Re: Command parsing... best module to use?
Thanks for the replies. Pyparsing looks just like what I need. -- http://mail.python.org/mailman/listinfo/python-list
Command parsing... best module to use?
Hey everyone. I am writing a game in python, and it includes a text console somewhat like the one in WoW and Runescape. I want to be able to include / commands, like IRC, and was wondering what the best module would be to parse these. Thanks a lot, Collin D -- http://mail.python.org/mailman/listinfo/python-list
Re: Tkinter - problem closing window
On Jan 5, 6:25 am, Djames Suhanko djames.suha...@gmail.com wrote:
Hello!
I'm sorry my terrible english (my native language is portuguese).
I has a litle program that open another window. When I close de root
window in quit button, I need clicking 2 times to close. is where the
problem?
The source:
1 #!/usr/bin/env python
2 from Tkinter import *
3 import sys
4 import random
5 class App:
6 def __init__(self, master):
7 frame = Frame(master)
8 frame.pack()
9 rotulo = Label(frame, text=Clique em 'Gerar' e boa
sorte!,borderwidth=2,bg=gray,justify=C ENTER,relief=SUNKEN)
10 rotulo.pack()
11
12 self.button = Button(frame, text=Sair, fg=red,
command=frame.quit,borderwidth=1)
13 self.button.pack(side=LEFT)
14 self.hi_there = Button(frame, text=Gerar Numero,
command=self.say_hi,borderwidth=1)
15 self.hi_there.pack(side=RIGHT,padx=2,pady=2)
16
17 def gera_seis(self):
18 a = {}
19 for i in range(6):
20 a[i] = %02d % int (random.randint(0,60))
21 resultadoA = %s-%s-%s-%s-%s-%s %
(str(a[0]),str(a[1]),str(a[2]),str(a[3]),str(a[4]),str(a[5]))
22 return resultadoA
23
24 def say_hi(self):
25 resultado = self.gera_seis()
26 raiz = Tk()
27 F = Frame(raiz)
28 F.pack()
29 hello = Label(F, text=resultado)
30 hello.pack()
31 F.mainloop()
32
33 root = Tk()
34 root.title($$$ Loteria $$$)
35 app = App(root)
36 root.mainloop()
--
Djames Suhanko
LinuxUser 158.760
Also for style, you might want to group the import lines so they look
like this:
from Tkinter import *
import sys, random
A bit more pythonic. :P
--
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Re: Tkinter - problem closing window
On Jan 5, 9:21 am, Roger rdcol...@gmail.com wrote:
On Jan 5, 11:52 am, Collin D collin.da...@gmail.com wrote:
On Jan 5, 6:25 am, Djames Suhanko djames.suha...@gmail.com wrote:
Hello!
I'm sorry my terrible english (my native language is portuguese).
I has a litle program that open another window. When I close de root
window in quit button, I need clicking 2 times to close. is where the
problem?
The source:
1 #!/usr/bin/env python
2 from Tkinter import *
3 import sys
4 import random
5 class App:
6 def __init__(self, master):
7 frame = Frame(master)
8 frame.pack()
9 rotulo = Label(frame, text=Clique em 'Gerar' e boa
sorte!,borderwidth=2,bg=gray,justify=C ENTER,relief=SUNKEN)
10 rotulo.pack()
11
12 self.button = Button(frame, text=Sair, fg=red,
command=frame.quit,borderwidth=1)
13 self.button.pack(side=LEFT)
14 self.hi_there = Button(frame, text=Gerar Numero,
command=self.say_hi,borderwidth=1)
15 self.hi_there.pack(side=RIGHT,padx=2,pady=2)
16
17 def gera_seis(self):
18 a = {}
19 for i in range(6):
20 a[i] = %02d % int (random.randint(0,60))
21 resultadoA = %s-%s-%s-%s-%s-%s %
(str(a[0]),str(a[1]),str(a[2]),str(a[3]),str(a[4]),str(a[5]))
22 return resultadoA
23
24 def say_hi(self):
25 resultado = self.gera_seis()
26 raiz = Tk()
27 F = Frame(raiz)
28 F.pack()
29 hello = Label(F, text=resultado)
30 hello.pack()
31 F.mainloop()
32
33 root = Tk()
34 root.title($$$ Loteria $$$)
35 app = App(root)
36 root.mainloop()
--
Djames Suhanko
LinuxUser 158.760
Also for style, you might want to group the import lines so they look
like this:
from Tkinter import *
import sys, random
A bit more pythonic. :P
In that case you probably want to take out the 'from' import and:
import Tkinter, sys, random
in order to avoid any namespace issues especially if you have a large
project with lots of gui manipulations. But that's just me being
pedantic. ;)
I agree... you could have conflicting functions.. not fun. XD
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Re: Factoring Polynomials
On Dec 18, 11:52 am, eric e...@ericaro.net wrote: On Dec 18, 8:37 pm, collin.da...@gmail.com wrote: I am trying to write a simple application to factor polynomials. I wrote (simple) raw_input lines to collect the a, b, and c values from the user, but I dont know how to implement the quadratic equation x = (-b +or- (b^2 - 4ac)^1/2) / 2a into python. Any ideas? with numpy: from numpy import * s=[1,-1] x = -b+s*sqrt( b**2-4*a*c )/(2*a) Erichttp://codeslash.blogspot.com Ahh. Great.. thank you. I didnt know about the sqrt function.. saves me from doing ^1/2. Thanks again. -CD -- http://mail.python.org/mailman/listinfo/python-list
Re: Factoring Polynomials
On Dec 18, 1:09 pm, Mark Dickinson dicki...@gmail.com wrote: On Dec 18, 8:47 pm, Scott David Daniels scott.dani...@acm.org wrote: else: # a single result (discriminant is zero) return (-b / (2 * a),) Maybe make that (-b / (2. * a)) to avoid getting funny results when a and b are integers. (Or do a from __future__ import division, or use Python 3.0, or ) And to make the function more bullet-proof, you might want to do something like (untested): from math import copysign [rest of example as in Scott's post] if discriminant: # two results root1 = (-b - copysign(discriminant, b))/(2*a) root2 = c/(a*root1) return (root1, root2) to avoid numerical problems when b*b is much larger than abs(a*c). Compare with the results of the usual formula when a = c = 1, b = 10**9, for example. But that still doesn't help you when the computation of the discriminant underflows or overflows... Isn't floating-point a wonderful thing! :) Mark Thanks for all your help! Its good to know how to do it w/ without numpy. And yes, floating point is the best thing since sliced bread. ^^ -CD -- http://mail.python.org/mailman/listinfo/python-list
Re: Factoring Polynomials
On Dec 18, 4:41 pm, James Mills prolo...@shortcircuit.net.au wrote: On Fri, Dec 19, 2008 at 10:11 AM, Gabriel Genellina gagsl-...@yahoo.com.ar wrote: En Thu, 18 Dec 2008 17:37:35 -0200, collin.da...@gmail.com escribió: I am trying to write a simple application to factor polynomials. I wrote (simple) raw_input lines to collect the a, b, and c values from the user, but I dont know how to implement the quadratic equation x = (-b +or- (b^2 - 4ac)^1/2) / 2a Why is this so hard ? This is simple simple expression. Reading through the Python tutorial and reading up on how to define functions is all you need! :) Here goes: def f(a, b, c): ... x = (-1 * b) + ((b**2 - (4 * a * c)) / (2 * a)) ... return (-1 * x), x ... f(1, 2, 3) (6, -6) cheers James Hiya James! Just one small problem with your equation above... The quadratic formula is: x = -b +or- (b**2 - (4 * a * c))^1/2 / 2a You just forgot the square root which makes quadratic a bit more complicated. You would have to download and import sqrt() from numpy or **.5 Also.. I need to build in functionality so the user does not have to directly call the function like: f(a,b,c) Instead.. they should be able to just raw_input their values. Also.. as with some of the examples above its a good idea to analyze the discriminant to make sure we have a real solution. Of course.. thats all pretty simple to build in. Thanks a lot! -- http://mail.python.org/mailman/listinfo/python-list
Re: Factoring Polynomials
On Dec 18, 5:30 pm, James Mills prolo...@shortcircuit.net.au
wrote:
UPDATE:
jmi...@atomant:~/tmp$ cat polycalc.py
#!/usr/bin/env python
from math import sqrt
def f(a, b, c):
if (b**2 - (4 * a * c)) 0:
return None, None # Can't solve
x1 = -b - (sqrt(b**2 - (4 * a * c)) / (2 * a))
x2 = -b + (sqrt(b**2 - (4 * a * c)) / (2 * a))
return x1, x2
print Polynomial Solver...
print
while True:
a = float(raw_input(a: ))
b = float(raw_input(b: ))
c = float(raw_input(c: ))
x = f(a, b, c)
if None in x:
print Can't solve!
else:
print x = (%0.2f, %0.2f) % x
jmi...@atomant:~/tmp$ ./polycalc.py
Polynomial Solver...
a: 1
b: 8
c: 5
x = (-11.32, -4.68)
Ahh. Great.. that answers a lot of questions.
Originally I was using just a = raw_input('a: ')
And was getting errors because you cant perform mathmatical operations
on strings. .
Thanks again!
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Re: Factoring Polynomials
On Dec 18, 5:10 pm, Steven D'Aprano st...@remove-this- cybersource.com.au wrote: On Thu, 18 Dec 2008 11:37:35 -0800, collin.day.0 wrote: I am trying to write a simple application to factor polynomials. I wrote (simple) raw_input lines to collect the a, b, and c values from the user, but I dont know how to implement the quadratic equation x = (-b +or- (b^2 - 4ac)^1/2) / 2a into python. Any ideas? def quadratic_solution(a, b, c): sol1 = (-b + (b**2 - 4*a*c)**0.5)/2*a sol2 = (-b - (b**2 - 4*a*c)**0.5)/2*a return (sol1, sol2) Because this looks like homework, I've deliberately left in two errors in the above. One of them is duplicated in the two lines above the return, and you must fix it or you'll get radically wrong answers. The second is more subtle, and quite frankly if this is homework you could probably leave it in and probably not even lose marks. You will need to do significant research into numerical methods to learn what it is, but you will then get significantly more accurate results. -- Steven The corrected function is: def quadratic_solution(a,b,c) sol1 = -1*b + ((b**2 - 4*a*c)**.5)/2*a sol1 = -1*b - ((b**2 - 4*a*c)**.5)/2*a return (sol1, sol2) Squaring the -b would give you some strange solutions :D -CD -- http://mail.python.org/mailman/listinfo/python-list
Re: Factoring Polynomials
On Dec 18, 11:37 am, collin.da...@gmail.com wrote:
I am trying to write a simple application to factor polynomials. I
wrote (simple) raw_input lines to collect the a, b, and c values from
the user, but I dont know how to implement the quadratic equation
x = (-b +or- (b^2 - 4ac)^1/2) / 2a
into python. Any ideas?
I completed the code:
#import
from math import sqrt
# collect data
a = float(raw_input('Type a value: '))
b = float(raw_input('Type b value: '))
c = float(raw_input('Type c value: '))
# create solver
def solver(a,b,c):
if b**2 - 4*a*c 0:
return 'No real solution.'
else:
sol1 = -1 * b + (sqrt(b**2 - 4*a*c)) / 2*a
sol2 = -1 * b - (sqrt(b**2 - 4*a*c)) / 2*a
return (sol1, sol2)
# execute
print solver(a,b,c)
Thanks to everyone who helped...
This really expanded my knowledge on some of the mathematical
functions in Python.
--
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Re: Factoring Polynomials
On Dec 18, 6:12 pm, Collin D collin.da...@gmail.com wrote:
On Dec 18, 11:37 am, collin.da...@gmail.com wrote:
I am trying to write a simple application to factor polynomials. I
wrote (simple) raw_input lines to collect the a, b, and c values from
the user, but I dont know how to implement the quadratic equation
x = (-b +or- (b^2 - 4ac)^1/2) / 2a
into python. Any ideas?
I completed the code:
#import
from math import sqrt
# collect data
a = float(raw_input('Type a value: '))
b = float(raw_input('Type b value: '))
c = float(raw_input('Type c value: '))
# create solver
def solver(a,b,c):
if b**2 - 4*a*c 0:
return 'No real solution.'
else:
sol1 = -1 * b + (sqrt(b**2 - 4*a*c)) / 2*a
sol2 = -1 * b - (sqrt(b**2 - 4*a*c)) / 2*a
return (sol1, sol2)
# execute
print solver(a,b,c)
Thanks to everyone who helped...
This really expanded my knowledge on some of the mathematical
functions in Python.
UPDATE:
'
#import
from math import sqrt
# collect data
a = float(raw_input('Type a value: '))
b = float(raw_input('Type b value: '))
c = float(raw_input('Type c value: '))
# create solver
def solver(a,b,c):
if b**2 - 4*a*c 0:
return 'No real solution.'
else:
sol1 = (-1 * b + (sqrt(b**2 - 4*a*c))) / 2*a
sol2 = (-1 * b - (sqrt(b**2 - 4*a*c))) / 2*a
return (sol1, sol2)
# execute
print solver(a,b,c)
--
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Re: Factoring Polynomials
On Dec 18, 6:23 pm, Russ P. russ.paie...@gmail.com wrote:
On Dec 18, 6:17 pm, Collin D collin.da...@gmail.com wrote:
On Dec 18, 6:12 pm, Collin D collin.da...@gmail.com wrote:
On Dec 18, 11:37 am, collin.da...@gmail.com wrote:
I am trying to write a simple application to factor polynomials. I
wrote (simple) raw_input lines to collect the a, b, and c values from
the user, but I dont know how to implement the quadratic equation
x = (-b +or- (b^2 - 4ac)^1/2) / 2a
into python. Any ideas?
I completed the code:
#import
from math import sqrt
# collect data
a = float(raw_input('Type a value: '))
b = float(raw_input('Type b value: '))
c = float(raw_input('Type c value: '))
# create solver
def solver(a,b,c):
if b**2 - 4*a*c 0:
return 'No real solution.'
else:
sol1 = -1 * b + (sqrt(b**2 - 4*a*c)) / 2*a
sol2 = -1 * b - (sqrt(b**2 - 4*a*c)) / 2*a
return (sol1, sol2)
# execute
print solver(a,b,c)
Thanks to everyone who helped...
This really expanded my knowledge on some of the mathematical
functions in Python.
UPDATE:
'
#import
from math import sqrt
# collect data
a = float(raw_input('Type a value: '))
b = float(raw_input('Type b value: '))
c = float(raw_input('Type c value: '))
# create solver
def solver(a,b,c):
if b**2 - 4*a*c 0:
return 'No real solution.'
else:
sol1 = (-1 * b + (sqrt(b**2 - 4*a*c))) / 2*a
sol2 = (-1 * b - (sqrt(b**2 - 4*a*c))) / 2*a
return (sol1, sol2)
# execute
print solver(a,b,c)
You need to put your denominator, 2*a, in parens. The way it stands,
you are dividing by 2, then multiplying by a. That's not what you
want.
Also, for better style, I suggest you compute the discriminanat once
and store it for reuse rather than repeating the expression three
times.- Hide quoted text -
- Show quoted text -
I see what you mean on the denominator and discriminant. Ill do that.
--
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Re: Factoring Polynomials
On Dec 18, 6:27 pm, Collin D collin.da...@gmail.com wrote:
On Dec 18, 6:23 pm, Russ P. russ.paie...@gmail.com wrote:
On Dec 18, 6:17 pm, Collin D collin.da...@gmail.com wrote:
On Dec 18, 6:12 pm, Collin D collin.da...@gmail.com wrote:
On Dec 18, 11:37 am, collin.da...@gmail.com wrote:
I am trying to write a simple application to factor polynomials. I
wrote (simple) raw_input lines to collect the a, b, and c values from
the user, but I dont know how to implement the quadratic equation
x = (-b +or- (b^2 - 4ac)^1/2) / 2a
into python. Any ideas?
I completed the code:
#import
from math import sqrt
# collect data
a = float(raw_input('Type a value: '))
b = float(raw_input('Type b value: '))
c = float(raw_input('Type c value: '))
# create solver
def solver(a,b,c):
if b**2 - 4*a*c 0:
return 'No real solution.'
else:
sol1 = -1 * b + (sqrt(b**2 - 4*a*c)) / 2*a
sol2 = -1 * b - (sqrt(b**2 - 4*a*c)) / 2*a
return (sol1, sol2)
# execute
print solver(a,b,c)
Thanks to everyone who helped...
This really expanded my knowledge on some of the mathematical
functions in Python.
UPDATE:
'
#import
from math import sqrt
# collect data
a = float(raw_input('Type a value: '))
b = float(raw_input('Type b value: '))
c = float(raw_input('Type c value: '))
# create solver
def solver(a,b,c):
if b**2 - 4*a*c 0:
return 'No real solution.'
else:
sol1 = (-1 * b + (sqrt(b**2 - 4*a*c))) / 2*a
sol2 = (-1 * b - (sqrt(b**2 - 4*a*c))) / 2*a
return (sol1, sol2)
# execute
print solver(a,b,c)
You need to put your denominator, 2*a, in parens. The way it stands,
you are dividing by 2, then multiplying by a. That's not what you
want.
Also, for better style, I suggest you compute the discriminanat once
and store it for reuse rather than repeating the expression three
times.- Hide quoted text -
- Show quoted text -
I see what you mean on the denominator and discriminant. Ill do that.- Hide
quoted text -
- Show quoted text -
UPDATE:
#import
from math import sqrt
# collect data
a = float(raw_input('Type a value: '))
b = float(raw_input('Type b value: '))
c = float(raw_input('Type c value: '))
# find discriminant
disc = b**2 - 4*a*c
# create solver
def solver(a,b,c):
if disc 0:
return 'No real solution.'
else:
sol1 = (-1 * b + (sqrt(disc))) / (2*a)
sol2 = (-1 * b - (sqrt(disc))) / (2*a)
return (sol1, sol2)
# execute
print solver(a,b,c)
--
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Re: Factoring Polynomials
On Dec 18, 6:41 pm, Russ P. russ.paie...@gmail.com wrote:
On Dec 18, 6:31 pm, Collin D collin.da...@gmail.com wrote:
On Dec 18, 6:27 pm, Collin D collin.da...@gmail.com wrote:
On Dec 18, 6:23 pm, Russ P. russ.paie...@gmail.com wrote:
On Dec 18, 6:17 pm, Collin D collin.da...@gmail.com wrote:
On Dec 18, 6:12 pm, Collin D collin.da...@gmail.com wrote:
On Dec 18, 11:37 am, collin.da...@gmail.com wrote:
I am trying to write a simple application to factor polynomials. I
wrote (simple) raw_input lines to collect the a, b, and c values
from
the user, but I dont know how to implement the quadratic equation
x = (-b +or- (b^2 - 4ac)^1/2) / 2a
into python. Any ideas?
I completed the code:
#import
from math import sqrt
# collect data
a = float(raw_input('Type a value: '))
b = float(raw_input('Type b value: '))
c = float(raw_input('Type c value: '))
# create solver
def solver(a,b,c):
if b**2 - 4*a*c 0:
return 'No real solution.'
else:
sol1 = -1 * b + (sqrt(b**2 - 4*a*c)) / 2*a
sol2 = -1 * b - (sqrt(b**2 - 4*a*c)) / 2*a
return (sol1, sol2)
# execute
print solver(a,b,c)
Thanks to everyone who helped...
This really expanded my knowledge on some of the mathematical
functions in Python.
UPDATE:
'
#import
from math import sqrt
# collect data
a = float(raw_input('Type a value: '))
b = float(raw_input('Type b value: '))
c = float(raw_input('Type c value: '))
# create solver
def solver(a,b,c):
if b**2 - 4*a*c 0:
return 'No real solution.'
else:
sol1 = (-1 * b + (sqrt(b**2 - 4*a*c))) / 2*a
sol2 = (-1 * b - (sqrt(b**2 - 4*a*c))) / 2*a
return (sol1, sol2)
# execute
print solver(a,b,c)
You need to put your denominator, 2*a, in parens. The way it stands,
you are dividing by 2, then multiplying by a. That's not what you
want.
Also, for better style, I suggest you compute the discriminanat once
and store it for reuse rather than repeating the expression three
times.- Hide quoted text -
- Show quoted text -
I see what you mean on the denominator and discriminant. Ill do that.-
Hide quoted text -
- Show quoted text -
UPDATE:
#import
from math import sqrt
# collect data
a = float(raw_input('Type a value: '))
b = float(raw_input('Type b value: '))
c = float(raw_input('Type c value: '))
# find discriminant
disc = b**2 - 4*a*c
# create solver
def solver(a,b,c):
if disc 0:
return 'No real solution.'
else:
sol1 = (-1 * b + (sqrt(disc))) / (2*a)
sol2 = (-1 * b - (sqrt(disc))) / (2*a)
return (sol1, sol2)
# execute
print solver(a,b,c)
A couple of style points. I would use -b rather than -1 * b. Also, you
don't need the else clause. You can simplify it to
def solver(a, b, c):
disc = b**2 - 4 * a * c
if disc 0: return No real solution.
sol1 = (-b + sqrt(disc)) / (2*a)
sol2 = (-b - sqrt(disc)) / (2*a)
return sol1, sol2- Hide quoted text -
- Show quoted text -
UPDATE:
#import
from math import sqrt
# collect data
a = float(raw_input('Type a value: '))
b = float(raw_input('Type b value: '))
c = float(raw_input('Type c value: '))
# create solver
def solver(a,b,c):
disc = b**2 - 4*a*c
if disc 0:
return 'No real solution.'
else:
sol1 = (-b + (sqrt(disc))) / (2*a)
sol2 = (-b - (sqrt(disc))) / (2*a)
return (sol1, sol2)
# execute
print solver(a,b,c)
--
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