixbuf, not to run
gtk.gdk.Cursors() without arguments.
Maybe i'm wrong :/
That is correct.
By gtk.gdk.Cursor() the documentation meant one of the valid
gtk.gdk.Cursor constructors with an empty cursor. This could probably
be phrased better.
Ross
I have try this:
def create_empty_cursor(window):
pix_data = #define invisible_cursor_width 0
#define invisible_cursor_height 0
#define invisible_cursor_x_hot 0
#define invisible_cursor_y_hot 0
static unsigned short invisible_cursor_bits[] = {};
color = gtk.gdk.Color()
pix = gtk.gdk.bitmap_create_from_data(window, pix_data, 1, 1)
return gtk.gdk.Cursor(pix, pix, color, color, 0, 0)
The problem is that I still get a black dot. I want nothing, not event
that dot. (I have try to set the pix to have size 0x0, but it crashes
the whole app).
I believe hiding the cursor is a common enough operation - there should
be some shorcut for doing it. I though that gtkgdk.Cursor *with no
arguments* is the way to do it. It looks now, it isn't :(
So, how do I hide the cursor?
TIA,
--
Ionutz Borcoman
http://borco.net/
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Re: [pygtk] no invisible cursor
On Mon, 2005-02-28 at 17:08 +0200, Ionutz Borcoman wrote: The problem is that I still get a black dot. I want nothing, not event that dot. (I have try to set the pix to have size 0x0, but it crashes the whole app). I believe hiding the cursor is a common enough operation - there should be some shorcut for doing it. I though that gtkgdk.Cursor *with no arguments* is the way to do it. It looks now, it isn't :( You'll need to set an empty mask for the cursor too. Ross -- Ross Burton mail: [EMAIL PROTECTED] jabber: [EMAIL PROTECTED] www: http://www.burtonini.com./ PGP Fingerprint: 1A21 F5B0 D8D0 CFE3 81D4 E25A 2D09 E447 D0B4 33DF signature.asc Description: This is a digitally signed message part ___ pygtk mailing list pygtk@daa.com.au http://www.daa.com.au/mailman/listinfo/pygtk Read the PyGTK FAQ: http://www.async.com.br/faq/pygtk/
Re: [pygtk] no invisible cursor
Ionutz Borcoman wrote: Hi, The reference says: To make the cursor invisible, use gtk.gdk.Cursor() to create a cursor with no pixels in it. When I try to use it, I get an error: import gtk gtk.pygtk_version (2, 4, 1) c = gtk.gdk.Cursor() Traceback (most recent call last): File stdin, line 1, in ? TypeError: Usage: gtk.gdk.Cursor(cursor_type) gtk.gdk.Cursor(display, cursor_type) gtk.gdk.Cursor(display, pixbuf, x, y) gtk.gdk.Cusrsor(source, mask, fg, bg, x, y) Any idea on what's wrong? Is this not supported in 2.4.1? Is it a bug? TIA, Try: pix = gtk.gdk.Pixmap(window, 1, 1, 1) color = gtk.gdk.Color() cursor = gtk.gdk.Cursor(pix, pix, color, color, 0, 0) John ___ pygtk mailing list pygtk@daa.com.au http://www.daa.com.au/mailman/listinfo/pygtk Read the PyGTK FAQ: http://www.async.com.br/faq/pygtk/
