Re: Https Form Page

2005-04-10 Thread Tim Roberts 
Hasan D [EMAIL PROTECTED] wrote:

I'm new on this httplib and urllib. Actually I dont know what should i use.

I want to fill the form in a https page , and return the result . I
write a test code but always gives errors. I cant find any good
example about this on the net. What should I do about this ?

import urlparse,urllib,httplib,string,htmllib,formatter

#port=443
target=https://www.abc.com/;
params = urllib.urlencode({'spam': 1, 'eggs': 2, 'bacon': 0})
http=httplib.HTTP(https://www.abc.com/,443)

If you want https, you should use the HTTPS class.

  http = httplib.HTTPS(https://www.abc.com/,443)

Or, even better, the HTTPSConnection class.

  http://www.noah.org/python/https/
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  Providenza  Boekelheide, Inc.
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Re: Https Form Page

2005-04-10 Thread Joshua Ginsberg 
It all really, really, really depends on your script processing the 
form. My suggestion is to use the openssl s_client program, manually 
submit your data, and see what your server is responding with.

-jag
inline: Pasted Graphic.tiffJoshua Ginsberg -- [EMAIL PROTECTED]
Brainstorm Internet Network Operations
970-247-1442 x131
On Apr 9, 2005, at 12:04 AM, Hasan D wrote:
 I cant figure out, always gives me the form page. Everything looks ok 
but ?

On Apr 9, 2005 2:07 AM, Joshua Ginsberg [EMAIL PROTECTED] 
wrote:
If url is your formpage and your formdata is correct, it should work.
Do you need to have a cookie set? Is it 304 redirecting you?
-jag

Joshua Ginsberg -- [EMAIL PROTECTED]
Brainstorm Internet Network Operations
970-247-1442 x131
On Apr 8, 2005, at 4:51 PM, Hasan D wrote:
Thank you for fast reply.
Your program works fine. But when i print the https_response it gives
me the form page. I want to send the form and print the result page.

On Apr 9, 2005 12:19 AM, Joshua Ginsberg [EMAIL PROTECTED]
wrote:
Try:
import urllib2, urllib
formdata = urllib.urlencode({'a':1,'b':2})
request = urllib2.Request(url)
request.add_data(formdata)
opener = urllib2.build_opener(urllib2.HTTPSHandler())
urllib2.install_opener(opener)
fs = urllib2.urlopen(request)
https_response = fs.read()
https_headers = fs.info().headers
https_mimetype = fs.info().type
-jag

Joshua Ginsberg -- [EMAIL PROTECTED]
Brainstorm Internet Network Operations
970-247-1442 x131
On Apr 8, 2005, at 2:13 PM, Hasan D wrote:
I'm new on this httplib and urllib. Actually I dont know what 
should
i
use.

I want to fill the form in a https page , and return the result 
. I
write a test code but always gives errors. I cant find any good
example about this on the net. What should I do about this ?

import urlparse,urllib,httplib,string,htmllib,formatter
#port=443
target=https://www.abc.com/;
params = urllib.urlencode({'spam': 1, 'eggs': 2, 'bacon': 0})
http=httplib.HTTP(https://www.abc.com/,443)
data='Name=xAdress=x'
headers = {Content-type:
application/x-www-form-urlencoded,Accept: text/plain}
print Sending Data On +target+...\n
http.putrequest(POST,target+/xxx.asp?q=7b=11,params)
response = http.getresponse()
print response.status, response.reason
http.send(data)
code,msg,headers = http.getreply()
print HTTP Code : ,str(code)
print HTTP Connection : ,msg
print HTTP headers : \n,headers,\n
HTML=http.getfile().read()
MyParser=htmllib.HTMLParser(formatter.NullFormatter())
MyParser.feed(HTML)
# Print all the anchors from the results page
print MyParser.anchorlist
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Re: Https Form Page

2005-04-09 Thread Hasan D 
 I cant figure out, always gives me the form page. Everything looks ok but ?


On Apr 9, 2005 2:07 AM, Joshua Ginsberg [EMAIL PROTECTED] wrote:
 If url is your formpage and your formdata is correct, it should work.
 
 Do you need to have a cookie set? Is it 304 redirecting you?
 
 -jag
 
 
 
 Joshua Ginsberg -- [EMAIL PROTECTED]
 Brainstorm Internet Network Operations
 970-247-1442 x131
 On Apr 8, 2005, at 4:51 PM, Hasan D wrote:
 
  Thank you for fast reply.
  Your program works fine. But when i print the https_response it gives
  me the form page. I want to send the form and print the result page.
 
 
 
  On Apr 9, 2005 12:19 AM, Joshua Ginsberg [EMAIL PROTECTED]
  wrote:
  Try:
 
  import urllib2, urllib
  formdata = urllib.urlencode({'a':1,'b':2})
  request = urllib2.Request(url)
  request.add_data(formdata)
  opener = urllib2.build_opener(urllib2.HTTPSHandler())
  urllib2.install_opener(opener)
  fs = urllib2.urlopen(request)
  https_response = fs.read()
  https_headers = fs.info().headers
  https_mimetype = fs.info().type
 
  -jag
 
 
 
  Joshua Ginsberg -- [EMAIL PROTECTED]
  Brainstorm Internet Network Operations
  970-247-1442 x131
  On Apr 8, 2005, at 2:13 PM, Hasan D wrote:
 
  I'm new on this httplib and urllib. Actually I dont know what should
  i
  use.
 
  I want to fill the form in a https page , and return the result . I
  write a test code but always gives errors. I cant find any good
  example about this on the net. What should I do about this ?
 
 
  import urlparse,urllib,httplib,string,htmllib,formatter
 
  #port=443
  target=https://www.abc.com/;
  params = urllib.urlencode({'spam': 1, 'eggs': 2, 'bacon': 0})
  http=httplib.HTTP(https://www.abc.com/,443)
 
  data='Name=xAdress=x'
  headers = {Content-type:
  application/x-www-form-urlencoded,Accept: text/plain}
 
  print Sending Data On +target+...\n
  http.putrequest(POST,target+/xxx.asp?q=7b=11,params)
 
  response = http.getresponse()
  print response.status, response.reason
 
  http.send(data)
 
  code,msg,headers = http.getreply()
 
  print HTTP Code : ,str(code)
  print HTTP Connection : ,msg
  print HTTP headers : \n,headers,\n
 
  HTML=http.getfile().read()
  MyParser=htmllib.HTMLParser(formatter.NullFormatter())
  MyParser.feed(HTML)
  # Print all the anchors from the results page
  print MyParser.anchorlist
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Https Form Page

2005-04-08 Thread Hasan D 
I'm new on this httplib and urllib. Actually I dont know what should i use.

I want to fill the form in a https page , and return the result . I
write a test code but always gives errors. I cant find any good
example about this on the net. What should I do about this ?


import urlparse,urllib,httplib,string,htmllib,formatter

#port=443
target=https://www.abc.com/;
params = urllib.urlencode({'spam': 1, 'eggs': 2, 'bacon': 0})
http=httplib.HTTP(https://www.abc.com/,443)

data='Name=xAdress=x'
headers = {Content-type:
application/x-www-form-urlencoded,Accept: text/plain}

print Sending Data On +target+...\n 
http.putrequest(POST,target+/xxx.asp?q=7b=11,params)

response = http.getresponse()
print response.status, response.reason

http.send(data)

code,msg,headers = http.getreply()

print HTTP Code : ,str(code)
print HTTP Connection : ,msg
print HTTP headers : \n,headers,\n

HTML=http.getfile().read()
MyParser=htmllib.HTMLParser(formatter.NullFormatter())
MyParser.feed(HTML)
# Print all the anchors from the results page
print MyParser.anchorlist
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Re: Https Form Page

2005-04-08 Thread Joshua Ginsberg 
Try:
import urllib2, urllib
formdata = urllib.urlencode({'a':1,'b':2})
request = urllib2.Request(url)
request.add_data(formdata)
opener = urllib2.build_opener(urllib2.HTTPSHandler())
urllib2.install_opener(opener)
fs = urllib2.urlopen(request)
https_response = fs.read()
https_headers = fs.info().headers
https_mimetype = fs.info().type
-jag
inline: Pasted Graphic.tiffJoshua Ginsberg -- [EMAIL PROTECTED]
Brainstorm Internet Network Operations
970-247-1442 x131
On Apr 8, 2005, at 2:13 PM, Hasan D wrote:
I'm new on this httplib and urllib. Actually I dont know what should i 
use.

I want to fill the form in a https page , and return the result . I
write a test code but always gives errors. I cant find any good
example about this on the net. What should I do about this ?
import urlparse,urllib,httplib,string,htmllib,formatter
#port=443
target=https://www.abc.com/;
params = urllib.urlencode({'spam': 1, 'eggs': 2, 'bacon': 0})
http=httplib.HTTP(https://www.abc.com/,443)
data='Name=xAdress=x'
headers = {Content-type:
application/x-www-form-urlencoded,Accept: text/plain}
print Sending Data On +target+...\n
http.putrequest(POST,target+/xxx.asp?q=7b=11,params)
response = http.getresponse()
print response.status, response.reason
http.send(data)
code,msg,headers = http.getreply()
print HTTP Code : ,str(code)
print HTTP Connection : ,msg
print HTTP headers : \n,headers,\n
HTML=http.getfile().read()
MyParser=htmllib.HTMLParser(formatter.NullFormatter())
MyParser.feed(HTML)
# Print all the anchors from the results page
print MyParser.anchorlist
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