Re: Flubbed it in the second interation through the string: range error... HOW?
On 5/29/2024 10:59 AM, MRAB via Python-list wrote: On 2024-05-29 15:32, Thomas Passin via Python-list wrote: On 5/29/2024 8:55 AM, Kevin M. Wilson wrote: Please recall, I said the format for the email failed to retain the proper indents. I'll attach a picture of the code! Purpose; to uppercase every other letter in a string. Thanks all, KMW Simpler is good, and readability is good. For a simple conversion that has a little touch of generality: s1 = 'this is a test' def convert(i, ch): return ch.upper() if i % 2 else ch result = ''.join([convert(i, ch) for i, ch in enumerate(s1)]) print(result) # tHiS Is a tEsT [snip] Small mistake there. The original code converted to uppercase on even indexes, whereas your code does it on odd ones. I wondered if anyone would catch that :) Anyway, I don't think the original question was whether to start with even or odd but ways to iterate character by character and do something, right? However, this has a weakness: what to do about spaces. Should they be counted among the characters to be uppercased? or should they not be included in the count of the alternation? If you want to uppercase every other letter that is not a space, things become a little more complicated. And then do you want this to apply to all whitespace or only spaces? If you want to skip changing spaces, then you need to track the state of converted characters in some way. It would probably be easier (and more readable) to use a "for x in t:" construction: Actually, I did mess up the action for a space. It should be: def convert(convert_this, ch): """Convert character ch if convert_this is True. Don't convert spaces. """ if ch == ' ': return (convert_this, ch) if convert_this: return (False, ch.upper()) return (True, ch) We should never get two printable uppercased characters in a row, even if there is a space between them, but my original convert(convert_this, ch) did. def convert(convert_this, ch): """Convert character ch if convert_this is True. Don't convert spaces. """ if convert_this: if ch == ' ': return (convert_this, ch) elif convert_this: return (False, ch.upper()) return (True, ch) convert_next = False result = '' for ch in s1: convert_next, ch = convert(convert_next, ch) result += ch print(result) # tHiS Is A TeSt There could be even more complications if you allow non-ascii characters but you were asking about processing character by character so I won't get into that. (You haven't specified the problem in enough detail to answer questions like those). [snip] -- https://mail.python.org/mailman/listinfo/python-list
Re: Flubbed it in the second interation through the string: range error... HOW?
On 2024-05-29, Mats Wichmann via Python-list wrote:
> On 5/29/24 08:02, Grant Edwards via Python-list wrote:
>> On 2024-05-29, Chris Angelico via Python-list wrote:
>>
>>> print(f"if block {name[index]=} {index=}")
>>
>> Holy cow! How did I not know about the f-string {=} thing?
>
> It's more recent than f-strings in general, so it's not that hard to miss.
I really should make a habit of reading through the "what's new" pages
when new releases come out...
--
Grant
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Re: Flubbed it in the second interation through the string: range error... HOW?
On 2024-05-29 15:32, Thomas Passin via Python-list wrote: On 5/29/2024 8:55 AM, Kevin M. Wilson wrote: Please recall, I said the format for the email failed to retain the proper indents. I'll attach a picture of the code! Purpose; to uppercase every other letter in a string. Thanks all, KMW Simpler is good, and readability is good. For a simple conversion that has a little touch of generality: s1 = 'this is a test' def convert(i, ch): return ch.upper() if i % 2 else ch result = ''.join([convert(i, ch) for i, ch in enumerate(s1)]) print(result) # tHiS Is a tEsT [snip] Small mistake there. The original code converted to uppercase on even indexes, whereas your code does it on odd ones. However, this has a weakness: what to do about spaces. Should they be counted among the characters to be uppercased? or should they not be included in the count of the alternation? If you want to uppercase every other letter that is not a space, things become a little more complicated. And then do you want this to apply to all whitespace or only spaces? If you want to skip changing spaces, then you need to track the state of converted characters in some way. It would probably be easier (and more readable) to use a "for x in t:" construction: def convert(convert_this, ch): """Convert character ch if convert_this is True. Don't convert spaces. """ if convert_this: if ch == ' ': return (convert_this, ch) elif convert_this: return (False, ch.upper()) return (True, ch) convert_next = False result = '' for ch in s1: convert_next, ch = convert(convert_next, ch) result += ch print(result) # tHiS Is A TeSt There could be even more complications if you allow non-ascii characters but you were asking about processing character by character so I won't get into that. (You haven't specified the problem in enough detail to answer questions like those). [snip] -- https://mail.python.org/mailman/listinfo/python-list
Re: Flubbed it in the second interation through the string: range error... HOW?
> On 29 May 2024, at 05:38, Kevin M. Wilson via Python-list > wrote: > > The format in this email is not of my making, should someone know, how to do > this so that it's a readable script do tell! > KMW Your mail program may have a plain-text mode to compose messages in try using that. Barry -- https://mail.python.org/mailman/listinfo/python-list
Re: Flubbed it in the second interation through the string: range error... HOW?
On 5/29/2024 8:55 AM, Kevin M. Wilson wrote:
Please recall, I said the format for the email failed to retain the
proper indents.
I'll attach a picture of the code!
Purpose; to uppercase every other letter in a string.
Thanks all, KMW
Simpler is good, and readability is good. For a simple conversion that
has a little touch of generality:
s1 = 'this is a test'
def convert(i, ch):
return ch.upper() if i % 2 else ch
result = ''.join([convert(i, ch) for i, ch in enumerate(s1)])
print(result) # tHiS Is a tEsT
However, this has a weakness: what to do about spaces. Should they be
counted among the characters to be uppercased? or should they not be
included in the count of the alternation? If you want to uppercase
every other letter that is not a space, things become a little more
complicated. And then do you want this to apply to all whitespace or
only spaces?
If you want to skip changing spaces, then you need to track the state of
converted characters in some way. It would probably be easier (and more
readable) to use a "for x in t:" construction:
def convert(convert_this, ch):
"""Convert character ch if convert_this is True.
Don't convert spaces.
"""
if convert_this:
if ch == ' ':
return (convert_this, ch)
elif convert_this:
return (False, ch.upper())
return (True, ch)
convert_next = False
result = ''
for ch in s1:
convert_next, ch = convert(convert_next, ch)
result += ch
print(result) # tHiS Is A TeSt
There could be even more complications if you allow non-ascii characters
but you were asking about processing character by character so I won't
get into that.
(You haven't specified the problem in enough detail to answer questions
like those).
***
"When you pass through the waters, I will be with you: and when you pass
through the rivers, they will not sweep over you. When you walk through
the fire, you will not be burned: the flames will not set you ablaze."
*Isaiah 43:2
*
On Wednesday, May 29, 2024 at 06:19:56 AM MDT, Thomas Passin via
Python-list wrote:
On 5/29/2024 3:14 AM, Chris Angelico via Python-list wrote:
> On Wed, 29 May 2024 at 16:03, Cameron Simpson via Python-list
> mailto:python-list@python.org>> wrote:
>> By which Thomas means stuff like this:
>>
>> print(f'if block {name[index]} and index {index}')
>>
>> Notice the leading "f'". Personally I wouldn't even go that far, just:
>>
>> print('if block', name[index], 'and index', index)
>>
>> But there are plenty of places where f-strings are very useful.
>
> I wouldn't replace str.format() everywhere, nor would I replace
> percent encoding everywhere - but in this case, I think Thomas is
> correct. Not because it's 2024 (f-strings were brought in back in
> 2015, so they're hardly chronologically special),
I only meant that they have been around for 9 years and are usually more
readable, so just change over already. I had some inertia over them
myself (imagine sticking with % formatting!) so I understand.
> but because most of
> this looks like debugging output that can take advantage of this
> feature:
>
> print(f"if block {name[index]=} {index=}")
>
> ChrisA
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Re: Flubbed it in the second interation through the string: range error... HOW?
On 5/29/24 08:02, Grant Edwards via Python-list wrote:
On 2024-05-29, Chris Angelico via Python-list wrote:
print(f"if block {name[index]=} {index=}")
Holy cow! How did I not know about the f-string {=} thing?
It's more recent than f-strings in general, so it's not that hard to miss.
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Re: Flubbed it in the second interation through the string: range error... HOW?
On 2024-05-29, Chris Angelico via Python-list wrote:
> print(f"if block {name[index]=} {index=}")
Holy cow! How did I not know about the f-string {=} thing?
--
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--
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Re: Formatted Output and Argument Parsing (was: Re: Flubbed it in the second interation through the string: range error... HOW?)
On Wed, 29 May 2024 at 23:06, Dan Sommers via Python-list wrote: > (For the history-impaired, getopt existed long before Python and will > likely exist long after it, but getopt's "replacement" optparse lasted > only from 2003 until 2011.) Depends on your definition of "lasted". It's not getting developed further, but it's still there. If you started using it, you're welcome to keep going. https://docs.python.org/3/library/optparse.html ChrisA -- https://mail.python.org/mailman/listinfo/python-list
Formatted Output and Argument Parsing (was: Re: Flubbed it in the second interation through the string: range error... HOW?)
On 2024-05-29 at 17:14:51 +1000,
Chris Angelico via Python-list wrote:
> I wouldn't replace str.format() everywhere, nor would I replace
> percent encoding everywhere - but in this case, I think Thomas is
> correct. Not because it's 2024 (f-strings were brought in back in
> 2015, so they're hardly chronologically special), but because most of
> this looks like debugging output that can take advantage of this
> feature:
>
> print(f"if block {name[index]=} {index=}")
defsnark:
After years of getopt (and even more, if you include non-Python
experience), I'm glad I decided to wait a decade before chugging the
optparse koolaid.
(For the history-impaired, getopt existed long before Python and will
likely exist long after it, but getopt's "replacement" optparse lasted
only from 2003 until 2011.)
That said, I agree that the = thing makes f-strings eminently useful for
debugging, and I wholeheartedly agree with not fixing things that aren't
broken.
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Re: Flubbed it in the second interation through the string: range error... HOW?
On 5/29/2024 3:14 AM, Chris Angelico via Python-list wrote:
On Wed, 29 May 2024 at 16:03, Cameron Simpson via Python-list
wrote:
By which Thomas means stuff like this:
print(f'if block {name[index]} and index {index}')
Notice the leading "f'". Personally I wouldn't even go that far, just:
print('if block', name[index], 'and index', index)
But there are plenty of places where f-strings are very useful.
I wouldn't replace str.format() everywhere, nor would I replace
percent encoding everywhere - but in this case, I think Thomas is
correct. Not because it's 2024 (f-strings were brought in back in
2015, so they're hardly chronologically special),
I only meant that they have been around for 9 years and are usually more
readable, so just change over already. I had some inertia over them
myself (imagine sticking with % formatting!) so I understand.
but because most of
this looks like debugging output that can take advantage of this
feature:
print(f"if block {name[index]=} {index=}")
ChrisA
--
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Re: Flubbed it in the second interation through the string: range error... HOW?
On 2024-05-29 05:33, Kevin M. Wilson via Python-list wrote:
The following is my effort to understand how to process a string, letter, by
letter:
def myfunc(name): index = 0 howmax = len(name) # while (index <=
howmax): while (index < howmax): if (index % 2 == 0):
print('letter to upper = {}, index {}!'.format(name[index], index)) name =
name[index].upper() print('if block {} and index {}'.format(name[index],
index)) elif (index % 2 > 0): print(index) print('Start:
elseif block, index is {}, letter is {}'.format(index, name)) # print('letter
to lower = {}'.format(name[index])) # print('Already lowercase do noting:
name = {}'.format(name[index])) index += 1 # index = name.upper()
return name
myfunc('capitalism')
Error message: Not making sense, index is 1, letter s/b
'a'letter to upper = c, index 0!
if block C and index 0
1
Start: elseif block, index is 1, letter is C
---
IndexErrorTraceback (most recent call last)
Cell In[27], line 21
17 # index = name.upper()
19 return name
---> 21 myfunc('capitalism')
Cell In[27], line 8, in myfunc(name)
6 while (index < howmax):
7 if (index % 2 == 0):
> 8 print('letter to upper = {}, index {}!'.format(name[index],
index))
9 name = name[index].upper()
10 print('if block {} and index {}'.format(name[index], index))
IndexError: string index out of
range***
So, I'm doing something... Stupid!!
***
"When you pass through the waters, I will be with you: and when you pass through the
rivers, they will not sweep over you. When you walk through the fire, you will not be
burned: the flames will not set you ablaze."
Isaiah 43:2
I think the code is this:
def myfunc(name):
index = 0
howmax = len(name)
# while (index <= howmax):
while (index < howmax):
if (index % 2 == 0):
print('letter to upper = {}, index {}!'.format(name[index],
index))
name = name[index].upper()
print('if block {} and index {}'.format(name[index], index))
elif (index % 2 > 0):
print(index)
print('Start: elseif block, index is {}, letter is
{}'.format(index, name))
# print('letter to lower = {}'.format(name[index]))
# print('Already lowercase do noting: name =
{}'.format(name[index]))
index += 1
# index = name.upper()
return name
myfunc('capitalism')
What is:
name = name[index].upper()
meant to be doing?
What it's _actually_ doing is getting the character at a given index,
converting it to uppercase, and then assigning it to `name`, so `name`
is now 1 character long.
It doesn't this when 'index' is 0, so after the first iteration, `name`
is a single-character string.
On the second iteration it raises IndexError because the string is only
1 character long and you're asking for `name[1]`.
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Re: Flubbed it in the second interation through the string: range error... HOW?
On Wed, 29 May 2024 at 16:03, Cameron Simpson via Python-list
wrote:
> By which Thomas means stuff like this:
>
> print(f'if block {name[index]} and index {index}')
>
> Notice the leading "f'". Personally I wouldn't even go that far, just:
>
> print('if block', name[index], 'and index', index)
>
> But there are plenty of places where f-strings are very useful.
I wouldn't replace str.format() everywhere, nor would I replace
percent encoding everywhere - but in this case, I think Thomas is
correct. Not because it's 2024 (f-strings were brought in back in
2015, so they're hardly chronologically special), but because most of
this looks like debugging output that can take advantage of this
feature:
print(f"if block {name[index]=} {index=}")
ChrisA
--
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Re: Flubbed it in the second interation through the string: range error... HOW?
On 29May2024 01:14, Thomas Passin wrote:
Also, it's 2024 ... time to start using f-strings (because they are
more readable than str.format())
By which Thomas means stuff like this:
print(f'if block {name[index]} and index {index}')
Notice the leading "f'". Personally I wouldn't even go that far, just:
print('if block', name[index], 'and index', index)
But there are plenty of places where f-strings are very useful.
--
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Re: Flubbed it in the second interation through the string: range error... HOW?
Your code is unreadable. The lines have all run together. And after
that, kindly explain what you want your code sample to do. "Process"
doesn't say much.
From what I can make out about what you are trying to do, you would do
better to index through your string with
for i, chr in enumerate(name):
# do something with the character
Also, it's 2024 ... time to start using f-strings (because they are more
readable than str.format())
On 5/29/2024 12:33 AM, Kevin M. Wilson via Python-list wrote:
The following is my effort to understand how to process a string, letter, by
letter:
def myfunc(name): index = 0 howmax = len(name) # while (index <=
howmax): while (index < howmax): if (index % 2 == 0):
print('letter to upper = {}, index {}!'.format(name[index], index)) name =
name[index].upper() print('if block {} and index {}'.format(name[index],
index)) elif (index % 2 > 0): print(index) print('Start:
elseif block, index is {}, letter is {}'.format(index, name)) # print('letter
to lower = {}'.format(name[index])) # print('Already lowercase do noting:
name = {}'.format(name[index])) index += 1 # index = name.upper()
return name
myfunc('capitalism')
Error message: Not making sense, index is 1, letter s/b
'a'letter to upper = c, index 0!
if block C and index 0
1
Start: elseif block, index is 1, letter is C
---
IndexErrorTraceback (most recent call last)
Cell In[27], line 21
17 # index = name.upper()
19 return name
---> 21 myfunc('capitalism')
Cell In[27], line 8, in myfunc(name)
6 while (index < howmax):
7 if (index % 2 == 0):
> 8 print('letter to upper = {}, index {}!'.format(name[index],
index))
9 name = name[index].upper()
10 print('if block {} and index {}'.format(name[index], index))
IndexError: string index out of
range***
So, I'm doing something... Stupid!!
***
"When you pass through the waters, I will be with you: and when you pass through the
rivers, they will not sweep over you. When you walk through the fire, you will not be
burned: the flames will not set you ablaze."
Isaiah 43:2
--
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Fw: Flubbed it in the second interation through the string: range error... HOW?
The format in this email is not of my making, should someone know, how to do
this so that it's a readable script do tell!
KMW
***
"When you pass through the waters, I will be with you: and when you pass
through the rivers, they will not sweep over you. When you walk through the
fire, you will not be burned: the flames will not set you ablaze."
Isaiah 43:2
- Forwarded Message - From: Kevin M. Wilson via Python-list
To: python-list@python.org
Sent: Tuesday, May 28, 2024 at 10:35:23 PM MDTSubject:
Flubbed it in the second interation through the string: range error... HOW?
The following is my effort to understand how to process a string, letter, by
letter:
def myfunc(name): index = 0 howmax = len(name) # while (index <=
howmax): while (index < howmax): if (index % 2 == 0):
print('letter to upper = {}, index {}!'.format(name[index], index))
name = name[index].upper() print('if block {} and index
{}'.format(name[index], index)) elif (index % 2 > 0):
print(index) print('Start: elseif block, index is {}, letter is
{}'.format(index, name)) # print('letter to lower =
{}'.format(name[index])) # print('Already lowercase do noting: name
= {}'.format(name[index])) index += 1 # index = name.upper()
return name
myfunc('capitalism')
Error message: Not making sense, index is 1, letter s/b
'a'letter to upper = c, index 0!
if block C and index 0
1
Start: elseif block, index is 1, letter is C
---
IndexError Traceback (most recent call last)
Cell In[27], line 21
17 # index = name.upper()
19 return name
---> 21 myfunc('capitalism')
Cell In[27], line 8, in myfunc(name)
6 while (index < howmax):
7 if (index % 2 == 0):
> 8 print('letter to upper = {}, index {}!'.format(name[index],
index))
9 name = name[index].upper()
10 print('if block {} and index {}'.format(name[index], index))
IndexError: string index out of
range***
So, I'm doing something... Stupid!!
***
"When you pass through the waters, I will be with you: and when you pass
through the rivers, they will not sweep over you. When you walk through the
fire, you will not be burned: the flames will not set you ablaze."
Isaiah 43:2
--
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--
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Flubbed it in the second interation through the string: range error... HOW?
The following is my effort to understand how to process a string, letter, by
letter:
def myfunc(name): index = 0 howmax = len(name) # while (index <=
howmax): while (index < howmax): if (index % 2 == 0):
print('letter to upper = {}, index {}!'.format(name[index], index))
name = name[index].upper() print('if block {} and index
{}'.format(name[index], index)) elif (index % 2 > 0):
print(index) print('Start: elseif block, index is {}, letter is
{}'.format(index, name)) # print('letter to lower =
{}'.format(name[index])) # print('Already lowercase do noting: name
= {}'.format(name[index])) index += 1 # index = name.upper()
return name
myfunc('capitalism')
Error message: Not making sense, index is 1, letter s/b
'a'letter to upper = c, index 0!
if block C and index 0
1
Start: elseif block, index is 1, letter is C
---
IndexErrorTraceback (most recent call last)
Cell In[27], line 21
17 # index = name.upper()
19 return name
---> 21 myfunc('capitalism')
Cell In[27], line 8, in myfunc(name)
6 while (index < howmax):
7 if (index % 2 == 0):
> 8 print('letter to upper = {}, index {}!'.format(name[index],
index))
9 name = name[index].upper()
10 print('if block {} and index {}'.format(name[index], index))
IndexError: string index out of
range***
So, I'm doing something... Stupid!!
***
"When you pass through the waters, I will be with you: and when you pass
through the rivers, they will not sweep over you. When you walk through the
fire, you will not be burned: the flames will not set you ablaze."
Isaiah 43:2
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